Algebraic Theory of Automata Networks (SIAM Monographs on Discrete Mathematics and Applications, 11)

Using this statement, we get a simple proof of the following. Theorem 2.30. Neither KX nor LX has a basis if X is not a singleton. Proof. Let X be a set having at least two elements. Given a nonnegative integer m, let Km x and Lmtx denote the subsets of KX and LX such that for every (p Km,x Lm,x, P X*, and distinct x\,X2 X, ( (x\) (XI) whenever \p\ m. Moreover, let K'x = for which (y) = x, p X*, y X. Let K and L denote generating systems of KX and LX, respectively. It is enough to prove that K is not a basis of KX and L is not a basis of Lx. It is clear that ••• on the condition that , ..., ) € (or 1) n) ,..., € x). Therefore, K and L L'x. In other words, there exist a K and L, nonnegative integers K 1 ,K 2 .l 1 .l 2 with k1 < k l1 < l2, words Pi,p2,qi,q2 € X* with |pi;| = ki 1^,1 = i = 1,2, and letters xij,, yij,,, X, i, j = 1, 2, with xi1 (;2, y (> i / y,-)2, i = 1, 2 such that ctpl(xiti) = api(x^2), i = 1, 2, and q. (v, i) = fiqi (y/,2), i = 1,2. Now we define the following mappings:

50

Chapter 2. Directed Graphs, Automata, and Automata Networks

By Lemma 2.29 it is clear that for any /z, v e Kx, {J 2 and
2.3 Automata and Semigroups Given an automaton A = (A, X, 8), let us consider for every p e X* the transition 8P : A -> A induced by the word p as defined by 8p(a) = S(a, p) for a e A. For a given word p € X*, the transition induced by p is the function 8P : A —> A that takes any state a e A to 8(a, p). We sometimes also say that the word p represents the transition 8p and 8P is the transformation of A corresponding to the word p. The characteristic semigroup of A is S(A) = {8P | p e X+}, where for every 8p, 8q € S(A), 8p8q = 8pq; moreover, it is understood that 8P = 8q if and only if 8(a, p) = 8(a, q) holds for every a e A. Sometimes we shall write 8(a, p)asa- p. Then we have (a • p) • q = a • (pq) for all a e A, p, q e X*. The set of all these mappings forms a monoid (i.e., a semigroup having identity element) Si (A) under composition as product operation and is called the characteristic monoid of A. (Of course, the identity element of this monoid is <$x, where A. e X* is the empty word.) If Si (.4) is a group, then A is called a permutation automaton. A permutation automaton is said to be trivial if its characteristic monoid is a singleton. Consider a semigroup 5. If 5 has no identity element, then let 5X denote the semigroup with Sx = S U {A.}, where A. is an arbitrary symbol with X ^ 5; moreover, the product operation in S is extended to 5X by A,s = sA = s (s e 5) and A.A. = A.. If S has identity element (i.e., if 5 is monoid), then let Sx = S. In short, 5X denotes the least monoid containing S as a subsemigroup. A caveat: (1) Easily constructed examples show that it is possible for S(A) to be a group even when A is not a permutation automaton. (2) It may happen that Si (A)

2.3. Automata and Semigroups

51

(S(A))^. For example, this occurs in all cases where S(A) is a group but A is not a permutation automaton. Example 2.33. The automaton A = ({0,1}, { }, 8) with (0, :c) = 5(1, x) = 0 is a trivial example such that S(A) is a group but A is not a permutation automaton.

AUTOMATON WHICH IS NOT A PERMUTATION AUTOMATON BUT WHOSE TRANSFORMATION SEMIGROUP IS A GROUP

Proposition 2.34. Let A — (A, X, ) be an automaton and let F = {e, z1, z2} be a monoid having two right zero elements with identity and distinct right zeros z 1 , Z 2 - Moreover, let F' = { z i , Z2\ be a semigroup with two right zero elements. (1) F is isomorphic to a submonoid ofS(A) if and only if there are states a1, a2 A and nonempty words Po, p1, p2 such that8(a{, po) = a, and 8(at, PJ) = aj, i, j €. {1,2}. (2) F' is isomorphic to a subsemigroup ofS(A) if and only if there are states a\, a^ € A and nonempty words p\, p2 e such that (a,;, PJ) = aj, i, j {1,2}.

Proof. The sufficiency of (1) and (2) is clear. As regards necessity, first we consider an automaton A = (A, X, 5) such that S(A) has a submonoid to be isomorphic to F. Then there are input words po, pi, P2 X+, a subset B of the state set A such that S' = [ , IB, $ IB} is an isomorphic monoid to F. Consider the isomorphism (p : F s" and assume that, say, (e) = \B,
52

Chapter 2. Directed Graphs, Automata, and Automata Networks

Proposition 2.35. Let A— (A, X, 8) be an automaton and let M be a submonoid of S(A) or Si (A). There exists a nonempty set B C A with the following properties: (1) The elements ofM map B into itself. (2) The restriction of the identity ofMtoB is the identical mapping e\s : B B. (3) If m1 and m2 are distinct elements ofM, then m\(b) m.2(b)for at least one b

B.

Proof. Set B = { (a) : a A}, where e denotes the identity of M. First we observe that whenever we have e(a) = b for some a, b A, the equality ee = e implies e(b) = e(e(a)} = e(a) = b. Thus e(b) = b holds for every b B, in accordance with (2). On the other hand, for every m M, we have m = em. Therefore, by m = em and e(a) € B, a A, we get m(b) — (em)(b) = e(m(b)) B, b B. Hence, we obtain (1). Finally, let mi and m2 be two elements of M such that m\(b)=ni2(b) for every b B. Of course, we have m\ = m\e,m.2 = m2e with e(a) B,a A. But then, for every a A, m\(a) = (m\e}(a) = m\(e(a}) = m2(e(a)) = (ni2e)(a) = m2(a). This implies m\ = ni2. Therefore, if mi and m.2 are two distinct elements of M, then we should have (3). We also prove the following consequence of the above statement. Proposition 2.36. Let A— (A, X, ) be an automaton and M be a submonoid of S(A) or S\ (A). There exists a nonempty set B C A with the following properties: (1) The map a monoid isomorphism. (2) If M is a group then every restriction i.e., the monoid

with

is

is a permutation of B; is a permutation group over B.

Proof. Consider an automaton A = (A, X, ) and let M be a submonoid of S(A) or Si (A). Then A has a subset B having the properties of Proposition 2.35. First we show (2). By conditions (1) and (2) of Proposition 2.35, M' = { : M, p X+} is a monoid such that the restriction of the identity e of M to B is the identical mapping e\B : B B. Then e\B is the identity element of M'. On the other hand, for every pair f1 B , g I B M', the mapping f1 B g I B is a permutation of B if and only if both mappings f\B and g\B have this property. In addition, f\s(b), g\B(b), (fg)\B(b) B, b B implies f \sg\B = (fg}\B- Therefore, if g is the inverse of / in M, then /\sg\B = e\B, i-e., both /|B and g\B should be a permutation of B. This completes the proof of (2). Mow we prove (1). By condition (5) ol Proposition 2.33, we obtain that with is a one-to-one mapping Thus it is enough to show But this condition comes rrom and Given a semigroup 5, let denote again the automaton with Moreover, tor every automaton and let as usual. Consider the automaton be defined by having Proposition 2.37. For every automaton , morphically by As(A) •

can be represented homo-

2.3. Automata and Semigroups

53

Proof. Define the automaton A' = (A, S(A), 5') such that 8'(a, s) = s(d), a e A, s € S(A). Let \A\ = n and consider the wth diagonal power A'^n of A'. Give a fixed arrangement a\,..., an of the elements of the state set A and let B = { ( a s ( i ) , . . . , as(n)) '• s e S(A)}. Clearly, then B = (B, S(A), 8") with 8"(b, 5) = 8(b, s), b e B, s e S(A), is a state subautomaton of A'An. On the other hand, it is obvious that r : 5 -» B with T(S) = ( a s ( i ) , . . . , «,(„>), s € 5, is a state isomorphism of As(A)to #• It is also clear that the mapping r' : B -+ A with T f ( ( a s ( l ) , . . . , as(n))) = asW, (a j( i),..., as(n)) e B is a state homomorphism of B onto .4'. In addition, A^ is an input subautomaton of A. Thus, of course, A homomorphically represents A. Therefore, using the transitive property of homomorphic representation, we obtain that A$(A) homomorphically represents A^. D Given a semigroup 5, let As = (5X, 5, 5$) be the automaton with 8s(s\, $2) = si$2 (si e 5X, 52 € 5), where 51*2 denotes the product of s\ by $2 in 5X. We call As the semigroup automaton (corresponding to 5). If S is a simple group, then we will use the name simple group automaton too. Every finite transformation semigroup (A, 5) can be identified with an automaton (A, S, 8s), where 8s(a, s) = s(a) = a • s (a e A, s e 5). Clearly, the characteristic semigroup of this automaton is S. For an arbitrary automaton A = (A, X, 5), the set {8X : x e X} is a generating system of its characteristic semigroup 5(^4). Similarly, (A, {8X : x e X}) is a generating system of the transformation semigroup T(A) = (A, S(A)), which is called transformation semigroup of the automaton A. We have a • 8P = 8p(a) = 8(a, p) for all a € A, 8P e 5(^4). We can derive similarly the transformation monoid ofT\(A) = (A, S\(A)) of A. Of course, we can consider any automaton A as a generating system of the corresponding transformation semigroup (A, 5(^4)) over the set A of its states (identifying x with y whenever Sx = 8y (x, y e X)). Finally, let us consider the semigroup automaton ,4$ corresponding to a semigroup 5. Then we can identify this automaton with the transformation semigroup (5X, 5), which we call the transformation semigroup of the semigroup S. Our central notions are those of homomorphic and isomorphic simulations. An automaton A = (A, X, 5) homomorphically simulates the automaton A = (A', X', 5') under a surjective mapping t\ of a subset B of A onto A' and a mapping 12 of X' into X* with ri(8(b, r2(;t))) = S'(Ti(b),x) (beB,xe X'). (It is understood that 8(b, r2(Jt)) € B holds for every pair b € B, x € X'.) If r\ is bijective, then we speak about simulation.

A HOMOMORPHICALLY SIMULATES A UNDER If then is called a homomorphic (isomorphic) simulation by nonempty words. If we have a homomorphic simulation by nonempty words, then we also

54

Chapter 2. Directed Graphs, Automata, and Automata Networks

say that A' divides A (or A can be divided by A) and we will use the notation A < A to indicate this. In addition, if there is a positive integer n such that |T2 t')| = n for every x' X', then we write A\ "M, and, moreover, we say that A divides A into equal lengths, denoting this by A\ \A, if A'\ \MA holds for some positive integer n. The above definition of division for automata (often encountered in the automata theoretic literatures) appears to be quite different from the definition of division for transformation semigroups of Section 1.2, which is most commonly encountered in the more algebraic literature. The latter involves two maps going in the same direction, while the former involves maps in opposite directions. This difference is superficial, as the following lemma shows. It establishes that for transformation semigroups the automata-theoretic notion of division is equivalent with the notion of division for transformation semigroups introduced in Chapter 1. Now we prove that the next statement is a consequence of Proposition 2.37. Corollary 2.38. For every automaton A, we have Proof. Let A be an arbitrary automaton. Proposition 2.37 implies On the other hand is obvious. Hence, by the transitive property of division we obtain Lemma 2.39. Let (X, S) and (Xr, ) be transformation semigroups. Let X = (X, S, ) and X' = (X', S', S') be the corresponding automata. Then (X, 5) divides (X1, ') according to the definition of division for transformation semigroups if and only if X divides X' according to the definition of division for automata. That is, (X, S) < (X', S') if and only ifX < X1. Proof. If (X, S) divides (X', S'), by definition there is a subset Y c X', subsemigroup T of , with Y • T c Y, an onto function a : Y X, and a surjective semigroup homomorphism :T S satisfying (y • 0 = fa( ) • fa(t) f°r all y Y , f T. To establish the division of automata, let r\ = fa and let r2 : S -*• T c (S')+ be given by choosing TI(S) to be an arbitrary member of i/rf 1 ^). Now for all y e Y, s e S, ri(8'(y, r2(j))) = fa(y • r2(s)) = fa(y) • Vi(t 2 (s)) = fa(y) • s = 8(n(y), s). Also, 8'(y, r2(s)) always lies in Y since Y • T c Y and (s) T. Thus (T\, r2) as constructed comprises a division of automata X < '. Conversely, suppose a division of these automata is given. By definition, this comprises a surjective mapping \ of a subset Y of X' onto X and a mapping of 5 into nonempty words (S')+ with ri(S'(y, T2(s))) = 5(ri(y), ) (y Y, s 5). Moreover, 8(y, T2(s)) € Y holds for every pair y Y, s S. We will use Proposition 1.10. We take the lifts x of any x in X to be the elements of the nonempty set rf1 (x). Distinct members of X never have a common lift, since r\ is a function. As a lift for s S, we take s to be the element of 5" represented by the nonempty word T2 (s) in S'. Suppose two elements of S have a lift in common: if T2(s) and T2(s\) represent the same element of S' for some s, s\ e S, then for all y € 7, ri(y) • s = S(ri(y), s) = n(8'(y, r2(s))) = Ti(8'(y, r 2 (si))) = <5(n(y), Sl) = n(y) • SL Since r\ maps Y onto X, this implies that x • s = x • s\ for all x e X. Since (X, S) is a transformation semigroup, it follows that s = s\. Therefore, distinct elements of 5 have no lift in common. This establishes condition (1) of Proposition 1.10. For all lifts x f l(x)

2.3. Automata and Semigroups

of

55

and; we have is a lift of X • 5. This is condition (2) of Proposition 1.10; hence (X, 5) divides

(X', S').

The listed concepts of simulation and divisibility for automata are extended to transformation semigroups in such a way that we handle the transformation semigroups as automata in the manner just discussed. It is an easy exercise to verify the following. Proposition 2.40. Let A = (A, X, are equivalent:

and A' - (A', X', ') be automata. Then the following

(1) A
(2) (A', S(A)) < A (3) (A', SC4')) < (A, S(A)\ (4) A < (A, S(A».

In addition, we note that, in general, A\\A does not imply (A', S(A'))IIA but, of course,.A||.Aimplies A'\\(A, S(A». Finally, (A', S(A \Aimplies X'H^by definition. Proposition 2.41. Let A = (A, X hold:

)andA = (A', X', 8') be automata. Then the following

(1) A homomorphically simulates A if and only if (A', Si(A)) homomorphically represents A. (2) A homomorphically simulates A by nonempty words (i.e., A < A) if and only if (A', SC/4')) homomorphically represents A. Proposition 2.42. Every automaton A = (A, X, 8) is homomorphically represented by the direct product of a discrete automaton (A, {!A}, <$i) (with 8\(a, I A) = a for all a A) and the characteristic semigroup automaton ( (A), S(A), .4)).

Proof. Let ^i(a, s) — a • s for all a € A, s e X(A), These maps make up a homomorphic representation.

and

s) = s for all s

S(A).

Recall that if S' and 5 are semigroups, then S' < S (S' divides 5) means S' is a homomorphic image of a subsemigroup of S. It easy to check that this is equivalent to the division of transformation semigroups ( x, ) < ( , S), recalling how division for transformation semigroups was defined in Section 1.2. Moreover, using Lemma 2.39, a division of the semigroup automata 'x, ', ') < x, S, ) is equivalent to the corresponding division of transformation semigroups. Lemma 2.43. Let S and S' be finite semigroups. Then the following are equivalent:

56

Chapter 2. Directed Graphs, Automata, and Automata Networks

Proof. (2) =>• (1) is trivial. Indeed, having (2), S has a subsemigroup which can be mapped homomorphically onto S', i.e., S' < S. (1) =>• (2). Suppose S' < S. Then S has a subsemigroup Y which can be mapped homomorphically onto S'. Obviously, then Y is a submonoid of S\ Let • Y -> S' denote an appropriate homomorphism and consider the mapping 2 • YX ->• S/x with = Then YX • F c F and 2 (^) = A. and (y) = (y), y e 7. Moreover, let X (y • t) = (y) • , y e Y , t e Y. Thus we get (2). It remains to prove that (2) and (3) are equivalent. (2) means that there are a subset Y of SX, a subsemigroup T of 5 with Y • T c. Y, a surjective mapping : Y -* S , and a surjective semigroup homomorphism I/TI : T -»• 5 satisfying (yt) = 2(y) (^) for all y e 7, f 6 7T (1) means that there exists a nonempty set y c S functions h : Y -» X, : S' - S such that h is surjective, y • (p(s) € Y, and h (y • (s)) = h(y) • s for all y € F and s e S. But by Proposition 1.9, these properties are equivalent and thus, indeed, (2) and (3) are equivalent. The proof is complete. Proposition 2.44. Let (X, 5) be any transformation semigroup. Then (1) (2)(X,S)

and

Proof. (1) Lift each s to the X-tuple whose X-component is x • s. Lift each s S to the X-tuple (s,..., s). Distinct states and inputs have distinct lifts. Using Proposition 1.10 we have a division. (2) follows from the previous proposition. We say the semigroup 5 divides an automaton A (S < A) if S divides the characteristic semigroup S(A) of A. We say S\\ln)A if S T S(A) for T a subsemigroup of S(A) such that for each s 5, there exists t S(A) induced by an input word in X+ of length n (where X is the alphabet of A) with
2.3. Automata and Semigroups

57

Proposition 2.46. If the automaton A homomorphically (isomorphically) represents the automaton A', then A homomorphically (isomorphically) simulates A' (in equal lengths), and, simultaneously, then A divides the automaton A (in equal lengths). Proposition 2.47. Given a semigroup S and an automaton A with n states, let S < A. Then As < An, where An denotes the nth direct power of A. Moreover, S\\A implies As\\An. In more detail, AS divides the nth diagonal power AAn of A (and, respectively, As|| provided S\\A) under appropriate mappings T\ : B (B c A"), and 12 S X+ (having a positive integer m with \T2(s)\ = m (s S) provided S\\A). Proof. Since 5 divides A = (A, X, 5), there is a surjective homomorphism : S' 5, where S' is a subsemigroup of S(A). In particular, if S\ \A, then has the property for an appropriate positive integer m that we can correspond an m-length word ps to every s S satisfying ( ps) = s, such that ps S'. Consider an arrangement a\,...,an of the elements of A and identify every transformation t : {ai,..., an} {a\,..., an] (including the identity transformation, too) with the state (t(a\),..., t(an}) of the direct power A". By transitivity of division, it suffices to show AS < . (Or in the case of S\\A, by transitivity of division in equal lengths, it suffices to show that As\ .) It is clear that, by this correspondence, has a subautomaton isomorphic to the automaton M = (Si(A), X, ), where '( , x) = 8tx ( S\(A), x X). Let us define for every St B = S' U { } c (A),

Moreover, for every s € 5, let (s) = ps ( X+) such that^r(<5p = s, and, simultaneously, \p\ m provided S\\A. By an elementary computation we obtain that n homomorphically simulates the semigroup automaton As under (TI, 12); therefore, by the fact that 2 maps into X+, AS < A . Furthermore, we have ,4s||. n provided S\\A. The proof is complete. We now prove the following. Proposition 2.48. Consider a pair A, B of automata and let n denote the set of states of B. Assume that S(A) < B (S(A)\\B). If B is nontrivial (i.e., n > 1), then A divides (divides in equal length) the nth diagonal power ofB. Proof. Let S(A) < B (S(A)\\B). By Proposition 2.47, this assumption implies As(A) (B)An (AS(A)\\(B )> where (B)An denotes the nth diagonal power of B. On the other hand, by Corollary 2.38, A\ \As(A)- Thus, by the transitive property of division, A < (B)An (AII(B) A M ). Now we are ready to prove the following statement. Proposition 2.49. Given an automaton A and a semigroup S, let S < A. Suppose that S is either a noncyclic simple group or a subsemigroup of the monoid F with two right-zero elements. Then S\\A.

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Chapter 2. Directed Graphs, Automata, and Automata Networks

Proof. By definition of division, since S < A = (A, X, 5), we have a subsemigroup S' of the characteristic semigroup S(A) and a surjective homomorphism r : S' S. First we suppose that 5 = {gi,..., gn} is a noncyclic simple group. Let r\,..., rn X+ with V(5r,-) = gf, i e [ I , . . . ,n}. Then, using Theorem 1.2, there exists a positive integer m such that for every s S there are permutations PSti,..., PSttn over {!,...,«}, withS = g l(1) • • • g s _,(„) • • • g • • • gPs>m(n). But then, of course, (^ l(1) • • • • •• 5 o w i > ' ' ' 5n>,.m<,)) = t(8rfiJ(ir..rps,l(n,-rPs,m(1)-..^,m(n)) = J. Consequently, there exists a positive integer t (= m(\r\ | + h |rn |)) such that for every s € S, there is a t-length word p with ( ) = s. Thus we have S\ \ A for the simple group S whenever 5 < A. Now we will study the case when S is a subsemigroup of the monoid having two right zero elements (for 5 = F = {e, i, 2} with identity and distinct right zeros zi, 22)- Then we have input words, p0, pi, p2 e X+ with ^( )= ,) = Zi, ^( 2) = Z2- Take t] words q0,qi, q2 X+ having o = (po) ', <1\ = (/>i) ,?2 = (P2)l • It is clear that Igol = \q\\ = l
2.4 Automata Networks and Products of Automata In what follows we also use the concept of compatibility in the following sense. This a broader concept than we encountered in Section 2.1, as it allows the new content of a node to be influence directly by several incoming messages. A transformation F : Xn Xn is said to be compatible with a digraph D = (V, E) (of ordern)if FhastheformF(*i, ...,*„)= (/i(*i,..., *„),..., / n (*i,..., *„)) ((jci,..., xn) X"), and f,• : Xn X, i = 1,..., n may depend only on ,- and those Xj for which (vj, vi,) E (including the case u,- = vi;). If F is compatible withD>, then sometimes we also say that F isD-compatible. Given an automaton A = (A, X, 8), let A = AI x • • • x An for some |A ( | > 1 and n 1 (where | A, | denotes the cardinality, i.e., the number of elements in A,). Then we say that A is a finite automata network of size n. Then the underlying graph DA — (Va EA) of A is defined by VA = {1,..., n}, EA = {(/, ;') | there exists x e X : cpj( really depends on its ith variable}. A is a D-network if D = (V, E) is a digraph with V = V> and E . In other words, A is a D-network if every mapping : A A (x X) is compatible with X . Note that a size n automata network may be regarded as comprising n component automata Ai — (A,, AI x • • • x An x X, ), {!,..., n}, where the are defined by for a = (Ai,..., an) A, a, € A,, :c € X. One may of course suppress the components of A = AI x • • • x An in the inputs to At on which does not really depend. Let Ai = (A,, Xf, ) be automata where i {!,...,«}, n > 1. Take a finite nonvoid set X and a feedback function Xf for every / {!,..., n}. The general product13 (or Gluskov-type product) of the automata Ai, with respect to the feedback functions 3, (i € {1,...,«}) is defined to be the automaton A = A\ x • • • x 13 A natural extension of this concept is the so-called generalized product introduced by F. G6cseg (see also later in this monograph), when the feedback components map into the input monoids of the component automata. Several generalized product families, derived from the Gecseg-type generalization, have also been defined.

2.4. Automata Networks and Products of Automata

59

An(X, („)) with state set A = AI x • • • x An, input set X, transition function 8 given by 8((ai,..., a n ), x) = (<5i(ai,
GENERAL PRODUCT

We shall use the feedback functions

where

, in an extended sense as mappings ana

In what follows,

bv

will also be denoted

We can imagine this structure as a working model in the following way. The product is a collection of automata such that every member of this collection is supplied with a transformer which is a special type of an automaton. The transformers, realizing the feedback functions mentioned above, are able to get an input vector containing a common external input sign and the state of all component automata. They can each transform this input vector into an appropriate input sign for their component automaton. The product is at work along a discrete time scale in the following way: all transformers of the product get a common external input sign x, and, simultaneously, all transformers get the value of the instantaneous states a\,..., an of all component-automata as input information. By the effect of this input vector (a\,..., an, x), the transformers produce an input sign xt =
Note that a single-factor product is different from its factor in general.

60

Chapter 2. Directed Graphs, Automata, and Automata Networks We shall use the following statement.

Proposition 2.50. Let

be a product of automata , and consider a permutation P over ( 1 , . . . , n]. Define the product and, moreover, for any state such that and input letter Then A is isomorphic to A'.

It is obvious that A is a finite automata network if X,? = A\ x • • • x An x X and X\, $2 : A\ x X -> Xi,... , Xn.15 If i is a positive integer for which every pt (t = ! , . . . , « ) really depends on not more than i state variables, then A is a v, -product. In addition, an a, — Vj-product (i = 0 , 1 , . . . , j = 1, 2 , . . . ) is an a,-product that is also a v,-product.

PRODUCT

15

Feedback from a factor to itself is considered to be of length 1. Thus, in a sequence of automata, feedback of length 2 is understood to be to the preceding factor.

2.4. Automata Networks and Products of Automata

•PRODUCT

-PRODUCT

V]-PRODUCT

V2-PRODUCT

61

62

Chapter 2. Directed Graphs, Automata, and Automata Networks

V3-PRODUCT

There is a close relationship between the ao-product of automata and the wreath product of transformation semigroups. If we have an ao-product as above, then consider the wreath product of the transformation semigroups of the At, (An, S(An)) * • • • i (A\, S(.Ai)); viewing this as an automaton, we see that the ao-product embeds into it under (a\,..., an) M» (an,..., a\} and x h> (/„,..., f\), where f\ e S(A\) is defined by /i = 0$i)*i using xi = (p\(x), and, similarly for i > ! , / } : A,_i x • • • x AI -> S(Ai) is defined by /)(a ( _i,... ,a\) = ( )Xi, using z = — (V, E) be a digraph with V = [ I , . . . , n] and, for every v e V, let Av = (Av, Xv, ) be an automaton. A general product A = AI x • • • x An(X, pi,..., n)) is a T)-product if each feedback function < (v V) is really independent of its uth (u V) state variable whenever (u, v) E. If A is a nonempty class of digraphs and T> A, then it is also said that A is a ^-product. (In what follows, by a class A of digraphs we always mean that A is a nonempty class.) Thus, if A is the class of all digraphs having neither cycles nor loop edges, then the -product is just the loop-free product, which is further equivalent to the cascade product or, by another name, the ao-product. If A consists of the cycles, then we obtain the concept of loop product. (Of course, if all factors are the same, then we speak about appropriate types of powers.) If A is the class of all digraphs having no edges, then the -product is called a parallel product or a quasi-direct product, or, in short, a q -product. In other words, we define the underlying graph T> = (V, E) (V = { I , . . . ,n}, E V x V) of A such that (i, j) € E if and only if the feedback function J really depends on its /th-state variable. Thus, an underlying graph is a digraph which may contain loop edges. We will use the following two facts throughout this monograph.

2.4. Automata Networks and Products of Automata

63

Proposition 2.52. Given a digraph D, suppose that an automaton A can be represented homomorphically (isomorphically) by a D-product of automata At,t = !,...,«. Then there exists a D-product of automata At, t = 1,..., n, having a state-subautomaton which can be mapped state-homomorphically (state-isomorphically) onto A. Proof. Let = (V''!' ), V^: B A,ijf2 : XB X be a homomorphism (an isomorphism) of a subautomaton B = (B, X SB) of the X -product = A\ x • • • x An(X', -product B\ x • • • x Bn(( ,..., 'n, X) in the following manner. For every t = , . . . , « , consider a fixed element dt of B't and define the mapping : Bt At such that

Moreover, let pt denote an ordering on X't. In addition, define (bi,... ,bn,x) = x' such that x' X't is the minimal input sign (with respect to pt) having t,2(x') = x" with ( (ri(bi),...,Tn(bn),x) =x". First we prove that B\ x • • • x Bn(( {,..., ( n, X) is a D-product. Consider t {1,...,«} and let { , t),..., (tm, t)} = E n {1,...,«} x {t}, where E denotes the set of edges of D. Then for every t {1,..., n}, (b\,..., bn) 6 B\ x • • • x Bn, x e X,
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Chapter 2. Directed Graphs, Automata, and Automata Networks

let

For every such that. with

defined bv ive have and is the minimal input sign (with respect to pt) having This means that

Therefore, is a state-homomorphism (state-isomorphism) of a state-subautomaton of the D-product onto A. Ihe proot is complete. We have the following direct consequence of the above statement. Proposition 2.54. Consider a class K. of automata and two classes A, A of digraphs having the property that every -product of .-products of automata from 1C is also a A-product of automata from K. Suppose that an automaton A can be represented homomorphically (isomorphically) by a A-product of automata Ai,... ,An, and assume that for every t = 1,..., n, At can be represented homomorphically (isomorphically) by a Aproduct ofautomata from K. Then A can be represented homomorphically (isomorphically) by a A-product of automata from K.. Here and throughout this monograph, if we are dealing with a class K. of automata, we always assume that k is nonvoid. A class of automata is called complete with respect to homomorphic (isomorphic) simulations under the given type 0 of products if every automaton can be simulated homomorphically (isomorphically) by a product of automata inK. K is called finite if it has a finite number of elements. Furthermore, it is said that /C is minimal if for every A K, k \ A is not a complete class of automata with respect to homomorphic (isomorphic) simulations under the 0-product. The complete (finite complete, minimal complete) classes of automata with respect to homomorphic (isomorphic) simulations by nonempty words are analogously defined. The next statement is clear. Proposition 2.55. Given a digraph D, let M = A\ x • • • x An(X, i,..., < ) be a product of automata A\,..., An such that M. homomorphically (isomorphically) simulates an automaton A by some mappings : B A, 12 : Y • X*. Then there exists a D-product M' = AI x • • • x An(X', (,..., • A, T2 : Y -» X'* having the following properties: \T2(y)\ = ^(y)!,}? e Y; moreover, for every positive integer k, I and ji, y2 € F, the kth letter ofr^yi) and the tth letter of 2) coincide only ifk = t andy\ = Y2Given a digraph D = (V,E), letDl = (V, E') be a digraph with E' = EU{(i, i) \i € V}. Similarly, if is a (nonempty) class of digraphs, then we put = {Dl \ D A). Thus, £ for every digraph D, a D -product of automata is a general product having an underlying graph Dl. Similarly, if M is a Dlproduct of automata and D A holds for a class of

2.4. Automata Networks and Products of Automata digraphs, then M is also said to be -product. In this sense we will speak about product, -product, product, etc. The following statement is obvious.

65 -

Proposition 2.56. Given a digraph D, an automaton is a Dl -product of automata At, t = 1,..., n, if and only if it is a TJ-product of products At(Xt, 0, then the af-product coincides with the a, -product. Proposition 2.61. Every ql-product is a v\-product. Furthermore, every vf-product is a vi+i-product. Proposition 2.62. Given a cycle digraph T> with V = ({1,..., m}, {(1, m), (2,1), (3, 2), ..., (m, m — 1)}), let M be a T^-product of automata. Then M also is an a.i-product of its factors. Proposition 2.63. Suppose that the automaton M. is an oiQ-product of factors M.\ and M.2, where MI is an a, -product ofAi,...,Am (having m factors for a given positive integer m); moreover, M.I is an aj-Vk-product (aj-v^-product) of Am+i,..., An. Then M. is an oimsx.(i,jrvm+k-product (am^ajyv^-product) ofA\ ,...,An Proposition 2.64. Suppose that an automaton A can be represented homomorphically by a general product ofnilpotent automata. Then A is a nilpotent automaton. Proposition 2.65. Given a monotone automaton A suppose that B is a single factor general product of A Then B is a monotone automaton.

66

Chapter 2. Directed Graphs, Automata, and Automata Networks Next we prove the following.

Proposition 2.66. Let be a product of automata having an underlying graph = ({1, ...,»},£), vertices with such that ( suppose that for any pair implies Then there exists a product having the underlying graph with nodes and edges such that for any

whenever

Proof. By the condition on edges, components. MX any arbitrary functions:

do not depend on their (i + l)th,..., nth-state We construct the following feedback

where It is easy to check that the product A' having the above feedback function components satisfies the required conditions. Corollary 2.67. Every cascade of automata can be isomorphically represented by a cascade of (copies of the same) automata such that for each i, at most one feedback function
2.4. Automata Networks and Products of Automata

67

Theorem 2.68 (Gluskov decomposition theorem). A class 1C of automata is complete with respect to isomorphic representations under the general product if and only if there exists an automaton A = (A,X,8) in K. which has input letters x\, X2, x^, X4 € X and distinct states ao,a A such that <S(0o>*i) = oo ( ,X2) = a,8(a,X3) = a, and 8(a,X4) = hold.

GLU§KOV CRITERION be a product Proof. For the proof of necessity, let such that a subautomaton of B has an isoof automata ana inmorphism onto A. For appropriate states put letters let Let with Because of there exists and . Thus t has the Then conditions 01 necessity. can be represented Conversely, prove that an arbitrary automaton isomorohicalry bv a power or A. Using the transitive property of isomorphic representation, without loss of generality Define the functions we mav assume that such that for every whenever implies Clearly, then the power isomorphically represents M, where the appropriate isomorphism is having and The proof is complete. Note that in the proof of sufficiency of the above theorem, the automaton M. can also be represented by a power of A having k > Iog2 n factors. (We leave to the reader the proof of this statement.) For homomorphic representations by automata networks, the minimal computational elements required to achieve an arbitrary finite state computation are characterized in the Letichevsky decomposition theorem by a simple criterion. Necessity of the criterion will be shown in Proposition 2.71. Although giving a proof of sufficiency is not difficult, we delay this until the end of Chapter 5. There two proofs of sufficiency are derived from much stronger independently proved results (e.g., Theorem 5.26). Theorem 2.69 (Letichevsky decomposition theorem). A class K, of automata is complete with respect to homomorphic representations under the general product if and only if there

68

Chapter 2. Directed Graphs, Automata, and Automata Networks

exists an automaton A= (A, X, 8) which has a state a € A, two input letters x,y and two input words p, q € X , under which

X,

It is said that an automaton A satisfies Letichevsky's criterion if it has the above property (*). If A = (A, X, 8) does not satisfy Letichevsky's criterion but we have

LETICHEVSKY CRITERION 8(ao, x) 5(0o. y), and (« *P) = « f o r some o G A, jc, y X, and /? X*, then A satisfies the semi-Letichevsky criterion. Otherwise we say that A does not satisfy any Letichevsky criteria or is without Letichevsky criteria. Proposition 2.70. Let there be given an automaton A = (A, X, 5), a state O A, four input words u, v, p,q € X* with \p\ = \q\ under which (ao, u) ^ 8( ao, v), and8(ao, up) = 8(ao, vq) = a$. Then A satisfies Letichevsky's criterion. Proof. We shall use the following simple fact. Assume that there are w\, W2, w(, w'2 e X*, x,y e X w\xw2, w(yw'2 € {up, vq} such that 8(ao, w\) = 8(ao, w(), 8(ao, w\x) ^ 8(ao, w(y). Then we obtain Letichevsky's criterion by setting ao, u, v, p, q to 8(ao, w\)(= 8(ao, w()), x, y, W2U)\, w2wi, respectively. Therefore, it remains to study the case when for every w\, W2, w{, w'2 e X*, x, y e X with w\xw2, w[yw'2 € {up, vq} and5(oo, ^i) = 8(ao, w'i), it holds that 8(ao, w\x) = 8(ao, w(y}. In this case, there are x\,.. .xn € X having u = xi • • • x,,, p = xi+i •••XH(XI--- xny, v = xi • • • x},, q = xj+i • • • xn(xi • • • xn)1 for appropriate s, t 0. But (ao, ) (a ,v) implies i j. Hence \p\ ^ \q\, a contradiction. D If a class 1C of automata contains an automaton satisfying Letichevsky's criterion, then we also say that /C satisfies Letichevsky's criterion. Otherwise, we say that /C does not satisfy it. If K does not satisfy Letichevsky's criterion but there exists A fC such that A satisfies the semi-Letichevsky criterion, then it is also said that 1C satisfies the semiLetichevsky criterion. Otherwise, we also say that 1C does not satisfy Letichevsky criteria or 15 without any Letichevsky criteria. As already mentioned, necessity of the Letichevsky criterion in proving the Letichevsky decomposition theorem follows by the next statement. Proposition 2.71. Suppose that a product of automata satisfies Letichevsky's criterion. Then it has a factor with this property.

2.4. Automata Networks and Products of Automata

69

SEMI-LETICHEVSKY CRITERION

WITHOUT LETICHEVSKY CRITERIA Proof. Let

) be a product of automata Suppose that A satisfies Letichevsky's criterion. Then there are a state such that , input letters input words and,

simultaneously,

. But then there are

and simultaneously,

with

such that and, But then At has Letichevsky s criterion.

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Chapter 2. Directed Graphs, Automata, and Automata Networks

Proposition 2.72. Suppose that a product of automata satisfies the semi-Letichevsky criterion. Then it has either a factor with Letichevsky's criterion or a factor with the semiLetichevsky criterion. Proof. Let A = A1 x • • • xAn(X, ,..., (pn) be a product of automata At — (At, Xt, t), t = 1 , . . . , n . Suppose that A satisfies the semi-Letichevsky criterion. Then there are a state ( a 1 , . . . , an e A1 x • • • x An, input letters x, y e X, input words p, q e X* such that ( 1 (a 1 , 1 (a 1 , ...,a n ,*)),... , n(an, p n (a 1 , ...,an, x ) ) ) ( a 1 , (a 1 , ...,an,y)),..., (an, n ( a 1 , . . . , a n , y ) ) ) , and, simultaneously, ( 1 (a 1 , 1 (a 1 ,..., an, xp)) ,..., n(an, n ( a 1 , . . . ,an, xp))) = ( a 1 , . . . , an). But then there are t e {1,...,n}, x t =

9) wim (at, ytqt) = at because then At has either Letichevsky's criterion or the semi-Letichevsky criterion. The next two observations show that a statement analogous to Proposition 2.71 does not hold for the semi-Letichevsky criterion. Proposition 2.73. There exists an automaton having Letichevsky criterion such that it has a single-factor product satisfying the semi-Letichevsky criterion. Proof. Let A = ({0,1, 2}, {x0, x1, x2], 8) be defined by 5(0, xi) = i, (1, xi) = 0, 5(2, xi) = 2, i = 0, 1, 2. Let .A({x, y), p) be given with p(i, x) = x1, p(i, y) = x2, i = 0, 1, 2. Then (0, (0, x)) = 0, (0, p ( 0 , y)) = 2, 5(2, p(2, x)) = 5 ( 2 , ( 2 , y ) ) = 2, and 5(1, (1, x)) = 5(1, (l, y)) = 0. It is easy to check that A satisfies Letichevsky's criterion, but the product A({x, y}, 2, we obtain (i,
2.5. Bibliographical Remarks

71

criterions or the semi-Letichevsky criterion, which is a contradiction. Therefore, the considered product is without Letichevsky criteria. Proposition 2.76. Let A be an arbitrary noncommutative strongly connected automaton. Suppose that an automaton B homomorphically simulates A. Then B satisfies Letichevsky's criterion. Proof. Consider a noncommutative strongly connected automaton A = (A, X, ). Suppose that A can be simulated homomorphically by an automaton B = (B, , SB) under T\ : B' A, TI : X XB*. Suppose that B' is minimal such that it has no proper subset B" for which B homomorphically simulates A under some ( : B" A, : X ->• XB*. Then, by the strong connectivity of A, for every b\, bi B' there exist x\,... ,Xk € X with . In addition, because 01 the noncommutativity 01 A, there are a state and input words having Consider the natural extension with Then tor every In addition, by the minimality or B , there exist words with On the other hand. implies that Indeed leads esultmg in a contradiction. Therefore, there are such that and, moreover, Let and Obviously, then The proof is complete.

2.5

Bibliographical Remarks

Section 2.1. Extensive treatment of graph theory is given by F. Harary [1969]. Theorem 2.1 is from K. Kuratowski [1930]. A nice presentation of this result was developed by G. A. Dirac and S. Schuster [1954], Theorem 2.2 was found by G. Chartrand and F. Harary [1967]. Lemmas 2.6,2.7,2.8,2.9, and 2.10, Theorem 2.11, Proposition 2.13, and Theorems 2.15 and 2.16 can be found in Ananichev, Domosi, and Nehaniv [in press]. Lemmas 2.8 and 2.9 can also be derived from Z. Esik [1989b]. The concept of digraph completeness is from Z. Esik [1991a]. Corollaries 2.19 and 2.20 are in Esik [1991a]. The other parts of this section are essentially new. Section 2.2. Many books have given accounts of various aspects of the algebraic theory of automata—for example, Bavel [1983], Eilenberg [1974], Gecseg and Peak [1972], Gecseg [1986], Ginzburg [1968], Hartmanis and Steams [1966], Holcombe [1982], Nelson [1968], Salomaa [1969], and Simon [1999]. The concept of automaton mapping is given and intensively studied in Raney [ 195 8] and Horejs [ 1963]. The generating systems of semigroups and groups of automaton mappings are intensively studied in Csakany and Gecseg [1965], Gecseg [1965], and Zarovnyi [1965]. Theorem 2.30 is due to S. V. Alesin [1970a] and P. Domosi [1972]. (In the present book a new and simpler proof of this statement has been produced.) S. V. Alesin [1970b] stated that the answer to Problem 2.31 is in the affirmative. But, unfortunately, there is a gap in the proof of his Lemma 3, and so the validity of

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Chapter 2. Directed Graphs, Automata, and Automata Networks

his results may be questionable. (See also Csakany, Mathematical Reviews 45 1687.) The other results are new but elementary. Section2.3. Proposition 2.34 issued from Eilenberg[l 974]. Proposition 2.47 is new. Proposition 2.49 was proved by Z. Esik [199la]. All the other statements are folklore. Section 2.4. Investigation of finite automata networks goes back to W. S. McCulloch and W. Pitts [1943], J. von Neumann [1966], E. F. Codd [1968], M. Minsky and S. Papert [1969], A. W. Burks [1970], and C. Choffrut [1986]. An extensive algebraic treatment of automata networks was given by M. Tchuente [1979,1982,1983,1985,1986] and by F. Fogelman-Soulie, Y. Robert, and M. Tchuente [1987]. Structural and behavioral equivalence relations in automata networks were studied by T. Saito and H. Nishio [1989]. A verification tool for distributed systems using reduction of finite automata networks was described by E. Madelaine and D. Vergamini [1989]. Finite (and infinite) automata systems as parallel communicating finite (and infinite) automata networks were intensively investigated by Z. Fiilop [1991], C. Martin-Vide and Gh. PSun [1999], C. Martin-Vide and V. Mitrana [2000, 2001], C. Martin-Vide, A. Mateescu, and V. Mitrana [2002], and I. Babcs&ryi and A. Nagy [2004]. Product and completeness of automata were intensively investigated by F. Gecseg and I. Pea* [1972], S. Eilenberg [1974,1976], J. Dassow [1981], and F. Gecseg [1986]. The concept of the Gluskov-type product is introduced by V. M. Gluskov [1961]. Several specialized types of the Glu§kov-type product were defined. The concepts of Dproduct and A-product were proposed by Z. Esik [1991b]. The quasi-direct product was given by F. Gecseg and I. Peak [1972]. The cascade product is from M. Yoeli [1961]. The loop product was defined by Z. Esik [1987a]. The family of a,-products was introduced and intensively studied by F. Gecseg [1974,1976a, 1986]. The family of v,-products is due to P. Domosi and B. Imreh [1989]. The family of a,-v,-products was given by F. G6cseg and H. Jiirgensen [1991]. Products of automata with identity are from Z. Esik and J. Viragh [1986]. Theorem 2.68 was proved by V. M. GluSkov [1961]. Theorem 2.69 can be found in Letichevsky [1961]. The proof of Proposition 2.76 is new.

Chapter 3

Krohn-RhodesTheory and Complete Classes

While the fundamental information concerning complete classes with respect to homomorphic representations under the general (Gluskov-type) product is concentrated in the celebrated classical criterion of A. A. Letichevsky, the well-known Krohn-Rhodes decomposition theorem is the basis for studying the cascade product of automata. The cascade product of automata is a general model of automata networks without feedback, and the theorem describes how to synthesize any finite state automaton using such a cascade, and, moreover, it describes the necessary irreducible components in detail. We shall derive the Krohn-Rhodes decomposition theorem from a sophisticated result called the holonomy decomposition theorem, which generally yields much more efficient decompositions than in the original proofs of the former. Characterization ofhomomorphic representation is important since one of the major tools for representations is homomorphism. While it is not too general, it is powerful enough. We study homomorphic representation in networks of automata with no feedback (cascade and quasi-direct products) and with low bounds on feedback length (a -products for i 2) here.

3.1

Krohn-Rhodes and Holonomy Decomposition Theorems

Theorem 3.1 (Krohn-Rhodes decomposition theorem). Given a finite automaton A, let F be the flip-flop monoid (the smallest monoid with two right-zero elements); moreover, let GI, ... ,Gn denote all simple groups that divide the characteristic semigroup S(A). Then A can be represented homomorphically by a cascade product of components from {Af, Ad, • • •, Acn }• Moreover, if A is a nontrivial permutation automaton, then the factor AF may be excluded. Conversely, let i be a cascade product of automata which homomorphically represents the automaton A. If a subsemigroup S of the flip-flop monoid or a simple group S is a homomorphic image of a subsemigroup of S(A), then S is a homomorphic image of a subsemigroup of S(Bt) for some component automaton Bt (t € {1,..., n}). In addition, a subsemigroup S of'the monoid¥with two right-zero elements 73

74

Chapter 3. Krohn-Rhodes Theory and Complete Classes

can be embedded isomorphically into a finite semigroup T whenever T has a subsemigroup that can be mapped homomorphically onto S. Irreducibility. A finite semigroup S is irreducible if whenever S divides a wreath product of finite transformation semigroups (x2, s2) (X\, S\), then S divides s2 or S divides S\. Equivalently, if 5 divides the cascade product of finite automata A and B, then either S < A or S < B. Or again, equivalently, "S is irreducible" means that if S divides the -product of finite automata, then it divides one of the factors. For any finite automaton A, let PRIMES(A) denote the set of simple groups that divide S(A). This notation also applies to transformation semigroups viewed as automata. We will derive Theorem 3.1 from the following, for whose proof we shall rely on the holonomy decomposition theorem and a series of lemmas. Theorem 3.2. (Krohn-Rhodes prime decomposition theorem for transformation semigroups). Let (A, S) be a finite transformation semigroup. Then (A, S) divides a wreath product of transformation monoids (M,-, M/) such that each M, 6 PRIMES(S) or M{ is the flip-flop monoid. In the case that (A, S) is a permutation group, then the flip-flop monoid is not required and the division can be chosen to be an embedding. Conversely, for every wreath product of finite transformation semigroups (Bi, si,) which (A, S) divides, we have that G PRIMES(S) implies that G divides si, for some i. Moreover, if M is any divisor of the flip-flop monoid which divides S, then M embeds into some 5,. The subsemigroups of flip-flop monoid F are the monoid F with two-right-zero elements itself, the two-element monoid with zero elements, the semigroup with two right-zero elements, and the trivial monoid. It is clear that any divisor of F is actually isomorphic to one of these. Thus the second part of this theorem characterizes the irreducible finite semigroups as the finite simple groups and the subsemigroups of the flip-flop monoid. We will say that the class JC of automata satisfies Krohn and Rhodes' criterion if for every finite simple group S there is an automaton A tC having that 5 is a homomorphic image of a subsemigroup of S(A), and, moreover, following the last part of the KrohnRhodes decomposition theorem, a class K, satisfying the Krohn-Rhodes criterion, must contain an automaton A such that a subsemigroup of S(A) is isomorphic to the monoid F with two right-zero elements. These two forms of the Krohn-Rhodes theorem yield an immediate corollary. Corollary 3.3. A finite transformation semigroup (resp., finite automaton) divides the wreath product (resp., cascade product) of flip-flops if and only if it has no nontrivial group divisors, or, equivalently, if and only if it has no simple group divisors. Such transformation semigroups (resp., automata) all of whose group divisors are trivial are called aperiodic, and the result shows that they can be represented homomorphically by cascades of flip-flops (resp., divide a wreath product of flip-flops). We begin with last part of Theorem 3.2.

3.1. Krohn-Rhodes and Holonomy Decomposition Theorems

75

Lemma 3.4. If S is a subsemigroup of the flip-flop monoid F and S divides a finite semigroup T, then S is isomorphic to a subsemigroup ofT. Proof.

with identity e and xy = y for any We have Take such that maps them to e, I, and r, respectively. By replacing e by its unique idempotent power and r and by the unique idempotent powers of ere and ete, we may assume that ere = r and ele = 1. Let f = (lr)m be the unique idempotent power of Let be the unique idempotent power of fl. Then and and

Clearly ana and g are distinct. Thus {e, /, g} makes up a subsemigroup of T isomorphic to F. Simplifications of this proof establish the result for the other subsemigroups of F. Next we do some work toward establishing which semigroups are irreducible. Lemma 3.5. The flip-flop monoid F and all its subsemigroups are irreducible. Proof. Suppose F divides a wreath product of transformation semigroups (X x Y, W) = (X, S) z (Y, T); then by the above lemma F W. Let (E, e) be the identity and (L, 1} and (R, r) be the two right-zeros in the embedded copy of the flip-flop. Case 1. r t. Since (R, r)(L,£) = (L, ), we have rt = l and, similarly, re = r, whence t cannot equal e. Similarly one shows r cannot equal e. Thus e, r, l T are pairwise distinct, so the projection from W to T is injective on the embedded copy of F. Thus F embeds in T. Case 2. r = t. We examine the right coordinates of the embedded flip-flop monoid. We have E,R,L : Y S. Since (L, l) and (R, r) = (R, t) are right-zeros in the embedded copy, for all y e Y, L(y)L(y • I) = L(y), R(y)R(y • t) = R(y), L(y)R(y • I) = R(y), R(y)L(y • t) = L(y). Similarly, since (E, e) is the identity in this copy of F, also E(y)F(y • e) = F(y) and F(y)E(y • e) = F(y) for each F e {E, L, R}, y € Y. Since r = t, R cannot equal L, so there exists a yo e Y with R(yo) =£ L(yo). We have R(yo)R(yo ' I) = R(yo) and R(y0)L(yQ • t) = L(JO), whence R(y0 - £) ^ L(y0 • t). Let yi = yo -1. Since te = t — et, we have y\ • e = y\ = y\ • t. Thus, the above equations applied to y = yi show that (L(yi), R(yi), £(ji)} has the multiplication table of F. We already know that L(yO /= R(yi), so L(yi)E(yi) = L(yi) andL(yi)R(yi) — R(y\) imply E(yi) ^ R(y\). Similarly E(y\) ^ L(y\). Thus we have an embedded copy of F in S. The proofs of irreducibility of other subsemigroups of F are simplifications of this one. Lemma 3.6. A nontrivial finite group is irreducible if and only if it is a simple group. Proof. Let G be a nontrivial finite group. If a group G is not simple, then it has a proper normal subgroup N, so by Lemma 1.16 G is not irreducible. Conversely, if G is a simple group and G divides (X, 5) = (^2, 52) 2 ( X i , Si) for some finite transformation semigroups (Xi, Si) (i = 1, 2), then by Proposition 1.11 there exists a permutation group (Z, G) with Z c Xi x X\ and subgroup G of S mapping homomorphically onto G.

76

Chapters. Krohn-Rhodes Theory and Complete Classes

Consider the projection homomorphism TT\ from S to S\ restricted to G. Let N = ker n\. Let lg = (i,e) denote the identity of G. Clearly, e2 = e Si. Define a homomorphism : ker i -+ ' = x ••• x (\ \ times) by \jr(h, e ) f a ) = hfa • e) for all xi e XL (This defines each jci-coordinate of the |Xi (-tuple.) Of course ty(h, e) can be considered a function from X\ to Si. Now, given (h, e), (hf, e) e N = ker n\, if \j/(h, e) = i/r(h', e), then for all fa,x\) e X2 x X\ we have (xi,x\) • (h, e) = (x2,x\) • (i,e)(h,e) = (x2 • ifa)hfa • e),xi • e) = fa • ifa)h'fa • e),x\ • e) = fa,x\) • (i,e)(h',e) = (x2,x\) • (h',e), whence (h,e) = (h',e), and so ^ is injective. We also have, for each *i € Xi, ir((h,e)(h',e))fa) = hfa • e)h'fa • e • e) = hfa • e)h'fa • e) = (ty(h, e)(xi))(ifr(h', e ) f a ) ) . Thus iff is an injective homomorphism on N. Thus G/N is isomorphic to the subgroup n\ (G) of Si and N is isomorphic to the subgroup ty (N) of S*1. Therefore every Jordan-Holder factor of G occurs as a Jordan-Holder factor of G/N or of N, then hence divides G/N or N, and hence divides S\ or S*1. But since = G 1 is simple, G is a Jordan-Holder factor of G. This proves G divides S* or Si. In the latter case, we are done. In the former case, G divides S = S2 x • • • x S2. Take H a subgroup of the direct product mapping onto G, say, r] : H G, and let HI denote the subsemigroup of S2 consisting of those elements s, of S2 such that s, occurs as the ith component of some element of H. Consider the homomorphisms pt : H, G given by Pi(si) = r / ( l , . . . , 1, Sj, 1,..., 1), si HJ-, 1 in each coordinate j i denotes the idempotent of S2 occurring in that position in the identity element of the group H. Let k = \Xi\. Then TJ(SI, ..., sjO = PI(SI) • • • Pk(sk) for all (s\,..., Sk) € H, and since the Pi(Si)Pj(sj) = Pj(sj)pi(si) (si € Hi,Sj e Hj) always holds for / / j, it follows that 77(51,..., s k ) p i ( s f ) r i ( s \ , . . . , sk)~l = Pi(si)pi(s-)pi(si)-1 e pi(H{). Thus each /?,(#/) is a normal subgroup of G. Since G is not trivial and n is surjective, these subgroups cannot all be trivial. Therefore by simplicity of G there is an / such that pi(Hj) = G, whence G divides S2. This proves that G is irreducible. Lemma 3.7. If (X, G) is a permutation-reset transformation semigroup, then (X, G) <(X,{U})KG,G). Proof. Recall that (X, {I*}) has a semigroup consisting of the identity permutation 1* and all constant maps cx : X • X, with cx(x'} = x for all x' e X. Define TJS : X x G -» X by (x, g) t-+ x • g. For g e G c G, define g by fa, gi) • g = fa • lx, gi • g) = fa, gig)- For cx € G, define cx by fa, gi) • cx = fa • cx.g-i,gi • 1) = (x • gf 1 , gi). Then ^((*i, gi) • I) = x\ • gig = Vfa, gi) • g, and ^(fa, gi) • cx) = ir(x • gf 1 , gO = x ' g^gi = x = i/ffa, gi) • cx. This proves the lemma. D Lemma 3.8. If (X, { l x } ) is a finite transformation semigroup with transformations consisting of the identity transformation and all constant maps on X, then (X, {lx}) embeds into the direct product of copies of the flip-flop. Proof. Let A = {0,1}; then the flip-flop is (A, {1A}). Let n be such that 2n > |X|. Let / : X -» A" be any injective function. Let // : X ->• A be the /th component of /. Let x' € X and s € {lx}- Then s = cx for some x e X, or s = \x- Let ^(cx) = (c/^),..., c/n(X)) and ^(Ix) = (!A» • • • > IA)- Then ty is an injective homomorphism.

3.1. Krohn-Rhodes and Holonomy Decomposition Theorems We have

77

On the other hand, This establishes the

embedding. Holonomy. We introduce the holonomy groups and related notions. First, fix a finite transformation semigroup (A, 5). The holonomy decomposition theorem (Theorem 3.9), from which we shall derive the Krohn-Rhodes prime decomposition theorem, is proved by a detailed study of how 5 acts on subsets of A. Recall that if q A and s € S, then

In this section, we write A, for the identity Let acts on Q as just described. transformation on A. Then clearlv We have a reflexive and transitive relation on Q given by there exists Consequently, we have an equivalence relation on Q,

and Observe that choose a unique representative For each equivalence class in then tor appropriate always holds, since whence and implying we have Thus, the set of representatives of the Bv svmmetrv. it follows that but not if is partially ordered by We also write equivalence classes and We say p is a tile of q and write Thus, is The set of tiles of q for any for all i implies equals Since Q contains the singletons, for denoted by the union of its tiles, Define Hq to be the set of permutations of Bq induced by elements of s Sx. That is, if for s € S\ the function sq : Q Q defined by sq(z) = z • s = {a • s \ a € z] (z € Q) restricts to sq : Bq Bq and permutes the elements of Bq, then sq Hq. Hq is called the holonomy group ofq in (A, 5), and clearly Hq divides S,16 and (Bq, Hq)isa permutation group called the holonomy permutation group of q. then we can wnte and Suppose and Since q is finite, then we claim for some Let This shows that s permutes implies Suppose Let ; we have and so the elements with be such that is the identity permutation on q, and let Let , we have Then Since 16 In the exceptional case Hq = [ q], we have that division of 5 is guaranteed since 5 contains an idempotent. In all other cases, the identity transformation on Bq is, of course, represented by the idempotent power of any nontrivial sq Hq,so that Hq is a quotient of the subsemigroup of 5 consisting of those elements s for which sq permutes Bq.

78

Chapter 3. Krohn-Rhodes Theory and Complete Classes

and. since z is a tile of a. it follows that We have or This proves if z is a tile of a, then z • s is also whence a tile of q. Moreover, if and , then Since Bq is finite, this proves s permutes the elements of Bq. Thus sq Hq as claimed. Furthermore, q = p implies that, say, (Bq, Hq) is isomorphic to (Bp, Hp). We saw s = uq>pvq>p permutes the elements of q and, similarly, vqtpuqtp permutes those of p. Take n > 1 such that (uq,pvqtp)n is the identity permutation of q. Letuq,p = vq,p(uq,pvq z • uq,p e Bp is bijective with inverse z' *-> z' • uq,p. For sq e Hq, the map sq i->> Uq,psqUqtp € Hp is an isomorphism of groups with (z-uq,p)-uq,psquq,p = (z-Sq)'Uqtp. Hence, we have an isomorphism of permutation groups. Now for each q let uq = uq 1 and p p'. s, then actually p' is equivalent to p: ifh(p) = i, we have qo < •• • < qi = p < p', and so by h(p') = i the last inequality cannot be strict, i.e., p = p'. Clearly, for each i with 0 / h, Q contains at least one element having height i. For each i (1 < i < h), define (#,-, %•) to be the direct product of the holonomy permutation groups of the height i representatives in Q. Then #, = fl/tcp)^ Bj an^ Hi = Y[h(j)=i HP- Then (#/»%•) is a permutation group and (#,, 'H,) is the associated holonomy permutation-reset transformation semigroup obtained by adjoining all constant maps taking values in #,. Denote elements of #, by boldface variables b or b/. and so

Notation. Suppose that b is a tile of some p Q with height i and the p represents its equivalence class. That is, b - p and p = JJ. Then we denote by [b]p any arbitrary element of fy containing tile b in the p-position. Also, if g € Hp, then we write [g]p for any arbitrary element of , containing g in the ^-position and identity elements in all other positions. Observe that BH = BA and / Hh = HA since A is the only set of height h. Thus b/, = [bh]A =J h for all tiles bh of A and [g]A = g for all permutations g in the holonomy group of A = A. Theorem 3.9 (holonomy decomposition theorem). Let (A, S) be a finite transformation semigroup; then (A, 5) divides a wreath product of its holonomy permutation-reset transformation semigroups (B\, Hi)l"'l (Bh, 'Hh)-

3.1. Krohn-Rhodes and Holonomy Decomposition Theorems Proof. Let * be a new symbol and define goes from h to 1 by and, letting

79 inductively as i

, which we suppose has already been well defined for we define

(It is understood that the last case will apply also if /? = *.) Observe that in the second case is the representative of the equivalence class of p, and so and in fact Observe that if .Thus is not then is eithe or a singleton. If then can have no effect on the value of in the above definition. If h(p) = i, then only the -position of b, may affect the value of ni. In all cases at most one position of b, can affect the value of n(. Let * be the set of (bi,..., b/J such that ni(bi,..., b/,) is a singleton. The 17,-'s will give our covering map n by "successive approximation." Indeed, an easy induction establishes that for every Let be the unique element of the singleton be given by letting We show that

is a surjective function: given an arbitrary a € A, we choose Now assuming containing a. Then a and are defined and we proceed with by induction for and let

In the case h(p) < i, existence of elements of height i in Q guarantees that an arbitrary fixed b* exists. In the case h(p) = i, since i > 0 the fact that p is the union of its tiles guarantees the existence of a tile b' of p containing a, so b may be taken to be b' • up. It is clear that a e ni, (b,,..., b/,) and h(^ (b,,..., b/,)) < i since either (1) h(p) < i, and so ?/,-(b,-,..., b/,) = p which contains a, or (2) h(p) = i, and then /7,(bi»..., b/,) is a tile b • up of p containing a. It follows by induction that a e f ? i ( b i , . . . , b/,) and h(rii(bi,..., b/,)) < 1, whence »/i(bi,..., b/,) is the singleton {a}. This proves that r\ is surjective. We shall use Proposition 1.10 to establish the division. In the terminology of Proposition 1.10, surjectivity of r\ gives an element ( b i , . . . , b/,) e as a lift of state a. Recall that an element of the wreath product is given by describing its component actions. (See the discussion following the definition of wreath product in Section 1.3.) Thus to specify lift of an s € 5 to the wreath product we need to give appropriate functions fori For is mst an element of Such an h -tuple of functions determines a transformation in the wreath product.

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Chapter 3. Krohn-Rhodes Theory and Complete Classes

We define a lift for a member s of S to the wreath product by defining i = h,... ,1 inductively, First,

for

We record that which has height less than the observation that Fixing for tor the moment, write Then, wnting p for ana for define inductively as i goes down from h — 1 to 1, by

This is just

for

Of course h(p) and h(q) are necessarily less than / + 1. It is understood that the third case applies also if p = *. In the first case, constant [b • uq]~ is a constant map taking a value in Bi whose g-position is a particular tile of q. Clearly this constant map lies in Hi. In the second case, we have h(D\ = i = h(a} = h(n • s} > 1. whence a = D • s == ». Therefore This implies that represents an element of so that In all cases. as required. Now we are ready to establish the division. Fixing we again write and suppose by induction for that for as defined above we have

We have already observed that this holds with / + 1 = h, and now assuming inductively that it holds for i + 1, we establish it for i (i > 0). We must show that holds. Now we shall consider four cases. Case 1. and contradicting Now

We have

-lest imply since by definition of n/ since

since where

Therefore,

according to the definition

3.1. Krohn-Rhodes and Holonomy Decomposition Theorems

81

Case 2. Now definition of ni, since h(p) = i. And since h(q} = i, by definition of ni, we have

by

by definition of

where

So Case 3. s maps Bp bijectively onto Bq. Again

We have

since

since Therefore Case 4.

This implies that and and by definition of

acts as the identity on Bq.

and i Then by definition, so the conclusion holds by induction hypothesis.

and

for all By induction we conclude that all In particular, it follows from and all that the height of the latter is less than i and from the case i = 1 holds for all that lies in and that and Moreover, lifts of distinct members of A are distinct since n] is a function, and lifts of distinct members of 5 are distinct. If s\ 82 (s\, S2 € 5), then there is an a € A such that a • s\ a - S2. Taking a lift a of a we have n(a • J/) = (0) • s,• = a • s,, but these are distinct for i = 1,2, and therefore the lifts s{ and are also distinct. By Proposition 1.10, this establishes the division and proves the holonomy theorem.

We now derive the Krohn-Rhodes theorem as a consequence of the holonomy theorem. Using the lemmas above, the following theorem implies the Krohn-Rhodes decomposition theorem for transformation semigroups. Theorem 3.10. A finite semigroup is irreducible if and only if it is a nontrivial simple group or a subsemigroup of the flip-flop monoid. Proof. By Lemmas 3.5 and 3.6, the nontrivial simple groups and subsemigroups of the flip-flop monoid are irreducible. Let 5 be any irreducible finite semigroup; ( , 5) divides a wreath product of permutation-reset transformation semigroups of the form ( ,, ) by the holonomy theorem. Since 5 is irreducible it divides one of the HI. Now (#,, Hi) < ( , { ,}) l (Hi, HI) by Lemma 3.7. So either S divides {IgJ and by Lemma 3.8 embeds

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Chapter 3. Krohn-Rhodes Theory and Complete Classes

in the flip-flop monoid, or 5 divides the group %,. In the latter case S is a group and, by Lemma 3.6, S is a simple group or the trivial group. This completes the proof. From the holonomy decomposition theorem, the Jordan-Holder coordinate theorem for finite groups, the preceding lemmas, and Fact 1.15, we obtain the Krohn-Rhodes prime decomposition theorem for transformation semigroups. The corresponding result (Theorem 3.1) for a finite automaton A = (A,X,8) follows by taking the transformation semigroup (A, S(A)) and using the result for transformation semigroups.

3.2

Some Results Related to the Krohn-Rhodes Decomposition Theorem

In this section we characterize the complete classes of finite automata with respect to the homomorphic representation under the or, products for i = 0, 1,2. First we show an application of the Krohn-Rhodes theory. Theorem 3.11. Let then either

be an oiQ-product. IfG is a simple group with

Proof. First, we note that if we restrict ourselves to a noncyclic simple group G, then our statement is a direct consequence of the Krohn-Rhodes theorem and Proposition 2.49. We consider a direct proof of our statement which does not use this direct consequence. Let , and . Obviously, the man with and is a well-defined semigroup homomorphism. For each be the collection of those transformations 8 with If Sb is nonempty, then it is a subsemigroup of S(A) and the mapping with is a homomorphism. Since there is a subgroup H of S(A) such that G is a homomorphic image of H and Since H is a subgroup of SL4), by Proposition 2.36, there is a nonempty set with the following properties: (a) The restriction of each is a permutation of W. (b) The mapping with . is an isomorphism of H onto a permutation group over W. if and only if Thus for we have for all Let B\ be the set of the first components of the elements of define W. For each to be the permutation of B\ obtained by taking Then the restriction of with is a well-defined homomorphism of H onto a permutation group over B\. Set N = ker , so that N is a normal subgroup of H and HIN = P. Let be the homomorphism taking Clearly, is a subgroup of S(B). We can consider as a homomorphism of H onto . If tor some i then also Therefore ker Moreover, factors through . it follows that H /N is a homomorphic image 0f H\. From we also have Since

3.2. Some Results Related to the Krohn-Rhodes Decomposition Theorem

83

the simple group G is a homomorphic image of H and N is a normal subgroup of H, either G is a homomorphic image of H/N or N maps homomorphically onto G. In the former case G is a homomorphic image of HI and therefore G||(n)H. From now on we assume that G is a homomorphic image of N. Let b e B\ be any fixed state. If N for a word p X+, then 8i(b, where p e X+ and ^ e AT. Since each member of N is induced by some word of length n, the same holds for Hb, i.e., Hb c {(($2X7 : e Z+, |?| = n}. Because G divides #ft, we obtain G\\WC. D Corollary 3.12. Lef G be a nontrivial simple group. If G\\Afor an ctQ-product A of automata in /C, where /C is any class of automata, then G\ \Bfor some B € /C. n Theorem 3.13. Let S be an irreducible semigroup. IfS \ \Afor an oiQ-product A of automata in /C, where /C is any class of automata, then S\\B for some B e /C. In addition, if S\\B for some B € /C and S is a subsemigroup of the flip-flop monoid, then S embeds in S(B) in equal lengths with respect to B. Proof. If S is an irreducible semigroup, then by Theorem 3.10, 5 is either a simple group or a subsemigroup of the flip-flop monoid. If S is either a noncyclic simple group or a subsemigroup of the flip-flop monoid, then we can apply Proposition 2.49. If 5 is a (cyclic or noncyclic) simple group, then we can apply Corollary 3.12. This completes the first part of the nroof. For the second nart. assume that S\ \B for some B = (B. X. 8} K such that S is a subsemigroup of the flip-flop monoid. First we suppose that S = {e, t, r] is the flip-flop with monoid. Using Lemma 3.4, there exists a subsemigroup M, v, w € navmg an isomorphism K onto S. Let, say, such that e is the identity of 5. We shall use the obvious facts that for every pair i, j of positive integers, Let Then and Therefore, such that w', v', w' have equal lengths and K is an isomorphism. This completes the proof if 5 is the flip-flop semigroup. We can give similar treatment for the subsemigroups of 5. n Proposition 3.14. Every reset automaton can be represented isomorphically by a direct power of the two state reset automaton.

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Chapter 3. Krohn-Rhodes Theory and Complete Classes

Proof. Let be an arbitrary reset automaton with state set Consider the nth direct power of the two state reset automaton for which Let be mappings such that for every and furthermore, if and only if Clearly then A can be under embedded isomorpmcally into Take two alphabets X and Y. For a fixed positive integer n, consider a mapping Moreover, be the automaton, where and, for arbitrary and

Lemma 3.15. For every can be represented homomorphically by a cascade product of an n-state counter and two-state reset automata. Proof. Of course, a direct product of automata can be considered as a special type of their cascade product. Therefore, using Proposition 3.14, every reset automaton can be represented homomorphically by a cascade product of two-state reset automata. To prove our lemma, therefore, it is enough to show that can be represented homomorphically by a cascade oroduct of an n-state counter and certain reset automata. be a counter. Moreover, take the automata Let and where * is an arbitrary symbol with moreover, for arbitrary and

Clearly, all the

are reset automata. Take the cascade product

with

where

and

3.2. Some Results Related to the Krohn-Rhodes Decomposition Theorem

85

Now we define a subautomaton with X' = X of B and that of a mapping under which R.r is a homomorphic image of B'. Let B' consist of all b 6 B for which there are words and with such that

Moreover, let where denotes the mirror image of p. It is routine work to show that Bf is a subautomaton of B, and is a homomorDhism or onto We will also use the following lemma. Lemma 3.16. Let be automata. Assume that for and an integer there exist mappings and such that the following two conditions are satisfied: for arbitrary b

B and

Then a cascade product o RT by B homomorphically represents A. where, for arbitrary

Proof. Form the cascade product

and To an arbitrary state d = ((D. va). b) of P we correspond the state then of A. Assume that D receives an input signal x in this state d. If to which the state of A is corresponded. In the opposite state, i.e., if then The state of A corresponding to this which is for arbitrary is equal to since, b € A. (Observe that in the second case a = X.) In both cases we have that the mapping given by is a homomorphism of D into A. By (2), y is a mapping onto A. We are ready to give a proof of the next statement. Theorem 3.17. A class JC of automata is complete with respect to homomorphic representations under the cascade product if and only if (1) the two-state reset automaton can be represented homomorphically by a cascade product of automata from K, (2) every counter (of prime power length) can be represented homomorphically by a cascade product of automata from /C,

86

Chapter 3. Krohn-Rhodes Theory and Complete Classes

(3a) there is an automaton A K such that a subsemigroup S ofS(A) is isomorphic to the monoid with two right-zero elements, and (3b) for every simple group G there is an automaton with Proof. The first two conditions are obviously necessary.17 The necessity of (3a) and (3b) comes directly from the Krohn-Rhodes decomposition theorem. (Actually, (3a) and (3b) constitute Krohn-Rhodes' criterion.) For the converse, first note that every counter can be represented homomorphically by a cascade product of counters with prime power length. (We omit the easy proof of this statement.) Thus we may assume by the conditions (1), (2), and Lemma 3.15 that for every r : [p• e X+ : \p\ — n} -+ [p Y+ : \p\ = n}, the automaton RT can be represented homomorphically by a cascade product of automata from K,. Let 5 be an arbitrary noncyclic, irreducible monoid. By our conditions (3a), (3b), and Proposition 2.49 we have that S\ \A for some A K. Using Proposition 2.47, we then get As\\B^n, where HAn denotes the nth diagonal power of an appropriate subautomaton B = (B, Y, SB) of the automaton A satisfying the conditions of Proposition 2.47 and n is the number of states of A. Thus, let AS\ | n under the mappings r\ : Bn S, r2 : S -> Y+. Then, denoting by e the identity element of S, we get {Ss(Ti(8'(b, r2(e))), e) : b e Bn} = {riO$'(b, T2(e))) : b e Bn} = {^(b) : b Bn] = S. Therefore (taking a, T, A, B of the lemma to be i\, 12, AS, B, respectively), we have the conditions (1) and (2) of Lemma 3.16. Then AS can be represented by a cascade product of the automaton KT2 by the direct power Bn. Therefore, combining this with (2), for every irreducible semigroup 5, we conclude that As can be represented homomorphically by a cascade product of automata from K, for every irreducible semigroup S. Using the first part of the Krohn-Rhodes decomposition theorem, this implies that /C is complete with respect to homomorphic representations under the cascade product. The proof is complete. D Theorem 3.18. None of conditions (1), (2), (3a), and (3b) of Theorem 3.17 can be omitted. Proof. For (3a) and (3b), the statement comes directly from the Krohn-Rhodes decomposition theorem. (See Theorem 3.1.) For (1), we now show that there exists a class /C satisfying (2), (3a), and (3b), which is not complete with respect to homomorphic representations under the cascade product. Let be a (countable) system of automata with

moreover, let Then

be defined by

and Thus a subsemigroup of S(A\) is isomorphic to the monoid with two

17 Although it may be counterintuitive to those used to transformation semigroups rather than automata, to obtain (2), it is not sufficient to homomorphically represent all prime-length counters with single-letter input sets. For example, using such counters, the single-letter-input modulo-four counter cannot be homomorphically represented.

3.2. Some Results Related to the Krohn-Rhodes Decomposition Theorem

87

right-zero elements. On the other hand, by Proposition 1.5, for every n = 2, 3 , . . . , the degree-n + 1 symmetric group is isomorphic to S(An). Since the degree-two symmetric group can be embedded isomorphically into a larger symmetric group, and, furthermore, every simple group can be embedded isomorphically into a symmetric group, then /Co satisfies (3b). Therefore, {.4o} U /Co satisfies (3a) and (3b). Let A = ({0,1}, [x, y}, 8) be an automaton having S(i, x) = 1 and 8(i, y) = 2, i = 1, 2. Then A is a two-state reset automaton. For every positive integer n, set Bn = (A x {1,..., n + 1} U {*}, A x {jc, y}, 8'n), where * is a new symbol and

with (a, b) {0,1} x {1,..., n + 1}, (c, z) {0,1} x {x, y}. Let K, consist of the counters and all automata Bn,n = 1,2,— It is now obvious that /C satisfies (2). For (3a) and (3b), first note that for every n, An is a homomorphic image of a subautomaton of a cascade product A x Bn({x, y}, \, )- (Hint: (z) = z, I. But then we have again that An is a homomorphic image of a subautomaton of a cascade product A x Bn({x, y}, \ x • • • x T>m(X, 1 and T>i,..., T>m-\ are counters. Then a cascade product C x T>m(X, \jr\, ^2) also has a nonautonomous strongly connected subautomaton, where C is a counter Ck. (C can be a trivial counter having only one state if m = 1). Let us denote this subautomaton by D= (D, X, 8"). The automaton Dm cannot be a counter, so it is Bn for a particular n. Since D is a nonautonomous strongly connected automaton, no state in D has be fixed the symbol * as its second component. Let and with Put Thus, If = a-y. then, bv A and the definition of Bn, we have But then b\ = bi follows. Therefore, » and, consequently, one of and has the symbol * as its second component. Hence, m > 1 and there exists a k, 1 k < m, such that £>* = BI for £ particular 1. Denote again D = (D,X, 8") a nonautonomous strongly connected

88

Chapter3. Krohn-Rhodes Theory and Complete Classes

subautomaton of D1 x • • • x D m ( X , ( p 1 , . . . , pm). If V has a state for which its th component is *, then all state of V has this property. Clearly, then D can also be represented by a cascade product D1 x • • • x D-1 x Dl+1 x • • • x D m ( X , ( p ( , . . . ,
90

Chapter 3. Krohn-Rhodes Theory and Complete Classes

By an elementary computation we obtain the next observation. Proposition 3.20. Let Cn be a nontrivial counter, i.e., n > 1, and let 1C be a class of automata. Cn can be represented homomorphically by a cascade product of factors from 1C if there is a multiple ofm such thatCm can be embedded isomorphically by a cascade product of factors from 1C. Further, Cm can be embedded isomorphically into a cascade product of factors from K if and only if there are automata Ai = ( A i , Xi, , ) K, i = 1,..., k, k > 0, and integers 1 = mo <m\ < • • • < mk = m such that

(1) mi_1 is a divisor of mi (i e {1,...,k}), and (2) for every i e {1,..., k} there are distinct states a 1 , . . . , a mi / mi _ 1 Ai, and a word u € X* with |u| = w,-_i and

Let us call 1C of automata precomplete if it satisfies the following conditions: (i) There is an automaton A such that F is isomorphic to a subsemigroup of S(A). (ii) For every simple group G there is an A e 1C with G < S(A). The Krohn-Rhodes decomposition theorem readily implies that every complete class for the cascade product is precomplete, but the converse fails in general. It may well happen that although 1C is precomplete, any strongly connected automaton is trivial, i.e., a one-state automaton if it can be represented homomorphically by a cascade product of factors in 1C. Proposition 3.21. Let q = pl be a prime power. There exists a precomplete class K' such that for any Ko, Cq cannot be represented homomorphically by a cascade product of factors from K' U Ko unless Cq can be represented homomorphically by a cascade product of factors from /Co.

Proof. Define the automata An, n > 3, as follows: An = ({1,..., qn} U {*}, {jci,..., xq, y}, ), where, for every i {1,..., qn} and j {1,..., q},

Observe that the word x1, ...,xq induces a cyclic permutation of the states in A' = {1, q + 1,..., q(n — 1) + 1}. Moreover, yx2 --'Xq induces the transposition y (1) = q + 1, y (q + 1) = 1, y(a') = a', a' A'\{1, q+1} of A'. Consequently, by Proposition 1.5,thedegree-n symmetric group divides S(An). In addition to the automata An define A = ({1,..., 2q] U {*}, (x, y, z,*2, ...,xq,}, 5) by the following rules: 5(1, x) = (q + l,x) = (q + l,z) = 2, (1, y) = (1, z) = (q + l , y ) =q+2, (i,xi) = i + 1 (mod 2q), (q + /,*,-) =

3.2. Some Results Related to the Krohn-Rhodes Decomposition Theorem

91

q + i + 1 (mod 2q), i = 2 , . . . , q, and the value of the transition function 8 is * for the rest of the cases. We have 5(1, XX2 • • -xq) = 8(q + 1, XX2 • • -xq) = q + 1, 5(1, yx2 ---Xq) = 8(q + I , y x 2 •••x q ,) = 1; further, 8 ( l , z x 2 . . . . x q ) = 1, S(q + l, Z x 2 •••*,) = q + 1. Consequently, by Proposition 2.34, S(A) has a subsemigroup isomorphic to F. Besides those mentioned above, the automata An have the following property: for every i {1,..., qn] and u ( x 1 , . . . , x q , y}+ with q x |u|, it holds that (i, MM) = *. Similarly, (i, uu) = * in A whenever i e {1,..., 2q} and M e {x, y, z, X 2 , . . . , xq}+ with q x |u|. Set K' = [A] U [An | n 3}. K' is a precomplete class. Let Ko be any class of automata such that Cq cannot be represented homomorphically by a cascade composition of factors from Ko. The above property of the automata in K' and Proposition 3.20 jointly imply that for every integer m > 1, Cm can be represented isomorphically by a cascade product of factors from K' U Ko only if Cm can be represented isomorphically by a cascade product of factors from Ko- It follows that Cq cannot be represented homomorphically by any cascade product of factors from K' U Kon Now we need some auxiliary results and definitions. Let m, n be positive integers with m > 2 or n > 2. We denote by K(m, n) the class of all strongly connected automata A = (A, { }, ) satisfying the following condition: there are distinct states a 1 , . . . t a m A such that (i) (ai,, ) 8(at, y), (a i , ) = ai (ai, ) = a i+1(modm ) for all i {1,..., m}, and (ii) for every i {1,..., m}, z € {x, y}, and u, v { }* with |u|, |v| < n, we have (a i , zu) = (ai, zv) if and only if |u| = |v|. An example of an automaton in k(m, n) if m {1,..., m}, [ x , y } , ), where

2 is C(m, n) = ({1,...,n} x

for all i € {1,..., n} and j € {1,..., m}. For later use we remark that C(m, n) is just the cascade product Cn x Clm({x, y}, ) with (i, j, x) = (i, j, y) = x and

where Cn denotes a counter (with n states) and denotes a counter with identity (having m states). In particular, C(m, 1) is isomorphic to . To include the case m = 1 (so that n 2), we define C(l, n) = ({1,..., n} U (2'}, {x, y}, 5), where 5(1, x) = 2, 5(1, y) = 2', (i, ) = (i, ) = i + 1 (mod n), i = 2 , . . . , n, (2', ) = 5(2', y) = 3 (modn). We see that C(l, n) K(l, n). The proof of the following statement is omitted. Lemma 3.22. For every pair of integers m, n with m 2 or n A € k(m, n) we have that C(m, n) is a homomorphic image of A.

2 and automaton

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Chapter 3. Krohn-Rhodes Theory and Complete Classes

Take an automaton C(l, n) so that n > 2. For technical reasons we treat the twostate reset automaton Ao as being equipped with the fixed input signs x, y, i.e., AQ = ({0, 1}, {x, y, 8}) with 8(i, x) = 0, 8(i, y) — 1, / = 0, 1. It is easy to see that for every pair of words u, v e {x, y}* if U = V (i.e., u and v induce the same transition in C(l, n)), then either u = v = or u, , and the last letter of u coincides with that of v. On the other hand, AQ also has this property. Lemma 3.23. For all A € k(l, n), AQ can be represented homomorphically by an nthdiagonal power of A. Proof. Let A = (A, {x, y}, 8) e /C(l, n) be given. Then (i) S(fli, *) (a 1 , y), ( a 1 , x n ) = (alt yn) = alt and (ii) for every z € {x, y} and u, v € {x, y}* with |u|, |v| < n, we have (a1, zu) = (a1, zu ) if and only if |u| = |v|. By (a 1 , x) (a 1 , y), we may assume without loss of generality thatai (a1, y). Consider the nth-diagonal power B = (An, X, ) = A\ ] • • • An of A with A\ = • • • = An = A and let B' = (B', X, 8") be a state-subautomaton of B generated by its state (fli, <5(fli, jc), . . . , (a\, x n - 1 ) ) . Then none of the states a\, (a\, x), . . . , ( a i , x n - 1 ) coincides with 8(a\, y); moreover, for every p e {x, y}*, z e {x, y}, (ai, y) { (a\, pz), (a\,xpz), . . . , ( a \ , x n - 1 p z ) if and only if z = y. Let : B {0, 1} be given by

moreover, let

for every p X*, z {x, y}. By the definition of A, ty is well defined and it is a statehomomorphism of B' onto A0. D Lemma 3.24. For all A diagonal power of A.

k(m,

n),

can be represented homomorphically by an wth-

Proof. We may assume that m 2 since otherwise the statement is trivial. By Lemma 3.22 it suffices to prove that is a homomorphic image of a state-subautomaton of the nthdiagonal power of C(m, n). Consider the nth-diagonal power B = (An, X, ) = A1 A • • • An, of C(m, n) with A\ = • • • = An = C(m, n) and let B' — (Bf, X, 8") be a state-subautomaton of B generated by its state ((1, 1), (2,1),..., (n, 1)). Put ((i lf j{),..., (in,jn)) = («$((!, 1), p), 8((2, 1), ) , . . . , ((n,1),p)) and (( , ) , . . . , ( ;, ;)) = OHO, 1), pz), *((2, l ) , p z ) , . . . , <$((«, 1), pz)) for a given pair p e {;c, y}*, z { , }. Then, by the definition of C(m, n), [ii,..., in] = [i{, • • •, ] = {1,..., n}, and simultaneously,

3.2. Some Results Related to the Krohn-Rhodes Decomposition Theorem

93

Define :B {1,..., m} such that ^(((1,1),• • •, (n, 1))) = 1; moreover, for every p [x, y}, if(( ( ( l , 1), />), «((2,1), p),..., ((n, 1), p))) = p(x) + 1 (modm), where p(x) denotes the number of occurrences of the letter jc in the word p. Clearly, then ty is well defined and it is a state-homomorphism of the state-subautomaton B1 of the nth-diagonal product of C(m, n) onto . Lemma 3.25. Given a class 1C of automata, suppose that all counters and a strongly connected nonautonomous automaton can be represented homomorphically by a cascade product of factors from 1C. Then either AQ or can be represented homomorphically by a cascade product of factors from 1C for an integer m >2. Proof. Suppose that a strongly connected nonautonomous automaton A = ( A , X , 8 ) can be represented homomorphically by a cascade product of factors from 1C. For every x X, let Ax denote the set of all states a e A such that a = (a, xr) for some r 1. Since A is a strongly connected nonautonomous automaton, there are x\, x2 e X and a\ AXl with (a\,xi) (a1,X2). Let n 1 be any integer with the property that (a, x ) AXl for all a e A, and (a, x") = a whenever a AX}. Starting with a\, successively compute the states a\,...,at, at = (a,i-1, X2x ), i 2, until repetition occurs. Thus the states GI, ..., at are pairwise distinct and (at, X 2 x n - l ) = as for some s {1,...,t}. From the choice of n and a\ we have a\,..., at AXl and (ai;, x ) = a,,, i e {1,..., t}. If (ai, x1) = 8(at, X2) for some i {1,..., t}, then take a word v X+ with (ai, v) = a\ and define u = - We see that (a\,x\) (ai,X2) and 8(a\,x\u) = 8(a\,X2u) = a\.Letk = \u\. It is easy to prove that a cascade product of Ck+1 with A has a subautomaton belonging to k(l, k +1). (Hint: define Ck+1 x A({x, y},( , ) by 1. Form the cascade product Cn x A({ }, ( ), where (pi(c,a,x) =
94

Chapter 3. Krohn-Rhodes Theory and Complete Classes

following hold: (1) There is a strongly connected automaton which can be represented homomorphically by a cascade product of factors from k. (2) There is an automaton A e 1C such that S(A) is isomorphic to the right-zero semigroup with two elements. Proof. The necessity of (1) is obvious, while the necessity of (2) can be derived from the Krohn-Rhodes decomposition theorem. By Lemma 3.25, either AQ or C can be represented homomorphically by a cascade product of factors from k. In the first case the proof is done. Supposing that Clm can be represented homomorphically by a cascade product of factors from 1C, choose A = (A,X, ) with property (2). By Proposition 2.34, there are states a\, ai € A and words v\, v2 € X+ with (ai, v\) = a\ and (ai, v2) = 02, i = 1, 2. We may as well suppose that |v1| = |u2| = mn for some n 2 (for v\ can be replaced by (v2V\)m and V2 by (v\V2)m). Observe that there exists an nth-cascade power of €„ which is isomorphic to the counter Cmn having mn states. Indeed, let C = ({1,..., m}, {x, y}, 5^) be given with

be given with

moreover let

(c1,..., cn} € ( 1 , . . . , m}n. An easy technical computation shows that this cascade power is isomorphic to Cmn. Now we consider a cascade product B = Cmn x A({x, y}, , ) such that (c, a, z) = x and

c e { 1 , . . . , mn}, a € A. Let B' be a state-subautomaton of the cascade product B generated by the state (1, a\). It is obvious that B' k(1, n). By Lemma 3.23 this completes the proof. D Let m 1 and n 2 be integers. We call the automaton A = (A, X, 8) an (m, ri)automaton if there are a € A, sets X i , . . . , Xm c X, and signs jti, X2 € Xi with the following conditions, where L denotes the language X\ • • • Xm:

for every

and there is a

with

Moreover, we say that A is an m-automaton if it is an (m, n)-automaton for some n 2. Obviously, A is an m-automaton if and only if | X | > 2 and it is an (m, n)-automaton forn = |X|.

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95

Proposition 3.27. If A is an m-automaton and A is a homomorphic image of the automaton B, then B is also an m-automaton. Also, if none o f A 1 , . . . , An is an m-automaton, then no cascade product with these components is an m-automaton. Proof. For the first part of this statement, consider an m-automaton A = (A, X, 5) with a A, sets X\,.. .,Xm c X, and signs x\,x2 X1 having the above properties (1) through (3). Let B = (B, X', ') be an automaton having a homomorphism = ( ) l onto A Then for every a' € and u' € (u),u L+, L = X1. • • Xm we obtain '(a', x{) £ '(a', x'2) and that 8'(a', u'V') (a) holds for some i/ e ir2l(v), v e L*. By the finiteness of the state set B ofB, there exists a state a such that for every u' 2 l ( u ) , u is a having '(a', u'V') = a'. For the second part of our statement, consider a cascade product .4 = (A, X, 5) = .Ai x • • • x An(X, ( i,..., n) such that none of the automata At = (A t , Yt, ), t = 1,..., n, is an m-automaton for some m. Assume that contrary to our statement, A is an m-automaton with a = ( a 1 , . . . , a n ) A, a, € A,, t = 1 , . . . , n , sets X i , . . . , Xm c X, and signs x1, x2 X1 having the above properties (1) through (3). But then for every u € L+, L = Xi • • • Xn, there exists av & L* with (a, uV) = a. Suppose that (a1, ( (ai,..., an, z\)) 1 (a1, (a\,..., an, z2)) for some z1,Z2 X1 and put Xi' = { ( , . . . ') | (a't e A r , r = 1, . . . , , X,-},i = 1,..., m. But may not really depend on its state components and thus for every ... x'm X • • • X ,there exists a word x1 ...xm € L such that (a\, ...,an,xi ...xm) = x{...x'm. Then we have that for every u' e (Xi • • • X'm)+ there exists a v' € (Xi • • • X'n)* such that (a1, u'V') = a1. Thus we obtain that A\ is an m-automaton, which is a contradiction. Therefore, (a\, \(a\,..., an, z 1 )} = (ai, (a\t..., an, z2)) necessarily holds. We get in a similar way that i(a\, l.jc' € X,}, i = 1, . . . , m . Recall that for arbitrary MI, M2 6 (L*)Xi • • -X r , t = l , . . . , n , with |ui| = |M 2 | and x e Xt+i(modn), (p2(a{, ...,a'n,x) =
<m.

Repeating this procedure for At, t = 3 , 4 , . . . , n, finally, we obtain that (a, x1) = 8(a, x2), a contradiction. Therefore, A is not an m-automaton. D The following result, which can be derived from the previous theorem, shows the complete structure of the complete classes of automata with respect to homomorphic representations under the cascade product.

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Chapter 3. Krohn-Rhodes Theory and Complete Classes

Theorem 3.28. A class K, of automata is complete with respect to homomorphic representations under the cascade product if and only if (1) there is an m-automaton in k for some m 1, (2) for every prime power n > 1, there is a multiple m of n, automata Ai = (A{, X{, Si) € /C, i € {1,..., k}, k > 0, andintegers 1 = mo < m\ < • •• < m^ =m such that (2a) mj_i is a divisor o/m, (i e {!,...,£}), (2b) for every i e {1,..., k} there are distinct states a\,..., ami/mi_l € A, and a word u € Xf with \u\ = m/_i and 8j(ai, u) = a2,..., Si(ami/m._l-i, u) = ami/mi_

i(ami/mi_l,u')

= a\,

(3a) there is an automaton A € K such that a subsemigroup S ofS(A) is isomorphic to the monoid with two right-zero elements, and (3b) for every simple group G there is an automaton A € /C with G < S(A). D Proof. The necessity of condition (1) can be derived from Proposition 3.27. Indeed, if none of the automata At, t = 1,..., n, is an m-automaton for some m, then, by Proposition 3.27, all of their cascade products preserve this property. In addition, if B is a subautomaton of A and B is an m-automaton for some m, then A is also an m-automaton by definition. Thus, applying again Proposition 3.27, none of the cascade products of the above automata At, t = 1 , . . . , n, can represent homomorphically an m-automaton. This ends the proof of the necessity of condition (1). As regards the necessity of condition (2) of the above result, observe that all counters can be represented homomorphically by a cascade product of automata from /C if and only if /C has property (2). (See also Proposition 3.20.) By Theorem 3.17, this establishes the necessity of condition (2). The necessity of conditions (2a) and (2b) comes directly from the Krohn-Rhodes decomposition theorem. As to sufficiency, condition (2) is equivalent of condition (2) of Theorem 3.17. In addition, conditions (3a) and (3b) are the same as conditions (3a) and (3b) of Theorem 3.17. Thus, applying Theorem 3.17, it remains to show that, by our conditions, we can ensure condition (1) of Theorem 3.17. Let A = (A, X, 5) be again an m-automaton with a state a e A, sets X\,...,Xm c X, and signs x\,x2 € X\ with the following conditions, where L denotes the language Xi • • • Xm : (a) 1 < |Xi|,..., \Xm\ < n; (b) S(a, *i) + 8(a, *2); (c) for every u e L+ there is a v € L* with 8(a, uv) = a. Consider a cascade product B = ({1,..., m} x A, X, 5') = Cm x A(X, (p\, (p2) such thatCm = ({1,.. .,m}, {xcm}, c m ),f>c m (c,xc m ) = c + 1 (modm),
3.2. Some Results Related to the Krohn-Rhodes Decomposition Theorem

97

p e X* there exists a q e X* such that <5'((1, a)) = (1, a). In other words, the state (I, a) of B generates a strongly connected nonautonomous state-subautomaton of B. By Lemma 3.26, this completes the proof. Proposition 3.29. None of conditions (1), (2), (3a), or (3b) of Theorem 3.28 can be omitted. Proof. By Proposition 3.27 we cannot omit condition (1). The rest of the statement is a direct consequence of Theorem 3.18. A well-known open problem is whether the following natural question is undecidable in general. Problem 3.30. Given a finite class K. of automata and a finite automaton A, decide whether A can be represented by a cascade product of automata from JC. Lemma 3.31. Let A = (A, X, 5) be an automaton having states a, b A, a b, words p,q,r X+, \p\ = \q\, with 8(a, p) = a, S(b, p) = b, S(a, q) = b, 8(b, r) = a. Then there exists a single-factor product A(X, (p) such that Fcan be embedded isomorphically into S(A(X, ( )}, where F denotes the monoid with two right-zero elements. Proof. Consider the automaton A having the conditions of Lemma 3.31. Furthermore, let B = ({a1, a2), {X0, x1, x2}, ) be an automaton with S#(a,, XQ) = at, <$£(a,, */) = aj, i, j {1,2}. Clearly then S(B) is isomorphic to F. Thus, it is enough to find a singlefactor product A(X, cp) which isomorphically simulates B by nonempty words. By our conditions in Lemma 3.31, there are words p,v'(= qr), v"(= pr), w'(= q), w"(= p) X+, \v'\ = \v"\, \w'\ = \w"\ with 8(a, p) = a, (b, p) = b, (a, v') = 8(b, v") = a, 8(a, w') = 8(b, w") = b. It can be seen that in this case there exists an unambiguously defined

(b, w)) = b. Indeed, let Y be an arbitrary nonempty set having at least 3\p\ + \r \ elements. Thus there are words u, v, w e Y+ with \u\ = \p\, \v\ = \v'\ = \v"\ = \pr\, \w\ = \w'\ = \w"\ = \p\ such that uvw does not contain letters in Y+ with double occurrences. Define

• X such that

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Chapters. Krohn-Rhodes Theory and Complete Classes

Then A isomorphically simulates B by nonempty words under r\ : {a, b} -> (a\ ,02], r2 : (XQ,XI, x2} -> {«, v, w] with Ti(a) = a\, T\(b) = a2, T2(x0) = u, r2(*i) = v, T2(x2) = w. This is the end of the proof. n Lemma 3.32. Let A = (A, X, 5) be an automaton such that G < S(A)for some noncommutative group G. There exists a single-factor product A(X,
(Note that the orders of Sx and 8y are each more than 1, since these group elements do not commute.) Observe that each of these words is of the same length, namely, of length o(8x)\x\ + o(8y)\y\. We compute that a • q = a0 • xyq = a0 • xyy x yx = a0 • x y x y x = a Q • xx yx = a 0 • x 0 yx = OQ • yx = b. It is trivial to check that a • p = a, b • p = b, and b • r = a. But then the states a, b and the words p,q,rofA satisfy the conditions of Lemma 3.31. This ends the proof. D Lemma 3.33. Let A = (A, X, 5) be an automaton such that G < S(A)for some noncommutative group G. Then A satisfies Letichevsky's criterion. Proof. Given an automaton A with n states, let G < S(A) for a noncommutative group G. By Proposition 2.47 we obtain AG < A n, where A n denotes the nth-diagonal power of A. It is clear that AG is strongly connected. In addition, G is noncommutative. Thus AG is a noncommutative strongly connected automaton. Therefore, by Proposition 2.76, AAn satisfies Letichevsky's criterion. Obviously, then A also has this property. This ends the proof. D Lemma 3.34. Let A = (A, X, 5) be an automaton having Letichevsky's criterion with a stateaQ € A, inputletters x, y X, and words p, q X* suchthat (a0, x) (a0, y) and (ao, xp) = (ao, yq). There exists a single-factor product B = A(X, (p) and a counter Ck such that the two-state reset automaton can be homomorphically represented by an aQ-productCk x B +2({x, y], ,..., |pq|+2). Proof. Let A = (A, X, 8) be an automaton having Letichevsky's criterion with a state a0 A, input letters x, y e X, and words p, q e X* such that 8(ao, x) ^ S(OQ, y) and

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Some Results Related to the Krohn-Rhodes Decomposition Theorem

99

(a0, xp) = (a0, yq). Suppose that (a0, xp') = (ao, yq') holds for some p'', q' € X having p = p'p", q = q'q"'. Then A will also have Letichevsky's criterion for the state ao> input letters x, y X, and words p'q", q'q". Therefore, we may assume p" — q" whenever (ao, xp') = (a0, yq') holds with p = p'p", q = q'q". We also assume the minimality of p and q such that 8(dQ, xp') = 8(dQ, xp'p") implies p" = A., and, similarly, 8(dQ, yq') = 8(d0, yq'q") implies q" = A for every p', p", p'", q', q", q'" with p = p'p"p'" and q = q'q"q'". Thus the following feedback function is unambiguously defined.

[for

Consider the single-factor product B = (A, {x, y}, SB) = A({x, y}, k+i) such that

Put H

(Note that Let the product M receive the input signal z m its state (c, b\,..., bk) e H. The next state <$x ((c, b\,..., bk), z) is obtained in the following way. The first component c is set to c + 1 (mod A:), the c (mod A:) + 1-th component &c(modit) = «o is replaced by 8e(aQ, z), the c + 1 (modfc) + 1-th component &c+i(mod;t) = 8(aQ, z'), z' e {*, y} assumes the value 8(a<), z'z\), and each of the components bc+s(modk)+i = 8(aQ, z"z\... zs-i), z" e {x, y}, s = 2,..., k - 1 is changed for £,+,-+1 (m0dfc) = <$(flo, z"zi •.. z,). Thus, for every (c, b\,..., bk) the c — 1 (mod k) + 1-th component bc-i (mod/t) shows the value of the last incoming input letter for M. Define AQ = ({ai, aj\, {x\, X2], SQ~) with 5o(«,-, Xj) = «;, i, j e {1, 2}. Then AQ is the two-state reset automaton. For every (/, b\,..., bk) €. M we represent the state of AQ by &/_i (mod*) such that, say,

It is obvious that ^ : H —> {a\, d2\ is a homomorphism of a state-subautomaton of M. onto >^. This ends the proof.

100

Chapter 3. Krohn-Rhodes Theory and Complete Classes We have the following direct consequence of Theorem 3.17.

Theorem 3.35. A class JC of automata is complete with respect to homomorphic representations under the a. \-product if and only if (1) the two-state reset automaton can be represented homomorphically by an a\-product of automata from /C, (2) every counter (of prime power length) can be represented homomorphically by an a\-product of automata from k, (3a) there is a single-factor product B of an automaton A € K such that a subsemigroup S of S(B) is isomorphic to the monoid with two right-zero elements, and (3b) for every simple group G there is a single-factor product B of an automaton A e /C with G < S(B). Now we are ready to prove the following well-known result. Theorem 3.36. A class 1C is complete with respect to the homomorphic representations under the ct\-product if and only if (1) every counter (of prime power length) can be represented homomorphically by an a\-product of automata from /C, and (2) for every simple group G there is an automaton A € K, having a single-factor product BwithG < S(B}. Proof. The necessity of (1) and (2) are obvious. To show sufficiency it is enough to prove that by our conditions (1) and (2) we obtain the conditions of Theorem 3.35. Indeed, using conditions (1) and (2) of our statement, condition (1) of Theorem 3.35 comes from Lemmas 3.33 and 3.34. Furthermore, using again conditions (1) and (2) of our statement, condition (3a) of Theorem 3.35 is a direct consequence of Lemma 3.32. The proof is complete, in Proposition 3.37. Neither condition (1) nor (2) of Theorem 3.36 can be omitted. Proof. It is trivial that none of the counters satisfies Letichevsky's criterion. Thus the class of all counters is not complete with respect to the homomorphic representations under the general product and thus it is not complete for the homomorphic representations under the a\ -product. Then it is obvious that we cannot omit condition (2). Now we prove that we cannot omit condition (1). For every n > 2, let An = (An, Xn,8n) be the automaton where An = {0,1,..., n, 1',..., n'}, Xn = {x1,..., xn}, n(0, ,-) = i, Sn(i, jci) = 0, n(i, Xj) = i', n(i', xk) = i for every i, k {1 , . . . , n } , j ( 2 , . . . , n}. To see that /C = [An \ n > 2} satisfies (2) of Theorem 3.36, we show that the degree(n — 1) symmetric group can be embedded isomorphically into the semigroup of a single factor product of An. Obviously, this holds if and only if the degree (n — 1) symmetric group can be embedded isomorphically into the semigroup of the digraph Dn = (An,{(a,b) | a,b An, there exists x e Xn : n(a,x) = b}) which has the structure Dn = (A B , {(0, i), (i, 0), (i, i'), (i', i) | i = 1 , . . . , n}).

3.3.

Homomorphically Complete Classes Under the Quasi-Direct Product

101

To prove this fact, we consider a game similar to that in the first part of Section 2.1: let us place n — 1 coins c, onto the vertices 1',..., (n — 1)' so that c, is placed onto i'.lt is sufficient to prove that every pair of coins can be interchanged so that the others get back to their initial locations. We can restrict ourselves to the case that c\ and ci are the coins to be interchanged. Let us first move c\ to n' in four steps along the path 1'lOnn'; meanwhile all other coins are rotated around the cycles i'li', i = 2,..., n — 1, since there are no loop edges. After this transformation we see that c\ is on n', and for every i = 2 , . . . , n — 1, c,is back on vertex i'. Next, in a similar way, move ci to 1' along the path 2'2011' and rotate the coins c\,c3,..., cn-\ around the cycles n'nn', 3'33',..., (n — l)'(n — l)(n — 1)', respectively. Now the placement of the coins is this: c\ is on the vertex n', GI is on 1', and for / = 3,..., n — 1, c, is on /'. Finally, with a similar procedure, move c\ to 2' so that all the coins c, get back to i', i = 3 , . . . , n — 1, and ci gets back 1'. This completes the proof that JC satisfies (2). To see that k = [An \ n > 2} does not satisfy (1) we show that for every ai-product B of factors from JC, none of the counters of length greater than 2 can be represented homomorphically by B. Assume to the contrary that there is such a counter. By Propositions 2.59 and 3.20, there are a single-factor product A = (An, X, 8) = An (X, (p), distinct states a\, ...,
3.3

Homomorphically Complete Classes Under the Quasi-Direct Product

Recall that a quasi-direct product of automata is a special type of the general product such that the feedback functions of the component automata are really independent of the state components. Therefore, a quasi-direct product of automata At — (At, Xt, ,), t = 1,..., n, can be given as an automaton A = (A, X, 8) = At(X, ,..., Xt,t = 1,..., n, do not depend on the state variables). The following statement is obvious. Proposition 3.39. The quasi-direct product of automata At = (At, Xt, 8t) given by X and : X -> Xt, t = 1,2, is isomorphic to the quasi-direct product of automata AI and A\ given by X and
102

Chapter 3. Krohn-Rhodes Theory and Complete Classes

Theorem 3.40. There exists no minimal complete class of automata with respect to homomorphic representations under the quasi-direct product. Proof. Consider an arbitrary complete class k of automata with respect to homomorphic representations under the quasi-direct product. It is enough to show that for every automaton A = (A, X', 8A), the class K \ {K} also is a complete class of automata with respect to homomorphic representations under the quasi-direct product. Let A = {a\ , . . . , « „ } and take two distinct symbols X0, x\ X'. Consider an automaton B = (B, X, B) for which B = {1,..., n2 + 1}, X = X' U {x0, xi}; moreover, for all b e B and x X,

Consider a subautomaton B" = ({1,..., n}, X', 8'B) of B. It is clear that B" is isomorphic to A. Therefore, for our theorem it is enough to prove that B can be represented homomorphically by an appropriate quasi-direct product of automata from k \ {A}. It can be seen that B satisfies the following condition: (1) For every b, c e B there exists ape

X+ with 8&(a, p) = 8&(b, p).

Indeed, in case b = c this is obvious. Now let b ^ c. Using the definition of , we have that by b < c, p = (xiXQ -l y- b and, similarly, by b > c, p = +l c l b c x£ - (xix£- ) - satisfy condition (1). We show that for all distinct states a/, aj• e A of A and also for every word p'0 = x{... x't, x(,..., x't e X' satisfying <$B(a,, p') = SB (a/, p'), there exists a word p € [ x ( , . . . , x'tY such that 65(0,, p) = SB(OJ, p) and \p\ < n(n — 1). Indeed, assume that for an appropriate index r, 1 < r < t, there exists an s, 1 < s < t — r, such that (a,<, x{... x'r+s) = %(o,, x{... x'r+s) = SB(OJ, x{... xfr). Then, by the input word x'r+s+l... x't, SB(a,, x{... x'r+sx'r+s+l... x't) = 8B(ai,x'l... x'rxfr+s+l... x't) and 8s(aj, x{... x'r+sx'r+s+l... x't} = 8 B ( a j , x { . . . x'rx'r+s+l... x't}. Consequently, the word p can be constructed such that its length does not exceed the number of pairs (ar, as) A x A, ar ^ as. Thus, \p\ < n(n — 1) holds. Let Dt, = (Dt, Xt, f), t = 1,..., m, befiniteautomata having an index t {1,..., m} with Dt = A. Suppose that a quasi-direct product M. = , • • • m} can be given such that it homomorphically represents B. By Proposition 2.52, we may also assume thatjVfhasastate-subautomatonA/' = ( N , X , ) with a state-homomorphism : N B onto B. (And then Y = X.) Assume that A/" is minimal in the sense that B is not a statehomomorphic image of a proper state-subautomaton of M. By the definition of SB, B is strongly connected. Thus, using Proposition 2.25, N is also strongly connected. Because of Proposition 3.39, we can assume that either every Dt, t = I,..., m, is equal to A or there exists an index k € {1,..., m} such that A £ [ D 1 , . . . , D k } , but A = Dk+\ = •• • = Dm. Especially, thus Dm = A necessarily holds. Since |A| < |B|, by the assumption that M. state-homomorphically represents B, it follows that m > 1.

3.3. Homomorphically Complete Classes Under the Quasi-Direct Product

103

Consider the quasi-direct product Mi = Dt(X,
However, using that for every b, c e B there exists a p e X+ having 8B(b, p) = 8B(c, p), we obtain the existence of a word q X+ with 8B(\js((di, ...,dm, ai)), ) — SB( ((di,..., dm, aj)), x'0q). Since JV is strongly connected, an r e X+ can be found such that8tf((di, ...,dm, a,-),x* Q qr} = ((di, ...,d m ,ai), )Hence, ((d1,..., dm), x'0qr) = SMl((d\,..., dm), X'Q), where 5^, denotes the transition function of the quasi-direct product MI . On the other hand, using, in order,

and we get

For every u = 1,..., m we extend the function u : X -+ Xu to X+ such that for all x'lt...,x'k X, u ( x { . . . x ' k ) = u(x{)...(pu(xfk). Continuing the proof, that t / f ( ( d i , . . . , dm-i,di)) = ^ f ( ( d \ , . . . , dm-i,aj)) holds for all pairs (d\,..., dm-\,«,-), (d\,..., dm-i,Oj) e N, we show that (2) for every positive integers and r' e X+, 8A(aj, Vm^r')) ^ 8A(ajt

^(x^qrYr')).

Indeed, by virtue of <5 B (^((di,..., dm, a;)), x'0qr) = 8B(if((di, ...,dm, a,-)), x'Q) = n + 1 and 8*f((di, ...,dm,a,),x'Qqr) = 8j^((di, ...,dm,a(),x'0), we get 8B(^((di,..., d m , a j ) ) , X ' 0 ( q r ) z ) = SBW((di,... ,dm, ai)),xl(qr)*-1) = ••• = 8BW((di,... ,dm, ai)),xt0)=n + l. Consequently, because of 8&(\ls((d\, ...,dm, a,-)), XQ) = n + 1 ( (( i , . . . , dmtOj)), X'Q), 8B(ir((di,..., d m , d j ) ) , X'Q) ^ n + 1 = 8B(\(f(di, ...,dm, a,-), x'0(qr)z). Thus, according to the definition of 8B, for every word r' € X+ with \r'\
104

Chapter 3. Krohn-Rhodes Theory and Complete Classes

From this, by the substitution r" = r', we obtain 8u(du, t of the quasi-direct product M\. Hence, by &t3(ilr((d\,..., dm, a;)), jc^r') ^ 8BW((di, ...,dm, ay)), x'0(qr)zr") we have 8A(ajt 0, 8A(aj, dm-\,aty) for all (d\,..., d m-1 ) N', where at A, is an arbitrary state such that (d\,..., dm-\, at) 6 N. It is clear that the mapping \jf' is well defined according to the fact that for every pair (di,...,d m _ 1 ,fl,-), (di,...,dm-i,aj) € N, i l r ( ( d i , . . . , d m - 1 , a i ) ) = ((di,.. .,dm-i, fl;)). By an easy computation we obtain that V' is s homomorphism of a subautomaton N' = (N', X, N') ofM onto B. Therefore, if the automaton B can be represented homomorphically by a quasi-direct product M having t factors equal to A, then B can be represented homomorphically by a quasi-direct product M.\ having £. — 1 factors equal to A, too. If Dm-\ = A, then, similar to M i, we can construct a quasi-direct product M.2 = • • • m-2) such that 5 can be represented homomorphically by A^2 and M2 has £—2 factors equal to A Repeating this procedure, finally we get a quasi-direct product Mm-k = FIf=i A(X ^ > i , . . . , ^>jt) which homomorphically represents B and V\,..., T>k € /C \ {^4}. Consequently, /C \ {^4} is also a complete class with respect to the homomorphic representation under the quasi-direct product and this completes the proof of our theorem.

3.4

Homomorphically Complete Classes Under the Cascade Product

The following statement is a direct consequence of Theorem 3.1. Lemma 3.41. Let K,bea class of automata having fewer states than an appropriate prime number p and let C be a counter with p number of states. Then C cannot be represented homomorphically by a cascade product of factors from 1C.

3.4. Homomorphically Complete Classes Under the Cascade Product

105

The next statement is obvious. Lemma 3.42. Let Cbea nontrivial counter and take a cascade product M. = (Mi x • • • x Mn, X, 8) of automata Mt = (Mt, Xt, 8t), t — 1,..., n, with the following properties: (1) C can be represented homomorphically by M.. (2) There exists a positive integer k and a fixed-state m of an appropriate Ms, s {1,..., n}, such that 8((mi,..., m n ), xk+£) e MI x • • • x Ms_1 x {m} x Ms+\ x • • • x Mn, ( m 1 , . . . , mn) € MI x • • • x Mn, x € X, t = 0, 1, Then C can be represented homomorphically by a cascade product of factors Mi,...,Ms-i,Ms+i,...,Mn. Now we prove the following. Lemma 3.43. LetC = (C, {xc}, 8c) be a nontrivial counter and let k be a class of automata such that (1) C can be represented homomorphically by a cascade product of factors from /C, (2) N € k implies that C cannot be represented homomorphically by a cascade product of factors from K \ {N}. Then for every automaton A=(A, XA, A) there exists an automaton B=(B, XB, and a nontrivial counter D = (D, { X D } , ) as follows:

)

(3) B is a two-degree weakly nilpotent automaton. (4) A and D can be represented homomorphically by a cascade product of components from K, U {B}. (5) D cannot be represented homomorphically by a cascade product of factors from /C. (6) If any nontrivial counter £ can be represented homomorphically by a cascade product of factors from (K \ {N}} U {B} and A/" e /C, then £ can be represented homomorphically by a cascade product of factors from k \ { N } . Proof. Denote p a prime number for which every element of K has fewer states than p. Construct automata D = ({!,..., p], {*£>}, <$£>) and B = (B, XB, B) in the following way. Set

moreover, let B

Obviously,

and

with

and Thus, (3) holds.

106

Chapter 3. Krohn-Rhodes Theory and Complete Classes

To (4), take a cascade product of factors from K and let N = (N, {xc}, ) be a (state-)subautomaton of N having a (state-)homomorphism : N --> C onto C. Because of (1) there exists such an N, obviously. Denote (C 0 , X0) a fixed element of C x XA and construct the ao-product M. = with M n+i = B as follows: For any state ( m 1 , . . . ,mn,(c,a, d)) and input letter x of M. let

and

Take the subset M' of state set of M with M' = {(m 1 ,..., mn, (c, a, d)) \ ( m 1 , . . . , mn, (c, a, d)) € N, (c, a, d) B \ {(a0, a0, a0)}, ( m 1 , . . . , mn) = c}. By an easy computation we get that : M' -> A with ((m 1 , ...,mn,(c,a,d))) = a is a statehomomorphism of a suitable state-subautomaton of M. (with state set M') onto A Take an arbitrary fixed element xA of XA and let XA), t = 1,..., n + 1, holds for every state ( m i , . . . , mn, (c, a, d)) of M.'. It can be easily shown that : M' -> D with ((m 1 ,..., mn, (c, a, d))) = d is a state-homomorphism of an appropriate state-subautomaton of M! (with state set M') onto D. This ends the proof of (4). In consequence of Lemma 3.41 we receive (5). To (6) let us take a cascade product M = (M1 x • • • x Mn, X, )= , ,..., of factors Mt = (Mt, Xt, ), t = 1 , . . . , n, from (K \ {N}) U {B} and suppose that a nontrivial counter C' can be represented homomorphically by M. Obviously, by M1 = B thefirstcomponents of states ( ( m 1 , . . . , mn),x2+i), (m 1 ,... , m n ) e M1 x • • • x Mn, x e X, e = 0, 1 , . . . , are equal to (a0,, a0 , a0). Thus, by Lemma 3.42, we can suppose M1 B. Let s, 2 < s < n, be the first index (if it exists) with Ms = B. By (2) we obtain that C cannot be represented homomorphically by a cascade product of factors M 1 , . . . , M s - 1 • Consequently, for every pair c e C,m M1 X - - - x Mn and input letter x X there exist positive integers k1, k2 such that the first 5 — 1 factors of (m, xkl) and SM (m, xk2) coincide but . Then either the sth factor of (™, xkl+l) or the k2+l sth factor of (m, x ) coincides with (a0, a0, a0). Obviously, then the 5th factor of (m, Xmax(*i.*2)+^)) i — i 2 , . . . , coincides with (OQ, OQ, ao). Therefore, there exists a positive integer k, such that for every state m and input letter of M., the 5th factor of &M (m, xk) coincides with (a 0 , , a 0 , a0). Then, using Lemma 3.42, we can suppose Ms B. Repeating this procedure we have that C' can be represented homomorphically by a cascade product of factors from K \ N. This ends the proof of Lemma 3.43. n Lemma 3.44. Assume that for a given finite list C0, ..., Cj of nontrivial counters there canbe found a finite list B 1 , . . . , Bj, Bi+1, . . . , B i+j of automata having the following properties: (1) For arbitrary k {0,..., j], Ck can be represented homomorphically by a cascade product of factors from { B 1 , . . . , Bi+k}.

be a cascade pro

3.4.

Homomorphically Complete Classes Under the Cascade Product

107

(2) ByN (B\,..., Bi+k}, k = 0 , . . . , j, none ofCk,.. -, Cj can be represented homomorphically by a cascade product of factors from (B\,..., Bt+j }\N. Then for every automaton A there exists an automaton Bt+j+i and a nontrivial counter Cj+i as follows: (3) Bi+j+i is a two-degree weakly nilpotent automaton. (4) A and Cj+i can be represented homomorphically by a cascade product of factors from (5) IfJ\f € {Bi,..., Bi+k}, k = 0 , . . . , j+1, then none of Ck,..., Cj+1 can be represented homomorphically by a cascade product of factors from {B\,..., Bi+j+1] \{N}. Proof. Considering /C = (B\, . . . ,Bi+j;}and C = Cj, we obtain conditions (1) and (2) of Lemma 3.43. Then, using the notation #,•+_/+! = B and Cj+1 = D, it can be assumed that properties (3)-(6) of Lemma 3.43 are satisfied. Because of (3) and (4) of Lemma 3.43, we can see the validity of (3) and (4) directly. It remains to show (5). Suppose that to the contrary of our statement, for an appropriate k,0
108

Chapter 3. Krohn-Rhodes Theory and Complete Classes

the cascade product, then it should be a minimal homomorphically complete class under the cascade product too. Thus, it is enough to prove that every automaton A = (A, X, <5) can be represented homomorphically by a cascade product of factors from (JC U /Ci). Consider for an arbitrary automaton A the automaton Ai = (Ai, Xi, ;) in F having an isomorphism onto A. Using (1), we have that Ai can be represented homomorphically by a cascade product of factors from K U K1. Therefore A also has this property. This ends the proof. We obtained the following direct consequence of this result. Corollary 3.46. There exists a minimal homomorphically complete class under the cascade product. Finally, we note that, by Lemma 3.41, there exists no finite homomorphically complete class of finite automata under the cascade product.

3.5

Bibliographical Remarks

Section 3.1. Theorem 3.1 issued from K. B. Krohn and J. L. Rhodes [1962 and 1965]. A more detailed description of this result was developed by K. B. Krohn, J. L. Rhodes, and B. R. Tilson [1968]. It has a new proof in Esik [1999]. An extension of Theorem 3.1 was given by Z. Esik [1989a]. An attractive presentation of the Krohn-Rhodes theory was given by A. Ginzburg [1968]. The proof of Theorem 3.2 was described in Lallement [1971] and Eilenberg [1976]. Some aspects of the Krohn-Rhodes theory were studied by J. L. Rhodes and B. R. Tilson [1989], B. Austin et al. [1995], C. L. Nehaniv [1996], and Z. Esik [2000]. Results in this section (with the notable exception of the holonomy decomposition theorem) are mostly originally due to and derived from K. B. Krohn and J. L. Rhodes [1962 and 1965] and appear in the book edited by Arbib [1968]. They have been reformulated and treated by many authors, e.g., A. Ginzburg [1968] and S. Eilenberg [1976]. Lemmas 3.4, 3.5, 3.6, and 3.7 can be derived from the results of A. Ginzburg [1968]. Theorem 3.8 is due to H. P. Zeiger [1967]. Theorem 3.10 issued from K. B. Krohn and J. L. Rhodes [1962, 1965]. The original idea of the holonomy decomposition theorem (Theorem 3.9) is due to H. P. Zeiger [1967], with a correct proof for partial transformation semigroups given by S. Eilenberg [1976]. Our proof, which makes reference only to fully defined transformation semigroups, is inspired by Eilenberg's. Section 3.2. Proposition 3.11 and Corollary 3.12 were discovered by Z. Esik [1991b]. Theorem 3.13 can be derived from Z. Esik [1989a]. Proposition 3.14 was found by H. P. Zeiger [1967]. Lemma 3.15 appears in Domosi [1984]. Lemma 3.16 is an extended form of the Lemma 1.3 of F. Gecseg's book [1986, p. 25]. Lemma 3.16 was also proved by P. Domosi [1984]. Theorem 3.17 was elaborated by Z. Esik and P. Domosi [1986]. Theorem 3.18 was shown by P. Domosi and Z. Esik [1988a]. Proposition 3.19 was found by Z. Esik and J. Vkagh [1986]. Proposition 3.20 was developed by Z. Esik and P. Domosi [1986]. Lemmas 3.22, 3.23, 3.24, 3.25, and 3.26 were proved by P. Domosi and Z. Esik [1988a]. Lemma 3.27 is a new result. Theorem 3.28 is a strengthening of Theorem 3.17 and can be derived from Theorem 3.17 using results in Esik and Domosi [1986] with results from

3.5. Bibliographical Remarks

109

Domosi and Esik [1988a]. Theorem 3.29 is from Z. Esik and P. Domosi [1986]. Some related connections were described by P. Domosi and Z. Esik [1986] and P. Domosi and Z. Esik [1988b, 1988c]. Lemmas 3.31, 3.32, 3.33, and 3.34 are essentially new results. Theorem 3.35 is a direct consequence of Theorem 3.17. Theorems 3.36 and 3.37 were shown by Z. Esik [1986]. Section 3.3. Theorem 3.40 was shown by P. Domosi [1980]. Section 3.4. A minimal homomorphically complete system under the «o-product was presented by P. Domosi [1976]. A nice presentation of this result is in Gecseg [1986]. The results of this section are based on Domosi [1982].

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Chapter 4

Without Letichevsky's Criterion

In Chapter 5 we will see the importance of Letichevsky's criterion in the composition of automata networks. In this chapter we consider networks of automata without Letichevsky 's criterion. In particular, we describe several types of networking with very restricted structure of the permitted links. Assuming that the component automata are rather simple of particular types, the resulting networks that can be constructed are already computationally as general (with respect to homomorphic representation) as what can be constructed with unrestricted networking. We also show that the hierarchy of vi -products (automata networks in which there are at most i links to an automata from components of the network) is strict for this type of representation. We prove even more: The ao-Vi-hierarchy is strict for both homomorphic representation and homomorphic simulation. In addition, the v/ -hierarchy also has this property. This means that the number of permitted links may have a strong influence on the computational capacity of the network if component automata have a certain structure (i.e., satisfy the so-called semi-Letichevsky criterion).

4.1 Semi-Letichevsky Criterion We start with the following statement. Proposition 4.1. Let A = (A, X, 8) be an automaton having the semi-Letichevsky criterion and let a € A, jc, y e X, p e X*, (a, x) (a, y), (a, xp) = a (such that for every q e X*, a (a, yq)). For every automaton A' there exists a single-factor product M. of A such that A can be represented homomorphically by a diagonal product of its connected state-subautomata andM.. Moreover, we also have this property for a single-factor loop-free product M. of A whenever (a, xk) = a holds for some positive integer k. Proof. Let A = (A', X', ') be an arbitrary automaton. Assume that (a, xk) = a holds for some positive integer k and then construct M. = A(X', (p) such that for every b 6 A, x' € X', (b, x') = x. In this case, M. is a single-factor loop-free product of A. Otherwise, put p = x1 ...xm withai = (a,x),a2 = (a 1 ,x 1 ), . . . , a m = (a m-1 ,x m-1 ),a = (am,xm), 111

112

Chapter 4. Without Letichevsky's Criterion

and for every b e A, x' e X', let

Then At is a single-factor product of A. In both cases we have S(8(a, x), (p(8(a, x), q)) ^ 8(8(a, y),
for all x e X. We have the following. Lemma 4.2. Every automaton in C. can be represented isomorphically by an otQ-V2-power of the elevator. Proof.LetA = ({0,..., n}, X, 8A) e C.lfn = 1, then A can be represented isomorphically by a quasi-direct power of the elevator having a single factor. Thus we may suppose that n > 1. Consider the ao-vz-power £%+1(X,
Clearly then we can assume that : A ->• {0, l}n+1 given by

is a state-isomorphism of A onto a subautomaton of

4.1 . Semi-Letichevsky Criterion

113

Lemma 4.3. Every monotone automaton can be represented homomorphically by a diagonal product of automata from L. Proof. Let £' be the class of all automata A = ({0, . . . , n}, X, 8A), n = 1,2,...,

S*(0, *) = 0, 8A(n, *) = n and 8A(j, jc) € {0, ;, j + 1}, 0 < j < n, for all x e X.

First we prove that all elements in £' can be represented homomorphically by a diagonal product of factors from £. Consider an arbitrary automaton A = ({0, . . . , n}, X, 84) e £' with n > 1. (We can take out of consideration the trivial case n = 1.) Define automata t), = 2,...,n, having

A(j,x)

ifj = t-l,

S

for all jc e X. Clearly then At e £ for all t = 2, . . . , n.

AUTOMATON An

Letfi c A 2 x - • -xA n withB = {(1,..., 1), (2,.... 2), (2, 3,.... 3),.... (2, . . . , £ , . . . , € ) , . . . , (2,..., n)} U {(l1..., ln) | 0 e {€1,..., €„}}. By an elementary computation we have that the mapping \js : AI x ... x An -> {0,...,n} with

is a state-homomorphism of an appropriate state-subautomaton of the diagonal product Ai A • • • A An onto A. Using the transitive property of the diagonal product, to establish our assertion we shall prove that every monotone automaton can be represented homomorphically by a diagonal product of factors from CJ. Consider a monotone automaton D = (D, X, 8-p) and denote a partial ordering on D for which d -D(d,x),d D,x X. Take a rearrangement d\,..., dn of the elements of D such that for every dt, dj D, di dj, and d, < dj implies i < j. Consider all bijective mappings of the form fs : {di, ...,dn} {1,..., n], s = !,...,«!. For every mappuig fs (1 s n!), define an automaton As = ({0, ...,n},X,8s) having

It is clear that As e £', 1 < 5 < «!. Take the diagonal product M — A\ A • • • A.An. We shall prove that M. homomorphically represents the automaton A. Define the set B C {0,..., n}nl as follows: (1) For every d^ € D there exists a (b\,..., bm) e B and an s e {!,...,«!} having f,(
114

Chapter 4. Without Letichevsky's Criterion

(2) For every (b1,..., bm) e B and s, t {1,..., n!}, 0 {bs,, bt,} implies f (bs) = ft-l(bt). (3) For every pair (£1,..., )) e B, t {1,..., n\], bt 0 implies that for arbitrary xi,... ,xr e X there exists an s {!,...,«!} with f (bs) = f (bt) and f (8s(bs, x1. ..x j )) = 8v(f (bt), Xl. ..*,-), 7 = 1, . . . . r. Let i/r : B {d\,..., dn] be a mapping for which ((b\,..., bn\)) = dk whenever (b\,..., bn\) e B has a component bt, t {1,...,n!} with f (bt) = dk. By conditions (1) and (2), \jf is a well-defined surjective mapping. Using (3) and the definitions of the mappings S, s = 1,..., n\, \ l f ( ( & i ( b \ , x ) , . . . , 8m(bn\, jc))) = 8x>(if((bi, ..., b n! )}, x), (b1, ..., bn\) €B,xeX. Therefore, the diagonal product A\ A • • • AAn has a state-subautomaton (with state set B) having a state-homomorphism onto A. By Lemmas 4.2 and 4.3 we can immediately derive the next statement. Theorem 4.4. Every monotone automaton can be represented homomorphically by an -V2-product of the elevator. Now we turn to the automata having the semi-Letichevsky criterion. Let A = (A, X, <5) be an automaton satisfying the semi-Letichevsky criterion. Given a state a € A, put A'a = A'a = 0 if there exists no x e X, p e X* having (a, xp) = a. Otherwise, let p e X* be the shortest word having this property for an appropriate x e X, and put

Given a positive integer r, a nonnegative integer s, we say that A is (r, sO-weighted if there exists an a e A with \A'a\ = r and |A£| = s. (Of course, it may be possible that A is (r, 5)-weighted and, simultaneously, (r', s')-weighted such that (r, s) /= (r;, 5') (with r, r' > 0).) Proposition 4.5. Let A be an (r, s)-weighted automaton (having the semi-Letichevsky criterion). There exists a single-factor product B of A such that B is an (r, r — l)-weighted automaton. Proof. Let A = (A, X, 8) be an (r, s)-weighted automaton (having the semi-Letichevsky criterion). There are a e A, x, y e X, p € X*,8(a,x) ^ 8(a,y),8(a,xp) = a with \A'a\ = \xp\ = r, IA^I = s (such that for every q € X*, a ^ 8(a,yq)). Put xp = xi • • • xr, xi,..., xr € X. Define (p : A x X -> X such that for every a' e A, x' € X,

It is clear that the single factor product A(X, (p) of A is an (r, r — l)-weighted automaton. Define the automaton £'k = ({1 ,...,/:,*}, {xi, x2}, 8'k) with 8'k(i,xi) = i + l (mod k), <%(*> *i) = *> ^fe(1' *2) = <%(*' JC2) = *,1
4.1. Semi-Letichevsky Criterion

115

SEMI-ELEVATOR £'k

Lemma 4.6. Let A = ( A , X , 8 ) be an (r, s)-weighted automaton (having the semiLetichevsky criterion). The semi-elevator of length r can be represented homomorphically by a diagonal power Bs+1, where Bis a single-factor product of'A. In particular, ifs = r — l, then we may assume that B is an input-subautomaton of A. Proof. By our conditions, there are a € A, x, y e X, p e X*, 8(a, *) ^ 8(a, y), 8(a, xp) = a with \A'a\ = \xp\ = r, \A'^\ = s (such that for every q X*, a 8(a, yq)). For technical reasons, we put a\ = a and xp = z\*--Zk such that z\,..., Zk € X, k > 1. Moreover, we put a,+1 = 8(a, z\ • • • z/), 1 < i < k, and A' = [a\,..., ak}. Let us consider the semielevator £'* of length k having £'k = ({1,..., k, *}, [xi, X2\, 8'k) with 8k(i, x\) = i + 1 (modfc), 8'k(*, *1 = *, 8k(i, *2) = 8k(*, x2) = *, 1 < i < k. We prove that £'k can be represented homomorphically by an appropriate diagonal power Bs+l such that (1) B is an input-subautomaton of A if s = \p\, and (2) # is a single factor product of A if s < |/?|. Let a,,,..., a,-, € A' be distinct states such that 8 (afj, yij) e A' for every yij. e X, j = l,...,s. Ifs = \p\, then let B be the input-subautomaton of A with input set {x, y}. Obviously, then 8(at,x) = ai+i(modk) A' and (aj, y) = a,+i(mod*) A' hold for every i € {!,..., k}, j {2,..., k}. In addition, (a1, y) i A'. I f s < \p\, then let B = A({x, y},
Clearly, then B has a state-subautomaton B' = (B', {x, y}, 8') generated by its state a\ such that for appropriate distinct states a\,..., a^ we have 5'(a,, x) = fl,+i(modik)> and simultaneously, for every j e {!,...,*},^ e X*, 8'(ai r yq) £ A'. Consider the state-subautomaton D = (D, Y, 8") of the diagonal power (B')s+l generated by the state (0i, ...,as+i). For every positive integer m, we obtain 8"((a\,..., as+i),xm) = (flm+KmodJt), • • • , «m+5+i(mod*))- Simultaneously, if r = xuy, then for every q € [x, y}*, there exists a t € {1,..., s + 1} with 8'(at, rq) £ (a\,..., ak}. Hence 8"((ai,..., a j+ i), rq)

(a|rq|+l(mod/fe)» • • • , a\rq\+s+l(modk))-

116

Chapter 4. Without Letichevsky's Criterion Define the mappings

:D

{1,..., k, *},

: {x,y}

{x1, x2} with

fa(x) = jci, (y) = x2- By an elementary checking, we get that is a state-homomorphism of a state-subautomaton of Bs+l onto £'*. The proof is complete. Proposition 4.7. Let A = (A, X, 8) be an (r, s)-weighted automaton (having the semiLetichevsky criterion). Every monotone automaton can be represented homomorphically by an cti-v2 +l)-product of B, -where B is a single-factor product of A. In particular, if s = r — 1, then we may assume that B is an input-subautomaton of A. Proof. Using Theorem 4.4, it is enough to prove that the two-state elevator can be represented homomorphically by a diagonal power Bs+1 such that (1) Bis input-isomorphic to an input-subautomaton of A if s = r — 1 , and (2) Bis a single factor product of A if s < r — 1 . But it is evident that every semielevator of length k > 1 can be mapped homomorphically onto the elevator. Thus, using Lemma 4.6, the proof is complete. D Next we prove the following lemma. Lemma 4.8. Let A = (A,X,8) be an (r, s)-weighted automaton (having the semiLetichevsky criterion). Then every product C x T>(Y, 1 (i.e., \p | > 0). For technical reasons, we put a\ — a and xp = x\- --xr such that xi,...,xr € X, r > 1. Moreover, we put a (+ i = 8(a, x\ • • • jc(), 1 < i < k, and A' = { f l 1 ( . . . , 0 r } .

First we recall that all counters have singleton input sets and thus they are autonomous automata. But then an arbitrary product of a counter and any other automaton coincides with the «o-product of the considered counter and the considered automaton. By Proposition 2.65, this single-factor product is also a monotone automaton. Thus we will assume without any restriction that C x T>(Y,
4.1. Semi-Letichevsky Criterion

117

C x T>(Y,
8e(ao, x) e A if jc e X, and 8s(a, x) e [8(a, x') \ x' e X} if a € A, jc e {;ci,..., xn}. Clearly then A is a subautomaton of B, where B is a connected automaton satisfying the semi-Letichevsky criterion. It remains to prove the existence of automata A0 ,..., As having the above properties. To this statement we shall show the existence of A\ such that the number of nontrivial cycles in AI is fewer than the number of nontrivial cycles in AQ. Applying this result inductively, we can reach that As does not contain any nontrivial cycle; i.e., it is a monotone automaton. Let a\,..., a,- and b\,..., b}; be two cycles of A with a\ —b\. Observe that in this case a* 7^ bk, 1 < k < min(z, y), would imply that, contrary to our assumptions, A satisfies Letichevsky's criterion with &(at-\, x) ^ 8(at-\, y) and 8(ai-i, xp) = 8(ai-\, yq) = a for some ai-\ € A,x,y e X,p,q € X*. We also have this consequence if a^ = bk, 1 < k < min(z, j) but i ^ j. Therefore, if two cycles have a common element, then these cycles should coincide. Let au+i,..., av be a nontrivial cycle in A. If there are a state a 6 A\{a\, ...,an] and words p, q e X* with S(a, p) € {fl«+i, ...,av] and a € {8(au+i, q),..., (av, q)}, then A satisfies Letichevsky's criterion, a contradiction.

118

Chapter 4. Without Letichevsky's Criterion

Therefore, for every a e A\{ai,..., an} and words p, q e X* with (a, p) 6 {au+\,..., av}, it holds that a £ (8(au+i,q),..., 8(av, q)}. Let a\,..., au e A denote all states for which there are words p\,..., pu € X* having 8(at, pi) 6 {««+i, • . . , av}, i = !,...,«. (We note that {a\,..., au} = 0 may be possible.) Finally, let A \ {a\,..., av} = {av+\,... ,an} for appropriate a v +1> • • • ,an £ A. (Note that {av+\,... ,an} = 0 may be possible but {«!,..., au, av+i,... ,an] ^0 because A satisfies the semi-Letichevsky criterion.) Hence, we can consider an arrangement a\,..., au, au+\,... ,av, av+\,..., an of the set of states in A = (A, X, 8) such that au+i, ...,av form a cycle of length v — u > 1; moreover, 5(a,, x) / a; for either l<j
with

Consider the counter

be an

Let

-product with

and

whenever be a mapping with otherwise. It is routine work to show that iff is a state-homomorphism of Mi onto A. Next we show the following corollary. Corollary 4.10. Given a finite set /C of automata satisfying the semi-Letichevsky criterion, let ck be the least common multiple of all positive integers which are lengths of cycles of automata in /C. Moreover, let mjc be the minimal number of cycles of automata in K. such that every prime power divisor ofcjc divides at least one of these lengths of cycles.18 Consider an (r, s)-weighted automaton A = (A, X, 8) € /C (with semi-Letichevsky criterion, s < r). If an automaton B can be represented homomorphically by a general product of automata from /C, then it can be represented homomorphically by an a i-vj-product of factors in K, with i < 1 and j < mjc + 2(5 + 1) + !. In particular, ifs = r — 1 and for every cycle of length k in B, the counter with k states, as well as the counter with r states, can be represented homomorphically by an oiQ-product of automata in 1C, then B can be also represented homomorphically by an UQ-VJ-product of factors from /C with j < m^, + 2(5 + !) + !. Proof. Suppose that B satisfies the semi-Letichevsky criterion and let r' denote the least common multiple of the lengths of all cycles in B. Then r' \ c/c- Therefore, by Lemma 4.9, B can be represented homomorphically by an oro-product of a counter with r' states and a monotone automaton M. On the other hand, by Proposition 4.7, for every (r, s)-weighted 18

Thus m/e = 0 if all cycles are trivial (having length of 1).

4.1. Semi-Letichevsky Criterion

119

automaton A e /C, M. can be represented homomorphically by an cto-V2(S+i) -power of a single-factor product A' of A, where A may be an input-subautomaton of A if s = r — 1. In addition, by our assumptions, mjc is the minimal number of cycles of automata in /C such that every prime power divisor of CK. divides at least one of these lengths of cycles. If w/c = 0, then c/c = 1, leading to r' = 1. Therefore, in this case we are ready. Consider the (r, s)-automaton A = (A, X, 5) e /C (having the semi-Letichevsky criterion) with a € A, x, y € X, p e X*, 8(a, xp) = a, 8(a, x) ^ 8(a, y), and \A'a\ = r, \A'a\ = s (such that for every q e X*, a ^ 8(a, yq)). Again, for technical reasons, we put fli = a and xp = z\ • • • zr such that zi,. •., zr e X (r > 1). Moreover, we put ai+i = 8(a, zi • • • Zi), I < i < r, and A' = {a\, ..., ar}. Let c denote the least common multiple of r and the lengths of cycles in B and define the ao-product B' = Cc x A(X, (p\, ^2) of the counter Cc = ({I, ...,c},{xc},8c) (with c states) and A such that for every x € X, V\(x} is the (only) input letter xc ofCc; moreover, for every i e (1,..., c}, x e X,

Since r |c, it is obvious that for every

if and only if t = 1 and 8(j, ^(tr + j, j, ;c)) j + l(mod r). By this observation, B' is a (c, s)-automaton with c\cjc. Suppose m/c > 0 and let AI, ..., Am, m < m/c € /C, denote automata for which c divides the least common multiple of c\,..., cm, where c, denotes the length of an appropriate cycle in A,•, i — 1,..., m. Obviously, the counter Cc with c states can be represented homomorphically by a direct product of counters with c\,...,cm states. On the other hand, for every i = 1,..., m, the counter CCi with c, number of states can be represented isomorphically by a single-factor product #, of A{. Therefore, using Proposition 2.53, an appropriate a0- vm -product of B\,..., Bm and a single-factor product A' of A (which may be an input-subautomaton of A if s = r — 1) homomorphically represents the (c, s)-automaton B' (having the semi-Letichevsky criterion). We prove that every single-factor product B" of B' can be represented homomorphically by an appropriate ciQ-vm -product ofBi,...,Bm and a single-factor product A' of A. Recall that B' is an ao-product of a counter and A. On the other hand, all counters have singleton input sets, and thus they are autonomous automata. But then an arbitrary product of a counter and any other automaton coincides with the ao-product of the considered counter and a single-factor product of the considered automaton. Therefore, B" can be represented homomorphically by an a0-product of Cc and a single-factor product A of A. Hence, we can see as before that, indeed, every single-factor product B" of B' can be represented homomorphically by an appropriate <xo-vm -product of BI , . . . , Bm and a single-factor product A of A. Applying Lemma 4.8, an «0-product T of a counter with r'\c states and a monotone automaton M. can be represented homomorphically by an «o-v>2(.y+i)+i -product B", where B" is a single-factor product of B'. As we proved before, B' can be represented homomorphically by an appropriate aQ-vm -product ofBi,...,Bm and a single-factor product A' of A. Thus, by Proposition 2.63, F can be represented homomorphically by an

120

Chapter 4. Without Letichevsky's Criterion

ofo-vm+20r+i)+i -product of automata Bi,...,Bm and A' (where B{ is a single-factor product of A, , i = 1 , . . . , m, and .A' is a single-factor product of .4). Hence, F can be represented homomorphically by an «i-v^+2(j+1)+1 -product of AI, . . . , Am and A. In addition, also by Lemma 4.8, if s — r — 1, then f can be represented homomorphically by an ao-V2(H-i)+i~ power of B' too. Therefore, applying again Proposition 2.63, if for every cycle of length k in B, the counter with k states, as well as the counter with r states, can be represented homomorphically by a single-factor ao-product of an automaton in K, (and s = r — 1), then T can be represented homomorphically by an ao-vm+2(S+i)+i -product of m factors in 1C, and A. But then we are ready because m < mjc and F homomorphically represents B. Suppose that B = (B, X&, SB) is without any Letichevsky criteria and that it can be represented homomorphically by a product of factors in /C. By Propositions 4. 1 and 2.54, we can restrict our investigations to the case when B is connected. If B is strongly connected, then it forms a cycle of length | B \ and then our statement obviously holds. Otherwise, it has a state bo e B which generates all states and, simultaneously, <$/?(£, p) ^ p holds for every p € Xg. Then B can be embedded isomorphically into the automaton B' = (B, XgUfe], 8'), where for every b e B,

Let m denote the least common multiple of all positive integers which are lengths of cycles in the automaton B. Then, by the construction ofB',m also is the least common multiple of all positive integers which are lengths of cycles in the automaton B'. By Lemma 4.9, B' can be represented homomorphically by an or0-product of a counter with m states and a monotone automaton. Because B can be represented homomorphically by a product of factors in 1C, it is easy to see that the counter of m states also has this property. On the other hand, by Lemma 4.7, every monotone automaton can be represented homomorphically by a product of factors in 1C. Thus we have that the automaton B' can be represented homomorphically by a product of factors in 1C. Observe that B' satisfies the semi-Letichevsky criterion (by Se(bo, z) = b0 and SB^Q, x'q) ^ b0, x' e XB, q e (X& U {z})*). Thus we can apply again Lemma 4.9, Lemma 4.8, and Proposition 2.63. The proof is complete. We have the following conjecture. Conjecture 4.11. Given a finite class 1C of automata, let CK denote the least common multiple of all positive integers which are lengths of cycles of automata in 1C. Moreover, let mjc be the minimal number of cycles of automata in 1C such that every prime power divisor ofcjc divides at least one of these lengths of cycles. For every nonnegative integer s, there exist an integer r > s, a finite set 1C of automata, an (r, s)-weighted automaton A e 1C (having the semi-Letichevsky criterion), and an automaton B such that B can be represented by a general product of factors from 1C but B cannot be represented homomorphically by an ai-Vj-product of factors in K ifi < 1 and j < mjc + 2(,s + 1). Problem 4.12. Prove or disprove Conjecture 4.11. The next observation gives a partial solution of Conjecture 4.11.

4.2. Without Any Letichevsky Criteria

121

Proposition 4.13. There exists an automaton A without Letichevsky criteria and a class 1C of automata having the semi-Letichevsky criterion such that A cannot be represented by an cto-product of factors from K.. Proof, Let /C be a singleton class having the automaton B = ({1, 2, *}, {*i, x2], <$) with 8(1, xi) = 2, 6(2, x2) = 1, 6(1, x2) = 8(2, jci) = 6(*, *i) = 6(*, *2) = *. Moreover, let A = ({0o, «i, a 2 }{y1, y2}, 6') be defined by 6/(o0, yi) = «i, S'(OQ, y2) = a2, 8'(ai, vi) = <$'(0i, y2} = a\, S'(a2, yi) = S'(a2, y2) = a2. Consider an arbitrary ao-power Bn(X,
4.2 Without Any Letichevsky Criteria Now we study automata satisfying neither Letichevsky's criterion nor the semi-Letichevsky criterion. The following statement is obvious. Proposition 4.16. A = (A, X, 6) is an automaton without any Letichevsky criteria if and only if for every state OQ e A, input letters x,y € X, and an input word p e X* having 5(«o, xp) = OQ, it holds that S(OQ, x) = 6(#o, )0Obviously, if A = (A, X, 5) has the above properties, then there exists a nonnegative integer n such that for every p e X* with |p| > n, each 8(a, p) (a e A) generates an autonomous state-subautomaton of A Denote by n^(< n) the minimal nonnegative integer having this property.

122

Chapter 4. Without Letichevsky's Criterion

Proposition 4.17. nA < max(|A| - 2, 0). Proof. Take out of consideration the trivial cases. Thus we may assume |A| > 2. Consider a € A, xi,..., xm+2 € X, having 8(a, xi • • • xmxm+i) ^ 8 ( a , x i - - - xmxm+2). If a, 8(a, *i), 8(a, Xix2),..., 8(a, x\ • • • xm), 8(a, xi • • • xmxm+i), 8(a, *i • • • xmxm+2) are not distinct states, then A satisfies either Letichevsky's criterion or the semi-Letichevsky criterion, a contradiction. Hence, m < \A\ — 3. Thus n^ < \A\ — 2. We also note the next direct consequence of Proposition 4.16. Proposition 4.18. If A is a strongly connected automaton without any Letichevsky criteria, then A is autonomous. By this observation, we immediately get the following. Proposition 4.19. Suppose that A= (A, X, 8) is a strongly connected automaton without any Letichevsky criteria. There exists a k > 0 such that for every a, b € A, a = b, if and only if there exists a pair p,q e X* with \p\ = |#|(modA:)19 and8(a, p) = 8(b, q). Lemma 4.20. Given an automaton A= (A, X, 8) without any Letichevsky criteria, a e A is a state of a strongly connected state-subautomaton of A if and only if there exists a nonempty word p e X* with 8(a, p) = a. Proof. Let a e A be a state of a strongly connected state-subautomaton of A. By definition, for every nonempty word q e X*, there exists a word r e X*wtih8(a,qr) = a. Conversely, suppose that 8(a, p) = a for some a e A and p € X*, p . Then for all prefixes p' of p and input letters x, y € X, 8(a, p'x) = 8(a, p'y). Therefore, for every q e X*, 8(a, q) = 5(a, r), where r is a prefix of p with \q\ = |r|(mod \p\). But then a generates a strongly connected state-subautomaton of A. We shall use the following consequence of the above statement. Proposition 4.21. Let A = (A, X, 8) be an automaton without any Letichevsky criteria. Moreover, suppose that a & A is not a state of any strongly connected statesubautomaton of'A. If'8 (b, p) = a for some b e A and nonempty p € X*, then8(a, q) ^ b, q e X*. Conversely, if 8(a,r) = c for some c e A and nonempty r e X*, then 8(c,q)^a,qeX*. d Next we prove the following proposition. Proposition 4.22. Given a class 1C of automata without any Letichevsky criteria, let A be an automaton which can be represented homomorphically by a general product of factors from JC. There exists an automaton A e /C, a q-power M of A with a single factor such that M. is an autonomous automaton; moreover, A can be represented homomorphically by a diagonal product of its connected state-subautomata and M.. 19

Recall that a = fc(modn) means n\a — b. Moreover, a

b(modn) means n/a — b.

4.2. Without Any Letichevsky Criteria

123

Proof. Consider the automaton A' — (A', X', <$')• We distinguish three cases. Case 1. There exists an A = (A, X, 5) e K, having a nontrivial cycle. In other words, there are distinct states a\,..., am e A, in > 1, and (not necessarily distinct) input letters xi,...,xm e X such that 5(a,-, jc,-) = a,+i(m0dm)- By Proposition 4.16, this implies that for every jc e X, 8(at, x) = a,+i(modm). Consider a fixed jc e X and let M = A(X, \A\ — 1, 8(a, q) ^ 8(a, q'\ then for every pair of words r, r' e X*, \r\ = \r'\, we have 8(a, qr) ^ 8(a, q'r'). Proof. Suppose that our statement does not hold, i.e., there are a e A, q, q', r, r' e X*, \q\ = \q'\ > \A\ - 1, |r| = |r'| having 8(a, q) ^= 8(a, q') and 8(a, qr) = 8(a, q'r'). Then, of course, |r| = |r'| > 0. We distinguish the following three cases. Case 1. There are qi,n, q2,r2,q{, r[,q'2,r'2 with q = q\r\ = q2r2,q' = q{r( = q2r2, \qi\ < \q2\, \q[\ < \q'2\ such that 8(a, q{) = 8(a,
This holds automatically if \q\ = \q'\ > \A\.

124

Chapter 4. Without Letichevsky's Criterion

Case2. Therearegi, r\, qi, TI with*? = q\r\ = qiri, \q\\ < \q2\, suchthat5(a, q\) = 8(a, q2),but5(a, q() ^ 8(a, q'2) holds for all distinct prefixes , of -Theseassumptions imply (\q\ =) \q'\ < \A\ — 1. On the other hand, \q\ = \q'\ > \A\ — 1 is supposed. Hence, we necessarily have \q\ = \q'\ = \A\ — 1. Thus we get 8(a, q() ^ 8(a, q2) for all distinct prefixes q{, q'2 o f q ' , where \q'\ = |A| — 1. This implies that for every d e A there exists a prefix q[ ofq' with 8(a, q() = d. Then for every d e A there exists an r( e X* having 8(d, r ) = 8(a, q'). On the other hand, we may assume 8(a, qrzr\) = 8(a, q) as in the previous case. Now we suppose 8(a,qr) = 8(a,q'rf) as before. Substituting d for 8(a,q) (= 8(a, qrzri)), there exists an r[ 6 X* holding 8(a, qr() = 8(a, q'). Put b = 8(a, qr)x (= 8(a,q'r'),c = 8(a,q),c' = 8(a,q'). Hence 8(b, zn) = c,8(b, zrir{) = c' and 8(c, r) — 8(c', r') = b (with c c'}. Therefore, by Proposition 2.70 we obtain again that A satisfies Letichevsky's criterion contrary to our assumptions. Case 3. Let 8(a, q\) / 8(a, q2) and 8(a, q{) ^ 8(a, q^) for all distinct prefixes q\, qi of q and q{,q'2 of q', respectively. Then|^| = \q'\ < \ A|-l. Recall that \q\ = \q'\ > \A\-l is also assumed. Thus \q\ = \q'\ = \A\ — 1, which implies that for every d € A there are ri,r{ € X* satisfying 8(d, n) = 8(a,q) and 8(d,r{) = 8 ( a , q f ) . Therefore, assuming 8(a, qr) = 8(a, q'r') for some r, r' 6 X*, and substituting d for 8(a, qr)(= 8(a, q'r')), we obtain 8(a, qrn) = 8(a, q}, 8(a, qrr{} = 5(a, q'} (with 5(a, qr) = 8(a, q'r')). Put c = 8(a, q), c' = 8(a, q'). Then 8(d, n) = c, 8(d, r() = c', 8(c, r) = 8(c', r') = d (with c £ c'). By Proposition 2.70, this implies that A satisfies Letichevsky's criterion, a contradiction again. Lemma 4.24. Let A = (A, X, 8) be an automaton without any Letichevsky criteria. For every state a € Awe have one of the following two possibilities: (1) There existq, q' € X*, \q\ = \q'\ > |A| - 1, suchthat8(a, qr) ^ 8(a, q'r') for every r,r' £X*, |r| = |r'|. (2) 8(a,q) = 8(a,q') for every q,qf € X*, \q\ = \q'\ > |A| - 1. Proof. Suppose that (1) does not hold. Then for every q, q' e X*, \q\ = \q'\ > |A| —1, there exist r, r' e X*, \r\ = \r'\, having 8(a, qr) = 8(a, q'r'). Using Lemma 4.23, 8(a, qr) = 8(a, q'r'), \r\ = |r'|, and \q\ = \q'\ > \A\ - 1 implies 8(a, q) = 8(a, q'). Thus (2) holds whenever (1) does not hold. The following statement is obvious. Lemma 4.25. Given a digraph V = (V, E), let v € V, pi, P2, p'2, Pi, P4 e V* such that PIP2P3VP4V and pip'2p3vp4v are walks and vp4V is a cycle. \p2\ = \p'2\(mod\p4V\)ifand only if there are positive integers k, I having \p\pip'3v(p4v)k\ = Ipip^Psv^tv)*]. Lemma 4.26. Let A = (A,X,8) be an automaton without any Letichevsky criteria. Consider a state a € A and suppose that there are q,q' € X*, \q\ = \q'\ |A| — 1, 8(a,q) 8(a,q'). Then there are q,q' (with \q\ = \q'\ \A\ - I) such that for an appropriate triplet u,v,v' € X*, q = uv and q' = uv', for which we have the following

4.2. Without Any Letichevsky Criteria

125

properties: (1) For every prefixes z ofv and z' ofv' with \z\ = \z'\ > 0, 8(a, uz) i=- 8(a, uz'). (2) For every prefixes wx ofz and w'x' ofz' with ww' A and x, x' € X, S(a, uw) = 8(a, uw') implies x = x'. (3) For every words r, r' e X* with \r\ = \r'\, 8(a, uvr) ^ 8(a, uv'r'). Proof. Consider a e A and suppose that our conditions hold; i.e., there are q, q' e X* having \q\ = \q'\ > \A\-l, 8(a,q) ^ 8 (a, q'). In this case, by Lemma 4.24,8 (a, qr) 8(a,q'r') holds for every r, r' e X* with |r| = |r'| > 0. Thus, it is enough to prove that we have properties (1) and (2). Then Proposition 4.17 implies that 8(a,q) and 8(a,q') generate autonomous state-subautomata of A. We will distinguish the following cases (omitting some of the analogous ones). Case 1. There are u, u', v, v', e X* such that q = uv, q' = u'v', 8(a, u) = 8(a, u') and for every nonempty prefixes r of v and r' of v', 8 (a, u)(= 8 (a, u')) (a , ') 8 (a, u') (= 8(a, u)) 96 8(a, ur), and 8(a, ur) ^ 8(a, u'r').21 Let, say, \u\ > \u'\ and let v" be a prefix of v' with \v"\ = \v\. Submit q' with uv" and then we will have our requirements. Case 2. There exists a prefix u of q having <5(a, u) = <5(a, q'). We shall use the fact that, in this case, v ^ X for v e X* with q = uv because of 8(a, q) ^ 8(a, q'). Let t2 e X* be a nonempty word with minimal length having 8(a, q't\t2) = 8(a, q't\) for some word t\ e X* and assume that ?2 is minimal in the sense that for every nonempty p € X*, 8(a, q't\p) = 8(a, q't\) implies \t2\ < \p\-22 Then, using that 8(a, qf) generates an autonomous state-subautomaton of A, we have q = uv, where u is a nonempty prefix of t\t\ for a suitable k > 0. To prove that in this case \u\ = j^r'Kmod |?2l) is impossible, assume the contrary. Recall again that 8(a,q') generates an autonomous state-subautomaton of A. But then, applying Lemma 4.25, there are words r, r' e X*, \r\ = \r'\, having 8(a, qr) = 8(a, q'r'). By Lemma 4.23, then |q| = |q'|<|A| — 1, contrary to our assumptions. Thus we have the following cases. Case 2.1. Suppose \u\ | |(mod |r2|) such that for all prefixes u\ of u and u ( of q' with uiu( i=. A, 8(a, u\) = 8(a, u() implies u\ — u and u\ = q'. Then we obtain our requirement again (having q = uv, where v is a nonempty prefix of t\t\ for a suitable k>0). Case 2.2. Assume \u\ ^ | |(mod lt 2 l) and, simultaneously, let, for some prefixes u\ of u and u\ of q', 8(a, MI) = 8(a, u\) such that u = u\v\, q' = u\v(\ furthermore, neither m = u\ = X nor v\ = v( = .23 If vi = X and v( X, then 8(a, u\} = 8(a, u'^) ^ 8(a, u'1v'lv)(= 8(a,uv)). Recall that u is a nonempty suffix of q. But then A has either Letichevsky's criterion or the semi-Letichevsky criterion, a contradiction. Similarly, it also leads to a contradiction if we assume v\ ^ A and v1 . Thus X ^ [vi, v(} can be assumed and we may also assume k$.{u\,u\] analogously. 21

H = u' = X is possible. The finiteness of the state set of A implies the existence of t\ and t223 If MI = u j = A. or v\ = i/j = A., then we may get either the previous case or this case considering appropriate M I , U ] , vi, Vj withuiu'j ^A-anduii/j 7^ A.. 22

126

Chapter 4. Without Letichevsky's Criterion

By \i<\ |0'|(mod|r2|), either | Ul | & K|(mod|f 2 |) or |vi| & K|(mod|f 2 |). Case 2.2.1. Suppose \u\\ ^ |ui|(mod |f2|) and let, say, |ui| < \v{\. Take a prefix vf of t\t2 for a suitable k > 0 with = \q\ and let us consider u\v\v' instead of q'. Case 2.2.2. Suppose |ui| = |u'p!(mod|f2|). Then |ui| |i/p!(mod|f2|). Let, say, l"i I < |M'I I- Take a prefix v' of fif| for a suitable k > 0 with (MI^I/! = \q\ and submit q' with «i i>i i/. In both Case 2.2.1 and Case 2.2.2, we have words24 it;, w\, W2, u/p w'2 e X*, A. ^ {w\,w'l}, \w\\ =£ lu/jKmodl l), w'2 is a prefix of wi (or, in the opposite case, W2 is a prefix of w'2), q = ww\W2,q' = ww^w^, such that S(a, ww\) = 8(a, ww'j), and 8(a, ww\) (= S(a, ww\}) generates an autonomous state-subautomaton of A. Then let iu, w\, W2, w , w'2 X* be arbitrary strings with these properties for which min(|w1 |, \w( |) is minimal. Suppose that for every nonempty proper prefixes z\ of w\ and z\ of w( we have 8(a, w) £ [8(a, wz\), 8(a, wz\)} and 8(a, wz\) •£ 8(a, wz[). Moreover, recall that 8(a, w) ^ 8(a, ww\)(= 8(a, ww{)) because 8(a, ww\)(= 8(a, ww()) generates an autonomous state-subautomaton of A. By these conditions, we are done, since we have our properties for q = ww\W2, q' = ww'^w^. Now we assume \w\ \ \w( |(mod j^l) such that for some prefixes z\ of w\ and z\ of w{, 8(a, z\) = 8(a, z( ) such that w\ = ziZ2, w{ = z\z'2\ furthermore, neither z\ = z\ = A. nor Z2 = z'2 — ..25 We can prove A {z\, z(, Z2, z'2] in a way similar to the proof of X i {u1, u'p vi,v{} in Case 2.2. Then either |zi| |zil(mod |r2|) or |z2| |z2|(mod |t2|). It remains to prove that these cases are impossible. If |z1| |zil(mod|f2l) and, say, \Z2\ > \Z2\, then considering the prefix w'2 of w'2 having \Z2W2\ = \z2w2\, we can submit w, w\, W2, w{, w'2 with w, z1, z2w2, z{, Z2W2, contrary to the the minimality of min(| w\ \, \ w{ \). If Izil = kil(mod |r2|) with |z2| |z2|(mod |t2|) and, say, |z1| > |z'|, then considering the prefix w'2 of w'2 having \z\w'2\ = | | , we can submit w, w\, w(, W2, w'2 with , Z2, w>2, u>2, contradicting the minimality of min(|w\|, \w( |). The proof is complete. We shall use the following definition. Let A = (A, X, 5) be an automaton. For every pair a, b € A, consider a fixed xa,b e X with 5(a, xa,b) = b if it exists and put pa(x) = xa,b if 8(a, x) = b. Moreover, put pa( ) = . and pa(x\ • • •xn) = pa(x\)pB(a,Xl)(x2} • - • Ps(a,xr-xn-i)(xn)- Clearly, then (a, w) = 8(a, pa(w)) holds for every w X*. Lemma 4.27. Let A= (A, X, 8) be an automaton without any Letichevsky criteria. Consider a, a, A, p e X* with S(a0, p) = a. If there are q,q' e X*, \pq\ = \pq'\ > |A| — 1, (a, q) 8(a, q'), then there are an input letter x e X, a word u € X*, and single-factor products B = (A, X, SB), C = (A, X, 8c) of A such that for every z, z' e X* with \z\ < |z'| < \pu\ + 1 we obtain ( (a0, z), 8c(ao, z)) ( (00, z'), 8c(aQ, z')); moreover, {(8B(ao,z),8c(ao, z))\z X*,\z\ < \pu\},{(8B(ao,z),8c(ao,z))\z = Zixz2,z\, Z2 € X*, |zi| = \pu\] and {(8B(ao, z), 8c(a0, z))\z = Zix'z2, x' eX,x' x, zi,z2e X*, \Z1\ = \pu\\ arepairwise disjoint sets. 24

In Case 2.2.1, of course, w = l,. If zi = zi = A. or Z2 = z — . then we may get either the previously discussed case or this case considering appropriate z\, z ,Z2,z'2 with z\z\ . and z2z2 •• 25

4.2. Without Any Letichevsky Criteria

127

Proof. Let A = (A, X, 5) be an automaton without any Letichevsky criteria. Consider a,OQ e A, p € X* with <5(a0, p) = a. If there are q,q' € X*, |p#| = \pq'\ > \A\ 1, S(a, q) ^ 8(a, q'), then we may assume q = uv and A, ' : AxX -> A having the following properties. Let*', y' e X be arbitrary fixed-input letters and for every b e A, y X, let

By Proposition 4.16, for every prefix p' of /?M, 8 (ao, p') £ [8(ao, pux\r), 8(ao, pux2r) | r e X*}. (We note that S(a0, p') 8(ao, p") also holds for every pair of distinct prefixes p', p" of pu.) On the other hand, by our assumptions and Lemma 4.23, for every r, r' e X*, \r\ = \r'\, it holds that S(ao, pux\zr} S(a0, pux2z'r'). Therefore, S(a0, pux\zr') ^ 8(ao, pux2z'r'). But then (8(a0, pux\zr), 8(ao, pux\zr)) (8(ao, pux\zr'), 8(ao, pux2Zfr')) is valid for every r, r' e X*. In addition, by property (1) of Lemma 4.26, for every prefix w of z and it/ of z' with |u;| = |u/|, ( (ao> pux\w), S( , pux\wj) (S(OQ, puxiw), 8(ao, pux2U>')). Therefore the single-factor products B = A(X, (p) and C = A(X, |A| — 1. Assume that 8(a, q) 8(a, q') holds for some q, q' e X*, \pq\ = \pq'\ < |A| — 1 and let q, q' be words of maximal length having this property. Then there are q = uv, q' = uv' (having \q\ = \q'\ < |A| — 1) such that we have the following properties: (1) For all prefixes r ofv andr' ofv' with \r\ = \r'\ > 0, we have 8(a, ur) ^ 8(a, Mr'). (2) For all prefixes wx of v and w'x' of v' with ww' ^ X and x,x' € X, 8(a, uw) = 8(a, MW/) implies x = x'. (3) For all distinct prefixes p\, P2 of pq, 8(a0, p\) 8(ao, P2)(4) For all words r, r' with \r\ = |r'| > \q\(= \q'\), 8(a, r) = 8(a, r'). Proof. Consider a e A and suppose that our conditions hold. Suppose that for every prefix u of q and u' of q', 8 (a, u) = 8(a, «')impliesw = u' = A.. Obviously then (1) and (2) hold.

128

Chapter 4. Without Letichevsky's Criterion

Now let q = uv, q' = u'v' such that MM' ^ X and<5(a, M) = 8(a, u'). Suppose that \u\ and |M'| are minimal in the sense that for every prefixes u" of M and u'" of u' with u"u"' ^ X and 8(a, u") = 8(a, u'"), we have {u", u'"} - {M, u'}. Assume that, say, M = A.. This implies 8(a, u') = a with u' /: X. But then, by Proposition 4.16, a generates an autonomous state-subautomaton of A. Therefore, 8(a,q) = 8(a,q'), a contradiction. Now let X £ {u, u'}. Clearly, v = v' = X is impossible because 8(a, q) ^ 8(a, q'}. Let, say, v = X. Then, by the minimality of M and u', we have (1) and (2) again. Next we assume X ^ {M, M', u, t/}. If |M| = |M'|, then we can consider, say, uv' instead of u'v'. Therefore, \u\ ^ \u'\ can be supposed. Assume that, say, |M| > \u'\. Then submit v with v", where v" is a subword of v' with \v"\ = \v\. Because of the minimality of \u\ and \u'\ for every subword w of M and w' of M' with |iy|, \w'\ > 0, we obtain that 8(a, iu) = 8(a, w') implies w = u and w' = u'. Submitting q, q', u, u', v, v' with uv", q', u, u', v", v' we get (1) and (2). Now we prove (3), omitting some analogous cases. If there are no distinct prefixes p(, p'2 € X* of pq' with 8(dQ, p() = 8(aQ, p'2), then change pq for pq' and pq' for pq. Therefore, in this case, we are ready. Otherwise, we may suppose (ao, p = 8(ao, p'2) for some distinct prefixes p{, p'2 e X* of pq'. Let, say, p( = p'2r' for some nonempty r' e X. By Proposition 4.16 and 8(ao, p'2) = 8(ao, p'2r'), this implies that 8(ciQ, p'2) generates an autonomous state-subautomaton B of A. Moreover, 8(GO, P'\) = 8(ay, p'2r') = S(CIQ, p'2), r' 7^ X implies that this autonomous state-subautomaton is strongly connected. Recall that bythemaximalityof \q\(= \q'\), 8(ao, pqx) — S(«o, pq'x') holds for every x, x' € X.Thus, 8(ao, pqx) is also a state of the state-subautomaton B of A. Then <$(a0, pq) ^ 8(a0, pq') and 8(ao, pqx) = 8(ao, pq'x') imply that 8(ciQ, pq) is not a state of B. Indeed, if 8(ao, pq) and 8(ao, pqx) are states of B with 8(ao, pq) ^ 8(ao, pq') (and \pq\ = \pq'\), then B cannot be autonomous, i.e., by Proposition 4.18, it is not strongly connected, a contradiction. Therefore, for every prefix p\ of pq, S(CIQ, p\) is not a state of B. Suppose that, contrary to our assumptions, S(OQ, p\) — S( , p2) holds for distinct prefixes p\ and p2 of pq and put, say, p\ = pir\ (where r1 X is assumed). In other words, <5(flo, P2r\) = 8(ao, p2) holds such that 8 (a0, pi) is not a state of B. But 8 (a0, pqx) = S(0o, Pq'x'), x, x' € X, implies that there exists an r2 € X* such that 8(ao, p^ri) isastateof B. Clearly, then A satisfies either Letichevsky's criterion or the semi-Letichevsky criterion, a contradiction. Finally, (4) is a direct consequence of the maximality of |#|(= \q'\). This completes the proof. Lemma 4.29. Let A = (A, X, 8) be an automaton without any Letichevsky criteria. Consider a pair a,ao e A of states and a word p e X* with 8(ao, p) = a and suppose that 8(a, r) = 8(a,r') holds for every r, r' e X*,\pr\ = \pr'\ > \A\ - I. Assume that8(a,q) / 8(a,q') holds for some q, q' e X*,\pq\ = \pq'\ < \A\ - 1 and let q,q' be words of maximal length having this property. Then there exist an input letter x, words u, v, v', w € X*, q = uv,q' = uv', v = xw such that for every nonnegative integer i < \pu\, there are <XQ — v\-powers B = (B, X, SB), C = (C, X, 8c) of A having states bo e B,CQ € C such that for every z, z' € X* with 0 < |z| < k'l < \P4\ ~i we have (8B(bo,z),8c(co,z)) ^ (8B(bo,z'),8c(co,z')), and, moreover

4.2. Without Any Letichevsky Criteria

129

{(&B(bo, z), &C(CQ, z))|z € X*, |z| < i}, {(SB(fco, z), <$c(c0, z))|z = Zi*z2, |zi| = i, |z2| < l M | - l } f l l W / { ( B(b0,z),«c(Co,z))|z € X * , Z = Z l J C ; Z 2 , | Z l | = I, *' € X,x' ^X,\Z2\

\pq\ —i} arepairwise disjoint sets.

<

Proof. Assume that our conditions hold. Then there are q,qf, u, v, v' e X*with# = uv, q' = uv' (having \q\ = \q'\ < \A\ — 1) such that we have properties (l)-(4) of Lemma 4.28. Consider yi,..., y\pq\, y( pu | +1 ,..., y'\pq\ e X such that, in order, p = yl-> y\p\, u = y\P\+i • - • y\Pu\, v = V|pu|+i • - • y[pq\, v' = y'lpu\+l • • • y[pqV Moreover, consider words pk, vt, v't e X*, where, in order, pk is a prefix of pu of length k, 0 < k < \pu\, vt is a prefix of v of length £, and vft is a prefix of v' of length t, 0 < t < \v\(= \v'\). Finally, let y' e X be an arbitrary fixed-input letter. By our assumptions, without any contradiction, we can define the functions X, \ : X -+ X, • X, j = 2 , . . . , \pu\ - i + 1, having the following properties. For every d € A, y e Y,

Let

Moreover, put

and put By Proposition 4.16, S(a0, p') {8(a0, p"), S(a0, puy\pu\+ir), S(a0, puy'lpu]+lr) | r e X*} holds for every pair of distinct prefixes p', p" of pu. But then, of course, for every z, z' € X* with |z| < \z'\ < \pq\ — i, we have SC(CQ, z) ^ &C(CQ, z'). On the other hand, by Lemma 4.28, we may also assume (a0, pur) (a0, pur') for all prefixes r of v and r' of v' with |r| = \r'\ > 0. Thus SB&Q, riy\pu\+ir2) ^ &B(bo, r'^'r^), x' e X,x' £ y| p «| + i,ri,r(,r 2 , € X*, |n| = |r{| = \pu\ - i, \r2\ = \r2\ < \v\. Therefore, (&B(bo, z), 5c(c0, z)) 7^ (f>B(bo, z'), 5c(c0, z')) if z and z' are arbitrary words with |z| <

130

Chapter 4. Without Letichevsky's Criterion

Iz'l < \pqI ~i26 or z = riy\pu\+ir2,zf = r[x'r^ wherex' e X,*'

Ji^i+i, n, r[, r2, r^ €

Then we obtain that for every z, z' e X* with \z\ < \z'\ < \pq\ we have (8&(bQ, z), 8c(co, z)) ^ (8B(bo, z'), 8c(c0, z')),and,moreover, {(8B(b0, z), 8c(c0, z))|z € X*, \z\ < i}, {(<$B(fco,z),<$c(co,z))|z = Ziy| p «|+iZ2, Izil = \pu\ -i, \Z2\ < \q\ - \u\] and {(8B(bo, z), 8c(co,z))\z € X*,z = z\x'z2, Izil = \pu\ -i, \Z2\ < \q\ - \u\,x' e X , x f ^ V| pK |+i}are D pairwise disjoint sets.28 Thus we have our statement, assuming x = y\pu\+iLemma 4.30. Let A = (A, X, 5) be an automaton without any Letichevsky criteria. Suppose that there exist a 6 A,xi,x2 e X, p,r,r' 6 X* having \r\ = \r'\ such that 8(a, px\z) / 8(apx2z')for every nonempty prefixes z ofr andz' ofr' with \z\ = \z'\. There are a state a' e A, an input letter x € X, and single-factor products B = (A, X, 8&), C = (A,X,8c) of A such that for every z, z' e X* with \z\ < \z'\ < \p\ + I we have (8B(a',z),8c(af,z-)) £ (8B(af, z'), 8c(ar, z')); moreover, {(8B(a',z),8c(a',z))\z € X*, |z| < |p|}, {(* B (fl',z),«c(fl' f z))|z = Zi*z 2 ,Zi,z 2 € X*,\zi\ = \pl\z2\ < \r\] and {(&B(af, z), 8c(a', z))|z = Zi^z 2 , x' e X, x' £ x, zi, Z2 6 X*, |zi| = \p\, |z2| < |r'|} are pairwise disjoint sets. Proof. If there are words s,s' e X, \px\rs\ = \px2r's'\ > \A\ — 1 with 8(a, px\rs} ^ 8(a, pxir's'}, then we have our statement applying Lemma 4.27. Thus let 8(a, px\rs) = 8(a, px2r's'} for all words s, s' X*, \px\rs\ = \pxir's'\ > \A\-l. Assume that, say, 8(a, px\r} is a state of a strongly connected state-subautomaton of A. We will prove that in this case, 8 (a, px2rr) is not a state of any strongly connected statesubautomaton of A. Indeed, if 8 (a, px2r') is also a state of an appropriate strongly connected state-subautomaton of A, then 8 (a, px\r} and 5 (a, px2r') are states of the same strongly connected state-subautomaton of A since 8(a, px\rs) = 8(a, px2r's'), s, s' e X*, \px\rs\ = \px2r's'\ | A| — 1. But then, by Proposition 4.19, 8(a, px\r} = 8(a, px2r'), a contradiction. Therefore, we may suppose that, say, 5 (a, px\ r) is not a state of any strongly connected state-subautomaton of A. Now we consider (not necessarily nonempty) words u,u',v,v' with r = uv, r' = u'v', 8(a, u) = 8(a, u') and suppose that u and u' are minimal in the sense that for every prefix u" of u and u'" ofu', 8(a, px\u"} — 8(a, px2u'") and u"u'" •£ X implies u" = u and u'" = u'. Observe that by our conditions, \u\ = \u'\ is impossible, i.e., \u\ ^ \u'\. Let v" be a prefix of v with \v"\ = \v'\ if |u| > \v'\ and let v" = vz be for an arbitrary word z e X* with |uz| = |v'|if |v| < |i/|. Now we prove that 8(a, p\) ^ 8(a, p2} for all nonempty prefixes p\ of px\uv and p2 of px2u'v" with \pi\ = \p2\ > \p\. If v" = v', then this statement is true because of the conditions of our lemma. Thus we may assume v" ^ v' and max(|w|, |w'|) > 0. If \P!\ = \p2\ < mm(\pxiu\, \px2u'\), then we have 8(a, p\) ^ 8(a, p2) by our conditions. 26

ThenSc(bo,z)^Sc(b0,z'). Then^(c 0 ,z)^6 B (co,z'). 28 Clearly, i = 0 is possible and then {(5s(i0, z), SC(CQ, z))|z e X*, |z| < i} = 0. 27

4.3. Networks of Automata Without Any Letichevsky Criteria

131

Suppose\pi\ = \p2\ > min(|px1u|, |px 2 u ' )-Ifi ?// isa(proper)subwordofi',then|M| < \u'\ should hold. In other words, there exists a nonempty q e X* with 8(a, P2q) = 8(a, p\). By Proposition 4.21, 8(a, p^q) = 8(a, p\) = 8(a, p2) would imply that 8(a, p\) is a state of a strongly connected subautomaton of A. But then 8(a, px\r) also should have this property, contrary of our assumptions. Hence, we obtain 8(a, p\) ^ 8(a, p2). Now we study when v" = vz for some nonempty z e X*. Then \u\ > \u'\. We may suppose \P\\ = \P2\ > min(|/>jciM|, Ip^w'l) again. But then there exists a nonempty q e X* having 8(a, p\q) = 8(a, p-i). Hence, similar to before, we also receive 8(a, p\) ^ 8(a, p-i) as a consequence of Proposition 4.21. Thus, we may assume for the considered words r, r' that for every z, z\, Z2,z', z\, z'2 with r = zziZ2, r' = z'z'iZ2 we obtain z\ = z\ whenever 8(a, px\uz) = 8(a, px2u'z') with max(|w|, |M'|) > 0 and \z\\ = \z\\. In other words, if p' is a subword of px\r or px2r' and there are x, x' X having 8(a, p'x) 8(a, p'x'), then p' = p should hold. Of course, we also have this property ifthere are no prefixes u of r or u' of r'with (a, px\u) = 8(a, px2u'). Therefore, we can define (p : A x X -> A and A hi the following manner. Let x', y' € X be an arbitrary fixed input letter; moreover, for every pair b e A, y e X, let

Then, similar to the proof of Lemma 4.27, because of Proposition 4.16, 8(a, p'} $ [8(a, p"),8(a, px\z),8(a, px2z') \ z, z' e X*, z is a prefix of r,z' is a prefix of r'} holds for every pair of distinct prefixes p', p" of p. On the other hand, by our assumptions, for all prefixes z of r and z' of r' with |z| = \z'\, it holds that 8(a, px\z) 8(a, px2z'}. Therefore, 8(a, pxiz1) 8(a, px2z'). But then (8(a, px1z), 5(a, pxiz)) (&(a, px\z), 8(a, px2z')} is valid for every prefix z of r and z' of r'. Therefore, by a' = a, the single-factor products B = A(X, (p) and C = A(X, ') satisfy the conditions of our Lemma 4.30.

4.3

Networks of Automata Without Any Letichevsky Criteria

In this section we show that some very restricted types of networking (in terms of the number of incoming links and feedback) already suffice for realizing the computational capacity obtainable by unrestricted networking of automata that satisfy neither the Letichevsky nor the semi-Letichevsky criterion. In particular, automata networks whose components have no more than one incoming link and receive no feedback at all (even about their own states) are all that will be required. Thus, if components are too simple (without any Letichevsky criteria), then no amount of cleverness or complexity in networking can achieve more computationally than this simple restricted type of networking. Let A = (A, X, 5) be an arbitrary automaton without any Letichevsky criteria. Consider a pair a A, p e X* and suppose p = x\.....xm with x\,.. .,xm e X. Put

132

Chapter 4. Without Letichevsky's Criterion

po = A and pk = x\ • • -Xk, 1 < k < m. By Proposition 4.16, for every 0 < k < t < m, 8(a, pk) = 8(a, pt) implies 8(a, ptf} = 8(a,pty),x,y € X. Therefore, we can define the automaton Aa,p = (A0tp, X, 8a,p) such that Afl;p = {a} U [8(a, x\ • • •*,) \ i = 1,..., m} U {8(a, x\ • '-xmq) \ q e X*}; moreover, for any x e X, &a n^., we have that Aa,p is an autonomous automaton which can be represented by a single-factor product of A. Proof. By Proposition 4.16, for every a €. A, p\, pi e X*, x\,X2 € X, 8(a, p\x\p2) = 8(a, p\} implies 8(a, p\x\) = 8(a, p\X2). Hence, for every pair yi, yz e X, we obtain 8(a,q\yi) = 8(a,q2y2) whenever 8(a, q\) = 8(a,q2) such that q\ and qi are distinct prefixes of the same word. Then, for every pair a e A, p e X*, we can define the singlefactor product B — A(X, (p) such that for every pair b € A, x € X,

By the construction of 13 and Proposition 4.17, the state 8 (a, p) of the automaton B generates an autonomous state-subautomaton. Clearly, then the state a of the automaton B also generates an autonomous state-subautomaton B'. It is easy to prove that the state-subautomaton B' of B coincides with the automaton Aa,p. n Proposition 4.32. Let B = A\ x • • • x An(X, tp\,..., 0. Let there be given a positive integer t e {l,...,n}, a state a € At, and a nonempty word p = z\ • • • zm, z\,... zm £ X t . l f there exists a state a' with double occurrences in the sequence a, 8t(a, z\), ...,8t(a,zi--- zm), then, by Proposition 4.16, a' generates an autonomous state-subautomaton of APut, in order, At,a,p = (At)a,P, A,,a

p — (8t)a,p. Therefore At>a,p = (At,a,p, Xt, 8tp = {a}U{8(a, z\ • • -z,) | i = 1, 29

Recall that a diagonal product of automata with a single factor coincides with a ^-product of these single factors. (See Proposition 2.57.)

4.3. Networks of Automata Without Any Letichevsky Criteria

133

..., m] U {S(a, zi • • • zmq) \ q e X*}, and, moreover, for any x e Xt, 8t,aip(a, x) = 8t(a, zi), 8t,a m, x, y e X,. Thus, for every r e {1,..., n}, a e At, p e X,*, |p| = m, A,a,P is an autonomous automaton; moreover, for every q e X*, 8t,a,P(a, pq) = 8t(a, pq). Simultaneously, At,a,p preserves the property that it is without any Letichevsky criteria. Let B' = (B', X, ') be an arbitrary connected state-subautomaton of the product B and let bo = (&0)i, • • •, ) e B', bott € At, t = 1,..., n, denote a state for which B' is connected. B is autonomous, and thus B' should be also autonomous. Let p e X* with \p\ = m be given and for any t € {1,..., }, put pt = ,«)• r) = 5/((^o,i, • •., Z?o,n), ^")- Then we also have that 5x(( • • •, £o,n), ) = <$'((fco,i, • • • > &o,»)> P) is a state both of Aland H'. But then, for every t e {1,..., n}, the fth component of ^((^o.i. • • •, ^o,«), p) generates the same autonomous state-subautomaton in At,bol,Pt and At. Hence, by the structure of M and B', for every p, q € X* with \p\ = m, we can also get 8^(b0,1, • • • , bo,n), pr) = 8'((bQti,..., b0 ) pr). This completes the proof. By Propositions 4.32 and 4.22, we can derive the next statement. Corollary 4.33. Let B = A\ x • • • x An(X,
(flj,...,fl;_1,fl;.«;+P---X) = *(fl,/o. K <_iX,<«,...,<) = <*(«>/>"). But then, by Proposition 4.16, this state component a't of At generates an autonomous state-subautomaton in At. Thus we obtain the same product A if we assume that the values of (pt (a{,..., a,_ l5 a't, a't+l, ...,a'n,x) md(pt(a'{,..., a't'_lt a't, a" +1 ,..., a£, x) are unambiguously defined by the state a't and thus, for every x', x" e X, < p t ( a ( , . . . , a^_ p a't, a't+l, ...,a'n,x') = (pt(a'{,... ,a"_va't,a"+l,... ,a^,jc"). On the other hand, it is clear that "A 5! HA- Thus, because of |p| = n^, the fth component of the state vector 5 (a, p) generates an autonomous state-subautomaton of At. Thus we get the same product automaton A if we suppose that for every state ( a j , . . . , a'n} — 8(a, pq), q € X*, and x e X, the value of < p t ( a { , . . . , a'n, jc) is unambiguously defined by the state component a'r

134

Chapter 4. Without Letichevsky's Criterion

Having these assumptions, we can construct a product A = ( A , X , 8 ) = AI x • • • x An(X, ( p { , . . . , (p'n) of the automata At = (At, X t , 8 t ) in the following way. For every (a\,..., an) € A, x e X, t € { I , . . . , n],

But then the state a of this product generates the automaton Aa,p as a state-subautomaton. Finally, by Lemma 4.31, Aa,P should be autonomous, as we have stated. D Consider an automaton A = ( A , X , 8 ) without any Letichevsky criteria and let 0o e A be fixed. For an arbitrary pair k, t of positive integers, put PA,OO(X, k,l) = * if 8(a.Q, px\) = 8(ao, px2) holds for every p e X*, \p\ = k — 1 and x\,X2 € X. Moreover, put PA,OO(X, k, V) = * if for every a = 8(ao, p), p € X*, \p\ = k — 1, property (1) of Lemma 4.24 holds, and, simultaneously, t>tk, where -4 denotes the length of the words q, q' € X*, \q\ — \q'\ having maximal length such that 8(a,q) = 8(a,q'); furthermore, 8(a, s) 8(a, s') for all nonempty prefixes s of q and s' of q' with \s\ = \s'\. Otherwise put AA,«O(*> *• *) = *-3° to addition, put PA,OV(XI • • • xn) = pA,a0(x\, 1, k)pA = ( D , X , 8') with D = (PA ,a0(p} I P € X*,\P\<\A\],

Consider a positive integer t e {!,...,«}, a state a € Xt, and a nonempty word p = Zl • -'ZnA,Zl, . ..ZnA & Xt.

Let pi,..., pu be a complete list of all words of length of HA in X*.

Lemma 4.37. The diagonal product D Aa0ta1 A • • • AAio,pu homomorphically represents A. Proof. By Proposition 4.36, for every p, q e X*, PA,a0(P) = PA,a0(q) implies 8'(ao, p) = 8'(ao, q). Thus, we can unambiguously define the mapping i/r : D x AaQtpl x • • • x AaQtpu -> 30 Thus wealsoput/o^oQ^, k, (.) = x if there area = <5(ao, p), p € X*, \p\ — k — l, such that we have property (1) of Lemma 4.24.

4.3. Networks of Automata Without Any Letichevsky Criteria

1 35

A such that (1) \fr(X,OQ, ...,oo)=«o; (2) for any p e X* with \p\ < nA, 1r((8'( , p), 5flo,pl(ao, p),..., S (a0, p))) = <Wp, (a0, p), where p, is the first word in the list p\,...,pu such that for the prefix of/?' of p, of length \p\, 0.4,00 (X) = PA^pY (3) for any pair p,q e X* with \p\ = nA, &((8'(X, pq), 8^(00, pq)..., 5oo,pB(«o, />#))) = 5ao,ft(ao> M)> where /?, is the first word in the list p\,..., /?„ such that pA,a<>(pi) = PA,OO(P)Recall that for all words r e X* of length nA, 8(ao,r) generates an autonomous subautomaton in A. By this observation, using Proposition 4.36, we have that ^ is a statehomomorphism of the diagonal product D Aao,pl A • • • Aao,pu onto A. By Lemma 4.34 and Proposition 4.32, each of the automata Aio.p,i = ! , . • • , « , can be represented homomorphically by a diagonal product of a single-factor product of the factors of A. For every i = 1,..., nA, x e X, define £?I>JC = (fi,, X, <$,,*) in the following way. If PA,OO(X, i,£) = * for every positive integer t, then let 5, = {0}, S,-)JC(0, z) = 0, z e X. If/o^>ao(jc, i, ^) = Jc for every A: e X and positive integer £, then let J5, = {0,1, . . . , / — 1, *, x} with

Otherwise, denote m, the maximal positive integer for which PA,a0 (x, i, m,-) = x, x e X and define B(- = {0,1,..., i - 1, *} U {(x, t) \t = 1,..., m,},

Lemma 4.38. Let x\,..,, xs be an arrangement of the elements of the input set X. The diagonal product B\tXl A • • • B\,XS A • • • ABnA<Xl A • • • ABnAtXs homomorphically represents the above defined automaton D. Proof. Let D' = (D', X, 8") denote the state-subautomaton of this diagonal product BI,XI A • • -Bi>Xs A • • • BnA<Xi A • • • BnA<Xs generated by the state (0,..., 0). It is easy to prove that ^ : B[xlx--.xBlxA -» Bwith^((5Ul(0, p),...,S U i (0, p),..., ^.(O, p),..., Sn^s (0, />))) = <5'(A,, /?) is a state homomorphism of £>' onto T>. Lemma 4.39. Given an integer i > 0, an automaton A = (A,X, 5) without any Letichevsky criteria, states OQ, a € A, vw/tfa p, i — 1, \pq\ = \pq'\ > |A| — 1, let

136

Chapter 4. Without Letichevsky's Criterion

5(a0, P) = a and 8(a, qr) ^ 5(o, q'r')for every r, r' 6 X*, \r\ = \r'\. Then BitX, x € X can be represented homomorphically by a single factor product of A. Proof. By our assumptions, the state a e A of the automaton A = (A, X, «5) has property (1) of Lemma 4.24. Then we can apply Lemma 4.27 provided that \pu\ > i — 1. In more detail, we can define the automata B and C as in Lemma 4.27. Obviously, then for an appropriate nonnegative integer j > \pu\ and for every u' e X*,\u'\ = j, there exists x e X such that, whenever i > 1, for every xf, y i , . . . , y/_i e X, x' ^ x, the states (SB(a0, u'), 8c(a0, u')), (8B(a0, w'yO, 8c(a0, u'yi)),..., (8B(a0, u'yi • • • y,--i), 8c(a0, u'yi • - • y/_i)), (8s(ao, u'y\ - • • yi-ix), 8c(aQ, u'y\ • • • y,_i*)) of the diagonal product B&.C are distinct. Similarly, whenever / = 1, for every x' e X,x' ^ x, the states (5B(a0, M'), 8c(a0, u')), (5B(oo, u'x), 8c(a0, u'x)), (8B(aQ, u'x'), 8c(aQ, u'x')) of the diagonal product #AC are distinct. In addition, {(5(g(ao, z), 8c(ao, z))\z = z\xz2, z\, Z2 € X*, \zi\ = i + j - 1} and {(5(B(a0,z), 5c(a0, z))|z=zi*'z2,*' e X,x' / x,z\,Z2 € X*, \z\\ = i + j — 1} are disjoint sets. Clearly, then the mapping ty with i{r((8B(aQ, u'), 8c(ao, M'))) = 0, if((8B(a0, u'v), 8c(aQ, u'v}}} = m,v e X*,\v\ = m, m = 1 , . . . , i 1, if((SB(a0,u'vxr),Sc(ao,ufvxr)')) = x,v,r e X*,\v\ = i - 1, if((8B(ao,u'vx'r)t 8c(ao, u'vx'r)}} = *, x' e X, x' x, v, r e X*, \v\ = i — 1, is a state-homomorphism of an appropriate state-subautomaton of B AC onto BI,X . Lemma 4.40. Given an integer i > 0 an automaton A= (A, X, 8) without any Letichevsky criteria, Iet8(a, q) = 5(a, q') for every a € A, q, q' € X* having \q\ = \q'\ > \A\ - I for which there are ao e A, p € X*, q", q'" with the properties \p\ = i — l, \q"\ = \q'"\ < \A\ — I and 8(ao, p) = a, 5(a, q") ^ 8(a, q'"). Suppose that \q"\(= \q'"\) is maximal with this property. Then BI!X,X € X can be represented homomorphically by an otQ-v\-power of A. Proof. By our conditions, the automaton A has condition (2) of Lemma 4.24. Then we can apply Lemma 4.29 assuming that \pu\>i — \. (Then, by our assumptions, there exists a maximal positive integer m, with PA,OO(X> *>m<) = x- Moreover, m, = \q"\ = \q"'\ > 0.) Clearly, then the mapping $ with ^((5 B (feo,z),5 c (c 0 ,z))) = |z|,z € X*,0 < |z| < i, ^((&13(bo, PZIXZ2~),8C(C0, ZiXZ2))) = (X,\Z2\ + l ) , Z l , Z 2 € X*, |Zl| = / - 1,0 <

\Z2\ < nii, is((8B(bo,zixz2),8c(co,zixz2)V = *,zi,Z2 e X*, \z\\ = i - l , |z2| > m,-, ^((8B(bQ,zixfZ2),8c(c0lzix'z2^ = *,x',x' e X*,xf £x,zi,Z2£ X*, \zi\ = i - l,is a state-homomorphism of an appropriate state-subautomaton of B AC onto B{tX. For every class K, of automata without any Letichevsky criteria, put Mk = [ I , . . . , nB] if there exists a B € JC such that for every A € k, n& > n^. Otherwise, let Afc be the set of all positive integers. Lemma 4.41. Consider a class /C of automata without any Letichevsky criteria. Suppose that for every A = (A', X', 8') € /C, a' € A', yi, y2 € X', p', q, q' € X'*, fc > 0, with k < \p'l \p'yiq\ = \p'y2q'\ < \A\ - 1, 8'(a', p'yiq) £ &'(a1, p'y2q'}, there exist A = (A,X,8) € / C , f l € A,xi,x2 € X,p,r,r' € X* having \p\ =k,\r\ = \r'\ = |o|(= |o'|) 5MC/I f/raf 8(a, px\z) / 5(a, px2z'}for all prefixes z ofr and z' ofr' with \z\ = \z'\. Then for every pair i e Af/c, x 6 X, BitX can be represented homomorphically by a single factor product of A

4.3. Networks of Automata Without Any Letichevsky Criteria

137

Proof. By our assumptions, we can apply Lemma 4.30. (Then, by our assumptions, there exists a maximal positive integer m, such that PA,a0(X, i , m f ) = x. Moreover, m, = \q\ = \q'\ > 0.) Clearly, then the mapping V with ((8B(a,z), 8c(a, z))) = |z|,z e X*, 0 < |z| < i, is((8t3(a,zixz2),8c(a,zixz2))) = (x, |z2| + l),zi,Z2 e X*, |zi| = i-1,0 < \Z2\ < mt, if((8B(a,Zixz2),8c(a,Zixz2))) = *,Zi,Z2 € X*, |zi| = i - 1, |Z2| > »»,•, ^((SB(a.zi*'z2),Sc(fl,zi*'z2))) = *,x' e X,x' ^ x,zi,Z2 e X*, |zi| = i - 1, is a state-homomorphism of a state-subautomaton of B AC onto . Lemma 4.42. Le? 1C be a class of automata without any Letichevsky criteria and assume that there exist integers k, k' > 0 such that \p\ ^ k whenever A = (A, X, 8) e /C, a € A, xi,X2 e X, p, r, r' € X* having |r| = |r'| = fc' such that 8(a, px\z) =£ 8(a, px2z')for all prefixes z o f r and z' ofr' with \z\ = \z'\. Then all of the qi-products of factors in 1C preserve this property. Proof. Consider an automaton A = (A, X, 8) e /C. By Lemma 4.24, for every a € A we have one of the following two possibilities: (1) There exist q,q' e X*, \q\ = \q'\ > |A| - 1 such that 8(a, qr) r , r ' e X * , |r| = |r'|. (2) S(a, ?) = ( ) for every?,?' e X*, \q\ = \q'\ > \A\ - 1.

8(a, q'r') for every

By our conditions, we have \p\ ^kin both cases whenever x\,X2 € X, p, r, r' e X* with |r | = |r'| = k' such that 8(a, px\z} i=- 8(a, px2z'} for all prefixes z of r and z' of r' with |z| = |z'|. By the above properties (1) and (2), it is clear that all single-factor products of A preserve this property. On the other hand, it is also clear that a diagonal product of automata has the conditions of our statement if all of its factors have it. By Proposition 2.57, this completes the proof. Lemma 4.43. Let 1C be a class of automata without any Letichevsky criteria and assume that there exist integers k, t > 0 such that for appropriate p,r,r'eX* with \p\ = k, \r\ = \r'\ = i we have that there are an automaton A = (A, X, 5) e /C, state a € A, input letters x\,X2 € X, such that 8(a, px\z) ^ 8(a, px2z'} for all prefixes z of r and z' of r' with \z\ = \z'\. Then for every integer k' with k' < k there are p,r,r' e X* with \p\ = k',\r\ = \r'\ = t + k — k' such that an appropriate ctQ-v\-power A = (A, X, 8) of an automaton in 1C also will have a state a € A having the above property. Proof. Consider an automaton A = (A, X, 5) 6 1C. By Lemma 4.24, for every a € A we have one of the following two possibilities: (1) There exist?, q' € X*, \q\ = \q'\ > |A| - 1 such that 8(a, qr) ^ 8(a, q'r') for every r , r ' e X * , |r| = |r'|. (2) 8(a,q) = 8(a,q') for every?,?' € X*, \q\ = \q'\ > |A| - 1. Suppose that (1) holds for some A = (A, X, 8) e /C, a e A, with a long enough q (and q') such that there are p,r,r' e X * , x i , X 2 e X having \p\ > k, \r\ = |r'| =t+k-k', px\r is a prefix of ?, and pxjr' is a prefix of q' for which 8(a, px\z) 8(a, px2z') for all

138

Chapter 4. Without Letichevsky's Criterion

prefixes z of r and z' of r' with |z| = |z'|. Then the automaton A with its state a e A also has the properties of our statement. Otherwise we have to assume that (1) does not hold for any A = (A, X, 8) e /C, a e A, q, q' and p, r, r' e X*, x\, X2 € X having \p\ > k, \r\ = \r'\ with the above properties. In this case we should have an automaton A = (A, X, 8) e /C, a state a G A such that (2) holds; moreover, there are p, r,r'eX*,xi,X2€X having \p\ > k, \r\ = \r'\ = t for which 8(a, px\z) (a, px2z') for all prefixes z of r and z' of r' with |z| = |z'|. Then, similar to the proof of Lemma 4.29, we can construct a diagonal product of two UQ-VI -powers of A such that it has the conditions of our statement. Consider yi y^,, yf p | + 1 ,..., y']pxiz] € X such that, in order, p = yi • • • y\p\, xi = y\p\+i, x2 = y'lpl+1, z = y\p\+2 • • • y\pxit\, z' = y[p|+2 • • • y[px^. Moreover, consider words pm, vn, v'n e X*, where, in order, pm is a prefix of p of length m, 1 < m < \p\, rn is a prefix of r of length n, and r'n is a prefix of r' of length n, 1 < n < \r\(= |r'|). In addition, let x' € X be an arbitrary fixed-input letter. By our assumptions, without any contradiction, for every nonnegative integer i < \p\ we can define the functions tp\ : X -> X, X, X, (p'}• : A x X -> X, j =2, ...,\p\ — i, having the following properties:

Let 13 = (B, X, 8B) = A\pl~i+l(X, < p l t . . . , , z) ^ &e(b, z')- On the other hand, by Lemma 4.28, we may also assume 8(a, px\w) ^ 8(a, px2wf) for all prefixes w of r and w/ of r' with |u;| = lit;'). Therefore, (5B(^, z), <5c(c, z)) (5B( , z'), <5c(c, z')) if z and z' are arbitrary words with |z| < |z'| < \pxir\31 orz = zi^iZz andz' = z^z^, Izil = Iz'J = \p\,x e X,x ^ x\, 0 < |^| = |z'|, where 12 is a prefix of r and 22 is a prefix of r'.32 Then we obtain that for every z, z' € X* with |z| < \z'\ < |pjcir| we have (<$#(&, z), 5c(c,z)) ^ (S B (fc,z'),<$c(c,z')); moreover { (*, z),«c(c,z))|z € X*, |z| < »}, { B 31 Then5c(ft^)^5c(*,z'). 32 Then3 B (c,z)^ e(c,z').

4.3. Networks of Automata Without Any Letichevsky Criteria

139

and

are

pairwise disjoint sets. Then we have our statement for The proof is complete. Now we are ready to prove the next theorem. Theorem 4.44. Let K be a class of automata without any Letichevsky criteria. The following statements are equivalent: (1) Every general product of factors from 1C can also be represented homomorphically by a ql -product of the factors from 1C. with (2) For every there exist having for all prefixes such that having z of r and Proof. First we assume that we have condition (2) of our statement and let be a product of automata, that each of At,t = I,. ..,n,is without any Letichevsky criteria). Next we prove that M can be represented homomorphically by a diagonal product N of automata such that each of its factors is a single-factor product of an appropriate factor of M. By Proposition 4.22, we can restrict ourselves to proving our statement to the connected state-subautomata of M. On the other hand, by Proposition 2.75, M and thus all of its connected state-subautomata of M preserve the property that they are without any Letichevsky criteria. Let A = (A, X, 8) be a connected state-subautomaton of M without any Letichevsky criteria. If A is autonomous, then we are done by Corollary 4.33. Then we may assume that A is nonautonomous and thus nA > 0. Let us denote again by ao a state for which the (nonautonomous) automaton A is connected; moreover, let ao = (a o ,1,..., ao,n), ao,t At. t = 1 n. Consider a complete list P1 D,, of all words of length of n in homomorphically represents A. By Lemma X*.Bv Lemma 4.37, , can be represented 4.34 and Proposition 4.32, each of the automata homomorphically by a diagonal product 0f a single-factor product 0f the factors 0f A. It remains to prove by (1) that D can be represented homomorphically by a qlproduct of factors from 1C. But it is a direct consequence of Lemmas 4.38 and 4.41. Now we assume that (2) does not hold. This implies that there exist A = (A', X', $') with such that for every having for every prefix z of r and z' of r' with |z| = |z'|, we have \p\ k. By Lemma 4.42, we obtain that every ql-product of these automata in K preserves this property. But, by Lemma 4.43 it can be shown that the ( o-V1 -product does not preserve this property. Thus we obtain this fact for the general product, too. This ends the proof. Next we prove the following proposition.

1 40

Chapter 4. Without Letichevsky's Criterion

Proposition 4.45. There exists an ao — v1-power M of an automaton A without any Letichevsky criteria such that M cannot be represented homomorphically by any ql -product of A. Proof. Let A = (A, X, 8) with A = { o, a 1 ,a 2 , a 3 ,a 4 }, {x1, x2],

Moreover, let B = (B, X, $') with A = {b0, b\, b2, b3, b4, b5}, [ x 1 , x 2 ] ,

Define the functions

In addition, give follows:

in the following way:

: {(a 1 ,a o ) , (a2, a1), (a3, a1), (a4, a2), (a4, a3), (a4,

a4)}

B as

is a state-isomorphism of a state-subautomaton of the a 0 -VI -power Obviously, onto B. On the other hand, bv an elementarv comoutation. we obtain Ax A for every diagonal product D = (D, Y, SD) of arbitrary singlefactor products of A, state d D, and input letters y1, y2 Y. Therefore, B cannot be rep•power A x A resented homomorphically by any ql-power of A. Thus the also cannot be represented homomorphically by any ql-power of A. We will also use the next statement. Lemma 4.46. If A is an automaton without any Letichevsky criteria, then every single-factor product of A can be represented homomorphically by an ao-v1-power of A. Proof. First we suppose that A is connected. Let us consider a single-factor product A -power M = A n A (X of the automaton A = (A, X, 8) and construct the

4.3.

Networks of Automata Without Any Letichevsky Criteria

1 41

of A in the following way. For every (a 1 ,..., anA .) € An A, let )(a i ,_ 1 ,x); moreover, let be an arbitrary fixed-element Denote by ao € A a state for which A is connected. Let B = be a statesubautomaton of the an-v1 -Dower M. of A generated bv its state (an an}. Then for everv with , and for every for some A such that a On the other hand, 8 (an, (an, )) generates an autonomous state-subautomaton in A(X, if \p\ n A. Thus, for every p. q. q' X* with I p\ = nA and lql = \q'\, 8(a o , ( o, pq)} = Thus, we obtain that B A with ((a 1 ,..., an A)) = anA is a statehomomorphism of B onto .A. If A is not connected, then considering Proposition 4.22, we may assume that it can be represented homomorphically by a diagonal product M.' of its connected statesubautomata and an autonomous automaton M. which is a q-product of A with a single factor. We have already proved that all connected state-subautomata of A can be represented homomorphically by an ao-v1-power of A. Obviously, the direct product of M and these ao-V1 -powers is an a0-V1 -power of A which homomorphically represents the diagonal product M!. By the transitive property of homomorphic representation, this completes the proof. Now we are ready to prove the following result. Theorem 4.47. Let K be a class of automata without any Letichevsky criteria. Then every general product of factors from 1C can be represented homomorphically by an ao-v1-product of the same factors.

Proof. Let M = A1 x • • • x An(X,

again be a product of automata At = (At, Xt, 8t), t = I,... ,n, (such that each of At, t = 1,..., n, is without Letichevsky criteria). Using Lemma 4.46, it is enough to prove that M. can be represented homomorphically by a diagonal product M of automata such that each of its factors is either a single-factor product of an appropriate factor of M. or an ao-v1-product of certain factors of M. By Proposition 4.22, we can restrict ourselves to proving our statement for the connected state-subautomata of M. On the other hand, by Proposition 2.75, M and thus all of its connected state-subautomata of M preserve the property that they are without any Letichevsky criteria. Let A = (A,X, 8) be a connected state-subautomaton of M. not having any Letichevsky criteria. If A is autonomous, then we are done by Corollary 4.33. Then we may assume that A is nonautonomous and thus nA > 0. Let us denote again by ao a state for which the (nonautonomous) automaton A is connected; moreover, let ao = (ao,1. ••• a o,n ),n) ao,t At, t — 1,... ,n. Consider a complete list p 1 , . . . , pu of all words of length of nA in X*. By Lemma 4.37, D A a 0 ) p l • • • ao,pu homomorphically represents A. By Lemma 4.34 and Proposition 4.32, each of the automata Aao,pi, i = 1 , . . . , u , can be represented homomorphically by a diagonal product of a single-factor product of the factors of M. Then it is enough to prove that D can be represented homomorphically by a diagonal product of oV1 -products and single-factor products of factors from M..

142

Chapter 4. Without Letichevsky's Criterion

Let x 1 , . . . , xs be an arrangement of the elements of the input set X. By Lemma 4.38, the diagonal product B I , X 1 A • • • B 1,Xs A • • • BnA,Xl A • • • BnA,Xs homomorphically represents the automaton D. To complete our proof we now show that each of B i , x , i = I,... , n A , x e X, can be represented homomorphically by either a single-factor product or an a0-V1 -product of factors from [ A 1 , . . . , An}. By Lemma 4.24, for every At = (At, Xt, t) e ( A 1 , . . . , An], there are two possibilities: (1) There exist a0, a e At, p, q, q' e X*, \p\ > i - 1, \q\ = \q'\ > \At\ - 1 such that (a0, P) = a and t(a, qr) t(a, q'r') for every r, r' e X*, \r\ = \r'\. (2) t(a, q) = t(a, q') holds for every a € At, p, q, q' e X* having t (a 0 , p) = a, p e X*,\p\=i-l,\q\ = \q'\> \A\-l. Suppose that there is an automaton At = (At, Xt, t) [ A 1 , . . . , An} having property (1). Then, applying Lemma 4.39, we get Bi, x as a diagonal product of single-factor products

of A.

In case (2) we can apply Lemma 4.40, assuming that \pu\ > i — 1. (Then, by our assumptions, there exists a maximal positive integer mi, with p (x, i, m,•) = x. Moreover, mi- = | -l| = | q - l | > 0 . ) ' This result directly implies the following two statements. Theorem 4.48. Let 1K be a class of automata without any Letichevsky criteria. Then every general product of factors from K can be represented homomorphically by an a o -product of the same factors. Theorem 4.49. Let K be a class of automata without any Letichevsky criteria. Then every general product of factors from 1C can be represented homomorphically by a v1-product of the same factors.

4.4

Product Hierarchies of Automata

Theorem 4.49 shows that single links already suffice for homomorphically representing any automata network built from automata without any Letichevsky criteria. In contrast, we are going to prove that the ao-Vi -hierarchy becomes strict for homomorphic representation if the component automata are permitted to satisfy the semi-Letichevsky criterion as we show in this section. Theorem 4.50, the main result of this section, implies even more: (i) (ii) (iii) (iv)

The vi,-hierarchy is strict for the homomorphic representation. The ao-vi,-hierarchy is strict for the homomorphic representation, The vi,-hierarchy is strict for the homomorphic simulation. The ao-vi,-hierarchy is strict for the homomorphic simulation.

Let n 1 be an integer and let Cn = (Cn, {x}, n) with Cn = { 1 , . . . , n } and x) = i + 1 (modn) for all i Cn. Thus Cn is a counter with length n. Let us consider the elevator 2 = ({0,1}, {x1, x2}, 2) so that (0, x1) = 0 and 2(0, x2) = 2 ( l , x 1 ) = X 2 ( l > 2) = 1. We set /C = { 2} U {Cp | p > 1 is a prime} and prove the following. n(i,

4.4. Product Hierarchies of Automata

143

Theorem 4.50. Given a fixed positive integer i, there exists an automaton M. which can be homomorphically represented by an ao-vi+1 -product of automata from 1C such that it cannot be simulated homomorphically by any Vi-product of automata from K. Proof. Let i be a fixed positive integer and let m be the product of the first i + 1 prime with M = {1,..., m + 1} and numbers. We define M

First we prove that M. can be homomorohicallv represented bv an an-vi+1 -product of automata from 1C. For each j = 1,..., i + 1, let pi denote the jth prime number. We with construct an ao-vi,+1 -product A

It is straightforward to show that A maps homomorphically onto M. Now we show that M. cannot be simulated by a vi,-product of automata from 1C. Assume to the contrary that a vi-product A = (A, X, 5) = A\ x • • • x An(X, 1 , . . . , n) of automata from 1C homomorphically simulates M. We may suppose that n is minimal with this property, i.e., if B is a vi,-product of automata from 1C which homomorphically simulates M, then the number of factors of B is at least n. Let A' A and let 1 : A'

1 44

Chapter 4. Without Letichevsky's Criterion

M, X* be mappings such that 1 is onto and for all a A' and z [x, y}, where it is assumed that We prove that m and | 2(x)| are relatively prime. Suppose the contrary and let d be an arbitrary prime number which divides m and | 2 (x) \. Because of the definition of 8' there exists a positive integer k and state a 3 A' with 8 (a, 2(x))km) = a with 1 (a) {1,..., m}. But then, by the structure of A, d \ 2(x) implies that there exists a positive integer l such that 8(a, ( 2 (x)) l ) = a and d leading to S'( 1 (a),x l ) = 1(a), (a) {1,..., m}, a contradiction. Therefore, m and 2 (x)) are relative primes. We show that m and I 2 (y) I are relatively prime. For this we suppose the contrary and Thend let d be a prime number which divides m and Therefore, d does not divide Because of the structure of M. there exists a positive integer k, a state a € A' with and ( But then, by the structure of A and d \ there exists a positive integer l such that d and a, contradicting (Of course, m and m — d + 1 are relative primes. Thus, indeed, Thus we obtain that m and are relatively prime. By this observation, A also homomorphically simulates M by the mappings M and with and Then we can also assume . In addition, we may choose A' such that the cardinality of A' is minimal. Let us partition A' as A' where and A1 = If a Ao and b A', then, by the minimality of the cardinality of A, there is a word u {x, y}* with 8(a, 2(u) = b). Therefore, if the jth component of ao is equal to 1 and Aj = 2 for some j — 1 , . . . , n and ao € ao, then the jth component of a is equal to 1 for all a € A'. But then we can get rid of the jth component obtaining a vi,-product of n — 1 factors that homomorphically simulates M. Since this contradicts the minimality of n we have that the jth component of a is necessarily 0 for all a Ao and j {1,..., n] with AJ = 2Now we show that for every a A1 there exists j {1,...,n} such that the jth component of a is equal to 1 and AJ = 2. Indeed, by the minimality of the cardinality of A', for every a A1 (= ~l(m + 1)) there exists an ao € Ao such that for a suitable u {x, y}*, 8(ao, 2(u)) = a. Because of |n 2(x)| = 2(y), (ao, 2(x )) = a also holds whenever for every j { 1 , . . . , n } , AJ = 2 implies that the jth component of a is 0. But (ao,2 (x 1u1 ))Ao, a contradiction. Now let a be a fixed state. We have 8(a, 2(y)) A1, so that the jth 1 l) component of the state 8(a, 2(y)) is equal to 1 and AJ — £2 for some j € {1,...,n}. Suppose that j really depends on its state variables having indices j 1 ,..., jt with t i. For .s = !,...,*, define rs = p if Aj; = Cp and rs, = 1 if Aj = 2- Let r be the product of the integers r 1 , . . . , rn. It is clear that m r. Thus, (a, ( 2 (x)) r ) (q) with € {2,..., m}. But then the jsth component of a and 8 (a, ( 2 (x)) r ) are equal for all s = I,... ,t. Therefore, the jth components of (a, 2(y)) and 8(a, 2(x) 2(y)) are equal to 1, which contradicts 8(a, 2 (x) 2 (y)) € Ao. This ends the proof.

4.5. Bibliographical Remarks

145

Let us summarize some of the results of this chapter for homomorphic representation by automata networks with component automata from a class K of non-Letichevsky automata. The ai,-product hierarchy collapses at i = 0 if K is without any Letichevsky criteria (Theorem 4.48) and at i = 1 if K satisfies the semi-Letichevsky criterion (Corollary 4.15). That is, in these two cases, no feedback at all, or only feedback of a component's own state to itself, respectively, suffices to achieve computationally what can be achieved with unrestricted feedback. Meanwhile, the v.,-product hierarchy (bounding the number of incoming links to components by i) collapses at i = 1 for automata without any Letichevsky criteria (Theorem 4.49); moreover, even ao-VI-products suffice (Theorem 4.47). Nevertheless, in the semi-Letichevsky case, if no feedback is allowed, then the number of permitted links can determine what can be homomorphically represented or homomorphically simulated. Taking into consideration that the concept of homomorphic simulation is more general than the concept of homomorphic representation, and, moreover, that the concept of vi,-product is more general than the concept of ao-vi[-product, by Theorem 4.50, we can derive that33 (1) the ao-vi,-hierarchy is strict for both homomorphic representation and homomorphic simulation, and (2) the vi,-hierarchy also has this property. The product hierarchies for the Letichevsky case are treated in detail in the next two chapters of this monograph (in particular, Theorems 5.27 and 6.15).

4.5

Bibliographical Remarks

Section 4.1. Lemmas 4.2 and 4.3 and Theorem 4.4 are essentially contained in Domosi and Gecseg [1992]. Corollary 4.15 is a consequence of the Esik-Horvath characterization theorem due to Z. Esik and Gy. Horvath [ 1983]. The other parts of this chapter are essentially new but they can also be derived from the results of Z. Esik and Gy. Horvath [1983]. Some related results are in Esik [1983]. Section 4.2. These technical observations on basic properties of automata without any Letichevsky criteria are new but more or less trivial. They are necessary to the description of some results in Section 4.3. Section 4.3. Theorem 4.47 was obtained by F. Gecseg and H. Jiirgensen [1991]. Theorem 4.48 issued from Z. Esik and Gy. Horvath [1983]. Theorem 4.49 is given in Gecseg and Imreh [1987]. The other results are new. Section 4.4. This section is based entirely on Domosi and Esik [1990] and Domosi, Esik, and Imreh [1989]. These results generalize the statements of P. Domosi and Z. Esik [1988d]. Some related characterizations are given in Imreh [1977], Gecseg [1986], Domosi and Esik [1987], Gecseg and Imreh [1987a, 1987b], Imreh [1988], Domosi and Gecseg [1989], Domosi [1990], and Domosi and Gecseg [1992]. 33

See also the introductory part of this section.

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Chapter 5

Letichevsky's Criterion

The application of two-state elements is very often used in engineering technology. We will show that this conventional solution is not the only possibility. We may build digital and electronic circuits using completely different structures. In particular, automata having Letichevsky's criterion and certain types of transformers (which realize feedback functions) can be also considered. The conventional methods make up just one special case where the applied automata are two-state flip-flop automata and the feedback functions are elementary logical units. Thisfact more or less is well known. But using our results, many other solutions can be derived. A further challenge of research is to determine which ones are important from the point of view of future technologies.

5.1

Homomorphic Simulation and the v2-Product

We start with a simple observation. Lemma 5.1. Let 1C denote a class of automata. Every v1-product of factors in 1C is an ao -product of loop products of factors in K. Let B = (B, {x', y'}, 8B) be the automaton where B = {0,1,1', 2} and

Moreover, let

be the automaton with Bo = {0, 1,1'} and

The following statement is obvious. 147

148

Chapter 5. Letichevsky's Criterion

Lemma 5.2. Consider a (general) power M = (Bn, X, 8) of B.If a,b Bn and u X* with 8(a, u) = b, and if no component of b is 2, then no component of a is 2. Suppose that no component of b is 2. If \u\ is even, then for each i . [n], the ith component of a is 0 if and only if the ith component of b is 0. If \u\ is odd, then for each i [n], the ith component of a is 0 if and only if the ith component of b is in {I, I'}. Next we prove the following lemma. Lemma 5.3. If a stronslv connected automaton A is homomorphically simulated bv a V2-power , then A is homomorphically simulated by some vl1-power Proof. Suppose that a V2-power M = (Bn, X, SM) = Bn (X, \,..., n) homomorphically simulates the strongly connected automaton A = (A, Y, 8) by the mappings \ : A' A (A' Bn), 2 : Y X*. Let D = (V, ) denote an appropriate graph for M such that the in-degree of each vertex is at most 2. Since A is strongly connected, we may assume that A' is strongly connected in the following sense: For any a, b A' there exists a word u Y* with 8 M ( a , 2(u)) = b. Define there exists Then, since A' is strongly connected, the set H is also strongly connected, i.e., for every pair a, b H there exists a word u € X* with S M ( a , u) = b. Thus, by Lemma 5.2, if the ith component of some state in H is 2, for some i € [n], then the ith component of each state in H is 2. Moreover, if for some i, j [n] there exists (a 1 ,..., an) H such that ai( = aj = 0 or ai, aj {I, I'}, then for all (b\,..., bn) H it holds that bi = bj = 0 or bi,bj {l,l'}. Let i denote any fixed integer with i € [n]. Let (y, i), (K,i) E denote the two edges of D with target i. (Without loss of generality we may assume that there are two such edges.) We show how to define the function i(. We will distinguish several cases. In each case, it will hold that if both (a\,..., an) and 8j^((a\,..., an), x) are in H, then

In fact, except for Case 1, we shall even have that the letters i an, x) are equal. Moreover, it will be clear that the functions depend at most on ai, and one of ai, and aK. If i € (j, k}, then we may take so from now on we assume that i {j, k\. Case 1. The ith component of some state in H is 2. Then the ith component of each state in H is 2. We define (a 1 ,..., an) = x' for all (a\,..., an) Bn. Case 2. The ith component of no state in H is 2 but there is a state in H whose j th or Kth component is 2. Then the j th component of each state in H is 2, or the k th component of each state in H is 2. For each (a\,..., an} Bn, define i ( a \ , . . . , a n , x} = i, ( b 1 , . . . , bn, x), where ( b 1 , . . . , bn) agrees with ( a . , . . . , an) except that bj = 2 if the jth component of each state in H is 2 and bk = 2 is the kth component of each state in H is 2.

5.1. Homomorphic Simulation and the v2-Product

1 49

Case 3. No state in H has its ith, jth, or kth component equal to 2. We divide this case into three subcases. Case 3.1. For all (a\,..., an) H, either ai, = aj, = 0 and ak € {1,1'} or ai, aj {1,1'} and ak = 0. Then for (a 1 ,..., an) € Bn, define

where (b 1 ,..., bn) is obtained from (a 1 ,..., an) by setting its jth component to 0. Case 3.2. For all (a\,..., an) H, either ai, = ak = 0 and a, {1,1'} or ai, ak {1, 1'}and aj, =0. This subcase is symmetrical to the previous one. For(a 1 ,... ,an) € Bn, define

where (b\,..., bn) is obtained from (a\,..., an) by setting its kth component to 0. Case 3.3. For all (a\,..., an) H, either ai, = aj =ak = 0 or ai, a,-, ak {1,1'}. For (a 1 ,..., an) € Bn, define

where ( b 1 , . . . , bn) is obtained from (a 1 ,..., an) by setting its jth and kth components to O. Since we have SM for all states (a 1 ,..., an) € H and x € X such that S M ( ( a 1 • • • , a n ) x ) € H, it follows that A is homomorphically simulated by Bn(X, 1 { , . . . , ( 'n) using the same mappings I : A' A (A' B n ), 2 : Y X*. Moreover, since each function {(a 1 ,..., an, x) depends at most on ai, and one of aj and ak, they define a vl1-power of B. Lemma 5.4. If a strongly connected automaton A is homomorphically simulated by a v\1-power Bn(X, 1 \,..., n), then A is homomorphically simulated by some v\-power with m n. Proof. Suppose that a v1-power M = (Bn , X , 8 M ) = B n ( X , 1 ' - - , n) homomorphically simulates a strongly connected automaton A = (A, Y, 5) by the mappings \ : A' A (A' B n ),2 : Y X*. We need to show that a vrpower B o m (X, {,..., 'n) for some m n homomorphically simulates A. When A has a single state, this is clear. Moreover, we may assume that there is no n' < n such that a v\l -power of B homomorphically simulates A. Let H = (b € Bn | there exists b' A', y Y, p, q X* : 2(y) = pq, 8 M (b', p) = b). Suppose that (a 1 ,..., an) € H. If ai, = 2, for some i € [n], then since .A is strongly connected, bi( = 2 for all (b 1 ,..., bn) H. But then n > 1 and A is homomorphically simulated by some vl1-power Bn~l(X, 1 '{,..., n_1), contrary to our assumptions. Thus, no component of any state in H is 2. For each i [n], ( a 1 , . . . , an)

1 50

Chapter 5. Letichevsky's Criterion

and x € X, define (ai, ...,an,x) = i(b\,..., bn, x), where (b\,..., bn) is obtained from (a 1 ,..., n) by setting its ith component to 0. Thus, when ai, = 0, then ' i (a 1 ,..., an, x) = i(a 1 , ...,a n , x), and if ai{ {1,1'}, then SB(ai, (a 1 , ...,an, x)) = 8Bo(ai, (a\,..., an, x)) whenever B(ai ,( (ai,...,an, x)) 2. Since this holds for all i [ n], it follows that A is also homomorphically simulated by , completing the proof. Lemma 5.5. Suppose that M = B n o (X, \,..., ( n) is a loop power, so that its underlying graph is a cycle. Suppose that (a\,..., an), (b\,..., bn) Bno such that ai, = 0 if and only if bi = 0, i 6 (1,...,«}. Then for every word u € X* whose length is a multiple of n it holds that ai, = bi, implies Proof. Let us consider a loop power M. with the underlying graph D = (V, {(i, i + l (mod n)) | i V}) and a pair(a 1 ,..., an), (b\, . . . , b n ) € B o having our conditions. Suppose that ai = bi for some i {1,..., n}. Then i+\ (mod n) (a1, • • •, a., x) = ( i+1 (mod n ) ( b 1 , . . . , b n „ x ) for every x € X. Therefore, if ai+1(mod n) = bi+1(mod n) = 0, then the i + 1 (mod n)th components of 5 ((a 1 ,..., an), x) and ((b 1 ,..., bn„), x) coincide. On the other hand, by the definition of B0,, if ai+1(mod n), b i+1(modn) {1, 1'} then the i + 1 (mod n)th components of S M ( ( a 1 , . . . , an), x) and M ((b 1 ) • • •. bn}, x) are equal to 0. By these observations, it is easy that for every word u € X*, the i + \u\ (mod n)th components of 5x((a 1 ,..., an), u) and SM ((b 1 , • • •. bn), u) are the same. Lemma 5.6. Let M. = (M, X, M) be a loop power Of Bo having n factors. Consider ( a 1 , . . . , a n ) Bno with either ai = ai+1(mod n) = 0 or a if , a i+1(modn ) {1, 1'} for some i {!,..., n}. Consider a word w X* of even length. Then 8j^((a\,..., an), wz) = M ( ( a 1 , • • • an), z)for every z X* of length n. Proof. Consider a loop power M = (M, X, SM) of Bo having n factors and a state (a1, ...,an) Bno with either ai, = ai+1(modn) = 0 or ai,(,ai,+1(modn) {1, 1'} for some i {1,..., n}. To prove our statement we may assume i = 1 without any restriction. Let w € X* be a word of even length; moreover, let x 1 , . . . , xn € X. Put (a t , 1 ,..., at,n) = 8M((a\,..., an), w xi. ..xt), t = 1,..., n, and (a0,1, • • •, ao,n) = (a1, • • • , a n ) • It is clear that flf-1,1 € {1, 1'} implies at\ = 0. In this case at,i = S(a\, \(a\,..., an, X2k+1 • • • xt)) for every 0 k < t/2. Moreover, at-\,\ = 0 with at-\,n = 0 also implies that at t1 = 8(a\, ( ( a 1 , . . . , a n ,X 2 k + 1 • • - x t ) ) if 0 k < t/2. It is clear that a t ,_i,2 € {1, 1'} implies at,i = 0. This means that at,2 = 8(a 2 , 2 (a 1 , • • • ,a n ,x 2 k + 1 • • •*?)) for every 0 k < (t - l)/2. In addition, we have for t > 1 and 0 k < (t - l)/2 that at,_1,1 coincides with 8(a\, \(a\,..., an, X2k+\ • • • *t-1)). Thus at-\,2 = 0 also implies that a t, 2 coincides with 8( a2, 2(a\, ...,an, X 2k+1 • • • x t -1x t )) for all 0 k < (t — l)/2. Then we obtain by an induction that atj = $(a j , (a\, • •., an, X 2k+1 • • .xt-j+\.. .xt) coincide for every 1 j t and 0 k < (t — j + l)/2. This ends the proof. Lemma 5.7. Let M = (M, X, 8 M) be a loop power of Bo having n factors, If M(a, um) = a holds for some a Bon , u X*, and m > 0 such that the length of u is a multiple of n, then _M(a, u2) = a.

5.1. Homomorphic Simulation and the V2-Product

1 51

Proof. Let a = (a\,..., an) Bno and first we suppose that |u| is odd (such that \u\ is a multiple of n). Then S M (a, um) = a implies that m is even. On the other hand, n divides \u\. Therefore, in this case, n is also odd. Thus there is an i {1,...,n} such that either ai = ai+1mod n) = O or{ai, aj+1(m0d n)} {1,1'}. Then we can apply Lemma 5.6 with wz = um~l and |z| = n. Therefore, M(a, um-1) = M(a, z). On the other hand, we can apply again Lemma 5.6 with wz = u such that M (a, u) = M ( a , z). Then, using M (a, um~l) = a, u) and 8 M ( a , um} = a, we obtain M(a, um) = M ( a , u2) = 0 if |u| is odd. M( Now consider the case when \u\ is even. Put (b\,..., bn) = M(a, M) and (c 1 ,..., cn) = M(a, u2). Of course, for alli {1,..., n}, bi = c, = O whenever ai, = 0. Therefore, we are done if ai, = ci, whenever a, {1, 1'}• Thus let ai, ci, with ai, € {1,1'} for some i {1,..., n}. But then, by Lemma 5.5, bi, = ci, implies 8(b i , i(b 1 ,...,b n , uk)) = 8(C i , i ( C I , . . . , cn, uk)) = bi for every k 1 and thus M(a, um) a, a contradiction. On the other hand, ai ci, with ai, {1, 1'} and bi ci, implies ai, = bi and then, by Lemma 5.5, 8 (ai, (a1, ,an, uk)) = 5(bi, i(b1, -..,bn, uk)} for every k: 1 resulting in ai, = (ai, (a 1 ,..., an, u)) = 8(b i , i(b\, ...,bn, u)) = c,-, a contradiction. The proof is complete. Now we are ready to show the following statement. Theorem 5.8. There exists a singleton class K, of automata which is complete with respect to the homomorphic representation under the general product but not complete with respect to the homomorphic simulation under the v2-product. Proof. Let k consist of the single automaton B, defined above. Thus, by Theorem 2.69 we have that K. is complete with respect to the homomorphic representation under the general product. Consider an arbitrary finite simple group G other than a cyclic group of order 2. Let AG denote a strongly connected automaton such that G < S(A G ) (e.g., AG is the automaton (G, G, G) withSG(g, h) = gh for all g, h G). Suppose that AG can be homomorphically simulated by a V2-power Bn(X, ( \,..., n)) of the automaton B. Since AG is strongly connected, by Lemmas 5.3 and 5.4, AG can be homomorphically simulated by a v1-power of the automaton Bo defined above. But by Lemma 5.1, this PI-power is an ao-product of loop powers of Bo. Thus, by Theorem 3.1, there exists a loop power

of Bo with G < M. But then, by Proposition 2.49, G| |M. Therefore, there exist a positive integer m and a subgroup H of S(M) such that G is a homomorphic image of H and each element of H can be induced by a word over X' of length m. Since H is a group, it follows that each element of H can be induced by a word whose length is any multiple of m. In particular, each element of H can be induced by a word of length km. But then, by Lemma 5.7, it follows that the order of each element of H is 1 or 2, contradicting the assumption that G is a simple group of order > 2. In Theorem 6.15, we will prove that the above result is sharp. Finally, we note that we can derive the following result as a consequence of Theorem 5.8.

1 52

Chapter 5. Letichevsky's Criterion

Theorem 5.9. There exists a singleton class 1C of automata which is complete with respect to the homomorphic representation under the general product but not complete with respect to the homomorphic representation under the v2-product. 5.2

Automata with Control Words

We will create "control words" for any automaton that satisfies Letichevsky's criterion. These will serve as logical signals in nearly all our further constructions. Let a = ao ... am and b = bob\ ...bn denote nonempty words over an alphabet A having the following properties: (1) ao = bo, the letters of a are pairwise distinct, the letters of b are pairwise distinct, and b\ does not occur in a. (2) If a = w xy and b = w'xy' for any factorizations with x a letter and w, w' nonempty, then y = y' (w, w' A+, x A, y A*). (3) m n (and n > 0). Equivalently, |a| |b| (and |b| 2). Given a and b as above, define control words, u = u\... us and v = v\... vs:

The following lemma is obvious from (1) and (2). Lemma 5.10. Given control words u, v, for all

we have

implies implies implies We next show the following lemma. Lemma 5.11. Let A= (A,X,8) be an automaton satisfying Letichevsky 's criterion. There are states u\,..., us, v\,..., u s (€ A) and input letters x1, ...,x's,x",..., x"( X) such that8(ut,x't) = u t + 1 ,8(v t ,x t ") = vt+\(t = 1,.... s - l),8(us,x's) = u1, 8(vs,x") = v.. Moreover, u = u\... us and v = v\... vs are control words. Proof. Consider an automaton A = (A, X, 8) satisfying Letichevsky's criterion; i.e., there are a state ao A, two input letters x1, y1 € X, and two input words p = X2 ... xm+\, q = y2... yn+1 X* (x2,..., xm+1, y2, • • •, yn+1 X}, under which 8(ao, x1) 8(a o , y1) and 8(an,x 1 p) = (an,y\q} = an. Suppose that p and q have minimal length; i.e., implies and Introduce

5.2. Automata with Control Words

153

the notation au = S ( a o , x\... xu) (u = 1 , . . . , m) and bv = (ao, j1... jv) (v = 1,..., n). Moreover, we set bo = ao, a = a0 • • • am, and b = b o ... bn. Without loss of generality, we may assume \p\ = m n = \q\. If p is the empty word (m = 0), then (ao, x1) = ao and q cannot be empty lest (ao, y1) = (ao, x1). In any case, n > 0. This yields condition (3). If for, every pair i (= 1,..., m), k (= 1,..., n) we have ai, bk. then we get condition (2). (And, of course, b\ does not occur in a.) By minimality, each of the state words a = ao ... am and b = bo... bn then has no repeated states letters. In other words,

and

utnerwise, ai, = bk tor some i (= i,..., m) ana K (= i , . . . , n). we win taKe i to be the least such i and k to be least such k for this i. (Observe that k = 1 is not possible, for otherwise \bob\ai+1.. .am\ = n + 1 (by minimality), and then n + 1 = m — i + 2, whence m - i + 1 m, implying i 1, but then we would have a\ =b\, which is not the case.) So none of the states a\,..., a,_i is the same as any of the states b\,..., bk-\. By minimality, \Xi+\... xm+\ \ = \ y k+1 ... yn+1 I since either of these words results in transition from a, = bk back to ao. Thus, we may replace y k+1 ... yn+1 by x i + 1 ... xm+\ (or vice versa) to obtain condition (2). Under this replacement, a and b are of unchanged minimal length and so of course cannot contain repeated letters. We know b\ {ao • • • ai-1} and b\ {bk,... bn} = {a i ,,..., am}. Thus, b\ does not occur in a. Thus, conditions (1) and (2) are established in every case. Finally, we can define u = U\...US and v = v\... vs as in (4) and (5). The proof is complete. Using Lemma 5.10, we now prove the following technical lemma useful in establishing well-definedness of and performance of logical operations with control words and inputs. Lemma 5.12. For any alphabet X, control words u, v over an alphabet A, and any mapping f ; {MI, vi,}2 x X —> {u1, v1} with f(u1, u1, x) = u\ and f(v\, v\,x) = v\ (x X) there exists a mapping g : A3 x X A satisfying

Proof. Let g(a, w\, W2,x) be any fixed element of A whenever a

{ui, vi,} \ {ao} with Furthermore. if a in the case that w \ , w 2 (u i ,-u. v,-u} and a set and g if Taking into consideration Lemma 5.10, g is unambiguously determined on (A \ {ao}) x A2 x X and has the values given in statement of this lemma. We still must extend g in a well-defined way to [a0] x A2 x X. That is, ao

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Chapter 5. Letichevsky's Criterion

We distinguish the following three cases. Case 1. m = 0. We put

(w1, W2 £ A, x 6 X). Then we obtain ao = u\ = • • • = us and a0 {v\,..., vs-\}. On the other hand, f(u1, u1, x) = u1(= ao) and f(v\, v\, x) = v 1 (= b\) are supposed. Hence, our assertions hold whenever a = ao and {w\,W2} {ui,v1}(= {a o ,b \ }). Now we suppose that {w\, W2\ = {u1, v1) (= {a o ,b 1 })- Then g(a o , w\, W 2 , x ) = f(w\, w 2 ,x); moreover, for every j = 2 , . . . , s we have {w1, W2 {Uj, Vj}. Therefore, we have our conditions. This ends the proof of Case 1. Case 2. m O, m + 1 | n + 1, i.e., n + 1 = k(m + 1) for some positive integer k. We set otherwise

and

(w 1 , W2 A,x X). Then vi, ao if i {1,..., s — 1}. Moreover, ui, = ao implies ui+I = a\ for any i {1,..., 5 — 1}. Therefore, similar to Case 1, we have our assertion if i, j {1,... ,s — 1). If {w 1 , W2 {m, v\] with (w\, W2) (u1 u1), then b\ {]w1, W2. Hence, in this case, {w\, W2 {uz, vz} if z > 1. It remains to study the case of (w\, W2) = (u1, u1). Then we supposed f(w\, W2, x) = u\ (= a\), corresponding to g ( a o , a \ , a \ , x ) = a\(x € X). On the other hand, by {w'1,w2} (u Z , v z } , z > 1 and ((a\, a\) =)(w\, W2) = (w\, w'2), we have g(ao, w1, w'2, x) = uz (x X) with uZ = a\, whenever ao {M Z _I, uz-i} (or more precisely, whenever ao = «z-i)- This completes the proof of Case 2. Case 3. m + 1 n + 1. Define

(w\, w2 € A,x X). Then MI = ai, vi = fci, M n+2 = /?«-«+!, v«+2 = a\, um+2 = b\\ furthermore, vm+2 = ao or vm+2 = bm+2, depending on whether m + l = n o r m + l < n. By property (1) of aoai... am and b$b\... bm (see their definition), we have, in order, ao [a\, b\, bn-m+i}, a\ b\, and, if m + 1 < n, then b\ bm+2. On the other hand, m + / n + 1 implies n 2m + 1, leading to £m+2 a\ (provided m + 1 < n) by property (2) of ao ... am and bob1 • • • bn (again, see their definitions). Furthermore, bi = bj (i, j = 0 , . . . , n) implies i = j by (1). Therefore, by m + 1 < n, n 2m + 1 implies bm+2 7 bn-m+i, too. Similarly, since m n and m + 1 + 1, then m < n which, in addition, shows bn-m+\ b\. But then {a\, b\}, {a\, bn-m+\}, {ao, b1} by m + 1 = n or {a1, b1, {a1 n-m+1 {b1, bm+2) by m + 1 < n are pairwise different sets. Therefore, if w\ W2 and{w1, w2} {u1, v\], {um+2, vm+2}, [un+2, vn+2}}, then our statement is valid, where the appropriate values of g(ao, w\, W2, x) (x X) are, in order, f(w\, W2, x),b\,a\. (By the way, a\ = bn-m+\ is possible. In this case, we may leave the set {un+2, vn+2\ = [a\, bn-m+1} out of consideration whenever w\ w2 is assumed.) Finally, if w\ = W2, then f(u1, u1,*) = u\ and f(y\,v\,x) = v\ (x 6 X) lead to g(a o ,a 1 ,a\,x) =

5.2. Automata with Control Words

155

g(ao,bn-m+i,bn-m+l,x) = a1(x X) and g(ao, b 1 ,b 1 ,x) = g(a0, a0, ao, x) = b\ or g(ao, bi,bi,x) = g(ao, bm+2, bm+2, x) = b\ (x X), depending on whether m +1 = n or m + 1
Lemma 5.13 leads to the following statement. Lemma 5.14. There exists a mapping g : A2

A satisfying

((a,b) A2). Using Lemma 5.12 and its consequences (Lemmas 5.13 and 5.14) we can conclude the following. Corollary 5.15. Given a positive integer n, a pair of alphabets X, A, and control words u, v over A, let f : {u1, v 1 } n x X u1I, v1} be a mapping with f(u1, ..., u1, x) — u\ and f(v\,..., v\, x) = v\. There exists a mapping g : An x X A satisfying

((a,w1,...,wn,x)

A n x X).

We shall use the following lemma. Lemma 5.16. Let A = (A, X, 5) be an automaton satisfying Letichevsky's criterion. There are states u1, . . . , us, v\,..., vs ( A) and input letters x{,..., x's, x", ..., x"( X) such

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Chapters. Letichevsky's Criterion

that8(ut,x't) = ut+i,8(vt,x") = vt+\(t = 1, ...,s - l),8(us,x's) = u 1 , 8 ( v s , x " ) = v\. Moreover, u = u\... us and v = v\... vs are control words. We close this section with the following definitions. Let A = (A, X, 8) be an automaton satisfying Letichevsky's criterion. Moreover, let u = u\... us, \ = v 1 . . . v s ( A*) be control words as constructed in Lemma 5.11 such that for appropriate input letters x 1 {,..., x's, x f { , . . . , x's'( X) we have 8(ut, x't) = ut+i, 8(vt, xt") = vt+i (t = 1,..., s 1), 8(us, xs) = u1, 8(vs, x") = v\. For any a, a', a" A andfixedpair u\... us, v\... vs of control words we shall use the following operations on the alphabet A:

(We remark that in consequence of Lemma 5.14, are unambiguously defined.)

and

Proposition 5.17. For every automaton A satisfying Letichevsky's criterion, we can give a single-factor product of A which is an m-automaton for some positive integer m. Proof. Let A = (A, X, 5) be an automaton satisfying Letichevsky's criterion; moreover, let u = MI ... us and v = v\... vs be appropriate control words having the properties given in Lemma 5.16. Define the single-factor product M. = A(A, ( ) with (a, w) = x[a, g(a, w)] (a, w A), where g : A2 A is given as in Lemma 5.14. It is clear that M. is an (s, |A2|)-automaton with Xi, = {ui, vi,}, i {1,..., s}. Thus M. is an m-automaton for m = s. The proof is complete. Recall that a loop product is a P-product, where D is a cycle. We now prove the following. Proposition 5.18. For every automaton A satisfying Letichevsky's criterion, we can give a single-factor product M. of A such that every counter can be represented homomorphically by a loop power of M. Proof. Given a counter Cl with l states, let A = (A, X, 8) be an automaton satisfying Letichevsky's criterion. Construct the single-factor product M. of A as in the previous

5.3. The Beauty of Letichevsky's Criterion

1 57

proposition. To prove our statement, we give a loop power of M which isomorphically represents a counter having sl states. Consider the loop power £ = M s l ({x}, \,..., ( sl) of M with ( i ( a 1 , . . . , a s i , a s l + i ) = ai+1(modsi) ((a{,... ,asi) e Asl,asl+l A) and correspond the state C(vu£, k) (k {1,..., si}) to the integer k. Clearly, then £ has a subautomaton B with state set C(vu£, k) (k {1,..., si}) such that this correspondence is an isomorphism of B onto the 5^-state counter. This ends the proof.

5.3 The Beauty of Letichevsky's Criterion Recall that an automaton A satisfies Letichevsky's criterion if there are a state OQ A, two input letters x, y X, and two input words p, q X* under which S ( a o , x) = (ao, y) and (a0, xp) = S(ao, yq) = ao- If the class k of automata contains an automaton satisfying Letichevsky's criterion, then we also say that k satisfies Letichevsky's criterion. Otherwise we say that k does not satisfy it. This well-known criterion can be used not only for characterization of complete classes with respect to homomorphic representations under the general product but also for description of complete classes with respect to isomorphic and homomorphic simulations. Under the generalized product, homomorphic representation is quivalent to both homomorphic and isomorphic simulations. The Gluskov product behaves quite differently. In this section we show that, contrary to this fact, a class of automata is complete with respect to homomorphic representations under the GluSkov product if and only if it is complete with respect to both homomorphic and isomorphic simulations. Therefore, in this sense the GluSkov product behaves similarly to its generalized form. For every digraph D = (V, E) with V = {1,...,n} and positive integer s, we define the digraph D [ s ] = (Vs, Es) having Vs = {1,..., ns}, Es = {(i, i - 1 (modns)) I i Lemma 5.19. Let A = (A, X , 8 ) be an automaton having Letichevsky's criterion with s length control words. Consider an automaton A = (A', X', S'), with A' = {1,..., | A'|}, and its digraph D(A) = (A', E) (having E = {(i, j) A' x A' | there exists x X: S'(i, x) = j } ) . Then A can be simulated isomorphically by a (D(A))[s-power of A. Proof. Let A = (A, X, 8) satisfy Letichevsky's criterion; that is, there are a state ao A, two input letters x, y X, and two input words p, q X* under which (ao, x) (ao y) and 8(a o , xp) = S ( a o , yq) = ao. Introduce the notation, j c i . . . xs = xpyq, ak = 8(a0, x\... xk), and y i . . . ys = yqxp, bk = 8(a0, y i . . . yk), where k = 1,..., s and x\,..., xs, y i , . . . , ys X. We may assume that 0, = bi{ implies a,-+i = bi+\ and xi,+1 = yi,+1 for any i = 1,..., s — 1. Otherwise we could exchange ai,+1 with bi+\ and ,+i with y,-+1. Clearly, then as = bs = ao. Let A = (A', X', 8') be an automaton with state set A' = {1,..., r} for some positive integer r. Moreover, let D = (A', E) having E = {(i, j) A' x A' \ there exists x 6 X: 8'(i,x) = j}. We shall prove that A has a D[s]-power which isomorphically simulates A. Let Z i , . . . , Zf be distinct finite nonempty sets for which Zi = X'. Define the and power Ars with respect to such that for any

158

Chapters. Letichevsky's Criterion

By the above definition of t, t = 1 , . . . , « , it is easy to show that Ars forms a (D(A ))tsl-power of A. We shall now show that Ars isomorphically simulates A under suitable mappings :B A' and 2 : X' Z \ Z 2 - - - Z s . Consider a subset B of the state set of Ars with /

and let 8" be the transition function of Ars. Let for any u A' and z\ Z\, 8f(u, z\) = v. To avoid technical difficulties, first we suppose that u > v. Then, taking into consideration as = bs = ao, for any i = 1,..., r, I = 1,..., 5 — 1, we have the following equalities:

moreover,

Therefore, using the fact that as = bs = ao and u > v,

On the other hand, for any

and similarly, for any i = 1,..., r,

5.3. The Beauty of Letichevsky's Criterion

159

Thus we obtain

Then we get

Consequently, Ars isomorphically with where Z2 • • • zs is an arbitrary fixed element of Z2 • • • Zs. The proof is complete.

It is easy to check that we also have this equality if u and simulates A' under

We shall use the following direct consequence of this result. Lemma 5.20. Every automaton can be simulated isomorphically by a general power of an automaton satisfying Letichevsky's criterion. Next we prove the following theorem. Theorem 5.21. A class k of automata is complete with respect to isomorphic or homomorphic simulations under the general product if and only if it satisfies Letichevsky's criterion. Proof. Suppose that k does not satisfy Letichevsky's criterion. Then, by Proposition 2.71, for every product M. of automata in /k, we also get that M. does not satisfy Letichevsky's criterion. Moreover, by Proposition 2.76, if this product M isomorphically or homomorphically simulates an automaton M, then N should not be noncommutative and strongly connected. In this case, k is not complete with respect to isomorphic or homomorphic simulations, a contradiction. This completes the proof of the necessity. Conversely, assume that k contains an automaton A satisfying Letichevsky's criterion. Then, using Lemma 5.20, every automaton can be simulated isomorphically by a general product of factors from k. This completes the proof. Given again an automaton A satisfying Letichevsky's criterion, its single-factor product M constructed in the proof of Proposition 5.17, let u and v be control words as given in Lemma 5.16. Construct the power M s (A, \,..., ( s} of M holding i(a\,..., as+\) = ai+1 i {1,..., 5}. Clearly, then considering a state (a\,..., as) of Ms such that a\... as {u, v}, getting an input letter z1 {u1, iv1}, the product goes to the state (a 2 , . . . , a s , z 1 ) . Similarly, if for some 1 , then and k

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Chapter 5. Letichevsky's Criterion

getting an input letter Zk+\ [uk+i, Uk+l, the product goes to the state (a 2 , ...,as, Zk+i)Therefore, this product simulates isomorphically the two-state reset automaton, where u and v as the states are corresponded to the states 0 and 1 (or inversely), and, moreover, the effect of the input letter 0 is simulated by the input word u and the effect of the input letter 1 is simulated by the input word v. Given a digraph D = (V, E) with V = {1,...,n}, let P = R m ({0, l}r, i,..., m) be a D-power of the two-state reset automaton R = ({0, 1}, {0, 1), SR) such that (pi (x 1 ,..., xm+r) = x if x\ = ••• = xm+r = x. (This special assumption is necessary to avoid difficulties when we directly apply Corollary 5.15.) Put, for example, u instead of 0 and v instead of 1 to all of the possible states of the component automata, and similarly, do it for every component of the input vectors x {0, l}r. Of course, we have got a product which is isomorphic to P, whenever we consider u and v as letters of the alphabet {u, v}. But we can consider the derived product as a power of the appropriate sth power of the automaton A and the input vectors in {u, v}r as s-length words simulating the effects of input letters of {0, l}r in the automaton P. Formally, for every digraph D — (V, E) with V = [ I , . . . ,n} and positive integer s, we define the digraph D[s] = (Vs, Es) as before (having Vs = {1,..., ns}, Es = {(i, / - 1 (modns)) | i € Vs] U {((k - l)s + 1, is) \ (k,£) E } ( u { ( j , j ) | j € Vs], and considering a D-power of the two-state reset automaton, we obtained as follows. Proposition 5.22. Given a digraph D = (V, E), let P = Rm({0, l}r, lt..., m) be a Dpowerofthe two-state reset automaton R = ({0, 1}, {0,1}, 8- R ) such t h a t ( p i ( 0 , . . . , 0) = 0 and i ( l , . . . , 1) = 1 (i € {1,..., m}). Moreover, let A = (A, X, 8) be an automaton satisfying Letichevsky 's criterion, and let u and v be control words as given in Lemma 5.16. P can be simulated isomorphically by a D[s]-power of A with control words in (u, v}r under the mappings where

Obviously, we have the following consequence of this proposition. Corollary 5.23. Given a digraph D, let A be an automaton having Letichevsky's criterion with s-length control words. Every D-product of the two-state reset automaton can be simulated isomorphically by a D[s]-power of A using s-length words for the simulation. It is an obvious consequence of Gluskov's theorem (see Theorem 2.68) that every automaton can be embedded isomorphically into a (general) product of two-state reset automata having flog 2 n] factors, where [x] denotes the minimal integer kx with kx x. Therefore, using Proposition 7.18, we can also derive the following statement from the above corollary.

5.3. The Beauty of Letichevsky's Criterion

1 61

Theorem 5.24. Let n be a positive integer; moreover, let A be an automaton having Letichevsky's criterion with s-length control words. Consider the digraph D = (V, E) with V = {1,..., ks}, E = {(i, i - 1 (modfks)) | i V} U {(i, i) | i V] U {(1, .s), (s, ks)}, where k = [log2(n + 1)1- Every n-state automaton can be simulated isomorphically by a D-power of A using s-length words for the simulation. We observe that the D-power of A considered in the previous result is ana 2 -v 2 l-power of A. Thus we receive the next theorem. Theorem 5.25. A class k of automata is complete with respect to homomorphic or isomorphic simulations under the a2-vl2-product of automata if and only if it is complete with respect to homomorphic representation under the general product. We will show later a generalization of this statement. Now we give a proof of the following classical result. Theorem 5.26. A class K, of automata is complete with respect to homomorphic representations under the a2-product if (and only if) it is complete with respect to homomorphic representations under the general product. Therefore, 1C has these properties if and only if it is satisfies Letichevsky's criterion. Proof. It is evident that every «2-product is a general product. Thus the necessity of the first part of our statement is trivial. Proof of the necessity of the second part. Assume that K, is a complete class of automata with respect to homomorphic representations under the general product. Then we can also assume that every automaton A can be simulated homomorphically by a general product B of factors in k. Let A be a noncommutative strongly connected automaton. Then, by Proposition 2.76, B should satisfy Letichevsky's criterion. Using Proposition 2.71, B will have a factor in K, having Letichevsky's criterion. (We note that an automaton satisfies the Letichevsky criterion if either one of its homomorphic images or one of its subautomata has this property. By this fact, we can also derive the second part of the necessity of our statement using Proposition 2.71.) Proof of the sufficiency of both parts. Let us consider the following facts. By Proposition 5.17, there exists an m-automaton as a single-factor product of A. Proposition 5.18 implies that for every counter C, there exists a loop power of a single-factor product of A which homomorphically represents C. Having Corollary 5.23, the two-state reset automaton can be simulated isomorphically by an a\-power of A (having s factors). Using Theorem 5.24, every automaton can be simulated isomorphically by an a2powerof A. Therefore, the class M. of a2-powers of A has all of the properties of k in Theorem 3.28. By Proposition 2.51, M. is a complete class of automata with respect to homomorphic representations under the cascade product. The proof is complete. We note that, by Theorem 3.35, we can derive a simpler proof of the sufficiency. In addition, observe that reset automata have the properties of the automaton A given in

1 62

Chapter 5. Letichevsky's Criterion

Theorem 2.68. Therefore, we can also derive the proof of the sufficiency of both parts of our theorem by Theorem 2.68, Lemma 3.34, and Proposition 5.18. By Theorem 5.26 it is proved that Letichevsky's criterion can be used to describe those classes which are complete with respect to homomorphic representations under the a2-product. On the basis of this result, the next statement shows that for i = 2, and thus for every i 2, the ai,,-product is homomorphically as general as the Glu§kov product. Theorem 5.27 (Esik-Horvath characterization theorem). For every automaton A and class 1C of automata, A can be represented homomorphically by an a2-product of automata from 1C if (and only if) A can be represented homomorphically by a Gluskov product of automata from k. Proof. If k satisfies Letichevsky's criterion, then we apply Theorem 5.26. If 1C satisfies the semi-Letichevsky criterion, then we consider Corollary 4.15. It remains to study the case when 1C does not have Letichevsky's criterion. Then we consider Theorem 4.48. The proof is complete. Of course, the Letichevsky decomposition theorem (Theorem 2.69) can be derived from the above result. We remark it is now easy to see that a direct proof of the Letichevsky decomposition theorem can be generated in the following way. Proof of Letichevsky decomposition theorem. The necessity of Letichevsky's criterion directly comes from Proposition 2.71. As to sufficiency, we observe that reset automata have the properties of the automaton A given in Gluskov's theorem (Theorem 2.68). Therefore, we can derive the direct proof of the sufficiency by Theorem 2.68, Lemma 3.34, and Proposition 5.18.

5.4

Bibliographical Remarks

Section 5.1. Lemmas 5.5 and 5.7 and Theorem 5.9 are given in Domosi and Esik [2002]. All other results in this section were developed in Domosi and Esik [2001]. Section 5.2. The results of this section are presented in Domosi and Nehaniv [2000]. Section53. Lemmas 5.19 and 5.20 are new. Theorem5.21 was proved by P. Domosi [1994]. Proposition 5.22, Corollary 5.23, and Theorem 5.24 are new observations. Theorem 5.25 is a strengthened version of the main result in Domosi [1996]. Theorem 5.26 is a well-known result of Z. Esik [1985]. It highly improves the main result of P. Domosi [1983]. The EsikHorvath theorem (Theorem 5.27), i.e., the fact that the a2-product is homomorphically equivalent to the general product, was proved by Esik and Gy. Horvath [1983]. A nice explanation of this statement and Theorem 5.26 is given by Gecseg [1986].

Chapter 6

Primitive Products and Temporal Products

In this section, one of our fundamental concepts is that of the primitive product. Why is it important? A primitive product is a composition of a finite sequence of finite automata such that feedback is limited to no further than the previous factor. Furthermore, the input to each factor depends only on the global input to the system and the states of at most three factors (including the factor itself). Conversely, the state of a factor may directly influence only at most three factors (including the factor itself). Thus, the number of the possible local links is also strongly restricted. We show that the primitive product is one of the simplest type of products that preserve the completeness properties of the general product. The primitive product is general in the sense that exactly those classes are complete with respect to homomorphic representation under the primitive product which are complete with respect to homomorphic representation under the general product (i.e., with unrestricted networking). On the other hand, we will see that the primitive product is a special type of the ao1-vl2'product such that it has a strong restriction on the permitted number of local links. By our results in Chapters 3, 4, and 5, we can establish that an a i -Vj-product or an ai-vlk-product with i<2 or j 2 or k < 2 cannot preserve the generality in the considered sense. Therefore, we would lose the generality of the primitive product if we tried to give further restrictions on the structure of permitted links. Additional conditions guarantee a strongplanarity property (outerplanarity), which is desirable in the engineering of sequential circuits. Also studied in this chapter is the temporal product This is a model for multichannel automata networks, where the network may cyclically change its internal structure during its work on each channel. We will see that this concept may be much stronger with respect to homomorphic or isomorphic representation than the general product. Therefore, the study of automata networks which can modify their inner structure during their work may prove very important from the point of view of many applications.

1 63

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Chapter 6. Primitive Products and Temporal Products

6.1

Primitive Products

Take the above considered general product A = A\ x • • • x An(X, \, • • •, n) and its underlying graph D = (V, E). For any t V, denote by i(t) and o(t) the sets of incoming and outgoing edges of t, respectively, and assume that (1) for any t V there exist 7, k {1,..., t - 1, t + 1} and r € {t - 1, t + 1,..., n] such that one of the following conditions is satisfied:

and and if only if mini

and

then min

max{c, d} if and

max{

Then we say that A is a primitive product.

The following statement is obvious. Proposition 6.1. Every primitive product is an a2-V2-product. On the other hand, by Corollary 2.67, we obtain the next proposition. Proposition 6.2. Every a1-vl2-product of automata can be isomorphically represented by a primitive product of copies of the same automata.

6.1. Primitive Products

165

For any class /C of automata, let us consider the class P(k) of primitive products having factors from 1C. It is easy to see that P(P(k)) P(k) does not hold in general. However, we have the following. Proposition 6.3. Let M = M \ x • • • x Mn+i(X, » • • •. +i). n I, be a product of primitive products Mi = MI,\ x • • • x MI,Ji, (X,•, i,..., ij,), ji 2, i = 1,..., n + l, having the following properties, 1 , . . . , n may really depend only on their input variables. Moreover, . i , . . . , j-i, i = , . . . , n , really do not depend on their last (ji)th-state variables, and, if some n+1,k (k = 1 • • > jn+1) really depends on its input variable, then it may additionally depend only on its kth state variable and at most one other state variable, and, simultaneously, there exists at most one n+1k,' ( ' = 1 • • • j n + 1 ) jn+1) with k kf depending on its kth state variable. Furthermore, the input set of Mn+i is Xn+i = M I 1 } x M2,J2 x • • • x Mnjn, where Miji. ,i = 1,..., n, denotes the state set of the last factor of the product MI, and each n+1,k (k = I,..., jn+1) may depend at most on one component of X n+1 , and, moreover n+1. and +1,k+' do not depend on the same component of Xn+lfork k' (k, k' = 1,..., 7n+i). If n+i has the form n+i(mi, ...,mn, mn+1, x) = (m1 , . . . , mnjn) Xn+\, where m, is the state of Mi and m,>;( the state of Mi's last factor, then M is isomorphic to a primitive product of M i j, i = 1,..., n + 1, j = 1,..., ji. Proof. Let P be an arbitrary permutation over {1,..., n}.34 Considering the short notation Ne = Me,\ x • • • x Mt,jt (t = 1,..., n + 1), by Proposition 2.50, we can construct the product

with u — ji + • • • + jn+i such that M! is isomorphic to M.. Denote n+i.s1. • • • n+i,sr with s\ < • - • < sr to be all feedback functions of the product Mn+i depending on at least one component of the input set Xn+\ = M1,j1 x M2j2 x • • • x Mnjn. From our assumptions it follows that r < n. Suppose that for every l {1,..., r], P(n — l + l) = t, whenever n+1,St depends on the tth component of Xn+\. Clearly, then M' forms a primitive product of the Mij, i = 1,..., n + 1, ; = 1,..., ji. Lemma 6.4. Let D = (V, E) be the underlying graph of a primitive product of automata. Then D has the ordered cycle property. Proof. The nodes of D are already integers, so we consider D under its natural labeling. Claim. Take any pair of undirected paths i\... im, j\... jn consisting of nodes in D, with ji < ii < jn and suppose either im < ji or jn < im. Then the paths contain a common point. Proof of Claim. Assume that the claim is false; then there is a minimal counterexample, with all nodes distinct and n + m least. Consider im-\: if im-\ < j\ or jn < im-\, then the path i\... im-\ would yield smaller counterexample unless m = 2. If on the other hand 71 < im-\ < jn, then im-iim 34

In other words, let P be a bijective mapping of {1,..., n} onto itself.

1 66

Chapter 6. Primitive Products and Temporal Products

yields a shorter counterexample unless m = 2. So m = 2 for a minimal counterexample. Now, consider the path j\ • • • jn. If i2 < j1 then i2 < 71 < i'i < jn. In this case, by (2), i2 < j2 < i1 must hold, and thus, 72 • • • jn yields a shorter counterexample until n = 2. If yn < i2, then ji < i\ < jn < i2- Then, by (2), i\ < jn-\ < i2 must hold, but in this case ji • • • jn-i yields a shorter counterexample. We have established that n = m = 2 in any least counterexample. Thus, i2 < ji < i1 < J2 or ji < i\ < J2 < i2 now by condition (2) of the definition of primitive product, since j\ = minjji, 72} < i\ < max{j\, 72} = 72, we have j\ < i2 < 72, a contradiction. Therefore, no least counterexample can exist. This establishes the claim. Now let c\ denote the least node in the real cycle. It is connected by edges in the real cycle to two other nodes. Now these two nodes and c\ are pairwise distinct. Let c2 denote the lesser of the two and let ck denote the greater. We have c\ < c2 < ck. Proceeding around the real cycle in the direction from c\ to c2 denote the nodes c3, c4, etc., until we reach ck. We assert that Ck is the greatest node in the real cycle; if not, let ci be the node with least i such that c, > ck. Note that i 3. By leastness of i, ci_1 < ck, and so it must be that ci, > Ck > ci,-1 > c\, but then the path CkC\ and the path c,C i _i would comprise a counterexample to the claim. Hence, ck must indeed be the greatest node. Furthermore, it must be true for each i = 1,..., k — 1 that ci+\ > ci: If not, take an i such that ci+\ < ci. Then we have i {\,k — 1], and so c\ < ci+\ < c,
6.2

Primitive Products and Letichevsky's Criterion

We constructively show that if A is a finite automaton satisfying Letichevsky's criterion, then any finite automaton can be homomorphically represented by (i.e., is a homomorphic

6.2. Primitive Products and Letichevsky's Criterion

167

image of a subautomaton of or, equivalently, is a letter-to-letter (length-preserving) divisor of) a primitive product of copies of A. Take two alphabets X and 7. Let n = is (l > 1) be a fixed integer and consider a mapping : Xn Yn having the property { (/?) | p Xn} {w | w {u, v}£} for some fixed words u. v € Ys. We shall denote the reverse of ( ) bv (p}. to be the Set Define automaton, where d is a positive integer, Rr,H,d = {(k, p,q) € (1,...,n} x X* x Y+ \ k+\q\ =n+d, \p\ (0, k}, is a prefix of a word in H (pp' H for somep' X*),and, furthermore, q — q'q", where q'' is a suffix of u or v and q" {u, v}*}, and, for arbitrary (k, p, yq) € R ,H,d (y { , vt \ t = 1,..., s}) and x X,

To simplify the proof of the next result, we introduce some auxiliary notions. Let A = (A, XA, 8A) be an automaton satisfying Letichevsky's criterion, and let u\... us, v\ ... vs be any pair of its control words. For any w\...ws with wt {ut, vt} (t = 1 , . . . , s) we shall use the short notation w. Consider a word a\... an A+ and an integer k (= 1, . . . , n). We will denote by c(a\ ...an, k) the (k + l)th cyclic permutation of a\... an. In more detail, let

let In addition, for any pair t, k with t the reverse of c(a\... an, r). and for any integer r, denote by moreover, let B be an automaton with Let M onto be a subautomaton of M. having a homomorphism implies such that . Then we say that M y-represents R ,H,d (with respect to We have the following. Lemma 6.6. Let A = (A, XA, 8A) be an automaton satisfying Letichevsky's criterion and let u\... us, v\... vs be any pair of its control words. Consider an alphabet X, a multiple n of s with n = is, l > 1, a word r Xn, and a mapping : Xn An having the property (p) € {u,v}+lfor each p Xn. Then there exists a primitive power M. of A such that R ,M,i is y-represented by M. In addition, apart from the feedback functions for the last factor, the feedback functions of the factors of M. really do not depend on their last state variable.

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Chapter 6. Primitive Products and Temporal Products

Proof. For the proof of our statement, first we are going to define a product N = having the following structure:

The first s factors provide a "small clock" in which u = u\... us cycles. The next n factors (s + 1,..., s + n) make up a "big clock" in which vul-1 cycles. The next n factors (.s+n + l,...,.s + 2n) make up a buffer into which values flow from the big clock, starting with v1. At the kth position of the buffer, if the input letter x matches the kth letter of r when the signal (headed by v\) is about to reach this position, then the signal is permitted to continue; otherwise instead of switching to state v\ we switch to uI, indicating rejection of the input.35 Finally, if the word has not been rejected by the nth input step, the acceptance signal reaches the end of the buffer, and then the buffer contains n letters which are the reverse of vul-1 with a2n+s = v\ (and of u£ otherwise with a2n+s = u1).

35

Lemma 5.12 guarantees that for each factor t of the buffer, (ar-1,«i-r(modj)) = (v\, u1) only when k = t — s — l(modn), especially for the first factor of the buffer, i.e., for t = n + s + 1, (as+n, as) = (v\, u1) if and only if k = n.

6.2.

Primitive Products and Letichevsky's Criterion

1 69

In the next step, the buffer cycle starts again, while in the last n — s + 1 factors (2n + s + 1,..., 3n + 1), the coded word (r) begins to take form if the signal has arrived. Now (r) = w 1 . . . wl, where each wj {u, v}. For each j = 1,..., I with w l _ + 1 = v in this step v1 simultaneously enters factor 2n + js + 1, while for the j with wl-j+1 = u and u1 enters this factor. It is important to observe that (r) can be fully recovered from the states of these t nodes at this time, as follows from u\ v\ and the form of (r) {u, v}£. In the next s — 1 steps, the letters in these factors shift to the next highest factor and the respective letters of u and v flow in. Thus, this last part will contain (r) except for its first .s — 1 letters, as a2n+s+1• • •, a3n+1 after s steps. Observe that the letters of (r) appear as n successive states a3n+\ of A3nn+1, which is the last factor. If the signal did not arrive, the above transition rules imply that u1 will be in the buffer after n input letters and will then flow through and out of the next part. We will use the fact that, except for the last (3n + l)th factor, the feedback function (pt of the tth does not depend on its last state factor a3n+1 • As to the mapping onto R T,{r},d, take a triplet (k, p, yq) R,{ r },\ (y {ut, vt \ t = 1,...,*}). We represent this triplet (k, p, yq) by an appropriate state b = c(u, k)c(vul~l, k)c(zu l ~ l , k - \)e\... en-s+1 of N. The number k is represented by the value c(vu l ~ l , k) and c(zul~l, k — 1), z = z 1 . . . zs represents p with zi, {ui, vi,}, i = 1,..., s. Namely, if z\ = u1, thenp = is assumed, and if z\ = z\, then p is understood as the k:-length prefix of r. In other words, z\ = v\ means r = pp' for some p' X* (with \p\ = k). And z\ = MI means p = . Setting y 1 . . . yn {u, v}£, assume

Then k and the mirror image of e\ obvious considering the structure of l > 2, then the mirror image of e\

i represents

If

then this is

(Observe that k and representing unambiguously determine moreover, for anv We have similar consequences unambiguously determines for and l = 2. The motivation for this representation should be clear from the explanation of the buffer cycle discussed above.

input letter

input letter

input letter

input letter merged word (in which a letter is if and only at least one of the arriving letters is )

MERGE OF STRINGS

THE LAST LETTER OF THE PREVIOUS CODED WORD

FIRST LETTER OF THE WORD THE NEW CODED WORD ARISES

NEXT LETTER GOES OUT

NEXT LETTER GOES IN NEXT WORD ACCUMULATED

CODED WORD PASSED OFF

6.2. Primitive Products and Letichevsky's Criterion

171

Formally, we define the product N = A3n+l(X, \,..., 3n+\) such that for any (a 1 ,..., a3n+1) A3n+l, x X, and t {1,..., 3n + 1}, we have

Now we give the formal definition of B' and that of a mapping :B R ,{r},i under which R ,{r},i is an (y-represented) homomorphic image of B'. Let B' consists of all b A3n+1 for which there are (k, p, q) R ,[r},i such e l ul-1 that b = c(u, k)c(vu ~ , k)c(z , k - \)e\... en-s+i, z = z\...zs, with z,- {ui,-, vi,}, i = 1 , . . . , s , where

e\... en-s+\ is defined as above, and q is represented by k and e\... en-s+\ as we explained. (Recall that by the structure of R ,(r},i, yn-s+k • • • yn-s+ius... uk+1 yn-2s+k • - • y n -2s+1u s ... u k + 1 ... ys+k ... y s +1u s ... uk+\yk unambiguously determines q = yk ... yn whenever k < 5 and l > 2. Similarly, by the structure of R ,{r},i> ys+k • • • ys+1us ... uk+\yk unambiguously determines q = yk ... yn, whenever k < s and 1 = 2. Moreover, q = e n - s+1 ... ek-s+1 is assumed if k s.) Furthermore, let (b) = (k, p, q). It is routine work to show that N has a subautomaton B' with state set B' which can be mapped homomorphically by onto R ,{r},i- Finally, by (b) = (k, p, q), the last letter of b is the same as the first letter of q. Therefore, N y-represents R ,{r}, 1-

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Chapter 6. Primitive Products and Temporal Products

Applying Proposition 2.66 to the product N, it is clear that we will get a product N', which also y-represents R ,{r},i; moreover, similar to N,, apart from the last factor, the feedback functions of the factors of N"' really do not depend on their last state variable. Thus it is enough to observe that by an inductive application of Proposition 2.66, we can derive from the product A/" a primitive product M. In particular, every vertex of the underlying graph of N has not more than two incoming and two outgoing edges in the resulting product. Moreover, if there is a vertex with two outgoing edges, then it is an element of a cycle with one edge going into another element of the same cycle, and all the other cycle elements have one outgoing edge connecting them with other elements of the cycle. In addition, cycle elements have only one incoming edge, coming from another element of the cycle.36 Using Theorem 2.1, we may assume that N is a primitive product, for otherwise we could relabel its components by an appropriate permutation of their indices. This ends the proof of Lemma 6.6. We next prove the following lemma. Lemma 6.7. Let A be an automaton satisfying Letichevsky's criterion, and let Ak(X, ( [, ..., ( 'k}, k i ( X , y'[,..., ( 'i) be primitive powers of A such that, apart from the last factors, the feedback functions of the factors really do not depend on their last state variable. Suppose that they y-represent, in order, R r ,Hi,d and R T,H2,d for some : Xn An, + HI, H2 [p X | |p | = n } ( H 1 , H2 are not necessarily disjoint sets), and d 1, where n is a multiple of s as before. There exists a primitive power M. = Ak+l+l(X, 1 , . . . , ( k+l+1), which y-represents R- ,Hi\JH2,d+\ • Moreover, apart from the last factor, the feedback functions of the factors of M. really do not depend on their last state variable. Proof. Define the power Ak+i+l For any

I in the following way.

Clearly, this power of A is primitive. Now we consider, in order, appropriate homomorphisms ' and \ " such that Ak (X, {, ..., (p'k} y-represents R r ,H 1 ,d with respect to ', and, moreover, Al(X, '{, ..., £) y-represents R ,H2,d with respect to - ". It is clear that t does not depend on its last state variable if k + l + l. Therefore, it is a routine work to show that the power M. y-represents R ,H 1 (uH 2 ,d+1 with respect to the homomorphism having the following properties:

36 The cycles may be wired in such a way that their first element is connected to the last one and all the others are connected to the previous ones. Then the cycles can represent clocks so that, for instance, if d\ ... dms is a state of a cycle (with ms length) representing the kth state of an arbitrary clock, then d2 • • • dmsd\ will represent its k + 1 (modms)th state.

6.2. Primitive Products and Letichevsky's Criterion

1 73

whenever (with \p\ € {0, c} including the possibility of p = ),

provided

Using the definition of R
are well

We shall use the following concept as well. Define the subautomaton Rr of . , xn ,d to have state set R d = R-c,xn,d\{(k, q) I (k, A, q) R ,x\d}' This is a subautomaton since px is a prefix of a word of Xn for every p € X* with |p| < n, x X. For (k, p, q) Rr,d, we have |p| = k always, so we will use the short notation (p, q) for (k, p, q) R td- We have, for (p, yq) Rd (y € {ut, vt \ t = 1 , . . . , s}) and x X,

*.

Let M = (W x Z, X.M, 5>j) be an automaton with Y c Z; moreover, let B = (B, X, 5e) be a subautomaton of M. having a homomorphism : B R ,^ onto R such that ((M;,z)) = (p, yq) ((w, z) B, (/?, yq) € Rr,d, y Y) implies z = y. Then we also say that M. y-represents R.T d (with respect to 1/r). The following statement is obvious. Proposition 6.8. Let , : Xn Yn, i = 1 , . . . , m, be a system of mappings; moreover, let d be a positive integer. For any i = 1,..., m, let Mi = (Wi{ x Zi,-,X, 8,;) be an automaton which y-represents R /. Consider an automaton Mm+\ = (Mm+\, Xm+\, 5 m+ i) with Xm+i = Ym, a product U = Rr,d x • • • x RTm,d x M m +1(X, \,..., m+\) with

Define the product

Then M homomorphically represents U.

with

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Chapter 6. Primitive Products and Temporal Products

Lemma 6.9. Let A = (A, X, 8 A) be an automaton satisfying Letichevsky's criterion and let u = MI ... us, v = v\... vs, be any pair of its control words. Consider an alphabet X, a multiple n of s with n = ls,l > \, and a mapping : Xn An having the 1 n n property \ (p) 6 {u, v} for each p € X . For any integer d > \X \, there exists a primitive power M. of A such that R Tt d is y-represented by M. Moreover, apart from the lastfactor, the feedback functions of the factors of M really do not depend on their last state variable. Proof. By Lemma 6.6 and by an inductive application of Lemma 6.7, we can prove that ^T,XMX»I is y-represented by an appropriate primitive power M' = Ak(X, {, ..., 'k) of A. Since R ,\xn\ is a subautomaton of 'R- ,xn,\xn\^ this primitive power M.' also yrepresents R ) |x n i- If d = \Xn\, then M' has the required conditions. Otherwise, let n k+t M = Ak+i(X, 1 ,x k+e) with£ = d - \X \ such that for any ( a 1 . . . , ak+i) € A X,t = l,...,k + t,

This power of A is primitive and y-represents Tit4. Lemma 6.10. LetT>=(D,X, 8) and B=(B,Y, 8') be automata with D c 5. Moreover, let : Xn Yn (n > 0) be a mapping and assume that for a suitable integer d > 0 the following two conditions are satisfied: (I) For all a € B, ( p , q ) e R ,d, p 8'(a,a (p)) ( D).

Xn: 8'(a,q)

D implies 8(8'(a, q), p) =

Then there exists an a o-product R j x B(X, \ which homomorphically represents D) such that ( 2((p, Y)» x) ((p, yq) R
6.2. Primitive Products and Letichevsky's Criterion

1 75

Lemma 6.11. Let D = (D, X, 8) be an automaton. Consider a product N = (B1 x • • • x Bm, Z*, 5') = B1 x • • • x B m (Z*, < p i , . . . , m) of automata Bt,l t<m, with D BI x • • -xBm. Let , : Xn Zn (n > 0), 1 i £, be mappings; moreover let : Xn (Z l ) n wif ,-( p) = z 1 f . . . zn,i, i = l , . . . , £ , wheneverr(p) = (214,..., z1,/)... (z n1 , . . . ,Z n ,/) 5MC/I that the following two conditions hold: € D implies

(1) For every

(2)D Then f/ie product V each

homomorphically represents D, where for

we have

and

Proof. First we apply Lemma 6.10, taking N in the role of B. Consider the ao-product U = R ,d X N(X, X1 X2) given by Lemma 6.10 and the product V = R i) dx ) just defined. with For a state where given we put

(for some h

0, for each j = 1, . . . , l ) . We write this state as

Define an injective mapping

Denote by U (resp., y) the transition functions of U (resp., V).

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Chapter 6. Primitive Products and Temporal Products

If \p\ < n, in 8u(((p, yq), b\,..., bm), x), the only changes are that the row of y's is lost, p is replaced by px, and bf is replaced by b\, which is b{ acted on by
where This shows that for any

we have

Therefore, the product U can be embedded isomorphically into the product V. But by Lemma 6.10, U homomorphically represents D. Thus, V also has this property.

6.3

Homomorphic Completeness Under the Primitive Product

In this section, we will establish that a primitive product of Letichevsky automata can homomorphically represent any finite automaton . To avoid trivialities, we note that it is enough to restrict ourselves to cases in which S has at least three states. Consider an automaton A satisfying Letichevsky's criterion and let u = u\... us, \ = v\... vs denote a pair of control words for A as before. We put U U = U V U = U, and so that and are, respectively, logical AND and logical OR on the set {u, v}. First we show the following technical result. Lemma 6.12. Define the automata with

where for

6.3. Homomorphic Completeness Under the Primitive Product

1 77

There exist a positive integer m and input words y o , y 1 , Y 2 , Y3 of C having the following properties. Given an appropriate subset (b\,..., bn} of the state set of B, for every transformation r of inducing y there exists a word such that

Proof. Consider states of C having the form (u4a1u13. ..u4anu13), a 1 , . . . , a n {u, v}, and use the short notation (d, e) = u4du8eu4, d, e € {u, v}. We represent i, i {1,..., n}, by the state U18('~1)u4vu13u18(n~l) of C, which, using the short notation, is (u, u ) i - 1 1 , u)(u, u) n ~'. First we show that we have words qo,o, qi,./ {u, v}+,

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Chapter 6. Primitive Products and Temporal Products

i = 1, 2, 3,4, j = 1,..., n, all having the same length such that

where

and, otherwise,

Using the symmetry of the structure of C to show the existence of the q 's, it is enough to prove the existence of go,o 7u {u, v}+, i = 1, 2, 3,4. Define the following input letters (not words!) of C:

It can be proved by an elementary computation that the words go,qo,o = xo y q1,1 = x1 5x 2 4 , q2,1 = x3 5x 4 4 , q3,1 = 59, q4,1 = x65 x74 satisfy our requirements. (See the detailed elementary computation below.) Put ; and use the short notation , which all BV an elementary computation we get that the have the same length, induce the following transformations YJ of {b\, ...,bn}:

(The detailed computation is given below.) Using the well-known fact that y\, Y2, Y3 generate all transformations on the n element set {b1, ...,bn] (see also Proposition 1.5) and that Yo is the identity, we obtain our technical result. Proof of the properties of qo,o and qi1i, i = 1, 2, 3,4. The following detailed elementary computation shows that the words q0,0 = xo9 q1,1 = x1 5x 2 4 q2,1 = x3 5x 4 4 , q3,1 = x59, q4l = X6 5 x7 4 satisfy our requirements in the proof of Lemma 6.12:

6.3. Homomorphic Completeness Under the Primitive Product

(1)

(2)

(3)

(4)

= c(u2d1u8e1u8d2u8e2u8d3u8e3 • . .u8dnu8enu6, x04) = c(u4d1u8e1u8d2u8e2u8d3u8e3 . . . u8dnu8enu4, *03) = c(u3d1u8e1u8d2u8e2u8d3u8e3 . . .u 8 d n u 8 e n u 5 , x 0 2 ) = c(u2d1u8e1u8d2u8e2u8d3U8e3 . . .u8dnu8enu6, xo) = (U4d1u8e1u8d2u8e2u8d3u8e3 . . .u8dnu8enu4). 4 8 8 8 8 8 8 8 4 5 4 c(u d1u e1u d2u e2u d3u e3 . . . u d n u e n u , x1 x2 ) 3 17 8 8 8 8 8 5 4 = c(u d1u d2u e2u d3u e3 . . .u dnu enu , x 1x24) = c(u2d1u17d2u8e2u8d3u8e3 . . . u8dnu8enu6, x13x24) = c(u4d1u14d2u2d2u8e2u8d3u8e3 . . . u8dnu8enu4, x12x42) = c(u3d1u14d2u2d2u8e2u8d3u8e3 . . . u8dnu8enu5, x1x24) = c(u2d1u14d2u2d2u8e2u5d2u2d3u8e3 . . . u 8 d n 8 e n u 6 , x24) = c(u4d1u11d2u5d2u8e2u2d2u5d3u8e3 . . . u8dnu8enu4, x23) = c(u3d1u11d2u5d2u8e2u2d2u5d3u8e3 . . . u8dnu8enu5, x 2 2 ) = c(u2d1uud2u5d2u8e2u8d3u8e3 . . .u8dnu8enu6, x2) = (U4d1u8d2u8d2u8e2u8d3u8e3 . . . u8dnu8enu4). (5c(u4d1u8e1u8d2u8e2u8d3u8e3 . . . u8dnu8enu4, x35x44 = 5c(u3d1u8e1u8d2u8e2u8d3u8e3 . . .u8dnu8enu5, x34x44) = c(u2d1U8e1U8d2u8e2u8d3u8e3 . . . u8dnu8enu6, x33x44) = 5c(ud1u2d1u5e1u2e1u8d2u8e2u8d3U8e3 . . . u8dnu8enu4, x 3 2 x 4 4 ) = c(d1u2d1u5e1u2e1U8d2u8e2u8d3u8e3 . . . u8dnu8enu5, x3x44) = c(u2d1U5e1U2e1u5d1u2d2u8e2u8d3u8e3 . . . u8dnu8enu5d1, x44) = c(u4d1u2e1u5e1u2d1u5d2u8e2u8d3u8e3 . . .u 8 d n u 8 e n u 2 d 1 , x43) = c(u6e1u8d1u5d2u8e2u8d3u8e3 . . . U8dnu8enu2d1u2, x 4 2 ) = c(u5e1u8d1U5d2u8e2u8d3u8e3 . . . u8dnu8enu6, x4) = (U4e1u8d1u8d2u8e2u8d3u8e3. . .u8dnu8ewu4). 6c(u4d1u8e1u8d2u8e2u8d3u8e3 . . . u8dnu8enu4, x59) = c(u12e1U8d2u8e2u8d3u8e3 . . .u8dnu8enu5, x 5 8 ) = c(u11e1u8d2u8e2u8d3u8e3 . . .u8dnu8enu6, x57) = c(u13e1u8d2u8e2u8d3u8e3 . . .u8dnu8enu4, x56) = c(u12e1u8d2u8e2u8d3u8e3 . . ,u8dnu8enu5, x55) = c(uue1u8d2u8e2u8d3u8e3 . . .u8dnu8enu6, x54) = c(u13e1u8d2u8e2u8d3u8e3 . . .u8dnu8enu4, x53) = c(u12e1u8d2u8e2u8d3u8e3 . . .u8dnu8enu5, x52) = c(une1u8d2u8e2u8d3u8e3 . . . u8dnu8enu6, x5) = (u13e1u8d2u8e2u8d3u8e3 . . . u8dnu8enu4). 4 8 8 8 8 8 8 8 4 5 4 c(u d1u e1u d2u e2u d3u e3 . . . u d n u e n u , x6 x7 ) 3 8 8 8 8 8 8 8 5 = c(u d1u e1u d2u e2u d3u e3 . . .u dnu enu , x6*x7*) = 5c(u2d1u8e1u8d2u8e2u8d3u8e3 . . .u8dnu8enu6, x63x74) = c(u4d1u5e1u2e1u8d2u8e2u8d3u8e3 . . . u8dnu8enu4, x 6 2 x 7 4 ) = c(u3d1u5e1u2e1u8d2u8e2u8d3u8e3 . . .u8dnu8enu5, x6x74) = c(u2d1u5e1u2e1u8d2u8e2u8d3u8e3 . . .u8dnu8enu6, x74) = c(u4d1u2e1u5e1u8d2u8e2u8d3u8e3 . . . u8dnu8enu4, x73) = c(u3d1u2e1u5e1u8d2u8e2u8d3u8e3 . . .u8dnu8enu5, x 7 2 ) = c(u2d1u2e1u5e1u8d2u8e2u8d3u8e3 . . .u 8 d n u 8 e n u 6 , x7) = (u4(d1 v e1)u8e1u8d2u8e2u8d3u8e3 . . . u8dnu8enu4).

1 79

1 80

Chapter 6. Primitive Products and Temporal Products

Proof of the properties of J (j = 0,1, 2, 3). The next detailed elementary computation shows that the j (j — 0, 1, 2, 3), which all have the same length, induce the transformations j of [b\,.. .,bn} given in the proof of Lemma 6.12. (0') Identity.

c ((d 1 ,

u, . . . , dn, u), q0,o) = (d1, u, . . . , dn, u).

(1') n-cycle. c((d1, u, d2, u, d n _ 1 , u, dn, u), q1,1 . . .q1,1q1,1 . . .q3,nq2,1 • • .92,11) = c((d 1 ,d 2 ,d 2 , . ..,d n _ 1 ,d n _ i ,d r t ,d n ,d 1 ),q 3 , 1 ... q3,nq2,1 • -.q2,n) = c((u, d2, u, . . . , d n _ 1 , u, dn, u, d1), q2,1 . . . q2,n)

= (d2, u, d3, . . . , u, dn, u, d1, u). (2') Transposition.

c((d1,

u, . . . , dn, u), 91,192,191,2 • • • q1,nq3,1 • • • q3,nq2,1 • • • q2,n

(q1,1 • • • q1,1q3,1 • • • q3,nq2,1 • • • q 2 , n ) n-1 ) = c((d1, d2, d2, u, dn, u), 92,191,2 • • • 91,nq3,1 • • • q3,nq2,1 • • • q2,n (q1,1 • • • ql,nq3,l • • • q3,nq2,l • • • q 2 , n ) n - 1 )

= c((d2, d1, d2, u, d3, . . . , u, d n _ 1 , u, dn, u), q1,2 . . . q 1 ,nq 3 , 1 • • • q3,nq2,1 • • • 92,n (q1,1 • • • q1,nq3,1 • . . q3,nq2,1 • • • q 2,n ) n-1 ) = c((d 2 ,d 1 ,d 2 ,d3,d 3 , ...,d n _ 1 ,d n _ 1 ,d n ,d n ,d 2 ),q 3 , 1 ...q 3 , n q 2,1 • • • q 2 , n (91,1 • • • ql,nq3,l • • • q3,nq2,l • • • q2,n.)n-1)

=

c ((u,

d1, u, d3,

d n _ 1 , u, dn, u, d2), q2,1 . . . q2,n

(q1,1 • • • q l,n q3,l • • • q3,nq2,l . • • q 2 . n ) n - 1 )

= 5((d1, u, d3, u,

u, dn, u, d2, u), (q1,1 . . . q1,nq3,1 . . . q3,nq2,1 • • • q 2,n ) n-1 ),

and now applying the n-cycle operation n — 1 times, we obtain ((d1, u, d3, u, , u, dn, u, d2, u), (0U . . . q1,nq3,1 • • • q3,nq2,1 • • • q 2,n ,) n-1 ) = (d2, u, d1, u, d3, . , d n _ 1 , u, dn, u). (3') Collapsing. c((d1, u, d2, u, d3, , dn, u), q1 ,1q3,2q4,1 q2,1q3,1 92,1) = c((d1, d2, d2, u, d3, . . . , dn, u), 93,294,192,193,192,1) = c((d1, d2, u, u, d3, . . . , dn, u), q4,1q2,1q3,1q2,1) = c ((d 1 v d2, d2, u, u, d3, dn, u), q2,1q3,1q2,1) = c ((d 2 , d1 v d2, u, u, d3, dn, u), 93,192,1) = c ((u, d1 v d2, u, u, d3, . , dn, u), q 2 , 1 ) = (d1 v d2, u, u, u, d3,

, dn, u).

Now we are ready to prove our key result for this section. Theorem 6.13. Let A = (A, XA, A) be an automaton satisfying Letichevsky's criterion. For any automaton £ there exists a primitive power P of A such that can be represented homomorphically by P. Proof. Let u = uI ...u s , v = v 1 ... vs denote a pair of control words of A as before. Consider an integer n > 3 and define the power N = A 1 8 n s (X N , p 1 , . . . , p 1 8 n s )> XN = A6n, of A in the following manner. For any state ( a 1 , . . . , a 18ns ) e A 18ns , input

6.3. Homomorphic Completeness Under the Primitive Product letter

1 81

= (z 1 ,..., Z6n) € X^, and t (= 1,..., 18ns)', we have

It is easy to check that N is a primitive power of .A; moreover, whenever , (1 t 18ns) really depends on its input variable, then it may additionally depend only on its tth state variable and at most one other state variable. Therefore, N has the properties required by Proposition 6.3 for the last component of M. Denote by SN the transition function of N and consider the automaton C given in Lemma 6.12. Observe that whenever N is in the state having the form (w\ 1 , . . . , w\ x, by the effect of words having the form if and only if Therefore, using the short notation bk for the state bk of N, by Lemma 6.12 we have that there exists a positive integer m having the following property. For every transformation v on {b 1 , ...,bn], for all such that there exists a word Every n-state automaton £ is isomorphic to a subautomaton of an n-state automaton D with the following properties: (1) For each transformation r of the n states of D, there is an input letter XY inducing y. (2) There are at least as many distinct letters of D that induce r as there are that induce y in . Thus, to complete the proof, it suffices to establish the result for the following nstate automaton having these properties whose states are a subset of those of N. Let D = (D, XD), <$ D ) D = { b 1 , . . . , bn], where bk, k = 1 , . . . , n , are the states of N discussed before. For each transformation r of \b\,..., bn} let there be an input letter XY of D having D(b k , Xy) = r (bk), k = 1,..., n. Furthermore, let there be at least as many letters of D which induce each given transformation r as there are in £. We shall show that D can be represented homomorphically by a primitive power of A. Clearly, {8D(b k , x) I bk D, x XD] = D. To each length ms input word p = x\... xms of D, we associate the transformation vn induced bv this word on the set D = (b1 bn}.n > • Define, following Lemma 6.12, "" »»*• The mapping satisfies

1 82

Chapter 6. Primitive Products and Temporal Products

For every d > 0 and a a state of N, (p, q) € R ,d, P € (XD) ms , we clearly have, whenever N(a, q) D, that 8D(8N(a, q), p) = 8j^f(a,q (p)) D). Furthermore, by taking t to be a letter of XD inducing the identity under $D (that is, SD (bi, t) = bi{ for all b( D) and letting q be ( (tm5)); with msj < ms+d and p = Ld-ms(j-1) implying (p, q) R td, we derive 8 D D(8 N (b i ,q), p) = <5p(bi,, p) = bt. Therefore, D = [ 8 D ( 8 N ( a , q), p) \ a a state of N , ( p , q ) R ,d, (a,q) D}. This shows that conditions (1) and (2) of Lemma 6.11 hold. For every i (= 1,..., 6n), define : (XD)ms Ams as follows: for each 1 j ms, the jth letter of ,(/?) ( € (XD)mj) is equal to the ith component of the jth letter = (Zj,i, • •., Zj,6n) of (/>). Therefore, as in Lemma 6.11 (taking i and n of the lemma to be 6n and ms, respectively), we can construct the product V = R i!x • • • x R r6n x N ( X D , {,..., ( 6n, n+i) which homomorphically represents D. By Lemma 6.9, given an integer d |X D | ms , for each i = 1 , . . . , 6n, we obtain a primitive power Mi of A such that apart from its last one, its feedback functions do not depend on the last state variable, and furthermore, Mi v-represents .| . ) . Now set ^fi(m\,..., m 6n , m6n+1, x) = x for each i = 1 , . . . , 6n and 6n+1(m1, ..., m6n, m6n+1,x) = (z1,..., Z6n)> where x € XD, zi, is the state of the last factor of Mi (which represents i,d) for 1 i 6n, and m 6n+i is the state of N. By Proposition 6.8 (considering , XD, 6n to be M, X, m of the proposition), we obtain M = M\ x • • • x M6n x A/"(XD, 1, ..., 6/i+i)» which homomorphically represents V, hence , hence . On the other hand, observe that we have the conditions of Proposition 6.3 for the product M (taking , XD, 6n to be M n+1 , X, n of the proposition). By Proposition 6.3, M is isomorphic to a primitive power P of A Therefore, 8 is homomorphically represented by the primitive power P. This completes the proof. Corollary 6.14. Let K. be a class of finite automata. If 1C satisfies Letichevsky's criterion, then K, is complete with respect to homomorphic representations under the primitive product. By the Letichevsky decomposition theorem (Theorem 2.69), a class of finite automata is complete with respect to homomorphic representations under the Glu§kov product if and only if it satisfies Letichevsky's criterion. Therefore, one obtains the following statement. Theorem 6.15. Suppose that 1C is a class of finite automata. Then the following statements are equivalent: (1) satisfies Letichevsky's criterion. (2) 1C is complete with respect to homomorphic representations under the Gluskov product. (3) k is complete with respect to homomorphic representations under the ai, -product for all i 2. (4) k is complete with respect to homomorphic representations under the ai, -product for some i 2. (5) 1C is complete with respect to homomorphic representations under the Vj-product for all j 3. (6) 1C is complete with respect to homomorphic representations under the Vj-product for some j 3.

(7) k is complete with respect to homomorphic representations under the -Vj-product for all 2, j 3. (8) 1C is complete with respect to homomorphic representations under the a i -V j -product for some i 2, j 3. (9) K, is complete with respect to homomorphic representations under the primitive product. Remark. Theorem 3.36 implies that there exists no finite class of automata which is complete with respect to homomorphic representations under the a\ -product. Therefore, by Theorems 2.69 and 5.9, there is a class of finite automata satisfying Letichevsky's criterion which is complete with respect to homomorphic representations for neither the a1-product nor the V2-product. This shows that the above result is sharp.

6.4 Temporal Products Let A = (A, Y, 8) be an automaton with Y = Xk for some nonempty finite set X and positive integer k. We say that A is a k-channel automaton (with respect to X). If there exists a (onechannel) automaton A' = (A, X, ) such that for every pair a € A, (x 1 ,..., xk) Xk, we haveS(a, (x 1 ,.. .,x k )) = S'(a, x 1 .. .Xk);ihenitissaidthatAhas a one-channel analog A. Thus A' isomorphically simulates A in equal lengths under ( , ), where \ : A A and T2 : Xk X* are defined by (a) = a, 2((xi,..., Xk) = x1 ...xk. If . A' is a product of automata, then .A is a simple type of temporal power of this product (defined below). In this case, the components of this structure A are fixed during its work. In the general case of temporal products, the internal structure of A will be allowed to change cyclically as it operates.

TEMPORAL PRODUCT OF AUTOMATA A 1 ,A 2 , A3 WITH

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Chapters. Primitive Products and Temporal Products

We will see that the temporal compositions of the general product and the cascade product can be represented by very simple models of finite automata networks which are cyclically able to modify their inner structures. We will show that, despite their simplicity, they have a very strong completeness property. Let At = (At, Xt,8t),t = 1, 2, be automata having a common state set A (= AI = A2). Take a finite nonvoid set X and a mapping of X into X\ x X2. Then the automaton A = (A, X, 8) is a temporal product (t-product) of AI by A2 with respect to X and ( if for any a A and x X, 8(a, x) = 8 2 (8 1 (a, x\), x2), where (x\, x2) = (x). The concept of the temporal product is generalized in the natural way to an arbitrary finite family of n > 0 automata At (t = 1,..., n), all with the same state set A, for any mapping ( : X "=1 Xt by defining 8(a, x) = 8n( • • 82(8 1 ( a , x\), x2),...,*„) when (x} = (x\,..., xn). In particular, a temporal product of automata with a single factor is just a (one-to-many) relabeling by X of the input letters of some input-subautomaton of its factor or, equivalently, a quasi-direct product with just this factor. Note that the formation of the temporal product is associative. We apply the notation -product for each of the following concepts, respectively: g-product, -product, qi-product, o-product, t-product. Given a class 1C of automata, the notions (k), H(k), s(k), P (k) stand for the class of all isomorphic images for k, all homomorphic images for k, all subautomata for k, and all -products for k, respectively. We define the (left) multiplication of these operators as usual in the literature. For any sequence O\,...,On of the discussed operators we write O\... O n ( k ) instead of O 1 (O 2 (... O n (k)...)). Moreover, we use the short notion T for S PtIPp. Let us first consider some simple examples:

THREE AUTOMATA A. B. AND C. AUTOMATON C is A (SECOND) QUASI-DIRECT POWER a-POWER) OF A WITH THE FEEDBACK FUNCTIONS

6.4. Temporal Products

1 85

C\, C-2 ARE ISOMORPfflC COPffiS OF C.

AUTOMATON D1 is A t-PRODUCT OF C\ AND C-2 (HENCE A Ta -POWER OF A) , AND WITH

AUTOMATON D2 AS AN ISOMORPHIC COPY OF B.

186

Chapter 6. Primitive Products and Temporal Products

t-PRODUCT OF D2 BY D\ (HENCE A Tq -PRODUCT OF A AND B) WITH* AND

BI IS A q-PRODUCT OF A\, A2 WITH THE FOLLOWING VALUES OF ITS FEEDBACK FUNCTION AND B2

IS AN ISOMORPfflC COPY OF B.

6.4. Temporal Products

1 87

C\ IS AN ISOMORPfflC COPY OF B\ AND C2 IS AN ISOMORPfflC COPY OF B2.

t-PRODUCT OF C1 BY C2 WITH PRODUCT OF A\, A2 AND B2.

188

Chapter6. Primitive Products and Temporal Products

BI IS A qe-PRODUCT OF A\ AND A2 HAVING THE FOLLOWING VALUES OF ITS FEEDBACK FUNCTION

C\ IS AN ISOMORPHIC COPY OF B} AND C2 IS AN ISOMORPHIC COPY OF B2.

f-PRODUCT OF C\ BYC 2 WITH/I i = (HI, t>i), h2 = (MI, t^), h3 = (U2, U]) IS A Tqt PRODUCT OF A\, A2 AND B2.

6.4. Temporal Products

189

Let K, again be a class of automata. We say that the automaton A is a TB -product of automata from K if A E 7>(K) (= S P t I P B K ) . It is said that K. is complete with respect to homomorphic (resp., isomorphic) representations under the TB-product if HT B (K) (resp., 7^(K)) is the class of all (finite) automata. (Note that /S7>(K) = TB(K) and HST B (K = #7>(K) hold for every class of automata.) Now we study the T -product. Theorem 6.16. The following statements are true: (1) An arbitrary T -product of autonomous automata is an autonomous automaton. (2) An arbitrary T -product of permutation automata is a permutation automaton. (3) An arbitrary Tq-product of reset automata is a reset automaton. Let A — (A, X, 8) be an automaton and define for any x E X the automaton Ax = ( A , { x 0 , x } , x) such that X0 x is an arbitrary symbol; moreover, 8x(a, X0) = a and x(a,x) = (a, x) (a € A). Lemma 6.17. Let 1C be a class of automata which contains an automaton B with Ax 6 SPt({B}), X E X. Then A & SPt(K). Proof. Let Mx = (M, {X0,X}, S'x) € Pt(B), x e X, be automata with Ax e S({MX}). Moreover, let x 1 , . . . , xn be an arrangement of the elements of X. Take the temporal product M = MXl x • • • x MXn(X, ) such that for any xt E X, (xt) = ( z 1 , x , , . . . , zn,x,), where z1,x, = • • • = zt-i,x, = zt+i,x,. •. zn,x, = XQ and zt,x, = xt. It is clear that A is a subautomaton of M Lemma 6.18. Let 1C be a class of automata having a (not necessarily different) pair At = (At, Xt,t),t = 1,2, of elements with the following properties: (1) There is a pair a € AI, x e X\ with a 1(a, x). (2) There is a triplet a1, a2 € A2, y € X2 with a1 a2 and ($2(01, y)

82(a 2 , y).

Then for any positive integer m there can be found an automaton M = (N, X, 8) € Pq (JC), pairwise disjoint sets B\,..., B2m_m C N, and (not necessarily different) inputs yi, y2,xi,...,xs € X,s > 1, such that Bm+t = {b m+t ,b m+t (l) ... ,b m+l (s) },8(b (K) +t ,x k ) = bm+t, k=l,...,s, bm+t [b (1) m+1 ,..., b(s)+t,}, t = 1,..., m. Moreover, (la) if 1C contains a nonautonomous automaton, then for any t = 1,..., m, (bt,yi) (bt, 3*2) (and thus, yi y2); (2a) if 1C contains a nonpermutation automaton, then y2 = x\ = • • • = xs, s = m + 1, \Bm+t\ = m + 2, t = 1,..., m; and (3a) if 1C is a class of permutation automata which has a nonautonomous automaton, then s = 2,*i =yi,x2 = y2,xi / x2, Bm+t\ = 3,t = 1,... ,m. Proof. For a suitable system V\,..., Dr € AC of automata construct a quasi-direct product D1 x • • • x D r ( X ,
190

Chapter 6. Primitive Products and Temporal Products

First we prove that for a suitable M there are pairwise disjoint sets B\,..., B2m ^ N such that bt (bt,yi),8(bt,y2)},8(b(V+t,xk) = bm+t, bm+t i {b(»+t,... ,b%>+t},t = 1 , . . . , m, k = 1,..., s. (Note that the special cases y\ = y2 and s = 1 are allowed.) Let T>\ = AI and Cc') = x, x' e X. (If there is no danger of confusion, then we omit the arguments of any feedback function on which it really does not depend.) Then for an arbitrary (a, d2, ...,dr) e N and x' e X, the first component of 8((a, d2,..., dr), x') is 8i(a, x). Thus, if we suppose that for every pair b' e {bu}(J(Bm+u \ {bm+u}), u = 1,..., m, b" e (Bv \ {bv}) U {bm+v}, v = 1,..., m, the first component of the vector b' is equal to a and the first component of the vector b" is equal to 8i(a, x), then we obtain b' b". Since D1 = A\ and (x'} = x, x' e X, this assumption does not lead to a contradiction even if 8(b', x') = b" for an x' e X (by u = v and b', b" € Bu or b', b" e Bm+M). Therefore, for a suitable W and B 1 , . . . , B2m c AT we get that [bu, b( 1 ) v , . . . , b(s)+v} and [8(bu, x'), 8(bn+v, x'),..., 8(b^+v, x')}, x' e X, u, v = 1,..., m, are pairwise disjoint sets. (In particular, if u = v, then we also have this fact.) Thus, if we prove that there are pairwise disjoint sets B\,..., B2m c N having these properties, then the first part of our lemma is shown. (Naturally, yi = y2 and s = 1 are possible.) If b' — bm+u, b" = bm+v, 1 < u < v < m, then suppose the existence of an appropriate z e {1,..., r} for which Dz = A2, {dz, d'z} = {82(ai, y), 82(a2, y)}, where dz and d'z denote the zth components of b' and b", respectively. Then we obtain b' b" by (2). It remains to study the case b' e {bu}\J(Bm+u\{bm+u}),b" e {bv}\J(Bm+v\{bm+v}), 1 < u < v < m. Thenassumethe existence of an appropriates 6 {1,..., r} for which Dz = A2, {dz,d'z} = {a 1 ,a 2 }, where dz and d'z denote the zth components of b' and b", respectively. Then we obtain again b' ^ b" by (2). For every x' € X, let z(x'} = y in both of the above cases. Thus, for every pair b' e{bu}(J (Bm+u \ {bm+u}), b" e {bv} U (Bm+v \ {*„,+„}), 1 < u < v < m, and x', y' 6 X, we get 8(b', x') 8(b", y'). In accordance with 8(b +t,Xk) = bm+t, k = 1,..., 5, and ( bm+t {b m+t, • • • , m+fK t = l,...,m, let, for any z e {1,..., r}, the zth component of bm+t be equal to 82(d{, y), i = 1, 2, with Dz = A2 if and only if, for every k € {1,..., s}, the zth component of b(K)+t is equal to a,. We allowed 5 = 1 (apart from cases (la)-(3a), which we shall study soon after the general case). Thus, in the case b' e {b(^+t,..., b(+ t ] or b" e [ b 1 . t , . . . , &£+,}, the assumption {dz, d'z] = {a 1 , a2} does not contradict our restrictions holding for the structure on fli,..., B2m c N. There is no problem if (bt, yi) = 8(bt, y2), too. (In this case we may get the appropriate sets by yi = y2.) Then, apart from cases (la)-(3a), we obtained b' b" for all possible cases of b' 6 Bu and b" e Bv. Thus the required sets B\,..., B2m can be constructed. Now suppose that /C contains a nonautonomous automaton, i.e., for an A3 = ( A 3 , Xi, 83), in KC, we have a € A3, x, y e X3 with 3 (a, x) ^ 3 (a, y). Then let yi, y2 € X be given with yi y2 and suppose that t = A3 and t (y 1 ) = x, t (y2) = y hold for some t € {2,..., r}.Ifa € A3 is the tth component of every vector &r, t = 1,..., m, then we get (la).

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191

If k contains a nonpermutation automaton A4 = (A4, X4, 4), then there are a1, a2 e A4, x € X4 with a1 a2 and (a1, x) = (a 2, x). Then for any pair bm+t(u) bm+t(v) e Bm+t, t = 1,..., m, 1 < M < v < m + 1, let us give a z e {1,..., r] with Dz = A4 and {dz, d'z] = {a1, a2}, where dz and d'z denote the zth components of bum+t and bvm+t, respectively. Thus we obtain bum+t bvm+t; moreover, since pz(x') = x (x' € X) we do not get a contradiction assuming (bum+t, xu) = (bvm+t, xv) = bm+t (by y2 = xu = xv). Thus we have obtained (2a). In addition, let .As = (A 5 , X5, 5) e 1C be a nonautonomous permutation automaton, where 1C is a class of permutation automata. There exists a triplet a e A5, ;x, y e X5 with 85(a, x) (a, y). It is clear that for some pair k,l, > 1 of integers, (a, xk) = l 5(a, y ) = a. Thus there can be found a positive integer t such that r < k, I and xk-t) 5(a, x£-t) and 5 (a,x k - f+1 ) = 5(a, yl-f+1). In other words, for a suit5(a, able pair a1, a2 € A we get a1 a2 and 5(01, x) = 85(a 2 , y). For every pair blm+t, b2m+t e Bm+t, t = 1,.... m, let us give a z e {2 r} with Dz = As and{dz, dz} = {a1, a 2 ] , wheredz, dz denote the zth components of bm+t(1), b m + t 2 ) , in order. Then, by the choices PZ(XI) = x, pz(x2) = y we get b1m+t b2m+t and that the zth components of 8(b1m+t, x1) and (b2m+t, X2) are equal. Now we suppose that Dw = A5, p w (x 1 ) = x, pw(x2) = y, {dw,d'w} = {01,02} whenever the state vectors bm+t(1), bm+t(2) have different toth components dw and d'w for some w; e {l,...,r}. Then we may assume (b1m+t,x1) — (b 2 m+t ,X 2 ) = bm+t and x1 =y 1 ,x 2 = y 2 by(3a). Finally, to have the conditions x\ = yi and X2 = y2 in (3a), let v e {1, . . . , r} be not necessarily different from w with Dv = As, (pv(yi) = x, (pv(y2) = y, respectively, and let the uth component of every bt,t = 1, . . . , m, be a suitable state a e AS with 85 (a, x) 8$(a, y). Then it is clear that we can suppose x\ = yi and KI = y2. D Theorem 6.19. Any class K, of automata is complete with respect to isomorphic representations under the Tq-product if and only if it contains (not necessarily different) automata At = (A,, Xt, 5t), t = 1, 2, 3, with the following properties: (1) There exist a € AI, x, y e X\ such that (a, x) £ 8i(a, y). 02 and 82(01, x) = (2) There can be found a triplet a\,ai € A2, x e Xi having a\ 82(02, x). (3) There are a\, ai € A3, x e ^3, with a\ ^ a2 and 83(01, x) ^ 83(02, x).

Proof. If /C does not contain any automaton having (1), then fC is a class of autonomous automata. If (2) does not hold for any automaton from /C, then JC is a class of permutation automata. Finally, if 1C has no element with (3), then 1C is a class of reset automata. Thus, by Theorem 6.16, we have proved the necessity.

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To show sufficiency, we show that if 1C fulfills conditions (l)-(3), then 1C is complete with respect to isomorphic representations under the Tq -product. By Lemma 6.17 it is enough to show that for any fixed nonvoid finite set A there is an automaton A/" € Pq (K) having A € SPtI(W) for all A = (A, [yi, y2}, 8A) with 8A(a, yi) = a, a € A. By our condition (1), we get condition (1) of Lemma 6.18. Moreover, (3) is the same as condition (2) of Lemma 6.18. In addition, by (1), there is a nonautonomous automaton in /C; furthermore, by (2) the class fC has a nonpermutation automaton. Thus conditions (la) and (2a) of Lemma 6.18 also hold. Using these facts, consider an automaton N = (N, {yi, y2}, 8) as in Lemma 6.18 and a bijective mapping h : N -> N such that for every t = 1,..., m, h - 1 ( b t ) = bm+t, h - 1 ( 8 ( b t , y1) e Bm+t\(bm+t};moreover,/!-1 ( (bt, y2)) € Bm+t \ {bm+i} whenever 8A(at, y2) = at, t = 1 , . . . , m. Let M' = (N, {yi, y2}, 5') be an automaton (state-isomorphic to JV) for which 8f(h(b), x) = h(8(b, x ) ) , b e N, x e {yi, y2}. Construct the temporal product M. = (N, {yi, y2}, M) = A/" x N'({y\, y2}, (p) such that N defined by g(at) = bt,t = 1 , . . . , m, is a state-isomorphism of A onto a subautomaton of N. Therefore, A € SPtIPq (1C). By the proof of Theorem 6.19 we have also shown the following statement. Theorem 6.20. Let 1C be a class of automata containing a nonreset element. 1C is complete with respect to isomorphic representations under the Tao-product if and only if it is complete with respect to isomorphic representations under the Tq-product. By the proof of Theorem 6.19 we have proved that if 1C does not satisfy (l)-(3) of Theorem 6.19, then 1C is either a class of autonomous automata, a class of permutation automata, or a class of reset automata, respectively. It is clear that these classes of automata are closed with respect to the homomorphism. Thus we can derive from Theorem 6.16 and Theorem 6.19 the following. Theorem 6.21. Any class 1C of automata is complete with respect to isomorphic representations under the Tao-product if and only if it is complete with respect to homomorphic representations under the T -product. Now we start a complete characterization of T (1C) (and Tq (1C)) for any class 1C of automata. If a given class 1C of automata (or any member of 1C) has a number of special properties, then we list them. In this way, we may omit many new definitions. (In this sense, for example, we speak about monotone reset automata, autonomous permutation automata, etc.) Theorem 6.22. If 1C is a class of autonomous reset automata which contains a nontrivial automaton, then T (lC) = T q (K) is the class of all autonomous reset automata. If 1C is a class of trivial automata, then T (K) = Tq(lC) is the class of all trivial automata.

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193

Proof. Let A and B a pair of autonomous reset automata, where A is nontrivial. It can be easily seen that there exists a quasi-direct power of A having a subautomaton isomorphic to B. It is also clear that any class of autonomous reset automata is closed under the general product, the oro-product, the quasi-direct product, homomorphism, isomorphism, and the temporal product. Thus it remains to show that T (/C) = Tq(1C) holds for any class of trivial automata. But this statement is obvious. Theorem 6.23. If 1C is a class of autonomous permutation automata and 1C has a nondiscrete automaton with at least two states, then T (1C) = Tq (1C) is the class of all autonomous permutation automata. If 1C is a class of discrete automata containing a nontrivial automaton, then Tao (1C) = Tq (1C) is the class of all discrete automata. Proof. It is clear that for an arbitrary class 1C of discrete automata, Tq (1C) is a class of discrete automata with Tao (1C) = Tq (1C). Moreover, it is easy to show that SIPq (1C) contains all discrete automata provided that 1C is a class of discrete automata having a nontrivial automaton. Therefore, the second part of our theorem holds. It is also obvious that Tq (1C) is a class of autonomous permutation automata with Tao(JC) = Tq(1C), whenever 1C is a class of autonomous permutation automata. It remains to show that if this 1C has a nondiscrete automaton, then Tq (1C) is the class of all autonomous permutation automata. Observe that for any nondiscrete (autonomous) permutation automaton T> e K we get (1) and (2) of Lemma 6.18. Therefore, for every positive integer m there can be found an M = (N, X', 8") € Pq(1C) and, moreover, pairwise disjoint sets BI, ..., B2m c N and x e X, such that B, = [bt, 8(bt, x)}, Bm+t = [bm+tj 8(bm+t, x)}, t = 1 , . . . , m, with | ZB1| = • • • = |52m| = 2. (A/" is autonomous; therefore we can suppose s = 1 and yl = y2 = x\ = •-• = xn = x.) Let A = ({a\,..., am}, X, 8^) be any autonomous permutation automaton having m states. Give the mapping h : N -> N with h(8'(bm+t, x)) = bt, t € {1,..., m}, and h(bm+i) = 8'(bt, x) whenever 8(at, x) = at, t € {1,..., m}, x € X. (The latter condition does not lead to a contradiction because of the fact that .A is an autonomous permutation automaton.) Construct the automaton N' = (N, X, 8") (which is isomorphic to N) such that for any b' e N let 8"(h(b'), x) = h(8'(b', x ) ) , x e X. Take the temporal product M = (N, X, 8M) = Af x N'(X, (p) with (x) = (x,x),x e X. It can be immediately seen that by 8^(at,x) = al,t e { ! , . . . , m } , x e X, we get 8M(bt,x) = 8"(8'(bt,x),x) = 8" (h(bm+i), x) = h(8'(bm+i,x)) = bt. Therefore, A can be embedded isomorphically into M. Thus Tq(1C) contains all monotone permutation automata. The proof is complete. Theorem 6.24. Let 1C be a class of autonomous automata which has (not necessarily different) automata At = (At, Xt,8t), t = 1,2, as follows: (1) There is a triplet ai,a2 € AI,X e X1 with a1 ^=a2and8\(a\,x) = (a 2 ,x). (2) For suitable a1, a2 G A2 and x e X2, a\ a2 and 2 («i, x) 2(a2, x). Then T U Q (K) = Tq(K) is the class of all autonomous automata. Proof. Let A = (A, X, 8) be any autonomous automaton. We shall show A e Tq(1C). Take an arrangement a\,..., am of the elements of A and let N = (N, X, 8') be an autonomous

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automaton having the following properties: there are pairwise disjoint sets B1 , . . . , N, where (la) \Bt\ = 2, \Bm+t\ = m + U = 1, . . . , ro; (2a) for a suitable bt e Bt, Bt = [bt, 8'(bt, x)}, t = 1, . . . , m, x e X; (3a) there is a bm+t e Bm+t such that for every b^+t e Bm+t \ {bm+t} it holds that &'(b(m+t> x) = bm+t, t = l,...,m,xeX. Now let h : N -» N be a bijective mapping with h(bm+t) = bt and *'fo, *), € 5m+, \ {bm+t}, t = l,...,m, if 5(0,, x) = at,le{lt..., m}, x e X. Similar to the proofs of Theorems 6.19 and 6.23, we construct an automaton AP = (N, X, 8") (wtochisisomorptoctoAOsuchthatforanyfc' e N, 8"(h(b"), x) = h(8'(b', *)), x € X. Take the temporal product M = (N, X, 8M) = N x AT'(X, ) such that (x) = (x,x),x e X. Then for an arbitrary fixed t e {!,..., m}, 8 A ( a t , x ) = at, at e A, implies 8M(bt, x) = 8"(8'(bt, x), x) = 8"(h(b(»+t), x) = h(8'(b ( 1 ) t , jc)) = h(bm+i) = bt, where b(1)+i e Bm+i \ {bm+l}. It can be seen directly that (h 1 , h2) with h1 : A -*• N, hi(at) = bt,t = 1, . . . , m, and hi : X -» X, h2(x) = x, x e X, is an isomorphism of A onto .M. Therefore, A can be embedded isomorphically into M. To prove that Tq(JC) contains all monotone permutation automata, it remains to show that Pq (/C) contains an automaton jV = (Af, X, 5') having conditions (la)-(3a). Consider the automaton A\ in condition (1) of our theorem. By a\ a2 and 5i(fli,:c) 7 5i(a2,^),ai,fl2 ^ AI,JC € X\, it is clear that we have one of 5i(ai,^) ^ a\ , 81 (02, x) ^ 02. Thus we obtain conditions (1) and (2) of Lemma 6.18. (In particular, we also obtain condition (2a) of Lemma 6.18. Naturally, conditions (2a) and (3a) of Lemma 6.18 do not hold.) To obtain all required properties of A/", we consider B\,..., B^m ^ N defined in Lemma 6.18 with s = m + 1. Thus all requirements (la)-(3a) hold occurring in the proof of our theorem. (It is clear that in this case we get for every t e {1, . . . , m} and yi, y2 € X, 8(bt, yO = 8(bt, y2~) ^ bt.) Theorems 6.22, 6.23, and 6.24 completely characterize all classes rao(/C) (= whenever /C is a class of autonomous automata. Indeed, if /C does not satisfy condition (1) of Theorem 6.24 and, simultaneously, it contains a nontrivial automaton, then we can apply Theorem 6.23. If either K, is a class of trivial automata or K, does not satisfy condition (2) of Theorem 6.24, we can apply Theorem 6.22. Theorem 6.25. If K, is a class of permutation automata containing a nonautonomous permutation automaton, then Tao(1Q = Tq()C) is the class of all permutation automata. Proof. Let A = (A, X, 8) be an arbitrary permutation automaton and let, for every x e X, Mx = (M, {x0, x}, 8X) be as before, where x0 ^ x is an arbitrary symbol, A c M , and

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195

moreover, for every b e A, x(b, XQ) = b and x(b, x) = 8(b, jc). By Lemma 6.17, it is enough to show that for an appropriately chosen A/" e T q (K), we get Mx e SPtI({Af}), x eX. Consider a list a\, ...,am of the elements of A and let M = (N, X, 8') be an automaton with the following properties. For any distinct pair x, y e X there exist pairwise disjoint sets #1,..., B2m c N having (la) \Bt\ = \Bm+t\=3,t = l,...,m; (2a) for an appropriate bt e Bt, Bt = {bt, 8'(bt, x), 8'(bt, y)}, t = 1,..., m; (3a) Bm+t = {bm+t, blm+t, b2m+t}, where '(blm+t, x) = 8'(b2m+t, y) = bm+t, t = l,...,m. Take the bijective mapping h : N -» N such that for every t E {1,..., m}, h(bm+t) = bt, h(bm+1t) = 8'(bt, y) and for every x e X, h(b™+t) = S'(bt,x\ whenever 8(at,x) = at, {1,..., m}. Construct again an automaton M' = (N, X, 8") which is isomorphic to N and "(h(b'), x) = h(8'(b', x)), bzN,xeX. Let x0 be an arbitrary symbol. Construct the temporal product M = (N, {XQ, x}, 8X) = NxJ\f'({xo, x}, (p) suchthat^(^r) = (jc, y), X, h2(xo) = XQ, h2(x) = x is an isomorphism of Ax onto Mx. Therefore, A can be embedded isomorphically into M.. We now show N € Tq (1C). Let = (D, Xx>, 5x>) be any nonautonomous permutation automaton from AC. It can be seen easily that T> has the following properties: (Ib) For a triplet a e A, x, y e X-D, &v(d, x) ^ 8 D )(d, y). (2b) There are distinct states d1, d2and distinct inputs x, y € -Xp such that 8 D (d1,x) = 8v(d2, y). (3b) There exists a triplet d\, d2 € D, x e X having p(^i, x) 8-D(d2, x). (4b) There are d G D, x G X with 8v(d, x) d. By conditions (lb)-(4b) we obtain as follows. Using Lemma 6.18, for any distinct pair x, y € X there can be constructed a quasi-direct power of V having the conditions (la)-(3a) given above. In detail, by Lemma 6.18 we can get bt {8'(bt, x), 8'(bt, y)} and bm+t i {br£_t, bS{t], with &J!i, ^ b%>+t, t = 1 , . . . , m. By (2b), we may obtain 8'(bt, x) 8'(bt, y). Finally, the disjunctivity of B\,..., B^ comes from Lemma 6.18. This ends the proof. Of course, for every nonmonotone reset automaton A, the two-state reset automaton can be embedded isomorphically into A. Therefore, using Proposition 3.14, every reset automaton can be embedded isomorphically into a quasi-direct power of A as long as A is a nonmonotone reset automaton. Thus, by Theorem 6.16, we have the following. Theorem 6.26. If 1C is a class of reset automata containing a nonmonotone reset automaton, then Tq(lC) is the class of all reset automata and T(/C) is the class of all automata.

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Observe that Theorems 6.22-6.26 inform us about the structure of Tao (/C) and Tq (/C) whenever K, is a class of either autonomous automata, permutation automata, or reset automata. Otherwise, we can use Theorem 6.19. This is summarized in the next statement. Corollary 6.27. For every class of automata, TaQT (1C) = T (JC). Moreover, T ()C) = Tq(lC), whenever 1C consists of autonomous automata, or /C has a nonreset automaton. In particular, ifK. is a finite class of automata, then for an arbitrary automaton A it can be decided whether or not A e Tao(/C) or A e Tq (K). Now we shall study the Tg -product. Lemma 6.28. If 1C is a class of autonomous automata, then Tg(lC} = Tq(lC). The following statement characterizes all complete classes with respect to isomorphic representations under the Tg -product. Theorem 6.29. Any class /C of automata is complete with respect to isomorphic representations under the Tg-product if and only if)C contains a nonautonomous automaton. Proof. Every quasi-direct product is an ao-product. Moreover, every ao-product is a general product. Thus because of Lemma 6.28 and Theorem 6.16 we obtain the necessity of our condition. To establish the sufficiency, let A = (A, X, ) € 1C be a nonautonomous automaton with a suitable triplets € A, x, y e X satisfying (a, x) 8(a, y). Observe that K satisfies condition (1) of Theorem 6.19. By Theorem 6.20, it is enough to show that for suitable single-factor products AI, A3 of A, conditions (2) and (3) of Theorem 6.19 also hold. We prove this fact as follows: (la) There exist a\, 02 € A, x, y e X with a\ a2 and (a\,x) = 8(a 2 , y). (2a) There are a1, a^ e A, x e X holding a\ ^ a-i and 8(a\,x) ^ 8(02, y). If A is not a permutation automaton, then (by x = y) we have (la), obviously. Therefore, to establish la) it is enough to take the case that A is a permutation automaton. Then we have a triplet a e A, x, y € X with 8(a, x) ^ 8(a, y). Thus there are a pair a( (= 8(a, x)), a'2 (= 8(a, y)) from A and positive integers k, I such that a{ a'2 and 8(a{, xk) = 8(af2, y1) (= a). By an easy computation we obtain that (la) also holds. Suppose that any permutation automaton B is trivial if B is a subautomaton of A. Then by our assumptions, A has a nonautonomous definite subautomaton A. If A is not a reset automaton, then we obtain (2a) by definition. If A is a nonautonomous reset automaton, then there are a, b e A, jc, y e X with a b and 8(a, x) = a, 8(b, y) = b. Hence we get (2a). Now let us assume that A has a subautomaton that is a nontrivial permutation automaton. Then for a suitable pair b e A, z € X there is a positive integer k > 1 holding 8(b, zk) = b and 8(b, z1} b if t does not divide k. Then (2a) holds whenever a1 = b, a2 = 8(b, z k - 1 ) , and x = y = z. Indeed, since a\ a2, ( a 1 , x ) = 8(b, x), 8(a 2 , x) = b, and (b, x) ^ b, respectively, we get (2a). In the proof of Theorem 6.29 we also proved the following statement.

6.5.

Bibliographical Remarks

197

Theorem 6.30. If any class K, of automata is complete with respect to isomorphic representations under the Tg-product, then it is complete with respect to isomorphic representations under the Tqt-product. It is clear that the class of all autonomous automata is closed under homomorphisms. Therefore, using Lemma 6.28, we have the following. Theorem 6.31. Any class )K of automata is complete with respect to isomorphic representations under the Tg-product if and only if K, is complete with respect to homomorphic representations under the Tql-product. As a consequence of Lemma 6.28, moreover, via Theorems 6.29-6.31, respectively, we obtain that the Tg-product is equivalent with the Tqt -product from the point of view of isomorphic and homomorphic representation. Thus our statements also hold whenever for any i > 0 we consider either TUi -products, or TVl -products or Tprimitive -products instead of Tg -products. Thus we have obtained the next result. Theorem 6.32. For every positive integer i the Tg-product is equivalent to the TUi-product and also to the TVi-product from the points of view of both homomorphic or isomorphic representations. Similarly, the Tg-product is equivalent to the Tprimitive-product from the points of view of both homomorphic or isomorphic representations. Note that using Lemma 6.28 for any class K, of autonomous automata Theorems 6.22-6.25 gives information about the structure of Tg()C) = Tqe(K.). Moreover, if /C has a nonautonomous automaton, then Tg(JC) = Tqt(JC) is characterized by Theorem 6.31. By these facts, we obtain the following statement. Corollary 6.33. For any class 1C of automata, TgTg(JQ = 7^(/C). In particular, ifK, is a finite class of automata, then for an arbitrary automaton A it is decidable whether .4 e r.(/Q(= 7X/Q). D

6.5

Bibliographical Remarks

Section 6.1. Basic properties of primitive products were described by P. Domosi and C. L. Nehaniv [2000]. Section 6.2. Connections of primitive products and Letichevsky's criterion were also shown by P. Domosi and C. L. Nehaniv [2000], Section 6.3. By Letichevsky's result [1961], a class of finite automata is complete with respect to homomorphic representations under the GluSkov product if and only if it satisfies Letichevsky's criterion. Theorem 6.15 is the main result hi P. Domosi and C. L. Nehaniv [2000] showing the same fact for the primitive product. Section 6.4. Temporal products were introduced by G. I. Ivanov [1973]. An abstract model of multichannel finite-state machines was introduced by A. Gill [1970]. Temporal compositions of a,-products were introduced by F. Gecseg [1976a]. They were also studied by P. Domosi [1986]. All results of this section are from P. Domosi [1988].

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Chapter 7

Finite State-Homogeneous Automata Networks and Asynchronous Automata Networks Computer network routing, communication, and computation problems involving identical (or different) component processors connected according to a graph D with synchronous update are in fact just automata network problems. The interconnection digraph D, which we call the underlying digraph of the network, is often referred to in the literature as the topology of the network. State-homogeneous automata networks are those that have the same set Z of states at every node of D. They are natural generalizations of the concept of cellular automata, but many receive external inputs and have different local automata. The n-completeness of a homogeneous finite automata network means that it is able to simulate a complete homogeneous finite network in a very strong sense. The main results of Sections 7.1-7.4 (similar to the results of Chapter 2) show that the homogeneous automata networks (having all loop edges) are very stable: removing many links, the network with n 1 nodes remains n-complete as long as it remains strongly connected and has a central element. If the network has more than n nodes, then strong connectivity is enough for ncompleteness (i.e., a central element is not necessary in this case). These results are in accordance with the well-known experimental results that many real-world networks are very stable against removing several links. We also show in this chapter a new method for the emulation of the behavior of any (synchronous) automata network by a corresponding asynchronous one which is obtained by a simple construction over very similar digraph (Section 1.5). In particular, most results for automata networks can be carried over in a wholesale fashion to the asynchronous realm. Special cases of this result show how synchronous generalized cellular automata (automata networks with only one input symbol, a clock tick) and synchronous cellular automata (which, in addition, are state-homogeneous) can also be emulated by the corresponding type of asynchronous network. The results of this section also hold for automata networks over locally finite digraphs. So, for example, asynchronous universal cellular automata can be constructed from synchronous ones.

199

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7.1

Chapter 7. Finite State-Homogeneous and Asynchronous Automata Networks

State-Homogeneous Networks and Some Technical Lemmas

From now to Section 7.5, let us consider state-homogeneous automata networks, that is, automata networks in which each local component automaton has the same state set Z. We shall recover, with a new proof, an important result concerning completeness under projection for such networks, as well as an extension in Section 7.3, and in Section 7.4 further results on minimality of networks that are complete in this sense. Here we recall the definition of automata network for the special case of statehomogeneity: Given an automaton A = (A,X,8), let A = Zn for some |Z| 1 and n > 1 (where |Z| denotes the cardinality, i.e., the number of elements in Z). Then we say that A is a finite state-homogeneous automata network (of size n with respect to the basic local state set Z). Then the underlying digraph DA = ( VA, EA) of A is defined by VA = {1,..., n}, EA = {(i, j) I there exists x e X such that cpj(8x) really depends on its ith variable). A is a T>-network if D — (V, E) is a digraph with V = VA and E EAIn other words, A is a "P-network if every mapping 8X : A -»• A (x e X) is compatible with Z>. Note that a size-n automata network may be regarded as comprising n component automata At = (Z, Z" x X, ,•), / {1,..., n}, where the 5, are defined by

forz = ( z i , . . . , Zn) € Zn,x e X. One may of course notationally suppress the components of Z" in the inputs to AI upon which 5, does not really depend. If n = 1 or |Z| = 1, then we say that A = (Zn, X, 8) is a trivial (finite) automata network. In this section we will investigate the state-homogeneous automata networks having state sets of the form Z" for a positive integer n > 1 and finite set Z of cardinality at least two. Therefore, by an automata network we shall mean a nontrivial finite statehomogeneous automata network. We shall derive a sequence of technical results on self-maps of powers Gn of a group G. In later sections, we will regard G as the local state set in an state-homogeneous automata network. We start with the following result, which can be shown by elementary computation. Lemma 7.1. Given a finite group G and a positive integer n > I, let us define for every distinct i, j e {1,..., n} the Junctions F(t) : Gn -+ G", t = 1, 2, 3, FJ4) : Gn -> G", and Uij : Gn -> Gn as follows:

7.1 . State-Homogeneous Networks and Some Technical Lemmas

201

Then for arbitrary, pairwise distinct i, j, k e [I, . . . , n} we get

Proof. Although it is simple and elementary, we give a detailed proof of our statement to make the matter more understandable. In particular, we prove our statement by the following computations:

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Chapter 7. Finite State-Homogeneous and Asynchronous Automata Networks

Lemma 7.2. Given a finite group G and a pair of relatively prime integers m, n with \ <m < n, let us define for every t e {1,..., n}, the transformations T{ : Gn —> G", 7Ti(k) : Gn -+ G", k = 1, 2, 3,4, as follows:

Then for any fixed

|K= 1,2,3,4}).

Proof. For every Thus we shall show onl) k = 1,2,3,4). clear that by the simple fact that every permutation is a composite of transpositions and, moreover, transformations can be generated by permutations and elementary collapsings, using the notation in Lemma 7.1, we obtain On the other hand, {{r(0), if | k = L , 2 , 3 , 4 , l = 1, Thus, it is enough to prove that for every 1,2,3,4,1 = !,...,«}). Using = 0, 1,..., by an inductive application of Lemma 7.1, k = 1,2,3,4,l = I, We have ^•_ m _i( mo dn) )I -+./m-l (modn) {l,...,n,},y=0,l...). Therefore, because m and n are relatively prime, we receive Moreover, we also have F^ (luui applying Lemma 7.1 again, we obtain L i, j 6 {1,..., n}, and thus, having F^ c the proof is complete. We shall use the following lemma.

Hence,

7.1 . State-Homogeneous Networks and Some Technical Lemmas

203

Lemma 7.3. Given a positive integer n, let G — {g} denote a finite nontrivial cyclic group with a generator g € G. There exists an arrangement a1, . . . , am (m = |G|n)of the elements in the nth direct power Gn ofG such that for every i = 1, . . . , m — 1 there is a j e [I, . . . , n} with a,-+1 € {(gi, . . . , g,-_i, g/g -1 , gj+i, . . . , g,,), (gi, . . . , g;-i, g;g, gj+i, ..., gn)}, whenever ai, = (gi, . . . , gn) (e G"). Proof. If n = 1 , then our statement is trivial. Now let us suppose that our statement holds for n > 1 and let ai, . . . , am be a suitable arrangement of G". Then (g, a\), (g, 02), . . . , (g, a m )> (g2, flm), (g2, flm-i), • • • , (g2, fli), (g3, fli), (g3, a2), • • • , (g3, am), • • • , (*|G|, flr), where f = 1 (resp.,f = m)if |G| is even (resp., odd) is a suitable arrangement of the (n+l)th direct power Gn+1 of G, where (gK, a,-) = (gk, g1 . . . , gn), whenever, a,- = (gi, . . . , gn) (fc = 1, . . . , |G|, i = l , . . . , m). The result now follows by induction. Given a nonvoid set Y, a positive integer w, let 7y denote the full transformation semigroup of all functions from Y to Y. In addition, for every subset H 7y , let (H ) denote the subsemigroup of 7y generated by H. Moreover, for any finite set X with |X| > 1 and positive integer n > 1 , denote by Tx,n the subsemigroup of all transformations of 7x having theformF(jci,...,j: n ) = (A: f (i),...jr t ( n )), (*!,...,*„) €Xn,t \ {1, . . . , n } -» {!,...,«}, and let

where / : X2 -» X, i, 7 € (1, . . . , n}, (jci, . . . , jcn) e Xn}. (It is understood that the case i = j is allowed in the above definition of FX» .) Define the elementary collapsing tj,k : {1, . . . , n} -+ {1, . . . , n} for 1 < j k < n,

Moreover, as usual we say that Ujk : {1, ...,n}-> {1,..., n} for 1 < j transposition if

k < n is a

Finally, define ui,j : Xn -» Xn by

where (x\,,.., *„) e Xn similarly as in the previous lemma. In the following, we shall identify X in a fixed but arbitrary way with the group of residue classes of integers modulo q = \X\. Now we are ready to prove the following key lemma. Lemma 7.4. For any fixed t e {!,...,n}, Txn is generated by the union of {{r<°>, Te(k) | k = 1,...,4}} and the set of all Junctions F : Xn -> Xn having the form F(XI, ...,*„) = (*i,..., */_i, f(xit..., xn), ^+1,..., *„), / : Xn -» X, w/iere X\, . . . , Xn € X.

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Chapter 7. Finite State-Homogeneous and Asynchronous Automata Networks

Proof. We can take out of consideration the trivial case \X\ = 1. Thus we assume \X\ > 1. It is clear that without loss of generality we may suppose I = 1. On the other hand, using Lemma 7.2, {£/,,, | i,j e {!,...,«}} C ({T(0\T^ \ k = 1,...,4). Thus it is enough to prove that the union of {Ufj \ i, j e {!,...,«}} and the set of all functions F : Xn -* X" having the form F ( x 1 , ...,*„) = ( f ( x \ , . . . , *„), x2, . . . , xn) generates 7x« . For every pair i e {1, . . . , n}, f : Xn ->• X, define the function Fiif : Xn -> Xn with F i t f ( x i , ...,*„) = (xi,...,Xi-i,f(xi,...,xn),xi+i,...,xn), ( X I , . . . , X H e X). Thus, by letting /' = Uij o /, we have FJ,f = U{j o Fitf o Ufj. So for every pair i € {!,...,«}, / : X n ' - > X, Fitf € (Tx,nU{F : X"' -» Xn \ F(*i, ...,*„) = ( f ( x i , ..., xn), x 2 , * 3 , ...,*„),/: X n ^ X, *i, ...,*„ e X}). Let us identify X with a nontrivial finite cyclic group with generating element g e X. Thus we also have that for any c\, . . . , cn e X, F (1) e>J; ( C ,,... >Cn ), F(2)€i;i(cli...;Cn) € (Tx,nV{F : Xn ^ Xn \ F ( J C I , . . . , x n ) = (/(jti, . . . , x n ) , x 2 , X 3 , ' . . . ,xn), / : X»" -» X, x = (jci, . . . , jcn) € X"}), whenever € e {1, -1),

otherwise, where x = (x\,..., xn) e Xn. On the other hand, by Lemma 7.3, there exists an arrangement GI, . . . , am of Xn such that for every k = 1,..., m — 1, ;?* e {^(1)e 7 (ci c«) I 6 6 {-1,1}, j e {!,..., n } , C l , . . . , c n € X}, tk € {F(\;.,(cl)...,Cn) | 6 e {-1,1},'7 e {!,..., n}, c i , . . . , cn € X}, where

But then p\,..., pm-\ is a set of transpositions such that {p\,..., pm~i} generates all permutations over Xn. Furthermore, t1,..., tm-\ is a set of elementary collapsings over Xn. Thus by the well-known fact that for every j = 1,..., m — 1, (p\,..., pm-\, tj} generates all transformations over Xn, the proof is complete. D Lemma 7.5. Tx,n £ (IV).

7.1 . State-Homogeneous Networks and Some Technical Lemmas

205

Proof. Using Lemma 7.1, we have that for any pair i ^ j {1,...,«}, Ujj e (r x «). On the other hand, [F$ \ i, j € { ,...,«}} C (IV) holds by definition. Recall that Uij transposes the elements in the ith and yth positions and that F(3)- replaces the yth entry by the ith. Therefore, by the simple fact that every permutation can be composed as a product of transpositions and, moreover, transformations can be generated by permutations and elementary collapsings, we obtain the inclusion of our statement. Finally, it is trivial that FX« \ Tx,n is nonvoid. D

Lemma 7.6. Given an alphabet X and a positive integer n >

We have F^

<-,_,) e
Proof. If n = 2, then our statement holds by definition. Otherwise, n > 2 and for every b e X, define

where For every

where x = ( x 1 , . . . , xn) e X"). It is clear that F ) = F . On the other hand, for every i e {2,..., n - 1}, Fta.,,...,^,) = C/f-Ln-i o F£> otf,-_i,B_io F(c. Cn _ 0 . Simultaneously, we have by definition that F (0) € rx» holds for every z € {2,..., n — 1}. Moreover, by Lemma 7.5 we have i,j e (IV )• Thus we get our result by induction. Lemma 7.7. Given an alphabet X and a positive integer n _i) is allowed) and let

where. Then we have Fl Proof. We have c € X arbitrary with c , and

d, and set

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Chapter 7. Finite State-Homogeneous and Asynchronous Automata Networks

where jc = (*i,..., JCM) e Xn; moreover, define F(Cli...iC(1_,) as in Lemma 7.6. In addition,

let

and for every a e X, let

((x1, ...,xn) € X"). It is clear that Fc(3), Fd F(5), Fa(6) € YXn. Next we show that F (cL.,cn-,),(d, 4,-,)€ < r x">- Indeed, by an easy computation we get F^. Cn 0 (t/] ^_ i} = fy,....A-,) o F®, o f/ n _2, n -i o Fc^2 o f/ n _ 3>n -i o • • • o U2,n-i o F^6> o f/ lin _, o F«> o t/i, n _i o ^2,«-i o • • • o Un_2,n-i- On the other hand, by Lemma 7.7 we have Utj e (fx"). But then C.,c,-,),(« *-,) = fc<3> o F^.....c..,,,tf „._,, o Ff implies fg»...A.l)>w „._,, € (Tx"}- It remains to prove that F,(1) . ^ /j ^ ^ e (Fy n ). This connection, completing the proof, comes from Let JFxn-ix{rf} be the semigroup of functions {F e 7x« I F(^i,..., *„) e Xn l x {rf}, j c i , . . . , xn e X, where F is really independent of xn}. By the above statement we get the following result. Lemma 7.8. Fxn-1-'xw £ (IV). Proof. For every pair (ci,..., c n _i), ( r f i , . . . ,dn-\) e Xn-1, let us define the mappings F^ Cn i} (di dn i}, F^ Cn i} (d[ dn i} as in Lemma 7.7. Observe that F(c? CB_!) (dj 4_i) acts as a transposition in the permutation group over the set Xn-1 x {d}, while Ffa Cn_{) (fH dn-\) acts as an elementary collapsing in the transformation semigroup over the set Xn-1 x {d}. By Lemma 7.7 we obtain that all of these transpositions and elementary collapsings are in {Fx«>. It is well known that the set of all transpositions and elementary collapsings on a set generates all mappings on that set, so any map taking X""1 x {d} to itself may be written as the restriction to X""1 x {d} of a composite of the above functions. A moment's reflections shows that the set of all these F^ c , ,d d ., F(CI . cn-i) (di dn_1)infactgeneratesallof^:x»-1x{d}.sinceafunctioninthelatterisuniquely determined by its behavior on X""1 x {d}. In addition, it is clear that FX« \ Fx»-lx{d} is nonvoid. This completes the proof. D Now we are ready to prove the key lemma. Lemma 7.9. 7xn is generatedby the union ofTX« and the set of all functions F : Xn ->• X" having the form F(x\,..., xn) = (/(*i, • • •, xn), x2, x^,..., *„), / : X" ->• X, where X\, . .. , Xn € X.

Proof. We can take out of consideration the trivial case |X| = 1. Thus we assume |X| > 1. For every pair i e {1,..., n}, / : Xn -+ X, define the function F/,/ : X" ->• X" with

7.2. Network Completeness for Digraphs Having All Loop Edges

207

Fitf(xi, ...,*„) = (xi,..., xt-i, f(xi,..., xn), xi+i, ...,*„) (x\, ...,xneX). Thus, by letting /' = Ui j o /, we have F/ / = t/, ; o F, /> o C7, ; . So for every pair i e {1,..., n}, / : X* -» X, F,,/ e {rx«U{F : X» -> X" | F(JCI, ...', JCB) = (/(^i,..., *,,), *2, *3, • • •, *»), / :X"-^X,*i,...,jcB€X}). Let us identify X with a nontrivial finite cyclic group with a generating element g e X. Thus we also have that for any whenever

otherwise, n

where x = ( x 1 , . . . , xn) e X . On the other hand, by Lemma 7.3, there exists an arrangement a\,..., am of X" such that for every where

But then p\,..., pm-\ is a set of transpositions such that {p\,..., pm-\} generates all permutations over Xn. At the same time, t\,..., tm-\ is a set of elementary collapsings over Xn. Thus by the well-known fact that for every j = 1,..., m — 1, (p\,..., pm-\, t};,} generates all transformations over Xn, the proof is complete.

7.2 Network Completeness for Digraphs Having All Loop Edges We start with the following. Lemma 7.10. Let D= (V, E) be a strongly connected digraph containing all loop edges. Using the notation of Lemma 7.1, let Fitj : Xn -> Xn denote any of F$, F$, F$, or Utj, where i, j e V. Then

Thus F-- and Ftj (i, j e V) are composites of Junctions in FX« that are compatible with the graph.

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Chapter 7. Finite State-Homogeneous and Asynchronous Automata Networks

Proof. ForFi(4)} this is clear. We first establish that if there is a directed walk on digraph D from i to j, then Fi,j is a composite of functions compatible with the graph, where € e {1, 2, 3}. Since by Lemma 7.1 £/,-,_,• is a composite of such, the result will then follow. We shall proceed by induction on the length L (the number of edges counting repetitions) of the walk. For L = 0, we have i = j and by definition FJJ is compatible with D. Also when i = j or L = 1, clearly Ffj is compatible with X>. Now suppose that i j, L > 1, and that we have a walk length L + 1 from vertex i to vertex j. Denote the penultimate vertex on the walk by v. If v = j, then Fij = FitV, or, ifv = i, F{j — Fvj. In either case, we have a shorter walk connecting the vertices so Fij; has the required property. Otherwise i, j, and v are pairwise distinct, so by the previous lemma F,ij is the composite of F's whose subscripts are among (i, v), (v, j), j and i, and which have the required property by induction hypothesis. Recall that

(where the case i = j is allowed hi the above definition). We have the following direct consequence of the above lemma. Proposition 7.11. Consider the subsemigroup {Tx"} of 7xn generated by the elements of TX»- For any strongly connected graph on n vertices containing all loop edges, this subsemigroup is also generated by a subset of Yx« consisting of some maps compatible with the graph. Let A = (Zn, X, 8), B = (Zm, Y, <$') be networks (having the same basic set Z). We say that B simulates A by projection if there exists an H c {!,... ,m} such that every 8X : Z" -> Zn(x € X) is an //-projection of a mapping S'p : Zm -> Zm (p e Y+). If there exists a X>-network B which simulates a given network A by projection, then it is said that A can be simulated on V by projection. A digraph D is called n-complete with respect to simulation by projection if every network of size n can be simulated on D by projection. The following statement is obvious. Proposition 7.12. Given a positive integer n > 1, a digraph is n-complete with respect to simulation by projection if and only if it has a strongly connected subdigraph having this property. Consider a digraph V = (V, E) and a D-network A = (Zn, X, 8). If (i, i) £ V for some i e V, then we obviously have that the ith component of 5 does not depend on its i th-state variable. In this case the I'th component-automaton of the network must be a reset automaton without identity. (B = (B, X&, SB) is called reset automaton without identity if for every input letter x e X, {&&(b, x) \ b e B} is a singleton.) On the basis of this fact, it is clear that an important special case of the finite automata networks is when the communication link has all loop edges. In this case all components of the network may depend on their own states, too. We shall use the characterization as follows.

7.2. Network Completeness for Digraphs Having All Loop Edges

209

Theorem 7.13. Given a positive integer n > , a digraph of order n having all loop edges is n-complete with respect to simulation by projection if and only if it is strongly connected and centralized.

Proof. Sufficiency of the condition follows directly from Proposition 7.11 and Lemma 7.9, since the members of rx« are composites of compatible maps and centralization (without loss of generality at vertex 1) implies that all of 7x» is generated by maps compatible with the digraph. For necessity, obviously T> must clearly be strongly connected. Let q — \Z\, and identify the elements of Z in a fixed but arbitrary way with the elements {0,1,..., q — 1} of the modulo q residue ring of integers. Suppose F e 7z», such that the image of F excludes exactly one element of Z": |Im F\ = qn - 1, where Im F = (F(z) | z = (zi,..., zn) e Zn}. Clearly, if F is a written as a composite of functions on Zn, then at least one of them also has q" — I elements in its image. Thus it is enough to show that such a function cannot be a transition function of a network which is not centralized. For such a function F — (/!,...,/«) there exist unique a = ( a 1 , . . . , «„) and b = (bi,...,bn) such that F - 1 ( d ) = 0 and \ F - 1 ( b ) \ = 2. Since we identify Z with the elements of the ring of integers modulo q, one has the sum (*). Notice that for a bijective F' = (//,..., /„') one has X^ez™ //(z) = Ec,6z4n-1~lc«' hence, it follows, since F is "almost" bijective,

Since a ^ b, this sum is nonzero for at least one component i. Now suppose that the network is not centralized. Then for each i, the component function /} of F depends on only j variables with j < n. (Of course, the exact value of j may depend on i.) Suppose, without loss of generality, these variables are zi, •.., Zj. It follows that the cardinality of f{~1 (f{ (z\,..., Zj•, 0,..., 0)) is a multiple of q n - j . Thus,

for all components i. This contradicts (*) and a ^ b, so no such F may be a transition function of the network.

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Chapter 7. Finite State-Homogeneous and Asynchronous Automata Networks

Using the above theorem and the preliminary results above, we recover the following characterization. Theorem 7.14. Given a positive integer n > 1, a digraph!) = (V, E) having all loop edges is n-complete with respect to simulation by projection if and only if one of the following conditions holds: (1) P has a strongly connected subdigraph of order m > n. (2) D has a strongly connected centralized subdigraph of order n.

Proof. Let £> = (V, E) be a digraph having all loop edges and consider a D-network A = (Z |V| , X, 5) having the underlying graph DA = (VA, EA) with VA = V,EA = E. Suppose that A is maximal in the sense that {8X \ x e X} is the set of all functions which are compatible with DA. Using Proposition 7.12 and Theorem 7.13, it is enough to prove that D is n-complete if it has a strongly connected subdigraph D' = (V, E') of order m > n. prV'(8x) exists if Sx is really independent of all ; & V. Define the network B = (Zm, X, 8') such that for any pair b € Zm,x e X, 8'(b,x) = prV'(8x)(b) and let V = {vi,...,vm} with (1 <)t>i < • • • < vm(< | V|). Then B has the underlying graph VB = {!,..., m}, EB = {(i, j) I (vi,Vj) e E'}. On the other hand, by the maximality of A, [8'x \ x e X} is the set of all functions which are compatible with VB- Therefore, by Lemma 7.10, for all i, j € VB, there exists p e X+ such that U{j = 8'p, where Uij(zi,..., zm) = (zi,..., zt-i, Zj, Zi+\,..., Zj-i, Zi, Zj+i,..., zm), ((zi,..., zm) € Z m ). Therefore, by the strongly connectivity of DB and Lemma 7.10, for any pair i,j e VB, there exists a p e X+ such that Ufj = 8'p. (Clearly, then 8'p = 8'Xs o • • • o 8'Xi whenever p = x\ ...xs (x\, ...,xs € X).) Simultaneously, by the maximality of A, for any (i, j) e E&, there exists an x e X such that Fiijtf = S'x, where Fijtf(zi,..., zm) = (zi,..., Z j - i , f ( z f , Zj), zj+i,..., zn). Hence, taking into consideration that for every pairwise distinct i, j, k e VB, Fkj,/ = Ut,k o Fijtf o UM, we obtain that for all distinct i, j e VB and / : Z2 -> Z, there is a p e X+ having Fjjtf = 8'p. Applying Lemma 7.8 (taking X, n, d to be Z, m, z, where Z e Z is arbitrary), Fzm-lx{z} C {8'p \ p e X+}. Therefore, by n < m we obtain that for every network having the form C = (Z n , Y, 8") and input letter y E Y, there exists a word

7.3. Complete Automata Network Graphs with Minimal Number of Edges

211

p € X+ such that Sy is a {1,..., n}-projection of 'p. But then there is an H c V such that for every y € 7, there can be found a p G X+ having Sy = prn( p). This means that in this case D is n-complete. This ends the proof of our theorem.

7.3 Complete Finite Automata Network Graphs with Minimal Number of Edges In this section, we extend the investigation of P-networks by taking into consideration digraphs not necessarily having loop edges at every node. (As we have already remarked, if we consider A = (Zn, X, 5) as a network of finite automata, then its ith componentautomaton is a reset automaton without identity whenever (i, i) is not an edge of .) Problem 7.15. For every positive integer n > 1, give a complete characterization of n-complete digraphs with respect to simulation by projection. The first steps into this direction are the characterizations of n-complete networks (with respect to simulation by projection) having minimal number of edges. Recall that the n-complete digraph D = (V, E) has minimal number of edges if for every n-complete digraph D' = (V, E'), \V\ = \V'\ implies \E\ < \E'\. First we show the next statement. Theorem 7.16. Given a positive integer n > 1, a digraph with n vertices is an n-complete digraph with minimal number of edges if and only if it is isomorphic to the digraph V = (V, E) with V = {1,..., n} and E = {(i, j) \ i, j eVJ =i + l (modn) or j = 1}. Proof. It is clear that for an arbitrary m e {1,..., n}, the functions T(0), T k) \ k = 1, 2, 3,4, defined in Lemma 7.2 are compatible with Z>. Suppose that m is chosen such that it is relatively prime to n. Then the sufficiency of this statement is a direct consequence of Lemma 7.4. For necessity, we may assume the n vertices are V = {1,...,«}. First we show the existence of j e V with {(i, j) \ i e V} c E, whenever D is n-complete. Then by suitable relabeling we show that the digraph is isomorphic to the one in the statement of the lemma. Let T : Xn -> Xn such that \{T(xi, . . . , * „ ) : *i, . . . , * „ € X}| = |X"| - 1. First we show that for every F\,..., Fm e 7x«, T = F\ o • • • o Fm implies the existence of an index i preserving the property \{Fi(x\,..., xn) : x\,...,xn € X}\ = \Xn\ — 1. Of course, if FI ,..., Fm are injective, then T = F\ o • • • o Fm should be also injective, a contradiction. On the other hand, T = F\ o • • • o Fm implies | {F(jci,..., xn) :x\,...,xn € X}\ < min{|{F, (*i,..., #M) : x\,... ,xn € X}\ : i = 1,..., m}. Therefore, we obtain our assumption regarding the existence of an index i preserving the property | [F,\(xi,..., xn) : n Xl,...,xneX}\ = \X \-l. Now we identify the elements of X in a fixed but arbitrary way with the elements of (1,..., |X|) and consider Xn as a subset of the nth direct power of integers. For every (aiti,...,aitn),...,(amii,...,am,n) € Xn, let £{(au, ...,a ( >) | i = l , . . . , m } = (E"=i au> • • •' ET=i ai,n)• Let a = ( f l i , . . . , aB), b = (bi,...,bn)eXn denote distinct elements with IF,"1^)! = 0 and \F - 1 l (b)\ = 2. And let j e {1,..., n} be an index with

212

Chapter 7. Finite State-Homogeneous and Asynchronous Automata Networks

We prove that | X \ does not divide prj (£{F, (xi, ...,xn) : x\, ... ,xn e X}) . Indeed, then />r,(£{F(- (*!,...,*„) : *lt . . . ,xn e X}) = prj(^{(xi, . . . ,*„) : x\,...,xn e X}) + bj - cij) = IX^KESo"1 *) + fy ~ aJ- of course, by this equality we have that |X| does not divide />o(E{F,(*i, ...,*„):*!,...,*„€ X}). Suppose that for every j eV there exists an i e V with (/, j) £ E. Consider the set Vx of all functions of the form Xn -> Xn which are compatible with T>. Now we show that for every F € £>x, |X| divides />/v(£{F(*i, . . . , xn) : *i, . . . , xn e X}), implying F, £ Vx. By F e I?x we have that for an appropriate i e {!,...,«}, prj(F(x\, ..., *„)) = p r j ( F ( x i , ..., xt-i, x't, xt+i, ..., *„)) ((XL ...,xn) e Xn,x't e X, £ = j is allowed). Therefore, for an arbitrary fixed c e X, prj(^{F(x\, . . . , *„) : x\,...,xn € X}) = \X\pr j(£,{F(xi,...,xt-i, c,xt+i,...,Xn) : x\, . ..,*/_i,**+i f ...,*„ € X}). But then |X| divides prj(£[F(x\, ...,xn) : x\,...,xn e X}) for every j = 1, . . . , n. Hence we get F, £ Z>x- Consequently, there exists a T 6 Tx» with T ^ (Px)- This ends the proof of the existence of j e V with {(i, j) \ i e V] c. E whenever T> is n-complete. Then we are done if we can prove the existence of a permutation p : V -> V with {(P(0, PO')) I », 7 e V, p(j) = p(i) + 1 (modn)} c E. Consider the mapping r(0) : Xn -> Xn defined by r(0)(*i, ...,*„) = (*„,*!, . . . , xn _ i ) (^i , . . . , xn e X) . To complete the proof of our theorem, we will show T(0) ^ T>x if there exists no such a permutation p. It is also clear that an n-complete digraph P, having n vertices, should be strongly connected. Therefore, all vertices have (nonloop) incoming edges. Thus, by the minimality of \E\, we get \E \ {(i, j) : i e V}\ = n — 1. Simultaneously, the strongly connectivity of D implies {j} x (V \ {;}) n E 0 (where 7 € V with {(/, ;) \ i € V] c. E). On the other hand, if there exists no permutation p having the above discussed property, then by the strong connectivity of D, V x {j} c E, and \E \ {(i, 7) : i e V}\ = n - 1, we can prove |{y'} x (V \ {7}) n E\ 2, implying the existence of two distinct vertices i'i, 12 6 V with {(€, ir) | r = 1, 2, € € V} n E = {(j, iO, (7, i2)}. It is enough to prove that in this case T(0) D- Clearly, F\ e PX implies the existence of functions /* : X > X, fc = 1,2, with prik(F\(x\, . . . , *„)) = /*(*/). Therefore, the cardinality of {(yi, y2) I y* = pnk(Fi(xi, ..., xn», k=l,2, xi,...,xne X} is not greater than |X|. In a similar way, for every F\, ...,Fm eT>x,m > 1, there exist functions fk : X -> X, fc = 1, 2, such that prik(F\ o • • • o F m (x 1 , . . . , *„)) = fk(prj(F\ o • • • o F m _i(*i, . . . , A:m))), implying that the cardinality of {(yi, y2) I Jk = /?r(t(Fi o • • • o FW(JCI, . . . , *„)), A: = 1, 2, jci, . . . , xn € X} is not greater than |X|. On the other hand, the cardinality of {(ylt y2) I yk = prik(T(Q)(x^ ..., xn)), k = 1, 2, *lt . . . , xn 6 X} is |X|2, yielding to T(0) ^ Px- The proof is complete. Now we prove the following characterization. Theorem 7.17. Given a positive integer n > 1, T> = (V, F,) with V = {l,...,m}, m > n, is an n-complete digraph with minimal number of edges if and only if there exists a permutation p : (1, . . . , m} \-> {I, . . . , m] such that E = {(/?(/), />0')) I p(0. p(j) € {!,...,« + !}, p(j) = p(i + 1 (modn + 1))} U {(/?(!), p(r))}, wnere r € {1, . . . , n + 1}, r ^ 2, anJ, moreover, r — 2 and n + 1 are relatively prime.31 37 The case r = 1 is not excluded. Moreover, if there are more than n + I vertices, then all except for n + 1 are isolated.

7.3. Complete Automata Network Graphs with Minimal Number of Edges

213

Proof. To show sufficiency it is enough to prove for any n > 2 the n-completeness of V = ({I, . . . , « + !}, {(i, i + 1 (modn + 1)) | i e {1, . . . , n + 1}} U {(1, r)}), where r e {1, . . . , n + 1}, r ^2, and, in addition, r — 2 and n + 1 are relative primes. Consider the set Dx of all functions of the form Xn+l -> Xn+l which are compatible with £>. By definition, we obtain {T(0\T^k) \ k = 1, . . . , 4, } C Dx, where r(0), j-( )^ ^ _ i; . . . ? 45 are defined as in Lemma 7.2 (taking m,t,n of the lemma to be r — 2, r, and n + 1, respectively). Identifying X with a finite group and using Lemma 7.2, we get Tx,n+i £ (Dx}, too. On the other hand, we have by definition (F : Xn+l -+ Xn

| F(XI,

Xn+

| F ( X I , ..., Xn+i) = (*i, . . . , *,-_i (modn+l)> f(*i, *i+l (mod«+l))> *i+l (modn+1), • • • »

. . . , Xn+i)

= (xn+i,X\, . . . , *i-2(modn+l)» /(*!» *i-l (mod «+!))» xi • • • > xn),

f : X2 -» X, i € {1, . . . , n + 1}, (*i, . . . , JC B+ I) e Xn+l} c T>X. But then, {F : Xn+l -+

*,+!),/ : X2 -> X, i e {!,..., n + 1}, (*lf . . . , xn+l) € Xn+1} U Ti.,,+1 c (Dx), implying FX-+I ^ {^x>. Applying Lemma 7.8, this shows the n-completeness of V. Using the obvious fact that n-complete digraph must have a strongly connected n-complete subdigraph, by our minimality conditions, we consider only digraphs which have a strongly connected subdigraph, and all vertices outside of this digraph are isolated. Thus, the sufficiency just established implies that by the minimality conditions, we may restrict our investigations to the strongly connected n-complete digraphs having not more than n + 2 edges. (We can take out of consideration the isolated vertices.) If we have n + 1 vertices and fewer than n + 1 edges, then our digraph is not strongly connected. On the other hand, if we consider a strongly connected digraph V with n + 1 vertices and n + 1 edges, i.e., a cycle having n + 1 length, then for every F e (Dx), there exist * € { ! , . . . , « + !}, /) : X -» X, i = 1, . . . , n + 1, with Therefore, for any 1 < i'i < ii < ••• < im < n + 1, pr,-1)...(/Bi(F(jci, . . . , xn+\)) = (//,(*,-,+* (niod«+i)), • • • ' A, (*i*+* (modn+i))) (*i,..., *»+i e X), which obviously shows that this type of digraph cannot be n-complete. But then it is enough to consider only strongly connected digraphs having n + 1 vertices and n + 2 edges. By the strong connectivity of T> we may suppose that T> = (V, E), with |V| = n + l , | £ | = n + 2, has a cycle C = (C, Ec) with k length for some 1 < k < n + 1, where C = {w lf . . . , vk}(C V), EC = {(Vi, vi+l(modk)) I i = 1, . . . , k}(C E). Using the strong connectivity of V again, for every C C V there are distinct (u/, i>;), (v* ,vt)eE with u, ,vteC,Vj,vseV\ C. Therefore, by an induction we get the structure of V in the following manner. If k < n + 1, then V = {ui, ...,vk, vk+i, ..., vn+i], E = Ec U {(vjt+,--i, u*+,-) I i = 1, . . . , n —fc+ 1} U {(vn+i, v^)}, where £ e {1, . . . , k} is arbitrarily fixed.

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Chapter 7. Finite State-Homogeneous and Asynchronous Automata Networks

If k = n + 1, then, of course, V = C, and E = EC U {(v n+1 , ve)} for some £ € { 2 , . . . , n + l}. To complete the case k = n + 1, it suffices to study digraphs having the form X> = ({vi,..., vn+i}, {(Vi, v i +Kmodn+i)) ' {1,..., n + 1}} U {(vi, ve)}), where t e {1,..., n + 1), t 2, such that l — 2 (modn + 1) and n + 1 are not relative primes. Then n + 1 and t — 2 have a divisor d > 1. We claim that for each mapping F e (Dx), the following holds: then i

There exists an integer c(F), such that if pri (F) really depends on its kth coordinate, k- c(F)(mod d).

Trivially, our property holds for each compatible map F e T>x, as can be seen by taking c(F) = 1. Moreover, if G and F both have this property, one easily checks that so does F o G with c(F o G) = c(F) + c(G). By induction, this establishes the above property for all maps generated by composing compatible maps. Therefore, for every F e (Dx) and i e {1,..., n + 1}, prt (F) depends only on a proper divisor of n + 1 many variables, which is fewer than n. Therefore, digraphs having structure like this are not n-complete. It remains to study the case k < n + 1. Then V = {vi,... ,Vk, Vk+i,..., vn+i}, E = EC\J {(vk+i-i, vk+i) \i = l,...,n-k+l}U {(vn+1, u/)}, where t e {1,..., k} is arbitrarily fixed. Of course, if k = 1 or t = 1, then we have one of the cases discussed previously. Thus we assume k, t ^ 1. Given a set X with X >2,letMx = {F : Xn -> X" : X -l < \{F(xi,...,xn) : (*!,...,*„)€ Xn} (< X" )}. Clearly, then for every F : Xn -> X", F e (Mx). To complete our proof, by Theorem 7.13, it is enough to show that there exists a digraph V = (V, E') with n vertices such that it is not centralized, and, simultaneously, for every pair F e (Dx), H {1,..., n + 1}, H = n, the existence of prH(F) implies prn(F) e (D'x) whenever prH(F) e MX (where D'x denotes the set of all functions of the form F : Xn i-» X" to be compatible with V). By an elementary computation it can be proved that T>' = (V, E') has this property whenever E' = V x V \ { ( v t , vr) vt e V'} (and \V'\ = n). (See the detailed proof below.) Therefore, there exists a T € Mx with T (D'x}. But then for every F (Dx], H C {1,..., n + 1}, H = n, prH(F) T. Therefore, T> cannot be n-complete as we stated. Proof. We prove the following: For every pair F e (Dx), H C. {1,...,n + !}, \H\ = n, the existence of prH(F) implies pra(F) e (D'x} whenever prH(F) e Mx (where Dx denotes the set of all functions of the form F : Xn ->- Xn to be compatible with D). Observe that for every F e Dx there are fj : X -+ X, j = 1,..., 1-1,1 + 1 , . . . , n +1, ft : X2 -> X with F(xi,... ,xn) = (f 1 (x k ), f 2 ( x 1 ) , . . . , ft-1(x t -2) t ft(xt-i, xn+i), ft+\(xt),..., fn+i(xn» ((xi,..., JC.+1) Xn+l). Assume H = { I , . . . , n + 1} \ {/} with i t (I1, n + 1}. If i = t, then /^+i really does not depend on its variable. Moreover, f\ and fk depend on the same variable. In addition, prjj (F) has only n variables. This implies \{prH(F)(xl,...,xi-i,xi+l,...,xH+l):(xi,...txi-i,xi+l,...,xn)eXn} < X n~2. If / = k, then /i and fk+\ really do not depend on their variable (and prH (F) has only n variables), which also leads to the above result. In addition, i f i £ { t — l,l,k,n + l}, then fi+i really does not depend on its variable (and prH(F) has only n variables). Hence we get \{prH(F)(xi,...,Xi-i,xi+i,...,xn+i) : (xi,... ,*«_i, xi+i,..., xn) Xn}\ < Xn-1.

7.3. Complete Automata Network Graphs with Minimal Number of Edges

215

Therefore, H = {1,..., n + 1} \ [i], i e {1,..., n + 1} \ (t - 1, n + 1} and F = Fl o ... oFm,Fl,...,FmeVx implies \{prH(F)(x1,...,xm):(xi,...,xn) e Xn} Xn-1\. Hence, in this case, /?r# (F) £ MX- Thus we may assume H = [ I , . . . , n + 1} \ {/}, i e { £ - l , n + l}. Let F = FI o • • • o Fm with F\, . . . , Fm eT)x, such that prH (F) exists for a suitable H = { I , . . . , i — 1, i + 1 , . . . , n + 1}, i e {t — 1, n + 1}. It remains to prove that there exists a mapping T e D'x satisfying pru(F} = T (either prH(F) e MX or not). First we study the case m = 1. Consider a mapping F € DX, a set /f = {!,..., i — 1, i + 1,..., n + 1} with i e {£ — 1, n + 1} (such that the existence of prH(F) is not supposed). First we prove that prjj(F) exists and there exists T e D'x having prH(F) = T. Define functions/, : X -+ X, j e {1,..., t-\, t+\,..., n+1}, ft : X2 -> X with F(XI, ..., xn+i) = (fi(xk), / 2 (*i),..., fi-i(xt-2), ft(xt-i, xn+i), fi+i(xi),..., fn+i(xn)) ((xi,..., xn+\) e Xn+l}. Assume i = t — 1. Clearly, then ft really may not depend on its first variable; i.e., there exists a g : X —> X with ft(xt-i,xn+\) = g(xn+i) (xt-i,xn+i € X).Therefore, wecan write F(XI, ..., xn+i) = (fi(xk), f2(xi),..., n+1 ft-i(xt-2), g(xn+i), ft+i(xt),..., /»+I(JC B )) < ( j c l f . . . , xn+l) e X ). Take T : Xn -» Xn 6 D'x vrHhT(xi,...,xt-3,xi-2,xi,...,xn+i) = (f\(xk), / 2 (*i),..., ft-2(xt-i), gU B+ i), /£+i(^),..., /B+i(^«)) ((*i, • • •, ^n+i) e Xn+1). Obviously, then prH(F)(xi, ..., Xi-2, Xi,..., xn+i) = T(XI, ..., ;t£_2, Xi,..., xn+i). Then we get the existence of prH(F) and that prH(F) — T with T e D'x- We can handle the case i = n + 1 similarly. Now let i = t — 1 and m > \. Take a pair FI € (D*) and F2 € £>x- Studying the case m = 1, we have already proved the existence of appropriate mappings /2j : X -> X, j = 1,..., t - 1, t + 1 , . . . , n + 1 and g2 : X -> X for which F 2 (*i,..., *B+i) = (/2.lUjfc)» /2,2(^l), • • - , /2,£-2(^-3), /2,£-l(^£-2), g2(^n+l), / 2 ,*+l(**),•••,/ 2 ,n+l(*n))

((jci,..., jcn+i) e Xn+1). Then there exists r2 e Z)^- with r 2 (^i,..., xi-$, xe-2, xt,..., Xn+l) = (f2,l(Xk),

/2,2(Xi), . . . , /2>/-2(^-3), ft(^n+l), / 2 ,M-lfo), • • • » /2,n+lU«»

((^1>

..., jc^-i, j c £ , . . . , Jcn+i) € X"). Clearly, then prw(F2) = T2. Let us suppose inductively that prH(F\}(x\,..., *£_3, ^_ 2 , x f , . . . , xn+i) = T{ o • • • o I^fo,..., ^_3, ^_ 2 , ^, ..., JCB+I) ( ( x i , . . . , xt-2, X L , . . . , xn+i) € X n } for appropriate T / , . . . , T^ e D'x. (Note that, considering the case m = 1, we have the existence of T[ € D^ for m = 2.) Put TI = T{ o ••• o r^_: and let TI^I, ... ,xt-3,xt-2,xt, - - - ,xn+i) = ( f i , i ( x i , . . . , Xi-2,

Xt,..., Xn+i), . . . , fi,t-2(Xi, • • • , Xt-2,

. . - , X n + 1 ),

fitt(Xi, ..., Xi-2,

XL,..., Xn+l),

fl,l+l(Xi, ...,Xi-2tXt, ...,Xn+i), ...,/!,„+! (Xi, ...,Xt-2,Xt,...,Xn+i))((Xi,

...,

Xt-2,

Xi,..., JC B+ I) e Xn) for appropriate /; : Xn -> Xn, j = 1, ...,t- 2, i,..,, n + 1. Hence TI o T2(x\,..., **_3, ^_ 2 , ^ , . . . , JCH+I) = (/ 2 ,i(/uUi, • • •, ^-2, , • • •, *B+I)), /2,2(/l,l(^l, • • • , Xi-2, (/l,n+lC*l> • • • » Xi-2,

Xt,..., Jf«+l)), • . . , /2>/-2(/M-3(*l, • • • . ^-2, ^, Xt, . . ., Xn+i)), /2,t+l (fl,l(xi,

• • • , Xi-2,

• • • , JCn+l)), ^2

Xt, • • • , *n+l))» • • • » /2,n+l

(fi,n(xi, • • •, JC£-2» ^, • • •, ^n+i)))- On the other hand, the existence of TI € (D'x) with prH(Fl)(Xl,...,Xt-3,Xt-2,Xt,...,Xn+i)

= Ti(Xi,...,Xt-3,Xt-2,Xt,...,Xn+i)

((*i,

. . . , xt-2, xt,..., xn+i) e X") and the formula T\(x\,..., ^_3, */_2, x / , . . . , xn+1) = (/l,l(-^l> • • • ,-*€-2»^» • • • »*«+l)» • • • »/l,£-2(^l. • • • ,Xi-2,Xi, . . . ,Xn+i),fiti(Xi, Xt, • •• ,*n+l), fl,t+l(Xi, . . . ,Xt-2,Xt, . . . ,Xn+i), ..., fl,n+l(x\, . . . , Xi-2,

...,

Xt-2,

Xi, • • • , *n+l))

((*i,..., xt-2, xt,..., xn+i) e X") implies the existence of gi : Xn+l ->• Xn+l such that

FI(XI, . . . ,Xn+i)

=

(/l,l(Xl, . . . ,Xt-2,Xt, . . . ,Xn+i), . . . ,fl,t-2(Xl,

. . . ,Xt-2,Xt, . . . ,

Xn+l), fl,t-l (Xl, ... ,Xt-2,Xt, ... ,Xn+i), gi(x\, . .. ,Xn+i), fitt+l(Xi, ... ,Xt-2,Xt, . . . ,

xn+i),..., fi,n+i(xi,..., xt-2, xt,..., xn+i))((xi,..., xn+l) e X"+1). Obviously, then

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Chapter 7. Finite State-Homogeneous and Asynchronous Automata Networks

P?H (F\ o ¥2) exists and coincides with T\oT2. Therefore, we have that whenever FI e DX and FI e (Dx), the existence of prH(F\) with prH(F\) <E (D'x} implies the existence of prji(F\ o F2) such that prH(F\ o Fj) e (D'x). It is clear that considering the case m > l,i = n + 1, we obtain the same consequence. Therefore, we could prove our statement by induction.

7.4 Completeness and Computation The next statement Shows a very simple example for n-complete digraphs. (We should note that it can be derived as a consequence of Thdorem 7.17.) Proposition 7.18. Given a positive integer n > 1, V = (V, E) with V = {1,..., n + 1} and E = {(i, i + 1 (mod n + 1)) | i e V} U {(1, 1)} is an n-complete digraph?*

JVoo/.LetA^. = {F : Xn+l -+ Xn+l \ F(Xl,... ,x n+1 ) = (/(*i,* n+ i),*i,*2, ...,*„), f : X2 ->• X, xi,..., xn+i € X}. We have by definition that all F e Ax«+i are compatible with T>. In particular, T : Xn+l -> Xn+l with T(XI, ..., *n+i) = (xn+i, xi,..., *„)(*!,..., xn+\ € X) is also compatible with Z>, so for every i e {1,..., n + 1} and F e AX«+I, [I] : Xn+1 -> Xn+l r (i-Kmodn+i)) oFor «-i+i € (A xn+1 ). In other words, for all functions F having Fll](Xi, ..., Xn+i) = (X\, ..., X,-_2(modn+l), f(*i, *i-l(modn+l)), *i> •••, Xn+i), I €

{!,...,n + I } , / : X2 -> X,xi,...,xn+i e X, we get F1''1 € {Ax»+i}. Considering the functions defined in Lemma 7.1, then we get Ff_lf, F^4\ F^ j € (Ax»+i),*' € {2,..., n + 1}, k e [1,2,3}, t € {!,...,« + 1}. Applying Lemma 7.1, this leads to F$, Ff\ Ufj e (A xn+ i), i, j e {1,..., n + 1}, k e {1, 2, 3}. But then, using Lemma 7.8, we receive ^x"x{d} ^ {A*«+i). In other words, for an arbitrary F : Xn+l -> Xn+1 with F(XI, ..., xn+\) £ Xn x {d} (xi,..., xn+i e X, d is fixed and F independent of *n+i), we have F e {A^»+i >. On the oihet hand, of course, for any F': Xn -> Xn there exists an F e Fx*x(d] such that F' = FH, when /f = {1,..., n}. Therefore, D is n-complete. Now let for any fixed i, j e {1, . . . , n + 1} and / : X2 -> X, F € rxn+i with. . . . , *n+1) = (*!,..., x,-_i, f ( x i t X j ) , xi+i, ..., Xn+i) (x -I,..., xn+i € X), and moreover, let F [ / + 1 ( m o d n + 1 ) ] (*i,...,X n + i)

=

(Xi,...,X|-_i(modn+l),/(^+l(modn+l),^),^,

. . . , X B+ I). Using F»+1 (modn+1)] e < A xn+ , ) and F = £/w+1 (modn+1) o t/w o F^1 <mod"+1>] o Ui+i(nodn+i).j, we get F e (A x «+i), which leads to T^+i c (A x «+i). For a positive integer n > 1, let K = {/i, . . . , 4), L = {y'i, . . . , je] be subsets of {!,..., n}. Moreover, let F : Xn > XM be a transformation. The (K, L)projection of F, if it exists, is defined as the function prK
As before, k (modm) denotes the least positive integer I for which m\k — (..

7.4. Completeness and Computation

217

be finite automata networks (having the same basic set Z). We say that B computes A if there exist subsets {1,..., m} such that every (x e X) is a (K, L)-projection of a mapping : Zm -> Zm (p e Y+). (Of course, in this case we should have If B is a D-network and B computes A, then we also say that D computes A. D is called n-complete with respect to computation by projection if every network of size n is computable on D. Problem 7.19. For every positive integer n > 1, give a complete characterization of n-complete digraphs having all loop edges with respect to computation by projection. We show the following partial result regarding the above problem. Theorem 7.20. Let us consider the family of linear digraphs of the form

Cm is n-complete with respect to computation by projection if m > 2n + 1.

Proof. We will omit the study of the trivial case n = 1. Thus we assume n > 2. Let us identify X with the -degree cyclic group with a generator g e X and identity element e e X (i.e., = e holds). First we prove that for every finite set X with , a pair of positive integers n, I with t < n, and elements c 1 , . . . , cl G X, the function FClt...,Ct is a composite of L2n+1 -compatible functions whenever Fc1,...,ct(Xl,...,X2n+l)

Put TI(XI, ..., x2n+1) = (x1,• • •, xe, e, g, xi+3,..., x 2n+i )- In addition, tor every € e {-1,1}, i, j = 1, ...,l + 1, i < ;, let

(x 1 ,..., x2n+1 € X). Of course, Te and all i = 1, . . . , l , c e X) are compatible with L2n+1 • On the other hand, observe that , defined in Lemma 7.1 (taking n of the lemma to be 2n + 1), are also £2n+1 -compatible. In addition, using computations similar to those in Lemma 7.1, for every pairwise distinct i, j, k € (1, ...,t + 1} and c e X, we obtain

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Chapter 7. Finite State-Homogeneous and Asynchronous Automata Networks

Hence, it is clear that all functions Re,ij,c ( {—1» 1 } , i , j = 1,.. ., + l,i < j, c X) can be composed of 2n+1 -compatible functions. Thus, applying the fact that for every i = 1,...,€,

and using the obviously £2/1+1 -compatible function

..., x2n+i € X), we obtain FCl,...)Q = TI o /?i,i^+i )Cl o Tc\,t o • • • o RI,1-1,1+1,0^ ° i,£ °fli,£,M-i,c€° 7^,* ( A , . . . , Q € X). This ends the proof that for every i < n and , . . , Q e X, FCI>...)Q is a composite of £2^+1 -compatible functions. Now we define the £,2n+\ -compatible functions

T ( X 1 , . . . , x 2n +l) = (x1 • • • -Xn+3,

x n+3,

xn+4, • • • , x2n)

(x 1 ,..., X2n+1 € X), and for every f : Xn -> X, let

Put

and consider for every c,d e X,

(x 1 ,..., x2n+1 € X). For every f : Xn -> X, set

Then we have for every fi : Xn -> X, i = 1,..., n, x 1 , . . . , X2n+1 e X,

7.5. Asynchronous Automata Networks

219

(where y, z € {e, g}). By our constructions, the above-defined function is a composite of £2«+i -compatible functions. Hence, taking into consideration that ft : Xn -» X, i = !,...,«, are arbitrary, this completes the proof for the case m = 2n + 1. It is also clear that this implies the validity of our result for every m > 2n + 1, too. Problem 7.21. For every positive integer n > 1, give a complete characterization of n-complete digraphs with respect to computation by projection (such that we take into consideration the loop edges of the communication links as we discussed in this section).

7.5 Asynchronous Automata Networks In this section we derive a general result which shows how it is possible to emulate the behavior of a given synchronously updated automata network by a corresponding asynchronous one. This allows one to transfer results concerning the usual (synchronous) automata networks to the asynchronous realm, including, for example, cellular automata and their generalizations. Moreover, the result also holds for infinite automata networks over locally finite underlying graphs. We show that any automata network A with global synchronous updates can be emulated by another one, A, whose structure derives from that of A by a simple construction but whose updates are made asynchronously at its various component automata (e.g., possibly randomly or sequentially, with or without possible simultaneous updates at different nodes). By emulation, we refer to the existence of a spatial-temporal covering (local time), allowing one to project the behavior of A continuously onto that of A. We also show the existence of a spatial-temporal section of the asynchronous automata network's behavior which completely determines the synchronous global state of A at every time step. We give the construction of the asynchronous automata network, establish its freedom from deadlocks, and construct local time functions and spatial-temporal sections relating any possible behavior of A to the single corresponding behavior of A on a given input sequence starting from a given initial global state. This establishes that the behavior of any synchronous automata network actually can be emulated without the restriction of synchronous update, freeing us from the need of a global clock signal. Local information is sufficient to guarantee that the synchronous behavior of A is completely determined by any asynchronous behavior of A starting from a corresponding global state and given the same input sequence as A. Moreover, the relative passage of corresponding local time at any two nodes in A is bounded in a simple way by approximately one-third of the distance between them. As corollaries, any synchronous generalized cellular automaton or synchronous cellular automaton can be emulated by an asynchronous one of the same type. Implementation aspects of these asynchronous automata are also discussed, and open problems and research directions are indicated. Relaxing our usual assumptions, for this section we will allow consideration of automata networks over possibly infinite digraphs. For a digraph T> = (V, E), we say node w is a neighbor of v if there is an incoming edge from w to v, that is, (w, v) e E. The neighborhood of v is the set N(v) c V of all neighbors of node w. The reflexive-symmetric

220

Chapter 7. Finite State-Homogeneous and Asynchronous Automata Networks

closure T> of a digraph V = (V, E) is a digraph the same set of vertices V and edges

Thus £> has as edge set the symmetric and reflexive closure of the relation E. The digraph T> is essentially the same as the underlying undirected graph ( ) of D with all loop edges added. The digraph V is locally finite if its reflexive-symmetric closure has no node with infinitely many neighbors. Here we will define a slightly extended concept of automata network that allows for synchronous or asynchronous updates of the states of local automata which are connected according to a locally finite digraph. As before, an automata network (or P-product of automata) is defined by giving a digraph D = (V, E), a V -indexed set of automata Av, an external input alphabet X, and a V -indexed set of feedback functions that are compatible with D. Specifically, to each vertex v e V, let an automaton Av = (Av, XV,8V : Av x Xv -> A,,) be associated. The set Av is the set of local states, Xv is the set of local input letters, and 8V is the local transition function at node v. As before, if there is no danger of confusion, we write av • xv for the state 8v(av, xv) whenever av e Av and xv e Xv. A global state of the automata network A is an element a of A = Y[v€y AV For a vertex v e V, denote by av e Av the u-component of a. Let X ^ 0 be an external alphabet, and let Xs = X U {9} where 3 X may be regarded as a wait symbol. For each node v € V, let there be a feedback function

This determines a local input letter xv e Xv to Av as a function of the external input letter (or wait symbol) x e X9 and the state nodes in the neighborhood of v. We may extend > Xv by letting ^(a, *) = = (V, E), automata {Av}vev, feedback functions [
where av e Av is the u-component of global state a 6 A. With these data A is the (synchronous) automata network (or a general product or Gluskov product) of local automata Av over the digraph Z> according to the feedback functions pv. In this synchronous case, the wait symbol 5 is actually superfluous and X rather than X9 may be used throughout, as we shall see. It is only required in the asynchronous generalization, so in the synchronous case the definition of automata network here is essentially identical to the standard one. For all natural numbers n e N, let xn be a letter in X. If the sequence x\, x%, x$,... is input to A in a synchronous network, starting from an initial global state a(0) e A with v i->- av(0), then the global state a (n) of A at time n is given inductively by

7.5. Asynchronous Automata Networks

221

for alFn > 1. Note that we are using a discrete model of time. Thus the successive states of the local automaton Av at node v, av(0), av(l), av(2),... and the successive global states o(O), a(l), a (2),... of the entire network A depend in general on the particular values of external inputs, except in the case \X\ = 1. The function a : N -> A with a(n) having u-component av (n) e Av is called the behavior of the synchronous network A on the given input sequence {.x,,}weN and initial state a(0). Note also that in this synchronous case, a letter is read at each update, so the wait symbol is never used in place of an input letter by any feedback function = (V, E), a V-indexed set of automata Av, an external input alphabet X, and a Vindexed set of feedback functions {(pv}v^v that are compatible with A V-indexed family of read functions

which are used to determine whether the feedback function for node v receives the wait symbol 9 or a letter of external input, is also required. These ingredients completely determine the asynchronous automata network A. We will allow local update at a node v without necessarily changing local state at any other node, and local automata will be allowed to read the global input sequence asynchronously and independently according to their update times and local state in their neighborhoods. In particular, local automata will be allowed to wait (as a function of the state of their local neighborhood) before reading the next letter of external input. To capture the notion of asynchronous local updates, embed N as a model of time arbitrarily into the nonnegative real numbers R+ (or nonnegative rationals Q+, or N),

with r(0) =0 and i < j implying r(i) < T(J). At time t(ri) with n positive, a set of local updates will occur simultaneously in the asynchronous automata network. During the half-open interval [0, r(l)), the state of the automata network is an initial global state a(0) as above. For each n > 0, during open interval (r(n), r(n + 1)), the state of the network does not change at all. At time r(n), let UT(n) ^ V denote the nodes updated at time r(n). Formally, a (local) update is said to occur at node v 6 V at time r(n) e R+ if and only if v lies in the update set Ur(n). Thus subsets of the local automata of A will be updated instantaneously at time points r(l), r(2), ..., with all local automata having nodes in the update set UT(K) updated simultaneously as a function of the current states of their neighbors and possibly the input letters they are currently reading. We require that each node v e V is updated an unbounded number of times, i.e., v € Ur(n) for infinitely many n e N. An update pattern (T, V) of an asynchronous network is an order-preserving function (as above) T : N ->• R+ together with a family of update sets UT(n) V,n > 0. (Sometimes we will suppress the update sets and refer to r as an update pattern.) For t e R+ \ r(N)

222

Chapter 7. Finite State-Homogeneous and Asynchronous Automata Networks

and also for t = 0, one may define Ut = 0. Then for all moments in time t e R+, an update occurs at node v at time t if and only if v e Ut. A run of a network is a sequence of global states a(t) of the network, and we will soon see how an update pattern together with a infinite input word [xn}n>o (with xn in X for all positive natural numbers n) determine a well-defined run a : E+ -> A, with component values #„(?) = (o(O)u e A^ at time t e R+, called the (continuous) behavior of the asynchronous network A for this update pattern and input sequence, with initial global state a(0). The restriction a : r(N) -» A, of a to r(N), is called the (discrete) behavior of ^4 and clearly determines the continuous behavior a on R+, since nothing in the network may change at any t g r(N). An update pattern is not a part of the specification of the automata network and need not be given in advance. An update pattern and external input sequence are, however, required to determine a behavior of the network. Local Reading and Waiting. For each node v e V, we assume a next available letter *„*(„) €. X—which one will depend on how far Av has read(!)—is available at time r(n) to be read from the sequence of global external inputs x\, *2, £3,... which are read sequentially but not synchronously by the local automata in the asynchronous network. That is, the letters of external input x\, X2, x$,... are read in sequence at each node v, but node v is also permitted to wait and update itself before reading (or "consuming") a letter. This is why the feedback function must handle the case when the next letter is not to be read yet, i.e., {0,1} by defining Thus pv(a) does not really depend on the w-component aw of a € A unless w e N(v). If pv(d) = 1 when v e Ur(n), then the next external input letter is read and passed to the feedback function 0, if v e UT(n) and the next letter locally available for reading is x e X, a local update of state at node v is given by

Note that the values of
7.5. Asynchronous Automata Networks

223

Details of Asynchronous Behavior. To keep track, as external observers, of which letter of the external input sequence is currently available at time r (n) at node v, we note that the index n*(v) to the next letter for node v at time r(«) is given inductively by l*(v) = 1 and

Thus, starting from the first letter of the global input sequence {*n}n6N+> the index to the next input letter is advanced if and only if the input letter in position n*(u) has been read when Av was last updated. Thus the next external letter which may be read by the local automaton at node v e V at time r(n), with n a positive natural number, is denoted *n*(u) € X.

Up to but not including time T(«), the local automaton at v will have consumed x\,..., jcn*(v)_i. Thus *„.(„) indicates the next letter that the local automaton may consume at time r(h). It is important to note that the local automata Av do not themselves carry any information on what the next letter will be or where to find it, any more than do standard finite automata reading an input sequence. The notation jcw*(v) merely allows an external observer to describe which is the next letter of the external input sequence that is available to the local automaton. The updates of state at node v for n > 0 are formally described by

where *„*(„) e X is the letter in position n*(u) of the external input sequence. Recall that no change of state occurs at time t unless t = r(n) for some n > 0. Therefore at every node v e V, for all times r in the half-open interval [r(n — 1), r(n)), where n > 0, we have av(t) = av(x(n — 1)). Thus the state of node v during this interval, i.e., the state from time r(n — 1) up to and including any time just before time r(n), is exactly av(r(n — 1)). Given an initial global state a(0), the above update rule determines the state av(t) of Av and hence the state a(t) of the entire network for all t e R+, so we have a well-defined run, the (continuous) behavior of A. Note that if external inputs are always read (i.e., pv(a) = 1 for all a e A, v e V) and Ur(n) = V foreveryn > 0, then the sequence of global states a(r(0)),a(r(l)),a(r(2)),... is exactly the behavior of a uniquely determined corresponding synchronous automata network. To state our main result, we introduce notions of spatial-temporal covering and of asynchronous emulation (related to the notion of isomorphic simulation for automata).39 A spatial-temporal covering for digraph D is any function A, : R+ x V -> N such that following conditions hold: (1) The restriction A : M.+ x [v] -» N of A. to every given vertex v e V is surjective. 39 More general definitions of emulation allowing differing sets of nodes and alphabets for A and A, partial definition of it, etc., are possible (in analogy to the classical notion of division for synchronous automata), but for simplicity we shall use this one, which suffices for our purposes here.

224

Chapter 7. Finite State-Homogeneous and Asynchronous Automata Networks

(2) A is locally monotonically increasing, i.e., for all t, t' e R+ and v e V,

(3) For all t, t' e R+ and v € V,

where d denotes the distance metric in the associated digraph T> (the reflexive-symmetric closure of the relation E)• Let A be an synchronous automata network over a digraph = (V, E) with global state set A, and let A be an asynchronous automata network with the same input alphabet X, a digraph T>' = (V, E') with the same set of nodes, and global state set A. Let TT : A —> A be a function from global states of the asynchronous automata network to global states of the synchronous one, such that (a) = (n(a))v depends only on av for all a e A. Thus we can denote (n(a))v by n(av). ^ We then say that the behavior a : E+ ->• A of A starting in state a(0) for update pattern (r, U) ami input sequence x\, *2,... (*, € X for / € N) emulates the behavior a : N -> A of A starting in state a(0) with the same input sequence under the projection n if there exists a spatial-temporal covering A. : E+ x V -» N such that the following diagram commutes for each v € V:

That is, 7r(flj,(0) = av(k(t, v)) with av(n) = state in A of node v at time n e N and av(t) = state in A of node v at time t € R+. Theorem 7.22 (asynchronous emulation of synchronous automata networks). Let any synchronous automata network A over a locally finite digraph T> = (V, E) with local automata Av = (Av, XV,SV) (v e V) and external input alphabet X be given. We construct an asynchronous automata network A (with the same input alphabet X) such that every possible behavior of A with input sequence [xn}n>o emulates the (only possible) behavior of A with input sequence [xn}n>Q, when A starts in an initial global state a (0) depending only on the initial global state a(0) of A. Moreover, the following hold: (1) The underlying digraph for A is the reflexive-symmetric closure of the digraph for A (2) For each vertex v, the local automaton Av of A are not much more complicated than the local automaton Av of A. Moreover, Av is a direct product of Av, an identityreset^automaton, and a modulo three counter (with identity).40 In fact, Av has state set Av = Av x Av x {1, 2, 3}. ^Recall that forn > 1, a modulo n counter with identity is an automaton C\ = ({1,..., n}, {+0, +1}, Sc\) with Sci (i, +1) = i + 1 (rnodn), and &c\ (i, +0) = i, i = 1,..., n.

248

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Index generalized cellular, 231 generalized definite, 45 identity-reset, 44 monotone, 44 nilpotent, 44 one-channel analog of k-channel automaton, 183 prime divisors of, 74 reset, 44, 83 reverse definite, 45 semi-elevator, 114 set of generators of, 44 strongly connected, 44 trivial, 44 weakly (h, k) -definite, 45 weakly k-definite, 45 weakly nilpotent, 44 weakly reverse k-definite, 45 automorphism, 4

alphabet, 3 antihomomorphism, 4 anti-isomorphism, 5, 27 aperiodic automaton, 74 semigroup, 74 transformation semigroup, 74 associative law, 4 asynchronous automata network, 199 asynchronous automata network behavior of, 222, 223 automata network, 44, 58, 60 asynchronous, 199, 220, 221 behavior of, 223 state-homogeneous, 44, 199, 200,

208 synchronous, 220 underlying digraph of, 200 automaton

basis, 4 behavior of asynchronous automata network, 222, 223 of synchronous automata network, 221, 223 branch, 24, 37

#r,84

k-channel, 183 aperiodic, 74 autonomous, 44 cellular, 199 characteristic semigroup of, 50, 55 commutative, 45 connected, 44 counter, 45, 156 counter with identity, 45, 224 definite, 45 directable, 45 discrete, 44, 55 elevator, 45 embedding, 46 flip-flop, 46

catenation, 3 cells of cellular automaton, 232 cellular automata, 199 implementations, 233 class of automata, 64 commutator, 8 compatibility

253

254

for a digraph (elementary), 26 complete penultimate permutation, 32, 33, 36, 37 completeness precomplete class, 90 group complete (for classes of digraphs), 42 homomorphic representations with respect to -product, 161 homomorphic representations with respect to general product, 161 penultimate permutation, 29, 32 with respect to homomorphic representation for general product, 67 with respect to simulation under projection, 208 component of a mapping, 3 composition series, 20 configuration group, 27 semigroup, 27 space, 26 configurations permutation group on, 27 transformation semigroup on, 27 conjugation, 5 coset left, 6 right, 6 counter, 45 modulo n, 45 of length n, 45 counter with identity, 45, 224 modulo n, 45 of length n, 45 covering spatial-temporal, 223 criterion Krohn-Rhodes, 74 Letichevsky's, 68, 72, 98, 141, 142, 147, 152, 155-157, 159-161, 166, 167, 172, 174, 176, 180, 182, 197

Index semi-Letichevsky, 68, 121 size, 114 without Letichevsky criteria, 68 cycle, 24 disjointness, 24 length of, in an automaton, 46 of length n, 9 real, 24, 166 dead state, 44 digraph, 23, 200, 207-211, 213, 214 n-complete, 41 associated undirected graph, 24 centralized, 24, 210 connected for a vertex, 24 group n-complete, 41 homomorphically n-complete, 39, 41 homomorphically group n-complete, 40, 41 homomorphism onto, 24 intercommunication, xi, 25 isomorphically n-complete, 39, 41 isomorphically group n-complete, 40, 41 isomorphism, 24 outerplanar, 25 penultimately permutation complete, 29 planar, 25 strongly connected, 24, 37, 210 with all loop edges, 24 direct product of transformation semigroups, 15 directed graph, see digraph distance in an undirected graph, 24 division for automata, 54 in equal lengths, 54 of automata by semigroups, 56 in equal lengths, 56 of semigroups, 5, 16 of transformation semigroups, 16, 17

255

Index duality between position and contents, 13, 21, 27, 30 edge endpoints, 24 loop, 24 of a digraph, 23 of undirected graph, 24 self-loop, 24 elementary collapsing, 9 D(l) -compatible, 26 embedding in equal lengths, 56, 83 of semigroups, 16 of transformation semigroups, 15 face, 25 boundary of, 25 outer, 25 unbounded, 25 faithful semigroup action, 15 feedback, 60, 62 function, 59 feedback function for asynchronous automata network, 220 function, 2 bijective, 2 composite, 2 extension of, 2 image of, 2 injective, 2 one-to-one, 2 onto, 2 rank of, 2 restriction of, 2 surjective, 2 generating system, 4 minimal, 4 graph, 24 complete, 25 complete bipartite, 25 outerplanar, 25, 163, 166

planar, 24 subdivision of, 25 underlying, 62 group, 5 alternating, 9, 43 cyclic, 7 factor group of, 7 irreducible, 75 noncommutative, 98 prime, 75 simple, 7, 73, 75, 81 trivial, 5 holonomy, 77 homomorphic image of semigroup, 4 homomorphic representation, 46, 55,63 completeness for with respect to a given product, 66 homomorphic simulation, 53, 55 completeness for with respect to a given product, 66 homomorphism of automata, 46 of monoids, 5 of semigroups, 4 idempotent, 5 identity element, 5 index to next available letter, 223 inverse element, 5 isomorphic representation, 46, 63 completeness for with respect to a given product, 66 isomorphic simulation, 53 completeness for with respect to a given product, 66 isomorphism of automata, 46 of semigroups, 4 Jordan-Holder factor, 20

Index

256

left identity element, 5 left zero, 5 lemma position-contents duality (Corollary 1.7), 13 length of a path, 24 local finiteness of digraph, 220 local time, 225, 227, 229

map induced configuration map, 26 minimal element of partially ordered set, 3 monoid, 5 characteristic monoid of an automaton, 50, 51, 53, 55 flip-flop, 5, 73, 75, 81 free, 3 trivial, 5 neighbor of a node in digraph, 219 neighborhood of a node in digraph, 219 network D-, 200 topology, 199 networks genetic regulatory, 23 neural, 23 of automata, 23 next available letter which may be read at a node in an asynchronous automata network, 223 nodes of a digraph, 23 normalize, 6 order of a digraph, 24 of a group element, 7 ordered cycle property and primitive products, 165, 166

for digraphs, 25 for graphs, 24 ordering cyclic, 41 partition, 2 path directed, 24 permutation, 2, 9 cyclic, 9 complete, 9 of a word, 4 even, 9 holonomic, 77 inversion in a, 9 on configurations of a digraph, 27 permutation group, 9, 76 full, 10 holonomy, 77 position-contents duality and time reversal, 13, 21 position-contents duality, 13 power cartesian, 3 of a word, 3 of semigroup element, 5 product D-, 63 -,62 -, 60, 62 -, 66 , 161 -V2-, 164 -, 60

q-,62

cartesian, 2 cascade, 60, 62, 66, 84 diagonal, 47 direct, 47 direct for semigroups, 7 feedback-free, 60 general, 58, 67, 161 generalized, 59 Gluskov, 58, 72, 73, 157, 160, 162, 182 loop-free, 62

Index

257

parallel, 62 primitive, 163-165 quasi-direct, 62 right, 2 single factor, 156 single-factor, 159 temporal, 184, 192 with feedback, 60 wreath, 14, 78 projection H-, 3 completeness under, for networks,

200

read functions of asynchronous automata network,

221

really independent, 3 relation, 2 antysimmetric, 2 congruence, 6 equivalence, 2 linear ordering, 2 partial ordering, 2 pre-order, 2 reflexive, 2 symmetric, 2 total ordering, 2 transitive, 2 right identity element, 5 right zero, 5 semigroup, 4 abelian, 4 aperiodic, 74 characteristic semigroup of an automaton, 50, 53, 55, 56, 58, 73 commutative, 4 finitely generated, 4 generated by a subset, 4 irreducible, 75, 81 of all subsets of semigroup, 4 quotient, 6

set

ordered, 3 partially ordered, 3

source of a mapping, 2 of an edge, 24 spatial-temporal covering, 229 spatial-temporal section, 231 natural, 231 subautomaton, 46 input, 46 state, 46 subgroup, 6 commutator, 8 derived, 8 generated by a subset, 6 generated by an element, 6 normal, 6 proper normal, 7 submonoid, 6 subnormal chain, 20 subsemigroup, 4, 6 of the flip-flop monoid, 81 subword, 3 symmetric semigroup, 8 synchronous automata network behavior of, 223 target of a mapping, 2 of an edge, 24 theorem Esik-Horvath characterization theorem (Theorem 5.27), 145, 162 asynchronous emulation of cellular automata (Theorem 7.30), 233 asynchronous emulation of synchronous automata networks (Theorem 7.22), 224 asynchronous emulation of synchronous generalized cellular automata (Theorem 7.29), 232 Chartrand-Harary outerplanarity (Theorem 2.2), 25 Denes-Hermann (Theorem 1.3), 8 GluSkov decomposition (Theorem 2.68), 23, 67

258

holonomy decomposition (Theorem 3.9), 74, 77, 78, 82 Jordan-Holder coordinate theorem for finite groups (Theorem 1.19), 21 Jordan-Holder theorem for finite groups (Theorem 1.18), 20 Krohn-Rhodes decomposition (Theorem 3.1), 73, 82 Krohn-Rhodes prime decomposition (Theorem 3.2), 74, 77, 82 Kuratowski planar graph (Theorem 2.1), 25 Lagrange coordinate decomposition (Theorem 1.17), 20, 21 Lagrange coordinates (Lemma 1.16), 19 Letichevsky decomposition (Theorem 2.69), 23, 67, 68, 162 tile, 77, 78 transformation allowed, 29 compatible (elementary), 26 transformation group, 9 transformation semigroup, 8 aperiodic, 74 flip-flop, 14, 76 full, 10 height of, 78 identity-reset, 76 of a digraph, 39 on configurations of a digraph, 27 permutation-reset, 76 prime divisors of, 74

Index

wreath product, 14 transformations interpretation 1 of, 10, 26 interpretation 2 of, 12 multiplication of, 8 on a set, 8 transposition, 9 Turing machine, 233 universal computation asynchronous, 233 update asynchronous local, 221 local +1-update, 226 real update at a vertex, 226 set of nodes, 221 update pattern, 221, 234 vertex free, 28 of a digraph, 23 walk closed, 24 word, 3 control, 152 empty, 3 length of, 3 mirror image of, 3 prefix of, 3 reverse of, 3 suffix of, 3 zero element, 5