PIECEWISE LINEAR TOPOLOGY
J. R p. HUDSON University of Durham
University of Chicago Lecture Notes prepared with the assistance of J. L. Shaneson and J. Lees
W . A . BENJAMIN, INC. New York
1969
Amsterdam
PIECEWISE LINEAR TOPOLOGY
Copyright © 1969 by W. A. Benjamin, Inc. All rights reserved Library of Congress Catalog Card Number 72-75219 Manufactured in the United States of America 12345 S 2109 The manuscript was put into production on December this volume was published on March 7, 7969
W. A. BENJAMIN, INC. New York, New York 10016
7, 1968;
PREFACE This book c o n s i s t s of n o t e s on l e c t u r e s g i v e n a t t h e U n i v e r s i t y of C h i c a g o in t h e a c a d e m i c y e a r 1 9 6 6 - 6 7 .
My aim in
t h e s e l e c t u r e s w a s t o d e v e l o p PL t h e o r y from b a s i c p r i n c i p l e s and c o v e r most of t h a t part of t h e t h e o r y w h i c h d o e s not r e q u i r e t h e u s e of b u n d l e s .
Thus t h e book i s c o m p l e t e in
i t s e l f , a p a r t from a very l i t t l e a l g e b r a i c t o p o l o g y .
It c o v e r s
subdivision, regular neighbourhoods, general position, engulfing, e m b e d d i n g s , i s o t o p i e s and h a n d l e - b o d y t h e o r y , i n c l u d i n g a c o m p l e t e proof of t h e s - c o b o r d i s m t h e o r e m . Fortunately there have been considerable simplifications in t h e b a s i c t h e o r y , in p a r t i c u l a r in t h e proof of N e w m a n ' s theorem t h a t t h e c l o s e d complement of a n n - b a l l in a n n - s p h e r e is a n n - b a l l .
The original proof required a c o n s i d e r a b l e s t u d y
of ' s t e l l a r t h e o r y ' . This w a s first rendered u n n e c e s s a r y by Z e e m a n ' s proof, u s i n g a large i n d u c t i o n i n c l u d i n g r e g u l a r neighbourhood t h e o r y . t h i n g s further.
M . C o h e n ' s short proof simplified
I heard of C o h e n ' s proof j u s t in time t o put a
v e r s i o n of it i n t o t h e l e c t u r e s . A c e r t a i n amount of new material is i n c l u d e d , n o t a b l y t h e proof t h a t c o n c o r d a n c e i m p l i e s i s o t o p y for e m b e d d i n g s in c o dimension
<3.
I h a v e drawn h e a v i l y on E. C . Z e e m a n ' s
s e m i n a r n o t e s on C o m b i n a t o r i a l Topology (IHES, P a r i s ,
1963),
for much of t h e b a s i c t h e o r y , though my t r e a t m e n t of g e n e r a l p o s i t i o n and engulfing is s o m e w h a t different.
vix
The s e c t i o n on
VLXL W h i t e h e a d t o r s i o n is lifted direct from J. M i l n o r ' s p a p e r in t h e Bulletin of t h e A. M . S . , 1966. I am very grateful to t h e M a t h e m a t i c s Department at t h e U n i v e r s i t y of C h i c a g o for inviting me t h e r e t o give t h e s e l e c tures .
I a l s o w i s h t o thank J. Lees and J . L. S h a n e s o n for t h e
c o n s i d e r a b l e amount of time and effort t h e y s p e n t h e l p i n g me with t h e p r e p a r a t i o n of t h e s e n o t e s . My t h a n k s a l s o t o R. Lashof and M . A. Armstrong for many d i s c u s s i o n s during t h e c o u r s e , and t o E. C , Zeeman for introducing me t o PL t o p o l o g y and for a l l h i s h e l p and e n couragement s i n c e .
November, 1968
JOHN F. P. HUDSON
CONTENTS Part 1 Chapter I
Page BASIC DEFINITIONS AND SUBDIVISION THEOREMS
II
1
REGULAR NEIGHBORHOOD THEORY
42
III
PL SPACES AND INFINITE COMPLEXES
76
VI
GENERAL POSITION
90
V
SUNNY COLLAPSING AND UNKNOTTING O F SPHERES AND BALLS
VI
109
ISOTOPY
128
ENGULFING
160
VIII
SOME EMBEDDING THEOREMS
174
IX
CONCORDANCE AND ISOTOPY
183
SOME UNKNOTTING THEOREMS
198
OBSTRUCTIONS TO EMBEDDING AND ISOTOPY
2 03
EMBEDDING UP TO HOMOTOPY TYPE
218
VII
X XI XII
Part 2 HANDLE-BODY THEORY AND THE S-COBORDISM THEOREM
223
BIBLIOGRAPHY
2 78
IX
A Note from the Publisher This volume was printed directly from a typescript prepared by the author, who takes full responsibility for its content and appearance. The Publisher has not performed his usual functions of reviewing, editing, typesetting, and proofreading the material prior to publication. The Publisher fully endorses this informal and quick method of publishing lecture notes at a moderate price, and he wishes to thank the author for preparing the material for publication.
-
T h i s c h a r a c t e r i z a t i o n of f a c e s follows f r o m t h e d e f i n i t i o n . a p p e a r in the a p p e n d e x at t h e end of t h i s c h a p t e r .
The details
Note that this c h a r a c t e r i B.
z a t i o n i m p l i e s t h a t t h e d i m e n s i o n of a p r o p e r face of a c e l l i s s t r i c t l y l o w e r t h a n t h e d i m e n s i o n of the c e l l itself. T h e p r o o f s of t h e following e l e m e n t a r y r e s u l t s a r e left to t h e r e a d e r : (1) A c e l l i s c o n v e x .
M o r e o v e r , it is t h e c o n v e x h u l l of i t s v e r t i c e s .
(2) T h e i n t e r s e c t i o n and p r o d u c t of c e l l s a r e c e l l s . E P x e ^ = EP"-^.)
f(A)
(3)
T h e c o n v e x h u l l of a finite s e t is a c e l l .
(4)
Let
A C eP
be a c e l l .
Let
f: E ^ —> E ^
(We identify
be (affine) l i n e a r .
Then
is a c e l l .
( N o t e t h a t b y (4), it suffices to p r o v e (3) for the s u b s e t {(1, 0, . . . , 0), . . . , (0, . . . , 0, 1)} of A E u c l i d e a n P o l y h e d r o n in E ^
•
...
•
e ' ^ , e a c h n, a t r i v i a l i t y . ) is a n y finite u n i o n of c e l l s .
We h a v e the
following e l e m e n t a r y p r o p e r t i e s : (1)
>
T h e i n t e r s e c t i o n , u n i o n , and p r o d u c t of E u c l i d e a n p o l y h e d r a a r e
• • m
Euclidean polyhedra. (2)
tw
T h e l i n e a r i m a g e of a p o l y h e d r o n is a p o l y h e d r o n .
If f: P —> Q i s a m a p ,
P and Q p o l y h e d r a , t h e n we s a y t h a t
p i e c e w i s e l i n e a r provided that (1) f i s c o n t i n u o u s ;
and
(2) r ^ = { ( x , f ( x ) ) | x e
P}
is a polyhedron.
f
is
(Note,
if
P
E^^ and
L e m m a 1, 1
a)
Q
E^
F^^
If P^ and P^
Q another polydron, then
E ^ X e'"'
e'^' ' ^ )
a r e p o l y h t n l r a , axxci Hi P ,
P.,
f i s p i e c e w i s e l i n e a r if and only if
^ O.,
f P^ and i P ^
are piecewise linear,
Pyoof.
b)
i: P — P
c)
T h e c o m p o s i t e of p. L m a p s is
a)
i » 1.2, are.
<m
Since
T^m
Pfjp
is p . l . {- p i e c e w i s c l i n e a r ) ,
^ U 1
P
any p o l y h e d r o n ^
p, 1* map^
P^ a n d P ^ a r e c l o s e d , f is conLinuous if r^ ^
fjP.,
. Z
-- { ( x , f ( x ) ) | x e P ^ } = r^^M (P^ X Q),
b) If A i s a c e l l t h e n
F
~ {(x.x)j x€
A] == {(x, y) « AX a } x = y) =
^A {z « A X A j for all Here
m
i, 1 .< i < m ,
g.(z) = O},
where
if
I s t h e d i m . of t h e E u c l i d e a n s p a c e c o n t a i n i n g
/. s (x, y), A
g^(z) =
and
"m^' c)
Let
P G E^, Q Q E^,
g : Q - ^ R be p . l . m a p s .
R C E^' be ^ j o l y h e d r a , a n d l e t
Let
f S P
P e {(x. f(x), gf(x))) x « P } C
Q
and Thra
r = { ( x , f ( x ) , z ) { X 6 P . 7, € R} r ' {(x, y, gy) 1 x € P , y € Q} « (P^X R) r. ( P X F ^ ) . Hence
F
is a polyhedron.
The map
on the first and t h i r d f a c t o r s ,
TT ; E^' X e'^ X E ^ —> E ^ X E ^ ,
is l i n e a r .
Hence
Tr(F) = F
^
projection
is a polyhedron.
We now m a k e a d e f i n i t i o n w h i c h w i l l not be u s e d for at l e a s t t h e r e s t of t h e c h a p t e r , but w i l l be r e f e r r e d to e v e n t u a U y , A c o - o r d i n a t e m a p of
X is a map
Let
f j P —> Xj,
X P a
be a t o p o l o g i c a l s p a r e . p o l y h e d r o n , w h i c h i s an
-4-
e m b e d d i n g [ i . e . , a h o m e o m o r p h i s m onto i t s i m a g e ] . to d e n o t e s u c h a m a p . c o m p a t i b l e if e i t h e r
Two c o - o r d i n a t e m a p s f(P) H g(Q) = 0 o r
We u s u a l l y w r i t e
(f, P)
(f, P ) and (g; Q) a r e s a i d to be
there exists a co-ordinate map
(h; R)
s u c h t h a t t h e following h o l d : (1) h(R) = f(P) n g(Q) (2) f ^h and
g ^h a r e p i e c e w i s e l i n e a r .
A P . L . s t r u c t u r e on X i s a f a m i l y
^
of c o - o r d i n a t e m a p s s a t i s f y i n g
the followingj (1) Any two e l e m e n t s of (2) If X e X, t h e r e e x i s t s of
in
X
(3) then
are compatible, (f, P ) e ^^
such that
f(P)
is a neighborhood
X. ^
i s m a x i m a l ; i. e. , if (f, P)
(f, P ) € 3 If
Examples;
i s c o m p a t i b l e w i t h e v e r y m a p in
3
.
.
s a t i s f i e s ( l ) a n d (2), it i s c a l l e d a b a s i s for a P . L . s t r u c t u r e on X.
1) If
P
i s a p o l y h e d r o n , X p ° P —> P
2) If
U C E^ ,
f o r m s a b a s i s for a P . L.
structure.
the inclusion map}
= {(i,P)| P
i s a b a s i s for a P . L .
a p o l y h e d r o n , P C U, i : P —» U
structure.
S
-
2,
C e l l C o m p l e x e s , S i m p l i c i a l C o m p l e x e s , and S u b d i v i s i o n A c o n v e x l i n e a r c e l l c o m p l e x in E ^
i s a finite s e t of c e l l s in E ^ , K
such that 1) If A € K, e v e r y face of A i s in
K.
2) If A and B e K, t h e n
or
A r\ B = ^
A n B = c o m m o n face of A a n d B .
An n - s i m p l e x in E ^ i s t h e c o n v e x h u l l of ( n + l ) l i n e a r l y i n d e p e n d e n t p o i n t s , called its v e r t i c e s .
E a c h face of ein n - s i m p l e x i s t h e c o n v e x s p a n of s o m e of t h e
v e r t i c e s a n d t h e r e f o r e i s a n im- simplex,, face of
m < n .
We w r i t e o- < T for " o" i s a
T".
A s i m p l i c i a l c o m p l e x ia a c e l l c o m p l e x w h o s e c e l l s a r e a l l s i m p l i c e s . If K i s a n y c o m p l e x , b y | K |K
we d e n o t e t h e u n i o n of a l l t h e c e l l s in K.
t h e u n d e r l y i n g p o l y h e d r o n of If
K and
We c a l l
K,
L are cell complexes,
K is c a l l e d a s u b d i v i s i o n of
L. if t h e
following h o l d . 1)
|Kl = j L l ,
2) E v e r y c e l l of L e m m a 1. 2 . u n i o n of c e l l s of Proof.
K i s a s u b s e t of s o m e c e l l of
If K i s a s u b d i v i s i o n of
such that
L, t h e n e v e r y c e l l of
L
is the
K.
Since
1 k | ts j L l , it suffices t o s h o w t h a t if A i s a c e l l of
X € A, then t h e r e is a cell K
L.
x € B'
B of K, x E B, w i t h
a n d t h e r e is a c e l l
A' of
B C A. L
L
T h e r e is a cell
such that
B' C A',
and B'
But
of
A n A' B ' n A^
i s a c o m m o n face i s a face, B
A subdivision
A^, s a y ,
s a y , of B ' ,
K of
B ' Q. A'
a r e convex linear cells,
so
and x e B C A .
L i s s a i d t o b e s i m p l i c i a l if it i s a s i m p l i c i a l complex,
One of t h e m o s t i m p o r t a n t t y p e s of s u b d i v i s i o n of a s i m p l i c i a l c o m p l e x i s stellar subdivision.
In o r d e r to define s t e l l a r s u b d i v i s i o n , w e m u s t firsjt i n t r o -
d u c e t h e n o t i o n s of j o i n s , s t a r s , and l i n k s |
h o w e v e r t h e s e notions (let the
r e a d e r be f o r e w a r n e d l l ) a l s o a r e i m p o r ' t a n t in t h e m s e l v e s . Let
A and B be two s i m p l i c e s in E ^ .
of A and of joinable.
B form a l i n e a r l y independent set, then we say that
A a n d B are
B y A. B w e d e n o t e t h e s i m p l e x w h o s e v e r t i c e s a r e t h o s e of
The simplex
a r e joinable
A and B.
A . B i s c a l l e d t h e j o i n of A and B .
If K a n d
L a r e two s i m p l i c i a l c o m p l e x e s i n e'^, we s a y t h a t
K and
L
if t h e following h o l d :
(1) If A 6 K and (2) If A ' € K and i s a face of
If t h e s e t c o n s i s t i n g of a l l t h e vertia
A.B
B e L,
A and B a r e j o i n a b l e .
B' c L, also, then either
and of
A.B n A'.B' = ^ or
A . B r\A\
A'.B'.
If K a n d L a r e j o i n a b l e s i m p l i c i a l c o m p l e x e s , w e define K. L = K o L vj { A B | A t K, B e L} , c a l l e d t h e j o i n of
K and L.
a simplicial complex.
*
B y c o n v e n t i o n , we a l l o w
A o r B = p and w r i t e
A . 0 = j0.A = A.
K J j i s clearly
-
.xample;
Let
A a n d B be j o i n a b l e s i m p l i c e s .
whose elements a r e
A and a l l i t s f a c e s .
Then
By A we d e n o t e the c o m p l e x A and B a r e j o i n a b l e c o m p l e x e s ,
and A . B = (A.B) . Now l e t
K be a s i m p l i c i a l c o m p l e x .
K A c K, t h e n we m a k e t h e following
definitions; s t a r ( A ; K ) = {B€' K | B > A}. s t a r (A; K) = { B € K | B
i s a face of a n e l e m e n t of s t a r ( A ; K ) } .
l i n k ( A ; K ) = {B € K] B and A a r e j o i n a b l e a n d A . B e K } . The r e a d e r can e a s i l y verify that that
A and l i n k ( A ; K )
s t a r (A; K) and l i n k ( A ; K )
are complexes,
a r e j o i n a b l e , and t h a t t h e following e q u a l i t y h o l d s : s t a r (A; K) = A . l i n k ( A ; K ) .
Remark. of
In g e n e r a l , if
L i s a c o n v e x l i n e a r c e l l c o m p l e x and
L , t h e n if K i s t h e s e t of a l l c e l l s of
of L j i . e . ,
K i s a s u b s e t of
K and t h e i r faces,
L which is a complex.
K is a subset
K is a subcomplex
C l e a r l y , this notation is
c o n s i s t e n t w i t h t h e d e f i n i t i o n s of s t a r and s t a r . o Notation.
If A i s a s i m p l e x ,
A = p o i n t s of A not c o n t a i n e d in a n y f a c e .
A = s u b c o m p l e x of A c o n s i s t i n g of t h e p r o p e r f a c e s .
Definition of StgHit^r Subdivision.. a implex.
Let
a € A .
Let
(K A = p o i n t , we put
K be a simplicial complex,
T h e n define:
L = {K - "itaTCA; K)} U (a. A . link(A; K)) = [K - A . l i n k ( A ; K ) ] U [ a . A . l i n k ( A ; K ) l .
A € K a
-
( T h e r e a d e r w i l l n o t e t h a t in g e n e r a l if
K, L,, and M a r e t h r e e c o m p l e x e s
e a c h j o i n a b l e to the j o i n of the o t h e r two, t h e n the following e q u a l i t y is both
••
rneaningful and t r u e :
I
(K. L), M = K. ( L . M)
L i s c a l l e d t h e c o m p l e x o b t a i n e d f r o m K by s t a r r i n g A at can easily verify that The complex
K=K
o
L m a y also be obtained from
1
The r e a d e r
L i s i n d e e d a c o m p l e x and t h a t it i s a s u b d i v i s i o n of K a s follows.
K = K U A. P , w i t h A / K . T h e n s e t L = K u a . A . P . o o o We s a y t h a t t h e c o m p l e x L i s a s t e l l a r s u b d i v i s i o n of series
a.
r
= L such that
K
r
K.
I
Write
K if t h e r e e x i s t s a
is obtained from
K
r-1
by s t a r r i n g
a s i m p l e x a t s o m e i n t e r i o r point. Picture:
•
I
E x a m p l e of a n o n - s t e l l a r s u b d i v i s i o n ;
The complex
K'
i s c a l l e d a f i r s t d e r i v e d of t h e s i m p l i c i a l c o m p l e x
K if it i® o b t a i n e d a s a s t e l l a r s u b d i v i s i o n f r o m A
simplex
A e K, c h o o s e
a t A and if
B e K,
O
A e A.
decrf-asing d i m e n s i o n .
K as follows; A
Star each simplex
A at
A in o r d e r of
T h i s c o n s t r u c t i o n m a k e s s e n s e b e c a u s e if we s t a r
and
d i m B < d i m A, t h e n
•
A
B w i l l be a s i m p l e x of t h e
resulting subdivision. Note t h a t if A ' d e n o t e s t h e f i r s t d e r i v e d s u b d i v i s i o n of u s i n g , for
F o r each
A o b t a i n e d by
__
A , t h e s a m e s t a r r i n g p o i n t s , and A '
obtained s i m i l a r l y ,
I
d e n o t e s t h e s u b d i v i s i o n of
A
then
A ' = A, A ' . F r o m t h i s f o r m u l a it follows by i n d u c t i o n on d i m e n s i o n t h a t t h e g e n e r a l A A A s i m p l e x of K ' i s of t h e f o r m A A . . „ A , w h e r e A < A < . . . < A are 1 ^ r 1T ^ I s i n i p l i c e s in
K,
A f t e r r e a d i n g t h e d e f i n i t i o n of s i m p l i c i a l m a p , t h e r e a d e r w i l l be a b l e to p r o v e e a s i l y t h a t a n y t w o f i r s t d e r i v e d s of the s a m e c o m p l e x a r e s i m p l i c i a l l y ^^Si^iiiil. ho m e o m o r p h i c . If A i s a s i m p l e x w i t h v e r t i c e s {a , . . . . a }, — ^ a + . . „ + —7-7 ^ is ^ o n nt-l o n+1 n c a l l e d t h e b a r y c e n t e r of all the s t a r r i n g points
^
A,
K' i s c a l l e d a b a r y c e n t r i c f i r s t d e r i v e d of
K if
are barycenters.
An r^^ d e r i v e d s u b d i v i s i o n K^^) of
K i s defined i n d u c t i v e l y to b e a f i r s t
d e r i v e d of a n ( r - l ) t h d e r i v e d ,
-
3,
B a s i c L e m m a s on S u b d i v i s i o n Lemma 1.3.
Then
1) If K'
Let
K
be a s u b c o m p l e x of t h e s i m p l i c i a l c o m p l e x K
o
is a s u b d i v i s i o n of K, it c o n t a i n s a s u b d i v i s i o n of
2) If K' i s a s u b d i v i s i o n of o containing
1) P u t
K' = { s i m p l i c e s of K' c o n t a i n e d in K } . If A e K' , >• tA i s c o n t a i n e d in a s i m p l e x of K . F o r A C B, s o m e B e K. H e n c e '
A C B n
K
these faces; I K' o
K , t h e r e e x i s t s a s u b d i v i s i o n of K o
K' .
Proof. then
K^; anc
^
|K
Q
, a u n i o n of f a c e s of B.
o
Since
Q
A i s a s i m p l e x , it l i e s in o n e of
in a s i m p l e x of I.
o
Q
K . So K' is a s u b c o m p l e x of K' and o o By P r o p o s i t i o n 1. 2, e v e r y s i m p l e x of K i s a u n i o n of simplice o
w h i c h a r e in K'
a n d so a l s o in K' ; t h e r e f o r e K S K' o o o 2) B y i n d u c t i o n o n t h e n u m b e r of s i m p l i c e s in K — K^.
n o t h i n g to p r o v e . Let
K^ = K
pose that B y 1),
So s u p p o s e
A^, . , . , A^ e K — K^, w i t h
U {-A^. . . . , A
, a subcomplex.
i s a s u b d i v i s i o n of
K' c o n t a i n s a s u b d i v i s i o n 1
K^
such that
(A )' n
of A
K^ n
.
If n o n e , t h e r e is
i < j =C> d i m i < dim j,
B y i n d u c t i o n , we m a y supi s a s u b c o m p l e x of
Let
o a e A
n
,
K^.
Define
K' = K^ U a . ( A ) ' .
Notation.
If w e w r i t e
a s u b c o m p l e x of
K'
K, b y
or
(r(K) to d e n o t e a s u b d i v i s i o n of
ar(L) o r
L'
it i s c a l l e d t h e i n d u c e d s u b d i v i s i o n of w h i c h i s a s u b c o m p l e x of
K'.
K and if
w e m e a n t h e s u b d i v i s i o n of
u a s in
L and is t h e u n i q u e s u b d i v i i
L
is 1);
r-f T,
-
•K,
F i g u r e for L e m m a 1 . 3 , P a r t Z.
Remark. ^
L e m m a 1. 3 h o l d s e q u a l l y w e l l for c e l l - c o m p l e x e s .
J' L e m m a 1. 4.
If
K is a cell complex, then
K has a simplicial sub-
Pd i v i s i o n w i t h no e x t r a v e r t i c e s . Proof.
O r d e r t h e v e r t i c e s of K.
v e r t e x of A,
K A e K, w r i t e
B = a l l f a c e s of A not c o n t a i n i n g
a.
A
laB],
a the first
Define s u b d i v i s i o n of c e l l s
in o r d e r of i n c r e a s i n g d i m e n s i o n by t h e r u l e : A' = a . B ' , where
B'
i s t h e s u b d i v i s i o n of
of c e l l s of l o w e r d i m e n s i o n , c o n s i s t e n t b e c a u s e if t e x of
C.
(if
B d e t e r m i n e d by the ( s i m p l i c i a l ) subdivision A = a,
set
A' = a ) .
C i s a face of A c o n t a i n i n g
The c o n s t r u c t i o n is self-
a, then
a
is t h e f i r s t v e r -
-
L e m m a 1.5.
Let
s i m p l i c l a l c o m p l e x in r^^ d e r i v e d
be c o n v e x l i n e a r c e l l s . E^
with
CjKj.
Let
Then
K be a K h a s an
K^^^ c o n t a i n i n g s u b d i v i s i o n s of
Proof .
Let
be
increasing dimension.
T h e n c^
and t h e i r faces,
in o r d e r of
i s a p o i n t , and t h e r e i s o b v i o u s l y a f i r s t
(l) derived
K
of K in w h i c h
c^
is a v e r t e x .
Suppose t h e r e e x i s t s an ( r - l ) - s t
(r-1) derived K of K c o n t a i n i n g s u b d i v i s i o n s of ^ . F o r e a c h s i m p l e x cr c K^^ l e t o" e a r» c ^ , p r o v i d e d t h a t t h i s interesectior. (r) i s n o n - e m p t y . O t h e r w i s e , c h o o s e a n y p o i n t fr € L e t K^"' b e t h e r^'^ d e r i v e d obtained from
K^^ ^^ by s t a r r i n g e a c h s i m p l e x of
K^^
cr,
at
a, in o r d e r
(r) of d e c r e a s i n g d i m e n s i o n . of
o-n c
for a l l
r
We a r e going t o s h o w t h a t
ere
such that
cr n c
r
/
K
(if.
c o n t a i n s a subdivision
T h i s c l e a r l y i m p l i e s that ,
(r) K
c o n t a i n s a s u b d i v i s i o n of c . r Consider
c ^ n cr / Jif.
We m a y a s s u m e t h a t
c^O
t h e r e i s n o t h i n g to p r o v e , by t h e i n d u c t i v e h y p o t h e s i s . lowest dimension containing c , w i t h r e s p e c t to w h i c h c ^ = p r o p e r f a c e s of
c^
c
s i n c e o t h e r w i s e the Let
H = h y p e r p l a n e of
c ^ ; i . e . , H i s t h e \uiique h y p e r p l a n e , has interior points.
Then
i s s u b d i v i d e d a s a s u b c o m p l e x of
containing
^ - H H o". F o r (r-1) K , and so i t s 0
intersection with cr c c , a n d so r
(T i s a u n i o n of f a c e s of
cr.
3o c ^
cr n c
r
^ Cf,
& o n l y if
c o o" = H n o". r
Now we p r o v e by i n d u c t i o n on t h e d i m e n s i o n of with
meets
K^^^
c o n t a i n s a s u b d i v i s i o n of
.. ( r - l ) cr t h a t i o r b.ny v e K
a n c^. t
I:
= (a , t-^rl
-13-
clear.
By induction,
C N or /
K^^^ c o n t a i n s a s u b d i v i s i o n
We m a y a s s u m e t h a t
a s u b c o m p l e x , so s u p p o s e t h a t crr)C^=a-nH=cr,
Hence
ote.
c ^ n cr /
^ n c^ / ^ .
aOH|=a'.
o". L , a s u b c o m p l e x of
K^
L of c
o",
if
If cr n c ^ c cr, it i s a l r e a d y H e n c e we h a v e ;
^ r\ c
A
= 0".
, is a s u b d i v i s i o n of
By 'a-. | L | , for e x a m p l e , we m e a n t h e j o i n of
c n c^ .
{o"} a n d
|L|.
Clearly,
•
i•
C o r o l l a r y 1.6. i x i s t s an Proof .
If
K
C |L|,
r^^ d e r i v e d s u b d i v i s i o n
K and L^^^ of
By L e m m a 1. 5, s u b d i v i d e
L
simplicial c o m p l e x e s , then t h e r e
L w h i c h c o n t a i n s a s u b d i v i s i o n of
L to get a n
antains a s u b d i v i s i o n of e a c h of t h e s i m p l i c e s of K.
r^^ d e r i v e d Let
K'
L^^^
which
be t h e u n i o n of
K.
-14-
these subcomplexes . of
Then
K'
i s a s u b c o m p l e x of
L^^^ a n d a s u b d i v i s i o n
K. Corollary 1.7.
E v e r y E u c l i d e a n P o l y h e d r o n i s t h e u n d e r l y i n g s e t of a
simplicial complex, N Proof.
Let
A
be an N - s i m p l e x c o n t a i n i n g t h e c o m p a c t s u b s e t
P
of
N ii
, where
P = A ^ U . . . U A^, e a c h
A^ a c o n v e x l i n e a r c e l l . A p p l y N L e m m a 1. 5 t o find a s u b d i v i s i o n of A w h i c h c o n t a i n s a s u b d i v i s i o n of
mm e a c h A^, a n d t a k e t h e \mion of t h e s e s u b c o m p l e x e s t o get a c o m p l e x w h o s e undej WMm lying set is
P .
Definition . plex with
If P
| k | = P,
Unsolved P r o b l e m ; K both
=
L . K and
is a Euclidean Polyhedron and K i s c a l l e d a t r i a n g u l a t i o n of
Suppose
K and
Then is t h e r e a complex L?
K is a s i m p l i c i a l c o m -
P.
L are simplicial complexes,
and
M w h i c h i s a s t e l l a r s u b d i v i s i o n of
-15-
4.
P i e c e w i s e L i n e a r M a p s , S i m p l i c i a l M a p s , and S u b d i v i s i o n s . In t h i s s e c t i o n w e s t u d y t h e r e l a t i o n b e t w e e n p i e c e w i s e l i n e a r m a p s and
HI
simplicial maps. £. K—5> L
If
K and
L
are simplicial complexes, a simplicial map
is a continuous map
f:
[ K | —> [L]
w h i c h m a p s v e r t i c e s of K to -
v e r t i c e s of
L and s i m p l i c i e s of K l i n e a r l y into (and h e n c e onto) s i m p l i c e s of L .
Remarks ;
1) A l t h o u g h we w r i t e
the s e t
K to t h e s e t
L;
f ; K —> L ,
f i s n o t r e a l l y a function f r o m
but it m a y b e t h o u g h of a s a c o l l e c t i o n of l i n e a r m a p s
of s i m p l i c e s of K o n t o s i m p l i c e s of
L.
2) Any s i m p l i c i a l m a p i s p i e c e w i s e l i n e a r . 3) A s i m p l i c i a l m a p
f i s d e t e r m i n e d b y i t s v a l u e s on v e r t i c e s .
C o n v e r s e l y , g i v e n a function of
K'
map
g w h i c h a s s i g n s to e a c h v e r t e x of
in s u c h a w a y t h a t if v ^ , . . . , v ^
g(v^), . . . , g(v^)
a r e in a s i m p l e x of
f: K — > L w h i c h e x t e n d s
g.
n i =l
a r e in a s i m p l e x of
X.>0 '
Lemma 1.8.
Let
all
i,
set
K'
n
f( ^ \.v ) = i=l ' '
of
K,
N a m e l y , if
f: K — > L be s i m p l i c i a l .
of L , t h e r e e x i s t s a s u b d i v i s i o n
K a vertex
L, t h e r e e x i s t s a u n i q u e s i m p l i c i a l
n '
(Use L e m m a 1 . 1 . )
i=l
X g(v ) ' '
Given any subdivision
K such that
£; K' —> L '
L'
is
simplicial. Proof.
If A is a s i m p l e x of K,
f(A)
£(A) for t h e s u b c o m p l e x c o n s i s t i n g of f(A) induced
subdivision.
i s a s i m p l e x of and i t s f a c e s ,
L.
and
We a l s o w r i t e f(A)'
for t h e
- 16.
Let
K^ = { A n f '
(o-)! A € K and (re L ' } .
cell c o m p l e x ( t o g e t h e r with the empty set). cell
(or empty).
Then
For
A t y p i c a l face i s of t h e f o r m
K^ i s a c o n v e x l i n e a r
A r\ £"^(0-) i s a c o n v e x linear
B r> f
( T ), w h e r e
a r e (not n e c e s s a r i l y p r o p e r ) f a c e s of A a n d cr , r e s p e c t i v e l y .
B and T
(The r e a d e r
m a y v e r i f y t h e l a s t s t a t e m e n t by c o n s i d e r a t i o n of t h e a p p r o p r i a t e l i n e a r inequalities. )
H e n c e f a c e s of c e l l s of
( A n f~^cr))n ( C n f " ^
K^ and in K^.
Ti)) = ( A n c ) n (f-^(o-) n -1
w h i c h i s a c o m m o n face if Obviously, v e r t i c e s of
Anf
I ^^ | = | k | .
Moreover, ^ ) = ( A o c ) n (f"^((r n ti)),
-1 (cr) and
Cnf
( "H ).
A l s o , f i s l i n e a r on e a c h c e l l of
K^ to v e r t i c e s of
L'.
Let
K^ a n d m a p s
K ' = a s i m p l i c i a l s u b d i v i s i o n of
K^
w i t h no e x t r a v e r t i c e s , b y L e m m a 1 . 4 . N Lemma 1.9. Let
f:
Let
j K j —^ | l |
K and L
b e a m a p w h o s e r e s t r i c t i o n to e a c h c e l l of
Then t h e r e exists subdivisions ft K' —> L '
be s i m p l i c i a l c o m p l e x e s , w i t h
is s i m p l i c i a l .
K' and L ' of
K and
L
L C E
.
K is l i n e a r .
r e s p e c t i v e l y , s u c h that
M o r e o v e r , we m a y i n s i s t t h a t
L'
be s t e l l a r . fVi
Proof. derived
If A € K,
L^^^ of
L
f(A)
i s a c o n v e x l i n e a r c e l l ; h e n c e t h e r e e x i s t s an r
in w h i c h a l l t h e c e l l s
f(A), A e K , a r e s u b d i v i d e d a s s u b -
c o m p l e x e s . C o n s i d e r K^ = {A n f"^(B) | A £ K, B e L^^^}. T h e n a s i n L e m m a 1. 8, K, i s a c e l l u l a r s u b d i v i s i o n of K, f i s l i n e a r , on c e l l s of 1 m a p s v e r t i c e s onto v e r t i c e s . Subdivide K^ w i t h no e x t r a v e r t i c e s .
A, and
-17-
e m m a 1. 10.
Let
icial complexes. Dectively, so t h a t
Proof . iron.
Let
Say
f:
K | —5> | L |
Then t h e r e exist subdivisions fi K' —> L '
|K| Q E ^ ,
is s i m p l i c i a l .
|l) CE^.
3t s u b d i v i s i o n s
K and L L'
be
t h e g r a p h of f, i s a p o l y F^, by C o r o l l a r y 1 . 7 .
If
i s p r o j e c t i o n on t h e f i r s t f a c t o r , t h e n b y L e m m a 1. 9 t h e r e M^ and K^ of M and K r e s p e c t i v e l y ,
|M : M^ —> K^ i s s i m p l i c i a l . M o r e o v e r , if ir
£ = "TT o ( i r . I Im ) Z 1
K' and L ' of
We m a y i n s i s t that
F^ C
M be a s i m p l i c i a l s u b d i v i s i o n of
J F ^ X E ^ —> E ^
morphism.
be a p i e c e w i s e l i n e a r m a p of
: K
L e m m a 1. 9 t o t h e m a p
1
—> L .
tt^
such that
i s a b i j e c t i o n ; h e n c e it i s a h o m e o -
is p r o j e c t i o n on the second factor, But
x
i s a l i n e a r m a p , a n d so w e m a y a p p l y
^
f = tt^ « (ir^ M)
: K^ —> L .
Now c o n s i d e r t h e following d i a g r a m : ••1
K
L
M
In g e n e r a l we c a n n o t find s u b d i v i s i o n s of
K, L , and M w i t h r e s p e c t to w h i c h
f and g a r e s i m u l t a n e o u s l y s i m p l i c i a l , a s t h e following e x a m p l e s h o w s .
-
1/
-
-4>
f'f
L
J s
M
Here g
1
f and g m a p v e r t i c e s 1, 2, and 3 a s s h o w n and a r e l i n e a r .
To mak
s i m p l i c i a l (3 in M i s n o t a g i v e n v e r t e x ) , w e m u s t i n t r o d u c e v e r t e c 4 in K.
T h e n k e e p i n g f s i m p l i c i a l r e q u i r e s t h e i n t r o d u c t i o n of v e r t i c e s 4 and 5 i n L an K respectively-o
Then keeping
g simplicial requires
t h e n w e m u s t a d d 6 in L and 7 in K.
5 in
M a n d 6 in K; ar
C o n t i n u i n g in t h i s w a y we find it n e c e s s a :
to add i n f i n i t e l y m a n y v e r t i c e s b e t w e e n
1 and 2 in K, for e x a m p l e .
T h i s cai
n o t be d o n e b y s u b d i v i s i o n . H o w e v e r , t h e r e a r e s o m e t y p e s of d i a g r a m s in w h i c h it i s a l w a y s p o s s i b L to s u b d i v i d e a l l t h e c o m p l e x e s so t h a t a l l t h e m a p s a r e s i m u l t a n e o u s l y s i m p l i c Definition .
A finite d i a g r a m of c e l l c o m p l e x e s and p i e c e w i s e l i n e a r m a p
i s c a l l e d a o n e - w a y t r e e if 1) T h e c o r r e s p o n d i n g c o m p l e x i s o n e - c o n n e c t e d ; i . e . , t h e d i a g r a h a s no l o o p s ; and
-
2) E a c h c o m p l e x i s t h e d o m a i n of at m o s t one m a p . A s u b d i v i s i o n of a d i a g r a m plex a p p e a r i n g in
T.
T is a d i a g r a m obtained by subdividing each c o m -
A s i m p l i c i a l s u b d i v i s i o n of
T i s o n e in w h i c h a l l t h e
m a p s a r e s i m p l i c i a l w i t h r e s p e c t to t h e s u b d i v i d e d c o m p l e x e s . Theorem 1.11. Proof .
If
T i s a o n e - w a y t r e e , it h a s a s i m p l i c i a l s u b d i v i s i o n .
After a s u b d i v i s i o n , we m a y a s s u m e t h a t a l l t h e c o m p l e x e s of
are simplicial.
If
T
T h a s o n l y two c o m p l e x e s , t h i s t h e o r e m i s t h e n j u s t
Lemma 1.10. Suppose T
T has at least t h r e e complexes.
such that
T h e r e is a m a p
K i s n o t t h e r a n g e of a n y m a p in
T.
Let
K'
f« K and
L
L'
b e sub-
*
i i v i s i o n s of
K and
|e obtained from
L
such that
T by deleting
induction t h e r e i s a s u b d i v i s i o n
f; K' —> L ' f: K — > L slols >!<
T
of
T
is simplicial. and replacing
Let
T
L by L ' .
w h i c h is s i m p l i c i a l .
Let
be t h e By
L"
ncl c o r r e s p o n d i n g s u b d i v i s i o n of /•ision of K ' , s u c h t h a t
L'.
Apply L e m m a 1 . 8 to find
f: K " —> L "
is simplicial.
K", a sub-
be
• 20-
5.
P i e c e w i s e L i n e a r Manifolds Definition .
A piecewise l i n e a r m - b a l l is a polyhedron which is p i e c e -
w i s e h o m e o m o r p h i c to a n m - s i m p l e x .
A piecewise linear m - s p h e r e is a
p o l y h e d r o n w h i c h i s p. 1„ h o m e o m o r p h i c to t h e b o u n d a r y o n a n ( m + l ) - s i m p l e x . A p . l . m a n i f o l d of d i m e n s i o n
m,
m"^, i s a E u c l i d e a n p o l y h e d r o n in w h i c h
e v e r y p o i n t h a s a ( c l o s e d ) n e i g h b o r h o o d w h i c h i s a p . 1. m - b a l l ,
I Remark. m
One c a n s h o w by t o p o l o g i c a l a r g u m e n t s t h a t g i v e n a n m - m a n i f o l d
is uniquely d e t e r m i n e d by
M.
M,
H o w e v e r , t h i s r e s u l t w i l l a l s o follow f r o m
t h e r e s u l t s of t h i s s e c t i o n . B Lemma 1.12. p.l.
If A i s a c o n v e x l i n e a r c e l l of d i m e n s i o n
m, then
A is a .
m-ball. Proof.
containing
to w h i c h
Let
A be an m - s i m p l e x c o n t a i n i n g
A j i . e . , let
A be a simplex
A and c o n t a i n e d i n t h e u n i q u e h y p e r p l a n e c o n t a i n i n g 0 V A h a s an i n t e r i o r .
radial projection from Unfortunately,
a.
Choose
a e A c A,
It i s e a s y to v e r i f y t h a t
Then let
A with respeaj ' '
pt A —> A
be
p is a h o m e o m o r p h i s m .
p i s not p i e c e w i s e l i n e a r . »
We a r e going to a l t e r T h e n a i s j o i n a b l e to (r. • Let
A'
p t o get a p . l . m a p . C o n s i d e r cr € A , A n a.cr i s a u n i o n of c e l l s , and p ( A n a . o - ) =
b e a s u b d i v i s i o n of A w h i c h c o n t a i n s s u b d i v i s i o n s of t h e p o l y h e d r a
-1
p
(cr) = A rv a.cr , Let
of A.
cr < A.
T be a s i m p l e x of A ' .
Define
Then
p ' : A ' — > A, by l e t t i n g
p( T ) i s a s i m p l e x c o n t a i n e d in a face p'(
= p(^) if
^ i s a v e r t e x of A ' , anl
-
extending linearly.
Then p'
is a well-defined p . l . m a p , and p ' r = p r . •
So p '
is p . l . h o m e o m o r p h i s m
•
A—> A.
F i n a l l y , to define a p . l . h o m e o m o r p h i s m on A , f(a) = a , a n d t h e n e x t e n d m o r p h i s m ; i n fact
f: A — > A, w e j u s t s e t
f l i n e a r l y to A .
—> | aA
Then
f is a p . l .
f = p' homeo-
fs
a.A'
m a p s s i m p l i c e s l i n e a r l y onto s i m p l i c e s .
p'
c o n s t r u c t e d in t h e p r o o f of L e m m a 1. 12 i s c a l l e d a
PictureI
Remark.
The m a p
pseudo-radial projection.
It i s o b t a i n e d f r o m a n o r d i n a r y r a d i a l p r o j e c t i o n
by an a d j u s t m e n t which i n s u r e s p i e c e w i s e l i n e a r i t y .
In t h e s e q u e l , we s h a l l
c o n s t r u c t p s e u d o - r a d i a l p r o j e c t i o n s w i t h i m p u n i t y and w i t h o u t t h e d e t a i l e d d i s c u s s i o n of t h e l a s t proof.
-
L e m m a 1.13.
l)
Let
b " ^ and
B ^ be j o i n a b l e s i m p l i c i a l c o m p l e x e s
w h o s e u n d e r l y i n g p o l y h e d r a a r e a n m - b a l l and a q - b a l l , r e s p e c t i v e l y . b " ^ . B^l
is an m+q+1 ball. 2) L e t
and
b"^
m-ball,
s"^
m - s p h e r e and Proof.
and S^ be j o i n a b l e s i m p l i c i a l c o m p l e x e s , w i t h
[s'^l
3) L e t
a q-sphere.
a q-sphere.
1) L e t
h: B " '
Then
[B^.s'^I i s a n m + q + l b a l l .
and S*^ be j o i n a b l e s i m p l i c i a l c o m p l e x e s , Then
A
Let
h and k a r e simplicial.
b
1
B ^ , B^^, A^"^, a n d A ^
which
be s u b d i v i s i o n s s u c h that
T h e r e a d e r m a y v e r i f y t h a t if two c o m p l e x e s a r e join-
a r e j u s t t h e v e r t i c e s of "
qq
a q-simplex
and l e t k ; b'^ —> A^ b e a
a b l e , so a r e a n y s u b d i v i s i o n s of t h e s e two c o m p l e x e s . of
an
s i m p l e x (of s u i t a b l y h i g h d i m e n s i o n ) .
b e a p. 1, h o m e o m o r p h i s m ,
p.l,. h o m e o m o r p h i s m .
|S^
is an m+q+l sphere.
a " ^ and A^ be an m - s i m p l e x and
a r e n o n - i n t e r s e c t i n g f a c e s of a n o t h e r Let
Then
m B^^andB^^. qq 11
M o r e o v e r , the vertices!
Hence
h and k
determine
b y t h e i r v a l u e s on v e r t i c e s , a u n i q u e s i m p l i c i a l i s o m o r p h i s m h.k: 1
1
->A™.A;1. 1 1
But
|Af.A;i 1 1
a " ^ . A^ , an m + q + l s i m p l e x .
2) A s in 1), it suffices to show t h a t if a " ^ a n d A*^^^ a r e j o i n a b l e , i s an m + q + l b a l l . consider the map
A^^.A*^"'"^
t h e b a r y c e n t e r of A of a " ^
.
check that
Extend
q+1
.
Let
Let
a"^ =
a " ^ ^.A*^^^
^,
v
a v e r t e x of
defined a s f o l l o w s .
f(x) = x if x i s a v e r t e x of
f l i n e a r l y o v e r s i m p l i c e s of
f defines a p . I . h o m e o m o r p h i s m .
A
a"^. A^^^.
Now a p p l y 1).
q+1
a"^. Let
then Then f(v)
be
or a vertex
It i s not h a r d to
-
3) In 2), r e p l a c e m b y m + 1 . T h e n fs ^wiiiii;' 'm+l -q+l , •m+q+2 , Moreover, f( A . A^ )= A ^ where So a ' ^ ^ ^ . A ^ ^ ^
i s an m + q + 1
Lemma 1.14. linkiajK) Note ;
—» a " ^ . A^"*"^.
^m+q+2 A =
. m ^q+1 A .A
A s in l ) , t h i s suffices to p r o v e 3).
i s a s u b d i v i s i o n of
K,
K a n d K'
simplicial,
then
^link(a;K').
= m e a n s p . 1. h o m e o m o r p h i c .
Proof. that
If K'
sphere.
.
If
B' e link(a|K'), then
a B e K, a n d
aB'crl a B , s i n c e
aB' c K'.
Hence t h e r e exists B e K
a i s a l s o a v e r t e x of K.
define a r a d i a l p r o j e c t i o n
p; l i n k ( a ; K ' )
logical h o m e o m o r p h i s m .
In a d d i t i o n ,
5> l i n k ( a ; K).
B'.
The m a p
p is a topoand
H e n c e , u s i n g t h e t e c h n i q u e of
L e m m a 1. 12, w e m a y find a p s e u d o - r a d i a l p r o j e c t i o n [Notej
H e n c e we may-
p(B) i s a s i m p l e x w h i c h l i e s in B
i s s p a n n e d b y t h e i m a g e s of t h e v e r t i c e s of
such
In t h i s c a s e it i s u n n e c e s s a r y to s u b d i v i d e
p'; link] a; K
link(a;K')
=link(ajK').
i n o r d e r to define
the p s e u d o - r a d i a l p r o j e c t i o n . ] Corollary 1.15.
If h ;
simplicial complexes, then Proof.
Let
K'
Then h: l i n k ( a ; K')
and
L'
K | —> | L |
i s a p. 1. h o m e o m o r p h i s m ,
l i n k ( a ; K) ^ l i n k ( h a ; L), p r o v i d e d b e s u b d i v i s i o n s so t h a t
> link(ha| L')
ha
h: K' —> L '
i s a p . L homeomorphism.
K and L
i s a v e r t e x of L . is simplicial. Apply L e m m a 1.14.
-
P i c t u r e for 1 . 1 4 :
C o r o l l a r y 1. 16. t h e n if
A e K,
Proof.
K'
1.15, (n-l)
But
A = a is a vertex.
A w h i c h i s p . l . h o m e o m o r p h i c to
Let
h: I
K a s i m p l i c i a l complex,
sphere or ball, where
F i r s t consider the case
By 1 . 1 4 , it suffices, or ball.
i s a p. 1. n - m a n i £ o l d ,
is
b e a s u b d i v i s i o n of
subcomplex.
K'I .
|K|
link(A,K)
n e i g h b o r h o o d of let
If
r = dimension A
Let
B ^
|k|
A^, a n n= s i m p l e x .
K w h i c h c o n t a i n s a t r i a n g u l a t i o n of
B,
be a Then
K^, a s
| —> A^ b e a p. 1. h o m e o m o r p h i s m . in t h i s c a s e , to s h o w t h a t
l i n k ( a ; K') = link(a5 K^), s i n c e
I
|
link(a5K')
i s an ( n - l ) sphe
i s a n e i g h b o r h o o d of
L e t A' = s t e l l a r s u b d i v i s i o n of A^ o b t a i n e d by s t a r r i n g at h a . l i n k ( a ; K ^ ) S l i n k ( h a ; A').
So it suffices to p r o v e t h a t
link(ha;A')
a in T h e n b' i s an
sphere or ball. ^
C a s e 1;
h a = b e A.
C a s e Z:
O b € A,
«
Then
A' = h a . A.
A a p r o p e r face of
A,
So l i n k ( h a ; A ' ) = A, an ( n - l ) s p h e r e , g Say A = A ;
e« ,
. A i s an s-simpi'
-
Then
A^ = A ^ . B ^ ®
where
tar a t b to get A ' = b A B ;
B i s t h e c o n v e x h u l l of t h e v e r t i c e s n o t in A,
hence
link(bf A ' ) = A. B , an ( s - l ) + ( n - s - l ) + 1 =
(n-l)-ball. Now we c o n s i d e r t h e g e n e r a l s i m p l e x
A e K and p r o c e e d b y i n d u c t i o n on
d i m e n s i o n of A; i . e . , we a s s u m e t h a t if
B has lower dimension,
(B; K) i s a b a l l o r s p h e r e of d i m e n s i o n n - d i m B - 1. Write
A =
where
a i s a v e r t e x of
= Link(A^;K), an n - r s p h e r e o r ball, ikice
aA^ € K.
Moreover,
B € link(A,- K).
A a n d A^
r = d i m A.
B e l i n k ( a j L)
a face.
Then a
Let
i s a v e r t e x of
a , B . A^ e K
L,
B . ( a . A^) e K
That is, l i i i k ( a ; L) = l i n k ( A ; K ) .
is to c o m p l e t e t h e p r o o f , (n-r) manifold. !r+l
.
it suffices to s h o w o n l y t h a t
T h i s w i l l be t h e c a s e if, for a n y
,
riT
is a l s o an r-manifold,
A
r ,
A
L = link(A^}K)
is an
i s a n r - m a n i f o l d and
, . rr + *t"1J. and A b e i n g r - and ( r + l ) - s i m p l i c e s .
respectively.
•
It i s c l e a r t h a t a f^iven p o i n t .
• "
tex not in
cr.
A''
i s an r - m a n i f o l d .
L e t cr b e an r - s i m p l e x of Now,
A
cr) =
r+1 ^ e A'^ ' * be
^ ^ cr.
x be t h e v e r -
Let
i s a n e i g h b o r h o o d of
^
in
But
cr—> cr b y t h e i d e n t i t y , l e t
0"
cl(A
- cr) =
X . 0"
.
This is an r - b a l l .
x be m a p p e d to a p o i n t in
e x t e n d l i n e a r l y to get a p . l , h o m e o m o r p h i s m
•
r+1 A'^ ' L e t
< Ar+1
T "
(cl = t o p o l o g i c a l c l o s u r e . ).
with T
T
Namely, map
Consider
x . cr—> cr.
and
-
Definition .
The c o m p l e x
for a l l A £ K, (Note:
link(A;K)
i s a s p h e r e o r b a l l of d i m e n s i o n n - d i m A - 1.
We h a v e b e e n w r i t i n g
Remark.
K is c a l l e d a c o m b i n a t o r i a l n - m a n i f o l d if
link(A; K) = | l i n k ( A ; K) | . )
C o r o l l a r y 1.16 a s s e r t s t h a t if
is a combinatorial n-manifold. n-manifold, starring
let x e
A at x.
X in i t s i n t e r i o r K
|k|.
A e K.
star (a;K')|
(w. r . t .
|k|).
is a p.l,
C o n v e r s e l y , if
Say x e A,
Then
|K|
Hence
=
n-manifold, then
K
K is a c o m b i n a t o r i a l Let
K'
be obtained from
K t
| a . A . l i n k ( A ; K ) | , an n - b a l l contai
K a c o m b i n a t o r i a l n-manifold implie;
is a p . l . n-manifold. o Definition .
Let
P
a n y t r i a n g u l a t i o n of P say x e P
(or
xe
be an n - m a n i f o l d .
having x as a v e r t e x ,
9P)
if for
|K| = P
l i n k ( x j K) i s a b a l l .
P
b o u n d a r y of
P = J!^ , we s a y t h a t
Remarks;
P. 1)
If
Let
K,
P
To d e t e r m i n e w h e t h e r o r not
then t h e r e is a p . l . h o m e o m o r p h i s m
if give
l i n k ( x ; K) i s a s p h e r e . P , with
i s c a l l e d t h e i n t e r i o r of P , a n d P =
9P
W
x a verte is called t
is a manifold without boundary. x e P P
i s a p . l . h o m e o m o r p h i s m and so if K and K^
In p a r t i c u l a r ,
We s a y x e P
a t r i a n g u l a t i o n of
it suffices to c o n s i d e r o n l y one t r i a n g u l a t i o n of i p
x e P,
link(x; K) ^
i s in t h e b o u n d a r y o r inte having x as a v e r t e x .
Fc
a r e two s u c h t r i a n g u l a t i o n s k ( x 5 K ' ) , b y C o r o l l a r y 1.15.
P = P U P.
2) P n 9P =
s i n c e a b a l l i s n o t h o m e o m o r p h i c to a s p h e r e .
for p u r e l y t o p o l o g i c a l r e a s o n s .
This is t r
H o w e v e r , t h e n o n - e x i s t e n c e of a p . l .
homeo-
m o r p h i s m of a b a l l w i t h a s p h e r e a l s o follows f r o m t h e f a c t s t h a t a s i m p l e x
t
a p. 1. m a n i f o l d w i t h b o u n d a r y
|A , a p . L h o m e o m o r p h i s m p r e s e r v e s
b o u n d a r y , a n d t h e following l e m m a : L e m m a 1. 17. Proof .
Let
An n - s p h e r e i s an n - m a n i f o l d w i t h o u t b o u n d a r y . A b e an ( n + l ) s i m p l e x .
Assume
o a e A,
A a p r o p e r face.
. Star A at by im
a to get
A ' = a , A . B, w h e r e
A = A. B,
A=A. BuA.B,
so
A' = a . A . B u A. B . H e n c e l i n k ( a ; A ' ) = A. B, a n ( n - l ) s p h e r e . T h e n e x t l e m m a t e l l s u s how to find t h e b o u n d a r y of a m - m a n i f o l d
M
using
only o n e t r i a n g u l a t i o n . L e m m a 1.18.
If
| k | = M i s a t r i a n g u l a t i o n of t h e m - m a n i f o l d
K = {A € K I link(A;K) K
=
, and
Proof.
K|
Let
is a b a l l } .
Suppose j^or
K,
is an (m-1) manifold without boundary. A e K.
L e t B be a face of A of one l e s s d i m e n s i o n .
A = X. B, X t h e r e m a i n i n g v e r t e x . Lt-mma 1.17,
T h e n K i s a s u b c o m p l e x of
M, define
Then
l i n k ( A ; K) = l i n k ( x ; liiik(B; K)), so b y
l i n k ( B ; K) m u s t be a b a l l . a € |K|.
Let
a e A,
Then
Hence
K is a subcomplex.
A € K, and s t a r
A at
a to o b t a i n
K'.
Then link ( a ; K ' ) = A . l i n k ( A | K ) ,
5.
Therefore,
A e K implies •
To s h o w t h a t
K
a e M ; A / K
l i n k ( A , K) i s a s p h e r e = > a / e
is an (m-1) manifold without b o u n d a r y , let
M.
A e K.
tru; Thtin B € l i n k ( A ; K ) <=^> A. B e K <=> AB e K a n d l i n k ( A . B j K ) i s a b a l l . l i n k ( A B ; K ) = l i n k ( B ; l i n k ( A ; K)), so l i n k ( A B ; K ) b o u n d a r y of
|link(A;K)|.
®t w e a l r e a d y p r o v e d ,
[k|
i s a b a l l <5=i> B i s c o n t a i n e d i n
So link(A,K) = t h e b o u n d a r y of | l i n k ( A j K ) | ,
|.n (n - d i m A - 2 ) - s p h e r e ; t h u s
But
which
K is a c o m b i n a t o r i a l ( n - l ) manifold and by
h a s no b o u n d a r y .
Note; K=
In v i e w of 1, 18,
{ a e K| l i n k ( A ; K )
if K i s a c o m b i n a t o r i a l m a n i f o l d , we r e f e r to is. a b a l l } a s t h e b o u n d a r y of
K.
Dual C e l l s T h e m a i n a i m of t h e n e x t t h r e e s e c t i o n s i s to p r o v e t h a t if S i s a p . 1. sphere and
B C S i s a p . L b a l l of t h e s a m e d i m e n s i o n , t h e n
p. 1. b a l l of t h e s a m e d i m e n s i o n .
S - B
is a
In t h i s s e c t i o n we define a n d s t u d y d u a l c e l l s ,
in the n e x t w e p r o v e s o m e l e m m a s , and in S e c t i o n 8 w e p r o v e t h i s a s s e r t i o n and d e r i v e s o m e c o r o l l a r i e s . Let
K be a s i m p l i c i a l c o m p l e x and
If A € K, w e define
A
K'
its b a r y c e n t r i c first derived.
A , t h e d u a l c e l l of A, to b e the following
=
subcomplex:
s t a r (vj K'). v a v e r t e x of A
Picture:
A*
The r e a d e r w i l l o b s e r v e t h a t in g e n e r a l the u n d e r l y i n g p o l y h e d r o n of A a convex linear cell.
i s not
-
Suppose
0-€ K ' .
Then
say, where 1
a- € A
v of A.
But
if and o n l y if A A" =
Definition .
Now
cr e A
c € s t a r ( v ; K')
A^ .
{A^ . . . A I s
if and o n l y if
ere
star(v;K')
if and o n l y if v ^ A ,
IA
^ A 1
p . l . b a l l of d i m e n s i o n ( n - l ) l y i n g in
< A^ < . . . < A } . 2 s d i m n, a c o m b i n a t o r i a l fac e of
r e f e r r e d to s i m p l y a s a fac e of
Then
A
B w i l l be
B.
K be a c o m b i n a t o r i a l m-manifold.
Let
*
dim A = r.
B is a
B.
W h e n t h e r e i s no d a n g e r of c o n f u s i o n , a c o m b i n a t o r i a l face of
Let
So
So
If B i s a p, 1. b a l l of
L e m m a 1.19.
€ K, s
'I'
i s t h e b a r y c e n t e r of A . .
for e a c h v e r t e x
< . . . < A 1
A
a n d A.
A
s
A e K, °
is an ( m - r ) b a l l .
i s t h e d u a l c e l l of A in K t h e n
A
Furthermore,
if
a n d cl { | 3 ( A " ) | -
#
A e K and if |}
A'
a r e f a c e s of M
-
Proof .
To p r o v e t h e f i r s t a s s e r t i o n , l e t
,• ^A A A = {A....A 1 s
^ A
with
A < A . , w r i t e A. = A B . . T h e n J J J E v e r y cr e A ' i s of t h i s f o r m , w h e r e B. € l i n k ( A ; K ) , 3 Let
i ^ j
link(A;K)'
A A Ifcr=A,...A e A , I s
t h e n for e a c h
or 2 s B. < . . . < B , i = 1 o r 2, and 1 s
b e t h e f i r s t b a r y c e n t r i c s u b d i v i s i o n of
A
K'.
Define
j .
I
s
link(A;K),
which:
h: a ' ——?> A.link(A; K)'' by map
^
p i n g A to
A and
simplices.
Then by the last p a r a g r a p h ,
A.link(A;K)'
Then
s,
also the induced subdivision from A
A € K.
AB to
B,
B e link(A,-K), a n d e x t e n d i n g l i n e a r l y o v e r
is an ( n - r ) ball, since
h is a s i m p l i c i a l i s o m o r p h i s m .
link(A;K)
i s an ( n - r - l ) s p h e r e o r ba
Put
-
# Suppose morphism
A e K.
of
A
T h e n t h e r e s t r i c t i o n of h to
onto
A, link(A; K ) ' .
But
A
|k(A;K)
is a s i m p l i c i a l i s o a p . 1. b a l l w i t h
is
0
boundary
link(A; K).
A*, A^ , a n d
( T h i s w a s shown i n t h e p r o o f of L e m m a 1. 1 8 . )
9A''' - A^
a r e p . l . h o m e o m o r p h i c to
A. A,
^ . A and
So A,
respectively, where
A i s a s i m p l e x , (via t h e s a m e h o m e o m o r p h i s m ) .
A'' and
a r e f a c e s of
AA* - A ^
L e m m a 1. ZO.
Let
1)
A"\
K be a c o m b i n a t o r i a l m a n i f o l d .
be t h e d u a l c e l l s in K and K .
So
Let
i " 1, . . . , r )
T h e n t h e following h o l d :
= OB.
|K|
i=l 2) B. n B. = 0 , if ^ J 3) B. Note:
In 2),
B.
denotes the set
1) L e t
B
B..
9B.
K' = b a r y c e n t r i c f i r s t d e r i v e d of
K.
If x e | K | ,
x e cr,
A A o-=A^...A , A < , . . < A . T h e n cr e A . . 1 s 1 s 1 E v e r y point of K'( i s c o n t a i n e d in the i n t e r i o r of a (unique) s i m p l e x
0" 6 K ' .
2) ^f
j,
i s a u n i o n of d u a l c e l l s of l o w e r d i m e n s i o n t h a n t h e d i m e n s i o n of
Proof. some
i/
K'.
Let
H e n c e it suffices to s h o w t h a t
o one B
if
c € K', then
o" i s c o n t a i n e d in a t m o s t
. 1
_
A
So l e t
h: A
\
0- = A^, . . . , A , 1 s
Then
A
A^ < . . . < A , be in K ' . 1 s
If A^A^,
then
cr C j dA
Then
*
o" £ A^ . 1
Suppose
F o r let
A
—> A i l i n k ( A ; K )
b e t h e p . l . h o m e o m o r p h i s m defined in t h e p r o o f of
L e m m a 1 . 1 9 . T h e n h(cr) C | l i n k ( A | K ) [ . •> A < A^ ; a n d if A Athen 0- c A^
S i m i l a r l y , if cr C 9A
o" € K , t h e n
-
H e n c e we h a v e o n l y t h e p o s s i b i l i t i e s 0" C (A^ that
In c a s e
a n d , if A. e K , 1 < i < s,
cr / (K)', w e t h u s h a v e n o t h i n g m o r e t o p r o v e .
0- 6 ( K ) ' ; i . e . ,
A
€ K.
Then
cr C | A
S
0" C
^ c
9(A^) , a n d t h u s
| , a face of A X
A^
*
So
J.
is t h e u n i q u e d u a l c e l l w h i c h c o n t a i n s *
3) C o n s i d e r a g a i n t h e m a p
So a s s u m e
cr.
A
> A | k ( A ; K ) , defined a s in L e m m a 1 A ^ U s i n g t h i s h o m e o m o r p h i s m , it i s e a s y to s e e t h a t if (r = A . . . A ,
(proof).
h: A
X
*
A^ < . . . < A ^ , t h e n
cr e 9(A'") if and o n l y if
•
A < A^
implies
a face of sion.
|A
A^ C A
S
#
A ^ A^
or
cr e A .
Since
*
#
and h a s l o w e r d i m e n s i o n b y 1. 19, a n d s i n c e
, this shows that
9A '
A
i s t h e u n i o n of d u a l c e l l s of l o w e r dirr
-
M»
More Lemmas m If B^"" a n d
L e m m a 1. 21. h; B^—>
ap.l,
m B^^^ a r e p . 1. b a l l s ,
embedding
(or h o m e o m o r p h i s m ) , then there exists a
p.l. embedding (homeomorphism)
h': B
—> B X
A"^ X, A ,
Am
Proof.
and a ' ^ , r e s p e c t i v e l y . and j o i n u p l i n e a r l y . by s u b d i v i d i n g
n > m , a n d if
y. A! n ,
A^ A =
We m a y v i e w
h
extending
h„
^
• t ,h e i. n t e r i•o r of^ A A"^ X a n dJ y m
as a map
:m h: a " ^ — > a'^.
Set
h'(x) = y
T h i s i s a p . 1. m a p , b e c a u s e it i s s i m p l y t h e m a p o b t a i n e d
A ^ and
A^ to m a k e
h
extending l i n e a r l y o v e r s i m p l i c e s to get
s i m p l i c i a l , defining
h ' ( x ) = y, a n d
h ' s x . ( a " ^ ) ' —> y. ( A ^ ) ' .
It i s c l e a r l y
an e m b e d d i n g . L e m m a 1. 22. is joinable to
then
cl. (
V.
K. K
Let Let
-
K be a s i m p l i c i a l c o m p l e x and let V be a point which L
b e a s u b d i v i s i o n of
Then
p
Let
K .
t r i a n g u l a t i o n of F o r each
A e K', let
B < A.
p
-1
(A)
Moreover,
O I s t a r ( v 5 L) | ^ J^, 1= [0,1].
be radia l projection.
H o w e v e r , p c a r r i e s s i m p l i c e s of
A = cl.(|v. A
A of
K'
of
=
. A| O
K = { "a* a n d i t s f a c e s | A e K ' } . I ' ^ L = C1.(|V.K( - | 7 t i 7 ( v ; L )
A and its faces,
A
b'
Then ).
R onto s i m p l i c e s
K which contains a
K', | v . R ( ) = c l . ( | v . A) -
(in fact, a " t r u n c a t e d s i m p l e x " ) .
and its faces, A
KXl,
p : R — > K = link(v5 r K )
for e a c h s i m p l e x
A is a convex linear cell the s i m p l e x
Let
H e n c e w e m a y find a s u b d i v i s i o n
p(A)
|K
K.)
R = link(v} L ) .
i s n o t a p . 1. m a p .
c o n t a i n e d in
T h e n if
s t a r ( v ; L) ) i s p . l . h o m e o m o r p h i c to
(K' = i n d u c e d s u b d i v i s i o n of Proof .
v . K,
T h e f a c e s of
and the c e l l s
a c o m m o n f a c e of
A and
is a cell c o m p l e x and
B, 'b'.
|v.p"^(A)|) A
are
where Let
-
Let
K
be a s i m p l i c i a l s u b d i v i s i o n of
e a c h v e r t e x of
K
i s e i t h e r a v e r t e x of K'
-1 under
p
* .
Define
h(x) = (x, O), a v e r t e x
h: K
K w i t h no e x t r a v e r t i c e s . o r t h e i m a g e of a v e r t e x of
K'
r —> K X I b y s e n d i n g a v e r t e x
y in
Then
|R|
x in K'
to h(y) = (py, l ) , a n d e x t e n d i n g l i n e a r l y .
definition m a k e s s e n s e b e c a u s e
R
O
K
=
and b e c a u s e
i n t o t h e s a m e c o n v e x s u b s e t of r~>
that
in fact,
h
maps
A
Thi
h m a p s all the
v e r t i c e s of a n y s i m p l e x in K
h is a homeomorphismj
to
K X I.
It i s cle
h o m e o m o r p h i c a l l y onto
A X I, Lemma 1.22. cl. ( P - F )
If P and Q a r e
and c l . ( Q - F )
a r e f a c e s of
n-balls, P O Q = F
i s a c o m m o n f a c e , at
P and Q respectively, then
P u Q
i s ai
n-ball. Proof. h <1
T r i a n g u l a t e and l e t
s p h e r e if and o n l y if l i n k ( A ; F )
A e cl.(P-F). is non-empty.
Link(A; P - F )
f a i l s to be a
Similarly, link(A;F)
fails to
II i : ; Ij'i : 111
b e a s p h e r e if and o n l8F y if = link(A; F n P P- F- F =) / 8 ( P - if F ) .A e F . Similarly, to p . l .
DF = 9( Q ^ ) .
Now t h e i d e n t i t y
F —> F
So e x t e n d s (by L e m m a 1. 21)
homeomorphisms: h • P-F
^
a, F
1
h :
F
5>b.F
Cl
h^t Q - F (Here
a, b, c , and F
-> C o F . a r e a s s u m e d j o i n a b l e in s o m e E u c l i d e a n s p a c e . ) •
we m a y e x t e n d
to get h ^ : P — > a b F
Agaia •
and
—> b c F , givisj
-
). 1. h o m e o m o r p h i s m •
»
P U Q ^ abF U bcF ^ L e m m a 1. 23.
Let
acF
= a p . l . ball.
K be a c o m b i n a t o r i a l n - m a n i f o l d .
Let
+ = (K X 0) U (K X I).
Then
K
^ K via a p . l . h o m e o m o r p h i s m sending
, 1 ) to X if X € K. Proof. L e t { A . | i = 1 , . . . , N } be t h e s i m p l i c e s of K in o r d e r of d e c r e a s i n g I* I #I p n s i o n . L e t B. = A. , F . = | A . the p . l . b a l l s a r e o r d e r e d in o r d e r icreasing dimension. L e t D. = (B. X 0) U ( F . X I). L e t N| 1 1 1 I = cl. ( K - 0 B.). L e t U = V X 0. L e t U. = U U I J D. . L e t I i=l ' ° ° ^ ° Vl J .i = V U B. . We define i n d u c t i v e l y a s e q u e n c e of p . l . h o m e o m o r p h i s m s o U.
> V.
1
such that
1
h.(D.)=B..
j^i
2)
h. I U
3)
h . ( x , 1) = X for a l l x e K
Then t h e
i s g i v e n by h . ( x , 0 ) =
map
Z) d e f i n e s
h . o
x.
h^^ p r o v e s t h e l e m m a . Assume
h. , 1 - 1
defined,
Now, D. = (B. X 0) U (F^ X I). (B. X 0) o ( F . X I), a face of By 1 . 1 9 , ^ I. Ax 0
cl, ( B . - F . ) 1 1 F o r let A.
B. X 0 by 1. 19 and c l e a r l y a face of F . X I.
i s a face of
B. . 1
Also
( F . X 1) U ( F . X I) i s a face of 1 1
A be a s i m p l e x and l i n e a r l y e m b e d
A X I in vA
with
P s e u d o - r a d i a l p r o j e c t i o n f r o m a point in ^ X 0 g i v e s a p, 1. h o m e o -
•
morphism Now,
cl.(D. - F . X l ) 1 *1
m o r p h i c a l l y to with h. ^
«
(A X l ) u ( A X I)
> vA .
C U. , . 1-1
c l . (B- - F^ ).
Define
Hence h. , m a p s 1-1
D^
> B. .
cl.(D.-F.Xl) 1 1
h^ F^ x) by
d e f i n e s a p. 1. h o m e o m o r p h i s m
to a p . 1. h o m e o m o r p h i s m
D^ is a b a l l .
D^
1) = x.
homeoT h i s togethe
> B^ , w h i c h m a y be extends
C o m b i n e t h i s l a s t m a p w i t h h^ ^ to
get h^ . C o r o l l a r y 1. 24. • h o m e o m o r p h i c to with
T h e r e e x i s t s a n e i g h b o r h o o d of
K X I.
In fact,
K in K
t h e r e exists an imbedding
c(x, 0) = X, w h o s e i m a g e i s a n e i g h b o r h o o d of
K.
w h i c h i s p. 1. •
c: K X I
(The m a p
> K,.
c i s calle|
a boundary collar. )
L e m m a 1. 25.
If S i s a s p h e r e and x a n d y a r e p o i n t s of
exists a p . l . homeomorphism Proof .
Exercise.
(Hint:
S
> S sending
x to
S, t h e n ther
y.
Use p s e u d o - r a d i a l projection. )
f 4
8,
Removing Balls from Spheres. T h e o r e m 1. 26,
cl. (S-B)
By induction.
t h e o r e m for
plexes
B i s an m - b a l l c o n t a i n e d in t h e m - s p h e r e
S,
then
i s an m - b a l l .
Proof.
l)
If
S-B K
For
m = 0, t h i s t h e o r e m is t r i v i a l .
A s s u m e the
(m-l). i s a m a n i f o l d w i t h b o u n d a r y B. C K with
(Recall:
| K | = S, |K
~ s i m p l i c e s of
We s h o w t h a t
K-K
I = B.
K-K^
F o r there exist simplicial c o m Now
| K-K | = c l . { | K | - |K |}
and t h e i r faces. )
is a combinatorial manifold.
If A e K - K , t h e n o AB € K. S i n c e A ^ K ,
o ).
link(A;K)=link(A;K-K
.
F o r if B € l i n k ( A ; K ) , t h e n o H e n c e B € l i n k ( A ; K - K ). H e n c e l i n k ( A ; K - K ) i s a n ( n - r - l ) s p h e r e , o o
AB / K . o r = dim A.
Say A e ( K - K Claim;
) n
K . o
Let
r = dim A,
l i n k ( A ; kTiT ) = ^link(A; K) - link(A; K )\ .
For C e K-K
o
AB e K - K
BeJink(A;K-K^)
o
« = > AB < C , s o m e
AB < A C , , s o m e A C , e K - K 1 1 o
o
<5=
B < C ,, some 1
C,
1
in
l i n k ( A ; K ) - l i n k ( A ; K ). Now, link(A5K) or ball.
Since
i s a n ( m - r - l ) s p h e r e , and l i n k ( A ; K ^ )
link(A;K^) ^
is an ( m - r - l ) sphere
l i n k ( A ; K ) , it c a n n o t be a s p h e r e .
H e n c e by
induction. link(A;K-K^)
= cl( link(A,-K)
- | link(A; K^) | )
= I { l i n k ( A ; K ) - l i n k ( A ; K )} -o Is an m - r - l b a l l . 0 K
Hence
(= 9K ).
K-K^
is a c o m b i n a t o r i a l n-manifold with boundary
-
2) L e t K-K
L = K-K^ U V. K^ ,
v a joinable point.
e x t e n d s to a p . l . h o m e o m o r p h i s m
a s p h e r e , so t h e i d e n t i t y m a p on v.K
|K
K^ I , by L e m m a 1. 21.
l e t k:
m+1
L
v e r t e x of
A
|L
T h e i d e n t i t y m a p on >
K .
For
K
IS
e x t e n d s to a p. 1. h o m e o m o r p h i s m So | L |
is an m - s p h e r e .
By L e m m a 1. 25
be a p. 1. h o m e o m o r p h i s m s u c h t h a t v ' = k^v)
is a
m+1
Now taJice f i r s t d e r i v e d s u b d i v i s i o n s a n d follow by f u r t h e r s u b d i v i s i o n to get cir(L) and
p(A)
so t h a t k : a ( L )
5> p(A) i s s i m p l i c i a l .
"starCv; a(L)) = s t a r ( v ; a(v. K )) d o e s not m e e t o n o t m e e t P(A^), w h e r e A = V ' A ^ . By L e m m a 1. 22, cl. { V'.A^ K-K^
^
-
cl( VK
a(K ) a n d s t a r ( v ' ; (3(A)) o
s t a r ( v ; AF(L)) ) ^ K
star(v';P(v'.A^))| } ^
[( K - K ^ ) X {0} ] U
A^ X L
X l|.
Then
X I,
does
and
By L e m m a 1. 23,
T h i s l a s t p o l y h e d r o n i s p. 1. h o m e o -
m o r p h i c to i r r i T ^ I VJ c l . { | v . K ^ | - I ^ t i r C v j o - C L ) ! } = cl. { | a ( L ) | - I ^ ^ ^ ( v ; a(L))| } T h i s l a s t i s o m o r p h i s m b e i n g t h e r e s t r i c t i o n of k . s t a r ( v ' ; pA ) = s t a r ( v ' ; p ( v ' . A^))
and
A^
h o m e o m o r p h i s m b e i n g given by L e m m a 1. 23. i s an m - b a l l .
c l . { | (3A| -
(J So
|star(v';(:
Now,
p(A) = p(A^) u p(v. A^).
p o l y h e d r o n a b o v e i s p . 1. h o m e o m o r p h i c to
c l . (S-B)
^
Hence the l a s t
A^ X I
,
this last
K-K
a n d so
-
C o r o l l a r y 1. 27. homeomorphism A
'A -
=
Proof.
A is an n - b a l l a n d F .
h: F
.n-1
i s a face of
A, t h e n a n y p. 1.
e x t e n d s to a p . 1. h o m e o m o r p h i s m
A
V.
F
p f of 1 . 2 6 .
If
i s t h e b o u n d a r y of t h e b a l l So h | F
c l . ( A - F ) ; t h i s w a s s h o w n in 2) of t h e
e x t e n d s t o a p . 1. h o m e o m o r p h i s m
• cl.(A-F)
NOW h^U h : A
> A^ = v . a " ' ^ U A^"^
j m e o m o r p h i s m , and so w e m a y e x t e n d to a p. 1. h o m e o m o r p h i s m C o r o l l a r y 1. 28.
If A and
isap.l.
h'^ A —5> A ^ .
B a r e n - b a l l s and A n B i s a c o m m o n f a c e ,
t h e n A U B i s an n - b a l l . Proof.
I m m e d i a t e f r o m 1. 26 and 1, 22.
C o r o l l a r y 1. 29. a face of
M is an n-manifold,
B which l i e s in
Proof.
Let
A i s an n - b a l l . and of
If
B.
Hence
9M, t h e n
c: M X I
B an n - b a l l , and
B n M = F
is
M u B ^ M.
M be a b o u n d a r y c o l l a r .
Let
A = c ( F X I).
A r\ B = {c(x, 0)( x e F } = c ( F X 0) = F , a c o m m o n face of
A
A U B is an n - b a l l .
I Let
F ^ = c ( F X I u F X 1), a face of A.
homeomorphism.
By C o r o l l a r y 1. 27, l e t h ^ : A
p . 1. h o m e o m o r p h i s m . Let h • A U B rnorphism
Let
> vA
F^ extend
h: F^
> a""^
> vA, extending
i s a l s o a face of A ^ B , s i n c e h.
-1 Then h " h : A u B 1 z
w h i c h i s t h e i d e n t i t y on c ( ( F X I) u ( F X 1)),
be a p. L h, be a
F ^ = c l . (A - F ) .
?> A i s a p . l . Define
homeo-
k : M U B —> M
b y l e t t i n g it be a n e x t e n s i o n of h^ i s n o t a l r e a d y defined.
Then k
-1
h^
which is the identity whei
i s a p . 1. h o m e o m o r p h i s m .
-
APPENDIX TO CHAPTER I .
We w a n t to s h o w t h a t if A i s a c o n v e x l i n e a r c e l l , t h e n a c e l l
B is a
face of A if a n d o n l y if 1) If P
is the hyperplane spanned by
B,
P O A = B ;
and 2) No p o i n t of
P
l i e s b e t w e e n a n y two p o i n t s of
A - B.
C l e a r l y a n y face s a t i s f i e s t h e s e c o n d i t i o n s . be a s y s t e m of e q u a t i o n s for > 0, . . . , g^ given
A.
Suppose
0 } i s t h e s m a l l e s t face
j > s, t h e r e e x i s t s
x. € B with J
X . + X
. . .
+
C o n v e r s e l y , l e t {f. = 0, g. > o} 3 {f. = 0, g = . . . = g = 0 , 1 1 s of A c o n t a i n i n g B . T h e n
g.(x.) > 0. J J
Put
X.
L
=
t-s Then
g.(x) > 0 for a l l j ^ s + 1 . t!)
If y € B
X to y, t h e n f r o m l ) t h e r e m u s t e x i s t By 2), 3 = ^5:
y and/or
z
i s in
B.
a n d ji i s t h e l i n e s e g m e n t f r o m
z e £ O
w i t h x b e t w e e n y and z.
So by 1), y a n d z a r e in B .
So x e B.
Thus
-
C h a p t e r II - R e g u l a r N e i g h b o r h o o d T h e o r y
1.
Collapsing Definition .
Suppose
P^ C p
a r e E u c l i d e a n p o l y h e d r a , and s u p p o s e
B = c l „ ( P - P ) i s a p. 1. b a l l w h i c h h a s ir O that
r ?
P
c o l l a p s e s to
We s a y t h a t
P
P^
If P
suppose
P
r e t r a c t of setting
a s a face.
Then we say
P^
and write
P ^
P^^P^
t h e n if
P^
i s a s t r o n g d e f o r m a t i o n r e t r a c t of
B = cl(P - P^),
B, b e i n g a face of
BHP^
P.
p
if t h e r e
For
is a strong deformation
If (p^ i s t h e d e f o r m a t i o n r e t r a c t i o n ,
ep = 1 (J
P^ .
\e ,e .e P = P^ \ P^ 1 \ °' ' \ ^o '
then P^j
o
b y a n e l e m e n t a r y c o l l a p s e , a n d we w r i t e
c o l l a p s e s to t h e s u b p o l y h e d r o n
e x i s t s a finite s e q u e n c e
Remark.
B A P
t
to
then P
. o
o Definition .
P
i s s a i d to be c o l l a p s i b l e if
If t h i s i s t h e c a s e , we w r i t e
P
c o l l a p s e s to a s i n g u l a r point,
P^O.
By the p r e c e d i n g r e m a r k , e v e r y c o l l a p s i b l e polyhedron is c o n t r a c t i b l e . T h e c o n v e r s e i s f a l s e , h o w e v e r , a s t h e following e x a m p l e s h o w s . Consider a two-simplex:
Let
s p a c e obtained by m a k i n g the identifications shown.
D be the quotient
T h e s e c o n d d e r i v e d of t h i s
t w o - s i m p l e x is a t r i a n g u l a t i o n c o n s i s t e n t w i t h t h e i d e n t i f i c a t i o n s , consider
D to be a s i m p l i c i a l c o m p l e x .
a n d so w e m a i
M o r e o v e r , b y a t h e o r e m of W h i t e h e a d
-
D is contractible;
for
H^(D) = 0 , i > 0, a n d so
'Tr^(D) = 0, t h e o b v i o u s c e l l - d e c o m p o s i t i o n s h o w s ^^(D) = 0, a l l i.
Now D is not c o l l a p s i b l e . X 6 BB - B n D . o
Then
a r e not in K pose that K = K
o
Let
It t u r n s o u t t h a t
D X 1^0,
K, w h e r e
K = K ^ u {A} v j { a A } .
c o l l a p s e to
a
es
I = [O, l ] .
K .
We s a y t h a t
K = K^ \
2
.
l)
K , and s u p o
K collapses \
K^ ^
\
. . \
simplicially
K , and if \
o
o B e K i s c a l l e d a p r i n c i p a l s i m p l e x if
B i s not a p r o p e r face of a n y s i m p l e x of K.
Remarks;
aA
.
K is a complex,
face of no o t h e r s i m p l e x of
Suppose A and
i s a v e r t e x of
\
to K^ if t h e r e i s a finite s e q u e n c e xS this is the c a s e , we w r i t e K \ K
If
B u t no p o i n t of D
K c o l l a p s e s by an e l e m e n t a r y s i m p l i c i a l
K ^
\
Let
(We a l s o w r i t e t h i s c o n d i t i o n in t h e f o r m
T h e n we s a y t h a t
K , and we w r i t e
Definition .
D - D^ = B .
K C K be s i m p l i c i a l c o m p l e x e s . o
but a r e s i m p l i c e s of ^
+ A + aA.)
D^D^,
l i n k ( x ; D ) = l i n k ( x , B) = a p . l . b a l l .
has a p . l . ball as a link. Definition.
F o r suppose
K, t h e n
If t h e face
A of
A i s c a l l e d a f r e e fac e of
B is the p r o p e r B in
K.
An e l e m e n t a r y s i m p l i c i a l c o l l a p s e i s an e l e m e n t a r y c o l l a p s e .
\es
If K \
K a n d K = K + A + a A , t h e n aA i s a p r i n c i p a l s i m p l e x of K \ o o with f r e e face A . On t h e o t h e r h a n d , if B i s a p r i n c i p a l s i m p l e x of K w i t h free face
A, t h e n
B = aA; a n d if
K
= K - ({A} O {B}), o
\es
and K ^
K
is a subcomplex o
K^ .
, 3) It is f a l s e t h a t
|k|
L a s u b c o m p l e x of
K, i m p l i e s t h a t
K
L.
L e m m a 2. 1. if
a) A c o n e c o l l a p s e s s i m p l i c i a l l y to a s u b c o n e .
5 K a r e s i m p l i c i a l c o m p l e x e s , then v. K ^ v . K ^ , b) Say K ^ . K ^
K n K^ C K . 1 2 3 Proof. dimension. out
A^
Then
a r e s u b c o m p l e x e s of
K,
K^
a joinable pointj K^ ,
and
K U K^ \ K u 1 2 \ 3
L e t A ^ , . . . , A^ b e t h e s i m p l i c e s of K - K^ Then
v
Precisek
A^
in o r d e r of d e c r e a a
i s a f r e e face of the p r i n c i p a l s i m p l e x v . A ^ .
and v. A^.
Then
A^
i s a f r e e face of t h e p r i n c i p a l s i m p l e x
Collapst v . A^,
what r e m a i n s , etc. . . . b) It suffices to c o n s i d e r K^ = K^ + aA + A. Hence
Then
aA
K
\
K , with K A K C K . Suppose X ^ J ± ^ D a n d A a r e not in K^, s i n c e K^*^ K^ ^ K ^ .
K^ U K^ = K^ U K^ + aA + A defines a n e l e m e n t a r y s i m p l i c i a l collapse
K ^ U K^ ^ ^
K ^ U K^.
L e m m a 2. 2.
K K c o l l a p s e s to
s t e l l a r s u b d i v i s i o n of Unsolved P r o b l e m ;
K, t h e n
(r(K) i s a
""(K^)" It i s t r u e for
< 3.
In t h i s p r o o f w e do not d i s t i n g u i s h i n t h e n o t a t i o n b e t w e e n a s i m p l
and its a s s o c i a t e d s i m p l i c i a l c o m p l e x . complex
s i m p l i c i a l l y , a n d if
I s t h i s t r u e for n o n - s t e l l a r s u b d i v i s i o n ?
c o m p l e x e s of d i m e n s i o n Proof .
o-(K) \
K
If A i s a s i m p l e x , we w r i t e
A for th
A.
It suffices to c o n s i d e r e l e m e n t a r y s i m p l i c i a l c o l l a p s e s .
It a l s o suffices to
c o n s i d e r o n l y s u b d i v i s i o n s o b t a i n e d b y s t a r r i n g at o n e s i m p l e x . K = K^ + aA + A,
aA
a p r i n c i p a l s i m p l e x with f r e e face
So s u p p o s e
A, a n d s u p p o s e t h a t
o-(K) = K - B . l i n k ( B j k ) + b B l i n k ( B ; K ) , C a s e 1;
B n o t a face of
aA;
then
b e B,
B e K.
cr(aA) = a A , a n d
(r{K) = cr(K^) + aA + A . C a s e 2;
—
—
B
Let
[ P i c t u r e for C a s e 2]
A = BA^
1
(with A^ = ^ a p o s s i b i l i t y ) .
A.
Then
(r(aA) = b . B, a. A ^ . We h a v e : • xS . . . a.A^.biB a. A^. B + a A ^ . b . B , • • • since
A,.B+A..b. B 1 1
is a s u b c o m p l e x
of A ^ . b, B , and b y L e m m a 2. 1. •
But
•
.
aA = a . B A , + a B A ^ , 1 1
so
o-(aA) = a . B . A^ + a . b . B A^ . So,
o-(aA) ' ^ a ( a A ) .
K^n
= cr(aA) C K^, K u K
That i s , C a s e 3; that is,
Let
o-(K) B ^ aA
K^ ='(r(aA), K^ = crfaA),
Then
so
= (r(aA) ucr(K )
K_U K
= cr(K ) U(r( aA) = a-(K ).
cr(K^), b y L e m m a 2 . 1 . but
B C aA.
B^A
Put
(
= "not a face of");
B = aB^, A = A.B 1
aA = a A ^ B ^ = A ^ B .
So
1
Then
1
cr(aA) = A ^ . b . B = A ^ b ( a B ^ + B^) = a b A . B , + b. A f 1 1
l>y L e m m a 2. 1.
o-{K^).
^
\
a . b . A^B^ + bA 1 1
Now, abA^B +bA = abA^B + b(A.B^ + A ^ B ) 1 1 1 1 1 1 1 1 = a b A , B , + b A , B , X a ( b A , B^ + A , B^ ) + b A , B^ , 1 1 1 1 \ 1 1 1 1 1 1 b y L e m m a 2. 1 (both p a r t s ) . (r(aA) \
H e n c e we h a v e
a ( b A ^ B ^ + A^B^ ) + b A ^ B ^ .
Now, o-(aA) = (r(aA_,B, + a A ^ B , ) = (r(A,B + a A , B , ) 1 1 1 1 1 1 1 = a A ^ B , + b ( a B , + B j A , = a ( b A , B ^ + A^ B J 1 1 1 1 1 1 1 1 1 That is,
(r[aA) ^
(r(aA).
Case 4:
B = aA.
Then
b(aA + A) \
baA
and
+ bA.B, 1 1
.
Now c o n t i n u e a s i n C a s e 2). cr(B) = o-(aA) = b . B = b(aA + A).
abA \ aA = o-(aA).
Thus
(r(aA) \
But (r(aA).
Now proce<
a s i n C a s e 2). \e L e m m a 2. 3. plex
Let
K
\
L ,
L
a s u b c o m p l e x of t h e s i m p l i c i a l c o m -
K.
T h e n t h e r e e x i s t s a s u b d i v i s i o n K' of vS s u b d i v i s i o n of L , K ' \ L ' , a n d L ' i s s t e l l a r . Proof.
B.
Let
B = cl( K | -
L ) =
K-L
,
K
s u c h t h a t if
B H
A^ i s a f r e e face of the s i m p l e x
Write
B for t h e t r i a n g u l a l i o n K - L
of B and A r e s p e c t i v e l y , stellar;
such that
a p p l y L e m m a 1 . 1 0 to h
.
i s t h e indv
L ) = F , a f a c e of t h e ba
By C o r o l l a r y 1. 27, t h e r e i s a p. 1. h o m e o m o r p h i s m
where
L'
h : ( B , F ) —>
A (i. e . , d i m A^ = d i m A - 1 ) . of
B,
Let
B'
and
A'
be s u b d i v i s i
hr B ' — > A' i s s i m p l i c i a l a n d Note that as
h(F) = A^, B'
B'
is
contains a tri
-47a n g u l a t i o n of F , s a y F ' . d u c e d s u b d i v i s i o n on Let
B is
K'
b e a s t e l l a r s u b d i v i s i o n of
K whose in-
B'.
p: A —3> A^ b e t h e l i n e a r m a p w h i c h i s t h e i d e n t i t y on A^
the v e r t e x division
Let
v opposite
A " of A '
A^
to S'li i n t e r i o r p o i n t of
such that
and sends
Then t h e r e is a sub-
p : A " —5> A^' i s s i m p l i c i a l , a n d
A^'
is a stellar
s u b d i v i s i o n of A^ . Let
B"
hi B ' —> A '
b e t h e subdivi£ j n of
B'
making
was already simplicial,
e x t e n d s to a s t e l l a r s u b d i v i s i o n
L"
F" of
L " m e e t in t h e c o m m o n s u b c o m p l e x
h : B " —> A"
simplicial.
i s a s t e l l a r s u b d i v i s i o n of
L ,
F", K"
Put
K" = B" U L " .
F',
Since
Since and B"
and
i s a w e l l defined s u b d i v i s i o n of
K,
not n e c e s s a r i l y s t e l l a r . To p r o v e t h i s l e m m a , it suffices b y L e m m a Z. 1 t o p r o v e t h a t B " r i L« = F " . where
To p r o v e t h a t
B"
p : A " — > A" i s s i m p l i c i a l . 1
, in o r d e r of d e c r e a s i n g d i m e n s i o n ,
it suffices to p r o v e t h a t
B" ^ F " ,
as
xS A " \ A'^
Now l e t
{A.} be t h e s i m p l i c e s of A " 1 1 -1 \S -1 • p A. \ p A. o A. by c o l l a p s i n g t h e
-1
p r i n c i p a l s i m p l e x e s of p
A^ f r o m t h e i r t o p f a c e s in o r d e r .
gives t h e r e q u i r e d s i m p l i c i a l c o l l a p s e of
A
A"
onto
A'^ .
D o i n g t h i s in t u r n
-
Theorem 2.4. if
I K|
If L and
K are simplicial complexes,
| L | , then there exists subdivisions
L
K' a n d L' w i t h
C
K , and
L' C. K'
and
K Proof. most
By i n d u c t i o n , a s s u m e t h e t h e o r e m for a l l c o l l a p s e s c o n s i s t i n g of
(n-1)
elementary collapses.
T h e r e is a t r i a n g u l a t i o n of
P . , s a y K. , 1 1
K' n-1
\
\
K' . o
By i n d u c t i o n , t h e r e i s a s u b d i v i s i o n Now,
K' ^ extends to a s u b d i v i s i o n n-1
K" a n d K " , of K' n n-1 n s u c h t h a t K " \ K" ^ . n \ n-1
B y L e m m a 2. 2, K" n
\
X
K" . o
|K| =
> • • • ^ ^ ^Q ~
K ^ of K c o n t a i n i n g a s s u b c o m p l e x e s t r i a n g u l a t i o n s
there exist subdivisions K" ^ s t e l l a r , n-1
Suppose
K" , ^
K' , of n-1
K' of K . n n
^ n-1
with
By L e m m a '
a n d K ' . r e s p e c t i v e l y , with n-1 ^
K" = i n d u c e d s u b d i v i s i o n of o
\^
K
K' . o
Hence
-
2.
F u l l S u b c o m p l e x e s and D e r i v e d N e i g h b o r h o o d s Definition.
«
If K
o
i s a s u b c o m p l e x of t h e s i m p l i c i a l c o m p l e x
said to b e ful l if a n y s i m p l e x in simplex
of
K^ ;
i.e.,
L e m m a 2.5. deriveds, then
l)
K^
2) If then
K a l l of w h o s e v e r t i c e s l i e in K^
no s i m p l e x in K - K^
If K^
K' i s full in o
K and
K^ ^ K'
f
-1
Proof.
is a
i s a full s u b c o m p l e x of
K and K^ 9. K'
is any subdivision
K'.
i s full in
o
(0) = K ^ . 1) If '
1 < i ^ s, then ' s
is
a r e first
i s full in K and A e K - K , t h e n A n | K | O O O e m p t y o r a s i n g l e face of A. (And c o n v e r s e l y . )
such t h a t
o
K^ .
3) If K
4) K
K
h a s a l l i t s v e r t i c e s in K^ .
i s a s u b c o m p l e x of
i s a full s u b c o m p l e x of K^
K,
( L i n e a r m e a n s l i n e a r on s i m p l i c e s
o-e K ' , l e t '
A
there exists a linear map
K
0- = A , . . , A , 1 S
A
h a s a n i n t e r i o r point in K o
cr € K' . o 3) If A € K - K
1
< .. . < A and h e n c e
R
S
+
ft K
> R
= [0,oo).)
e K. A
is e i t h e r
If A. € K ' , 1 o
e K , s
So A. € K , o i o
i < s, and
meets O L e t A^ = s p a n { a , , . . . . a . } . 1 ^ 1
K
, l e t ( a , , . . . , a.) be t h e v e r t i c e s of A i n K . O 1 1 o Then A. e K and A . < A. S i n c e A H | K I i s 1 o 1 o
a l w a y s a u n i o n of f a c e s of A, e a c h of w h i c h i s s p a n n e d by i t s v e r t i c e s ,
A 1
= A n IK
. o 2) S u p p o s e
t a r y c e n t e r of
cr i s i n A .
A^ a face of A .
mi
K ^ ^ K i s full.
Therefore
Then cr r\
Let
ere K ' .
o" C A .
Choose
Ae K
such that the
Moreover, o - r \ [ K | C A n | K = A , o ~ o 1 = o" n A^ , w h i c h i s e i t h e r e m p t y o r a
face of
0".
one face.
T h u s , e v e r y s i m p l e x of
K'
which m e e t s
K ' m e e t s i t in exs
K' i s full in K ' . ( C o n v e r s e of 3 ) . ) o 4) If K^ ^ K i s a full s u b c o m p l e x , l e t f: K r"*" b e defined b y
setting
This m e a n s that
f(v) = 0 if v i s a v e r t e x of K
and
f(v) = 1
if v
i s a v e r t e x in
o K - K ^ , and e x t e n d i n g l i n e a r l y o v e r s i m p l i c e s .
Clearly,
| K^
+
C o n v e r s e l y , if
f: K—5> R
=f
(O).
-1
i s g i v e n and we s e t
K
= f
(O), t h e n
K
o a full s u b c o m p l e x .
It i s a s u b c o m p l e x b e c a u s e if x e a-, tr e K, t h e n
f(x) = 0 = > f((r) = 0. of
0" ,
then
o
It i s full b e c a u s e if
tr e K a n d f i s z e r o on t h e vertic
f((r) = 0 .
N ( L D; Le f)i n=i t i o n . rTL
Ssutpapr o( sve| Lt )h a t (union L^ i os vae rs uvbecr ot im c ep sl e) ,x of c a l lLe d. t hTeh ecnl ows e d define simplici
neighborhood
L^
of
Definition . Let
in
L.
Suppose that
K ^ C K b e a t r i a n g u l a t i o n of X C M; i . e . ,
K^
a fTill s u b c o m p l e x of
n e i g h b o r h o o d of
X in
M,
K.
Then
where
N = |N(K^;K')|
M aji m - m a n i f o l d , =X,
| K | = M;
X C with
is called a derived
K' C K' i s t h e f i r s t d e r i v e d s u b d i v i s i o n of O
a
C
K
X is a polyhedron,
K.
o
IS
(r) (] Definition . If K^C K i s a n y t r i a n g u l a t i o n of X C M a n d if K^ ' ^ K' t h e r^^ s u b d i v i s i o n , t h e n | N(K K^^^) | i s c a l l e d an r^^ d e r i v e d n e i g h b o r
f X in
M.
For
r > 2, a n
r^^ d e r i v e d n e i g h b o r h o o d i s a d e r i v e d n e i g h b o r h j
-
Remark.
T h e r e a s o n for t a k i n g full s u b c o m p l e x e s o r at l e a s t 2nd d e r i v e d s
a s d e r i v e d n e i g h b o r h o o d s i s t h a t we w a n t to be a b l e to p r o v e t h a t a d e r i v e d n e i g h b o r h o o d of
X c o l l a p s e s to X .
d e r i v e d n e i g h b o r h o o d of X i n
If
M is
M =
X = A^, then the first
M, w h i c h d o e s n o t c o l l a p s e to
X.
The
2nd d e r i v e d n e i g h b o r h o o d d o e s c o l l a p s e to X , h o w e v e r .
f
L e m m a 2.6. and K Then f
= f"^(0),
K
be a full s u b c o m p l e x of K.
f linear.
Suppose
0 < £ < f(v) ,
([0, E]) i s a d e r i v e d n e i g h b o r h o o d of
Proof . I'.,
Let
Let
K'
be obtained from
[K
= A
! N ( K ' ; K ' ) | = f'^([0, £]). a
A
< ... < A 1
r
f; K — >
v a n y v e r t e x in K - K , in K
K by s t a r r i n g e a c h s i m p l e x
€ A in o r d e r of i n c r e a s i n g d i m e n s i on, c h o o s i n g
^ . CUirH
Suppose
Let
A. 6 K. 1
A e f
) if
A
A r\ f
cr b e a p r i n c i p a l s i m p l e x of Then
at ^ N(K',K'),
A. e K' , so A. e K , s o m e i . 1 o 1 o
Take
i as l a r g e as possible with A
i+1' Hence
/ 1 I iC
= . . . = f(A^) = £
£(AJ = 0 o r £ .
, so
j < i*
f a r e g r e a t e r than
. . ^ ^ c f'^([O,
If f(A^) = 0, t h e n
A^
and l i e s in f"^([0, £ ] ) . N(K^,K')
£ ,
Therefore,
K ' ) C £"^[0. E ]. ]),
A^ < . . . < A^,
is a v e r t e x of
h a s a v e r t e x i n K^, s a y v , w i t h
£ ] C
=
1 ^ k < r - i , b y l i n e a r i t y of f.
Conversely, suppose
So
Then
have v e r t i c e s whose v a l u e s under
f~ ( £ ) n A
t h e n A^
A^ e K ^ .
K^ .
Then <
If f(A^) = £ ,
[ v | / A^, a n d so But v . A ^ . . .
e
K').
-
Ambient I s o t o p y Def inition. ij X X I land
An a m b i e n t i s o t o p y of a p o l y h e d r o n X i s a p. 1. h o m e o m o r p h i s m
X A I w h i c h c o m m u t e s w i t h p r o j e c t i o n o n I (i. e . , i s l e v e l p r e s e r v i n g )
has the p r o p e r t y that
h(x, O) = ( x , 0 ) , a l l
If h i s an a m b i e n t i s o t o p y , we w r i t e
x e X.
h^ for t h e p. 1. h o m e o m o r p h i s m of X
)nto i t s e l f defined by s e t t i n g h(x, t) = (h^(x), t ) . jontained
in X,
we say that h t h r o w s
X^
If X^
onto
X^
a n d X^ a r e p o l y h e d r a if b^(X^) = X^ .
Two
j l y h e d r a c o n t a i n e d in X a r e s a i d t o be a m b i e n t i s o t o p i c if t h e r e e x i s t s a n i m b i e n t i s o t o p y t h r o w i n g o n e onto t h e o t h e r .
The relation
"X^
is ambient
Usotopic to X " i s c l e a r l y an e q u i v a l e n c e r e l a t i o n . A homeomorphism
kr X
> X i s s a i d to b e a m b i e n t i s o t o p i c to t h e i d e n t i t y
t h e r e e x i s t s a n a m b i e n t i s o t o p y h of X w i t h h^ = k . If X C X, w e s a y t h a t t h e a m b i e n t i s o t o p y h of X k e e p s o
X
o
fixe d if
X I = i d e n t i t y m a p of X^ X I, Lemma 2.7. K| —> | K
Let
K C K b e s i m p l i c i a l c o m p l e x e s , and l e t o
be a p . l . h o m e o m o r p h i s m s u c h t h a t
1) h |
= identity.
2) h(tr) =0- , a l l
cr e K.
^Then h i s a m b i e n t i s o t o p i c to t h e i d e n t i t y v i a a n a m b i e n t i s o t o p y k e e p i n g
; fixed. Proof. ^dimension.
Let. c r 0 " I
Define
n
H on
b e t h e s i m p l i c e s of K - K , i n o r d e r of i n c r e a s i n g o
X I b y s e t t i n g it e q u a l to t h e i d e n t i t y .
Define
H
on K X 1 by setting defined on
H(x, 1) = (h(x), 1) a l l x 6 K.
cr. X I , a l l j < i . J
Then
H to
a point in
cr^ X I by defining
ar^ .
H h a s been^
H i s defined on t h e f a c e s of 1
Extend
A s s u m e that
cr. X I. J
1
^(o-^,— ) = (o"^, — ) and j o i n i n g l i n e a r l y ,
T h i s d e f i n e s a p. 1. h o m e o m o r p h i s m
H: K X I
a.
> K X I.
It
e a s y to c h e c k t h a t it i s l e v e l p r e s e r v i n g a n d i s t h e r e f o r e t h e d e s i r e d a m b i e n t isotopy. C o r o l l a r y 2. 8. and if
If h : B —> B,
h B = i d e n t i t y of B , t h e n
B a p. 1. b a l l , i s a p. 1. h o m e o m o r p h i s n i l
h i s a m b i e n t i s o t o p i c to t h e i d e n t i t y , keepii
B fixed. Proof .
Let
K = A, K^ = A
L e m m a 2. 9 .
Let
X in the polyhedron w h i c h i s fixed on Proof .
N
and apply L e m m a 2.7.
and N
M.
be two d e r i v e d n e i g h b o r h o o d s of t h e polyhec
T h e n t h e r e i s an a m b i e n t i s o t o p y t h r o w i n g
N^ onto |
X.
Let
K ^ Q J^
and
K^ Q J ^
b e t r i a n g u l a t i o n s of X C M, w i t h
K.l
full in J^ . L e t N = |N(K';J')|
p r i m e s denote first derived subdivisions,and suppose and N = |N(K' ; J ' ) | . Let K C J b e a c o m m o n subdivisio
of
K^C
JL
^
K^S
J^
simplicial. of J
o
±
and
Lt
Ct
,
C^
O
(Choose subdivisions making
They obviously a r e the s a m e . )
and, so
O
Then
K^
( p r i m e s denote first deriveds) N = ' o
1
• I-^q I —^
i s a full s u b c o m p l e x
N (J' ; K') o o o
is a derived
neighborhood. It c l e a r l y suffices to find an i s o t o p y t h r o w i n g throwing
N^ onto
N^.
N^ o n t o
N^
and an isotopy
We w i l l c o n s t r u c t an a m b i e n t i s o t o p y t h r o w i n g
N^onto
-
Let £: f'^(O) = fthat
—> R
K^ .
Then
0 < £ < f(v)
subdivisions " such that
K
be a m a p w h i c h i s l i n e a r on s i m p l i c e s , f i s a l s o l i n e a r on s i m p l i c e s of J ^ .
for a l l v e r t i c e s C J o ~ o
*
v in J ^ - K ^ .
and K, C J 1 1
of
K
o
Let £ be such
Then there exist first derived
C J o
f ' ^ ( [ 0 . £ ]) = I N(K *; J * ) | = | N(K
with
and K^ C J 1 1
respectively,
J * ) | = N*. by the p r o o f of
Lemma 2.6. L e t { A J = s i m p l i c e s of lA. € A. .
Say J^
J^.
Let
J^' b e o b t a i n e d by s t a r r i n g at p o i n t s
i s o b t a i n e d by s t a r r i n g
A^ € A^ .
I L e m m a 2.6, it i s c l e a r t h a t we m a y s u p p o s e simplicial homeomorphism linearly over simplices. ! identity, k e e p i n g
J^ —^^—> J^
A^ = A^ if A^ € K ^ .
>1< * N(K ; J ) .
throwing keeping
N
onto
o
| K^ |
By the L e m m a 2 . 7 , h is ambient isotopic to the
j K^ | fixed, for if
cr £ J ^ , h(o-) = cr, and h |
N
Let
£>0
fixed and t h r o w i n g
=
N(K
o
;J
o
) , a n d so N
1
onto
K^
fixed N , o
N.
is full in K. be such that
So l e t
K^
Then let £
M, a n d
in
M, t h e n N \ X . In v i e w of L e m m a 2 . 9 , it suffices to p r o v e t h a t
o
N^
i s a m b i e n t i s o t o p i c to
If X i s a p o l y h e d r o n c o n t a i n e d in t h e p o l y h e d r o n
|! d e r i v e d n e i g h b o r h o o d K
= identity.
S i m i l a r l y , t h e r e i s an a m b i e n t i s o t o p y k e e p i n g
if N i s a d e r i v e d n e i g h b o r h o o d of X
assume
and extending
fixed.
L e m m a 2. 10.
Proof.
Define a
by sending A. to
H e n c e t h e r e i s an a m b i e n t i s o t o p y k e e p i n g I ^ ^ | * N =
F r o m t h e p r o o f of
N \ X for o n e
K be a t r i a n g u l a t i o n of X 9 M, and
f: K
>R
all v e r t i c e s
+
be l i n e a r , with
v of K - K .
f
-1
(O) = K . o
We h a v e s e e n t h a t
N = f
is a d e r i v e d n e i g h b o r h o o d of K^.
So i t suffices to s h o w
£])\|KJ. Let
i = 1, , . . , r )
b e t h e s i m p l i c e s of K - K ^
d i m e n s i o n . T h e n C. = A^ n f Let
F . = A. n
-1
£ ), a f a c e .
U. = U VJ (U{C. j = 1 , . . . , i } ) . 1
O
1
in a f a c e .
'H ([0, £ ]) i s a c o n v e x l i n e a r c e l l a n d so a p. l . . | Now s e t Then
J
face of C . .
^ 1
Hence
U^ = (K^), a n d s e t
C. n U. 1
So c l { U . - U . J
1-1
U. \ 1
U. ^
1-1
i n o r d e r of i n c r e a s ^
= c l { C . - C. n U. J 1
But
1
= C . n A. = c l { C . - F . }
1-1
1-1
1
= C.
U^ = f" ([0,£ ]).
1
1
1
ig;
1
is a ball meeting
®
-
4.
E x i s t e n c e and U n i q u e n e s s of R e g u l a r N e i g h b o r h o o d s Definitio n.
L e t X b e a p o l y h e d r o n c o n t a i n e d i n the p. 1. m - m a n i f o l d
N C M i s c a l l e d a r e g u l a r n e i g h b o r h o o d of X in
M if
1) N i s a c l o s e d n e i g h b o r h o o d of X in 2) N i s a n m - m a n i f o l d , 3)
M.
M,
and
N^X.
T h i s s e c t i o n i s d e v o t e d to t h e p r o o f of t h e following t h e o r e m . T h e o r e m 2. 11.
Let
X C M,
M and m - m a n i f o l d ,
X a polyhedron.
Then
1) Any d e r i v e d n e i g h b o r h o o d of X i s a r e g u l a r n e i g h b o r h o o d ; 2) If N
and N
a r e r e g u l a r n e i g h b o r h o o d s of X in
BMSts a p . l . h o m e o m o r p h i s m
h : N^ —5> N ^
such that
M, t h e n t h e r e
h(x) = x if x e X ;
and
3) If X i s c o l l a p s i b l e t h e n a n y r e g u l a r n e i g h b o r h o o d of X a p . 1. m - b a l l . T h e o r e m 2. 11 i s p r o v e n b y i n d u c t i o n . i t e m e n t s , for e a c h i n t e g e r E(n)i
We c o n s i d e r t h e following t h r e e
n > 0:
If X i s a p o l y h e d r o n c o n t a i n e d in t h e m - m a n i f o l d
M, a n d if m ^ n,
e v e r y d e r i v e d n e i g h b o r h o o d of X i s a r e g u l a r n e i g h b o r h o o d . If N^ a n d N^
a r e d e r i v e d n e i g h b o r h o o d s of X i n m"^, a n m - m a n i -
a-iid if m ^ n , t h e n t h e r e e x i s t s a p . l . h o m e o m o r p h i s m identity on
h: N^ —> N^
which
X.
In a m a n i f o l d of d i m e n s i o n at m o s t •Biblepolyhedron is a p . l .
m-ball.
n, e v e r y r e g u l a r n e i g h b o r h o o d of a
L e m m a 2. 1 2.
Proof. of X in
Let
d i m M ^ n.
If X '^{X^}
^JID N i s a r e g u l a r n e i g h b o r h o o d j
M, t h e n X is a r e g u l a r n e i g h b o r h o o d of { x ^ } .
t r i a n g u l a t i o n of s t a r (x ; K) o of X .
U(n) i m p l i e s B(n).
=
M w i t h x^
a v e r t e x of K.
X . linkfx ; K) o o
Moreover,
Let
M = |K|
be
Then
i s a p. 1. m - b a l l , a n d a c l o s e d n e i g h b o r h o o d l '
| s t a r (x ; K)| ^ { x } .
So U(n)
i m p l i e s that
N is h o m e o |
to t h e p. 1. m - b a l l | s t a r ( x ^ , K ) | . L e m m a 2. 13. Proof .
E ( n - l ) and
B(n-l) implies
E(n).
L e t X ^ M b e a p o l y h e d r o n c o n t a i n e d in t h e m - m a n i f o l d
Let
K C K be a t r i a n g u l a t i o n of X C M, w i t h o ° ~
N=
N(K^;K') .
know t h a t N \ ^ X .
X
o
full in K.
M, m ;
Let
N i s c l e a r l y a c l o s e d ( t o p o l o g i c a l ) n e i g h b o r h o o d of X , and SO it r e m a i n s o n l y to show t h a t
do t h i s , it suffices to p r o v e t h a t
N i s a p . 1. m - m a n i f o l d .
N ( K ^ j K ' ) , for w h i c h we a l s o w r i t e
of n o t a t i o n , i s a c o m b i n a t i o r i a l m - m a n i f o l d .
N, by abiJ
Using induction and the formula ,
l i n k ( A B ; N ) = l i n k ( A ; l i n k ( B ; N)) w i t h a s i n g l e v e r t e x , it i s e a s y to s e e t h a t be a c o m b i n a t o r i a l m - m a n i f o l d if (and only if) for e v e r y v e r t e x
v of
N
N,
link(v; N) i s an ( m - l ) - s p h e r e o r b a l l . So l e t V be a v e r t e x of
N,
If v e K^, t h e n
s t a r (v; K') ^ N, a n d so
link(v; N) = l i n k ( v ; K ' ) = a s p h e r e o r b a l l of d i m e n s i o n ( m - l ) . S u p p o s e on the o t h e r h a n d t h a t
A € K.
Let
v e N-K' , o
Then v = ^
for s o m e s i m p l e
B = A r\ [ K^ [ ^ a s i n g l e (siiiiplicia^; face of A by f u l l n e s s of K^
(B i s c l e a r l y n o n - e m p t y ) .
-
Let
cr € K ' , a n d w r i t e
o" = A . , . . A , A^ < . . . < A e K. T h e n 1 s 1 s A^ < A < s o m e j , o r A < A^ o r A^ < A. So if
€ link(v;K')
= { B , . . . B . | A < B < . . . < B. € K}, t h e n 1 J ^ 1 J where
cr. e (A)'
and
cr € S,
|(We allow t h e p o s s i b i l i t y
(A)'
ere l i n k ( v ; K ' ) < ^ cr = cr o" , 1 ^
b e i n g t h e i n d u c e d s u b d i v i s i o n of K'
tr^ = 0 , i = 1, 2, a n d w r i t e
= ar^, .
on
A.
= cr^.)
Thus, l i n k ( v ; K ' ) = A . S . Let
Now A < B = > B / k ' . H e n c e s a k ' = Therefore o o r\ K' = A ' n K' = B ' . T h e r e f o r e , L o N c o n s i s t s of t h e s i m p l i c e s of L o o meeting
L=A.S.
B'
and t h e i r f a c e s .
T h e fact t h a t
B i s c o n v e x i n s u r e s t h a t it and i t s
faces f o r m a full s u b c o m p l e x of a n y s i m p l i c i a l c o m p l e x c o n t a i n i n g i t .
We h a v e
L r\ N = N ( B ' ; L ) = N ( B ' ; A ' S ) = N ( B ' ; A ' ) . S , the l a s t e q u a l i t y b e i n g a c o n s e q u e n c e of t h e fact t h a t N(B';A') manifold | A ' | N(B';A')|
B' £ A ' .
is a derived neighborhood.of the collapsible complex of d i m e n s i o n at m o s t ( n - l ) .
B'
in t h e
H e n c e b y B ( n - l ) and E ( n - l ) ,
i s a p . 1. b a l l w h o s e d i m e n s i o n i s
( d i m A - 1).
However,
S
is
p . l . h o m e o m o r p h i c to l i n k { A ; K ) .
In fact, if A < B and C i s t h e c o m p l e m e n t a r y A face, the m a p on v e r t i c e s w h i c h s e n d s B to C d e t e r m i n e s a s i m p l i c i a l h o m e o m o r p h i s m of ''
S onto
to m - d i m A - 1.
(liiik(A; K ) ) ' . «
Hence
A'.S
T h u s to c o m p l e t e t h e proof, link(v;N) = l i n k ( v ; K') A N. ^
Thus,
T. • T, 1 1
meets B'.
i s a p . l . b a l l of d i m e n s i o n e q u a l
i s a p . 1. b a l l fo d i m e n s i o n
m-1.
it r e m a i n s o n l y to s h o w t h a t
C e r t a i n l y , l i n k ( v ; N) C l i n k ( v , K ' ) A N,
0-€ l i n k ( v ; K ' ) O N = N ( B ' , A ' ) . S , t h e n ^
|s|
cr = (r^cr^ w h e r e
So v o - < v T . t r ^ w h i c h m 6 e t s 1 2
B',
« ^^ «
Conversely, ^ ^
So vo" e N, o-e l i n k ( v , N ) .
L e m m a 2. 14.
If M i s a n m - m a n i f o l d ,
B C M is an m - b a l l such that
F = B n M
t h e n t h e r e e x i s t s a p . 1. h o m c i o m o r p h i s m of
if X C M i s a p o l y h e d r o n , if i s a face of
B , a n d if B n X s
h: c l ( m - B ) —5> M w i t h h X = i^g
X.
Proof . and say
By i n d u c t i o n o n
m.
dim M = m,
1) c l ( M - B )
is an m-manifold.
Namely, triangulate c o m p l e x e s , and c o n s i d e r
y X^fyi^
,
M
so t h a t
B and F
l i n k ( x ; M - B ) , x a v e r t e x of
l i n k ( X ; M - B ) = l i n k ( X ; M), first
So a s s u m e 2. 14 for m a n i f o l d s of d i m (m-
an ( m - l ) ball o r s p h e r e .
x / F.
Then
a r e t r i a n g u l a t e d a s suli M-B .
If x e M - B , thJ
If x e M - B r» B,
suppose|
l i n k ( x ; M - B ) = l i n k ( x ; M) - link(x; B) i s a n (i
s p h e r e w i t h t h e i n t e r i o r of a n ( m - l ) - b a l l d e l e t e d , a n d so an ( m - l ) b a l l . then X € F .
[F O M - B = F ] .
(link(x;M))
= l i n k ( x ; M ) , a n d so
a f a c e of t h e ( m - l ) b a l l
So l i n k C x . F )
Moreover,
( l i n k ( x ; M)) n l i n k ( x ; B) = l i n k ( x ; M r i B )
link(x;B).
cl( I l i n k ( x ; M) I - | l i n k ( x ; B ) [ )
i s an {m-2) ball.
If x «
= linki
H e n c e by ina^'ction,
i s p . l . h o m e o m o r p h i c to | l i n k ( x ; M ) | , a n ( m - l ) t
-£)1Iberefore,
| link(x; M - B )
isp.l.
(m-1) ball.
This proves that
cl(M-B)
is
inanifold of d i m m . 2)
Let
boundary c o l l a r . jet
F^ = a ] ^ .
Choose
D = c ( F ^ X [0, £ ] ) .
c: a(cl(M-B) X I
such that
> cl(M-B)
c ( F ^ X [ 0 , £])
E x t e n d to a l l of
be a
does not m e e t
T h e r e i s a p. 1. h o m e o m o r p h i s m
is the i d e n t i t y on D - F . liiomeomorphism
£>0
Let
B uD—> D
X. which
M by t h e i d e n t i t y , g e t t i n g a p. 1.
M—> cl(M-B).
To s t a r t t h e i n d u c t i o n , we l e a v e it to t h e r e a d e r to v e r i f y t h a t in c a s e m = 1, icl(M-B) I
is a manifold,
I
Lemma 2.15.
It'-
,
,
—
I
and t h e n to p r o c e e d a s in 2).
E ( n - l ) and B ( n - l ) i m p l i e s
U(n).
!• • I . . I
Proof .
L e t N be a r e g u l a r n e i g h b o r h o o d of X i n M.
T h e n we w i l l s h o w
[that N i s p. 1. h o m e o m o r p h i c to a d e r i v e d n e i g h b o r h o o d of X in a-manifold, on X. Let r s o that
X
a polyhedron in
So l e t
K = K^ ^ ^ K^ ^ ^ ^ . . . ^
K" = b a r y c e n t r i c s e c o n d d e r i v e d of and U
an
U(n).
K C K C J be t r i a n g u l a t i o n s of X C N C M. o K^.
(M
M . ) , via a h o m e o m o r p h i s m which is the identity
T h i s t o g e t h e r w i t h L e m m a 2. 9 w i l l i m p l y
K ^
M.
K.
Let
i s a s e c o n d d e r i v e d n e i g h b o r h o o d of
We c a n c h o o s e
K^ b e t h e c o l l a p s e .
U^ = N ( K j ' ; K " ) . |K
|
K S K o
Then
Let
U^ = K " ,
in t h e n - m a n i f o l d
|Kj.
We
ft
I a r e going to c o n s t r u c t p. 1. h o m e o m o r p h i s m s •pointwise fixed.
We a s s u m e b y i n d u c t i o n t h a t
®o t h a t w e m a y a s s u m e in p a r t i c u l a r t h a t
> U. w h i c h l e a v e
K^
h a s b e e n c o n s t r u c t e d if i i s an m - m a n i f o l d .
r-1,
Now l e t u s o b s e r v e t h a t
U^ =
s t (o-jK").
Since
is a vertex
o-cK. 1 K'^ , t h e i n c l u s i o n
D is obvious.
S u p p o s e o n t h e o t h e r h a n d , t h a t T € U. A
then B
T I T . , where 1
<
I
< B
If B^ ^
€ K'.
s
T. m e e t s 1
KI*. 1
T h e n for s o m e
is a point, then
Suppose i,
B^ = tf-,
1
e K.". 1
( 1 o-eK. 1
B , . Then o - B , . . . B e K", 1 I s s t ( o - ; K " ) , a n d h e n c e so d o e s T,
Now let
U.^
1+1
B. e Kl , so B « 1 1 1 ir e K^ b e s u c h thai
So i n e i t h e r c a s e
K , = K. + A + B , A = a B , a e K . , A / K. . 1+1 1 1 1
c e n t e r s of s i m p l i c e s of A and
Hence
Otherwise, let
i s a v e r t e x of
T e
A
T. = B . , . . B , w h e r e 1 1 s
T h e n t h e o n l y bai
w h i c h a r e not b a r y c e n t e r s of s i m p l i c e s of
Therefore = U. + P + Q , 1
P = star(A;K"),
Q=st(B;K").
We n o w c l a i m t h a t t h e following two s t a t e m e n t s a r e t r u e : a)
U^ n P
i s a f a c e of
b) ( U ^ u P ) n Q To p r o v e a), l e t
P.
i s a f a c e of
Q.
L = l i n k ( A ; K") = A ' . S, w h e r e
(See L e m m a 2. 1 3 . )
Let
p: l k ( A ; K " ) — > L '
w h i c h i s defined o n v e r t i c e s b y s e n d i n g ^ C If
0- c P O U^, t h e n o" e l k ( A ; K " ) , a s
o-e l i n k { D ; K " )
for s o m e
D / it(A;K").
Therefore,
D e K.
as
S=
A < B^< . . . <
be simplicial h o m e o m o r p h i s m to
C for a n y s i m p l e x
and
A /
for s o m e
L.;
In a d d i t i o n ,
D e K.
(re P o u . = > o" e l':ak{A;K") O l k ( 6 ; K " ) ,
C o n v e r s e l y , it i s c l e a r t h a t a n y s i m p l e x of
C of
but some D
s u c h a n i n t e r s e c t i o n l i e s in
P
-63-
However, lk(Aj K") n
K " ) j/ ^ < = > AD e K ' .
F o r if
o- = B 1
< . . . < Bg « K ' , i s a s i m p l e x of t h i s i n t e r s e c t i o n , t h e n A a n d irertices of B , a n d c o n v e r s e l y . 1 D or
D < A.
But
So t h i s i n t e r s e c t i o n i s n o n - e m p t y if a n d o n l y if
A w a s a p r i n c i p a l s i m p l e x of
< A is the only p o s s i b i l i t y , in which c a s e
U De aB Since
P
D E aB.
^^ So we h a v e p r o v e n t h e
(link(A; K " ) n link(D; K " ) ) .
U. C l i n k ( A ; K " ) , w e m a y c o n s i d e r i t s i m a g e u n d e r t h e p . 1.
>omeomorphism p
B , 8 m u s t be
p: link(^; K « ) L ' .
lk{£);K")<S=^p(r€ •it"(D;L').
F o r if
If
cr € l i n k ( A : K " )
cr =
..
.
f r i t e B. = kr. . T h e n p( O" ) = . . . T £ L ' . But S' 1 1 I S « lk(D;K") b < B^ D^ < T^ po" e st(D; L ' ) .
and D € a B , t h e n
B^ < . . . < B^ 6 K ' ,
So w e h a v e :
-63(CI)-
p ( p n u )
=
M
.
=
DTaB T h e l a s t e q u a l i t y follows a n a r g u m e n t s i m i l a r t o t h a t u s e d in d e r i v i n g a s i m i l a r e x p r e s s i o n for However, i s full i n
L'.
U^ ( p a g e 62 ). (aB)' L'
is f\ill i n A '
L = A'.S.
Therefore, (aB)"
i s a p . 1. m a n i f o l d of d i m e n s i o n ( n - l ) .
E ( n - l ) ==^> N ( ( a B ) " , L ' ) aB|
a n d so a l s o i n
i s a r e g u l a r n e i g h b o r h o o d of
| aB
Hence But
in
s o b y B ( n - l ) , t h i s r e g u l a r n e i g h b o r h o o d i s a p . 1, ( m - l ) b a l l .
P n U^ i s a l s o a p . l . ( m - l ) b a U . b o u n d a r y of
Since
P n U^ C l i n k ( A ; K " ) , w h i c h l i e s
P = s t a r (A; K " ) , t h i s p r o v e s t h a t
To p r o v e b), l e t
Hence
P O U^ i s a face of
= link(:&;K') = B ' . S ^ , s a y .
P.
Define p^.lk(]S; K»') —5> L^
A
jy defining i t o n v e r t i c e s to s e n d € Q r\ (U. u P ) )r for
D = A.
D < B.
Since
>B8ibilities a r e
if a n d o n l y if
BC t o
C.
As before we have that
o- c link(]&; K " ) n l i n k ( ^ , K < ' )
for s o m e
D e K.
O n c e a g a i n , t h i s i n t e r s e c t i o n i s n o n - e m p t y if and o n l y if B < D B i s a f r e e face of t h e p r i n c i p a l s i m p l e x D « A or
P^(Qn(U u P ) )
D < B.
=
A, t h e o n l y
So t h i s t i m e w e find t h a t ) =
N((AB)";L').
Dt B or D = A ^Tjefore, w e s e e t h a t B(n-l)
i s full in L^ = B ' S ^
and i s c o l l a p s i b l e .
= > N ( ( A B ) " ; L j ^ ) i s a n ( n - l ) b a l l , a n d so
^
is a manifold.
Q = c l ( Q - F r Q ) , w h e r e t h e f r o n t i e r of
E(n-l)
Q O (U. ri P ) i s a face of Q.
| T o c o m p l e t e t h e proof, we a r e going to a p p l y L e m m a 2. 14. ive h y p o t h e s i s i m p l i e d t h a t
So
Recall that the
Moreover,
Q i s t a k e n w i t h r e s p e c t to
But F r Q = (U. U P ) A Q, a face of 1
Hence
Q.
is p. L h o m e o m o r p h i c to
m e n t g i v e s a p, L h o m e o n n o r p h i s m of
Hence cl {U
1+1
^ Q i s a l s o a face of
- Q} = U. vJ P .
U, O P
with
U. ^ u s i n g
A similar arj L e m m a 2.1^
again.
P r o o f of T l ^ e o r e m 2. 11. B(0), E ( 0 ) , ditid U(0), Then
Let
By t h e p r e c e d i n g l e m m a , it suffices to e s t a b i
M be a z e r o - m a n i f o l d ,
X a polyhedron,
M is a finite s e t of p o i n t s and X i s a s u b s e t .
hood of X i s a l s o X, a s if
P ^ X,
c o l l a p s i b l e , it i s a s i n g l e p o i n t , so Re'mark,
X u {P}
X C
H e n c e a n y d e r i v e d neig
d o e s not c o l l a p s e to X .
If Xj
B{0) i s a l s o trivial,.
In t h e c o u r s e of p r o v i n g L e m m a 2. 1, we a l s o s h o w e d t h a t given ar
regular neighborhood
N^
of X in
m"^, t h e r e e x i s t s a s e q u e n c e of m - m a n i f
N = V D ., , D V 1 r o with meets
V^ a d e r i v e d n e i g h b o r h o o d of V
1-1
X and
in a face a n d a l s o m e e t s
8V
cl(V^ - V^ m a face„
a n d m - b a l l , which:
-65-
15.
U n i q u e n e s s of R e g u l a r N e i g h b o r h o o d s w h i c h M e e t t h e B o u n d a r y R e g u l a r l y In S e c t i o n 3 w e p r o v e d t h a t d e r i v e d n e i g h b o r h o o d s of a p o l y h e d r o n in a
^manifold a r e a m b i e n t i s o t o p i c .
In t h i s s e c t i o n w e e x t e n d t h i s r e s u l t to a l a r g e r
l a s s of r e g u l a r n e i g h b o r h o o d s . Definition . ^manifold
A regular neighborhood
M i s s a i d to m e e t t h e b o u n d a r y r e g u l a r l y if e i t h e r
: r e g u l a r n e i g h b o r h o o d of X n 8M in |Note;
N of t h e p o l y h e d r o n
M m e e t s the boundary r e g u l a r l y .
+ C K - K .
o
f: K — R
-1 is linear,
o
^^^
f
(O) = K^, and f(v) > 6
f'^[0, £ ] =
H K N 8 K = ^ , 9 K
^'derived n e i g h b o r h o o d of
N O 9M i s a
9M o r b o t h of t h e s e i n t e r s e c t i o n s a r e e m p t y .
A d e r i v e d n e i g h b o r h o o d of X i n
F o r suppose
X in t h e p. 1.
9K in
9K.
Otherwise
for a l l v e r t i c e s
BK N f ' ^ [ 0 , £ ] i s a
T h e u n i q u e n e s s of d e r i v e d n e i g h b o r h o d s
shows t h a t t h e r e s u l t h o l d s for a l l d e r i v e d n e i g h b o r h o o d s . T h e o r e m 2.1
If N
ledron X in t h e m a n i f o l d imbient isotopy throwing
and N
a r e two r e g u l a r n e i g h b o r h o o d s of t h e p o l y -
M which m e e t s
9M r e g u l a r l y , t h e n t h e r e e x i s t s an
N^ o n t o N^, fixed on
X,
N a t u r a l l y to p r o v e t h i s t h e o r e m we w i l l n e e d s o m e l e m m a s . L e m m a 2. 17. fenifold.
Let
Let
N C M be m-manifolds.
X C N be a polyhedron,
ll^se B n Frj^(N) 1) B C Int M
i s a face of
Suppose
N n 9M i s a n ( m - l )
B C N and m - b a l l ,
B O X =
Sup-
B and e i t h e r
or
2) B n 9M = B^ i s a face of
B and
B^rs F r j ^ ( N )
i s a fac e of
B. .
'^en t h e r e e x i s t s a n a m b i e n t i s o t o p y of M, t h r o w i n g N onto c l { N - B ) , w h i c h i s i s t a n t o u t s i d e a n m - b a l l c o n t a i n e d in M not m e e t i n g
X.
-66-
Pictures:. l ) BCM.
2)
dN
-67-
Proof. triangulate
F i r s t of a l l , c l ( M - N ) M with
1) X e M - N .
cl(N-B)
a r e manifolds.
Nannely,
N a s a s u b c o m p l e x and let x be a v e r t e x of
Then
M-N .
lk(x; M - N ) = link(x; M) = s p h e r e o r b a l l of d i m m - 1 .
2) X € ( F r N ) n (Int M), But lk(x; M)
and
Then
link(x; N) a n d
link(x; M ^ F ) = l i n k ( x , M) - l i n k { x ; N ) .
l i n k ( x ; M) i s an ( m - 1 ) s p h e r e .
H e n c e l i n k ( x ; N)
is an ( m - l ) b a l l and t h e c l o s u r e of t h e difference i s a n ( m - l ) b a l l . 3) X € 8M n F r ( N ) . F r ^ ( N ) = 8N - N since we a s s u m e d t h a t
aM
, w h i c h is a p . l .
N n 9M w a s , a n d b y l ) and 2).
Now link(x; M - N ) = l i n k ( x ; M) - link(x5 N)
and
Link(x; M ^ n N) = link(x5 M) - link(x5 N) n link(xi N). B^ = l i n k ( x ; N ) , b o t h ( n - l ) b a l l s . SB.HB^ 1 2
i s a face of
This proves Let F
B^ and 2
cl(M-N)
= B n Fr{N).
Then
B ^ - B ^ n B^
i s a face of B ^ .
F
cl{N-B)
=BOcl(N-B).
F
is a face of
'2 = cl(B - F ^ U B^), a n d w e s a w t h a t
F^ ^
^et
n X = 0 .
Let
^
B , for i n
and in c a s e 2 , ® ^^
para-
M w i t h F ^ , B^ = B H aM, F ^ , B, N, and X a s s u b c o m p l e x e
C = s e c o n d d e r i v e d n e i g h b o r h o o d of F ^
^ngulation.
So
is a m a n i f o l d by L e m m a 2 . 1 4 .
F ^ = cl(B - F^);
Triangulate
B^ = l i n k ( x ; M),
B , - B^ i s an n - b a l l , 1 2
is a manifold. Let
Let
: a s e 1) of t h e s t a t e m e n t of t h i s l e m m a
5raph.
(m-l)-manifold,
in
M - N , w i t h r e s p e c t to t h i s t r i -
D = s e c o n d d e r i v e d n e i g h b o r h o o d of F ^
in N - B .
Note t h a t
Since
F ^ and F ^
are collapsible,
u n i q u e n e s s p a r t of T h e o r e m 2. 11. is a n m - b a l l .
E = C
B
D n B = F
C and
D a r e m - b a l l s , by t h e
C n B = F ^ , a c o m m o n face,
, a c o m m o n face, C*
so
Co
^
so D u B i s a n m - b a l l .
D is a s e c o n d d e r i v e d n e i g h b o r h o o d of
B in
M a n d so is an
m-ball. Now we c o n s i d e r t h e two c a s e s of t h e s t a t e m e n t of t h i s l e m m a . 1) B c int M. We define
f: E —» E
a s follows.
Put h | E = identity.
Now C n (B u D) = C n F r ( c l ( M - N ) ) = C n ( 8 c l ( M - N ) ) , a s But F ^ c F r N
and
boundary regularly. (C
C is a d e r i v e d n e i g h b o r h o o d in c l ( M - N ) Hence
C
B) (\ D = D n a ( c l ( N - B ) )
(B * > D)
h a v e i d e n t i c a l b o u n d a r i e s , b o t h c o n t a i n e d in E ,
h^:
C n (B u D)
morphism
> (C u B) n D.
h • C —> (C J B)'
morphism
Now, fixed.
> E.
h^
h, t h i s d e f i n e s a p . l . hoi
h
h : (B u D ) ' —> D|
e x t e n d s to a p . l . homeo-
h ^ : B U D —> D.
Let
( T h e r e a d e r i s a d v i s e d to c o n s u l t P i c t u r e 1 on p a g e
h(B u D) = B .
l e v e l for p o i n t s o u t s i d e E . X fixed.
Hence
e x t e n d s to
Moreover,
h is a m b i e n t i s o t o p i c to
Extend this ambient isotopy over
and l e a v e s
homeomorphism
a n d a p. 1. h o m e o m o r p h i s m
h ^ : C —> C u B a n d
h = h ^ u h^ : E
M o r e o v e r , t h e s e two ba
H e n c e t h e r e s t r i c t i o n of h
Together with
w h i c h a g r e e w h e r e t h e y a r e b o t h defined.
a n d so m e e t s
is an ( m - l ) b a l l .
i s a l s o an ( m - l ) b a l l .
t h i s c o m m o n b o u n d a r y e x t e n d s to a p . l .
C O SM =
keeping 9
M by l e t t i n g it be t h e i d e n t i t y at eve:
The resulting ambient isotopy t h r o w s
N onto
cl(I^
-69-
2) B n a M / 0 . a r g u i n g a s in l ) h : E^
> E^
Let
C^ = C n 8M,
D^ = D n 8M, E ^ = E
9M.
By
(one l o w e r d i m e n s i o n ) , w e m a y find a p. 1. h o m e o m o r p h i s m such that
( R e c a l l : BM =
)
h | aE^ = i d e n t i t y , h(c^) = C^ U B ^ , h(D^U B^) = D ^ .
Define
h on F r E
by setting h | F r E = l .
Then as before,
h i s defined on (C H (B U D))', w h i c h it m a p s h o m e o m o p r h i c a l l y onto ((C u B) n D ) ' .
( T h e s e a r e not e q u a l . )
to a - p . l . h o m e o m o r p h i s m of E
Once a g a i n , t h i s definition e x t e n d s
which is the identity on F r ( E ) .
Now h
is
a m b i e n t i t o t o p i c to t h e i d e n t i t y v i a a n i s o t o p y fixed on F r ( E ) , b y a c o r o l l a r y to 2.7 which we did not s t a t e . Notes;
l)
E x t e n d t h i s i s o t o p y a s in l ) .
The unstated c o r o l l a r y is;
If A^
i s a p r i n c i p a l face of A = v A ^ ,
«
any h o m e o m o r p h i s m the i d e n t i t y k e e p i n g
h : A — > A w i t h h vA^ = i d e n t i t y , i s a m b i e n t i s o t o p i c to vA^
fixed.
This applies because
E S vE^.
2) T h e m - b a l l o u t s i d e w h i c h t h e i s o t o p y i s c o n s t a n t i s L e m m a 2. 18.
If X C Int m"^
a n d N^
a n d N^
E.
a r e two r e g u l a r n e i g h b o r -
^h oods of X w h i c h l i e in Int M, t h e n t h e r e e x i s t s an a m b i e n t i s o t o p y t h r o w i n g N^ onto
N^.
Proof.
In t h e p r o o f of T h e o r e m
H
( s e e l e m m a 2 . 1 4 a n d the r e m a r k on
page 4 ^ ) , w e s h o w e d t h a t t h e r e e x i s t s a s e q u e n c e of m - m a n i f o l d s , Nj = V D V . TD . . . ' ^ V with ^ r r-1 o .W
ith B. = c l ( V . - V . J 1 1 1-1 Int M.
^
V
o
and m - b a l l w h i c h m e e t s
B o ( 9 V ) = B. n F r V . . i l l 1
a m b i e n t i s o t o p y of
a d e r i v e d n e i g h b o r h o o d of X in M and
Hence L e m m a 2.1
M, fixed o n X , t h r o w i n g
a-mbient i s o t o p i c to a d e r i v e d n e i g h b o r h o o d . P-re ambient isotopic.
V. . and 1-1
9V. in f a c e s . 1
Since
applies: there exists
V^ onto V^
Hence
N^
is
So i s N ^ , a n d d e r i v e d n e i g h b o r h o o d s
L e m m a 2. 19. of X r^ 8M in throwing
N^
Proof.
If X 9 M
a r e r e g u l a r neighborhood
9M, t h e n t h e r e e x i s t s a n a m b i e n t i s o t o p y of onto
Let
\ triangulation.
M, fixed on X-
N^ . M be t r i a n g u l a t e d w i t h N^
^^^
X n aM.
, and N^ and N^
Then
^o ~
a n d X a s s u b c o m p l e x e s with a
d e r i v e d n e i g h b o r h o o d of X w i t h r e s p e c t to thia
U^n BM i s a s e c o n d d e r i v e d n e i g h b o r h o o d in
9M of
We s a w in the proof of T h e o r e m 2. 11 ( s e e L e m m a 2. 15) t h a t in 91
t h e r e e x i s t s a c o l l e c t i o n of ( m - l ) m a n i f o l d s cl(V. -
is a ball meeting
9V. = Fr^^ V. , 1 oM 1
Therefore,
V. ^ and
Lemma 2.1
N = V 1 r ~ a(V.) in f a c e s .
As
a p p l i e s to e a c h p a i r
give an a m b i e n t i s o t o p y t h r o w i n g
V^ onto V^
b a l l in
X.
9M w h i c h d o e s not m e e t
=U o o 8(aM) = V.
,
V. , toJ 1 1 - 1
c o n s t a n t o u t s i d e of an ( m - l ) -
Call this ambient isotopy
b e t h e b a l l o u t s i d e of w h i c h it i s c o n s t a n t
such
(may take
H. , and let
Ej
E . = 2nd d e r i v e d neighboj
hood of
of
c l ( V . - V . J i n 9M). E . H X = Cf. 1 1-1 1 ^ Now t r i a n g u l a t e M w i t h X and E a s s u b c o m p l e x e s . L e t F . = 2nd d e r i l i 1 E . in M. F . n X = 0 . We e x t e n d H. to F . a s follows; P u t H. = ident 1 X ^ 1 1 1
on ^ r j ^ ( F ^ )
and e x t e n d
H^ and
H over
F.
S e c t i o n 3, L e m m a 2.7 and C o r o l l a r y 2. 8 . ) . M X 1.
T h i s d e f i n e s an a m b i e n t i s o t o p y of
a n d F . X I in t h e u s u a l w a y Now put
Similarly, X also.
N But
Ct
is a m b i e n t i s o t o p i c to
U^
U'ri o
is a m b i e n t i s o t o p i c to
H^ = i d e n t i t y on the r e s t
M throwing
p o s i n g t h e s e i s o t o p i e s d e f i n e s an i s o t o p y t h r o w i n g 9M,
N^
(see
V.
onto
onto U^
V.
Com-
9M, fixed on
U ' a d e r i v e d n e i g h b o r h o o d of o
U^, a n d a n y a m b i e n t i s o t o p y t h r o w i n g
-71-
onto
U' m u s t t h r o w o
U n 8M onto o
U' O 8Mp a s p . l . h o m e o m o r p h i s m s of o
manifolds p r e s e r v e boundary.
E. 1
SM
L e m m a 2. 20.
If N i s a r e g u l a r n e i g h b o r h o o d of X i n
M a n d if N
meets
)m r e g u l a r l y , t h e n N ^ X O (N n a m ) \ j X . Proof.
F i r s t s u p p o s e t h a t N i s a d e r i v e d n e i g h b o r h o o d of X , i. e . , ;K')| ,
iubcomplex.
Let
where
K^ ^ K i s a t r i a n g u l a t i o n of X C M w i t h be t h e s i m p l i c e s of
K-K^
which m e e t
K^ K^,
a full ordered
a s to s a t i s f y t h e following tow p r o p e r t i e s : o a) S i m p l i c e s of K
• p r e c e e d t h o s e of K .
b) A. p r e c e e d s i t s f a c e s , n | K I = B . , a s i n g l e face of A . . A. n N = | N ( B : ; Al) , a b a l l . O 1 ° 1 1 X I n N = N(BJ; a : ) , a face of t h i s b a l l . Hence X U. = K U { U ( N O A )} \ | K J U { U ( N n A )} = U.^^ , 1 o j=l '' j=i+l
-72r
,
as j=l
r
(N 0 A.) 1 (N p| A.) J ^ j=i+l J
a n d by L e m m a 2. 1,
d i v i s i o n in w h i c h t h e c o l l a p s e s a r e s i m p l i c i a l ) . K
C ( [J j=l
r\
p o i n t of K Now, U
r
^
L e m m a 2. 1 a p p l i e s b e c a u s e
X
( N n A )) = ^
|K
A.) C j K ^
j=l
is c o n t a i n e d in A . , s o m e J
U^ = N.
JL
U
In (
( a p p l i e d to a s u b -
In
(
U
A ), j=t+i ^
for if a
j, it i s c o n t a i n e d in a p r o p e r face of
C l e a r l y , t h e r e e x i s t s an i
such that
U^ = X u (N O 8M),
A., J
b y a)]
= X. Now s u p p o s e t h a t
regularly. Claim;
Then
N is a r e g u l a r n e i g h b o r h o o d of X w h i c h m e e t s the bour
N n DM i s a r e g u l a r n e i g h b o r h o o d of X n 9M in
N H 8M C 8N i s a r e g u l a r n e i g h b o r h o o d of X n 8N in
N n a M i s a n e i g h b o r h o o d of X H 8N i n
8N
w h i c h c o l l a p s e s to L e t N^ regularly.
9N.
X n F r N = ^ a n d N n SM is
N r\ 9M i s a n ( m - l ) m a n i f o l d
X n 9M = X O 9N,
b e a d e r i v e d n e i g h b o r h o o d of
X in M .
Then
Now, t h e r e e x i s t s a p . 1. h o m e o m o r p h i s m
h | X = i d e n t i t y and h(N) = N ^ .
in
i s o t o p y of N^, fixed on X, t h r o w i n g there exists a p.l, homeomorphism s u c h t h a t h'(Nry 9M) = N^ H 9 M . X,
since
N^
h: N
meets > N^
9M
such that
M o r e o v e r , h(N H 9M) and N^ O 9M a r e b o t h
r e g u l a r n e i g h b o r h o o d s of X r j 9N^
N ^ X U (N PI 9M)
SN.
because
X n 9N = (X O F r N ) u ( X n N o 3M) = X O 9M a s o b v i o u s l y a n e i g h b o r h o o d of X A 9M in
9M.
Hence t h e r e e x i s t s an ambient h(NA9M)
h'
But
o n N^ O 9Mo
of N onto
N^ w i t h
In p a r t i c u l a r , h ' | X = identity,
N^ ^ X U (N^ n 9M) ^ X .
(h') ^ p r e s e r v e s c o l l a p s e s .
Hence
-73-
P r o o f of T h e o r e m Z.16.
We a r e going to show t h a t any r e g u l a r n e i g h b o r -
hood w h i c h m e e t s t h e b o u n d a r y r e g u l a r l y i s a m b i e n t i s o t o p i c to a d e r i v e d n e i g h borhood.
Since d e r i v e d n e i g h b o r h o o d s a r e ambient isotopic, this will prove 2 . 1 6 .
So l e t N b e a r e g u l a r n e i g h b o r h o o d of X i n M m e e t i n g Then N ^ X u
(9M A N ) ^ X .
Let
K b e a t r i a n g u l a . t i o n of
N a r e t r i a n g u l a t e d a s s u b c o m p l e x e s , K^ and L , s a y . \s . \s vss es L ^ K^ U ( L n K) \ K^ . L e t L = K^ ^ . . . ^ with K
= K u ( L n K), s o m e o
s
d e r i v e d of that
K.
Let
s ^ r.
K^ = K^ ^ + A + B,
U. = U. ^ U P 0 Q, w h e r e 1
Let
M such that
and
t h e s e two c o l l a p s e s , K" =
2nd
T h e n we h a v e seen. ( L e m m a 2 . 1 5 )
U^ S U^ ^ U P = U^
• L e m m a 2 . 1 6 to s h o w t h a t i n fact
We a r e going to u s e
U. i s a m b i e n t i s o t o p i c to
I
U
1
^O P
X
We m a y s u p p o s e t h a t
U. = N(K'! ; K " ) , w h e r e 1 1 r
A = aB.
regularly.
P = •st~(A;K"). Q = s t a r ( ^ ; K " ) , and that t h e r e
1-1
e x i s t s a p . 1. h o m e o m o r p h i s m
8M
is a m b i e n t isotopic to
P
and
1-1
U^ , k e e p i n g
X fixed.
T h i s w i l l c o m p l e t e the
"proof. Either and
A and
B a r e both in
Q b o t h do not m e e t
9M.
ad we h a v e s e e n ( p a g e ^^ ) t h a t
9M o r n e i t h e r i s in In t h i s c a s e ,
Motopies t h r o w i n g
U^ onto
U^ ^ U P
S u p p o s e on t h e o t h e r h a n d t h a t ftar{A;K") n K" = s t a r ( A j K " ) a face.
We s t i l l h a v e t h a t
F r U^ i s a face of Q.
Q.
In t h e l a t t e r c a s e ,
P nFr(U._^U
P r\ 9(U^ ^ 'J P )
n F r ( U . ) = Q n 9(U.) i s a face of
9M.
P) = P n
i s a face of P .
P),
Similarly,
H e n c e b y L e m m a 2. 16, t h e r e a r e a m b i e n t and
A and
U^ i
^
^i*
B a r e both in
a n d s i m i l a r l y for P a Fr(U. ^ O P)
so P
9M, and
is a face of P ,
Then Q each meets and
H e n c e in o r d e r to c o n c l u d e t h e p r o o f by a p p l y i n g
9M
L e m m a 2 . 1 6 , w e m u s t show t h a t (Q n 9M) r\ F r U . Now,
a r e f a c e s of
N O 8M =
( P H 9M) n F r ( U ^ ^ ^
P r\ a M a n d
Q ndM,
and respectively.
K" I i s a r e g u l a r n e i g h b o r h o o d of | K^ .
Moreover,
>es \
.es
. K^oK.
K"
(We a r e a s s u m i n j •
h e r e that
i < s.)
Clearly, we have that
N((K^A
K)").
•
U. O 8 M = N(K:' n K" ; K " O K" ) =
A l s o , we j u s t n o t e d t h a t
P O 8M = s t a r ( A ; K ") an<
A •
/
Q ry 9M = s t a r ( B ; K " ) . a p p l y in
H e n c e , t h e a r g u m e n t s of L e m m a 2 . 1 5 ( s e e p a g e ( 3 )i
SM to show t h a t
( P n BM) n 8[(U^ ^ U P ) n BM]
(Q r\ 8M) n 9(U. PI 9M) a r e f a c e s of
P r\ 9M a n d
9[(U. ^ U P ) o 9M] = [ F r ( U . ^ u P ) ] n 9M, Thus
P ri 9M A F r ( U ^
face of
^
P)
i s a face of
and
and
Q n 9M, r e s p e c t i v e l y .
Bu
9(U. H 8M) = ( F r U ^ D 9M.
P O 9M a n d
Q
8M n F r ( U p
is
Q o 9M.
C o r o l l a r y 2.16. 1 (Annulus P r o p e r t y ) :
Say
B^ ^ Int B^,
B^ a n d B^ p . l j
e
m-balls.
Then
cl(B
- B ) i s p . l . h o m e o m o r p h i c to
B X I
C o r o l l a r y 2. 16. 2. ( G e n e r a l i z e d A n n u l u s P r o p e r t y ) : r e g u l a r n e i g h b o r h o o d s of X in
M with
regularly, then there exists a p . l . h: cUN^ - N^) Proof.
K | = M, w i t h are
and
^ ^ ^ ^^ ^ ^
N^ a r e |
meets
9MS
homeomorphism > (^^M^l^ ^ ^ •
C l e a r l y , 2. 16. 2 i m p l i e s 2. 1 6 . 1 , s i n c e a b a l l i s a r e g u l a r neighboj
h o o d of a n y i n t e r i o r p o i n t .
[0,1]
If N^
= X.
0 and 1) w i t h
To p r o v e 2. 16. 2, l e t Let
K^ be a full s u b c o m p l e x of
K — ^ [O, l ] b e a s i m p l i c i a l m a p = K^.
Choose
(vertices
T h e n b y 2. H . j
-75I
-1
[ t h e r e e x i s t s a p . l . h o m e o m o r p h i s m h : N^—S> ff [0,t^], h j K ^ = identity. -1 -1 N o w , h(N^) a n d ^ [0, f ^ ] a r e r e g u l a r n e i g h b o r h o o d s of X i n ^ [which
m e e t t h e b o u n d a r y r e g u l a r l y (in fact, is a derived neighborhood).
[ambient isotopic", CI
t^] 1
Addendum 2. 16. 3. leeting
atopy of f; P r o o f .
P C M -
k(h(N^)) = f \ o ,
a
S FrN h-^k-^Xl
(N^ U N^)
be a p o l y h e d r o n .
M , fixed o n P U N ^ , t h r o w i n g 2. 1 7 . 2 i m p l i e s
So XI.
N^
Then t h e r e e x i s t s an ambient
onto
N^.
c l ( N ^ - N ^ ) S ( F r ^ ^ N ^ X I).
:e N^ ^ N^ ( L e m m a 2 . 1 ) .
Similarly,
N^
N^ b e a s e c o n d d e r i v e d n e i g h b o r h o o d of r e g u l a r n e i g h b o r h o o d s of 1.2.)
homeomorphism
m N ,N ,N b e r e g u l a r n e i g h b o r h o o d s of X in M J> ^ O S u p p o s e N and N a r e (topological) neighborhoods I t
Let
9M r e g u l a r l y . Let
BN^ r e g u l a r l y and
H e n c e t h e s e two n e i g h b o r h o o d s a r e
such that
£ ] ^
f
N^.
meets
in p a r t i c i a l a r , t h e r e e x i s t s a p . l .
e^] —>
:1{N,-N ) 6 1
N^
N^ U P
meeting
Hence
i s a r e g u l a r n e i g h b o r h o o d of P.
Then 9M
N^ U N ^
regularly.
Hence t h e r e e x i s t s an ambient isotopy throwing
N^, k e e p i n g
N^ U P
fixed.
cl(N^-N^)FrN^. N^.
a n d N ^ "J N^
(N. O N^ = ^ ,
N^ U N^
onto
S i n c e a p . l . h o m e o m o r p h i s m i s c o n t i n u o u s and
i'PS c o n n e c t e d c o m p o n e n t s o n t o c o n n e c t e d c o m p o n e n t s , it follows t h a t t h i s t isotopy throws
N^
onto N^.
-76 C h a p t e r III - - P . L . S p a c e s and Infinite C o m p l e x e s 1.
Introduction. C h a p t e r s I a n d II h a v e b e e n c o n f i n e d to t h e s t u d y of c o m p a c t p o l y h e d r a a
p . l . manifolds contained in given E u c l i d e a n s p a c e s .
As in Differential
w h e r e one c a n i n t r o d u c e a b s t r a c t m a n i f o l d s , one c a n define P . L ,
Topold|
s p a c e s and
manifolds without r e f e r e n c e to an a m b i e n t E u c l i d e a n s p a c e and without the h y p o t h e s e s of c o m p a c t n e s s .
In t h i s c h a p t e r we p r o p o s e t o s t u d y a b s t r a c t P . L |
s p a c e s a n d m a n i f o l d s a n d to i n d i c a t e how to e x t e n d t h e p r e c e d i n g r e s u l t s to sv objects. One c a n a l s o define t h e n o t i o n of'a l o c a l l y finite infinite c o m p l e x containec in a given E u c l i d e a n s p a c e (possibly E°°).
We w i l l s h o w t h a t t h e n o t i o n s of P .
s p a c e a n d infinite c o m p l e x a r e e s s e n t i a l l y e q u i v a l e n t .
In p a r t i c u l a r ,
compact|
P . L . s p a c e s a n d m a n i f o l d s a r e no m o r e g e n e r a l t h a n t h e finite p o l y h e d r a and; p . l . manifolds which we have been considering.
2.
T r i a n g u l a t i o n of P . L . S p a c e s and M a n i f o l d s . Definitio n,
Let
X be a topological space,
a topological embedding maps
(f, P )
A co-ordinate map
f: P —> X of a E u c l i d e a n p o l y h e d r o n
P.
(f, P ) iSj Two such -
a n d (g, Q) a r e c o m p a t i b l e p r o v i d e d t h a t if f(P) r\ g(Q) i ^
there|
-1
exists a coordinate map are
p.l. maps.
(h, R)
such that
Equivalently, we say that
-1
f
h(R) = g(Q) O f(P) (f, P )
and
f
h and g
a n d (g, Q) a r e c o m p a t i b l e
-1
(gQ) i s a s u b p o l y h e d r o n of
(Put h = g|f"^gQ),
assuming
Q and
g
f: f
f(P) (\ g(Q) = j^.
(gQ)
> Q is a p . l .
map.
-77-
Definition .
A P. L. structur e
^
o n X i s a f a m i l y of c o o r d i n a t e m a p s
such that 1) Any tv/o e l e m e n t s of
^
are compatible.
2) F o r a l l x e X, t h e r e e x i s t s n e i g h b o r h o o d of x in 3)
^
(f, P ) e ^
such that
f(P)
is a topological
X.
i s m a x i m a l , i . e . , if
(f, P )
i s c o m p a t i b l e w i t h e v e r y m a p of
^
,
then If X i s a Z^^ c o \ i n t a b l e H a u s d o r f f s p a c e , t h e p a i r P. L.
(X, ^
) is called a
space.
Definition .
A f a m i l y of c o o r d i n a t e m a p s
:alled a b a s e for a P . L . s t r u c t u r e o n Lemma 3.1.
Every base
^
space X i s c o n t a i n e d i n a u n i q u e Proof. is
.
Let
^
g(Q) i
such that
s a t i s f y i n g 1) and 2)
is
X.
for a P . L . s t r u c t u r e on t h e t o p o l o g i c a l P . L, structure
^
are compatible.
S' •
F o r if
(f, P )
w e m a y find a finite c o l l e c t i o n f(P) O g(Q) C
IV
ipatible w i t h e a c h
on X
= t h e s e t of a l l c o o r d i n a t e m a p s in X c o m p a t i b l e w i t h t h o s e
T h e e l e m e n t s of
and f{P) n i n a p s in
^
^
U
h.(B.). 1
h . , so if w e l e t
RJ = h . ' ^ f P
and
(g, Q)
are
(h^, B^), . . . , (h^, B^)
By d e f i n i t i o n
f and
g
are
1
and
R." = h J ^ g Q ,
R^ and P-^'
| 8 u b p o l y h e d r a of A B . . L e t^ R^'' =• RJ H _r !1' . >!< T h e n U h . R [ = f(P) O g(Q).- 1 S'efore, P ^ = f ' (gQ) = f" (Uh^R^ ) = Uf h^R^ i s a p o l y h e d r o n , and g f -1 * ^ P ^ b e c a u s e in e a c h p i e c e f h^R^ it a g r e e s w i t h t h e p. L m a p
is
-78-1
g
-1
h^h^
f w h i c h a l s o i s defined o n t h i s p i e c e .
J^
It i s c l e a r t h a t
satisfies!
2) and 3) i n t h e definition of a P . L , s p a c e and i s t h e u n i q u e s t r u c t u r e containing ^
.
L e m m a 3. 2. maps,
If
f: P —5> X a n d
g: Q —» X a r e two c o m p a t i b l e c o o r t
X a topological space, then there exists -1
with
h(R) = f(P) u g(Q) a n d w i t h Proof.
Let
|k| = P
and
b e s u b d i v i s i o n s of K
and o
> X, a coordinate
-1
f and h
g p.l.
maps.
| l | = Q be triangulations with -
subcomplexes, triangulating
h
h: R
f L
1 1 gQ and g such that
o
fP
respectively.
g'^f; °
K' — L ' o o
K^
and
L^,
Let
I K^
and
is simplicial.
L«
N K'
and
L'
b e e x t e n s i o n s of t h e s e s u b d i v i s i o n s .
which h a s one v e r t e x
j(v) for e a c h v e r t e x v of
for e a c h v e r t e x v of K ' , a n d no o t h e r s . i:K'
L ' - L^
L'.
be a simplex
and one v e r t e x
i{v|
i a l r e a d y g i v e n o n v e r t i c e s and'
j : L ' —> A defined b y p u t t i n g j(v) = i(f
e x t e n d i n g l i n e a r l y to a l l of Let
A C F
Consider the simplicial homeomo]
> A d e t e r m i n e d b y t h e d e f i n i t i o n for
homeomorphism
Let
g(v))
if v e L ^
( j i s a l r e a d y defined on v e r t i c e s of
L ' - L^
R be t h e u n i o n of t h e i m a g e s of t h e s e s i m p l i c i a l h o m e o m o r p h i s m s ,
a simplicial complex. h(x) a
Define
fi"^(x)
h(x) = g o j
h: R
> X b y defining
if X e I m a g e
(x) if X e I m a g e
i. j..
T h e d e f i n i t i o n s a g r e e on t h e o v e r l a p , s i n c e if x 6 ( i m i) n I m (j) g o j " ^ ( x ) = g g " ^ f i ' ^ ( x ) = f i " ^ ( x ) . It i s not h a r d to s e e t h a t h : R —5> X i s a hoi -1
m o r p h i s m with image
f(P) o g(Q) , a n d t h a t
h
-1
f and h
g a r e p. 1. m a p s .
-79-
Corollary 3.3. there exists Proof.
If
(X, ^
(h, R) e ^ Let
) i s a P . L. space and C C X
with
then
C C Int h ( R ) .
(h^, R^), . . , , (h^, R^)
There exists a coordinate map with h c o m p a t i b l e w i t h e a c h
is c o m p a c t ,
be in
with
h ; R—5> X w i t h h.
(i.e., h
C C Int(h^(R^) U . . . U h^(R^)),
h(R) = h ^ ( R ^ ) u . . . ^ h ^ ( R ^ ) ,
h . : R.
>R
a r g u i n g a s in L e m m a 3 . 1 , it i s n o t h a r d to s h o w t h a t
i s p. 1. , a l l
i).
and
By-
h is compatible with e v e r y
element of ^ and so i n ^ . Definition . The P . L. space :for a l l x e X t h e r e e x i s t s Lemma 3.4. |then there exists
If
(X, ^
(h, R) e ^
(X, ^
) i s c a l l e d a P . L . m - m a n i f o l d if
h: a " ^ —> X w i t h
{h, A™) c ^
and x e I n t ^ h(A"^),
) i s a P . L . m - m a n i f o l d and C C X i s c o m p a c t , with
d) R i s a p . 1. m - m a n i f o l d , 2)
CClnt^h(R).
Proof, "
By L e m m a 3. 2, c h o o s e
p ) C Int g(Q).
Let
(f, P ) a n d
K^ b e a full s u b c o m p l e x of
et N b e t h e s e c o n d d e r i v e d n e i g h b o r h o o d of •manifold, for t h o u g h
|K|
of of L e m m a 2. 13).
in K.
with
= Q,
K^
Then
w h i c h i s a p. 1. m - b a l l .
i l s p h e r e o r b a l l for a l l v e K ^ , a n d A meeting
K^
K, | K
^
K n e e d n o t be a c o m b i n a t o r i a l m a n i f o l d ,
h a s a n e i g h b o r h o o d in
Splices
(g, Q) i n
K^.
C C Int f(P), = g
-1
fP.
N i s an e v e r y point
So l i n k ( v , K) = a n
link(A, K) is a s p h e r e o r b a l l for a l l
So t h e p r o o f t h a t
N i s a manifold g o e s t h r o u g h
(see
g | N —3> X i s t h e r e q u i r e d c o o r d i n a t e m a p of t h i s l e m m a .
-801
Note;
S t r i c t l y s p e a k i n g , t h e l a s t two l e m m a s h a v e b e e n u s i n g t h e fact t h a t
if in t h e P . L . s p a c e
(X, ^ ),
(h, P )
is a coordinate m a p such that
b e c o v e r e d by t h e i m a g e s of a finite n u m b e r of m a p s in ^ compatible, then
(h, P ) e ^
.
h(P)
with which h isj
T h e p r o o f i s left to t h e r e a d e r
(see Lemma
T h e n e x t l e m m a m a y be v i e w e d a s a f f i r m i n g t h e p o s s i b i l i t y of " t r i a n g u l a P . L , s p a c e s and m a n i f o l d s ,
a s we s h a l l s e e following t h e i n t r o d u c t i o n of loca
finite (infinite) c o m p l e x e s . Lemma 3.5.
Let
(X,
be a P . L . s p a c e .
s e t of s i m p l i c i a l c o m p l e x e s a n d s u b c o m p l e x e s , f. :
J,
—> X
T h e n t h e r e e x i s t s a count
K^
J^ , L^ C J^ a n d embedc
such that
1) x = U f.(|jJ). i=l 2) £ . ( | J j ) n y | J j . l ) = ^ if
4) f.
, f.:
1+1 1
If
L.
> K.. .
1
| i - k | a 2.
is a simplicial homeomorphism,
1+1
(X,
is a P . L . m - m a n i f o l d , w e c a n t a k e J , to b e a c o m b i n a t o r i £ m - m a n i f o l d and K. and L . to be c o m b i n a t o r i a l ( m - l ) m a n i f o l d s in 9 J . . 1 1 1 Proof. X is l o c a l l y c o m p a c t a n d oo Let X = C. , C. c o m p a c t . L e t i =l (h., R p 6 J
, i ^ 2,
such that
-1
( F r h.R.). 1 1
Let
e J" .
C.C
P . = c l ( R . - h." h. , R . ) , a p o l y h e d r o n . 1 1 1-1 1 ^ ' S. = h . 1 1
countable.
f. = h. P . . 1 1 1
Hence
Define i n d u c t i v e l y
C Int h.(R^). Let Let
X i s (r-compai
Let
-1. Q. = h. F r „ (h. , R . , ) , 1 1 X 1-1 1-1
K.,L. J , b e t r i a n g u l a t i o n s of 1 1 1
-81-
Q.S., 1
P, . 1
F o r e a c h i, let
LI a n d K1. . b e s u b d i v i s i o n s s u c h t h a t 1 1+1
i " ^ f.: LI > KI, ^ i s s i m p l i c i a L S i n c e K. O L . = t h i s defines a subi+1 1 1 1+1 1 1 d i v i s i o n of K^ U L^ w h i c h w e e x t e n d t o a s u b d i v i s i o n JI^ of J . T h e n J ' KI, LI a n d f. s a t i s f y t h e f i r s t p a r t of t h e l e m m a , i' 1 1 1 T h e p r o o f of t h e s e c o n d p a r t of t h e l e m m a i s s i m i l a r , u s i n g L e m m a 3 . 4 i n s t e a d of L e m m a 3. 2.
T h e d e t a i l s a r e left t o t h e r e a d e r .
To mcike t h e n o t i o n of a t r i a n g u l a t i o n of a P . L . s p a c e m o r e p r e c i s e , we i n t r o d u c e infinite c o m p l e x e s . (x . . . . . X ) w i t h * 1' ' n
(x., . . . , X ,0). 1 n
convex h u l l of a s u b s e t ; s e t of E ^ i
.
Let
fas aU ( o o ) - t u p l e s
F i r s t of a l l , w e v i e w E ^ C E ^ ^ ^
Note that u n d e r t h e s e identifications,
S of e " i s t h e s a m e a s i t s c o n v e x h u l l v i e w e d a s a s u b co = E^ , w i t h t h e w e a k t o p o l o g y . E ° ° m a y be v i e w e d i=l
E°°
m a y b e v i e w e d a s t h e t o p o l o g y of p o i n t w i s e c o n v e r g e n c e .
I The c o n v e x h u l l of a n y s u b s e t of
i s defined in t h e o b v i o u s w a y .
w e d e n o t e t h e c o n v e x h u l l of t h e p o i n t s
[(0,0,1,0,...), Definition .
the
(x^, . . . , x ^ , . . . ) w i t h a l l b u t a finite n u m b e r of x^ b e i n g z e r o ,
^and t h e t o p o l o g y of
ay
b y identifying
( 1 , 0 , . . . ),
In p a r t i c u l a r ,
(0,1,0,...),
etc. A l o c a l l y finite s i m p l i c i a l c o m p l e x
K in E°°
i s a c o l l e c t i o n of
|finite) s i m p l i c e s , K, s u c h t h a t 1) (r,T € K = > 2)
0-
€ K,
T < 0- = >
T
€ K.
3) F o r a l l X € | k | , t h e r e e x i s t s a n e i g h b o r h o o d l y f i n i t e l y m a n y s i m p l i c e s of K . K l i e s in s o m e
E^.)
u
of x in
meeting
( E x e r c i s e : P r o v e t h a t e v e r y finite subcompley:
Let
(X.
b e a P . Li. s p a c e .
U s i n g L e m m a 3. 5, a n d t h e t e c h n i q u e of
L e m m a 3 . 2 one c a n c o n s t r u c t an infinite l o c a l l y finite c o m p l e x
K
v e r t i c e s a r e v e r t i c e s of
> X of
and a h o m e o m o r p h i s m
h: | k |
whose |K| I
onto X s u c h t h a t t h e r e s t r i c t i o n s of h to finite s u b c o m p l e x e s a r e e l e m e n t s of ^ K
.
M o r e o v e r , if
is also;
c o n t a i n e d in
(X,
) i s a P . L . m - m a n i f o l d , t h e n we m a y i n s i s t tha
t h a t i s , e v e r y p o i n t of | K| .
K|
l i e s in t h e i n t e r i o r of a p . l . m-be
In t h e c a s e t h a t t h e r e i s a bound
on t h e d i m e n s i o n s of the
N s i m p l e x e s of L e m m a 3. 5, one c a n t a k e the complex
K CE
for s o m e finite
N.
In t h i s
K i s c o n s t r u c t e d w i t h i n a s u i t a b l e E u c l i d e a n s p a c e b y " b a r e han2
u s i n g t h e i n s t r u c t i o n s p r o v i d e d by L e m m a 3. 5. Definition .
The p a i r
(K,h)
l o c a l l y finite c o m p l e x ajid h : | K |
D e t a i l s a r e left to t h e r e a d e :
i s c a l l e d a t r i a n g u l a t i o n of
if
K is
> X i s a h o m e o m o r p h i s m s u c h t h a t the
r e s t r i c t i o n s of h to finite s u b c o m p l e x e s a r e e l e m e n t s of ^
.
-83-
3.
P . L). M a p s a n d S u b i d i v i s i o n T h e o r e m s Definition .
IS
Let
(X, ^
) and
c a l l e d a P . L . m a p if for a l l
(Y,
be P . L . s p a c e s .
(f, P ) e ^
e i t h e r e m p t y o r a s u b p o l y h e d r o n of
T h e n jZ(t X —» Y
and all
P , a n d if t h e l a t t e r ,
^ o f : f^f'^gQ
f'^^'^gQ
is
then
> Q
is, a p . 1. m a p . Notes;
l)
It i s e a s y to c h e c k t h a t a P . L . m a p i s c o n t i n u o u s .
2) B y a n a r g u m e n t s i m i l a r t o t h a t of L e m m a 3 . 1 , to s h o w t h a t a g i v e n m a p j i i s a P . L . m a p , it suffices t o c h e c k t h e c o n d i t i o n in the d e f i n i t i o n for e l e m e n t s (f, P ) of a b a s e of ^ Definition .
and e l e m e n t s
If ^ | K |
>
(g, Q) of a b a s e of h . ^
^
l o c a l l y finite s i m p l i c i a l c o m p l e x e s ,
/e s a y ^ i s P . L . if it m a p s e a c h finite s u b c o m p l e x p i e c e w i s e l i n e a r l y into a finite s u b c o m p l e x of Umark. id (X, ^
L,
T h e two d e f i n i t i o n s of P . L . m a p a r e c o n s i s t e n t . ) a r e P . L . s p a c e s a n d if
and Y r e s p e c t i v e l y , a n d if 0 and ttommutes
(X,:?)
(K, h) a n d ( L j j ) a r e t r i a n g u l a t i o n s of i^i a r e m a p s s u c h t h a t t h e following d i a g r a m
: X h IK
T h a t i s , if
A
L
0 i s a P . L . m a p if and o n l y if ijj i s a P . L . m a p .
Definition .
A map
f; X —> Y of t o p o l o g i c a l s p a c e s i s said, to b e a prop]
m a p if t h e i n v e r s e i m a g e s of c o m p a c t s e t s in Y a r e c o m p a c t . Definition .
A subdivision
K'
of a l o c a l l y finite c o m p l e x
K i s a loccdlyl
finite s i m p l i c i a l c o m p l e x s u c h t h a t K' 1) IK 2) E v e r y s i m p l e x of
K i s c o n t a i n e d in a s i m p l e x of
U s i n g L e m m a 1. 2 a n d l o c a l f i n i t e n e s s , of K i s a u n i o n of f i n i t e l y m a n y s i m p l i c e s of d i v i s i o n of K, t h e n K' s u b c o m p l e x of
K'.
M o r e o v e r , if
K'
i s a sub|
i n d u c e s a s u b d i v i s i o n ( i n t h e finite s e n s e ) of e v e r y
A.
If S i s a l o c a l l y finite f a m i l y of p o l y h e d r a
then there exists a subdivision
B.
i t i s e a s y t o s e e t h a t e v e r y simpt
K.
Theorem 3.6.
e a c h e l e m e n t of
K'.
K'
of
in
|K
K c o n t a i n i n g (finite) t r i a n g u l a t i o n s of
S.
If f: K —5> L i s a P . L . m a p of l o c a l l y finite c o m p l e x e s , t h e n t h e r e
exists a subdivision
K'
of K s u c h t h a t
h K' —> L
maps simplices linearl
into s i m p l i c e s . C. L'
If f: K — j > L
w i t h f; K' Proof .
A)
i s p r o p e r P . L . m a p , t h e n t h e r e e x i s t . s u b d i v i s i o n s K'j
> L'
simplicial.
Write
oo K = IJ i=l
'
s u b c o m p l e x e s , K. n K^ = ^ if
i-j| ^ 2 .
F o r e x a m p l e , if K i s c o n n e c t e d , l e t
and define
R^ = c l o s e d s i m p l i c i a l n e i g h b o r h o o d s of
R^ R^
b e a finite subcomplea for e a c h i .
Let
-85-
K = R . - R. . . i 1 1-1 to a v e r t e x of Each
The
R^
R. c o v e r 1
K b e c a u s e a n y v e r t e x of
K can be connected
b y a finite e d g e p a t h .
K j m e e t s f i n i t e l y o n l y f i n i t e l y m a n y p o l y h e d r a i n S.
induction subdividing
P r o c e e d by
K^ to c o n t a i n s u b d i v i s i o n s of i t s i n t e r s e c t i o n s w i t h m e m -
b e r s of S a n d w i t h t h e p r e c e d i n g s u b d i v i s i o n of K^
Then since
K^ i s not
changed after the ( i + l ) s t s t e p is o v e r , it is c l e a r that this defines the r e q u i r e d s u b d i v i s i o n of B), of K.
K,
S* = {(T n Let
K'
f"^(T)| or 6 K, T € L.}
b e a s u b d i v i s i o n of
i s a l o c a l l y finite s e t of p o l y h e d r a
K c o n t a i n i n g s u b d i v i s i o n s of t h e e l e m e n t s
of S. C), roper,
We m a y a s s u m e b y B t h a t { f(r | c 6 K}
f i s linea:r
n s i m p l i c e s of K.
i s a l o c a l l y finite f a m i l y of p o l y h e d r a in
Lve t h e s e p o l y h e d r a a s s u b c o m p l e x e s . ically finite c e l l s u b d i v i s i o n of
K.
Then
{(TAf
- 1
T|(r€K,
Let »
t € L'>
is L'
is a
A s i n t h e finite c a s e t h i s c e l l s u b d i v i s i o n
.8 a l o c a l l y finite s i m p l i c i a l s u b d i v i s i o n w i t h n o e x t r a v e r t i c e s .
[arning ;
|L| .
As f
C) i s f a l s e f o r n o n - p r o p e r m a p s .
le r e a l l i n e w i t h v e r t i c e s at t h e i n t e g e r s .
F o r example,
l o c a l l y finite s u b d i v i s i o n s to m a k e
f
triangulate
T h e r e is a P L m a p
ipping R h o m e o m o r p h i c a l l y o n t o t h e o p e n i n t e r v a l (O, 1). simplicial.
(See L e m m a 1 . 4 ) .
f: R — ^ [ 0 , 1 ]
It is i m p o s s i b l e t--
4.
P . L.
Subspaces
Definition .
Let
(X,
P . L . space with X C X. o — (X, ^ ) p r o v i d e d l ) X^
If
X,
(X^,
be a n o t h e r
(X , ^ ) i s c a l l e d a P . L . s u b s p a c e of o o
i(x) = X , i s a P . L . m a p .
(X , % ) i s a P . L . s u b s p a c e , t h e n
•
O
Examples;
Then
Let
h a s t h e r e l a t i v e t o p o l o g y i n d u c e d by X, a n d
2) i ; X Remark,
) be a P . L . space.
^
o
1) If
= { ( f , P ) e ^ | f(P)
^
<>0 C X i s o p e n a n d if
^ ^ = {(f,P) e S
vi I f(P) ^
the
(X , ^ ) is a P . L . s u b s p a c e of (X. 5 - ) . 2) E ^ h a s the n a t u r a l P . L . s t r u c t u r e g e n e r a t e d b y t h e i n c l u s i o n m a p s p o l y h e d r a in e'^.
A compact subspace
(with its n a t u r a l s t r u c t u r e ) .
F o r suppose
Then t h e r e is a coordinate m a p But X^
X^ of
(f, P )
E n" m u s t be a p o l y h e d r o n in C E^
i n t h e s t r u c t u r e of X ^ w i t h f(P) = Xj
i s a P . L . s u b s p a c e , so t h e c o m p o s i t i o n
Therefore
X^ = f(P)
3) In E'^,
4) If
d(x, X ) < 1} i s a P . L . o { x | d ( x , x^) < 1} i s n o t .
Lemma 3.7. —————
a r e p o l y h e d r a in E ^ , If
P — X ^ C E^
( X , % ) N O ^ ^O O
subspace,
^ -
i s a P . L . s u b s p a c e of
i s a P . L . s u b s p a c e of (X,
of X
.
K^ of K s u c h t h a t
E
and if X
i O
c l o s e d s u b s e t of X , t h e n t h e r e e x i s t s a l o c a l l y finite t r i a n g u l a t i o n and a s u b c o m p l e x
is a P . L.|
n is a p o l y h e d r o n in E .
{X
P^C P
i s a c o m p a c t P . L . subsr
h
K^
| K ^
X
o
h: K
is a triangul:
-87-
Proof . let k:
M
Let
h:
» X^
X
L
> X be a l o c a l l y finite t r i a n g u l a t i o n of X .
b e a l o c a l l y finite t r i a n g u l a t i o n of X ^ .
> X t h e i n c l u s i o n m a p . L e t M' and o r e s p e c t i v e l y , making the p r o p e r P . L. m a p
jet K
o
=
Image
Let
0 = h
K b e s u b d i v i s i o n s of (X
is closed)
fi
M
Then i
k.
and
simplicial.
-al
5.
Collapsing and Regular Neighborhood T h e o r y . Definitio n.
t h e n we s a y
If X^
X ^ X^
is a c l o s e d P . L . s u b s p a c e of t h e connpact P . L . s j
if t h e r e e x i s t s a finite s e q u e n c e of
X C X C . . . C X = X o 1 ~ — r isap.l.
(P. L. ) ball having
Definition .
If
l i n k ( h " ^ x ; K) i s a b a l l . Definition .
cl(X^-X.
Let
N ^ X
as a face. h; | K |
> M be a triang
We s a y x e 9M if
T h i s d o e s not d e p e n d u p o n the c h o i c e of
X^
(h, K).
b e a c o m p a c t P . L . s u b s p a c e of t h e P . L . m a n i f o l N of X i s a t o p o l o g i c a l n e i g h b o r h o o d
N, co
and N i s a n m - d i m e n s i o n a l P . L . s u b m a n i f o l d (i. e . ,
s p a c e w h i c h i s a m a n i f o l d ) of
X.
N m e e t s t h e b o u n d a r y r e g u l a r l y if
o r i s a r e g u l a r n e i g h b o r h o o d of X n 9M in T h e o r e m 3. 8 . M.
let
M (h i n t h e s t r u c t u r e ) .
Then a regular neighborhood such that
s u c h t h a t X. - X. ^ = c l ( X . - X. J 1 1-1 1 1-1
M is a P . L. manifold,
of a n e i g h b o r h o o d of x i n
P . L . s u b s p a c e s of
Let
as
N O6
9M.
X^ b e a c o m p a c t P . L . s u b s p a c e of t h e P . L . m - m ,
T h e n a r e g u l a r n e i g h b o r h o o d of X^ w h i c h m e e t s t h e b o u n d a r y r e g u l a r l y
exists.
If N
and N jL
a r e a n y two r e g u l a r n e i g h b o r h o o d s of X , t h e n t h e r e i ^
a P . L . h o m e o m o r p h i s m of N^
onto
N^ p o i n t w i s e fixed on X^ .
If
N^ ani
m e e t the bo\andary r e g u l a r l y , t h e n t h e r e e x i s t s a n a m b i e n t i s o t o p y H: M X I
>MXI
throwing
X fixed. X ^ O Proof . L e t (f, K) be an e l e m e n t of t h e P . L . s t r u c t u r e ^ of X s u c h ' X C int^^ f(K) and K i s a p . l . m - m a n i f o l d . Let N be the i m a g e u n d e r i O M a r e g u l a r n e i g h b o r h o o d of f
onto N
(X^) in
K.
and l e a v i n g
-89T h e i m i q u e n e s s t h e o r e m s follow s i m i l a r l y b y tciking N^ U N^ Q One c a n a l s o define r e g v i l a r n e i g h b o r h o o d s of n o n - c o m p a c t s u b s p a c e s of a P. L . manifold.
If X a n d X
are closed P. L. spaces, o
X
a s u b s p a c e of
we s a y X^ c o l l a p s e s t o X b y aji e l e m e n t a r y g e n e r a l i z e d c o l l a p s e if i s t h e \inion of a d i s j o i n t l o c a l l y finite f a m i l y of w h e r e , for e a c h i , B^ i s a p . 1. b a l l h a v i n g
P. L. subspaces
B^nX^
as a face.
if X c o l l a p s e s t o
cl(X-X^)
B^ of
X,
A generalized
c o l l a p s e i s a finite s e q u e n c e of e l e m e n t a r y g e n e r a l i z e d c o l l a p s e s . ^ X ^ X^
X,
o
We w r i t e
X^ b y a n e l e m e n t a r y g e n e r a l i z e d c o l l a p s e .
A g e n e r a l i z e d r e g u l a r n e i g h b o r h o o d of X ^
in t h e P . L . m - m a n i f o l d
M,
a closed P . L . subspace, is a closed topological neighborhood.which is an o i-submanifold and which c o l l a p s e s to
X by a n e l e m e n t a r y g e n e r a l i z e d c o l l a p s e .
T h i s d e f i n i t i o n g i v e s r i s e to t h e a n a l o g o u s e x i s t e n c e and u n i q u e n e s s 2orems a s for t h e c o m p a c e c a s e .
However, these generalized regular neigh-
Jorhoods h a v e h a d no i m p o r t a n c e so f a r .
C h a p t e r IV - G e n e r a l P o s i t i o n § 1.
Definitions Let
Then
K and
L b e P . L . s u b s p a c e s of t h e P . L . m a n i f o l d
K and L a r e in g e n e r a l p o s i t i o n ( o r
d i m (K n L) < d i m K + d i m L, - q .
Q, q = d i m Qj
K is in g e n . p o s . w . r . t . L) if .
(Note the s i m i l a r i t y b e t w e e n t h i s conditi
a n d t h e c o n d i t i o n in d i m e n s i o n s t h a t is n e c e s s a r y and sufficient for two subs p a c e s of a finite d i m e n s i o n a l v e c t o r s p a c e to s p a n t h a t s p a c e . ) -1 If f: P —?> Q is a m a p , a n d S (f) = S^(f) .
If
x e P| f
f(x)
h a s at l e a s t r - p o i n t a
P & Q a r e P . L . s p a c e s a n d f i s a P . L , m a p , then
follows f r o m t h e fact t h a t S'(f)
S'(f) =
P a n d Q m a y be t r i a n g u l a t e d to m a k e
i s a P . L . s u b s p a c e of
P.
If
f is p r o p e r , t h e n S^(f)
f linear t
i s a c l o s e d P„
s u b s p a c e , and d i m S^(f) = d i m S^(f). If f: P —> Q i s a m a p , P & Q P . L . s p a c e s of d i m e n s i o n p and q r e s p e c t i v e l y , we s a y t h a t
f i s in g e n e r a l p o s i t i o n p r o v i d e d
1) f is P . L . and p r o p e r . 2) for a l l
r,
(f) = 0
3) S
d i m S^(f) (i.e.
<
rp/(r-l)q
f is n o n - d e g e n e r a t e ) .
oo Let £ : P
>
f and ^^
t h e t o p o l o g y of
g be two m a p s
P — > Q,
P and Q P . L . s p a c e s .
be a p o s i t i v e , c o n t i n u o u s f u n c t i o n . Q,
t o ^ ) provided that
T h e n we s a y V x e P,
If f and g a r e m a p s ,
f
Let ^
b e a m e t r i c for
f i s an £ - a p p r o x i m a t i o n to ^
( f(x), g(x)) <
g (with r e s p
£(x).
f ( r e l K) m e a n s t h a t
a h o m o t o p y w h i c h i s t h e c o n s t a n t h o m o t o p y on
Let
K.
f i s h o m o t o p i c to
f
-91-
§2.
A p p r o x i m a t i o n of C o n t i n u o u s F u n c t i o n s by P . L .
L e m m a 4. 1. Let f: P — b e |p n P = ^ . 1 2
Let
s u b p o l y h e d r a of t h e p o l y h e d r o n P .
a continuous m a p , with
G i v e n £ > 0, t h e r e e x i s t s
1) f I P ^
is an
Proof. Implies > P 1
Let
p b e a m e t r i c for S/Z.
Let
C P, s u c h t h a t
K
B
Assume
w i t h t h e following p r o p e r t i e s :
f (w. r . t t h e u s u a l m e t r i c on I n . ) P
and choose
i s full in K,
5 > 0 such that
p(x, y) < 5
b e s i m p l i c i a l t r i a n g u l a t i o n s of r r e s h (K) < 5, a n d f|K
is linear.
^
f;
Chen f'|or„
-a any s i m p l e x of
| K | —>
o n v e r t i c e s of
b y f i r s t p u t t i n g f'(v) = f(v)
c.
If
'Ut f'l 0-= f I (T. F i n a l l y if e K , , cr^n K J = d, a s 1 Z 1' learly the m a p f
P—>
K^.K^.K^CK
iow define
f
f;
"^^P*
P3 .
6 - a p p r o x i m a t i o n to
d(fx, f y ) < P
^
i s a p. 1. m a p
2) fl P ^ ^ P 3 = f ' | P 3 ^ 3) f
Maps.
f
instruction, ggiark.
f
K^, b e defined by e x t e n d i n g l i n e a r l y t h e definition
o" r\ | K^ ( = 0 , h o w e v e r ,
a l r e a d y g i v e n on
K, is l i n e a r . 1 i s an
Since
for e v e r y v e r t e x v e K.
Vcr € K,
(i. e. , cr h a s no f a c e s in K^ ,
cr n | K^ | ^ jZ(, w e m a y put
T h e n we define o"^ and cr^.
f
-
cr by e x t e n d i n g
C l e a r l y , f ' j K ^ u K^ =
d i a m fa < 6 / 2
a n d d i a m f'cr < £ / Z
bv
< S - a p p r o x i m a t i o n to f.
f i s h o m o t o p i c to
f
( r e l P^,
P^)
by t h e h o m o t o p y
U) = tf(x) + ( l - t ) f ' ( x ) . T h e n d ( H J x ) , H (x)) < £ , a l l x e l " , a l l s , t e I. In 'j t s w o r d s , we c a n c h o o s e t h e h o m o t o p y H of f and f to a " a r b i t r a r i l y
L e m m a 4. 2.
Let
f: P —> Q be a c o n t i n u o u s m a p of t h e P . L, s p a c j
P
into t h e P . L. g - m a n i f o l d
of
P
on w h i c h
Q.
Then t h e r e exists
1) f ^ f ( r e l P ) , o 2) P (fx, f x ) < i5(x) a l l X / t o p o l o g y of Q),
Q C
stars.)
Q. P
f;
( p /
be a c l o s e d P , L .
Let
£ : P —> R
subspace
be a continuol
P—5> Q s u c h t h a t
s o m e g i v e n d i s t a n c e function for the
is a P . L. m a p .
Proof. with
P
f is a l r e a d y a P . L . m a p .
p o s i t i v e function.
3) f
Let
Let
{B^] be a l o c a l l y finite c o u n t a b l e f a m i l y of q - b a l l s in Q
I J Int B. . X U 1 Let
(For example, triangulate
Q and t a k e c l o s e d vert
Q. K be ( l o c a l l y finite) s i m p l i c i a l c o m p l e x e s t r i a n g u l a t i n g
P ^ ^ P , s u c h t h a t if
cr € K,
fcr C I n t ^ B^, s o m e j.
This is possible becau
t h e r e i s a U r i a n g u l a t i o n L of P , c o n t a i n i n g a t r i a n g u l a t i o n of P , s u c h tha oo L = 1 I L. , L. finite s u b c o m p l e x e s s u c h t h a t L . O L . = 0 if l i - i >2. iVi 1 1 1 J ' S u b d i v i d e e a c h L. to set 1 ®
LI s u c h t h a t 1
(T e L; i m p l i e s 1
T h e n f u r t h e r s u b d i v i d e ( p r o c e e d i n d u c t i v e l y ) to g e t L ' l and Let
a r e compatible; aJ
i = 1
s i m p l e x follows i t s f a c e s . then the 1 - s i m p l i c e s and
L'^
fer C Int B., s o m e j — J such that
for all i
t h i s g i v e s t h e r e q u i r e d s u b d i v i s i o n , K,
ooj- be t h e s i m p l i c e s of (For example:
of
K - K ^ , o r d e r e d so t h a t a
f i r s t t a k e t h e v e r t i c e s of L ^ -
L " - K and t h e v e r t i c e s of ( L " - L " ) - K , then o o ' o' o t h e 2 - s i m p l i c e s of L " -K , t h e 1 - s i m p l i c e s of ( L ' ' - L " ) - K and t h e z e r o o o l o o s i m p l i c e s of (L» - L " ) - K , e t c . . . . ) P u t K. = K u J A. . We a r e Z 1 o 1 o , j j= 1
-93-
to define i n d u c t i v e l y m a p s 1)
f.
2)
K.
f.: K —> Q
i s P . L.
f. f (rel P ) 1 o if cr € K, f^((r) c I n t ^ B^ , s o m e
3) 4) ^
(f.(x).f._^(x))
We s t a r t w i t h f iome j .
Let
K'
= f.
, all Suppose ^^
f. . i s defined. 1-1
b e a P . L. h o m e o m o r p h i s m .
N(AI;K'), R = R n K
U p . L . on R^ . R^ i s P . L . . x e R.
X .
T h e n f. ^(A.) C I n t ^ B., 1-1 1 Q J
b e a s u b d i v i s i o n of K s u c h t h a t N(A! j K') C f^ ^ ( I n t ^ B^).
.et h: B. —»
L= Fr
o
<
j.
H e n c e for e v e r y
. £>0
Then
Define
f.: K 1
Q
R = N(A! ;K'), R^ = A^ ,
R
R, = jZ! and
ther- exists
a l R ^ ^ R^ = h o ( f . _ j R 2 ' ^ R 3 ) .
f?
Put
and
a:R—>
h»(f.
|
R)
such that
p(a(x), h® f . )
<6
,
by f. R = h ' ^ a 1
T \ C1(|K|-R) = f . _ ^ I c l ( | K | - R ) . Now R i s c o m p a c t , so by c h o o s i n g
£ s m a l l enough we c a n e n s u r e that
L(x)-f^ ^(x)) < £ (x)/2^ for a l l XT | K | , and a l s o t h a t e v e r y .Bome I n t ^ B . . U J 4).
f^(o-) i s c o n t a i n e d
T h e n f. i s a w e l l - d e f i n e d m a p w h i c h c l e a r l y s a t i s f i e s 1), 3), 1
M o r e o v e r , f r o m the r e m a r k following l i e m m a 4. 1, w e s e e t h a t
— f.
. |R
(rel. R ^ R
^see t h a t 3) h o l d s .
) and s o , e x t e n d i n g the h o m o t o p y by the identity,
Call this homotopy
H^.
S y c o n s t r u c t i o n , f^ a g r e e s w i t h f^ ^ e x c e p t on a s i m p l i c i a l n e i g h b c r h r -c^ .
If cr € K,
0" m e e t s o n l y finitely m a n y of the R^,
T h e r e f o r e the f.
e v e n t u a l l y a g r e e on | K | —> Q. given
cr.
H e n c e putting
f -
Similarly, the homotopies
0" € K and so H = l i m
^
i s a w e l l defined c o n t i n u o u s ^
1 oo f ^ P (rel
a n d so
defines a P . L . m a p
H^ a r e e v e n t u a l l y the i d e n t i t y on
H. o . . . » H ,
•
K| X I — > Q ,
lim f. i —5> oo
K
). o
Remark.
U s i n g t h e r e m a r k following 4. 1, t h e r e a d e r c a n e a s i l y s h o w that
u n d e r t h e h y p o t h e s e s of 4. Z, we c a n find a h o m o t o p y such that x e P
§ 3.
f = H^
and
every
H of f, fixed on
s a t i s f i e s t h e c o n c l u s i o n s of 6. 2 a n d in a d d i t i o n , for e v e r i s,t
in[0,l],
d(H x, H x) < s t
£(x).
ApproxirngiLion of P . L . m a p s by N o n - D e g e n e r a t e P . L . Definition .
If X
E^
fi P — >
Let
f:
l)
f'jPj^
3)
f(P-P^)c!n
f2X be t h e unio
s p a n n e d by s u b s e t s of X . E ^ - i^X is d e n s e in
f2X i s a c l o s
E^.
P^^ and P ^ Q P be p o l y h e d r a , d i m P < n.
be a p. 1, m a p w i t h f j P ^ ^ P ^
e x i s t s a p. 1. m a p
P —> I^
non-degenerate.
Let
G i v e n £> 0 th
s u c h that
is n o n - d e g e n e r a t e
4) for a l l X 6 P , Note;
E^
of m e a s u r e z e r o , so
L e m m a 4. 3.
Maps.
is a finite s e t of p o i n t s in e " , l e t
a l l p r o p e r affine s u b s p a c e s of s u b s e t of
P
( f x , fx) < £
In g e n e r a l we c a n n o t shift
f to be n o n - d e g e n e r a t e on
c h a n g i n g it on P , if it is not a l r e a d y n o n - d e g e n e r a t e on P ^
example,
-95-
j l e t P 2 = 1 - f a c e of a 2 - s i m p l e x P , P^ = P , a n d s u p p o s e P r o o f of L e m m a 4. 3. (so t h a t
f:K—>
is linear.
land t h a t v , . . . ,v I VT i s = f(v.). |f(vp,
For
Let Let
be t h e v e r t i c e s of K^ n
r < i ^ s we m a y choose points jw^ , . . . , w. J
w^,
^ensure t h a t
f
For
i < r
If w e define i
4).
put
f ' : K —>
s, and f'(v) = f(v)
v , t h e n b y c h o o s i n g e a c h w^ c l o s e enough to
satisfies
K^
w^ a r b i t r a r i l y c l o s e to
, and w. e I^.
fto be t h e u n i q u e l i n e a r m a p s u c h t h a t f ' ( v p = w^, 1 lall o t h e r v e r t i c e s
is a p o i n t .
K^ , K^ C K b e t r i a n g u l a t i o n s of P^ . P ^ ^ P
be t h e v e r t i c e s of K - K K . 1 x 2 ,
such that w. /
flP^)
It c l e a r l y s a t i s f i e s 2) and 3).
for
f(vp, we m a y
To s h o w t h a t s u c h
,an f i s n o n - d e g e n e r a t e o n K^ , it suffices to s h o w t h a t i t s r e s t r i c t i o n t o e a c h cr e K [is.
T h i s w e p r o v e b y i n d u c t i o n on d i m cr.
Ls nothing t o p r o v e .
If
cr / K H K
y induction, f ' | v .
...v.
put
If
0 e K^O K^, f' | (r = f cr, so t h e r e
cr = v . . . . v .
is non-degenerate.
As
, j , < . . . < j. » j. > r . d i m P < n,
[spanifv. , . . . , f ' v . I / E ^ , so f'(v. ) i s n o t in t h i s affine s u b s p a c s . I ^t-1 •'t fe t h e p o i n t s
{f'(v. )
L e m m a 4. 4 .
Let
f'(v. )}
a r e independent;
o
f' j tr i s n o n - d e g i r e r a i c ,
f: P — > Q b e a P . L . m a p , Q a P . L . m a n i f o l d and
a P . L . s p a c e w i t h d i m P < d i m Q. Suppose f P
so.
There-
is non-degenerate.
Let
P^ Q P
be a closed P . L.
T h e n f:^ f ( r e l P ), w h e r e f o
Regenerate P . L . m a p a n d f ' ( P - P ^ ) C Int Q.
M o r e o v e r , given
subspace
is a non£ : P—> R ^
• p o s i t i v e c o n t i n u o u s f u n c t i o n , w e m a y i n s i s t t h a t ^ ( f ( x ) , f'(x)) < £ ( x ) , a l l x , a g i v e n m e t r i c for t h e t o p o l o g y of
Q.
Proof.
E x a c t l y a s L e m m a 4. 2, vising L e m m a 4. 3 i n s t e a d of 4. 1.
Remarks. 1) As in 4. 2, we c o u l d a c t u a l l y i n s i s t t h a t t h e r e be a h o m o t o p y H; f ^ f ( r e l P ) s u c h t h a t for a l l x e P o d(H
x , H x) < S
and a l l
s,t
in [O, l ]
(x).
T
2) In 4. 2 and 4. 4, one c a n i n s i s t t h a t if t h e g i v e n m a p t h e n so is t h e m a p §i4.
f is p r o p e r ,
f.
Shifting S u b s p a c e s to G e n e r a l P o s i t i o n . L e m m a 4. 5.
I^, w i t h P
Let
91^ r. P , o
P
o
x P
and
R, , . . . , R be p o l y h e d r a c o n t a i n e d i n j 1 r I
G i v e n c > 0 t h e r e e x i s t s an a m b i e n t i s o t o p y
h of
such that 1) h i s fixed on 2) h ^ ( P - P ^ )
i i P. o is in g e n e r a l p o s i t i o n w. r . t . e a c h
3) for a l l t,
d(h^x, x) < £ .
Proof. tions V I
Let
J
be a t r i a n g u l a t i o n of
R^
h a v i n g a s s u b c o m p l e x e s triangv
K C K, L , L of P S P , R , , w i t h K full in J . Let o 1 r o 1 r o V be the v e r t i c e s of K - K , a n d l e t X be t h e s e t of a l l the v e r t i c e s s o n ' / ^ Let w , . . . , w be p o i n t s in Int I , s u c h t h a t w, ^ X ' ' (w , . . . , w. I s 1/ I
a l l i; we m a y c h o o s e e a c h w^ to be l e s s t h a n any p r e a s s i g n e d d i s t a n c e fron n In p a r t i c u l a r , we m a y c h o o s e t h e vv^ so t h a t if I d e t e r m i n e d by p u t t i n g / ( v ^ = w^ a n d I
i (v) = v
is a m b i e n t i s o t o p i c to 1 v i a an a m b i e n t i s o t o p y
is the l i n e a r m a p
J —> I
if v e X, and v / v^ a l l h
s a t i s f y i n g 3) and 1) .
i, t
-97-
C e r t a i n l y we c a n m a k e I
i s o t o p i c to t h e i d e n t i t y by " s m a l l " m o v e s .
Then
see p r o o f t h a t i s o t o p y b y m o v e s i m p l i e s a m b i e n t i s o t o p y , C h a p t e r V, §1, emma 5.1.)
n
To c h e c k 2), l e t '
ere K - K , T £ R . . o 1
K^l = 0
possible).
=
0- = 0" . (w. . . . w. ). X 11 1 1 s
If
Let
Write
cr = cr CR 1 2
CR e K 1 o
and
o-^ = Vi^. . . v i ^ , i^ < . . . < i ^ .
I cr and T s p a n
Then
E , then
dim(jeo- Pv T) < d i m cr + d i m r - n ^ d i m P + d i m R^ - n . itr and T do not s p a n
E'^, t h e n s i n c e
3T the affine s u b s p a c e s p a n n e d by n T = j^.
Since
P-P
= |K
W^ /
W , . . . , W^
cr . w . . . . w^^ ^ h £-1
and
T .
^i
This implies
(T , t h i s s h o w s t h a t
K o-eK-K
d i m r ( P - P )'^R.] < d i m ( P - P ) + dim R.- n , o 1 o 1 all i,
1 < i < r.
L e m m a 4,
.
Let
g - m a n i f o l d Q, w i t h itive function. I'
P
o
P n aQ c P
Let
Q—$>lR
be a c o n t i n u o u s
dQ u P^ ,
i s in g e n e r a l p o s i t i o n w. r. to e a c h R^ ,
I 3) d(h^x,x) < £ ( x ) Proof.
.
T h e n t h e r e e x i s t s a n a m b i e n t i s o t o p y h of Q s u c h thats
1) h fixes t h e p o i n t s of 2} h ^ { P - P ^ )
C p, R . .. , , R b e c l o s e d P . L . sub s p a c e s of the 1 r
Let
for all x (d a m e t r i c for the t o p o l o g y of Q. ). be a l o c a l l y finite countable family of q - b a l l s such the'-.
.CO
Int^ B.. U 1 "" ® K,
Let
K Q K b e t t f i a n g u l a t i o n s of P C P o o
s u c h t h a t , forr
0- C I n t „ B. for s o m e i. L e t [A. be t h e s i m p l i c e s of K - K . Q 1 ^ J ^ . o so t h a t a n y s i m p l e x follows i t s f a c e s . L e t K.. == K u I I A. . We X o .O J
a r e going to define P . L . h o m e o m o r p h i s m s isotopies
H^^^ of Q
1) h / ' ' .
(i>l)
fixing
h.
(i > 0 )
of
Q and a m b i e n t
9Q vj P ^ , s u c h t h a t
= h. ,
2)
Vo- e K , V t,
3)
Vx,
d(H
H^^V) C Int^ B . , some J Q j < e(x)/2\
c
all
t.
4) h.( K^ - I K^ ) i s in g e n e r a l p o s i t i o n w. r . t e a c h of t h e We s t a r t by p u t t i n g s o m e i ^ 1. Let
V
Let
A. C Int „ B. , 1 Q J ,K. J ^ ^ B . ) , let 1-1 i - r j"
o
W = a(R
k
h^ = i d e n t i t y .
B.). j'
Note t h a t
Let
Now s u p p o s e
a : B —>
R^ .
h^ ^ is c o n s t r u c t e d ,
be a P . L,
homeomorphisr
V = a(h. , K . n B . ) = V W ah. A . , and le| ' 1-1 1 j' o 1-1 1 I
V O
c V , — o
By L e m m a 4. 5, for e v e r y £ > 0 t h e r e e x i s t s an a m b i e n t i s o t o p y k of fixed on each
W
U ic
such that
k^(V-V^)
a n d s u c h t h a t , for e v e r y
i s in g e n e r a l p o s i t i o n w i t h r e s p e c t
t,
/>(x,k x) < t
.
Now define
H^^^ by
H^^^fB. X I = ( a " ^ X 1) 0 k o ( a X 1) J H^^^l cl(Q - B.) X I = i d e n t i t y . J Put
h^ = H^^^o h^
.
By c h o o s i n g
£ s m a l l e n o u g h we c a n e n s u r e t h a t
x) < £(X)/2^ for all x e | K | , t e I, a n d a l s o t h a t , given cr € K, t £ Iil x(i) (or) C I n t ^ B^, for s o m e H^
j.
To c o m p l e t e the proof, we o b s e r v e t h a t , by t h e c o n s t r u c t i o n of t h e w e m a y h a v e t h a t e a c h i s t h e i d e n t i t y o u t s i d e t h e i n t e r i o r of s o m e if C is a n y c o m p a c t s u b s e t of H (i)
are the identity.
B^.
H
(i|
Hence
Q, t h e n on C X I a l l but a finite n u m b e r of t b |
H e n c e it m a k e s s e n s e to define
-99-
h=
lim
H^'Ih^'-^K
. . . CH^ .
i —> CO T h e n h i s an a m b i e n t iBotopy and by c o n s t r u c t i o n s a t i s f i e s 1), 2), and 3)
in
the s t a t e m e n t o£ t h e l e m m a . §5.
S h j i t i n g m a p s to G e n e r a l P o s i t i o n . L e m m a 4. 7.
Let
K b e a ( l o c a l l y finite) s i m p l i c i a l c o m p l e x a n d l e t
f: K — > Q be a P . L . m a p w h i c h e m b e d s e a c h s i m p l e x .
Let
K, a n d
l e t R, , . . . , R b e f c l o s e d P . L . s u b s p a c e s of t h e P . L . m a n i f o l d 1 n f( K) - | K
I) C Int Q.
ffhen t h e r e is a m a p
Let
f:
K
>
Q.
Assume
be a positive continuous function.
K —> Q and a h o m o t . ,
H: K X I —» Q of f and f
, such t h a t 1) H i s t h e c o n s t a n t h o m o t o p y 2) H i s a P . L . m a p 3) f 4)
e m b e d s e a c h s i m p l e x of K and f ' ( | K | - j K^ | ) C Int Q
Vo-,, 1
(T
in
K-K
r
o
r dim(n 1 dim[( n
f'S-.) ^
6)
d(H x , f x ) < £ ( x ) f'( K
-
r 2 )
d i m (r. - ( r - l ) q ^
f 5- ) n R.] < ^
5)
< 1
i
I
d i m (T. "+ d i m R. - r q ^ J
for a l l x and
K I) C Int Q . o ~
s,
(d a m e t r i c on
,
all
Q)
j.
Proof.
Let
[aJ
i = 1, 2, . . . ]
s i m p l e x following i t s f a c e s .
be the s i m p l i c e s of K - K ^ , w i t h eac i K. = K^ U U A^ , a s u b c o m p l e x . We
Let
going to define, i n d u c t i v e l y , P . L . m a p s
f^ ,
i ^ 0, a n d P . L ,
homotopies
i > 1, s u c h t h a t 1)
V 0" € K,
f. I 0" i s an e m b e d d i n g ;
2)
H^^^ i s a h o m o t o p y of f^ ^ to f^ w h i c h l e a v e s
3)
Vo-, , . . . , 0- € K . - K , 1 r 1 o dim{ n f.®-.) 1 S J =1 ' J r d i m ( f~] j=l
f. ^ ^
4) 5) '
Put
^
< g(x)/2^ f.(|K| 1
f
o
= f.
- |K
o
R.
- (r-l)q J
r S ^ ^ ^ ""j j=l
^^^ \
all
•
k.
,
I) C Int Q . -
Now a s s u m e
f. , i s defined, 1-1
a l l t h e following P . L , s u b s p a c e s of a)
diin
fixed;
i>l.
Let
L ,..,,L be 1 IN
Qs
, 1< j < n , r
j=l , all
cr, , . . . , 0- i n K. , a n d 1 r 1-1
1^ k ^ n .
J=1 (Note:
r
not
fixed, )
Now w e a r e going to a p p l y L e m m a 4. U . P
o
= f. J A , . L), a n d l e t l-i 1
P = P U f. , (A.). o 1-1 1
Let
L = l i n k (A^; K).
Note that
P O 8Q C P
o
Let .
-101-
By L e m m a 4 . 6 , t h e r e e x i s t s an a m b i e n t i s o t o p y h of Q, fixed on P
9Q, s u c h t h a t
h. ( P - P ) i s in g e n e r a l p o s i t i o n w . r . t . e a c h
o
L . , and
o
y s and
1
Vx, d(hgX, x) <
Define
m i n [ e ( y ) | y e A.. L
H^^^ on (A.. L) X I b y p u t t i n g
|by t h e c o n s t a n t h o m o t o p y o u t s i d e Clearly
H^^^^(x) = h^ f(x).
(A^. L) X I, and put
H^^^ and f^ s a t i s f y 2) a n d 4 ) . f. ^
fbecause
o n l y o n s i m p l i c e s of
differs f r o m
Iposite of f.
f^
Extend
f^ =
H^^^ to
K XI
= h^^o f^ ^^ .
C o n d i t i o n 5) h o l d s b e c a u s e
| h j ( l n t Q) C Int Q a n d b e c a u s e f.
.
s a t i s f i e s 5).
C o n d i t i o n l ) h o l d s for f^ A^. L, w h e r e it is the c o m -
and a h o m e o m o r p h i s m . o
To c h e c k 3), we f i r s t o b s e r v e t h a t i'or s u p p o s e
x e P ^ O f^
Then
: = f. j ( z ) , z e A . . L e t y e p.T , Jf K and so i s e m b e d d e d by f^ fore
P
|v
K
o
n f. , ( A . ) C f. , ( A . ) . i - r i' - i - P 1
f^
- ^"^o
^^^ ^^^^ h a v e =).
x = f^ ^y, s a y , w h e r e
p e A^ a n d Therefore
Therefore,
as
y e A^L, and
T e L . T h e n A^T i s a s i m p l e x y = z, so x e f^ f. ,
1-1
embeds
A., 1
o
I. J^(A^) r\ P ^ =
C o n d i t i o n 3) now follows for
L lition for f. ^ and t h e fact t h a t the L . . 1 To c o m p l e t e t h e proof, p u t fhese a r e w e l l defined
hi .
f^ f r o m t h e c o r r e s p o n d i n g c o n -
® i s i"- g e n e r a l p o s i t i o n w i t h r e s p e c t to
H = lim H^^^ and f = H = l i m H^^^ = linri i 1 . 1 1 -5> CD i-$> CO l - > OO p . 1. m a p s b e c a u s e H^^^ | A. X I = j A. X I for
F i n a l l y we put s o m e of t h e a b o v e r e s u l t s t o g e t h e r to g e t ; L e m m a 4. 8.
Let
Q be a P . L , m a n i f o l d such that
fjP^
s u b s p a c e s of there exist
P
, d i m P < d i m Q.
isP.L.
Q.
Let
be a P . L. space, Let
and n o n - d e g e n e r a t e . £ ; P —> IR
P^
a closed subspace.
f; P —> Q be a c o n t i n u o u s Let
be c l o s e d P |
be a p o s i t i v e c o n t i n u o u s f u n c t i o n .
gs P —> Q a n d a h o m o t o p y
Let
H; f
g (rel P^)
Thei|
such that
1) g i s a P . L . , n o n - d e g e n e r a t e m a p , 2)
i s in g e n e r a l p o s i t i o n ,
3) g ( P - P ^ )
i s in g e n e r a l p o s i t i o n w. r.t* e a c h
4)
g ( P - P ^ ) C Int Q ,
5)
Vx,
d(H X, fx) < £ (x) s
Vs€[0,l]
(d
R^ ,
s o m e m e t r i c for the
t o p o l o g y of Q-). Proof .
By 4. 2 a n d 4 . 4 w e c a n find
f ^ f (rel P^)
and a homotopy
|
b e t w e e n f and f r e l a t i v e P 5 v/ith f P . L . a n d n o n - d e g e n e r a t e , f ' ( P - P ) C Int Q , a n d d(H' ox , fx) < £ ( x ) ' 7 . L e t K C K b e t r i a n g u l a t i o n s j O
S
of Q, so t h a t p l i c e s of
K.
f:
K —> L i s l i n e a r on s i m p l i c e s .
Let
H"
a) g i s P . L . b) c)
o
be a h o m o t o p y of f
to a m a p
embeds the siml
g, r e l a t i v e
P ^ , satisfj
non-degenerate;
g l P - P ^ ) C Int Q r ^ r d i m Q g ^^ < ^ ^
d) d i m ( g o - n R . ) J e) d(H"x, f x ) s
Then f
^
d i m o"^ - { r - l ) q , cr^, . . . , o"^ in K - K ^ '
d i m crf d i m R. - q, J e(x),
all
x.
c e K-K
;
-103-
Then
c) and 4) i m p l y
2) and 3) in the s t a t e m e n t of the l e m m a . H'(x, It)
0 < t <
H"(x;2t-1)
Y
Put
-
H(x,t) = <
By the t r i a n g l e i n e q u a l i t y ,
Definition . codimension > r
Let in P
P
H s a t i s f i e s 5).
C e r t a i n l y , g s a t i s f i e s l ) and 4).
C P b e poiybpidara.
We s a y t h a t
P^ i s of l o c a l
if, for any t r i a n g u l a t i o n K^C K of
any s i m p l e x A of K^, t h e r e i s a s i m p l e x
B of
K with A < B
P , and for and
dim B - d i m A > r . Lemma 4.9.
Let
Q be a P . L . manifold,
j e c t i o n on the f i r s t c o o r d i n a t e . |XC(9QXI) = X . ' ' o
the p r o -
S u p p o s e X i s a p o l y h e d r o n in Q X I
If dim X < m - r ,
r>l,
jis a l e v e l - p r e s e r v i n g P . L , h o m e o m o r p h i s m the i d e n t i t y , s u c h t h a t
and p: Q X I — > Q
S2(p|hX)
and
dim X
o
with
< m - r - 1 , then there
h: Q X I—> Q X I , a r b i t r a r i l y close
i s of l o c a l c o d i m e n s i o n > r
in
hX.
Furthermore,
if S ( p | X ) i s a l r e a d y of c o d i m e n s i o n > r in X , we ^ o o 'cBxi i n s i s t t h a t h 9Q X I i s the i d e n t i t y . jgte;
' L e v e l - p r e s e r v i n g ' m e a n s t h a t h c o m m u t e s with p r o j e c t i o n onto the
»econd f a c t o r . B e f o r e p r o c e e d i n g with the proof of l e m m a 4. 9 we n e e d a n o t h e r t e c h n i c a l Sttima.
Lemma 4.10.
Let
K
o
b e a full s u b c o m p l e x of
d i v i s i o n of K o b t a i n e d by s t a r r i n g a l l s i m p l e x e s of decreasing dimension. then
K.
Let
K-K^
be the sul
in o r d e r of
i s a s u b c o m p l e x of K' and if A e K ' - K o o l i n k ( A ; K ' ) O K^ i s e i t h e r e m p t y o r a s i n g l e s i m p l e x . Proof.
Then K
One m a y r e a d i l y c h e c k , by i n d u c t i o n o n d i m e n s i o n , t h a t a genej f\
A
A
s i m p l e x of K' m a y be w r i t t e n in t h e f o r m C e K and i
B < C
1
< . .. < C . r
D € l i n k ( A ; K ' ) r> K^ if and o n l y if AD = BD. C . . . C and 1 r so
K'
Cj^ n K
BD <
Now if A e K ' - K AD e K'
o
B e K^,
i s w r i t t e n in the abcve foi
and D e K^.
B D < C < C ^ < . . , < C . 1 2 r
is a single simplex
if and o n l y if
where
In w h i c h c a s e
Now K
o
is full in K,
or s a y , and t h e a b o v e c o n d i t i o n s a r e satisfied
So link{A; K') H K
= l i n k ( B ; o") = a s i n g l e s i m p l e x (if it
i s not e m p t y ) . P r o o f of L e m m a 4. 9. C a s e 1:
F i r s t c o n s i d e r the c a s e when
a l r e a d y of l o c a l c o d i m e n s i o n > r
Q = A*^ a n d w h e n S^CpjX^)
in X ^ ; a n d we w i s h to k e e p
Let
K
Let
K' C (3'(A X I) be o b t a i n e d f r o m
is
9Q X I fixed.
C K C/p(a"rX I) be t r i a n g u l a t i o n s of X C X C a X I, w i t h
K^ full in
e
t h e s i m p l i c e s of Let F o r every
K-K^
X , ...,x i s
K C ^(A X I) b y s t a r r i n g at i n t e r i o r poi
in o r d e r of d e c r e a s i n g d i m e n s i o n . be the v e r t i c e s of
K , o
v , . . . , tr t h e v e r t i c e s of i t
K'-K
£ > 0 l e t v ' , . . . , v ' be p o i n t s in A X I s u c h t h a t t h e following hold:
-105-
1) t h e r e i s a l i n e a r h o m e o m o r p h i e m to V.' a n d
z to i t s e l f if
2) V. and 1 1
v.'
P(A X I) —> A X I, s e n d i n g
z i s a n y o t h e r v e r t e x of
a r e on t h e s a n i e l e v e l ;
v^
P(AXI);
d(v.,vl)
for all
i,
and 3)
Note;
for e v e r y
i, pv.' / ^^{px^ , . , . , px^, pv^' . . . . , pv.'_^ ^ .
C o n d i t i o n 3) doe.s not in fact d e p e n d upon the o r d e r of t h e v e r t i c e s
(Vj
v^). Let
h: (3(A X I)
We c l a i m t h a t
h
> A X I be t h e l i n e a r h o m e o m o r p h i s m of l ) a b o v e .
is t h e d e s i r e d h o m e o m o r p h i s r r .
To p r o v e t h i s c l a i m , l e t .We c o n s i d e r . C a s e 1;
{pjtr)
po" and
-1,
pr
cr, r
be s i m p l i c e s of t h e s i m p l i c i a l c o m p l e x
(pT). together span
Em .
Then
dim(pcr n P ") < d i m per + d i m p ;Therefore y a s e 2;
d i m ( p o") ^pT per and px
A) 0-
A X I.
LE v e r t i c e s of fore
hK',
do not span Write
- m < d i m per - r .
e'^.
cr = pcr^ ,
T = p T^ , cr^ N T^ = 0 .
By 3) on p a g e 102,
pCcr^^) a r e l i n e a r l y i n d e p e n d e n t of t h e v e r t i c e s of
P(T).
There-
(pj 0-)' ^(p T ) = p = a- n T . B) '
cr a n d Put
T both m e e t
K
o
and
0- = cr, ff,, (T f K . (T O K 1 2 2 o l o
cr O T € K . o = 0.
(K
o
is full. )
Put t = t t
,
O K^ = 0 , T^ £ K^. T h e n the v e r t i c e s of p(o-^) a r e l i n e a r l y i n d e p e n d e n t of ^se of per a n d p r t o g e t h e r . T h e r e f o r e (pjcr) ^(pt) = (p^cr^) ^ ( p r ) C K^ . 2
And so i s of c o d i m e n s i o n ik r
in K
by the g i v e n c o n d i t i o n s . o C) 0-, T b o t h m e e t K , cr r\ T / K . o o L e t p = cr O T. o" = per cr w h e r e cr O K = 0-, € K . 1
T =
I
Z
T, O K = l o
T, e K . o
Z
a s i n g l e s i m p l e x , p^^ s a y .
^
X
Now
p € K'-K . o
By 3), t h e v e r t i c e s of
of t h e ( s p a c e s p a n n e d b y t h e ) v e r t i c e s of po'2> Therefore p|ppj^
per o p r = pCpcr^) o p(pT2).
is one-one because
Therefore
S2(p|K^)
O
^
Let
O
Hence link(p;K') O K
pcr^^ a n d ^^^
But p o - ^ . p r ^
pr^^
^^^
o
s
a r e independl each other.
a r e f a c e s of pp^, and
has loc. codim > r
a n d so
S^(pjK^) =
(p cr) ^(px) = p.
Now,
. S^ip | h K ' ) n
=
U
CL[(P[
a)" pT -
0-
n
T],
T
where
T ranges over
hK'.
So S (p h K ' )
is of l o c a l c o d i m e n s i o n > r
in hi
P r o o f of L e m m a 4. 9 c o n t i n u e d - - T h e G e n e r a l C a s e . 9
Let
K triangulate
simplicial.
Let
p | X : K' —5> J '
K'
X,
J
and
triangulate J'
Q, be s u c h t h a t
p X? K —5> J
be first derived subdivisions such that
is still simplicial. *
Let
A,,..., A be t h e s i m p l i c e s of J . L e t A. = d u a l c e l l of I n 1 L e t K. = ( p | X ) " ^ A ' ' ' r r | k | o (A* X I). K. i s a s u b c o m p l e x . Claim: d i m K. < d i m A. - r . 1 F o r let
is
0- € K. . 1
Put
or = B , . . . I r
, B l
< ... < B , r
A. in J 1
T h e n po" = pfe, . . . p
*
(with p o s s i b l e r e p e t i t i o n s ) . d i m A. < d i m p B , ^ d i m B , . 1 1
Now, po* e A.
if and o n l y if A. ^ p B ^ .
Therefor
-107-
H o w e v e r , d i m B , il d i m B - ( r - l ) = d i m B - d i m tr < d i m X - d i m a. 1 r r Therefore But
d i m o" < d i m X - d i m B^ < d i m X - d i m A^.
So d i m tr < ( m - r ) - d i m A ^ .
m - d i m A. = d i m A. . H e n c e d i m cr < d i m A. - r . 1 1 1 S u p p o s e t h a t A , . . . , A , s < n, a r e t h e s i m p l i c e s of t h e b o u n d a r y 1 s if
5.
•
Let A. = d u a l c e l l of A. in J ' . T h e n , s i n c e d i m X < m - r - l , if 1 1 o -1 # # L. = (p X^) A , t h e n d i m L^ < d i m A^ - r , i < s , b y t h e s a m e a r g u m e n t as in the l a s t p a r a g r a p h .
# Now l e t
Bj^, . . . , B^ be t h e d u a l c e l l s
A^ a n d A ^ in o r d e r of i n c r e a s i n g
K. = ( p | X ).-1.B . , c h a n g i n g n o t a t i o n . We r e c a l l f r o m t h e J J t h e o r y of d u a l c e l l s t h a t t h e B, c o v e r J | , thyl t h e i r i n t e r i o r s a r e d i s j o i n t , and d i m e n s i o n , and l e t
that
9B.
1
i s t h e u n i o n of s o m e of t h e
B. w i t h
i < i.
3
Now we c o n s t r u c t i n d u c t i v e l y p. 1. h o m e o m o r p h i s m s
h^: B^X I —>
^
such t h a t 1) if
B. C 8B. , h. B. X I = h . . J 1 1 J J
2) S^(p h . K . ) 11
i s of l o c a l c o d i m e n s i o n > r
S u p p o s e t h a t h . i s defined for J
j < i-1.
in K. . 1
Then the m a p s
h., j < i-1 J
iefine a p. 1. h o m e o m o r p h i s m h ' s BB. X I 1 Since B^ i s a b a l l , into i t s e l f ,
h'
> 9B. X I. 1
e x t e n d s to a p . l . h o m e o m o r p h i s m of (9B^ X I)
a n d t h i s h o m e o m o r p h i s m e x t e n d s in t u r n to a p . l .
B. X I —5> B. X I, w h i c h i s l e v e l p r e s e r v i n g . ' a s e 1 of t h i s p r o o f w i t h X = h " K .
and
Q = B. .
To define
(B. X 3')
homeomornhisi.-
h . , w e now a p p l y t j e
Clearly
morphism,
S (pjh K|) = U s i.
(p|h. K.'), where
h: | j | X I — > | j | X I , defined b y t h e
h i s t h e p. 1. h o m e o -
h^.
Therefore
h satisfij
t h e r e q u i r e m e n t s of t h e f i r s t p a r a g r a p h in L e m m a 4. 9. T h e proof i n c a s e is n e a r l y the s a m e .
S^(p|X^)
i s a l r e a d y of l o c a l c o d i m e n s i on at l e a s t j
We s t a r t out b y defining
h to be t h e i d e n t i t y on
(9J) X I and t h e n e x t e n d t h e d e f i n i t i o n i n d u c t i v e l y in o r d e r of i n c r e a s i n g d i n j sions over the dual c e l l s
A^
of
J
(not
J) u s i n g C a s e 1.
C h a p t e r V: 51.
Sunny C o l l a p s i n g a n d Unknotting of S p h e r e s and B a l l s
S t a t e m e n t of the P r o b l e m Suppose t h a t
Then the p a i r
S^ C s"^ a r e P . L . s p h e r e s of d i m e n s i o n
(S*^; S^)
i s c a l l e d a s p h e r e p a i r of t y p e ( q , n ) .
c a l l e d t h e s t a n d a r d p a i r of t y p e (S^, s " )
n and q
(q, n).
respectively
The pair The sphere pair
i s c a l l e d u n k n o t t e d if it i s P . L . h o m e o m o r p h i c to t h e s t a n d a r d p a i r ;
i . e . , if t h e r e e x i s t s a P . L , h o m e o m o r p h i s m
h: S*^—>
. A*^"" such that
»n+l h(S ) = A Question;
Is a s p h e r e p a i r always unknotted?
Answer;
Y e s if No if
q-n > 3 q - n = 2 ( e . g . , T r e f o i l knot in 3 - s p h e r e . )
Unknown if
q-n = 1
(Schoenflies
Conjecture. )
We a r e going to s h o w in t h i s c h a p t e r t h a t the a n s w e r to t h i s q u e s t i o n is indeed a f f i r m a t i v e if
q - n > 3.
A r e l a t e d q u e s t i o n i s t h a t of t h e u n k n o t t i n g of b a l l p a i r s .
A p r o p e r ball
>air (B^, B^) of t y p e (q, n) i s a P . L . m - b a l l B™ c o n t a i n e d in P . L . g - b a l l B° such a w a y t h a t .the p a i r
(a"^. A^
= B"^ O 9B®.
T h e s t a n d a r d ( p r o p e r ) p a i r of type (q, r.'
a n d a p r o p e r b a l l p a i r i s s a i d to be unknotte d if
1^18 P . L . h o m e o m o r p h i c to t h e s t a n d a r d p a i r . J£®tion: ^acerj
Is a p r o p e r b a l l p a i r a l w a y s \inknotted ? Y e s if q - n > 3 - - w e w i l l p r o v e t h i s . No if q - n = 2 ? if q - n = 1.
-1 In o r d e r to p r o v e t h a t p a i r s of c o d i m e n s i o n > 3 ( i . e . q - n > 3)
are
u n k n o t t e d , we s h a l l a l s o h a v e to c o n s i d e r t h e Factorization Question; an m-manifold,
If K^ C_ K C M
a n d if K ^ K ^
and
a r e c o m p a c t P . L . s p a c e s , with
M^K^,
soes
M ^ K
In s o m e c a s e s t h e a n s w e r is a l w a y s a f f i r m a t i v e t L e m m a 5. 1.
If, in a d d i t i o n to t h e h y p o t h e s e s of t h e f a c t o r i z a t i o n questi
K C Int M = M - 3M, t h e n Proof.
L e t N b e a d e r i v e d n e i g h b o u r h o o d of K in M.
and
T h e n N C Int
So N i s a r e g u l a r n e i g h b o u r h o o d of K^, m e e t i n g the bound
regularly. M
M^K.
\K,
By t h e g e n e r a l i z e d a n n u l u s t h e o r e m , so
M
M - N ^^ ( F r N ) X I,
Therefo
\K.
H o w e v e r , t h e r e s u l t we w i l l n e e d for t h e u n k n o t t i n g q u e s t i o n i s : Theorem 5.2. m - m a n i f o l d , t h e n if
If K C K C M a r e c o m p a c t P . L . s p a c e s , o ~ M\K
and K \ K
t o
^
M
and if d i m ( K - K ) < m - 3 , o
an
thenM\l
o
H e r e d i m ( K - K ^ ) = l a r g e s t d i m e n s i o n of s i m p l i c e s of K not in K^. T h e proof of t h i s t h e o r e m o c c u p i e s t h e n e x t few s e c t i o n s . §2.
Sunny C o l l a p s i n g Definition .
and If
Say X ^ C X C M X I
are compact P . L. spaces.
( x ' , t ' ) 6 M X I, we s a y (x, t) i s d i r e c t l y b e l o w ( x ' , t ' ) U = M X I, t h e s h a d o w of
b e l o w a point of
U
.
if x = x '
If (x, t) and
t<
U is defined to be t h e s e t ^ y e M X l | y i s d i r e c
We w r i t e
sh(U)
for t h i s s e t .
-111-
Picturej Sun
/ / r
3h(u)
M
Definition . tions li I; and
X
K C K of X o o
s u n n y c o l l a p s e s to X and
X^
in M X I if t h e r e e x i s t t r i a n g u l a -
J of M s u c h t h a t
1) T h e i n c l u s i o n K —> J X I is l i n e a r (on s i n n p l i c e s ) , 2) t h e r e e x i s t s a s e q u e n c e of e l e m e n t a r y s i n n p l i c i a l c o l l a p s e s :
IK = K
r
,es ves \ K , \ ., . V r-1
\es \ K \ o
such that
( Kj X
K.
1-1
I ) . , sh(K.) = 1
I Picture: If K then
o-'
e n t i r e figure i n s i d e the box, (KI
sunny c o l l a p s e s to !K
j.
L e m m a 5. 3.
Suppose
XC MXI
X^ = X r\ [(M X 0) u (9M X I)]. MXL
Then Proof.
-
L e t M = | J , X = ' o Let
J ) n sh(K^) = j2f
S t e p 1):
Suppose that
X
s u n n y c o l l a p s e s to X^
in
M X I ^^ (M X O) u ( 9 M X I) U X .
c o n t a i n e d l i n e a r l y in J X I. (|kJ
Let I
a r e compact P . L. spaces.
K | , X = | K L o ,es K =
^r-1
where .es
K C K, and o es
\
\
^o
K
^^^^
be the sunny c o l l a p s e .
I J | X I ^ (I J | X 0) u (I 9 J | X I) u | K | U s h ( | K | ) .
Let
(3{J X I)
and
\j{J) b e s i m p l i c i a l s u b d i v i s i o n s u c h t h a t
c o n t a i n s a s u b d i v i s i o n of K and coordinate, is simplicial.
Let
o r d e r of d e c r e a s i n g d i m e n s i o n . of A. X I.
Consider
P^:
(3(J X I)
> >/(j), p r o j e c t i o n on the fij
{ A ^ be t h e s i m p l i c e s of F o r each
i,
(3(J X I) |
Y(J) -
(3(J X I) c o n t a i n s a t r i a n g u l a t
c l ^A^ X I - (A. X I) o (K u sh(K))^ .
Now, if t h i s set
n o n - e m p t y it i s a c o n v e x l i n e a r c e l l w i t h A^ X 1 a s a p r i n c i p a l f a c e . c o l l a p s e s to t h e c l o s u r e of t h e d i f f e r e n c e of i t s b o u n d a r y a n d A. X 1. A. X I y A . X I) u (A. X 0) U [(A. X I)
(K \ j s h (K)}
So doing t h e s e c o l l a p s e s in o r d e r of i n c r e a s i n g JXI| S t e p 2):
y
of|
Hence; So
. i we find t h a t
| J | X 0 ) u (|K| u sh(|K|)) u ( | 3 J | XI)
.
(J X 0) U ( a j X I) O K vj s h K ^ ( j X O) U (9J X I) u K.
In t h i s s t e p we u s e t h e e x i s t e n c e of t h e s u n n y c o l l a p s e .
We a r e going
show t h a t (J X 0) u (9J X I)
K u s h ( K p ^ (J X 0) u ( 9 J X I) u K o sh
-113-
L e t K. = K. ^ ^^ A
with
A = aB,
A
K. ^ = a B .
Therefore
A n sh(K.) C a B . Let B.
B be an i n t e r i o r p o i n t of
T h e n for
to A because Isince
b n e a r enough to
B,
B.
b be a point d i r e c t l y b e l o w
b. A n K^ ^ = a B ; n o t e t h a t
A can c o n t a i n no v e r t i c a l l i n e s e g m e n t s .
bA < sh(K^) V K^, t h i s innplies t h a t
ffrom the face
Let
bA
K = A.
b is joinable
So b. A n K. = A . So, c o l l a p s i n g bA
bB
K vj sh K \ K ' • sh K. - Int bA - Int bB = K u sh K. , j sh b a B U baB 1
Jsing t h e fact t h a t Step 1.
1
1-1
(baB) n (K u s h K . _ ^ ) C a B C
collapse vertically as
K u sh K. , u sh b a B \ K u s h K. . 1-1 ^ 1-1
icturer
U the definition:
if P and Q a r e ( c o m p a c t ) P . L . s p a c e s , P ^ Q, we s
I of l o c a l c ^ d i m e n y o n g r e a t e r t h a n o r e q u a l to ciangulation K C K of o , and dim cr
d i m T -C.
P C Q, and s a y
c in Q p r o v i d e d t h a t , fr -
cr 6 K , t h e r e e x i s t s o
t p K v "r!
L e m m a 5. 4.
L e t F : X X I —> M X I b e a P . L . e m b e d d i n g , X and
compact P . L. spaces, such that F " ^ ( ( M X 0) u ( 8 M X I) = X X 0 . Let
-TT : X X I —> X
, p: M X I —> M
b e p r o j e c t i o n s o n t h e 1st f a c t o r s .
Suppose that 1) S^ ( p ® F ) 2)
i s of l o c a l c o d i m e n s i o n ^ 2 i n
-rr S ( p o F )
XXI
is n o n - d e g e n e r a t e .
Ct
Then
F ( X X I) Proof.
s u n n y c o l l a p s e s to
By i n d u c t i o n o n d i m K.
triangulating
X and
of K X I
K, r e s p e c t i v e l y ,
and
1)
F ( X X O) in M X I . Let
M, r e s p e c t i v e l y .
K and J
Let
be s i m p l i c i a l c o m p l e x e j
a(K X I) and
p(K) b e subdi\
such that
Q:(K X I) c o n t a i n s a t r i a n g u l a t i o n
L of
F).
2) -IT : a(K X I) —5> (3(K) i s s i m p l i c i a l . Let \ L
b e a s u b d i v i s i o n of
for a s u i t a b l e s u b d i v i s i o n >/(LnKXO) Let B L
1
.,B
of
hn
J'
such that of
J.
p
F j ^/L: w/L—> J '
Note that
and l e t
A^, . . .
-yL c o n t a i n s a s u b d i v i s i o n
b e t h e r - s i m p l i c e s of
b e t h e ( r - 1 ) s i m p l i c e s of \ L - ^/(L
i s a face of, a n ( r + l ) s i m p l e x of
s o m e s i m p l e x of a{Ai X I), s o m e
or(K X I). j. S i n c e
J
(K X 0)).
Hence each trs Qr(A. X I) J
e a c h B^ i s c o n t a i n e d in A^ X I, s o m e
j.
pK.
Let
Any ( r - 1 ) s i m p l e x B^ l i e s in a face of A. i s s i m p l i c i a l , i J
t
m e a n s that
is simplicial
(KXO).
dim K = r s
L
-115-
N o w we a r e going to c o n s t r u c t " b l i s t e r s " o n t h e B^ a s follows. A
each
i, let
A
B. = b a r y c e n t e r of
B^.
Choose
it (how n e a r w i l l be s p e c i f i e d in a m o m e n t ) . and d i r e c t l y a b o v e
A B.. i
Choose
be a point o n t h e s a m e l e v e l a s shortly).
Let
We c h o o s e .
and, if
For
E. = 1
A. s u c h t h a t J A
X. If
directly below
B^i^ X X 1, c h o o s e B. C A. X I, a n d l e t ^ J
Y^
near
o Z. e A. X I ^ J
B^ and n e a r it (how n e a r to be s p e c i f i e d X Y Z B i 1 i 1
if
B. C X X 1 1
X.Z.B. I l l
if
B. C X X 1 1 -
X . , Y . , and Z. n e a r enough to 1 1 1 B ^ X X 1, E . O (X X 1) = B. H (X X ), and it' 1 1
We o b s e r v e t h a t
B^ and n e a r
so t h a t
(i. e. B. / X X 1) ; 1
E.n
E. = B.f^B. i j i j E . O (X X O) = B . a ( X X'O), 1 1
X. and Y. a r e not in 3 . b e c a u s e S ( Tr( S (p" f)) = 1 1 1 CO Z land so no s i m p l i c e s of \ ( L ) m a y c o n t a i n a v e r t i c a l l i n e s e g m e n t . Picture (of 4 b l i s t e r s ) :
Let
E!
o
E.
'1
be the b l i s t e r s w h i c h m e e t
R(j)
a b a l l of d i m ( r X 1) and m e e t s an ( r + l ) - b a l l . E. n h
Since
E. n Jz
8{A. X I) in a f a c e . J
E. = B. n Ji Jz
8(cl(A. X I - E . )) = E . n ^ h h
Hence
E. ) is an ( r + l ) - b a l l . Jz
cl(A. X I - E
... ^ E
Each bl
cl(A. X I _ J
B. , it i s not hard to s e e that Ji
a(A. X I) = a face of ^
cl(A. X I - E. o J Ji
A^ X I.
E.
.
Hence
h
C o n t i n u i n g t h u s l y , we at l a s t findl I
) i s a n (r+l)-ball.
A s i m i l a r a r g u m e n t si
that
c l ( A . X 1 - (A. X 1) o ( E .
. . . o E.
clfA
^ X I - E
^R(j) H e n c e t h e c l o s u r e of t h e c o m p l e m e n t of
J
^ w . . . v.-* E . ]. Jl jR(j)
face i s a l s o a face of c l [ A . X I - E . J hedron collapses.
So,
o ••••
], to w h i c h t h i s l a s t pel ^R(j)
A. X I V[(A. X 0) w (3A. X I)] J
Let A = (r-1)
)) i s a f a c e of
'
s k e l e t o n of
J
( E . o . . . vJ E
J
pK = (3K-{A. J .
J]
T h e n , by what we have
proved pK X I \ (pK X 0 ) u ( A X I)
(E^U
...
E^) ,
a n d so R = F ( p K X I) \ j F { { p K X 0) U (A X I) ^ ( E ^ v j . . . u E^))= 5. Moreover
sh(R) r^ R C S.
X 6 A X I,
Since t h e r e exist subdivisions m a k i n g the c o l l a p s e
it follows t h a t
F o r if F ( x ) € sh(R) n R, t h e n x e S ^ { p o F )
R s u n n y c o l l a p s e s to
S.
r\|S
and
simplici^
-117-
Now let
B. C X X 1 .
Z.X.B.
U. = 1
1
1
1 X
Z.X.B. u Z.Y.B. ^ X l l 1 1 1
te. V. = rx.B.
B. X X 1 i"*^
B. C X X 1.
X . B . o Y.B. ^ 1 1 11 rhen
~
B. i 1
X X 1 .
b a l l a l w a y s c o l l a p s e s to a f a c e . Recall that
loFrYL—> J'
B , . . ,B a r e t h e ( r - l ) s i m p l i c e s of yl and t h a t 1 s
is simplicial.
j r d e r e d so t h a t if F { B p
We m a y s u p p o s e in a d d i t i o n t h a t t h e
overshadows
^(Bj)
r(B.) in i t s s h a d o w and t h e r e f o r e a l l of J )te t h a t s i n c e S^CpoF)
B^
are
(i- s . h a s i n t e r i o r p o i n t s of
F(B.) J
in i t s s h a d o w ) t h e n
i < j.
i s of l o c a l c o d i m . at l e a s t two, n o n e of t h e p o l y h e d r a
m a y contain a v e r t i c a l line segment. ) Since
:x 0) o
E . \ U. a l l j , w e h a v e : J ^ J i-1
(A X I) -
(J
I
r
f.
i
i-1 V
+ J
U + 1 J
i
CXO)vj(AXl) - U V + U
I
1
s
U
J
1
ME
c o l l a p s e s to
i s
U + y E J
Hence
i+1 J
i-1 i-I s F [ ( K X 0 ) U ( A X I ) - I J V. + M U + U 1 J I J i i, F [ ( K X 0) u ( A X I ) -
U 1
feover,
r
\ E ] J
\
i V. J
+U J
s U. + J
(J
F.]. J
F ( I n t E.) = Int F ( E . ) m i s s e s the s h a d o w of ^ i-1 ^i-1 s (A X I) V. + U. + ( ^ E . ] . F o r o t h e r w i s e , we would n-. I J 1 J i ^
Int F ( E . ) E
meeting
sh(F(E^)), s o m e
j > i.
F r o m the c o n s t r u c t i o n of t h e bliat
this i m p l i e s that
F ( B . ) o v e r s h a d o w s F ( B . ) , an i m p o s s i b i l i t y for i < j . J ^ It now follows t h a t a n y s i m p l i c i a l s u b d i v i s i o n s w h i c h m a k e (l) a s i m p l i c i a l col l a p s e m a k e it a s u n n y c o l l a p s e .
Hence we m a y conclude that s s c o l l a p s e s to F((K X 0) v^ (A X I) - U V + i, J U ). s Now l e t k: A X I —5> A X I sends M X I.
B. to
Z.
Then F '
0); t h e r e f o r e
a n d so S 2 ( p ° F ' )
Tr|S ( p o F ' )
m a p and so i s n o n - d e g e n e r a t e . F'OK(AX
U. be t h e p . l . h o m e o m d r p h i s m wh
s a t i s f i e s t h e h y p o t h e s e s of t h i s l e m m a .
at l e a s t two in A X I, a n d
to
s V.
a n d i s t h e i d e n t i t y on cl(A X I - '-'V^).
S ^ C p - F ' ) C YL --[B^ I J = 1, . . . , sj-
F ( K X I) sunny S
Let
F' = Fok: A X
For
has local co-dimension
i s t h e r e s t r i c t i o n of a n o n - d e g e n e r a t e l
H e n c e by i n d u c t i o n F ' o k(A X I)
s F(A X I - U 1
s V. + M U.) ^ Y ^
s u n n y collad I
s u n n y c o l l a p s e s to
F(A|
This m e a n s that F((A X I) u (K X 0) - UV. + S i n c e F ( K X O) C (J x O)
UU.)
F{(A X 0) w (K X 0)) .
X I), t h i s c o l l a p s e is a l s o a s u n n y c o l l a p s e .
T
c o m p l e t e s t h e proof.
§3.
F a c t o r i z a t i o n of C o l l a p s e s - - P r o o f of T h e o r e m 1. 2. L e m m a 5. 5.
Suppose that Then
(Q X I)
Let
B C Q X I b e an n - b a l l , Q a c o m p a c t g - m a n i f o l d .
B H [(Q X 0) vj (9Q X I)] is a face of ( Q X 0) \J (3Q X I) U B .
B.
Suppose that
n < q-2.
-119-
Proof.
Let
F = B f\ [(Q X 0) u (SQ X I)].
h o m c o m o r p h i s m with h(x,0) = x. morphism
L e t h; F X I —> B b e a P . L .
By L e m m a 4. 9, t h e r e i s a P . L . h o m e o -
k: Q X I — > Q X I, l e v e l p r e s e r v i n g ,
I local c o - d i m e n s i o n ^ 2 i n k B . Ifirst c o o r d i n a t e ) . Iwith (F X I)
Consider
It i s of l o c a l c o d i m
K«h
Imorphism, such that
i s of
(p » pro}, on t h e
2 in F X I, a n d so i t s i n t e r s e c t i o n in ( F X I) ^ ( F X O).
Hence
k ' : F X I —> F X I, a l e v e l p r e s e r v i n g h o m e o -
Sjirlk'CK))
jection of F X I o n t o
S^CpjkB)
^(S^(pk|B)).
X 0) i s of l o c a l c o d i m e n s i o n
|we m a y apply L e m m a 4 . 9 to find
Let
such that
h a s l o c a l c o d i m ^ 1 in k ' ( K ) , -n- t h e p r o -
F.
= koho(k')"^: F X I—» Q X L
Is of l o c a l c o d i m e n s i o n ^ 2} i n
F X I.
T h e n S^(p
= k't h " k " ^ ( S ^ ( p | k B ) )
M o r e o v e r , S ( """jS (pc
I
^
codimension > 1 in S {po
hence
-irlsjpoip)
This is b e c a u s e
k'
is n o n - d e g e n e r a t e .
and k a r e l e v e l p r e s e r v i n g
b o u n d a r y p r e s e r v i n g , a n d b e c a u s e of t h e definition of
smma 5 . 4 ,
Finally,
h.
H e n c e by
k h ( F X I) s u n n y c o l l a p s e s to k h ( F X I) n ((Q X 0) u (aQ(X I)).
* ence by L e m m a 5. 2,
(Q X I)
(Q X O) u (9Q X I)
k h ( F X I).
A p p l y i n g k"
1
•both s i d e s of t h i s c o l l a p s e , w e s e e t h a t (Q X I) ^^(Q X 0) u ( a o X I) U B. T h e o r e m 5. 2. m-manifold IK.
M.
Let
K CT K C M , o ^
Suppose
K , K P . L . e u b s p a c e s of t h e c o m p a c t o K
a n d d i m ( K - K ^ ) <, m - 3 .
Then
Proof. r - b a l l and
It suffices to s u p p o s e t h a t
B o K
= F , a face of B .
o
triangulated as subcomplexes. in M.
Let
K
i.e.
Subdivide
M with
K, K , and o
B
N be a 2nd d e r i v e d n e i g h b o r h o o d of
M is a l s o a r e g u l a r n e i g h b o r h o o d of
regularly.
c l ( K - K ^ ) = B, a
K^
and N a l s o m e e t s t h e
H e n c e , by t h e g e n e r a l i z e d a n n u l u s t h e o r e m , t h e r e e x i s t s a p . l j
homeomorphism h: c l ( M - N ) — > F r N X I with h(x) = (x, 0)
if X € F r N.
Now, N n B i s a r e g u l a r n e i g h b o r h o o d of F So N O B
i s a n r - b a l l and N
of c o l l a p s i b l e s e t s .
Therefore
in B m e e t i n g
9B
rega
B i s an ( r - 1 ) b a l l , b e i n g r e g u l a r neighbo: ( F r N) n B i s a l s o a n ( r - l ) b a l l . '•I
Let
B^ = c l ( B - N ) .
b e t h e r e s t r i c t i o n of [i: Q X I ^
h above.
Let
Q = F r N.
—>
We m u s t now c o n s t r u c t a p. 1. h o m e o m o r p l
t, and
b e a p. 1. h o m e o m o r p h i s m s u c h t h a t
\ (I X 0) = ((I X O) u (O X I)).
Set X
\(l,t) = (l,t)
(Exercise: Construct
be a bo\andary c o l l a r .
li: Q X I — 5 > Q X I
X
T h e n define
by jji(c(x, s), t) = (c(x, \ ^ ( s , t)), ^ ^ ( s , t))
l i ( y . t ) = (y, t) T h e two d e f i n i t i o n s a g r e e on t h e o v e r l a p ( w h e r e The map
L e t h: F^ —> Q
Q X I t h r o w i n g Q X 0 into (Q X 0) ^ ( 9 0 X I),
Let fox e v e r y
F^ = B n F r N .
p. i s p. 1.
if X 6 9Q if
y € c l ( Q - I m c).
s = 1 in t h e f i r s t definition
F o r on I m ( c ) X I, it i s t h e c o m p o s i t e s
-121-
Im(c) X I
""
^ ^ >
ao X I X I ^ ^ ^
> aQ X I X I
^ ^ ^
> Im(c) X I .
This a l s o s h o w s t h a t i s i s a h o m e o m o r p h i s m . Now, iJL(hB^) i s a b a l l in Q X I JjihF^. I Hence t
meeting
d i m B^ < d i m M - 3 < d i m Q - 2. c l ( M - N ) \ ( F r N) v B , a p p l y i n g \ 1
/Therefore [Note: ^
m \ n v
If
B^.
Let
QXI
X O) . (9QXI)w jihB^.
- 1 - 1 : |J. to the p r e c e d i n g c o l l a p s e .
h
so
are simplicial, L
liirst deriveds, then Proof.
Therefore
NL-B^ = N U B ,
L C L C J o
(Q X O) i.; (8Q X I) in t h e face
o
M ^N
B.
But
N
full in J a n d L ' C L ' o
are
; J') u L' i A^^ =>J3implices of
J-L
which meet
L^, in o r d e r of
i e c r e a s i n e d i m e n s i o n . Then A.P. N(L' ; J ' ) A. , N(L' ; J ' ) , F o r fr 1 o 1 o f 1 N(L^5 J ' ) i s a r e g t i l a r n e i g h b o r h o o d of A^ L,^ w h i c h m e e t s A^ IND so A. 1
J'
N(L';J') o
i s a face of t h e b a l l A. M N ( L ' ; J ' ) . 1 o
regularly,
)
Unknotting of B a l l P a i r s a n d S p h e r e P a i r s
jptation;
If P = (B^, b'^) i s a p r o p e r b a l l p a i r , t h e n o P and v P
Jfe t h a t v P
(VB^. VB'^),
V a j o i n a b l e point.
is p r o p e r .
L e m m a 5.6. |t
denotes ball pair
denotes the sphere
Let
P a n d Q b e two u n k n o t t e d b a l l p a i r s of t y p e ( q , t t n ) .
Q be a p . 1. h o m e o m o r p h i s m .
^I'pHsm k : P
Q w i t h k|=P = h .
Then there exists a P . L. homeo-
Proof .
^
So t h e r e a r e P . L. h o m e o m o r p h i s m s h: P —5> Q
P —> v P , Q —> v 6
exter
a n d we c a n
conically.
L e m m a 5. 7.
T h e c o n e a n d s u s p e n s i o n ( j o i n w i t h a s p h e r e ) of an
ball o r sphere pair is an unknotted ball o r s p h e r e p a i r . Proof.
Exercise.
By B
we d e n o t e t h e s t a t e m e n t :
a r e unknotted.
Let
S
a l l p r o p e r b a l l p a i r s of type (q, •
= " a l l s p h e r e p a i r s of t y p e (q, m )
a r e unknottec
q, m L e m m a 5.8.
Proof.
Let
B
q, m
implies
P = (S^, s " ^ ) .
L e t V be a v e r t e x of
S
q, m
Let
K be a t r i a n g u l a t i o n of
S*^!
K
. L e t P . = ( s F ( v ; K ) , i F ( v , K )). Let o 1 o P = c l ( P - P , ) = ( K-st(v;K) , K -st(v;K ) ) . T h e n P and P a r e both! ^ 1 o o J. ^ r
»
«
p r o p e r b a l l p a i r s , and
P^ = P ^ .
homeomorphism
^ vP^
The identity
•
P ^ —> P ^
e x t e n d s t o a p. 1.
»
P^
•
a n d a p . 1. h o m e o m o r p h i s m »
P
P^—> v'P^-
,
So
,
i s p. 1. h o m e o m o r p h i c ( a s a p a i r ) to v P ^ u v ' P ^ , a s u s p e n s i o n of
P^ an*
so u n k n o t t e d . Definition.
A fac e of the p r o p e r b a l l p a i r
pair
F =
fine
c l ( P - F ) = (aB^ - A^"^, Lemma 5.9.
with A ^ ' ^ C
9B^ a n d
P = (B*^, b"^)
is a p r o p e r ba
=
- a " ^ " ^ ) , w h i c h i s a l s o a face of
Wed P.
L e t P and Q be u n k n o t t e d b a l l p a i r s of t y p e (q, m )
in a c o m m o n f a c e . T h e n if
B
which
^ j i s t r u e , P VJ Q i s a n u n k n o t t e d b a l l P' q-1, m - 1
-123-
Proof .
Let
F be the c o m m o n face.
Let
P^ = cl{P-F), Q = cl(Q-F). *
B
. J implies q-l,m-l
F,P.
1 2
hornoemorphisms preserve to p - L
a r e unknotted.
boundaries.
Then
F
i s u n k n o t t e d a s p. L
B y 5.6, t h e i d e n t i t y
F—3> F
extends
homeomorphisms: aF , H^.
-> b F
F -
-> c F u h,:P "1
>aF<^bF
e x t e n d s to
'extends t o
abF
k.: P
2
and
h
1
k : Q — > b c F , both h o m e o m o r p h i s m s ,
k^l P U Q
5> a b F i. > bcF '-X a F v i c F
L e m m a 5. 10, aeighborhood of
b"^
Let in
(B*^, B"^) B^.
h : Q —> b F u c F J
^
is
So •iknotted.
be a p r o p e r b a l l p a i r .
Then
B^ ^
Let
and
N be a r e g u l a r i m p l y (N, b " ^ ) ,
proper ball p a i r , is unknotted. Proof.
Let
K C K triangulatt
b " ^ ^ B*^, a n d s u p p o s e t h a t
iy u n i q u e n e s s of r e g u l a r n e i g h b o r h o o d s , w e m a y a l s o s u p p o s e t h a t „ \es \es = N(K ; K " ) w i t h o u t l o s s of g e n e r a l i t y , L e t K = L V . . . \ L K E . = (N(L'! ; K") , N(L." 5 K " ) , w h e r e 1 1 1 o = (N, K^
),
M o r e o v e r , E.
o = V £ K .
K" = 2nd d e r i v e d s u b d i v i s i o n .
is a b a l l p a i r , by r e g u l a r n e i g h b o r h o o d t h e o r y ,
fis e a s i l y s e e n to b e p r o p e r , E ^ = ( s t a r ( v ; K ), s t a r ( v , K ' ^ ) = vAlink(v;K",), l i n k ( v ; K"^)), a c o n e on a i e r e p a i r of t y p e (q l . m - l ) . R
E. IS u n k n o t t e d . 1-1
P\U
H e n c e E^^ i s •.nknotted. L
- L 1 1 - 1
'
A
U,
S u p p o s e by i n d u c t i o n
A = aB,
Then
E.
E. ^ P u Q, 1 1 - 1
E. = E. 1
1-1
U P u Q, w h e r e P = (st(A,K"),st(A.K'^)) Q = (st(B;K"),st(^;K^))
(See r e g i i l a r n e i g h b o r h o o d t h e o r y , C h a p t e r III^ Now P = A ( l i n k ( A ; K " ) , l i n k ( A ; K J J ) ) . A
or a ball pair, according as 9(link(A;K")) o
The link p a i r is e i t h e r a sphere
"
A
A € Int K^
•
of A € K^
.
Since
= l i n k ( A ; k " ) c l i n k { A ; K " ) = a(link(A; K")), in t h e e v e n t o
t h i s p a i r i s a p r o p e r b a l l p a i r o r a s p h e r e p a i r of t y p e ( q - 1 , m - l ) .
A e k! Hence
i s Tinknotted. N o w we a r e g o i n g to p r o v e t h a t Let
L = ( l i n k ( A , K ' ) , link(A; K^)) .
P = AP^.
Let
p t P ^ — L
P ( ^ ) = 0-
if
P n E^ ^ i s a face of
Let
P
and
E^
P^ = (link(A; K " ) , link(Ar K ^ ) ) .
That
b e t h e p s e u d o - r a d i a l p r o j e c t i o n g i v e n by 0- € l i n k ( A ; K ' ) .
(See r e g u l a r n e i g h b o r h o o d t h e o r y . ) . We n o w i n t r o d u c e s o m e n e w n o t a t i o n , b y w r i t i n g
P = (P, , P ) D
(P"big" and P " s m a l l " ) .
etc.
onto t h e d e r i v e d ideighborhood of
(aB)
Then
in L
P
t h e d e r i v e d n e i g h b o r h o o d of
(aB)
in
L
.
sends
and s e n d s D
S
P
(E. S
)
onl
1— X S
Using the s u b l e m m a appearing
s t h e end of t h i s p r o o f , w e s e e t h a t t h e i m a g e o£ P r> of t y p e
(q-1, m - l )
unknotted p a i r . P u E.
a n d so a face of P
S i m i l a r l y , ( s e e r e g . nbhd. t h e o r y ) ( P
. a n d of Q;
1-1
and of
hence E.
1
is unknotted,
is a p r o p e r ball p Theref-re
P IS a fac<
-125-
S u b l e m m a 5. 10. 1.
Let X C M C Q ,
MCQ
a manifold p a i r ,
jvl r> 8Q = 8M.
A s s u m e e v e r y t h i n g is t r i a n g u l a t e d so t h a t
M and Q.
N = d e r i v e d n e i g h b o r h o o d of X i n Q.
I
Let
Proof.
iitriangulates I* °
First.
F r , o M
XCMCQ,
M) = F r ^ ( N ) n M. U
with
X i s full in b o t h
Then
a(N n M) = ( a N ) n M . LQ
F o r say
L full in K , K full in K. o o
|>e f i r s t d e r i v e d s u b d i v i s i o n s , and s u p p o s e
N = N(L';K').
K
o
C K
L e t L ' C K' ^ o Then
k'
N n M = N(L';K^).
-Say A € K' . T h e n A e F r ^ J N n M) if and o n l y if A A L = ^ but t h e r e e x i s t I, o M B € L w i t h BA € K' . A e F r ^ ( N ) O M if and o n l y if A € K , A n L = ^ and o Q o 1 t h e r e e x i s t s B € L ' w i t h AB e K ' . It i s c l e a r t h a t t h e s e c o n d i t i o n s a r e e q u i •valent.
Therefore
Now,
Fr.iN M) = F r _ ( N ) a M. M U (8N) rv M = ( ( F r ^ N ) o M) u (N ^ M M) =
[But M r \ dQ =
r^ M) u (N r^.^M).
dU.
C o r o l l a r y 5. 11. i Proof .
If
If g - m > 3, t h e n ^
B
and
m-l,q-l
q - m k 3 , t h e n by T h e o r e m 5. 2,
[(since b o t h c o l l a p s e to a p o i n t . ) (B^, b " ^ )
30).
S
m-l,q-l
imply B
m, q
B^
H e n c e B*^ i s a r e g u l a r n e i g h b o r h o o d of
b"^.
i s u n k n o t t e d by 5. 10.
T h e o r e m 5. 12.
If q - m > 3, t h e n e v e r y p r o p e r b a l l p a i r o r s p h e r e p a i r
pf type ( m , q) i s u n k n o t t e d . Proof. B
We a l r e a d y h a v e t h e following S
m, q
m, q
and
start the induction, a s s u m e
S
m, q
==> B
implications:
., ,, m+l,q+l
m = 0, q > 3.
,
if
q-m > 3 ,
So we h a v e a p o i n t , P
s a y , in t h e
-i; i n t e r i o r of B ^ .
Triangulate
regular neighborhoods
§5.
B*^ w i t h
P
[ P C B*^] ^ [ P (2, s t a r ( P , K ) ]
By t h e u n i q u e n e s s of
w h i c h is c l e a r l y unknottec
Unknotting of E m b e d d i n g s of B a l l s in B a l l s . Now we a s k t h e following q u e s t i o n :
f, g : B " ^ — w i t h
L e m m a 5. 13. , m u 9B^ h : B"^
If B
f(x)
Proof.
^
k : b'^ — > B ^
Therefore
g(x), a l l x e B"^ ?
extending
k" =
k"(B"^ = k'h"^.
Let
: A"^
be t h e s u s p e n s i o n of Then S p
such
(B^^; b " " ) —> > A"^.
Let
P ( i . e . j o i n up p w i t h the
i s the i d e n t i t y on
-
> B ^ i s t h e i d e n t i t y on
SB^.
A^""^). Moreover,
T h e n k | dB^^ = k ' | a B ^ = h | 9 B ^
= h.
=
Let
f, g: b " ^ Assume
a r e ambient isotopic keeping h auch that
k ' : ( B ^ b " ^ ) ( B ^ ; B"^)
P = Qfk'h
Let k = (k")"^k'.
L e m m a 5. 14. =
Let
(Sp ) or: B*^
k|9B"^ =
if
h.
So k ' h " ^ I dB^^ = i d e n t i t y .
>
i d e n t i t y on A*^'"^).
= g'^aS^l), is there
is a P . L . h o m e o m o r p h i s m , then t h e r e exists a
be a P . L . h o m e o m o r p h i s m . 2 |3
onto
By L e m m a 5.6, t h e r e e x i s t s
t h a t k' I dB"^ = h | 9 B ^ .
embeddings
C B ^ i s an u n k n o t t e d p r o p e r b a l l p a i r and
> B""u
P . L. h o m e o m o r p h i s m
given P . L. dB^^ =
f
an ambient isotopy throwing
topy
as a vertex.
h^o f = g a n d
?> B ^ be P . L .
embeddings,
q - m > 3 and f | BB"^ fixed. h leaves
g]
T h e n f and g
( T h a t i s , t h e r e e x i s t s an a m b i e n t i s o 9B^
fixed.)
-127-
Proof.
There exists a P . L. h o m e o m o r p h i s m
h(fB"^) = The m a p
as
(B^.fB^")
fg ^h: fB™ —=> fB^^
f g ' ^ l f l a B " " ) = hlfCaB""). homeomorphism. kjB^
and
[|6.
and
So hWfg'^h: aB'i . f B " " - ^ dB"!,.
By 5 . 1 3 , t h e r e e x i s t s a P . L .
> b'^ w i t h k | a B ^ = h
s u c h that
(B^, gB"^) a r e u n k n o t t e d p r o p e r ball p a i r s .
i s a P . L. h o m e o m o r p h i s m ,
a | f B ' " = gf
.
fB""
isaP.L.
homeomorphism
and k | fB^" = fg"^h.
is a P . L . h o m e o m o r p h i s m , and a I
h j B^ —> B ^
The m a p a = h k " ^ : b'^ ^ So
Off = g.
B^
Moreover,
= i d e n t i t y , so a i s a m b i e n t i s o t o p i c to t h e i d e n t i t y k e e p i n g
BB'^ fixed.
Unknotting C o n e s We s t a t e t h e following w i t h o u t proof: ( L i c f c o r i s h ' s T h e o r e m ) If f and
g a r e P . L . e m b e d d i n g s of v . K into
|and V a j o i n a b l e p o i n t , w i t h f'^CSB^^) = >dimv;K ^ q - 3 , t h e n
B^,
K a polyhedron
= K, and if f|K = g | K , and if
f and g a r e ambient isotopic keeping
aB*^ fixed.
-128] C h a p t e r VI: § 1.
Isotopy
C o n c o r d a n c e , I s o t o p y , A m b i e n t I s o t o p y , a n d I s o t o p y by M o v e s . Definition .
The e m b e d d i n g s
f and g of
a r e c a l l e d i s o t o p i c if t h e r e e x i s t s a P L m a p 1)
=
E q u i v a l e n t l y , we s a y t h a t p r e s e r v i n g embedding ( F(x,t) = ('F(x),t)). We s a y t h a t
F: M X I
> Q such that
= ^ ( x . t ) .) f and
F : MX I
g a r e i s o t o p i c if t h e r e e x i s t s a level]
> Q X I such that
The relation between
f and
F
and F
^^ = f and F^ = g, i s "Flx.t) = ( F ( x , t ) , t ) . i
g a r e a m b i e n t i s o t o p i c if t h e r e e x i s t s an a m b i e n t
h: Q X I —> Q X I w i t h h o f = g.
We s a y t h a t F:MXI X e
Q (PL spaces)
F^ = g
2) F^ is an e m b e d d i n g ,
isotopy
M into
f and g a r e c o n c o r d a n t if t h e r e e x i s t s
a P L embedding
- > Q X I w i t h F ( x , 0) = (f(x), 0) a n d F ( x , 1) = (g(x), 1) for a l l
M. »
Definition . morphism,
h|Q-X
sup{h) C X C Q.
h; Q —> Q is a P L h o m e o -
= s u p p o r t of h.
Then
We s a y h
^
h i s s u p p o r t e d b y X if and o n l y j
is the i d e n t i t y .
If Q i s a P L in
Q is a P L s p a c e and
sup(h) = j^xe Q | h x / x |
s u p p o r t e d by X if if
If
q - m a n i f o l d and
Q as a P L subspace, then h
a p r o p e r m o v e if e i t h e r with sup(h) C B*^,
h is s u p p o r t e d by a P L q - b a l l containec
is called a m o v e .
We c a l l t h e m o v e
h | 8 Q = identity or there exists
such that
B ^ o 9Q i s a face of
B^.
B ^ C Q,
h
B ^ a q-bal
-129-
Definition . we s a y t h a t h^, . . .
If f a n d g a r e e m b e d d i n g s of
Q,
f and g a r e i s o t o p i c b y m o v e s if t h e r e e x i s t s a finite s e q u e n c e of p r o p e r m o v e s of
Q with
h, o . . . o h Of 1 r L e m m a 6. 1. below it
M into t h e q - m a n i f o l d
=
g. ®
E a c h of t h e following s t a t m e n t s i m p l i e s t h e o n e s
(f and g e m b e d d i n g s
M
Q*^).
a) f and g a r e i s o t o p i c by m o v e s . b) f and
g a r e ambient isotopic
c) f and
g are isotopic.
d) f and g a r e c o n c o r d a n t . Proof, with
b) =?> c ) .
h^f = g . c)
Define
d) .
F: MX I
-> Q X I b y F = h o ( f X l ) .
It suffices to s h o w t h a t a n y m o v e i s a m b i e n t i s o t o p i c to t h e
So l e t
C a s e 1;
h: Q X I —5> Q X I be an a m b i e n t i s o t o p y
Clear.
a) ==> b). identity.
Let
h; Q —> Q be a m o v e . Sup(h) C B*^ C Q a n d h | 9 0 = i d e n t i t y .
Then h l a s ' ^
identity, so h b'^ i s a m b i e n t i s o t o p i c to t h e i d e n t i t y k e e p i n g Hence h i s a m b i e n t i s o t o p i c to t h e i d e n t i t y ( k e e p i n g C a s e 2;
Supp h c B ^ c Q,
I F .J == c l ( 9 B ^ - F ) .
a PL define
Then by continuity,
h o m e o m o r p h i s m sending k: A^ X I
B ^ n BQ = a face
F
F
of
B^.
Let
Let a
B^
into a p r i n c i p a l face
X 1 = a h a " ^ , k | c l ( A - A^) X I = i d e n t i t y ,
aB^^ fixed.
Q-B*^ fixed).
h F^ = i d e n t i t y .
> A^ X I b y f i r s t p u t t i n g
is the
A^
— A
of A*^.
k | a'^ X 0 = identity, k(A^; l / 2 ) = (A^, i / 2 )
and
-130A^ = b a r y c e n t e r of A
q
XI.
Then
A^; t h e n e x t e n d i n g
k , b y j o i n i n g up l i n e a r l y , to
k is an a m b i e n t i s o t o p y e n d i n g in aha
C1(A - A^) fixed. ing 01(6*^ - F )
Therefore
fixed,
T h e o r e m 6. 2.
and so
h|B^
-1
and
i s a m b i e n t i s o t o p i c to t h e i d e n t i t y k e e p -
If Q i s a c o m p a c t q - m a n i f o l d and H: Q X I — Q X I
p r o p e r m o v e s of Q s u c h t h a t
K
Let
,n+l XI C E .
embedding. , let
H
K triangulate
= h.o 1 1
Q.
Given a l i n e a r m a p
... oh
Assume
h^ , . . . , h
. r
(KJ ^ E " , and v i e w
^ : K —> I,
K
K XI
i s an
p^ : K X I -—-> K be p r o j e c t i o n on the f i r s t f a c t o r .
Q
and p ( K X I) b e s u b d i v i s i o n s m a k i n g H J A / K X I )
0- 6 p(K X I).
L e t i C cr
whose projection under simplex
H ^(cr ).
of l e s s t h a n
Since
-n/Z
of l e s s t h a n
be a v e r t i c a l l i n e s e g m e n t in
P : K X I —3> I i s a point). H is level preserving,
with the v e r t i c a l .
an upward pointing v e c t o r , then
Given
H
such that
simpl
cr (i. e. a l i n e
i ) i s a l i n e in the H \ i ) m a k e s an angle
( M o r s p r e c i s e l y , if i
is v i e w e d a s
i ) is a v e c t o r which m a k e s an angle
H ^(f ) i s p o s i t i v e . ) M o r e o v e r , b y l i n e a r i t y of
H on s i m p l i c e s , t h i s a n g l e i s i n d e p e n d e n t of t h e c h o i c e of f Since
(3(KXI):
ir/Z w i t h , s a y , t h e v e r t i c a l unit v e c t o r ; e q u i v a l e n t l y , t h e l a s t
c j - o r d i n a t e of t h e v e c t o r
tical.
of
= Let
Let
Let
i
h i s i t s e l f a m b i e n t i s o t o p i c to t h e i d e n t i t y .
i s an a m b i e n t i s o t o p y , t h e n t h e r e e x i s t s a finite s e q u e n c e
Proof.
keeping
^(KXI)
H ^(i)
i s a finite s i m p l i c i a l c o m p l e x , t h e ^ c - x i e t i
m a k e s an a n g l e
l i n e in a s i m p l e x of
ir- a, (
p(K X I).
-
ii/< 'r, '
< (p w i t h t h e v e r t i c a l I'f H i s tn\ ^ - -rical
-131-
On t h e o t h e r h a n d , t h e r e e x i s t s < 5, then if (i,^)(cr)
has diameter
cr e K, a n y l i n e s e g m e n t c o n t a i n e d in the ( c o n v e x l i n e a r c e l l )
m a k e s an a n g l e of at l e a s t
Now meets
5 > 0 s u c h t h a t i£
separates
(l X
(p w i t h t h e v e r t i c a l .
K X I.
in at l e a s t o n e point.
s u c h a path and \
1
=
[s | K s ) <
KXi
T h i s is b e c a u s e if
t h e n if \ ( I ) n
^
(s (X^(s) > ^ ( s ) / and
That is, a path from
=
I —> K X I i s
the sets
f o r m a s p l i t t i n g of
I by disjoint,
n o n - e m p t y o p e n s e t s , c o n t r a d i c t i n g t h e c o n n e c t e d n e s s of I. "broken line"
H ' ^ ( X X I), X £ K, m e e t s
However,: ^
and
(i,^)K
X I)
and IQ h a s t
m e e t in at m o s t one point.
away f r o m | ) m a k i n g an a n g l e of at m o s t T|
lies inside
and (when w h e n d i r e c t e d
lies outside this cone.
point of i n t e r s e c t i o n w i t h s m a l l e s t
F o r if
t^ / 1, fe^mduf
c o - o r d i n a t e g r e a t e r than t^, then
the solid c o n e c o n s i s t i n g of all r a y s s t a r t i n g at
If Tj e ( i , 0 ' ) K , h o w e v e r ,
Therefore the
in at l e a s t o n e point.
is a point of i n t e r s e c t i o n w h o s e c o - o r d i n a t e i n I i s
TJ £ H ~ ^ ( X X I )
to K X 0
This p r o v e s that the
t c o - o r d i n a t e i s t h e o n l y point of i n t e r -
section. Therefore
^
= p£>Ho(i,^)
•K Then t h e r e e x i s t s a finite s e q u e n c e
is a h o m e o m o r p h i s m if
. . , , ^^^ of l i n e a r m a p s of
-I" Such t h a t 1) ^ J K ) = [O} 2) d i a m j2(.(K) < 5 3)
and
^^
and all
d i a m ^(K) < 6.
^^(K) = ( i j i.
a g r e e on a l l but one v e r t e x of
K.
K into
I
-132 Hf a? T h e n ^^ = 1 a n d ^^^ ~ tex such that *
^
Consider
^(v).
^^
*
•
Then
_1 •
d o e s not m o v e
8K.
Let v
be the v e r -
is supported by
* a n d is t h e i d e n t i t y o n ^^ ^(link(vi K)).
^(star{v;K)) ^
'
If
veBK',
I
T h e r e f o r e if v / 9K,
| s t a r { v ; K') | O ( 9 K ' ) = i s t a r ( v ; 3
*
i s a face of j?.
star(v;K') .
Since
^ i s a h o m e o m o r p h i s m , it follows that
IS a p r o p e r m o v e . T h e o r e m 6. 2 h a s s e v e r a l i m p r o v e m e n t s in e a c h of t h e following, q
H: Q X I
> Q X I is an ambient isotopy.
In a l l but t h e l a s t ,
Q
is a com-
pact P L q-manifold. 6 . 2. 1.
If or i s a n o p e n c o v e r of Q, t h e n or.e m a y c h o o s e t h e m o v e s
h^ s u c h t h a t
~
Proof. Let
e
Let
° ••• ® aXI=
to be s u p p o r t e d b y e l e m e n t s of
[ u x i j u e a } .
0 be t h e L e s b e s g u e n u m b e r of
i n d u c e d by t h e t r i a n g u l a t i o n s u b d i v i s i o n of K, of K^^^ ^ i ^ • barycentric Let
r
K of
Q.
H'^aXI)
covers
a . Q X I.
H ^ o - X I) w i t h r e s p e c t to t h e m e t r i c Let
be t h e r - t h b a r y c e n t r i c
s u c h t h a t m e s h K^^^ = m a x i m u m d i a m e t e r of a s i m p l e x g e n e r a l m e s h K' < m e s h K, n = d i m K, K' = f i r s t n n.+l
subdivision.)
6 > 0 be s u c h t h a t
is an e m b e d d i n g .
1) 6 < ~ € ,
Now c o n s t r u c t
2)
dim
5
a s in 5. 2, but w i t h K
implies replaced
(r) t h r o u g h o u t by t h e t r i a n g u l a t i o n s u p ( h . ) C j2f. 1
( s t a r ( v ; K^^^)).
K^ But
of
Q, and l e t h^ =
diam[( 1 X
^
t h e d i a m e t e r of
Then
_ ) ( s t a r ( v ; K^^^)] < e :
for
1 Jstar(v;K^^^)
i s a t m o s t \ €.
T h e r e f o r e (1 X
^ K
-133-
l i e s in s o m e e l e m e n t of
H"^(Q'X I), a n d so
jZf. _ ^ ( s t a r ( v ; K^^^)
l i e s in s o m e
e l e m e n t of a . 6. 2. 2.
If H k e e p s t h e b o u n d a r y fixed,
proper move
6. 2. 3 . the m o v e s
Let
h. k e e p s t h e b o u n d a r y fixed.
If t h e h y p o t h e s i s of 6. 2. 1 a n d 6. 2. 2 hold s i m u l t a n e o u s l y ,
Clear.
6 . 2. 4 .
Let
X QQ
H: Q X I — > Q X I
h^, . . .
such that
Let
of X in Q, w i t h
Q*^ not c o m p a c t .
T h e n t h e r e e x i s t s a s e q u e n c e of
H^ = h^o . . . • h ^
on a n e i g h b o r h o o d of
X.
K C K be finite c o m p l e x e s t r i a n g u l a t i n g t w o n e i g h b o r h o o d s o Int|K| D I ^q I•
|N{ C i n t K b y c h o o s i n g
m a p we m a y s t i l l define a s for
be an a m b i e n t isotopy,
be a c o m p a c t P L s u b s p a c e .
Proof.
that
then
h^ m a y be c h o s e n s o t h a t t h e c o n c l u s i o n s hold s i m u l t a n e o u s l y .
Proof.
moves
t h e n we m a y a s s u m e e a c h
K
^ ~ suitably.
^ ' = p . H o( 1,
6. 2, t h e r e e x i s t s 6 > 0
K). If
—> I = [O, l ]
N —> Q.
such that
We m a y a l s o s u p p o s e is a l i n e a r
By t h e s a m e a r g u m e n t
d i a m ^(N) < 6 i m p l i e s
^
i s an
embedding. Now suppose that
—^ ^
Ji^jFr N) = j i f j F r N) = { t } . , 1 Z o
Then
such that (^(f F r N = 1
d i a m ^^(N) < 5
* F r N. Z
and
So F r j ^ f N = F r jZf^'N. 1 z
i Now
x € ^^ Int N if a n d o n l y if
H" (X X l )
intersects
liappens if and o n l y if H ' ^ ( X X 1) h o m o l o g i c a l l y l i n k s j l a r l y for ii
^ . ^
Thus
0
N = 1
N. ^
(l X
(l X
which N).
Simi-
T h e n b y a r g u i n g a s in t h e p r o o f of 6. 2,
-134 V* d * 1 o n e c a n find a s e q u e n c e of p r o p e r m o v e s of P^^ N , fixed o n F r N, whose^ composite is
)
)
•
E x t e n d i n g t h e s e m o v e s to a l l of Q by the *
i d e n t i t y o u t s i d e of N, we s e e t h a t identity.
Therefdre
Now l e t ^ N
* „1
(j^i^
)
is i s o t o p i c by m o v e s to the
i s i s o t o p i c b y m o v e s to
.
0 = t = t^ < t^ < . . . < t ^ = t^^^ = 1, w i t h
—5> I, - 1 < i ^ r, s u c h t h a t
^.(v) = t. + " k t . . . - t.) i 1 (U IT 1 1
^^(v) = t^ if
v € F r N is a v e r t e x ,
if V e N - F r N is a v e r t e x .
V e F r N and ^^{v) = t, " \ Then and a g r e e on K^.
^ "2 and
Define i1j.(v) = t. 1 1
if v e N - F r N, v a g r e e on F r N.
if
always a vertex. So and
"S
*
a r e i s o t o p i c by m o v e s . 0. .
Then
h = h h
,. . .h,
r r-i C o r o l l a r y 6. 3; then § 2.
Let
h^ be a n i s o t o p y by m o v e s t h r o w i n g is an i s o t o p y by m o v e s and h K
1
r/
/
If f, g: m"^—* Q'^ a r e two e m b e d d i n g s , M
f and g a m b i e n t i s o t o p i c i m p l i e s
onto
= H 0
I
K . 1
0
compact,
f and g i s o t o p i c b y m o v e s .
L o c a l l y U n k n o t t e d Manifold P a i r s and t h e "Weak" I s o t o p y E x t e n s i o n T h e o r y Definition .
manifolds,
and
m a n i f o l d p a i r if
Say (Q, M) is a P L manifold p a i r ; M i s a P L s u b s p a c e of M H 9Q = 9M.
Q.
i. e.
We s a y t h a t
Q and M a r e P L (Q, M) i s a p r o p e r
(Q, M) is s a i d to be l o c a l l y u n k n o t t e d if
g i v e n a n y x e M, t h e r e e x i s t s a n e i g h b o r h o o d
V of x
in Q s u c h t h a t
( V , V n M) i s an u n k n o t t e d b a l l p a i r ; o b s e r v e t h a t it i s a p r o p e r b a l l p a i r if it i s a b a l l p a i r at a l l .
-135-
L,emma6.4.
If K C K t r i a n g u l e s o
l o c a l l y u n k n o t t e d if and only if g i v e n a n y
M C Q , then
(Q,M)
is
A € K^, (link(A; K), link(A; K^))
is an u n k n o t t e d s p h e r e o r b a l l p a i r . Proof. I
=> .
If K' C K'
I
A = v is a v e r t e x .
is any subdivision, then the radial projection
link(v;K') of
F i r s t we c o n s i d e r t h e c a s e w h e n
> link(v;K)
link(v; K' ). o
into s i m p l i c e s
H e n c e t h e s a m e i s t r u e of t h e p s e u d o - r a d i a l p r o j e c t i o n , a
P L homeonnorphism.
p unknotted.
I link(v; K^)
c a r r i e s t h e s i m p l i c e s of
H e n c e it suffices to show (link(v; K ' ) , link(v; K^))
is
But b y c h o o s i n g a s u i t a b l e s u b d i v i s i o n (for e x a m p l e , the r^h b a r y -
c e n t r i c , s o m e l a r g e r ) , we m a y s u p p o s e t h a t t h e link p a i r of v w i t h r e s p e c t to t h i s s u b d i v i s i o n l i e s in a n e i g h b o r h o o d an u n k n o t t e d p r o p e r b a l l p a i r . case
Q = A^-A^^^
a v e r t e x ) of If (v.
and
V of v
such that
(V, V n M)
is
In o t h e r w o r d s , it suffices to c o n s i d e r t h e
M = A ^ , and v e A^
i s a g i v e n point (not n e c e s s a r i l y
A^.
V € A^, s t e l l a r s u b d i v i d e b y s t a r r i n g V • A^).
T h e n t h e l i n k p a i r of
r
A^
at
r, getting the p a i r
is
the standard
If v e A, w h e r e
A
J*
unknotted s p h e r e p a i r of t y p e (B
(r+i-l,r-l).
0), s t e l l a r s u b d i v i d e by s t a r r i n g •
T h e t h e l i n k p a i r of v
A at
r
to get t h e p a i r ( v A B A ^ ^ \ v A B ) ,
• i+1 •
is (ABA
, AB), an u n k n o t t e d b a l l p a i r .
To p r o v e t h e r e s u l t of a n a r b i t r a r y s i m p l e x
A of K^, a s s u m e t h e r e s u l t
by i n d u c t i o n for s i m p l i c e s of l o w e r d i m e n s i o n t h a n A. [of A. and put A = a . B .
=A.B,
Let
a be a v e r t e x
( l i n k ( A ; K), link(A, K^)) =
l | l i n k ( a ; link(B,.K)), l i n k ( a ; l i n k ( B ; K ))].
By inductive, h y p o t h e s i s ,
-136link(B5 K^) C l i n k ( B ; K) i s a n u n k n o t t e d b a l l o r s p h e r e p a i r a n d so a l o c a l l y unknotted p r o p e r manifold p a i r . to the l i n k p a i r of t a .
As
H e n c e w e m a y a p p l y t h e r e s u l t for v e r t i c e s
in t h i s m a n i f o l d p a i r .
(link(v; K), link(v; K )) u n k n o t t e d i m p l i e s ( s t a r ( v ; K), s t a r (v;K o o'
unknotted. L e m m a 6. 5 ( w e a k i s o t o p y e x t e n s i o n t h e o r e m ) : locally unknotted manifold p a i r , with M c o m p a c t .
Let
(Q, M) b e a p r o p e r
Suppose that
h:M—>M
i s a. h o m e o m o r p h i s m w h i c h is a m b i e n t i s o t o p i c to t h e i d e n t i t y
Ij^.
there exists a P L homeomorphiam
If h i s a m b i e i
i s o t o p i c to
Ij^ keeping
Proof.
Let
c o n v e r i n g of
k : Q—5>Q w i t h k | M = li.
9M fixed, t h e n we c a n a s s u m e t h a t
K^ C K t r i a n g u l a t e
M ; i. e . ,
M C Q.
k i s fixed in 8qJ
or
be the star
or = { s t a r ( v ; K^) | v i s a v e r t e x of
K^} . w h e r e
s t a r ( v , K^) = | K^ | - U {cr e K^ | v / o*} . s e q u e n c e of p r o p e r m o v e s
By
Then let
Then
6 . 2 . 1 , t h e r e e x i s t s a finite
h ^ , . . . , h ^ , e a c h s u p p o r t e d b y s o m e e l e m e n t of
h ^ : M —5> M, w i t h h = h^o , . , ©h^.
If h k e e p s t h e b o u n d a r y fixed, we m a y
a s s u m e e a c h h. a l s o , 1 We a r e going t o c o m p l e t e t h e p r o o f b y s h o w i n g t h a t e a c h t e n d e d to C a s e 1;
Q.
So s u p p o s e t h a t
\r f. BK.
s u p p h ^ C s t a r ( v ; K^),
h^ c a n b e e x -
v a vertex.
T h e n h^ i s t h e i d e n t i t y o n l i n k ( v ; K^).
IVlc f c 7
( s t a r (v; K), s t a r ( v : K^)) i s a p r o p e r i m k n o t t e d b a l l p a i r , a n d i t s b o u n d a r y is the s p h e r e p a i r
( l i : - ^ • -i). l m k ( v j K^)).
m o r p h i s m of . s t a r ( v r^i } ' ' lirk^r t K ) link(v;K).
We m a y e x t e n d h^ to a p. 1. h o m e o -
by r
3 if
b e t h e i d e n t i t y on
By L e m m a 4, t M s m a p -istendt :c a p. i. h o m e o m o r p h i s m of
-137-
-A
s t a r (v; K) into i t s e l f , outside
star(v;K).
C a s e 2.
v e 9K.
is unknotted.' h
i
w h i c h we t h e n e x t e n d to a l l of Q by t h e i d e n t i t y
A s s u m e for t h e monnent t h a t
T h e n by t h e s a m e a r g u m e n t a s in C a s e 1, w e m a y e x t e n d
s t a r ( v ; K ) to a h o m e o m o r p h i s m of o
link(v;K).
s t a r ( v ; K) w h i c h i s t h e i d e n t i t y on
T h i s h o m e o m o r p h i s m e x t e n d s to
identity o u t s i d e 8(star(v;K))
link(v; K) u s t a r ( v ; K )
into i t s e l f w h i c h a g r e e s w i t h h^ on But
link{v; K ) \ j s t a r ( v ; K )). o o
l e m m a q u o t e d in C a s e 1, we m a y e x t e n d m o r p h i s m w h i c h is t h e i d e n t i t y on
h^ to
|link(v;K)
Q by t h e i d e n t i t y o u t s i d e
To p r o v e t h a t
star(v;K)
h^ is t h e i d e n t i t y on l i n k ( v ; K ^ )
on s t a r ( v ; K ) ( w h o s e b o u n d a r y is o
and i s t h e and is defined Hence by the
star(v;K), getting a homeo-
2 Fr^^ s t a r ( v ; K )
,
Now e x -
star(v;K).
( s t a r ( v ; K ) , s t a r ( v ; K^))
that it i s t h e conefon t h e s p h e r e p a i r
is u n k n o t t e d , we s i m p l y o b s e r v e
( l i n k ( v ; K ) , link(v; K^)) w h i c h is u n -
knotted b e c a u s e it i s t h e b o u n d a r y of t h e b a l l p a i r 1-emarks:
by t h e
s t a r ( v ; K ) , a n d so we get a h o m e o m o r p h i s m of
identity on l i n k ( v ; K ) .
tend to a l l of
(star(v;K), star(v;K^))
(link(v; K), link(v; K^))-
l ) k c a n b e c h o s e n to be t h e i d e n t i t y o u t s i d e of an a r b i t r a r y
leighborhood of
M.
2) It i s c l e a r t h a t if k i s c o n s t r u c t e d a s in t h e proof of L e m m a 6. 5, len k i s i s o t o p i c b y m o v e s to t h e i d e n t i t y and so a m b i e n t i s o t o p i c to t h e ^entity. 3) We a l s o p r o v e d t h a t t h e b o u n d a r y p a i r of a l o c a l l y u n k n o t t e d p a i r i s ?fally u n k n o t t e d .
-138§3.
U n i q u e n e s s of B o u n d a r y C o l l a r s a n d C o n s t r u c t i o n of C o m p a t i b l e C o l l a r a ' for P r o p e r Manifold P a i r s . Let
M C Q be compact P L manifolds, with
boundary collars
c ^ : 9M X I —5> M a n d
M A 8Q = 9 M . T h e n t h e
c ^ : 9Q
c o m p a t i b l e if c^ i s t h e r e s t r i c t i o n of
I —> Q a r e s a i d to b e
9M X I .
In t h i s s e c t i o n w e seel
how t o o b t a i n c o m p a t i b l e c o l l a r s i n g e n e r a l a n d , g i v e n a c o l l a r c^:
> M, w e c a n e x t e n d i t to a c o l l a r of c ^ . In t h e p r o c e s s w e
BMXI
p r o v e t h e u n i q u e n e s s of c o l l a r s u p to a m b i e n t i s o t o p y .
T h e s e r e s u l t s w i l l be;
u s e d to h e l p p r o v e t h e g e n e r a l i s o t o p y e x t e n s i o n t h e o r e m . Theorem
6.6.
If (Q, M) i s p r o p e r p a i r of c o m p a c t m a n i f o l d s a n d i s
a l o c a l l y u n k n o t t e d p a i r , t h e n t h e r e e x i s t c o m p a t i b l e b o u n d a r y c o l l a r s of M a n d of Q . Remark.
T h e r e a d e r w i l l o b s e r v e f r o m t h e p r o o f t o follow t h a t i t w o u l d
suffice to a s s u m e t h a t t h e p a i r (Q, M) i s l o c a l l y u n k n o t t e d a t t h e b o u n d a r y ; i. e . e v e r y point i n t h e b o u n d a r y of
M h a s a n e i g h b o r h o o d in Q , V, s u c h that
(V, V n M) i s a n u n k n o t t e d p r o p e r b a l l p a i r .
One w o u l d n e e d a v a r i a n t of
L e m m a 5 . 4 . T h e d e t a i l s a r e left t o t h e r e a d e r . Proof.
L e t Q""" = (Q X O) u (9Q X I) a n d l e t m"^ ^^ (M X O) L' (8M • " .
We w i l l c o n s t r u c t a P L h o m e o m o r p h i s m
Let A^,
K
o
M ^ into M,
9Q X I ——f- BQ by m a p p i n g (x, l ) onto x .
which sends Let
Q " ^ — Q carrying
C
K
t r v-_ be
-
: ia-'.-
M
C
—
Q.
Let
o^: aK
K'
be
t,b
barycentric
first
derive
decreasing dimension.
-139-
Let
s's A. 1
be t h e d u a l c e l l of A. in K and l e t 1
If A £ K , l e t i o
# A. be its dual c e l l in 1
A"" and A. be t h e d u a l c e l l s of A. in K and i, o i,o 1 o
OK. dK , o
respectively.
« We a r e going to c o n s t r u c t h o m e o m o r p h i s m s w h i c h , if A. € K l
Let A £ K . i o a £ K . i o Claim:
, send
(A.
O
B = (A* X 0) i 1 ' Let
X O) u (A.
1,0
C.
1
U {A^
1
X
XI)
onto
Let
B.
Ju = cl (9A7 - A ) and 1 1
A.
= ( a " X O) 1, o >< ; c. = cl(AA 1, o
1,
o
U (A*
1,
(B.,B. 1
, 1,
o
) i s an u n k n o t t e d b a l l p a i r .
T h e following p i c t u r e i n d i c a t e s t h e s i t u a t i o n :
B: vo
\
^ — c. 1 ^
o
X I) if
^ - A. ) if 1. o
(See t h e s e c t i o n on d u a l c e l l s , C h a p t e r I . ) If A. € 9K , t h e n 1 o
*
X, o
1,0
I).
#
(A^ X O) u (A^ X I) —> A^
-140 To p r o v e t h e c l a i m , w e u s e t h e p s e u d o - r a d i a l p r o j e c t i o n p: A. > A. l i n k ( A . ; K ) , U n d e r t h i s m a p , A. i s c a r r i e d onto ^ 1 1 1 1,0 A . . l i n k ( A . ; K ). L e t F , = ( C . , C ) a proper'ball pair. Under p 1 1 0 1 1 1, o s e c t i o n on d u a l c e l l s ) , t h i s p a i r b e c o m e s t h e p a i r a n unknotted b a l l p a i r .
The pair
(seethe! I
( l i n k ( A ^ ; K ) , link(A^;
dF ^ = (8C., 8C. J
(link(A; 9K), link(A; 8l
is also unknotted. Let
F
#
Z
=(A.,A. ); 1 i, o
unknotted p a i r .
under
Therefore
p it i s c a r r i e d onto A . p ( a F ), a l s o an -i-
F ^ X I is unknotted.
l fj
Let
F ^ = ( F ^ X 1) u ( 9 F ^ X I), an u n k n o t t e d p a i r b e c a u s e t h e r e i s a p. 1. h o m e o morphism
(F
p a i r in v. 8 F
X 1) u ( 9 F
X I) —> v . dF
(To s e e t h i s , e m b e d t h e f i r s t
s u i t a b l y a n d u s e a p s e u d o - r a d i a l p r o j e c t i o n , a s i n t h e follow-^
ing p i c t u r e ;
The identity
9F
> 9F Ld
h^ : F^
> a(9F.;:
e x t e n d s to h o m e o m o r p h i s m s Lt
-141-
h^sF^
-> c ( a F ^ ) ;
note that
aF^ = SF^ =
E x t e n d i n g h o m e o m o r p h i s m s defined on b o u n d a r i e s by t h e s e nnaps, we get h o m e o m o r p h i s m s ,
*
* X
-> (be). d F ^ .
h^rF^XI Finally,
-> a b ( d F ^ )
-> ( a b 8 F ^ ^ b c B F ^ ) = a c ( d F ^ )
^ ^ ^ ^ ^ (B^. B.
morphism.
is a h o m e o -
This proves the claim.
Now w e define i n d u c t i v e l y a s e q u e n c e of p. 1. h o m e o m o r p h i s m s « # • k . : ( A . X O) U (A. X I)
> A^
w i t h t h e following p r o p e r t i e s :
1)
k.(x, 1) = X
if X e 3 0 ;
2) '
k.(x, 0) = X
if X € a T - A. ; 1 1
3)
If
t h e n k. m a p s 1 ^
4) '
If A. < A. 1 J
'
A. € K , 1 o
(A." X O) U (A. X I ) i,o i,o
onto
A? ; i,o
and
H a v i n g defined
( = > i ^ j k. for J
and a ' ' C A.), t h e n k . = k . U a T X 0) U (A. X 1). J 1 J 1 J J
j
and 4), and t h e n e x t e n d it to a l l of I the " c l a i m , "
H a v i n g defined t h e
we define
by c o n d i t i o n s l ) , 2 )
B^ to s a t i s f y 3), if it a p p l i e s , by u s i n g k . , w e define
, by t h e i d e n t i t y on (Q X O) i-1 IS the d e s i r e d h o m e o m o r p h i s m .
k.|9B.
c:Q
(A* X O), to a l l of ^
> Q by e x t e n d i n g Q"*" .
Clearly
c
-142
To s o l v e t h e p r o b l e m of e x t e n d i n g a b o u n d a r y c o l l a r on t h e s m a l l e r m a n i f o l d of a m a n i f o l d p a i r , we f i r s t m u s t c o n s i d e r t h e q u e s t i o n of c o m p a i r i n g b o u n d a r y c o l l a r s of a m a n i f o l d . Lemma 6.7.
Let
a p. 1. e m b e d d i n g Suppose that a n d h: K X I
c K
c ! K X [O, £ ] — > o
X [0,£]
K X I with
is level p r e s e r v i n g .
is l e v e l p r e s e r v i n g ;
Consider
c(x, O) = (x, O), x e K.
> K X I, a p. 1. h o m e o m o r p h i s m ,
1) h « » c | K X [ 0 , 6 ] 2) h
K^ C K be finite s i m p l i c i a l c o m p l e x e s .
T h e n t h e r e e x i s t s 0 < 5 <E such that:
and
is a m b i e n t i s o t o p i c to the i d e n t i t y Tceepihg
(K X 91) U c(K^ X [ 0 , £ ] )
fixed. Proof. of K X 0 a n d Let
L e t a and p b e s u b d i v i s i o n s s u c h t h a t K X [ 0 , £ ] , and c : f f ( K X [ 0 , £ ] )
5 > 0 be s u c h t h a t no v e r t i c e s of a
and
0 < t < 5 and s u c h t h a t c(K X [0, 5] n (K X 1) = subdivisions
a;' and
P' of
a contains triangulations!
3> p(K X I) i s s i m p l i c i a l . p have a level t
such that
Now c h o o s e f i r s t d e r i v e d
a and p, u s i n g t h e following s t a r r i n g p o i n t s :
-143-
l)
tr h a s l e v e l
2)
If
0- e a{K
6 if X O)
o" h a s any p o i n t s of l e v e l cV
,
c(a) ;
o 3)
If
0-€
X [0,
I) ,
4)
a arbitrary otherwise .
CO - ca
;
N o t e t h a t 3) and l ) a r e c o n s i s t e n t b e c a u s e KX[0,8].
Now define
and
cr i s l e v e l p r e s e r v i n g on
c ' : a ' ( K X [0, £ ]) —> (3'(K X I) to be the s i m p l i c i a l
map defined by c ' ( a ) =
Then
c'
is a s i m p l i c i a l e m b e d d i n g w h i c h is
l e v e l - p r e s e r v i n g on K X [0, 6] and a g r e e s w i t h Now l e t
c on K^ X [0,£ ].
P" b e a f i r s t d e r i v e d s u b d i v i s i o n of
c: Qr'(K X [ 0 , £ ])
(3 such t h a t
> P"(K X I) i s s i m p l i c i a l ; it i s c l e a r t h a t s u c h a s u b d i v i s i o n
e x i s t s , and t h a t we m a y c h o o s e 1) p"(K X 1) = p'(K X 1) and
(3" s u c h t h a t P"(K X O) = P'(K X O) ; and
2) P"(c(K^ X [ 0 , e ])) = P'(c(K^ X [0,£ ])). Then let
h : P"(K X I) — > p'(K X I) be t h e n a t u r a l s i m p l i c i a l h o m e o m o r p h i s m
b e t w e e n two f i r s t d e r i v e d s of t h e s a m e c o m p l e x . K X [0,£ ], to s e e t h a t
clearly.
Then h o c = c'
on a l l of
M o r e o v e r , b y m o v i n g o n e v e r t e x at a t i m e , it is e a s y
h i s a m b i e n t i s o t o p i c to
1 by m o v e s k e e p i n g
(K X 91) u c(K^ X [0,£ ]) fixed. L e m m a 6. 8.
If c , and c
f 6 > 0 and an ambient isotopy
a r e b o u n d a r y c o l l a r s in H of
M, fixed in
9M, s u c h t h a t
9M X [O, 6] i s defined and l e v e l p r e s e r v i n g . nianifold. )
M, t h e n t h e r e e x i s t s
(M = c o m p a c t P L
-144Proof.
Let
6>0
be such that
exists an ambient isotopy that
"
I
H'
of
c ^ ( 9 M X [O, £ ] ) C i m c ^
9M X I, fixed
8M X 91, a n d
^ [0. S]) i s l e v e l p r e s e r v i n g .
Define
•
Then there
6<£,
such
H^ o n
-1
by H = c H ' c
C;>(8MXI) extend
H^ to a l l of
L e m m a 6. 9.
.
Since
If
c i s a b o u n d a r y c o l l a r of
H ^ c ( x , t ) = c ( x , 5t), a l l Let
is the identity on
8 M X 1 , we may
M b y t h e i d e n t i t y w h e r e it i s n o t already- d e f i n e d .
t h e r e e x i s t s an a m b i e n t isotopy
Proof.
H'
H of
M and
M, fixed on
0 < 5 < 1, t h e n
9M, s u c h t h a t
( x , t ) e 9M X I.
M^ = c l ( M - I m a g e s c), a P L m a n i f o l d .
be a boundary collar.
Define
c _ : 9 M X [0, 2] —> 9M
Let
c^:
9M^XI—
by
£4
0 ^t< 1 .
c ^ ( x , t ) = c ( x , t) C2{x,t) = c j ( c ( x , l ) , t - l ) Then
c^ Let
.
i s a w e l l - d e f i n e d e m b e d d i n g , s i n c e c j ( c ( x , l ) , 0 ) = c ( x , 1). a : [0, 2] X I
[0, 2] X I b e a P L a m b i e n t i s o t o p y w i t h
a | (0 X I) U (2 X I) = i d e n t i t y a n d h: M X I
,
5> M X I
ar^(t) = 5t if 0 ^ t < 1.
N o w define
by h[c2(x.s).t] = [c2(x.pQ<s.t)).t]
h(y, t) = (y, t) for a l l
y € cl(M - Im c^).
jection on the first coordinate.
Here
O b s e r v e that
p: [O, 2] X I
> [O, 2] i s p r o -
h is well-defined as
[c^Cx, pQr(2,t)),t] = [ c 2 ( x , 2 ) , t ] ;
and h[c2(x,0),t] = [c2(x,0),t] = [x,t],
h 9M X I = i d e n t i t y .
h
The m a p
i s p i e c e w i s e l i n e a r , for i n
f i r s t c o o r d i n a t e i s ^ i s t th(^ c o m p o s i t e :
^ I
so its
-145-
Im c
X I —
> aMX[0, 2]XI
^^
>
8MX[0,2]
L*
M To show h is a h o m e o m o r p h i s m , Then t = t'.
Therefore
x = x'
suppose that
and
h(c (x, s), t) = h(c ( x ' , s ' ) , t')-
p, a ( s , t) = p, Q;(S', t ' ) .
p r e s e r v i n g h o m e o m o r p h i s m , this i m p l i e s that
s = s'.
As
a is a level
So h is o n e - o n e ,
and h is c l e a r l y o n t o . To c o m p l e t e the proof, we j u s t n o t e t h a t if 0 < t < 1, h ( c ( x , t ) , 1) = =
1)), 1) = (c^CxjSt), 1) = ( c ( x ; 6 t ) , l ) .
L e m m a 6.10.
Let
c^ and c ^
be b o u n d a r y c o l l a r s of
Im c^ = I m c^, and s u p p o s e in a d d i t i o n t h a t level preserving.
c^
M, w i t h
^ ^ ^ ^ —^ ^ ^ X I
T h e n t h e r e e x i s t s a n a m b i e n t i s o t o p y h of
is
M , fixed on
aM., s u c h t h a t h ^ o ( c J a M X [0, 1 / 2 ] ) = c ^ l S M X [0, 1 / 2 ] . Proof.
L e t or
Q;(X, t) = ( a^x, t). P(t, i) =
;0
H
,
>I
We m a y w r i t e
be a p. 1. m a p s u c h t h a t
(3(t,0) = t,
- < t < 1
P (0, s) = 0 for
Now define Then
(3:1X1
> 9M X I.
0 < t < 1/2
Zl-1 P { l , s ) = 1,
Let
9M X I
0 < s < 1.
H^: 8M X I
> 8M X I by p u t t i n g
defines a n a m b i e n t i s o t o p y of
H J x . t ) = H^(x',t'), then t = f
and
9 M X I; ^^(x) =
H^(x, t) = (
gj(x),t).
for if ^^(x)
implie S
X =
x'.
-146-
T h e a m b i e n t i s o t o p y defined by
H
is a p. 1. m a p b e c a u s e it i s t h e S
c o m p o s i t e of p. 1. m a p s . Define
h: M X I
>MXI
by
h(c (x, t), s) = (c H (x, t), s) , X
h.(y, s) = (y, s) if
y e cl(M - Im c^).
morphism, as
^
s
Then h is a well-defined p . l .
^^ ~ '^Z^'^pll g ) ' ^ ^ ~
h ( c ^ ( x , t ) , 0 ) = ( c 2 H ^ ( x , t ) , 0 ) = (c2(o;^(x),t), 0) = ( c ^ ( x , t ) , 0 ) ;
t<j,
M o r e o v e r , if (c^Cx.t),!). so
homeo-
h(c ^{x, t), i) = {c^ia^^^
F i n a l l y , if t = 0,
so h^ = i d e n t i t y
^^(x) ,t), i) =
t), i) =
h ( c ^ ( x , t), s) = ( c ^ l x , t), s) = (c^(x, t), s) = (x, s),f,
h fixes t h e b o u n d a r y . Theorem 6.11.
( U n i q u e n e s s of B o u n d a r y C o l l a r s ) .
two b o u n d a r y c o l l a r s of
M, t h e n t h e r e e x i s t s a n a m b i e n t i s o t o p y
fixed on OM, w i t h h e = c . 11 ^ P r o o f . B y 6 . 8 and 6 . 9 , t h e r e e x i s t fixed on
9M
ambient isotopies
h of
H and
are
M,
K of
M,
s u c h t h a t if
c ' = H . c , and c ' = K , c _ , t h e n I m c ' = I m c ' i l l 2 1 2 1 2 is l e v e l p r e s e r v i n g . By 5. 10, w e m a y s u p p o s e a f t e r a n o t h e r
and ( c ' ) ~ ^ c ' ^ 1
a m b i e n t i s o t o p y t h a t we a l s o h a v e again, with
If c^ a n d c ^
c^ = c ^ on
8M X [O, 1 / 2 ] .
Now a p p l y 6 . 9 ,
6 = i/Z.
C o r o l l a r y 6. 12. manifold p a i r .
Let
(Q, M) b e a l o c a l l y u n k n o t t e d c o m p a c t p r o p e r
G i v e n a b o u n d a r y c o l l a r - c^
on M, t h e r e e x i s t s a c o l l a r
c^
of Q, c o m p a t i b l e w i t h c^ . Pxc o i .
By T h e o r e m 6. 6, t h e r e e x i s t c o l l a r s
f - s p r .fiv- ly, w h i c h a r e c o m p a t i b l e . homeomorphism
M
-
c and
c'
of
M and Q
By T h e o r e m 6. 11, t h e r e e x i s t s a p . l .
M, a m b i e n t i s o t o p i c to ' h e i d e n t i t y , w h i c h k e e p s |
|
-1479M fixed,
such that
he = c ^ .
By t h e w e a k I s o t o p y E x t e n s i o n T h e o r e m ,
L e m m a io, 5, t h e r e e x i s t s a p . l . h o m e o m o r p h i s m w i t h k(M) = M and k | M = h .
4.
Put
c^ = k
k: Q —> Q, fixed on
c'.
The l8otopy Extension T h e o r e m . Definition .
Let
F:MXI—>QXI
M and
Q be P . L . m a n i f o l d s .
i s s a i d to be p r o p e r if
l o c a l l y u n k n o t t e d if in a d d i t i o n , for a l l manifold p a i r is l o c a l l y u n k n o t t e d :
F"
X I) ^ 9M X I.
of
Q
F
is always
d i m Q - d i m M ^ 3.
a p r o p e r locally unknotted isotopy.
' ambient isotopy H
It is called
0 < s < t < 1, t h e following p r o p e r
T h e o r e m 6. 12 ( I s o t o p y E x t e n s i o n T h e o r e m ) :
compact, be
An i s o t o p y
(Q X [ s , t ] , F ( M X [ s , t ] ) ) .
locally u n k n o t t e d if it i s p r o p e r and
M
9Q,
Let
F i M X I —> Q X I,
T h e n t h e r e e x i s t s an
such that
F = H (F^ X Ij). Furthermore,
if F 8M X I = ( F o
that
H
so
H | 8Q X I = i d e n t i t y .
iRemarkss
l)
^.12
m a y be g e n e r a l i z e d
| ? " ^ ( 8 Q X I) a N X I, w h e r e
|(p08 8ibly ^•otopieB by ••ll
9M) X 1 , t h e n we m a y c h o o s e i
One
as
follows:
Call F
a l l o w a b l e if
N i s a n ( m - 1 ) - m a n i f o l d , m = dim M, in
8M
c a n define t h e n o t i o n of l o c a l l y u n k n o t t e d for a l l o w a b l e
defining t h e n o t i o n of u n k n o t t e d for c e r t a i n t y p e s of n o n - p r o p e r
pairs. One can
p r o v e t h a t if d i m Q " d i m M > 3, a l l a l l o w a b l e i s o t o p i e s
l o c a l l y iaaknotted, and o n e c a n p r o v e an i s o t o p y e x t e n s i o n t h e o r e m for
J'ich isotopies.
-1482) If
q - m > 3, o n e c a n p r o v e t h e c o r r e s p o n d i n g t h e o r e m for i s o t o p i e s
F:KX1—^>QX1 K
where
a s u b p o l y h e d r o n of
Unsolved P r o b l e m .
K i s a p o l y h e d r o n and F ' ^ ( 9 0 X 1 ) = K^ X 1,
K.
F i n d a d e f i n i t i o n of l o c a l l y u n k n o t t e d for i s o t o p i e s of
p o l y h e d r a in m a n i f o l d s w h i c h w o u l d m a k e t h e t h e o r e m w o r k for c o d i m e n s i o n ' < 3. 3)
One c a n a l s o g e n e r a l i z e by r e p l a c i n g
I by I^.
We s h a l l do t h i s l a t e r
in s e c t i o n 5. To p r o v e
6 . 1 2 , we s t a r t by p r o v i n g a r e s t r i c t e d v e r s i o n in a s p e c i a l
case. Lemma 6.12.1. isotopy,
Q and
ther exists
Let F : M X I
M compact.
Suppose
Q X I b e a p r o p e r l o c a l l y unknottej F | 9M X I = ( F ^ | 9M) X 1.
£ > 0 and a P . L. h o m o e m o r p h i s m
level preserving,
Then
h: Q X [ 0 , £ ] —> Q X [0,iS],
such that
1) h | dQ X [0, £ ] = i d e n t i t y . 2) h ( F ^ x , t ) = F ( x , t ) Proof. Let
c^ and
Let
for a l l
(x, t) e M X [O, £ ].
c : (3(M X I)) X I —> M X I b e a b o u n d a r y c o l l a r .
c ^ : 9(Q X I) X I
5> Q X I be b o u n d a r y c o l l a r s s u c h t h a t the
following d i a g r a m s c o m m u t e : 9(MXI)XI •l)
( F ^ X 1) X i 9(Q X I) X I
^^
> MX I F QX I
o
X1
I
-149-
9 ( M X I) X I
MXl
F X I
(2) \/
C.
9(Q X I) X I
-> Q X I
i Q x X
iThis is p o s s i b l e b e c a u s e fpair, a n d
(Q, F^(M)) i s a p r o p e r l o c a l l y u n k n o t t e d m a n i f o l d
(Q X I , F ( M X I)) i s a l o c a l l y u n k n o t t e d p r o p e r m a n i f o l d p a i r .
Now c h o o s e
6>0
such that
Q X [O,
c^([{Q X O) o (9Q X I)] X I)-
I'l'his i s p o s s i b l e b e c a u s e t h e s e t o nt h e r i g h t i s a n e i g h b o r h o o d of ' X I and b e c a u s e Define pearly, h
Q is compact.
h: Q X [0, 6] = Q X I by p u t t i n g i s t h e i d e n t i t y on (Q X O)
Jundary c o l l a r s of
QX 0 in
Q X I.
Moreover,
Cl) a n d (2) a n d t h e fact t h a t
(F^ X
h = c^
(c^" ^ | Q X [O, 5]).
(9Q X [0, 5]), s i n c e
c^
and
c^
are
h (F X I . . , ) = F | Q X [0, 5], o [O.oJ BM X I = F | 9M X I. In p a r t i c u l a r ,
-150h is l e v e l p r e s e r v i n g o n ( F ^ ( M ) X [0, 5]) Lemma 6.1, there exists
(9Q X [O, 5]).
Hence by
0 < £ < 5 a n d a p. 1. h o m e o m o r p h i s m
h ' : Q X I —> Q X I s u c h t h a t
h'
h is level p r e s e r v i n g and h'
( Q X 9 I ) u h(F^(M) X [ 0 , ^ ] ) U ( 9 Q X [ 0 , S ] ) .
The map
h'
h
is the identity'
satisfies the
r e q u i r e m e n t s of t h e l e m m a . L e m m a 6. 12. 2.
T h e o r e m 6 . 1 2 h o l d s in t h e c a s e
F I 9M X I i s t h e c o n s t a n t i s o t o p y Proof.
Let
t^ € I,
F^X i.
t ^ / 0 o r 1.
T h e n b y L e m m a 6. 12. 1, a p p l i e d in
b o t h d i r e c t i o n s , t h e r e e x i s t s 6- = ^ (t ) > 0 o \
: Q X [ ^ Q - t ' t^+fe] —> Q X [t^ - ^ , t ^
9Q X [ t ^ - ^
h^I Q X [0,
h ^ : Q X [ 1 - ^^(1), 1]
and
such that
a n d h^ (F^ x , t) [ F ( x , t )
we m a y find
Q is c o m p a c t and
for
5> Q X [0, £ ( 0 ) ]
h^
is t h e i d e n t i t y on
t^-^ < t t ^
+ .
Similarli
and
> Q X [1- e ( l ) , i ] with s i m i l a r p r o p e r t i e s .
T h e open
s e t s i n I of t h e f o r m (t - t i t ) , t + ^ { t )), [0, t ( 0 ) ) , a n d ( l - £ ^ ( l ) , l ] I, and t h i s c o v e r i n g h a s oa L e s b eos g uoe n u m bo e r a . C h o o s e n u m b e r s 0=t
o
= s
o
< s , < . . . < s . , < s =1, 1 ••• r-1 r
Now we define as follows:
let
such that
the property that t) = F ( x , t )
if
h a s b e e n defined and hafi
is t h e i d e n t i t y , a n d
(x, t ) e M X [ 0 , s .
J.
Then there exists
k : Q X [s^
—^ ^ ^
identity on
-• [ s . , , s . ] , a n d w h i c h s a t i s f i e s k ( F | . 1-1
a n d for s o m e
t
o
.
ji'
which is level p r e s e r v i n g , which is the
1
N o w df fine
Q X [0, s^] —> Q X [C
Suppose that
9Q X [O; s^
t) = F ( x , t) for s. o
H^^^ b y p u t t i n g
covel
s . - s. , < a . 1 i-i
i n d u c t i v e l y a s e q u e n c e of m a p s
H^^^ = i d e n t i t y .
|
-151-
„(i-»
„(i) . t
if
t
0 < t < s. i-1
and H^^^ = k k'^ t t s. ,
for
s. ,
1-1
s.
1-1
1-1
1
.
The definitions a g r e e for itself,
t = s.
H^^^ is a P . L . h o m e o m o r p h i s m of Q X [O, s^]
onto
a s shown by a l t e r n a t i v e definition (k^
XI)
Xl)(x,t),
1-1
Clearly
t s . ,
1-1
.
1-1
H^^^ i s t h e i d e n t i t y on
t ^ O
s.
BQ X [0, s . ] .
If
s^ ^ ^ t < s. , t h e n we h a v e
H'"^ (Fx) = k k ' ^ F X = k. F , (x) = F fx). s . ^ ^ o ' t s . , s . , t t ' ' t'' 1-1 1-1 1-1 o
(r) The l e m m a i s t h u s p r o v e d b y p u t t i n g L e m m a 6. 12. 3. an a m b i e n t i s o t o p y of
Let 9Q.
H = H
Q be a c o m p a c t manifold.
Suppose that
T h e n t h e r e e x i s t an a m b i e n t i s o t o p y of
Q
h
is
extend-
ing h . Proof.
Let
c : 9M X I —> M be a b o u n d a r y c o l l a r .
Let
0:
be a p. 1. m a p w i t h jl((0,t)
pefine
k: Q X I
=
t
for
all
t
^(l,t) = 0
for a l l
t
^ ( s , 0) = 0
for a l l
s.
5> Q X I b y k ^ c ( x , s) =
t)^'^^
^^
^
t in
I
—> I
-152 a n d k^(y) = y if
y e cl(Q - Im c).
n o t h a r d to s e e t h a t Lemma
Note t h a t
^^x, s) = c(x, s ) .
k i s an anabient i s o t o p y e x t e n d i n g
6.12.4.
Suppose that
Q and
It is
h.
M a r e compact and that
F : M X I —> Q X I i s a n i s o t o p y w h i c h is p r o p e r and l o c a l l y u n k n o t t e d . t h e r e exists an ambient isotopy Proof.
By
H of
Q such that
6. 12. 2, t h e r e e x i s t s
w i t h h (F^ X 1) = F I 8M X I. Let F ' = k " ^ F : M X I — ^ w h o s e r e s t r i c t i o n to a m b i e n t i s o t o p y k'
Let
Q X I.
F = H ( F ^ X 1).
h : 9Q X l—;^ 9Q X I, a n a m b i e n t isotopy,
k be an a m b i e n t i s o t o p y of Then F '
Q e x t e n d i n g h.
is a l o c a l l y u n k n o t t e d p r o p e r isotopy
9M is a c o n s t a n t i s o t o p y . of Q w i t h k'
Then
fixed on
By 6. 1 2 . 2 , t h e r e e x i s t s an
3Q and k ' ( F ^ X 1) = F ' .
Let
H = kk'. Remark; such that
T h e proof s h o w s t h a t if one i s g i v e n an a m b i e n t i s o t o p y h (F
F o r we h a d
o
X 1) = F
o n 9M X I, t h e n
H m a y be c h o s e n to e x t e n d
9Q h.
H | 9Q X I = h | 9Q X I in t h e proof.
P r o o f of T h e o r e m 6. 12. to c o n s i d e r t h e c a s e in w h i c h
By t h e l e m m a s a l r e a d y p r o v e n , it suffices Q is not compact.
p r o j e c t i o n onto the f i r s t c o - o r d i n a t e . P^ F ( M X I) m e e t i n g Q
h of
9Q r e g u l a r l y .
Let Let
Q
Let
P ^ i Q X I — ^ Q b e the
be a r e g u l a r n e i g h b o r h o o d of
Q^ = Q n
9Q a n d l e t
= C1(9Q"" - Q ), b o t h ( q - 1 ) - m a n i f o l d s . Now,
F|9MXI:9MXI
> Q^ X I, s i n c e F
is proper.
If F I 9M X I i s a c o n s t a n t i s o t o p y , define or : Q^ X I — i d e n t i t y ; o t h e r / i s e b y l e m m a 6. 1 2 . 2 l e t
a be s u c h t h t
Q^
is
compact
Q^ X I to b e t h e
-153-
( F ^ X 11 a M X I) = F I 8M X I a n d s u c h t h a t Let
hi8Q
XI
h j Q ^ X I = identity.
)>8Q'XI
5.
k t o a l l of
b e d e f i n e d b y h | Q ^ X I = o(
k : q''' X I — > q " X I w i t h k
Q by putting
The n - i s o t o p y E x t e n s i o n
Definition .
Xil i s t h e i d e n t i t y . and
By t h e r e m a r k f o l l o w i n g l e m m a 6. 1 2 . 4 , w e c a n
e x t e n d h to a n a m b i e n t i s o t o p y Now e x t e n d
|
(F. X 1) = F .
>< l k = i d e n t i t y o n cl(Q - Q ) X I.
Theorem.
An n - i s o t o p y is a P . L . embedding
F:MXI
— > Q X In
w h i c h i s l e v e l - p r e s e r v i n g ; i . e . , t h e following d i a g r a m c o m m u t e s : MX I
where
n
P^ = p r o j e c t i o n on t h e 2nd f a c t o r
F
. „ -> Q X I
(I^ = I X . . . X I cZ E^).
An a m b i e n t n - i s o t o p y i s a l e v e l p r e s e r v i n g P . L . H:QXI^
>QXI^
An n - i s o t o p y 9M X I ^ .
such that F: M X
H(x, 0, . . . , O) = (x, 0
—> Q X
homeomorphism O).
i s c a l l e d p r o p e r if
=
A p r o p e r n - i s o t o p y i s c a l l e d l o c a l l y u n k n o t t e d if, for a n y s i m p l e x
l i n e a r l y e m b e d d e d in l",
(Q X
, F ( M x A )) i s a l o c a l l y u n k n o t t e d m a n i f o l d
pair. If F : M X I ^
> Q X I^
defined b y F ( z , x ) = (F
z,x).
i s a n n - i s o t o p y a n d if x € l " , t h e n
F
is
A
-154
Theorem
6.13.
Let
F: M X
> Q X I^, M a n d Q P . L . manifoldg
M c o m p a c t , be a n n - i s o t o p y w h i c h i s p r o p e r and l o c a l l y u n k n o t t e d . t h e r e e x i s t s an a m b i e n t n - i s o t o p y F^l aM = F ^ l 9M for a l l identity.
1)
X 1) = F .
F"(9QXI) = N X I ,
m = d i m M.
If
H | dQ X
b e the
O) e l " ) .
L e t an a l l o w a b l e n - i s o t o p y F : M X r J „ -n
n-isotopy such that dim(m-l),
Q with
t e I^, t h e n w e c a n i n s i s t t h a t
(Note : 0 = ( 0 , 0
Remarks;
H of
Then
N
->QXI
a manifold in
b e an
9M of
T h e n o n e c a n p r o v e a n a n a l o g o u s t h e o r e m to 5. 13
for allowable n - i s o t o p i e s . 2) One a l s o c a n p r o v e a n a n a l o g o u s t h e o r e m for i s o t o p i e s of c o m p l e x e s into m a n i f o l d s ,
p r o v i d e d o n e h a s c o d i m e n s i o n at l e a s t
L e m m a 6. 14.
Let F : M X
u n k n o t t e d and fixed on
9M, i . e . ,
—> Q X
be a p r o p e r n-isotopy,
F^ 9M = F I 9M for a l l t . t o
a r e compact then t h e r e is a P . L . h o m e o m o r p h i s m HI 9Q X I = i d e n t i t y , H(F
3.
If
M and Q
H: Q X l " —> I^
H(Q X A) = Q X A for e v e r y face
locally
s u c h that
A of t h e c u b e
I^, and
Xl)aF. o Proof.
By i n d u c t i o n on n .
homeomorphism, QXA
Suppose
h ; Q X I^ ^
> Q X l " ^ is a P . L.!
e q u a l to t h e i d e n t i t y on Q X l " ^ a n d s e n d i n g
t o r 3 >ch face of A of
I^'^
and w i t h
h(F
Q X A to
Xi) = FiMXl""^
Then
o define
h': Q X
— Q X I^ b y h ' = h X 1.
Let
F • = ( h ' ) ' ^ F : M X I^ —> Q X l'
a n d r e g a r d t h i s a s a 1 - I,-jto^^y w i t h t h e l a s t c o o r d i n a t e of
I^^ a s p a r a m e t e r .
-155Let
A,, .. ., A be t h e f a c e s of 1 r
(with A^ = l "
in o r d e r of i n c r e a s i n g d i m e n s i o n
T h e n , b y t h e r e m a r k following
i n d u c t i v e l y PL, h o m e o m o r p h i s m s
6. 1 2 . 4 w e c a n define
k^: Q X A^ X I —5> Q X A^ X I,
level-pre-
s e r v i n g on t h e l a s t c o o r d i n a t e s u c h t h a t 1.
k j 9Q X A. X I = i d e n t i t y ,
2.
if A. < A. , k . = k . Q X A. X I , 1 J 1 J 1
3.
k.(F 1
o
s,t) = F'(x, s,t)
X,
Then k = h ' k ^ : Q X
—> Q X
and
for a l l x e M, s e A.,
tel.
1
is a P L h o m e o m o r p h i s m satisfying all the
required conditions. Definition .
Identifying
I
r
w i t h t h e face of
c o o r d i n a t e z e r o we define a p r i m a r y s i m p l e x of e m b e d d e d in I etc. V. .
1
n
w i t h a v e r t e x at
I
r+1
having the last
as a n - s i m p l e x linearly
1 2 0, a 1 - f a c e i n I , a two face {2-face) in I ,
T h u s a p r i m a r y s i m p l e x w i l l be of t h e f o r m
(O, v ^ , v^,, . . . , v^)
where
L\
L e m m a 6. 15. n - i s o t o p y , fixed on simplex
A in l "
Let
F: M X
9M,
—> QX
M and Q being c o m p a c t .
and a P L h o m e o m o r p h i s m
with p r o j e c t i o n onto
be a p r o p e r l o c a l l y u n k n o t t e d
A, w i t h
Then t h e r e is a p r i m a r y
H: Q X A —> Q X A
H | 8Q X A = i d e n t i t y
and
commuting
H ( F ^ X 1) = F | M X A
Q X A. Proof.
Let
L e m m a 6. 14. f| k:a{Q X l " ) t P(Q X
Let a
—> Q X
and
p(Q X I^)
be a P L h o m e o m o r p h i s m given by
p b e t r i a n g u l a t i o n s of
QX
is s i m p l i c i a l and the p r o j e c t i o n s
such that aCQ X l")
l",
I
fe
k: Q X
are linear.
Now c h o o s e c o n s t a n t s 5 , 6 , . . . , 5 a s follows: o 1 n
-156Choose either
5 > 0 o
s u c h t h a t , for a n y s i m p l e x cr in
d ( 0 , p a-)rr0
or
d(0,p cr)>6
Now s u p p o s e t h a t
ar(Q X I^) o r
.
cr i s a s i m p l e x of ^(Q X n
a vertex
x^
in Q X 0 and a v e r t e x
L e t xj—p^x^ (x^x'^...xl
for e a c h ^y) for
p(Q X l'*),
j.
Let
ye
or
p(Q X I ) h a v i n g
x^ in Q X I'^ - Q X I'' ^ for e a c h j < i.
A(p2(r,I^) Choose
[minimum angle between 5.>0
and
s u c h t h a t , for a l l s u c h cr,
e i t h e r A(p cr, I^) t::: 0 o_r A(p cr.l'') > 5 . . Now l e t A be t h e s i m p l e x (o, V, , v_, . . . , V ) in w h e r e v. e \ for e a c h i, d(0, v . ) s i 5 , and 1 2 n 1 1 o angle(Ov, V . . . V. for a l l j < i. A s a r e s u l t of t h e w a y we h a v e 12 j-li " J chosen the 6. , if cr i s any p r i n c i p a l s i m p l e x of Qr(QXI^) such that
p
th^ji p c r O A , Z
2 for e a c h
i,
cr m e e t s
in a face,
and
QXv
meets
or
Into".
X I^) Moreover,
J3.
cr^ s a y , and
Now c h o o s e f i r s t d e r i v e d s u b d i v i s i o n s
a'
QXv. and
p
meets
Intcr^.
of or and p s u c h t h a t ,
if 'P' d e n o t e s t h e s u b d i v i s i o n point of cr, t h e n 1. ' ^ e Q X v . if Q X v . m e e t s Inter, 1
and
2.
Q
k(^)
1
if cr ^ F ( M X I^)
8Q X I^.
N o t e t h a t t h e s e two r e q u i r e m e n t s a r e c o m p a t i b l e s i n c e p r e s e r v i n g on F ( M X I ^ ) Now l e t
and
k ' : cjr'(Q X I^)
k is l e v e l -
8Q X I ^ . > p'(Q X l")
be the
induced
simplicial
T h e n we s t i l l h a v e k' a P L h o m e o m o r p h i s m , e q u a l to t h e i d e n t i t y c and w i t h k ' ( F X 1) F . M o r e o v e r , k' is l e v e l - p r e s e r v i n g c - Q o l e t X be a v e r t e x of for s o m e
j.
But k ' x
a'CQ X I^) lying in Q X A. m u s t also lie
in
Then
the s a m e set,
and
x: i
sr-
QX
Q or
p^k'x-
map.
^Q X I , A. F o r ).
p^x.
v^
-157-
But k'
i s s i m p l i c i a l and so we m a y j o i n l i n e a r l y to get
all points
V-^^V '
V^^
y in Q X A.
// Lemma rotations,
6. 16 (A c o v e r i n g t h e o r e m ) :
r e f l e c t i o n s , and t r a n s l a t i o n s of
Let R'^.
h tfr we a r e g i v e n a p r i m a r y s i m p l e x cr(h). 1 such that h^, h ^ , . . . , h^ of e l e m e n t s of
Definition . [A
S u p p o s e t h a t for e a c h T h e n t h e r e is a finite set c Q h.(o-(h.)). i z 1
An r - f l a g in R^ i s a s e t of o r i e n t e d affine
C A^ C A^ C . . . C -A ], w h e r e
dim(Ap = i.
is a s e t of t h e f o r m fx e R^ d(x, A ) < 5 , o o ' where
be t h e g r o u p of
subspaces
An r - w e d g e on t h i s r - f l a g
(A x, A J < 5, o l I
. . . , 6 j . a r e p o s i t i v e c o n s t a n t s and
^(A
A )< r - l r
denotes angle between
oriented subspaces. We s h a l l show by i n d u c t i o n on d e c r e a s i n g
r
t h a t , given a n y r - f l a g in R^,
t h e r e i s an r - w e d g e on it t h a t m a y be c o v e r e d by finitely m a n y s i m p l e x e s of the f o r m r e q u i r e d in t h e l e m m a .
S i n c e an 0 - w e d g e i s s i m p l y a s p h e r i c a l
n e i g h b o u r h o o d , t h e c o m p a c t n e s s of
w i l l c o m p l e t e the proof of t h e l e m m a .
To s t a r t t h e i n d u c t i o n , c o n s i d e r an ( n - l ) - w e d g e
[ A C . ••CA ]. o n-1 T h e r e a r e two p o s s i b l e o r t h o n o r m a l c o o r d i n a t e s y s t e m s h a v i n g t h i s wedge a s [O, Ox ., Ox^ x_, . . . , Ox^ x_. . . X , ], one b e i n g s i m p l y t h e r e f l e c t i o n of the o t h e r 1 1 Z 1 Z n-1 in X = 0 . n
F o r e a c h of t h e s e c o o r d i n a t e s y s t e m s we h a v e a p r i m a r y s i m p l e x
and we c a n c h o o s e an ( n - 1 ) - w e d g e c o n t a i n e d in t h e union of t h e s e two simplexes-. see f i g u r e :
-158-
The inductive step.
Let
F = [A^
...
s e t of o r i e n t e d ( r + l ) - s p a c e s t h r o u g h
A^] be. a n r - f l a g .
A^.
Let ^
b e the
^ ^ la n a t u r a l l y i s o m o r p h i c to
t h e s e t of unit v e c t o r s o r t h o g o n a l to A ^ , w h i c h i s a n ( n - r - l ) - s p h e r e . for e a c h
B e ^
, let
W ^ be a w e d g e on t h e flag
[A^ C A^ C • . . C
given by the inductive h y p o t h e s i s , and s u p p o - " at W B (6^ ,
constants
B
, ... ,
i s a n e i g h b o u r h o o d of
B
). jrjli.en t h e s e t
B in ^
.
But ^ i s
' J
Now
eg,
C B]
i s d e t e r m i n e d by the | ^ (B, B ' ) <
^
'
c o m p a c t , and so we c a n c h o o s e
a finite s e t
B ,B , .,. ,B such that the c o r r e s p o n d i n g neighbourhoods X ^ s
cove
Let
(5^,5^, o r
W be t h e w e d g e o n F d e t e r m i n e d b y t h e c o n s t a n t s B. w h e r e 5. = min(5^ j=l,2,...,s. Then ^ C 1 1
P r o o f of T h e o r e m
6. 13 ( T h e n - i s o t o p y e x t e n s i o n t h e o r e m ) :
c o n s i d e r the special c a s e when
Q is compact.
X. = i n t e g e r , we m a y a s s u m e t h a t F : M X
M
Wj
First
By r e f l e c t i o n in t h e subspacefi
—» QXI^ i s t h e r e s t r i c t i o n of a P
e m b e d d i n g F : MXR^ —$> QXR^, c o m m u t i n g witJr p r o j e c t i o n o n r " , a n d w i t h F-^ 9M - F . | 8 M for a l l t « t
J. 15 a n d , 6 . 1 6 t h e r e a r e a fini
o'
II
^^
i^umber of s i m p l e x e s A^ in R.", .c veTir g " ., - rrf P L h o m e o m p r p h i f e m s k^C'QXA. — Q X A ^ k. 8Q X A.
1
1
c o m m u t i n g with projectioti onto the secoAd f a c t o r ,
i s t h e i d e n t i t y s-nd
s u c h that
-159-
X 1) = F | M X A. for s o m e P L e m b e d d i n g a . = F^ for such that
t = a v e r t e x of A ^ . ) 1) e a c h s i m p l e x of
Now l e t
Let
o r i g i n , be t h e s i m p l i c i a l c o l l a p s e .
and h . ( F 1
defined. that
o
X 1) = F
Let
aACA.. J
K=K
5> Q X K.
MXK.,
S t a r t with h
1
K^ = K^ ^ + aA + A. T h e n define
A^
, and
Let
O
h j 9Q X K^ = i d e n t i t y
= identity.
Suppose
1
o
= k
Putting
J,t
(k
j,pt
h.
1-1
p : a A —> aA be a P L r e t r a c t i o n .
h . : Q X K. —> Q X K. by h . ( x , t ) = (h. x, t) 1 1 1 ' 1 1, t
is Suppose
where
if t 6 K. , 1-1 if t € aA
One m a y r e a d i l y c h e c k t h a t t h i s is a P L h o m e o m o r p h i s m ,
h (F x , t )
col-
= the
such that
^.t
9Q X K^.
2) K
V k
Vl.t
identity on
In
We define i n d u c t i v e l y l e v e l - p r e s e r v i n g
h . : Q X K.
on
(In fact,
K be a t r i a n g u l a t i o n of
K^ l i e s in one of t h e
lapfi«:«". s i m p l i c i a l l y to t h e o r i g i n .
PL homeomorphisms
a . : M —» Q.
e q u a l to t h e
M o r e o v e r , if x € M, t e aA, .(x) = k a (x) = F (x). pt J.t J t
H = h :Q X I
—^ Q XI
The e x t e n s i o n to t h e c a s e w h e n
g i v e s the r e q u i r e d a m b i e n t n - i s o t o p y .
Q i s not c o m p a c t i s m o r e o r l e s s i d e n t i c a l to
the a r g u m e n t w h e n n = 1 and so w i l l be o m i t t e d .
C h a p t e r VII.
0.
Engulfing
Introduction. Suppose
X i s a c l o s e d s u b s p a c e of t h e P L m a n i f o l d
m a y pose the question:
Is t h e r e a q - b a l l
Q .
T h e n we
B in Q w i t h Xc:;;;!! B.?
Some
u s e s for t h e a n s w e r s to t h i s q u e s t i o n a r e in p r o v i n g e m b e d d i n g t h e o r e m s (See C h a p t e r VIII) and in p r o v i n g a w e a k g e n e r a l i z e d P o i n c a r e c o n j e c t u r e in d i m e n s i o n s
^ 5 and a v a r i a n t of t h e h - c o b o r d i s m t h e o r e m ( s e e
5).
We a p p r o a c h t h i s q u e s t i o n b y c o n s i d e r i n g t h e following two r e l a t e d questions: (A) If
U i s o p e n in Q a n d X i s a cc.:-^..ct PL. s u b s p a c e of
there a P L homeomorphism
h: Q — > Q w i t h
X.:::i.hU?
(B) If C and X a r e c o m p a c t P L s u b s p a c e s of subspace
C
of Q w i t h X ^ C
Q, i s
Q, i s t h e r e a c o m p a c t
a n d C ^ C ? What c a n w e i n s i s t a b o u t the
d i m e n s i o n of ( C ' - C ) ?
1.
Preliminary Results. Lemma 7.1.
and suppose
Y i s a c l o s e d P L s u b s p a c e of
A s s u m e that X ^ ^ X ^ PL homeomorphism on
Suppose that X ^ d X a r e compact P L
and let h: Q
UH^X^
s u b s p a c e s of
Q s u c h t h a t X ^ (9Q [j Y ) ^
be o p e n in Q.
Q, X^.
Then there exists a
> Q with compact support, which is the identity
9Q u Y U X . s u c h t h a t X i C h(U). o
-161-
Picture;
Proof.
Let
J
b e a t r i a n g u l a t i o n of
Q containing triangulations s
K , K, and L of X , X , and Y, r e s p e c t i v e l y . We m a y a s s u m e t h a t K .es .es .es Let K = K \ K ... \ K . T h e n K . \ i K . ^ and r r-1 o 1 1-1 K. ^
{ 9J I
|K. ^ .
l e m m a for Let
and Y. K = K
o
+ aA + A.
Let b / a be a point of R = link(A; J ) . Since
Since
dim A ^ q-1,
R—> {a,c}.S,
a^
H e n c e it suffices by i n d u c t i o n to p r o v e t h e es So we m a y a s w e l l s u p p o s e K = K^ K^ .
Then
aA C. U.
c l o s e e n o u g h to
A /
Let a
A A be t h e b a r y c e n t e r of so t h a t
R ^
Let
T h e r e f o r e t h e r e is a P L h o m e o m o r p h i s m
S a s p h e r e of d i m e n s i o n q - d i m A - 2
p^A = i d e n t i t y and
abA
A,
R i s a P L s p h e r e of d i m e n s i o n q - d i m A - 1 .
Define a P L h o m e o m o r p h i s m letting
K^.
P: A . R — A . (a
(S = ^ i s p o s s i b l e ) .
c ). S = (a u c ) . A . A. S by
p R = o' and e x t e n d i n g l i n e a r l y .
-162 Now l e t -y': (a>..' c ) . A — > ( a U c ) . A A v ' ( b ) = A, a n d y'(c)
>/'(a) = a ,
T h e n let
A * A ' T h e n l e t \ s (a \j c ) A . A, S —» ( a ^ c ) , A. A.i
= c.
be a P L h o m e o m o r p h i s m s u c h t h a t
be a P L h o m e o m o r p h i s m s u c h that
o 0 "Y[(a u c)A = -y' a n d - y l A . S = identityo
6 : s t a r ( A ; J) —» s t a r ( A ; J ) b e defined b y
5 = p
-1
vp.
Then i
'
A
*
*
5(abA) = a A . A = a A .
M o r e o v e r , 6 i s t h e i d e n t i t y o n A. R .
h | s t a r ( A j J^ = 5 a n d h = i d e n t i t y e l s e w h e r e , t h e n h | h ( U ) 3 |K . Definition .
So if w e put = i d e n t i t y and
If K = K^ + aA + A i s an elemfentary s i m p l i c i a l c o l l a p s e
^es K
K^, t h e n
dim(aA)
Lemma 7.2;
If
i s c a l l e d t h e d i m e n s i o n of t h e c o l l a p s e .
K
K^, t h e n we c a n r s a r r a n g e t h e e l e m e n t a r y s
simplicial collapses Proof.
K
Suppose
K
t o be in o r d e r of d e c r e a s i n g d i m e n s i o n .
K^ = K, + aA + A and 1
K
1
= K
o
+ bB + B
are
»
two s i m p l i c i a l c o l l a p s e s , a n d K
o
d i m B > d i m A.
+ aA + A i s a s u b c o m p l e x of ®
So K^ ^
\es (K^ + aA + A) \ K^
Lemma 7.3. exists
TCZ,
If
Then
aA ^Hl K^ ,
So
M o r e o v e r , K^— (K + aA + A) + b B + B. 2 o
K^. 2
i s in o r d e r of d e c r e a s i n g d i m e n s i o n . Z a r e p o l y h e d r a and if
a polyhedron, such that
YijX^lT,
Z^X, then there
z'^XuT^X,
and
d i m T ^ d i m Y + 1, Proof. K'.L'CJ'
Let so t h a t
K, L — J J'\K',
triangulate and let
X j Y r Z.
Choose subdivisions
J ' = K ^ Ve s
, es ^ K'
s i m p l i c i a l c o l l a p s e s in o r d e r of d e c r e a s i n g d i i - e n s i o n . least integer such that
We m a y s u p p o s e i
Let
be e l e m e n t a r y i
0, a s if
be the
i = 0
there
-163-
i s n o t h i n g to p r o v e . L ' ^ K^ So if
3.
Let
K^ =
^ + aA + A .
In p a r t i c u l a r , t h e c o l l a p s e
T = c l K! - K' 1 o
=
A^L',
as otherwise
h a s dimension < (dim L + l ) .
K: - K' , d i m T < d i m L + 1 a n d 1 o
Engulfing T h e o r e m s , Definition .
Then
T y p e (A).
A t o p o l o g i c a l p a i r (X, A) i s n - c o n n e c t e d , n k 0, if e v e r y
point of X m a y be j o i n e d b y a p a t h t o s o m e p o i n t of A a n d if for
1 ^ i < n.
t\X.
Z\X u
TT^^CX; A) = 0
[If A i s not c o n n e c t e d , w e i n s i s t the c o n d i t i o n h o l d s for a n y
b a s e point i n A. ] T h e o r e m 7. 4. A s s u m e BQ =
Let
Let
U b e an o p e n s u b s e t of t h e P L m a n i f o l d
X C Q b e a c o m p a c t P L s u b s p a c e of
b e a c l o s e d P L s u b s p a c e of (Q,U)
is k-connected,
Q.
Let
Q, a n d l e t
Yi.„ U
j = d i m X , s = d i m Y, s u p p o s e t h a t
and suppose that
there exists a P L homeomorphism
q'^.
j ^ q-3, s < q - 3 ,
and t < k.
h ; Q —> Q, w h i c h i s t h e i d e n t i t y o n
Then Y,
such that X c r h(U). Proof.
We l e t
k
and
s be fixed a n d p r o c e e d b y i n d u c t i o n on j .
g i v e n j, a s s u m e t h e r e s u l t for
So
j-1.
B e c a u s e of the c o n n e c t i v i t y a s s u m p t i o n s on ( Q , U ) , w e c a n c o n s t r u c t a map follows:
)Z(:X X I — > Q Let
on a path from
such that
K triangulate X I)
(KXl)
v to a p o i n t in
X,
by U.
{^((x. 1) = x K'^ =
all
skeleton.
^ ( x , 1) = x
and
Suppose that
j ^ d i m K, h a s b e e n d e f i n e d so t h a t
x, a n d ^(X X 0 ) c : U, a s Define
0(v, t) = .^^(t), w h e r e
is
: (K^^"^^ X I) IJ (K X 1) — » Q,
J ^(K^^^ X 0 ) ^ U
and
^(x, 1) = x ,
-164-
a l l X.
F o r each 3-simplex
a taetract of A X I.
such that
i s defined on (A X l) ^ (A X I),
Hence t h e r e exist
( A X I). d i m A ^ k, let
A of
Let
f ^ s ^
g ^ = (f^)^-
I —^ Q
Then
g ^ : (A. A ) ( Q ,
H ^ : A X I —> Q b e a h o m o t o p y of
H ^ ( x , 1) € U for a l l x € A.
extending
g^ =
U).
Since
> relative
T h e n if x € A e
a n d if
A
tel.
define
J Then
f^(x;2t-l)
1/2:^ t ^ l
H^(x;l-2t)
0
.
X I —5> Q i s a w e l l - d e f i n e d m a p , Ji^.CK^''^ X O ) ^ U , J
J
i2(.(x, 1) = X. J
F i n a l l y , put
^ =
J
where
and
j = d i m K.
B y t h e l e m m a s of C h a p t e r IV w e c a n a s s u m e , a f t e r a s m a l l h o m o t o p y of ^
relative
XXI
that
^
is also a n o n - d e g e n e r a t e P L m a p
(Lemmas 4.2
and 4. 4). Now l e t and
L b e a t r i a n g u l a t i o n of X X I , c o n t a i n i n g t r i a n g u l a t i o n s
L^ of (X X O) a n d ( X X I )
respectively,
m a d e s i m p l i c i a l by s u i t a b l y t r i a n g u l a t i n g Q. of
L.
Let
L'
b e a s u b d i v i s i o n of
of
L^ .
B y L e m m a 4 . 7,
embeds
e a c h s i m p l e x of
(rel L
L
such that Then
such that
L —5> Q c a n b e
^ embeds each simplex
L' ^ L ' = i n d u c e d s u b d i v i s i o n o
X X I ) , where
is a P L m a p which
a n d w h i c h s a t i s f i e s t h e following:
1) If cr, TE L ' - L ' ^ , dim(^'cr)/^ ( 0 ' T ) ^ d i m o" + d i m T - q ; 2)
F o r all
o- e L ' - L ^
3) F o r a l l ere L ' - L ' ^ ,
, d i m (filar)
^
L^
Y ^ dim T + s-q;
, d i m ( ^ ' o * T ) < dimcr + d i m T - q .
-165-
es L' = R ^ ^ n
Now l e t each
i.
es ^
R
o
= L' • o
( j ) - j. - s k e l e t o n 1
Let
of
R., 1
By i n d u c t i o n o n i, we a r e going to find P L h o m o e m o r p h i s m s
h . . ' Q — > Q, fixed o n for if we t a k e let
. ..
i=n
h^ = i d e n t i t y .
then X C
Let
U
Since Then let
U,
V=h^_^(U).
Let
Z be a p o l y h e d r o n s u c h t h a t
= aA u Z. By 1) and 2) above,
dim Z < max(j+l +s-q, j +1-j-q) ^ j-2. such that
T h i s will c o m p l e t e t h e proof
X 1) ^
S u p p o s e h^ ^ i s defined.
R. = R + aA + A. 1 i-1 (jZf'jaA)" V
Y, w i t h ^ ' ( R ^ ^ ^ c T h . U .
By 7. 3, t h e r e e x i s t s a p o l y h e d r o n
aA'^aA u T^laA, Z ^ T ^^ aA, and
+ aA +
dimT<j-l.
T
Therefore
(J T) by a c o l l a p s e "not c r o s s i n g Y " ; i. e . , a c o l -
l a p s e in w h i c h no p o i n t s of
Y are disturbed.
Now we a r e going to u s e t h e m a i n i n d u c t i v e h y p o t h e s i s to engulf U T].
D i m j2f'(T) < j - 1 .
Yo
CIV.
t h e r o l e of X i n t h e t h e o r e m , and Y j ^'(R^ a PL homeomorphism
So l e t t i n g
t h e r o l e of
o-: Q —> Q, fixed on Y \ j
play Y, t h e r e e x i s t s
with
aV.
Now by L e m m a 7 . 1 , t h e r e e x i s t s a P L h o m e o m o r p h i s m P: Q —> Q s u c h t h a t P i s fixed on Y ^ ^'{R^^^^u R.^-^^^R!^! 1 ^ i-i
+ aA + A.
T) a n d
So put
h. = porh. , . 1 1-1
U aA U Then
Now h.U. 1
This com-
p l e t e s t h e proof. Remarks;
We c a n i n s i s t t h a t
h have compact support.
In fact, in v i e w of
t h e fact t h a t t h e h o m e o m o r p h i s m of 7. 1 c o u l d h a v e b e e n t a k e n to be i s o t o p i c to the i d e n t i t y by m o v e s , t h e s a m e i s t r u e of
h.
-166
C o r o l l a r y 7. 5.
Let X , Y , Q , U
T h e o r e m 7. 4 e x c e p t t h a t Suppose that
X - X U
s a t i s f y a l l t h e h y p o t h e s e s of
X is m e r e l y a c l o s e d P L s u b s p a c e of is c o m p a c t .
Then there exists
s u p p o r t ) a h o m e o m o r p h i s m of Q, s u c h t h a t Proof.
Let X
taining X - X N Let
U.
X
h (with c o m p a c t
X ^
be a c o m p a c t P L s u b s p a c e of
T h e n X - X ^ ^ S U.
Q.
Q (or
X)
con-
But X ' = X ^ , Y' = Y [j C I ( X - X K ) .
h: Q —> Q be a P L h o m e o m o r p h i s m w i t h c o m p a c t s u p p o r t , s u c h t h a t
h | Y ' = i d e n t i t y and h(U) 3 X .
Then
(X - X j = X .
q C o r o l l a r y 7. 6. 9Q / 0 .
Let
Let
be an o p e n s u b s e t of the P L m a n i f o l d Q,
X be a c o m p a c t P L s u b s p a c e of
of X, w i t h d i m X = r < q - 3 , d i m Y = s ^ q - 3 . k > t , and a s s u m e
Yc^H U a n d X ^
m o r p h i s m (with c o m p a c t s u p p o r t ) such that X ^ Proof. s p a c e s of
U.
Q, Y a c l o s e d P L s u b s p a c e Assume
(Q, U) i s k - c o n n e c t e d
Then there exists a P L homeo-
h: Q — > Q, w i t h h | 9 Q ( j Y
- identity,
h(U). X' = X - X n
Q - 8Q.
9Q and
Y' = Y - Y p
8Q a r e c l o s e d P L s u b -
U' = U - U n 9Q i s o p e n in Q - dQ.
T h e p a i r ( Q - 8 Q , U')
i s q - c o n n e c t e d ; to s e e t h i s s u p p o s e — > (Q - 9Q, U - a Q n U) i s h o m o t o p i c I D*^ into
U.
rel
to a m a p of
T h e n by u s i n g a b o u n d a r y c o l l a r , one c a n p u s h t h e h o m o t o p y
s l i g h t l y off the b o u n d a r y without d i s t u r b i n g it on s'^ ^, g e t t i n g a h o m o t o p y H of f s u c h t h a t
H^(D^) C U - ( 9 0 ) N U.
-167-
Now l e t h'(U')3'X' h'
h ' : Q - 9 Q — > Q-8Q be a P L h o m e o m o r p h i s m such that
and h has compact support.
to be t h e i d e n t i t y o n
Re m a r k .
Define
h: Q—5> Q by e x t e n d i n g
9Q.
T h i s c o r o l l a r y c o u l d h a v e b e e n i n c l u d e d in T h e o r e m 7 . 4 u s i n g
a l m o s t t h e s a m e proof.
4.
Engulfing T h e o r e m s , Theorem 7.7.
manifold
of
Let
Q^, 8Q = jZf, w i t h
and s u p p o s e T h e n if
T y p e (B)
whoere
C a n d X be c o m p a c t P L s u b s p a c e s of t h e P L (Q, C) a t - c o n n e c t e d p a i r .
Proof.
CuXclC'^C
and
L e t X^ = c l ( X - X
uY^u Let
inclusions
C); a s s u m e
X^ / jZf. PL
and Y i C U
(Q, U) i s t - c o n n e c t e d . h ; Q - ^ Q such that X^ y Y ^ O Y < ^ : h ( U ) . 0
U
Then
Y^ in
d i m ( X ^ , l C) < r - 1
Q such that
Therefore
C UX =
X ^ , by L e m m a 2.
N be a r e g u l a r n e i g h b o r h o o d of Y ^ C
C
d i m ( C ' - C ) < r+1.
^ Y ^ , X^ A C . " Y u Y ^ , a n d d i m Y^ < r .
C b
s.
r < t, t h e r e i s a c o m p a c t P L s u b s p a c e
H e n c e by L e m m a 7 . 3 , t h e r e e x i s t s a c o m p a c t C ^
r = d i m X,
Y i s a c l o s e d P L s u b s p a c e of d i m e n s i o n
r < q - 3 , s < q - 3 , and
Q such that
Let
Y in
Q, and let
U = Int. N.
The
a r e both homotopy equivalences; therefore
By T h e o r e m 7 . 4 , t h e r e is a P L h o m e o m o r p h i s m h | Y = i d e n t i t y a n d X^ ( j ^ f : . h(U),
So
By 7. 1, t h e r e i s a P L h o m e o m o r p h i s m
= i d e n t i t y and
C ^XciTkhU.
k: Q—5>Q
with
S i n c e k h | Y = i d e n t i t y , khN i s a
-168r e g u l a r n e i g h b o r h o o d of Y„ C(2. Int k h N .
In p a r t i c u l a r ,
khN^Y.
But
C^Y
and
So b y L e m m a 5.1- (on f a c t o r i n g c o l l a p s e s), k h N \ i C .
b y L e m m a 7. 3 a g a i n , k h N ^ C ' ^ C ,
where
XCTC
and
So
i
dim(C'-C)<
d i m X + 1. Lemma 7.8. Q*^, c ' ^ C f ^ 9Q. r < q-3.
Suppose that A s s u m e that
Then t h e r e exists
C 0 X<:r
C and X a r e c o m p a c t P L s u b s p a c e s of
(Q, 9Q) i s r - c o n n e c t e d , d i m X = r , and
C
in Q, a c o m p a c t P L s u b s p a c e , s u c h t h a t
9Q) vj C, a n d d i m ( C ' - C ) < r + i .
Proof,
Let
N be a d e r i v e d n e i g h b o r h o o d of
U = Int^N.
Then
(Q, U) i s r - c o n n e c t e d .
C
9Q) u Y, w h e r e
PL homeomorphism
9Q in Q .
Let
Now, a s in t h e proof of 7 . 7 ,
dim Y < r.
So, by C o r o l l a r y 7. 6, t h e r e i s a
h : Q—» Q w i t h h | 9Q = i d e n t i t y , Y ^ i ^ h U ,
h'^YcTUcTN.
Now ( c A 9 Q ) 0 ( h " ^ Y ) is c o m p a c t , a n d so t h e r e i s a c o m p a c t p o l y h e d r o n in
9Q s u c h t h a t
n e i g h b o r h o o d of k : Q ^ Q ,
(C n 9Q) U (h"^Y)<:::rV = I n t ^ N ' , w h e r e P
in
fixed on
P
in
C u X ^ khV
Q and
P U C^P, P g
is a r e g u l a r n e i g h b o r h o o d of
L e m m a 7. 3, k h N ' ^ ^ P u C 0 T ~ ^ P u C , C = C
is t h e d e r i v e d
B y L e m m a 7. 1, t h e r e is a P L h o m e o m o r p h i s m
9Q O Y w i t h
r e g u l a r n e i g h b o r h o o d of by L e m m a S^l , k h N '
Q.
N'
T,^C y (T ^ 9 Q ) \ ( C U
where
9Q.
Now k h N '
is a
CcTlnt^khN'.
P U C in Q.
X cT-T and
P
So,
So, by
dimT
169-
^•
- ^ p p l i c a t i o n s of E n g u l f i n g . Definition^.
If
Q i s an o p e n m a n i f o l d ( i . e . , Q is not c o m p a c t and
8Q = fl), Q i s c a l l e d 1 - c o n n e c t e d at oo. if given is a C
Q, c o m p a c t ,
such that
T h e o r e m 7 . 9 (Stallings);
Proof.
and
Let
fold w h i c h i s 1 - c o n n e c t e d at oo. h o m e o m o r p h i c to
C C '
C ( ' Q, (Q-C)
there
is 1-connected,
be o p e n , { q - 3 ) - c o n n e c t e d P L m a n i -
Suppose
q = d i m Q ^ 5.
E u c l i d e a n s p a c e of d i m e n s i o n
We s h a l l p r o v e t h a t if
C compact,
C
Then
Q is P L
q.
Q is compact, then
C
is c o n -
t a i n e d in t h e i n t e r i o r of a P L q - b a l l c o n t a i n e d ( a s a P L s u b s p a c e ) in
Q,
03 T h i s is sufficient:
it i m p l i e s t h a t
Q =
B., w h e r e
B.
Int B.^^
a r e all
i=1 q-balls.
By t h e a n n u l u s t h e o r e m ,
9B X I. i
Moreover,
E*^ i s a l s o s u c h a u n i o n of b a l l s , a n d so it i s c l e a r how
to define a P L h o m e o m o r p h i s m of So l e t
Let
Q onto E .
CC- Q be a n y c o m p a c t s u b s e t of
compact subset, V
B^) i s P L h o m e o m o r p h i c to
J
so t h a t
Q.
( Q - C ) is 1 - c o n n e c t e d .
b e a t r i a n g u l a t i o n of
be t h e s u b c o m p l e x of
J'
Q.
Let
J
\
Let J
i;
do not m e e t ( i . e . , h a v e no f a c e s in) J'^, w h e r e
Let Let
C'ZI^C V = Q-C,
be t h e ( q - 3 ) - s k e l e t o n
c o n s i s t i n g of a l l s i m p l i c e s of
J.
A^<...
A g e n e r a l s i m p l e x of eJ.
r ^ 3.
Ifcr
J'
d o e s not m e e t
So d i m J ^ < 2.
J'
of which
J' = b a r y c e n t r i c first \
d e r i v e d of
be another
is of t h e f o r m
^
cr = A ^ . . . A^ ,
J^' , t h e n d i m A^ > q - 2 , 1 < i < r .
J.
-170-
Now, J^ i s full in J ' , so t h e r e i s a l i n e a r m a p ^ ( J ^ ) = 1 and ^ J
= J'^.
then there exists
If D i s a n y c o m p a c t s u b s e t of Q not m e e t i n g
0
d e r i v e d n e i g h b o r h o o d of J^
such that
in J .
J2((D)C [ 0 , B u t
In fact,
such that
D
Z and
and
Z
dim Z
of
is a
if D is c o m p a c t , D i s c o n t a i n e d
in a d e r i v e d n e i g h b o r h o o d of a finite s u b c o m p l e x of J ^ . compact P L subspaces
J ' —> I, s u c h t h a t
Q (can take
T h e r e f o r e t h e r e are
Z to be a q - m a n i f o l d ) "m
< q-3,
o
J
o n V) is c o m p a c t , a n d
- (J C^
dim J
< 2 < q-3 because
q ^ 5.
Since
Cd
V is one- connected and
Q is (q-3)-connected,
q > 5,
(Q,V)
is 2-connected. f,.
H e n c e by C o r o l l a r y 7, 5, t h e r e i s a P L h o m e o m o r p h i s m
h : Q —> Q, s u c h that
'4 V-, %
In p a r t i c u l a r ,
Q-hV = h(Q-V)
t*
a i s c o m p a c t and d o e s n o t m e e t H e n c e , we m a y t a k e Now l e t
D = Q - h V ; s o , Q-hVc;;:: Z ' ^ Z ^ , d i m Z^ < q - 3 .
U b e t h e i n t e r i o r of a P L q - b a l l c o n t a i n e d in
i s certainly (q-3)-connected. kU, by T h e o r e m 7, 4 . Zc^ k'kU.
Therefore
J_.
Q.
T h e n (Q, U)
T h e r e f o r e t h e r e is a k ; Q—5> Q s u c h t h a t By L e m m a 7 . 1 , t h e r e e x i s t s a k ' s Q
Q-hV^;:! k ' k U , a n d so
Q-V
Q
with
But
C ' = Q-V
(Weak G e n e r a l i z e d P o i n c a r e Conjecture):
be a c l o s e d (= c o m p a c t w i t h o u t b o u n d a r y ) P L m a n i f o l d , is [ m / 2 ] - c o n n e c t e d . _m the s p h e r e S .
m ^ 5.
Let
Assume
T h e n t h e r e is a t o p o l o g i c a l h o m e o m o r p h i s m of
M
m"^ M onto
-171Proof .
By PoinCare duality,
implies orientable. ) Therefore excision As
M is (m-1)-connected.
M is a homology sphere.
H . ( M , M - p t . ) = 0, for
i < m,
H . ( M - p t . ) = 0,
(1-connected Moreover,
by
all0
^ ^ ( M , M - p t . ) = 0, (by g e n e r a l p o s i t i o n ) , i T ^ ( M - p t ) = 0 .
Therefore,
M - p t . is ( m - 2 ) - c o n n e c t e d . If in
Ci£lIM-pt.
M not m e e t i n g
(M-pt)-C' = N-pt.
i s c o m p a c t , thiere i s a r e g u l a r n e i g h b o r h o o d C.
C = cl(M-N)
But
N is a m - b a l l , so
and
= 0.
by T h e o r e m 7 . 9 , c a t i o n of
Therefore
i s c o m p a c t in
N of
pt.
M-pt.
N - p t , i s h o m o t o p y e q u i v a l e n t to
M - p t . i s 1 - c o n n e c t e d a t oo.
Therefore
M i s t o p o l o g i c a l l y e q u i v a l e n t to t h e o n e point c o m p a c t i f i -
e " ^ , vh i c h i s
s"^.
We c o n c l u d e t h i s c h a p t e r w i t h a t y p e of h - c o b o r d i s m t h e o r e m . Theorem 7.11. Suppose
and
W be a c o m p a c t P L q - m a n i f o l d w i t h
^ M , where M ,M a r e disjoint q-1 manifolds. 1 ^ 1 (U (W, M ) i s r - c o n n e c t e d , (W, M ) i s s - c o n n e c t e d , w h e r e 1 M
s
Int W ^ M Proof.
Q = W-M^.
r + s + i = q. X R a; M
X
Then
W-M^
Q = LJ
M^ X [0, oo), W - M ^
M^ X [O, oo),
X R. w
It suffices t o p r o v e t h e f i r s t s t a t e m e n t of the c o n c l u s i o n . W e w i l l s h o w t h a t if
C i s c o m p a c t , C^:::: Q, t h e n
in t h e i n t e r i o r of a r e g u l a r n e i g h b o r h o o d of that
q > 5.
9W = M
Suppose that r
Let
N. , w h e r e e a c h
N.
M^
in Q .
Let
C is contained
F r o m t h i s it follows
i s a r e g u l a r n e i g h b o r h o o d of
M
and 1
N^C" Int
i
.
Then, since
N^
i s P L h o m e o m o r p h i c to
(^^r^Np X I
b y t h e g e n e r a l i z e d a n n u l u s t h e o r e m , a n d s i n c e by u n i q u e n e s s of r e g u l a r
-172 n e i g h b o r h o o d s and t h e e x i s t e n c e of b o u n d a r y c o l l a r s for we have
cl(N
1 1
- N.) ^^ M 1
X I.
1
h o w to define i n d u c t i v e l y P L
Fr_N. M U 1 1 ' U s i n g t h i s P L h o m e o m o r p h i s m , it is clear
homeomorphisms
h^:
Q,
N ^ — > M^^ X [O, N] i =i
such that
hj^ =
w h e r e both a r e defined.
required homeomorphism. n e i g h b o r h o o d of b o r h o o d of
M^
M^ —> U
is oo-connected.
^ ^
J^,
N'
C =
Let
N'
and let
Let
be a r e g u l a r neigh-
V = Int^CN'-M^).
J
be a t r i a n g u l a t i o n of Let
J^
M ^ ^ Q^.
Let
c o n s i s t of t h o s e s i m p l i c e s of
h(C) H |
= J^.
h: Q —» Q, w i t h Hence, since
^
|J JcTT h V .
J'
> w h i c h do
2nd c o m p l e t e p a r a g r a p h ) .
k : Q — > Q, w i t h with
h(C) dl h ( Q - V ) = Q-hV;!
J^
h(C)
T h e n if
is con-
( s e e p a g e 17,
We m a y s u p p o s e t h a t t h e s u b c o m p l e x of
M^ \ j Y, w h e r e d i m Y < r .
h(C)Cl Z ^ M ^ y Y.
V is compact) there
I J , i s full i n J ' , 1
t a i n e d in a d e r i v e d n e i g h b o r h o o d of a finite s u b c o m p l e x of
k':Q—»Q
U
As in t h e proof of 7, 9, d i m J ^ ^ q - r - i = s.
exists a PL homeomorphism
the form
Then
M^ X [O, 1 ) i s a h o m o t o p y e q u i v a l e n c e , so (Q, U)
By t h e engulfing t h e o r e m , C o r o l l a r y 7 . 5, {1
therefore
N be a r e g u l a r
(Q, V) i s a l s o c o - c o n n e c t e d .
J^^^ = r - s k e l e t o n of J . not m e e t
U = Int^N.
h^^ define the
A s i m i l a r s o r t of a r g u m a n t , but u s i n g a b o u n d a r y c o l l a r
M^, s h o w s t h a t Let
Q c ^ Q be c o m p a c t .
in Q, a n d l e t
M^ in W s u c h t h a t
the inclusion
of
So l e t
C l e a r l y the
J^
i s of
Z is the r e g u l a r neighborhood
By C o r o l l a r y 7 . 6 , t h e r e is a P L h o m e o m o r p h i s m
M^ u Y ^ k U . Z^k'kU.
By L e m m a 7. 1, t h e r e i s a P L h o m e o m o r p h i s m
So h C ^ l T k ' k U .
Therefore
•
r
C in
-173-
Int(h ^k'kN), a n d t h e l a t t e r i s a r e g u l a r n e i g h b o r h o o d of
M^
Q.
Note.
In fact, P o i n c a r e d u a l i t y and t h e H u r e w i c z t h e o r e n n e n s u r e s t h a t t h e
inclusions
iV;
-
h'^k'kU
M
1
W, M . b
W, a r e h o m o t o p y e q u i v a l e n c e s .
-174C h a p t e r VIII - - S o m e E m b e d d i n g T h e o r e m s
1.
An E m b e d d i n g T h e o r e m R e l a t i v e t h e Boundary-
Theorem 8.1. M compact.
Let
Let
m"^
and
f:(M, 9M)
£ 9M i s a P , L . e m b e d d i n g . c o n n e c t e d , and if
q"^ be c o n n e c t e d P . L . m a n i f o l d s ,
5> (Q, 9Q) be c o n t i n u o u s , and s u p p o s e t h a t If
q - m > 3 , then
M is ( 2 m - q ) - c o n n e c t e d and Q is (2m-q+l)f
f
(rel
9M) , w h e r e
f
is a P . L.
embedding. Proof. where
By t h e g e n e r a l p o s i t i o n t h e o r e m s of C h a p t e r IV,
g i s a P . L. m a p ,
We c a n s u p p o s e t h a t and
d i m ^^(g) ^ S2(g)
f
g ( r e l 9M),
2 m - q , and g ( I n t M) S Int Q.
Int M. F o r l e t
Q?: M — ( M X O) ^ (9M X I)
P: Q —5> (Q X O ) ( 9 Q X I) be P . L . h o m e o m o r p h i s m s s u c h t h a t
Q;(X) = (x, 1) if X € 9M a n d p(y) = (y, 1) if
y € 9Q.
Then let g'
be t h e fol-
lowing c o m p o s i t e : -1
a
M — »
(M X 0)
( 9 M X I)
> (Q
T h e n S (g') = (
| M X 0)(S (g) X 0), so
B u t we c a n c h o o s e
p so t h a t t h e r e i s a h o m o t o p y
s u c h t h a t for a l l
t, F ^ | 9Q X 1 =
h o m e o m o r p h i s m of
Q X 0 onto
X 0) o (9Q X I)
S (g')CIntM
the c o l l a r outer one.
F ^ | Q X 0 is a P . L .
Q, a n d F ^ ( x , t) = x, a l l Q
x e 9Q and
tel.
= cl(Q-j3(9Q X I)) to
9Q X I a n d t h e n e x p a n d i n g the i n n e r c o l l a r at the e x p e n s e of the S i m i l a r l y for s u i t a b l e a
G^: M —^ (M X 0) - (9M X I) w i t h G^
a n d d i m S (g') < 2m-q
F : (Q X 0) U {9Q X I) —» Q
| 9Q X 1 , F ^ =
T h i s c a n be s e e n by a d j o i n i n g a b o u n d a r y c o l l a r for
—5> Q.
a P . L . h o m e o m o r p h i s m of
, there is a homotopy
0 ^ = 0 ' , G^(x) e x X I for a l l x e 9M, and M onto
MXO
such that
G^(x) = (x, O).
i-l W'
-175Then
g' = F ^ o (g X 1 )o G^
homotopy is relative form
k . g .h, w h e r e
9M.
F ^ o (g X 1) c G ^
F ^ o ( g X l ) o G^
But t h e l a s t m a p m a y a l s o be w r i t t e n in the
k and h a r e P . L . h o m e o m o r p h i s m s of
r e s p e c t i v e l y , w h i c h a r e t h e i d e n t i t y m a p s on So we m a y a s s u m e as connected as
and e a c h
^^{g) C Int M.
9Q and
Q and M
9M.
D i m S2{g) < 2 m - q < m - 3 .
Int M
is
M, a n d so t h e r e i s a c o l l a p s i b l e c o m p a c t P . L . s u b s p a c e
of Int M, w i t h
Q C and
C
d i m C < 2 m - q + 1, by t h e Engulfing T h e o r e m 7.
By t h e s a m e t h e o r e m , t h e r e e x i s t s a c o l l a p s i b l e P . L . s u b s p a c e Int Q s u c h t h a t g ( C ) C D a n d
dim D < 2m-q+2.
D of
By g e n e r a l p o s i t i o n t h e o r e m s ,
t h e r e e x i s t s a P . L . h o m e o m o r p h i s m h : Q — > Q, fixed on g(C), so t h a t d i m ( ( h D - g C ) O g(M)) < ( 2 m - q + 2 ) + m - q = 3 m - 2 q + 2 < 2 m - q - l . So if D' = hD, g
D' = C
X, w h e r e
X i s a c o m p a c t P . L . s u b s p a c e of
M,
and d i m X < 2 m - q - l . Let
C^ = C, D^ = D ' , X^ = X, and s u p p o s e by i n d u c t i o n
we h a v e found c o l l a p s i b l e P . L . s u b s p a c e s
C^ C Int M and
X. C Int M, s u c h t h a t
= C. vj X . , d i m X. < 2 m - q - i
S^Cg) C C . ,
T h e n by the Engulfing T h e o r e m 7. C., C i n t M 1+1
with
C. 1
there is a compact P. L.
X. C C . ^ A 0, and 1 1+1 ^
same t h e o r e m , there is a P. L. subspace -
^^^
D" of Int
idimX. -1, 1
since
dim[k(D"-D. l
m-q < -3.
Let
D.^
1+1
-
= kD".
'
(< m - 3 ) .
By t h e
Q such that
d i m ( D " - D ^ < d i m X . + 2.
= i d e n t i t y and
and
subspace
dim(C.^,-C.) < dim X.+l. 1+1 1 1
tion T h e o r e m , t h e r e e x i s t s a P . L . h o m e o m o r p h i s m k | D . vj
Int Q,
By t h e G e n e r a l P o s i -
k : Q —> Q n
with
g(M) < d i m X. + 2 + m - q
-176For g"^D
= C iC
with
C
iv
k l a r g e enough,
"3 S (g). ^
and D
a n d with
Now l e t
X
=
as
K and L
triangulate
simplicial.
b a r y c e n t e r s to b a r y c e n t e r s ,
Since
and so i£ K" and L" g : K " —> L "
a n d N^ = N ( T ; L " ) , w h e r e
S and T
respectively triangulating
C
of r e g u l a r n e i g h b o r h o o d s , N^
We m a y e x t e n d isaP.L.
T h e n by u n i q u e n e s s
xC i s a n m - b a l l in Int M and N^ i s a q - b a l l
embeds
T and
cl(M-N^)
q is s i m p l i c i a l .
.
e x t e n d s to a P . L . e m b e d d i n g of N^ N by p u t t i n g
Since
N^
is a ball,
As
p i e c e w i s e l i n e a r l y in
p i e c e w i s e l i n e a r l y in
V to a l l of
embedding.
L e t N^ = N ( S ; K " )
-1
and e m b e d s gj 9N^
is s i m p l i c i a l .
N , a s S = q 2
> g|cl(M-N^)
Now
it c a r r i e s
a r e b a r y c e n t r i c 2nd
respectively.
-1
Also, N = q 1
k, now fixed),
a r e s u b c o m p l e x e s of K" and L "
and D zC
cliQ-N^)
M and Q r e s p e c t i v e l y ,
g is n o n - d e g e n e r a t e ,
derived subdivisions, then
S^lg) ^
So we get
triangulated as subcomplexes (some large
g: K — > L
in Int Q.
2 m - q - k < 0.
into
N^, f , s a y ,
f = g on c l ( M - N ^ ) , T h e n (rel.
f
9N^).
N o t e . T h e h y p o t h e s i s t h a t M be c o m p a c t can be r e m o v e d p r o v i d e d we Therefore f g ( r e l 9M), T h i s c o m p l e t e s t h e proof. insist that
f be a p r o p e r m a p , i. e . , f ^ ( c o m p a c t ) = c o m p a c t , and S2(f)
is compact. Corollary 8.1.1. c a n be e m b e d d e d in
,2m-k E
If k < m - 3 ,
a closed, k-connected m-manifold IM
•-177C o r o l l a r y 8. 1. 2.
If
Q*^ i s k - c o n n e c t e d , t h e n e v e r y e l e m e n t of
TT (Q) c a n be r e p r e s e n t e d by an e m b e d d e d s p h e r e p r o v i d e d t h a t ^ . / , q+k-1, r<min(q-3, — ).
2.
An E m b e d d i n g T h e o r e m Modulo the B o u n d a r y m
T h e o r e m 8. 2. fold, and l e t
Let
M
Q be a c o m p a c t P . L . m a n i f o l d ,
f:(M, BM) —5> (Q, 9 0 ) b e a c o n t i n u o u s m a p .
Q
a P. L. mani-
T h e n if
(M, 9M)
i s ( 2 m - q ) - c o n n e c t e d a n d (Q, 9Q) i s ( 2 m - q + l ) - c o n n e c t e d , and if then
£^ f
a P. L.
q-m>3,
v i a a h o m o t o p y of p a i r s , (MX I, SMX I) —> (Q, 8Q), w i t h
f
embedding.
C o r o l l a r y 8. 2. 1. If (Q, 9 0 )
i s k - c o n n e c t e d , an e l e m e n t of
Tr^(Q, 9Q)
m a y be r e p r e s e n t e d by a p r o p e r l y e m b e d d e d d i s k , p r o v i d e d t h a t
P r o o f of T h e o r e m 8. 2.
By t h e r e s u l t s on G e n e r a l P o s i t i o n ( C h a p t e r IV),
and by t h e H o m o t o p y E x t e n s i o n P r o p e r t y for p o l y h e d r a l p a i r s , f — f^ h o m o t o p y of p a i r s , w h e r e
f^ j 9M i s a n o n - d e g e n e r a t e P . L . m a p .
A g a i n by
General Position,
v i a a h o m o t o p y fixed on 9M, w h e r e
is a P . L,
f
^ f 1
Z
In p a r t i c u l a r , Write
f
Int M i s in g e n e r a l p o s i t i o n .
d i m ( S (f ) n Int M) < 2 m - q .
f for
f , and l e t X ^
T h e o r e m 7. X C C \ C
f o
m a p w i t h f - ( l n t M) C Int O and w h e r e
4
via a
= cl(S (f) - S (f) ^ 9M). O
By t h e Engulfing
^
, t h e r e e x i s t s a c o m p a c t P . L . s u b s p a c e C of M s u c h t h a t 9M a n d d i m C < ( 2 m - q ) + 1. B y the s a m e t h e o r e m , t h e r e
-178-
exists a compact P. L. subspace a n d d i m D < 2 m - q + 2. morphism
D of
Q
such that
f(C) C D \
D 8 Q
By G e n e r a l P o s i t i o n , t h e r e e x i s t s a P . L . h o m e o -
h: Q —> Q, fixed on f C
8Q, s u c h t h a t
dim[(hD - (fC) o 9Q) ^ fM] < ( 2 m - q + 2) + m - q < 2 m - q - l .
Therefore,
_I f
(hD) = C i^i X
and
Y, w h e r e
dim X < 2 m - q - l
(because
f is n o n - d e g e n e r a t e )
Y c 9M. Letting
C = C^, hD = D ^ , X = X ^ , Y = Y^, w e c a n define i n d u c t i v e l y
C . , X . , Y. C M and D. C Q guch t h a t X C C V C. - 9M, D. \ D. dQ, 1 1 1 1 o - i ^ i l ^ l a n d f"^(D.) = C.>- X. c Y. , w h e r e Y. C 9M and d i m X. C 2 m - q - i . T h e ^ i' 1 1 1 1 1^ i n d u c t i v e s t e p c o m b i n e s t h e f i r s t s t e p and the i n d u c t i v e a r g u m e n t u s e d in Theorem 8.1.
(At e a c h s t e p , t h e
A s s u m e now t h a t r e s p e c t i v e l y so t h a t
Y^'s a r e i g n o r e d . )
Q is compact. f: K —> L
as subcomplexes, where
Let
K and
is s i m p l i c i a l and
L t r i a n g u l a t e M and Q C^^ and D^^ a r e t r i a n g u l a t e d
k i s a n i n t e g e r s u c h t h a t X^ = ^^
S f i C, u 9M, C \ C, n 9M, D, \ D, " 9Q, f'^D, 2 k k ^ k k ^ k f"^(D 9Q) = C ^ 9M. L e t N = N(9M v. C ; K " ) K N
K
I
= N(9Q u D ; L " ) , w h e r e
K" a n d L "
Then
= C, o Y, , k k k and
so t h a t
K a r e 2nd d e r i v e d s u b d i v i s i o n s so -1
that
f:K"
> L"
is still s i m p l i c i a l .
N \
9M u C \ 9M and
N \ D
Then
f
c o l l a r s in
In fact, N^ a n d N^
M and Q r e s p e c t i v e l y .
Moreover,
9Q \ 9Q, so by u n i q u e n e s s of r e g u l a r
n e i g h b o r h o o d s and e x i s t e n c e of b o u n d a r y c o l l a r s , N^ S 9Q X L
^ ^ = N^.
N^ ^ 9M X I and
m a y be r e a l i z e d a s t h e i m a g e s of b o u n d a r y U s i n g t h e s e c o l l a r s and a d j o i n i n g to e a c h
-179a s e c o n d " i n n e r c o l l a r " , we m a y c o n s t r u c t honnotopies G^: Q —> Q w i t h the following p r o p e r t i e s : homeomorphism
M
3> M - N , F (aM) C N
g (8Q) = 9Q for a l l t . t L e t f^ = f <=F, 3
I
I
a l l h o m o t o p i e s of p a i r s G , N 2 = 9Q and 1 '' P . L.
G ° f oF
I
all
Q and c a r r i e s
0
= f.
0
(M, BM) in
J.
N
into
8Q, and
These homotopies are ^
(Q, 8Q); i . e . , G^fF^(9M) C g^fN^
G fF (8M) C G (8Q) £ dQ. t o t
C l e a r l y , f, 3
c
is the r e q u i r e d
embedding. It r e m a i n s to c o n s i d e r t h e c a s e in w h i c h
the
= identity, G O
=:iGofoF
0
t; G
1
c l ( Q - N ) h o m e o m o r p h i c a l l y onto
and
F ^ = identity, F^ is a P . L.
t
maps
M—> M
C ' s and D ' s a s a b o v e , a n d l e t
f,M u D
in Q m e e t i n g
Then D \ D H P Kl
so t h a t
xC
Q
9Q r e g u l a r l y .
^
Let
Let C
Let
N
= N{D o P - j L " ) . ^ iC X f'^CN^) = N ^ . A l s o , ^
1 iC simplicial,
\
\
J.
VP xC
, so N J.
9Q, P
= Fr Q . M and Q
a r e triangulated as sub-
be b a r y c e n t r i c 2nd d e r i v e d s u b d i v i s i o n s .
u 9M;K"), N
Now, N A P U' D
= Q
K and L t r i a n g u l a t e
and D
complexes. = N(C
P
J.
f: K — > L i s s i m p l i c i a l a n d K" a n d L "
Choose
b e a r e g u l a r n e i g h b o r h o o d of
and f (9M) C p "l
Q i s not c o m p a c t .
Then as
f: K" — L "
i s a r e g u l a r n e i g h b o r h o o d of
is
* P . in Q .
^
X
A l s o , N^*^ P ^
i s a r e g u l a r n e i g h b o r h o o d of
neighborhood).
A s in t h e c o m p a c t c a s e , we w a n t to u s e u n i q u e n e s s of
r e g u l a r n e i g h b o r h o o d s to c o n c l u d e t h a t N^ ^ SM X I, of c o u r s e . )
^^^
(N • N w
(We s t i l l h a v e
Let
^^
^^^ ^^ ^^ ^ d e r i v e d
^ P ) S (P ^
^
X I, 9 P X
X I). J.
-180Let
C , : aQ"" X I > q " be a b o u n d a r y c o l l a r . 1 C^.-aP^Xl 5> P ^ be a b o u n d a r y c o l l a r . Let C ^ : be a b o u n d a r y c o l l a r . P^ X [ 0 , £ ] C
Let
Let X I) X I —» P ^ X I
t. > 0 b e s u c h t h a t
X 0) ^ ( 8 P ^ X I)] X I).
to be the following c o m p o s i t e c p ^ x [0, >] — [ ( p ^ X 0)
Define
c:P^X[0,6 ]
(c^c)Xid. £
( a p ^ x I)] X I
.> 9 Q
> Q"
c. X I - 4 > Q^
Imc,
Imc • P^XO
T h e n it follows f r o m r e s u l t s in t h e s e c t i o n s of C h a p t e r IV on u n i q u e n e s s of regular neighborhoods that there exists a P. L. ( N ^ j N ^ n . p ^ ) S (P^X [ o , i Now define
homeomorphism
X [ 0 , £ ] ) ^ (P^ X [ 0 , 1 ] , ap^ X [ 0 , 1 ] ) .
f : M —5> Q''
by l e t t i n g
f
be the c o m p o s i t e w i t h P . L .
homeomorphisms: M ~ — >
cl(M-N^) —
-> C1(Q"'- N ^ )
— -
As in t h e c o m p a c t c a s e , we c a n c h o o s e "i and ^ so t h a t topy of p a i r s , (M, aM)
> (Q*; P^) C (Q, dQ).
Q . f = f
via a homo-
T h i s c o m p l e t e s t h e proof.
-181-
Note.
A s e p a r a t e a r g u m e n t for t h e c o m p a c t c a s e wovild h a v e b e e n
u n n e c e s s a r y , h a d w e d e v e l o p e d t h e r e g u l a r n e i g h b o r h o o d t h e o r y for r e g u l a r n e i g h b o r h o o d s of n o n - c o m p a c t P . L . s u b s p a c e s of a P . L . space.-
3.
E m b e d d i n g into a n o n - b o u n d e d m a n i f o l d .
Definition .
Let
f: X —5> Y b e a c o n t i n u o u s m a p of t o p o l o g i c a l s p a c e s .
T h e n B(f), the b r a n c h l o c u s of
f, c o n s i s t s of a l l t h o s e p o i n t s of X
no
n e i g h b o r h o o d of w h i c h i s e m b e d d e d b y f. Suppose
f: M — > Q, M c o m p a c t , i s a n o n - d e g e n e r a t e P . L . m a p of P . L .
manifolds (or spaces).
Then
and d i m B ( f ) ^
d i m S2(f).
with f : K — > L
simplicial.
star
st(Q;K)
degenerate.
But fr
equals
cr , b e c a u s e
M, B(f) C
K a n d L t r i a n g u l a t e M and Q r e s p e c t i v e l y ,
If x € B{f), l e t x e o", cr € K.
1
= fx
\
i s a P . L . s u b s p a c e of
F o r let
contains points
and z € T^ , w h e r e 2
B(f)
y, z , and
y ^ z, w i t h f(y) = f(z). tr < T . . 2
because
Then
Then the open Suppose
r. 4 T. b e c a u s e 1 ' 2
f is simplicial.
y e t^
f is non-
A l s o , n e i t h e r T. n o r T
Lt
^
f is n o n - d e g e n e r a t e .
Therefore
cr C B(f)
and
T and T
a r e c o n t a i n e d in T h e o r e m 8.3.
Let
m " ^ be a c o m p a c t P . L . m a n i f o l d ,
Q^ be a P . L . m a n i f o l d w i t h o u t b o u n d a r y . (M, 8M) i s ( 2 m - q - l ) - c o n n e c t e d .
Suppose that
T h e n if f: M — Q
f is h o m o t o p i c to a P . L . e m b e d d i n g ,
f.
8M f
q-m > 2
C^
Let and
is a continuous m a p ,
182 Proof.
Let
£ b e h o m o t o p i c to
d i m ^^(f^) < 2 m - q . so t h a t
Let
> L is s i m p l i c i a L
f^S^^ i Now l e t
of K'
K
o
Let
K'
dim
> 2m-q} .
Hence
K^ A B(f) = ^
K
.
Therefore
Then K
1 K ^ n S^^f^) =
1
be t h e s i m p l i c e s
= {a^.. . . o^ | ( T , < . . . < cr and 1 r 1 r o" « ~ 2m-q}.
so t h e r e e x i s t s a n e i g h b o r h o o d f|K
i s a c o m p a c t s e t not m e e t i n g N^
of
K^
c : 8M X I
is ( 2 m - q - l ) - c o n n e c t e d ,
such that
1
U of
| K^
in
K
is a n e m b e d d i n g and e a c h
M - h ( I m c) C U.
But
K^.
Hence t h e r e is a derived
M - U 9 N^ \ K^ .
> M be a b o u n d a r y c o l l a r .
T h e n (M, c ( 9 M X [O, l)))
and s o , f r o m engulfing t h e o r e m s [ C h a p t e r
t h e r e is a P . L, h o m e o m o r p h i s m
the identity.
K
h a s a n e i g h b o r h o o d e m b e d d e d by f.
Now M - U
Now l e t
be a f i r s t d e r i v e d s u b d i v i s i o n
cr so t h a t if d i m o"^ > 1, f^o"^ =
f I U i s an e m b e d d i n g , b e c a u s e 1
neighborhood
M and Q respectively,
be the 2 m - q - l s k e l e t o n of K, and l e t
o
point of K^
i s n o n - d e g e n e r a t e and
.
w h i c h do not m e e t
s u c h that
f^
K a n d L b e t r i a n g u l a t i o n s of
of K w i t h e a c h s i m p l e x s t a r r e d at then
, where
h: M —> M w i t h N^ C h ( I m c ) .
M S M - h ( I m c)
Composing with
7
],
So
by a h o m e o m o r p h i s m h o m o t o p i c to
f^ | M - h ( I m c)
gives the r e q u i r e d embedding.
-183C h a p t e r IX: C o n c o r d a n c e and I s o t o p y 1.
Introduction.
Definition . I
A p r o p e r c o n c o r d a n c e of
M in Q i s a P . L .
5> Q X I w i t h F " ^ ( Q X O ) = M X O ,
F:
MX
F
(9Q X I) = 8M X I .
F ( x , t) = (F^x, t),
F
F " ^ ( Q X 1 ) = M X 1 ,
is a c o n c o r d a n c e b e t w e e n
t = 0, 1.
F
embedding
F ^ and F ^ ,
i s s a i d to b e fixed on t h e b o u n d a r y
where if
F a M X I = (F (aM) X 1. o Definition .
Two p r o p e r e m b e d d i n g s
f and g a r e s a i d to be ( p r o p e r l y )
c o n c o r d a n t if t h e r e e x i s t s a c o n c o r d a n c e b e t w e e n t h e m . In t h i s c h a p t e r we c o n s i d e r t h e q u e s t i o n of w h e n c o n c o r d a n c e i m p l i e s isotopy.
F o r e x a m p l e , c o n c o r d a n c e d o e s not in g e n e r a l i m p l y i s o t o p y w h e n
the codimension
(dim Q - d i m M) is t w o .
F o r e x a m p l e , t h e " s l i c e k n o t s " of
c l a s s i c a l knot t h e o r y a r e p r e c i s e l y t h e k n o t s c o b o r d a n t to the t r i v i a l k n o t . The m a i n p o s i t i v e r e s u l t s t h a t we s h a l l p r o v e a r e t h e following two about a p r o p e r c o n c o r d a n c e Theorem 9.1. isotopy
H of
of
M in Q fixed o n t h e b o u n d a r y , M c o m p a c t .
d i m Q - d i m M > 3, t h e n t h e r e e x i s t s an a m b i e n t
Q X I, fixed on
T h e o r e m 9.Z . isotopy
If
F
9(Q X I), s u c h t h a t
H^c F
is level p r e s e r v i n g .
If d i m Q - d i m M k 3, t h e n t h e r e e x i s t s an a m b i e n t
H of (Q X I), fixed on
(Q X 0 ) u {dQ X I), s u c h t h a t
H^® F = F ^ X 1,
-1842.
Relative
Second Derived
Let N(K
C
- K o
l
This
; K 2
K' C
is
K'
1
ring the
be finite
) = { o - e K
subcomplex
Let
K^
called the
simplices
of
K^
K
(= K ' ) X
in o r d e r
some
derived.
K"
complexes.
simplex
Let
in order
from
by
^
K^
= p
l i n k l A j K ^ ) ^
L e m m a
or
- k J
- K * ;
K*)
starring
dimension.
that if
Proof.
a single
),
as
=
9.3.
- K^
e K^-
K^,
;K
) \ (K
- K
A
O
Let
{A
simplex.
K^"
(C }
- k J
; K y
Suppose that
A
N = N(K
If
A
K
C o ~
So t h e
= (K^
of decreasing
simplex
C.
-K
be the
all the e K
1
K
1
C
n
1+1
2
A. C.. 1 1
For
- K
(A.C.) 1 1
may
of
, i
same
K^ , 2
K. 1 ^Q)
simplices
is t r u e
is full
full is
of
N
of
in
K^'.
in K. , , 1+1 ^
or
not meeting °
.
each
By
i,
link(A^; K^)
fullness
Moreov
i = l , 2 .
a single
Y
Then
n
cl(N.' 1
( N . ^ J 1+1'
N . ^ J = 1+1'
^ (A.C.) n(K 1 i'
K
- K 1
simplex
C
i
.
,
in
o
H (K^-
N = M A
o
A..C.). J y
M
We
simplices - K
star-
'
) .
1 (
by
2
K^J
O
dimension.
K
K'
in
.
link(A;K^)
X
which meets
N. = (K - K ) u J 1 o (A.C.) 1 1
mod K
dimension.
- K^)''
1 order
K^
^
link(A;K2)
Then
K. - K } . ° l o
be o b t a i n e d f r o m
2
of d e c r e a s i n g
K^
of d e c r e a s i n g
k '
let
T meeting
A
Suppose
Then
s i m p l i c i a l neighborhood of
- K^
obtain a second derived
simpliciial for
O-
2
be f i r s t
2
Neighborhoods.
K
) = a
singl
Let
i
A..C.. 1 1 - K
o
) u ( U (A.C.r > , i i
A.C. 1
j^+1 C a . C .
1 1
.
So
(A.C.)
11
n
(N.^J
1+1
= A.C.
11
.
So
N. V N . ^ ^.
1^1+1
Therefore
N \ K -
K
^ l o
.
-185-
Lemma 9.4.
With t h e c o n d i t i o n s of L e m m a 9 . 3 , s u p p o s e
a r e m a n i f o l d s and
K
Q aK^ . o 1 same dimension as K .
Then
N{K. - K ;K_) 1 o d
K^ and K^
is a m a n i f o l d of t h e
Lt
Proof. and l e t
B y i n d u c t i o n o n t h e d i m e n s i o n of K ^ .
A e N.
If A m e e t s
K - K , then 1 o
Let
N = N(K^ - K^; K^),
link(A;N) = link(A;K_), Z
a sphere or ball. Suppose
A rA ( K ^ - K^) =
Then
link(A;N) = N [ l i n k ( A ; K J O K C^
- l i n k ( A ; K ) ^ K ; l i n k ( A ; K )]. X
^
O
0- e Link(A; N) < = > orA e N < = > cr < p , Ap e K^ and 0- e N [ L n K , - L 1 Now
K ;L o
K^], 2
L rN K^ C L t-\ K^ C L
p n, ( K ^ - K^) f ^
L = link(A;Kj. Z s a t i s f y t h e h y p o t h e s e s of t h i s l e m m a .
c e r t a i n l y e a c h of t h e s e c o m p l e x e s i s full in t h e n e x t . l i n k ( B ; L)
( L H ( K ^ - K^)) = l i n k ( B , L)
o r a single simplex. of t h e m a n i f o l d If A / K^ , simplex.
L
L
K^ C link(A;9K^)
p n o t e q u a l to
By L e m m a 9,3,
= link(AB; K^) H (K^- K^) = is a submanifold
is c o n t a i n e d in the boundary.
K^ C dK^ , so L ^^ K^ = p, a s i n g l e
p a n d so l i e s in link(A;N)
K^- K
, p A K^
is a s u b -
9p.
i s a m a n i f o l d of t h e a p p r o p r i a t e
l i n k ( A ; N ) \ L H (K - K^) = p \ o
If A e K^ , l i n k ( A ; N ) y i n k ( A ; N ) n
For
If B € L ,
K^ = l i n k ( A ; K ^ )
A is a face of a s i m p l e x m e e t i n g
T h e r e f o r e by i n d u c t i o n dimension.
( K ^ - K^)
L n K^ = L n ( K ^ - K^), a s
Since
c o m p l e x of
If A e K^, t h e n
L and
For
L*
= link(A; K^) \ 0.
is a c o l l a p s i b l e m a n i f o l d and so i s a P . L . b a l l .
if A / K^ . So
link(A;N)
-1863.
The Main L e m m a .
L e m m a 9. 5.
Let
> Q ^ X I,
b"^
p r o p e r c o n c o r d a n c e w h i c h i s fixed on the b o u n d a r y . Let
U be an o p e n n e i g h b o r h o o d of F ^ b " ^
ambient isotopy H^o
H of
in Q.
a n d m - b a l l , be a Suppose
q - m > 3.
T h e n t h e r e e x i s t s an
(Q X I), fixed o n (Q X 0) o (9Q X I), s u c h t h a t
XI) C U X L
Picture:
T h e m a i n i d e a i s to c o n s t r u c t " w a l l s " ( d o t t e d line) a n d t h e n to p u s h t h e c o n c o r d a n c e back behind the w a l l s .
T h a t i s , we find
W.
such that
FrW.
1
i s not o v e r s h a d o w e d b y W.
1
and u s e t h e s e to " p u s h t h e c o n c o r d a n c e b a c k "
u n t i l it e v e n t u a l l y l o o k s l i k e t h e 2nd p i c t u r e . P r o o f . o f L e m m a 9. 5.
F r o m t h e c h a p t e r s on G e n e r a l P o s i t i o n and
Sunny C o l l a p s i n g , t h e r e is a P . L . h o m e o m o r p h i s m p r e s e r v i n g and a m b i e n t i s o t o p i c to
h: Q X I
5> Q X I, l e v e l
1 by an a r b i t r a r i l y s m a l l a m b i e n t i s o t o p y .
-187such that
h F ( B X I)
X = hF(B"^XI), choosing
s u n n y c o l l a p s e s to
X
h F ( ( B X O)
= h F ( ( B ™ X 0) - (SB X I)).
o h n e a r e n o u g h to
(9B X I)).
We m a y a s s u m e by
1 that t h e r e is a neighborhood
V of
F^B"^
in Q s u c h t h a t X Let
C V X I C h(U X I). o K Q K b e t r i a n g u l a t i o n s of X
Let
G
C X and l e t
J be a triangulation
O
of
Q s u c h t h a t t h e i n c l u s i o n e m b e d s K l i n e a r l y in J X I and s u c h t h a t ves \es es t h e r e is a s e q u e n c e K = K^ ^r-1 \ "' ' \ ^ o ^^^^ s h a d o w K. n 1
K
C K. - "i-r
Let
a K and
^J
be s u b d i v i s i o n s s u c h t h a t if p^: Q X I
p r o j e c t i o n on t h e f i r s t c o o r d i n a t e , t h e n p^ | K:
c<.K
3>
> Q is is simplicial.
It follows f r o m t h e l a s t s e c t i o n of C h a p t e r V, a l r e a d y q u o t e d , t h a t m a y be c h o s e n so t h a t
p^|K
h
above
i s n o n - d e g e n e r a t e ; t h i s a l s o follows d i r e c t l y f r o m
the sunny c o l l a p s e .
So l e t
P^|K: .\"K
still simplicial.
Let
Let
> iK.. be t h e l i n e a r m a p defined by
>
the 2nd c o o r d i r a t e . setting
-{"K and
c<."K
.(v) = 0 if v is a v e r t e x of
a v e r t e x of
:v"K - oC"K. .
Then
i|i .
^"J
be 2nd d e r i v e d s u b d i v i s i o n s w i t h T; Q X I
o(."K. and
I
b e p r o j e c t i o n on
^ ^{v) = 1+ T(V) if v
(O) = oa'K , a s
is
cv"K. i s full in
-1
In p a r t i c u l a r ,
(O)
V X I.
Hence t h e r e exists
0 < t < 1 such that
'^[0, £ ] C V X I. o Let
W^ =
W^ = W = X .
[O, £ ].
T h e n W^ i s a d e r i v e d n e i g h b o r h o o d of
(See p i c t u r e following t h i s proof. )
in
-188-
Claim:
S h a d o w ( W p n W C I n t ^ W. .
Suppose X 6 (f and
x € W., y e W, and x o v e r s h a d o w s
YET
degenerate. p.p' = p.p 1 1
Let
Then
cr = po"^ , p € a"K. Since
F o r each vertex
v of
or the vertex
unless
p^cr = p^T , and
and p.T^ = p.o-^ . 1 1 1 1
p' 6 or "K^ . of
.
V = v'.
v'
of
t ^ with
Therefore
, cr^
y.
tr ^ T a"K.
because - 0.
shadow K . K 1 or^,
C h o o s e cr ^ T e a"(K), p^ j K i s n o n -
L e t T = p'x^ , w h e r e C K. ^ C K. , 1 - 1 - 1
(V) is not l e s s t h a n the v a l u e
p ^ v ' = p^v .
> ijj^Cy) u n l e s s
M o r e o v e r , i|i^{v) >4i^{v') (x^ / x^.
So it suffices to
s h o w t h a t rr , 4 x , . 1 '
1
If A € a " K - a " K . , t h e n B'
of a s i n g l e s i m p l e x
of
B'
link(A; a"K) n
B of
or'K. .
o v e r s h a d o w s any o t h e r .
So a s
o r the f i r s t d e r i v e d p^|K
embeds
T h e r e f o r e if cr^=
B ' , no point
P = p' and so cr = x,
a contradiction. Notation: Let throw
If S Q J x I, l e t Y. = W. o i i W
Y. onto 1
Y. 1-1
.
i
Y
o
Suppose ^^
N = N ( a " ( a A ) - a " ( a A ) ; o-'-K). and
S = S ^^ { p t s . lying a b o v e pts. of S } . r V X I.
Y
r
=W r
K. = K, , + A + a A . 1 1-1
Outside
N,
ijj. =
= X.
We a r e going to & &
Let N i s an ( m + l ) - m a n i f o l d
N\aA. C o n s i d e r 'N.
N /N
(See 2nd p i c t u r e following t h i s proof. )
( Q X I) S p^N = N[p^(aA) - p ^ ( a A ) ; p^(a"K)] \^p^(aA).
A a , t h i s s h o w s t h a t W \ o.
Then Since
p^
embeds
-189-
I a
-190W^
N i s a d e r i v e d n e i g h b o r h o o d of
^"(aA)
in N, a n ( m + l ) - b a l l .
S i m i l a r l y , W^ ^ ^ N i s a d e r i v e d n e i g h b o r h o o d of a " ( a A )
in N a n d so
i s an m + 1 - b a l l . Now If
a(W.
A € Q X 1,
N) = ( F r W . aN = [N
b o r h o o d of e i t h e r i s an n - b a l l . m-manifold.
N) - [W. n N ^ (Q X 1)] ^ [ W . F r ^
(Q X 1)] u F r ^ N ,
A m o d A o r of
N n (Q X 1) = a d e r i v e d n e i g h -
aA m o d aA
If A / Q X 1, aN = F r ^ N.
Y. r, N = (W. 1 i
Fr
W i '
N] L. [W.
1)]
N
N
= an n-ball
Y. ^ ^ " n ^ Y .
So N
Fr^N
T h a t t h i s i s a c t u a l l y t h e c a s e follows
Let
Then because
a n d s i n c e we m a y a s s u m e i s a l s o a b a l l , of d i m q.
is an ^"(aA)
N ^ (Q X 1)].
So
[W. N N N (Q X 1)]
W. ^ N N (Q X 1)]
0.
(Cor.
Y^ i s a n ( m + l ) - m a n i f o l d . 9.6.1).
J X I ( j = t r i a n g u l a t i o n of Q) so t h a t 'N, t h e
a r e all s u b c o m p l e x e s .
(Q X 1)
Nn(QX-l)\^0.
L e t u s a s s u m e for the m o m e n t t h a t e a c h
subdivision.
(Q X 1),
) n n \ ' F r W . o iT u.' W. n N n (Q X 1) ^ i 1 '
S p[FrW.
Subdivide
W
In e i t h e r c a s e
So W. N N \ [ ( F r W^
[FrW.
Similarly
in
W ^ ^ F r N = W. ^ O F r N = a d e r i v e d n e i g h b o r h o o d of
in F r N = an m - b a l l .
N].
K., etc. , , . .
R be a Znd d e r i v e d n e i g h b o r h o o d of 'N' in t h i s N
R is a ( q + l ) - b a l l .
Q X 1 w a s a s u b c o m p l e x of
S i n c e N r (Q X 1) J X I,
R n ( Q X 1)
-191R r Y^ i s a 2nd d e r i v e d n e i g h b o r h o o d of Y^
N in Y^, and so is an
( m + l ) - b a l l , by u n i q u e n e s s of r e g u l a r n e i g h b o r h o o d s . (R r. Y p PN ( Q X 1) i s a n m - b a l l . and (R -^- Y. because
[R
n ( Q X 1) is an m - b a l l .
iL. = d;. ^ o u t s i d e of 1
But
Similarly, R
1-1
q - m > 3.
Similarly, is an ( m + l ) - b a l l
A l s o , Y.
Fr R =
N.
T h e r e f o r e a l l of t h e following b a l l p a i r s a r e u n k n o t t e d :
Y. '- ( Q X 1) C R - ( Q X 1], [R n Y. C R],
[R " Y. , C R]. i-1 Y.
Moreover,
F r R r (Q X 1)
Y. onto
R
ambient isotopy onto
Y.
'
Y. 1
Y.
n ( Q X l ) C R n { Q X 1)],
F r R i s a face of Y. ' R 1
i s t h e b o u n d a r y of
find a n a m b i e n t i s o t o p y of R
' Fr R
Y.
R
(Q X 1).
R, fixed on F r R = cl{9R - R
H e n c e we m a y (Q X 1)), t h r o w i n g
E x t e n d i n g by t h e i d e n t i t y o u t s i d e of
H^ of
and
R, we get an
Q X I , fixed on (Q X 0) w ( 9 0 X I), w h i c h t h r o w s
Y.
,.
1-1
H e n c e by i n d u c t i o n t h e r e i s an a m b i e n t i s o t o p y (Q X 0)
( a O X I), w i t h
H^X C X^ C V X I.
H of
Q X I, fixed on
R e c a l l t h a t X = he
X 1).
-1
Define
H'
by H^ = h
Lemma 9.6. and N
to
V of V X I.
H'
x e y , y e N-N
y in N w i t h So
is the required ambient isotopy. Q X I with p ^ | N
an embedding
( = N a n d p o i n t s lying above N) i s a m a n i f o l d .
By i n d u c t i o n on d i m N.
Now s u p p o s e ball
Then
If N i s a s u b m a n i f o l d of
(Q X 1) C 9N, t h e n
Proof. :
H^h.
If
(Q X 1).
d i m N = 0, t h i s l e m m a is c l e a r . Then there exists a closed P. L.
V n (Q X 1) = ^ .
is a manifold n e a r
T h e n '"v^ i s P . L .
homeomorphic
x; i. e . , t h e r e is a n e i g h b o r h o o d of x
in
-192'N w h i c h i s P , L . h o m e o m o r p h i c to a b a l l . X e N n (Q X 1).
T r i a n g u l a t e ' n ' SO t h a t
Say, on t h e o t h e r h a n d , p^
'17 —> Q i s s i m p l i c i a l ^
for s o m e t r i a n g u l a t i o n of a ball m e e t i n g link(x;N)
Q.
Then
I'""
link(x; N ) = l i n k ( x ; N ) .
Q X 1 in a s u b s e t of i t s b o u n d a r y .
is a manifold.
—
But ""linkCx;
L,ink(x; N)
is
So b y i n d u c t i o n ,
l i n k ( x j N ) \ o , and so is a b a l l .
So N is a m a n i f o l d . Corollary 9.6.1. Let
K
with
X Q Q X I be a p r o p e r l y e m b e d d e d m a n i f o l d .
X be a p o l y h e d r o n .
( s h a d o w W) Proof.
aN = N
Let
Let
X C Int^^W,
If N = F r ^ W , t h e n
ax r
So W ^ F r ^ W
( Q X 1).
W b e a d e r i v e d n e i g h b o r h o o d of K
Then
in X,
W -- f r ^ W ^ i s a m a n i f o l d .
p ^ | N : N — > Q is an e m b e d d i n g .
T h e r e f o r e "TT i s a m a n i f o l d .
C l e a r l y , N ^ a'N.
i s t h e u n i o n of two m a n i f o l d s of t h e s a m e d i m e n s i o n w h i c h
m e e t in a s u b m a n i f o l d , o f o n e l o w e r d i m e n s i o n , c o n t a i n e d in t h e b o u n d a r y of each. Therefore it is a m a n i f o l d .
-1934.
P r o o f of T h e o r e m s 9. 1 a n d 9. 2.
T h e o r e m 9. 2. fixed on H of
Let
F : M ^ X I —> Q*^ X I be a p r o p e r c o n c o r d a n c e ,
SM, M c o m p a c t a n d
q - m > 3.
Then t h e r e is an a m b i e n t isotopy
Q X I , fixed o n (Q X O) w (8Q X I), s u c h t h a t
Proof.
B y i n d u c t i o n on
be t h e s i m p l i c e s of K^ ~ ^ ^
K - dK,
•••
on a n e i g h b o r h o o d
h^^^ of
h'
Q X I , fixed on
is defined.
U of
Now
N
N .J
Let
1
> QXI
C U X I and N
1
= (p, o 1
K
( 9 Q X I), s u c h t h a t
Triangulate
5> Q X I i s fixed M X I, Q X I ,
and
Let
1
M X I.
a n d N^ b e 2nd d e r i v e d 2 in
Q ,
Then clearly
2
respectively, N
= N X I, 1 3
. o
5> Q" X I .
Q* = c l ( Q - N^).
^ ^ ^ ^
in A . , b e c a u s e of t h e o r d e r i n g of t h e 1 " a ball.
9M.
M X I a n d of
M * = c l ( M - N^), a n d l e t
F ' I M* X I: M " X I
Let
> Q a r e s i m p l i c i a l , a n d so t h a t
^^^ ^ ^ ^
= (F')'^N O
{A.}^ 1 1
We s h a l l d e -
(i-1) F' = V ^''FrMXI
(p o F ' ) ( K . , X I) = F ' ( K . J . 1 1-1 o 1-1
such that
(Q X O)
A^ X I a r e t r i a n g u l a t e d a s s u b c o m p l e x e s of
n e i g h b o r h o o d s of
Let
Pi
M X I
K^ ^ X I a n d
M.
K^ .
K^ ^ a n d o n
F' Q so t h a t
K triangulate
in o r d e r of i n c r e a s i n g d i m e n s i o n .
i s fixed o n a n e i g h b o r h o o d of
Suppose that
where
Let
t h e s e s i m p l i c e s and a l l t h e i r f a c e s ) .
fine a m b i e n t i s o t o p i e s h^^^^ F
d i m Q.
H^ ° F = F^ X i d .
Let
F* =
i s a d e r i v e d n e i g h b o r h o o d of A.. 1
Put
B = A. n M 1
= A. - A. 1 1
aA. N^ , 3
-194Let
V be a r e g u l a r n e i g h b o r h o o d of F ^ B
t h e r e e x i s t s an a m b i e n t i s o t o p y
k ^ F ( B X I) C (int V) X I.
such that
V is a q - b a l l . k'
k of
in
Q .
By P r o p o s i t i o n 9.5,
Q ' X I, fixed on (Q X 0) w (9Q X I),
By u n i q u e n e s s of r e g u l a r neighbourhoods
By t h e u n k n o t t i n g of b a l l s , t h e r e e x i s t an a m b i e n t i s o t o p y
of V X I, fixed o n (V X O) o (9V X I), s u c h t h a t
k ^ k ^ F ' I B X I = F ^ X id I B X I.
We m a y e x t e n d
l e t t i n g it be c o n s t a n t l y t h e i d e n t i t y o u t s i d e
k'
to a l l of Q " X I by
V X I,
Put
F " = k ; k , F * : m''' X I — * q " X I. 1 1 Now t r i a n g u l a t e to m a k e with
X I
Q
B X I triangulated as a subcomplex.
s i m p l i c i a l and l e t Let
M
Let
So is
Lemma 9.7.
B in
N
simplicial.
Subdivide so t h a t
= (F " ^ N j X I. N D
4
in m " X I.
Q
F"
N^ be t h e 2nd d e r i v e d n e i g h b o r h o o d of F ^ B
N. = (p.F")"^N^.
n e i g h b o r h o o d of
X I
O
= F "^(NJ
4
M , and so N^
(
O
and in
p
are
Q .
is a d e r i v e d
4
i s a d e r i v e d n e i g h b o r h o o d of B X I
N^. T h e r e is an ambient isotopy k"
(M'" X 0) - (8M* X I), s u c h t h a t
k" N
of M
X I , fixed on
= N, .
1 5
D
(Proof postponed until l a t e r . ) P r o o f of 9. 2 c o n t i n u e d .
Let
k"
be a s in L e m m a 9 . 7 .
extension t h e o r e m , t h e r e exists an ambient isotopy on (Q" X 0) o (9Q' X I), so t h a t
k'" of Q
X I , fixed
k'" F " N , = F " N , . 1
Put
By the i s o t o p y
5
D
F'"= ( k p ' ^ F " . Then = N^ = N^ X I. C o n s i d e r X 1. T h e n t h e i m a g e of t h i s m a p i s c o n t a i n e d in
X I,
-195-
a s in fact
N , = F " (N J . 7 o ' 4
Moreover,
a{Fr
M'
N ) = (Fr .N ) ^ 8M . ' M* I
T h e r e f o r e w e a r e i n t h e s i t u a t i o n in w h i c h t h e i n d u c t i v e h y p o t h e s i s a p p l i e s to give u s a n a m b i e n t i s o t o p y I i
sides, such that
k*- ' of
X I, fixed on t h e b o t t o m a n d
kj^V'" Fr X I = F X i d l F r . N ^ X I. 1 M* ^ ° M- 7
The
k^^^
(4) e x t e n d s to a l l of (Q*X 0 ) u
Q
XI
to a n a m b i e n t i s o t o p y a l s o c a l l e d
k
, fixed on
{aQ*xi).
By t h e u n k n o t t i n g of b a l l s , t h e r e e x i s t s an a m b i e n t i s o t o p y Q"" X I, fixed o n ( Q " X O)
k^^^
of
(9Q" X I) U (Q" - N^) X 1, so t h a t
^ I = (^o ^
X I.
T h i s c o m p l e t e s t h e p r o o f of t h e
i n d u c t i v e s t e p b e c a u s e t h e r e l a t i o n of a m b i e n t i s o t o p i c i s a n e q u i v a l e n c e relation. To s t a r t t h e i n d u c t i o n put
q = 3, m = 0.
T h e n a s i m p l e v e r s i o n of
t h e s a m e p r o o f w o r k : t h e r e a r e no n e i g h b o r h o o d s in w h i c h to s t r a i g h t e n out the c o n c o r d a n c e , P r o o f of M''^ X I .
N
Now l e t
or: M
7
a n d so a n i n d u c t i v e h y p o t h e s i s i s not n e c e s s a r y .
Lemma
9.7.
N^
= N^ n (M'"^ X 0), 5 XI
5> M
B XI
in
N , = N X I, N_ n (BM* X I) = N , O (aM*X I). 6 7 5 D
XI
* (M
i s a d e r i v e d n e i g h b o r h o o d of
be a P . L. h o m e o m o r p h i s m throwing 5|s
X 0) O ( 9 M
b o r h o o d s of
X I) o n t o
M
X 0.
orN^ a n d
ofN^
aB, m e e t i n g the boundary regularly.
are regular neigh-
Let
N
= aN 8
(M
X 0)
5
>!<
Q'N^ ^ (M
X 0).
ambient isotopy
B y t h e u n i q u e n e s s of r e g u l a r n e i g h b o r h o o d s , t h e r e i s a n H of
a m b i e n t i s o t o p y of
M
X I such that
m"" X I defined by
H^(aN^) = Ng X I.
Let
H^ = [H^Km"' X 0)] X 1.
H' Then
be t h e
-196-H ' ( N ^ X I) = 1 o
o
X I) and
S i m i l a r l y , we m a y t h r o w
{ H ' ) " ^ H is a n a m b i e n t i s o t o p y fixed on aN.
onto
N
D
X I, k e e p i n g
in Suppose
F: M
fixed on 9M, M c o m p a c t , q - m > 3. H of Q X I, fixed on Proof. (Q X 0)
1) = (k^x, 1),
J2f(s, 1) = s, j^(l,t) = t, K':(QXI)XI K'
XI
3> Q X I
H^F
X id.
>QXI
HtQXIXI
and H^F = (K^) 5.
Q X I, fixed on
L e t <ji-. I^ —> I b e a P . L . m a p w i t h
by putting
is t h e i d e n t i t y .
->QXIXI
K of
L e t k b e t h e a m b i e n t i s o t o p y of Q
K'
s.tel.
Define
K ' ( x , s , t) = (k^^^ ^^(x), s , t ) .
i s t h e i d e n t i t y on ( 9 0 X I X I) ^^ (Q X 0 X I)
K^:QXI
is a p r o p e r c o n c o r d a n c e
is l e v e l p r e s e r v i n g .
0) = Jif(0,t) = 0 for a l l
->(QXI)XI
N^ .
T h e n t h e r e e x i s t s an a m b i e n t i s o t o p y
a(Q X I), s u c h t h a t
( a Q X I), w i t h K ^ F =
N^ onto
Q
By 9. 2, t h e r e e x i s t s a n a m b i e n t i s o t o p y
defined by
Com-
a g i v e s an a m b i e n t i s o -
M'" X I, fixed o n (M""X O) U (^M' X I), t h r o w i n g
Theorem 9.1.
X 0 fixed.
O
p o s i n g t h e s e two i s o t o p i e s a n d c o n j u g a t i n g with topy of
M
m"'x 0.
(Q X I X O).
a g r e e s with
by H = { K ' ) " ^ K .
Then
Then
K^ o n
Q X 1.
H is fixed on
Define
8(Q X I)
K ^ F = ( K ^ ) F ^ X id i s c e r t a i n l y l e v e l p r e s e r v i n g .
Extensions.
In t h i s s e c t i o n we quote w i t h o u t p r o o f two f u r t h e r r e s u l t s along t h e s e lines.
T h e f i r s t follows f r o m w h a t we h a v e a l r e a d y s h o w n , t h e s e c o n d c a n
be p r o v e n u s i n g a r e s u l t o n u n k n o t t i n g of c o n e s q u o t e d at t h e end of the c h a p t e r on Sunny C o l l a p s i n g and U n k n o t t i n g .
-197m 9.7. and
If F : M
Q X I —> Q X I i s a p r o p e r c o n c o r d a n c e and if
M is compact, then t h e r e is a ambient isotopy
Q X 0 , w i t h H ^ F = F ^ X id, and an a m b i e n t i s o t o p y with K^F l e v e l p r e s e r v i n g . •9.8.
H of K^
q-m > 3
Q X I, fixed on
fixed on Q X 91,
If K C K a r e p o l y h e d r a and f: K X I — > Q^ X I i s a c o n c o r d a n c e o
w i t h f"^(Q X 0) = K X 0, f"^(Q X 1) = K X 1, f'^{8Q X I) = K^ X I, and if dim K < q-3
and d i m K
Q X I, fixed on can insist that
< q - 4 , t h e n t h e r e e x i s t s an a m b i e n t i s o t o p y
Q X 0, w i t h
H , F = F X id. 1 o H be fixed on 9 Q X 1.
If F
H of
i s fixed on K , t h e n one o
-198C h a p t e r Xt 1.
An Unknotting T h e o r e m K e e p i n g the B o u n d a r y F i x e d .
T h e o r e m 10. 1. let
Let
M™ and
Q ^ be c o m p a c t P . L . m a n i f o l d s ,
f, g : M—5> Q be two p r o p e r P . L . e m b e d d i n g s .
ho mo to pic to and
S o m e Unknotting T h e o r e m s
Q is
g r e l a t i v e 9M.
T h e n if
(2m-q+2)-connected, then
Suppose that
f
and is
q - m ^ 3, M i s ( 2 m - q + l ) - c o n n e c t e d , f and g a r e a m b i e n t i s o t o p i c k e e p i n g
9Q fixed. Proof. f to
g.
Let
F t M X I —> Q X I be a ( l e v e l - p r e s e r v i n g ) h o m o t o p y of
F j 9 M X I = (f X i d ) | 3 M X I.
Now, ( M X I) is q ( m + l ) - ( q + l ) = 2 m - q + 1
c o n n e c t e d , and Q X I i s q ( m + l ) - ( q + l ) + 1 c o n n e c t e d . bedding t h e o r e m 8.1
, F
a proper embedding.
Therefore
H e n c e by t h e e m -
i s ho m o t o p i c r e l a t i v e a(M X I) to F ' : M X I —» Q XI, F'
i s a p r o p e r c o n c o r d a n c e of f to g, fixed
on 9M.
B y T h e o r e m 9 . 2, t h e r e i s an a m b i e n t i s o t o p y H of Q X I, fixed on
(Q X 0)
(9Q X I), w i t h H ^ F ' = F ^ X i d .
i s o t o p y , fixed on 9(Q X 1), t h r o w i n g Corollary 10.1.
Then
H | (Q X 1) X I i s a n a m b i e n t
g onto f = [ H | Q X 1 X l]^ o g .
Any k - c o n n e c t e d c l o s e d m a n i f o l d
^2m-k + l
L
M u n k n o t s in
2m-k
; i . e . , any two embeddings of M in E C o r o l l a r y 10. 1. 2;
If
a r e isotopic, If k ^ m - 2 .
Q is k - c o n n e c t e d , t h e n the e l e m e n t s of •Tr^(Q)
c a n e a c h b e r e p r e s e n t e d b y a u n i q u e i s o t o p y c l a s s of e m b e d d e d s p h e r e s , provided that r < min(q-3,
).
-1992.
An Unknotting T h e o r e m Moving t h e B o u n d a r y
T h e o r e m 10. 2.
If f, g: M " ^ — > Q*^ a r e p r o p e r P . L .
embeddings,
M c o m p a c t , £, g h o m o t o p i c a s m a p s of p a i r s (M, 9M) —5> (Q, 9Q); and if q-m>3,
(M, aM) is ( 2 m - q + l ) - c o n n e c t e d ,
and if (Q, 9Q) i s ( 2 m - q + 2 ) -
c o n n e c t e d , t h e n f and g a r e a m b i e n t i s o t o p i c . Note;
As in 10. 1, it suffices to s h o w t h a t
Unfortunately,
f and g a r e properly concordant.
we h a v e not p r o v e d an a p p r o p r i a t e e m b e d d i n g t h e o r e m ; we
n e e d to a l t e r a h o m o t o p y to a n e m b e d d i n g k e e p i n g Proof.
Let
F: M X I
> Q X I b e a ( l e v e l p r e s e r v i n g ) h o m o t o p y of
f to g, w i t h F ^ ( 9 M ) C 9 Q for so t h a t
F^ = F ^
p o s i t i o n f i r s t to
all t.
We m a y a s s u m e t h a t t h e r e is
for t < £ a n d F^ = F ^ [£,!-£
9MX
M X 91 fixed.
] in
for
t > 1-c .
9QX[P,1-£]
£>0,
Applying g e n e r a l
and t h e n to M X [ ; , 1 - £ ]
in Q X [c , 1 - - ] (this a l s o u s e s t h e w e l l - k n o w n h o m o t o p y e x t e n s i o n p r o p e r t y for p o l y h e d r a ) , we get a p r o p e r P . L. m a p
F': M X I —5> Q X I, with the
following p r o p e r t i e s :
2)
c M X [c , 1 - ^ ] .
3) d i m [ S ^ ( F ' ) r- (9M X I)] < 2 m - q 4) d i m ( S 2 F ' ) < 2 ( m + l ) - ( q + l ) = 2 m - q + l . Now ( M X I n t I , (WXIntI,
9(MXIntI))
9(QXIntI))
is
is
( 2 m - q + l ) - c o n n e c t e d and
(2m-q+2)-connected.
c o m p a c t p o l y h e d r o n in M X Int I.
Notice that
S^F'
is a
By an a r g u m e n t we h a v e u s e d s e v e r a l
-200times (see
Engulfing T h e o r e m 7 . 8
there exist polyhedra such that
C a n d D in
S^F' C c \ C
T r i a n g u l a t e so t h a t and
D ( 9 M X
simplicial.
I)
Let
M X Int I a n d Q X Int I,
respectively,
( 9 M X I), D ^D n (9Q x Int I), a n d
( F ' ) ' ^ D = C.
F'
is s i m p l i c i a l and
a r e all subcomplexes. N
a n d t h e e m b e d d i n g t h e o r e m 8. 2)
S ^ ( F ' ) , C , D, C
( 9 M X I),
T a k e 2nd d e r i v e d s k e e p i n g
= 2nd d e r i v e d n e i g h b o r h o o d of
D in
Q X I.
F'
Let
Li
\
N^ = ( F ' )
N ^ , a 2nd d e r i v e d n e i g h b o r h o o d of
F ' | c l ( M X I - N^) —> c l ( Q X I - N^) t h e p r o o f it suffices to find
kF'h
So N^
Let
boundary collar. C^(9MXI),
N2=N^(9MXI). Then
M X I.
is a p r o p e r e m b e d d i n g .
h | M X 91 = i d
is a proper concordance from
i s a r e g u l a r n e i g h b o r h o o d of
regularly.
in
P. L. homeomorphisms
a n d k : c l ( Q X I - N^) —> Q X I w i t h then
C
C Let
h: c l ( M X I - N^) —> MX I and
f to g.
k | Q X 9 I = id.
Now
d e r i v e d n e i g h b o r h o o d of
N, , T h e n
cl(M X I-N^).
(9M X I).
c : 9(M X I) X I —» M X I b e a
c(N2 X I ) ^ C [ ( N 2 X l ) . ( g N ^ X I)].
M X I and
cl(MXI-N)
So t h e r e i s a P . L .
Let
N ^ be a
a r e both r e g u l a r
homeomorphism
which is the identity outside N Im!
'
A s i m i l a r a r g u m e n t w o r k s for C o r o l l a r y 10.2.2.
For
( 9 M X I), m e e t i n g t h e b o u n d a r y
S o , b y t h e l a n i q u e n e s s of r e g u l a r n e i g h b o r h o o d s , N \ ^ F r ( N ) .
M X I —> c l ( M X I - N )
To c o m p l e t e
c(N3 X I) i s a l s o a r e g u l a r n e i g h b o r h o o d of
r e g u l a r at the b o u n d a r y .
n e i g h b o r h o o d s of
Then
If
Q.
(Q, 9Q) i s k - c o n n e c t e d ,
a n e l e m e n t of ^ ^ ( Q , 9Q)
i s r e p r e s e n t a b l e b y a u n i q u e q i+sko-t2o p y c l a s s of p r o p e r l y e m b e d d e d provided that r < min(q-3,
r-balls,
-2013.
U n k n o t t i n g in a Manifold w i t h o u t Boundary-
T h e o r e m 10. 3.
S a y M™ i s c o m p a c t ,
£, g: M—5> Q b e P . L . e m b e d d i n g s , (2m-q)-connected.
Then
dM /
,
f — g, q - m > 3.
= 0. Suppose
Let (M, 9M)
is
f and g a r e a m b i e n t i s o t o p i c .
U n f o r t u n a t e l y , we c a n n o t p r o v e t h i s t h e o r e m b a s e d only on p r e c e d i n g r e s u l t s b e e a u s e we did not p r o v e a c o n c o r d a n c e i m p l i e s i s o t o p y t h e o r e m for c o n c o r d a n c e s of a b o u n d e d m a n i f o l d in a n o n - b o u n d e d m a n i f o l d . Modulo t h i s gap, the p r o o f of 10.3 p r o c e e d s a s follows: Let
F : M X I — 5 > Q X I b e a ( l e v e l - p r e s e r v i n g ) h o m o t o p y of
As in t h e proof of 10. 2, we m a y a s s u m e t h a t F p o s i t i o n and S ^ F C M X Int I,
| Q | = Q X I be t r i a n g u l a t i o n s s u c h t h a t
Let
K'
b e a f i r s t d e r i v e d of
Fo" ^ FT .
Let
K^ Q K be t h e 2 m - q
t h e " d u a l s k e l e t o n " of t h e s i m p l i c e s of
K such that
K'
|K
= MX I
F : K —> Q i s s i m p l i c i a l . d i m cr > 1 and Fcr = FT
skeleton.
Let
L be i.e.
net m e e t i n g K^ , t o g e t h e r with (M X O) uy (M X 1) Then F '
( s e e p r o o f of e m b e d d i n g t h e o r e m 8 . 3
i. e . , l e t
C be a polyhedron containing
with
M X Int I.
C
Let
K^^ in K, t o g e t h e r w i t h the top and b o t t o m ;
w h i c h w e a s s u m e to be a s u b c o m p l e x . U say,
tog.
is a P . L . m a p in g e n e r a l
(dim S^F = 2 m - q + l ) .
and
f
Let
e m b e d s a neighborhood of ).
Engulf
K^ to
L
8M X I-
K^ w h i c h c o l l a p s e s to C ' (9MX I)
N be a d e r i v e d n e i g h b o r h o o d of C in dM X I
T h e n t h e n t h e r e e x i s t s a h o m e o m o r p h i s m , fixed in M X 91, M X I ^ cl('vIKI-N) a c o m p a c t s e t not m e e t i n g
K^ .
Hence
cl(MX I
- N) is contained in &
-202r e g u l a r n e i g h b o r h o o d of T h e o r e m 7. 9),
N.
L not m e e t i n g
K^
( s e e proof of
On the o t h e r h a n d , U c o n t a i n s a r e g u l a r n e i g h AW
borhood
N of
L.
p o i n t w i s e fixed. get a c o n c o r d a n c e cordance topic.
So N S N , v i a a h o m e o m o r p h i s m w h i c h l e a v e s H e n c e by c o m p o s i t i n g F'
between
f and
F g.
with h o m e o m o r p h i s m s ,
L we
Now a p p l y t h e u n p r o v e d c o n -
= > i s o t o p y t h e o r e m to d e d u c e t h a t
f and g a r e a m b i e n t i s o -
-203C h a p t e r XI:
1.
O b s t r u c t i o n s to E m b e d d i n g and I s o t o p y
Linking N u m b e r s .
If S^, S*^ a r e d i s j o i n t s p h e r e s in t h e s p h e r e n u m b e r of the m a p
S^ and S*^ in
S^
S>
i s defined to be e q u a l to the d e g r e e of - S*^,
by A l e x a n d e r d u a l i t y .
t h e linking
this l a t t e r being a homology p - s p h e r e
We s h a l l o n l y u s e t h e l i n k i n g n u m b e r r e d u c e d
m o d u l o 2 in t h i s c h a p t e r , and so w i l l not h a v e to w o r r y about s i g n s and o rientations. L e m m a 11.1 •
Let
M,N,W
be c o m p a c t c o n n e c t e d P . L. m a n i f o l d s
with
d i m W = d i m M + d i m N. S u p p o s e t h a t aW = U , r r ^ 1 J = , aN = U S . ^ " a n d s u p p o s e f: M — > W , g: N —> W a r e 1 J 1 1 + 1 p r o p e r P . L . m a p s in g e n e r a l p o s i t i o n w i t h fS. C S. , J J gS.^ ^ for e a c h j . S u p p o s e fM r. gN = ^ , and l e t L. = linking J J J
n u m b e r of
fS."""^,
gS.""'^
in
a w ) = 0, t h e n Proof.
( m o d 2).
If
aW) =
""
C o n s i d e r t h e following c o m m u t a t i v e d i a g r a m s , a l l h o m o l o g y and
cohomology having
V H
-f^
coefficients.
rs
m-V j
JM)
^^
'
-> V H
^
^^
- gs.^-^)
m-1^ J
>
j
- gN)
-204gN)<
^
,
" ^^^^^
^
9w
H
.
a
(3W,g8N) <
H'^^gaN)
T h e l e f t - h a n d i s o m o r p h i s m b e i n g g i v e n b y L e f s h e t z d u a l i t y and the r i g h t - h a n d o n e s f r o m t h e e x a c t c o h o m o l o g y s e q u e n c e s of and ^
9N C 9W.
Now t h e r i g h t - h a n d v e r t i c a l a r r o w m a p s the g e n e r a t o r of
(gS^
onto the g e n e r a t o r of
t h e g e n e r a t o r of
- gS^
- gN) for e a c h j . H
9W C N L'9W C W
2
L. =
H'^(gN, g9N)
for e a c h j .
) m a p s onto the g e n e r a t o r of
So in t h e f i r s t d i a g r a m , if l : I.
=
So
2
generates
gj = 0
.ince
2:
IS i
a boundary. Intersections.
Let
M"^, N^,
be P . L . m a n i f o l d s .
g : N — > W be p r o p e r P . L . m a p s in g e n e r a l p o s i t i o n .
L e t f: M
W,
If x € fM n gN ,
we c a n define an i n t e r s e c t i o n n u m b e r J?(X) a s e q u a l to the linking n u m b e r s ( m o d 2) of
link(x,fM)
L e m m a 11.2.
If
and link(x, gN)
in link(x, Q).
.
M S N S S^ , W S S ^ ^ a n d fM o gN = {x
x
,x },
i(xj = 0 .
then
L e m m a 11.3. then ^
I f M S N S B
X(x^) = l i n k i n g n u m b e r of
Proof.
.2n f9M, g9N in
and fM ^ g N = {x^ . . . x^^} , 9W.
T r i a n g u l a t e and r e m o v e t h e s t a r s of the p o i n t s
x., x ^
A p p l y i n g L e m m a 11.1 now g i v e s t h e r e q u i r e d r e s u l t .
c
. . . ,x . K
-2052,
An O b s t r u c t i o n to E m b e d d i n g a n d I s o t o p y .
Let
f: M"^ —> Q'^ be a p r o p e r P . L. m a p in p r o p e r g e n e r a l p o s i t i o n ;
i . e . , £ | 9 M : 9 M — > 8Q i s a l s o in g e n e r a l p o s i t i o n . pact, and
m < q-1.
f: K—5> L
is simplicial, and
Let K-K
K' a n d L ' and
o
T r i a n g u l a t e M a n d Q, g e t t i n g
Assume K and L
M is c o m such that
K C K a full s u b c o m p l e x t r i a n g u l a t i n g S f. o ^ b e f o r m e d by s t a r r i n g at t h e b a r y c e n t e r s t h e s i m p l i c e s of
L-fK
o
, in o r d e r of d e c r e a s i n g d i m e n s i o n .
Then
f : K ' —> L '
is still s i m p l i c i a l . If
0" € K^
0-'^ cr, w i t h Let
i s a ( 2 m - q ) - s i m p l e x , t h e n t h e r e e x i s t s a u n i q u e cr' e K^,
fcr = fcr', a s t h e t r i p l e p o i n t s h a v e d i m e n s i o n
link(cr;K'), S^ = l i n k ( c r K ' ) ,
3m-2q < 2m-q.
2 = link(f(r,-L'),
dim S
= m - ( 2 m - q ) - 1 = £ - m - i = d i m S . D i m S = 2 ( q - m ) - 1. Now, -I d i m cr = 2 m - q = d i m cr', f e m b e d s S a n d S . M o r e o v e r , S S = 1 Z 1 Z F o r if
T 6 S^ ^^ S^ , o-T a n d
link(T,'K') n
cr'r
e K'
= a single simplex
implies p.
cr,cr' e l i n k { T ; K ' ) .
Since
f embeds
But
p, t h i s m e a n s
cr = cr', a c o n t r a d i c t i o n . Now, define i.e. ,
fS^
and
fS^
i n 2 , m o d 2;
j2(^(cr) € Z^ .
Definition .
dim
^^(cr) = l i n k i n g n u m b e r of
K
o
c(f)
=
^ ^ ^.(cr)-cr€ C (reK ^ o dimcr = 2 m - q
< 2 m - q , c(f) = 0 .
since
(M)(g) Z
. ^
If
-206Now, Let
c(f)
i s d e f i n e d w i t h r e s p e c t to t r i a n g u l a t i o n s of
3f = f I 3M a n d l e t
c(9f)
M a n d Q.
b e d e f i n e d w i t h r e s p e c t to t h e i n d u c e d
triangulation. L e m m a 11. 4 . Proof.
ac(f) = c{af).
Suppose
that t h e r e exist
T e K^
and
T' ^ T a n d
dim T = 2 m - q - l .
fx' = fx.
Let
S
Assume
= link(t;K'), S X
Let g = f S ^ o for o t h e r w i s e
n o t in
T.
S^.
Then
g(S^) r \ g(S^)
dimS^f > 2 m - q .
a r e in S^f. T h e n if tr'
Moreover,
of
gS^
and
Now s a y
in S and S', r e s p e c t i v e l y , if
T < cr e S^f, l e t fcr : fcr',
f have d i m e n s i o n at m o s t
such that
y
such that
x b e v e r t e x of cr T < cr' b e c a u s e , a s 2m-q-2.
Thus
T < o" c o r r e s p o n d to i n t e r s e c t i o n p o i n t s
gS^. x € X^ a n d and
XT e S^f.
f ( l i n k ( x ' T ' ; K'))
unique point such that
Therefore
Let
and
Then
and
l i n k i n g n u m b e r of x ' e S^
B u t link(Tx; K') = l i n k ( x ; S ^ )
link(f(xT)j L ' ) = l i n k ( f x ; 2 ) ,
as
is the
and f
is
^ (XT) = ^ ( x ) . s
b e t h e v e r t i c e s of g(S^)
jl^^(XT)
in link(f(xT; L ' ) , w h e r e
f(x') = f(x).
link(T'x';K') = linklx'jS^)
p o i n t s of
c o n s i s t s e n t i r e l y of v e r t i c e s ,
e a c h p o i n t of i n t e r s e c t i o n
is a simplex such that
cr e S^f
f(link(xT;K'))
simplicial.
x and x'
Conversely,
m < q - 1 , t h e t r i p l e p o i n t s of the s i m p l i c e s
S^, S^^, a n d S
o S^ = ^ , a s a b o v e .
d e t e r m i n e s a p a i r of v e r t i c e s XT a n d X'T'
= link(T'; K ' ) , L^
2 = link(fT; L ' ) , d i m S^ = d i m S^ = q - m , d i m 2 = 2 ( q - m ) . a r e s p h e r e s , and
T / 8M, a n d
gCS^).
Then
cr €^
S^
m a p p e d by
' J^fC^") = 0- > T i= 1
g to i n t e r s e c t i o n (x.) = s u m of t h e ® ^
-207linking n u m b e r s
( m o d 2) of link{y^; gS^)
y^ = f(x.).
g is in g e n e r a l p o s i t i o n ( i t s double p o i n t s a r e of d i m e n -
Since
and link(y^; gS^)
in
link(y^;S),
sion z e r o a n d it h a s no t r i p l e p o i n t s ) , L e m m a 1 1 . 3 i m p l i e s t h a t t h i s s u m is c o n g r u e n t to z e r o m o d u l o 2. N o w , for fx = fx'
but
T / T'.
such that face
t'
T € K , dim T = 2 m - q - l , o Then suppose
fcr - fcr'
such that
fx = f r ' .
a r e s i m p l i c e s of S^f f(c^i) = i < p-1.
but cr / a ' .
for So
s u p p o s e t h e r e i s no T'
T < cr and cr e S f. Since
Therefore
f embeds t=t'.
having
T a s a face,
1(2).
By definition,
with
Then there exists
cr and cr', cr' ha s a
T h e r e f o r e if
""^'•••'""p
p is e v e n and we m a y s u p p o s e = ^^^^^ ,
i - 1(2),
= 0 ( m o d 2) in t h i s c a s e a l s o , cr > T
cr e S^f Now s u p p o s e X ^x', Let S2(f)
and
T E K^ a n d T € 9M and t h e r e e x i s t s
x € aM.
B = link(fx;L'), 9M,
Let
B^ = l i n k ( x ; K ' ) ,
a 2(q-m)-ball.
shows that
Lemma
^ ^^(cr) = l i n k i n g n u m b e r of cr > X (T 6 S^f Now
9c(f) = ^ X
s i m p l e x e s of
But
fx = fx',
(q-m)-balls.
x is a p r i n c i p a l s i m p l e x of
9B^ a n d BB^ a r e e m b e d d e d d i s j o i n t l y in
(all m o d u l o 2).
such that
B^ = l i n k ( x ' ; K ' ) ,
Since
s i m i l a r to t h a t for t h e f i r s t c a s e , u s i n g
T'
11.3
aB^ and
9B,
An a r g u m e n t
i n s t e a d of L e m m a 11.2 9B^ i n
9B = ^g^(x)
( ^ ^^((r)).x w h e r e we s u m o n l y o v e r a >X
^ ^^^(cr) = 0 if x / S^(9f) 0- > X = ^g^(x) if X € S2(9f) .
-208So
9c(f) = c(9f).
So c{£)
r e p r e s e n t s an e l e m e n t Q;(f) e H
(M, d M j Z ) m ~^ q^^' (L
if
9f is an e m b e d d i n g , L e m m a 11.5.
c(f)
a{i)
g i v e s an e l e m e n t
and
a(f)
a(f) e H ^ ^
do not d e p e n d on t h e c h o i c e of t r i -
angulation. Proof. K I = S (f) o ^ a
Suppose
f: K — > L
and K ' , L '
a r e obtained from
( 2 m - q ) - s i m p l e x of fS^f .
K, L and f:
is s i m p l i c i a l , K^ i s full in K w i t h
a K — > (3L
Now s u p p o s e
K, L a s a b o v e .
aK: pL a r e s u b d i v i s i o n s of
i s s t i l l s i m p l i c i a l , and l e t
by s t a r r i n g s i m p l e x e s not in
.
link((r^, fa'K)
> link((r^, fK').
or'K, p ' L
be o b t a i n e d
Then pseudo-radial projection
a s s u r e s us that t h e r e is a P. L. h o m e o m o r p h i s m sending
L e t cr be
link(cr^, (3'L)
So
= ^
.
> link(cr, L ' )
Thus each
p r i n c i p a l s i m p l e x o c c u r s w i t h t h e c o r r e c t coefficient and g i v e s r i s e to t h e same homology c l a s s . L e m m a 11.6.
If
f,
—> Q*^,
m
a r e p r o p e r P . L.
in p r o p e r g e n e r a l p o s i t i o n , and if f = g a s m a p s then
a(f) = »(g).
If f | 9M i s a n e m b e d d i n g and
maps
(M, 9M) —> (Q, 9Q), f = g ( r e l 9M), t h e n
«(f) = a ( g ) . Proof. between
Let
f and g.
F: M X I
> Q X I be a l e v e l p r e s e r v i n g h o m o t o p y
F | M X 91 i s in g e n e r a l p o s i t i o n .
Therefore,
let
G: M X I —5> Q X I be a P . L . m a p i n p r o p e r g e n e r a l p o s i t i o n w h i c h a g r e e s with F
on M X 91.
T r i a n g u l a t e so t h a t G is s i m p l i c i a l .
So
M X 0, M X 1, and
9M X I a r e s u b c o m p l e x e s and
9 c ( F ) = c ( a F ) = c [ F | M X O] + c [ F ] M X 1] + c ( F | 9M X I).
Let
p^,: C(MXI) X Z^
where
5> C(M) X Z^
be the m a p i n d u c e d by p r o j e c t i o n ,
C = s i m p l i c i a l c h a i n s w i t h r e s p e c t to t h i s t r i a n g u l a t i o n .
ap,^c(F) = c(£) + c(g) + p J c ( F I aM X I)).
In t h e e v e n t t h a t has this property. Note:
F | 9M X I
Then
(f|9M)Xl,
c ( G | a M X I) = 0, so
Now s u p p o s e t h a t
Let
F:MXI
f and g in g e n e r a l p o s i t i o n . ^(F) e
as a map
M in E ^ .
If F '
Then t h e r e is always a
j e c t i o n onto t h e f i r s t c o o r d i n a t e .
T h e n define
Let
f and g.
L e m m a 11.7.
If f a n d g a r e c o n c o r d a n t ,
Proof.
b e a h o m o t o p y of f and g a n d
F S G (rel
F
9(M X I) = M K9I).
L e m m a 11.8.
p: M X I —> M be p r o -
=
d(f, g) t h e " d i f f e r e n c e c l a s s " b e t w e e n
Let
so
i s a n o t h e r h o m o t o p y of f and g,
a(F) = a(F').
d(f.g)
Then let
T h e n F | 9 ( M X I) i s an e m b e d d i n g , ^^ defined.
(rel
Q = E^.
> E ^ X I be a P . L . h o m o t o p y of
9 { M X I ) ) , so
We c a l l
also
ap^_^c{G) = c(f) + c(g).
9M = ^ and
be two e m b e d d i n g s of
h o m o t o p y of f a n d g.
F ^ F '
G
3Q)]
Definition . £, g: M —> E ^
Therefor
one m a y suppose
In v i e w of t h i s l e m m a , w e m a y v i e w a
TT[(M, 3 M ) , ( Q ,
then
is
T h e l a s t i s in C(9M).
Then
Therefore
d(f,g) = 0. G a concordance.
a{F) = a{C) = 0.
If h: M —> e ' ^ i s an e m b e d d i n g , d(f,g) + d ( g , h )
= d{f,h).
then
Then
-210-
Proof .
Let
F , f S g.
Let
G: g S h.
Define
by
0 < t < -
F ( x , 2t) H(x,t)
H: f S h
= G(x;2t-1)
.
T h e n it i s not h a r d to s e e t h a t a(H) = a(F) + a(C}. Remark. and
Say f: M™ —> Q*^ i s a p r o p e r P . L . m a p in p r o p e r g e n e r a l p o s i t i o n ,
2 m - q = 0.
Then
a(f) 6 H (M;Z ). o ^ ^
'
a(£) is defined,
s i n c e 2 ( m - l ) - ( q - l ) = - 1 , and
H o w e v e r , it i s c l e a r f r o m t h e definition t h a t
= 0 ( m o d 2),
M is t r i a n g u l a t e d with f simplicial.
T h e r e f o r e we
may view a(f) e H (MrZ_). S i m i l a r l y , if f , g : M —> E ^ a r e e m b e d d i n g s o ^ dM = 0 and 2 m - q + l = 0, d(f, g) e H (M; Z ). Note that t h i s is c o n s i s t e n t 2m with the fact t h a t M c o n n e c t e d i m p l ioe s t h a t^ M c a n be e m b e d d e d in E
and any two embeddings of 3.
QJ-Q isotopic.
O b s t r u c t i o n to I s o t o p y of E m b e d d i n g s of a Manifold in E u c l i d e a n S p a c e .
Suppose if
M in
f^: m"^
> E^
i s an e m b e d d i n g ,
g: M—5> E*^ i s an e m b e d d i n g ,
d(f^, g) e H ^ ^
upon the i s o t o p y c l a s s of
g.
are isotopic,
Then
g
m"^
into
d(g,f) = 0 .
c l a s s e s of e m b e d d i n g s of T h e o r e m 11.9. Let
Let
f ^ : M — b e
M c o m p a c t , dM = 0,
For
d(f^,f) =
^2^
Then
depends only
g) + d(g,f), a n d if g and f
> d(f^, g) defines a m a p of i s o t o p y E^
into
q+1^^'
m"^ b e a k - c o n n e c t e d c l o s e d m a n i f o l d , a P . L. embedding.
m a p of i s o t o p y c l a s s e s of e m b e d d i n g s onto
k<m-4.
T h e n g —> d(f^, g) defines a Z^).
-211-
We f i r s t p r o v e t h i s t h e o r e m in a s p e c i a l c a s e .
Then we use this
s p e c i a l c a s e to p r o v e t h e g e n e r a l r e s u l t , i Let j and k
k
S"^ and B
d e n o t e a P . L . s p h e r e and a P . L. b a l l of d i m e n s i o n
respectively.
0 s 2s+l L e m m a 11.10. L e t f: S X B 5> B be a p r o p e r P . L . with s > 3. T h e n t h e r e e x i s t s a l e v e l p r e s e r v i n g P . L . m a p 0 s 2s+l F : S X B X 1 ——> B in g e n e r a l p o s i t i o n s u c h t h a t
(1)
embedding
=f
(2) F ^ (3) F
t
is a P. L.
embedding
S° X aB® = F
X aB® , for a l l t e I
and (4)
a{F) e Hg(S° X B®; Z^) 0
Proof .
Write
S XB
is n o n - z e r o
s = B^ U B^ .
By g e n e r a l p o s i t i o n , a n y m a p
2s+l g:B^ 5> B — fB^ w i t h g dB^ = f BB^ is h o m o t o p i c to a P . L , e m b e d d i n g k e e p i n g t h e b o u n d a r y fixed. H o m o t o p y c l a s s e s of s u c h m a p s 2 s+1 a r e d e t e r m i n e d by e l e m e n t s of ir (B - fB ) = Z. C h o o s e g so t h a t s ^ 2s+l gB^ w fB^
d e t e r m i n e a g e n e r a t o r of
B^) X 1 (a) F ^ = f (B)
(c)
FJb^
TT^^{B
- fB^).
-> B^®"^^ X 1 b y
= g , FjB^ =f aB^) =
aB^ , for a l l t e I.
Define
-212Now e x t e n d c o n i c a i l y on e a c h b a l l .
Then
a ( F ) = l i n k i n g n u m b e r of F
X 1) and F 9 ( 3 2 X I) in
X I)
r e d u c e d m o d 2, w h i c h i s one by c o n s t r u c t i o n . Let
M be a r e g u l a r n e i g h b o r h o o d of a n r - s p h e r e , d i m M = r + s .
f: M —$> B
r+2s+l
be a P . L, e m b e d d i n g w i t h
p r e s e r v i n g P. L. m a p
(1) (2) F ^
F:MXI
r+2s+l
T h e n t h e r e is a l e v e l
X I such that
= £ is a n e m b e d d i n g
(3) F ^ | 9 M = f | 9 M
for a l l
(4) ^ ( F ) ^ 0 in HJM; Proof.
>B
s ^ 3.
Let
Z^)
tel = Z^.
T h e proof is by i n d u c t i o n on
r, keeping
s fixed.
When
r = 0
this is simply L e m m a 11.10. The inductive step ;
Let K C L
triangulate
L e t N b e t h e d e r i v e d n e i g h b o r h o o d of K in L .
S^ C M w i t h Then
M = N.
K full in L .
-213-
L e t cr b e an r - s i m p l e x of K.
Let
cr
be t h e d u a l c e l l of cr in
K'.
Notice that (1) cr (2) SN
i s an s - b a l l p r o p e r l y e m b e d d e d in
N;
N r\ star(o-, K) i s a r e g u l a r n e i g h b o r h o o d of cr
in N
meeting
regularly; (3) N n s t a r (cr, K) n N - star(cr, K) i s a d e r i v e d n e i g h b o r h o o d of cr in
•
Jt*"" i
a . link(cr, K), and so is
P . L . h o m e o m o r p h i c to S
(1) a n d (3) a r e c l e a r e n o u g h . of IT
To s h o w (2):
in o r d e r of d e c r e a s i n g d i m e n s i o n .
Let Then
s XB
.
T^. . . T^ be t h e s i m p l e x e s N n a-^^link(cr, K ) ^
N rs aTjink{cr^K) by an e l e m e n t a r y p o l y h e d r a l c o l l a p s e . S i m i l a r l y , N n rT.link(cr, Let
h: N
N n O-T Jink(cr, K) b y a n e l e m e n t a r y ( s i m p l i c i a l ) c o l l a p s e . >M
be a P . L . h o m e o m o r p h i s m .
fD o aB = f9D. Now (B is an s+1 b a l l E in B. r + 2 s + l w i. t h,
, fD) i s a n u n k n o t t e d b a l l p a i r , so t h e r e 9E = fD u (E n, BB „ „ r + 2 s + l .).
By g e n e r a l position we m a y a s s u m e that ( r + 2 s + l ) = 0.
So f ^ E = D u X .
n e c t e d , so t h e r e is a p o l y h e d r o n
L e t D =hcr .
d i m ( E r i f ( M ) ) ^ ( r + s ) + (s+1) -
X = a finite n u m b e r of p o i n t s . D'
M is con-
w i t h D i-' X C D' \ D , d i m ( D ' - D ) < 1.
-214-
We c a n a s s u m e
D ' - D C Int M.
EofD'CE'\E,
Now c h o o s e
E ' n fM = fD'.
a s s u b c o m p l e x e s and f s i m p l i c i a l . D'
T h e n put W
1
sl
in B
d i m ( E ' - E ) < 2, E ' - E C Int
p o s i t i o n we m a y a s s u m e
hood of
E'
By general
Now t r i a n g u l a t e w i t h
Let
8M , U^ = N^ ^ 9B
= c l [ a M - U j , and
1
W
z
=
,
Int U
.r+2s+l cl[B -N
(r+2s)-balls, N
] are
z
E'
in B^
= ^ ^ M ^ I ' "^2 "" ^ ^ ^ 2 ' Then
r+2s+l balls.
LD
n e i g h b o r h o o d of D in
D',E'
N^ = 2nd d e r i v e d n e i g h b o r -
in M and N^ = 2nd d e r i v e d n e i g h b o r h o o d of
U^ = N ^ n
with
2
are
2'
N
being a r e g u l a r
X
M is an ( r + s ) - b a l l and, f r o m t h e a b o v e r e m a r k s on
(T* e t c . , V^ ^ S^"^ X B®.
N^ a n d
cl(M-N)
are
(r+s)-balls.
By i n d u c t i o n , t h e r e is a l e v e l p r e s e r v i n g P . L . m a p E ' r V ^ X I — > with 1) F ' = f V , X I , o 1 2) F^ = a P . L. e m b e d d i n g , 3) F^' I 4)
X I = f I av^ X I ,
a{F') i 0 in
Define
F:MXI
for a i l t € I ,
X I; Z^) = Z^ . 5> B
F^ 9M = f 9M
XI
for a l l
a s follows:
t € I ,
F , V, X I = F ' . 1 1 1 Extend
F,
1
over N, X 1 1
M - N^ X 1
P . L.
2'
5> N^ X 1 2 ->
- N^] X 1
put
^
-215-
by c o n i c a l e x t e n s i o n .
Then
S (F) S s u s p e n s i o n of S ( F ' ) . Moreover, Z ^ t h e l i n k i n g n u m b e r s c o r r e s p o n d and a ( F ) = s u s p e n s i o n of aCF') / 0 in P r o o f of T h e o r e m 11.9. k^m-4, Let
M is a c o m p a c t k - c o n n e c t e d c l o s e d manifold.
f ^ : M — i s
T| e "TT,
a P. L, embedding.
be an e l e m e n t r e p r e s e n t i n g
iCTA
a P . L. embedding r e p r e s e n t i n g Now f iS o
Z^) .
Let
^ .
Z^).
Let
k+1 i: S —5> M
be
[i [which e x i s t s b y e m b e d d i n g T h e o r e m 8.1].
i s u n k n o t t e d in E
, so b o u n d s a k+2
By g e n e r a l p o s i t i o n a s s u m e (k+2)+m - ( 2 m - k ) = 2 k - m + 2 < k - 2 .
ErNf^(M)
has
disc, D
s a y , in
dimension <
By t h e f a m i l i a r a r g u m e n t u s e d for
e x a m p l e in p r o v i n g t h e e m b e d d i n g t h e o r e m s , w e define i n d u c t i v e l y s e t s C. C M, D. C i ' l
X. C M w i t h 1
d i m X. < d i m X. ^ .
C
E v e n t u a l l y , for
Now t r i a n g u l a t e with
f
D
simplicial, C
a 2nd d e r i v e d n e i g h b o r h o o d of C
= f,
XI F(N^
outside
embedding,
f^
X I) C
e l e m e n t of
H, , ( N , X I? Z^). k+1 1 Z
J:N^
X I
5> M X
1 s e n t e d by the s a m e c h a i n .
I
X^^ i s e m p t y . as subcomplexes,
N^,
F
N ^ X I,
and
K
D^^ in E^™
in M.
Now l e t
L e t N^ " ^o F.MXI—
i s in g e n e r a l p o s i t i o n , F ^
and
X I)
is the
is an
non-zero
(in t h e n o t a t i o n of L e m m a 1 1 . 1 , r = k+1,
s = m - ( k + l ) ^ 3, r + 2 s + l = 2 m - l . ) where
0, f "^D. = C . u X. , i ^ o i i i
and D K
l e t N^ = 2nd d e r i v e d n e i g h b o r h o o d of
F = f
X
i = R say,
O
be s u c h t h a t
.
But c l e a r l y , a{F) = J ^ j ^ F | N^ X I),
is inclusion;
But j^,,:
in fact,
both elements
X I; Z^) —5>
are
repre-
maps
-216-
the n o n - z e r o e l e m e n t onto a n e w ennbedding h a v i n g
4.
So
=
T h u s we h a v e found
the r e q u i r e d "difference c l a s s " from
f^ .
Other Results.
In t h i s s e c t i o n w e o u t l i n e s o m e m o r e r e s u l t s t h a t c a n be p r o v e n a b o u t o b s t r u c t i o n to i s o t o p y of e m b e d d i n g s . I)
Suppose
M^
is a k - c o n n e c t e d c o m p a c t closed P. L. manifold,
k < m - 4 , and s u p p o s e
m-k
is even.
Suppose
f^; M"^—5> E ^ " ^ ^ is an
embedding.
T h e n t h e c o r r e s p o n d e n c e b e t w e e n i s o t o p y c l a s s e s of
b e d d i n g s of
M in E ^ ^ ^
and
^2)
em-
^^ s e c t i o n 3 i s a l s o
one-to-one. II) C o n s i d e r m a p s of a n o r i e n t a b l e c l o s e d m a n i f o l d Q*^.
M"^ in a m a n i f o l d
T h e n o n e c a n d e v e l o p a n o b s t r u c t i o n t h e o r y a n a l o g o u s to t h e a b o v e ,
but with coefficients
in
Z, p r o v i d e d
q-m
i s odd.
T h e n if
M is o r i e n t a b l e ,
Zm - k k - c o n n e c t e d and c l o s e d and
f^J M — > E
a m a p f r o m i s o t o p y c l a s s e s of e m b e d d i n g s of For
i s an e m b e d d i n g , o n e g e t s M in E ^ " ^ ^ to
Z).
k < m - 4 , t h i s m a p i s o n e - t o - o n e and o n t o . III)
Suppose
c y l i n d e r of
f =
f: M — > Q i s in g e n e r a l p o s i t i o n .
X I) U Q {(x,0)~f(x)}
^
If
ftr = fcr', o"' / cr, a n d l e t
f(link(o-;M)) a n d
f(link(
C(f) = 2
I] ^ 0"
^
(C^ = m a p p i n g
cr i s a ( 2 m - q ) - s i m p l e x of S f,
0"' b e s u c h t h a t
in
Let
link(f(r,-Q). '
let
= lixiking n u m b e r ( m o d 2) of Then let denotes the chain one
-217-
o b t a i n s f r o m t h e u s u a l t r i a n g u l a t i o n of p r i s m a t i c homology theory). represents
A(f) e
Suppose inclusions
Then
or X I ( o r d e n o t e s a c h a i n in
aC(f) = C(f) € C J M X O).
t ' ^ ' '
^^^^^ "
F : M X I —> Q X I is a h o m o t o p y of
(C^; M)
>(C^sMXl)
homotopy equivalences.
So F
and
(C^; M)
M, z p .
d e p e n d s on the h o m o t o p y c l a s s of f.
If
aM = 9Q =
theory over
->(Cp;MXI)
are
F,,A(£) = A(g).
So A(£)
i< 3m-2q+2,
M) = 0 for
and q - m is even, then
i < 2m-q ,
A(f) = 0
implies
If q - m i s o d d , t h e n t h e r e i s a n a n a l o g o u s ,
Z, and the analogous result is t r u e .
If F
i s a h o m o t o p y of f and g, fixed on t h e b o u n d a r y , s a y , we c a n
A(F)
to m e a s u r e the o b s t r u c t i o n to g e t t i n g a n i s o t o p y .
however, of
T h e n the
In p a r t i c u l a r , if f i s h o m o t o p i c to an
, q - m ^ 3, 2 m - q > 1 ,
is homotopic to an e m b e d d i n g .
use
f and g.
A(f) = 0.
•Tr^(M) = 0 f o r f
'
induces an i s o m o r p h i s m
M; Z^)
embedding,
So C(f)
F.
A(F)
d e p e n d s not o n l y upon
In g e n e r a l ,
f and g but a l s o upon t h e c h o i c e
-218-
Chapter XII: Embedding Up to Homotopy Type
1.
Introduction.
T h e o r e m (Browder, Sullivan, Cassen): topy equivalence (M c o m p a c t ) , i s an i s o m o r p h i s m , t h e n
If f: M"^ —> Q'^ i s a h o m o -
q - m > 3, 3M =
a n d if i^:-ir^(9Q) —> Tr^(Q)
f i s h o m o t o p i c to an e m b e d d i n g ,
k Corollary . Let P . L. m a n i f o l d , q - k > 3,
K
iTi b e a finite s i m p l i c i a l c o m p l e x ,
M
Q*^ a P . L. m a n i f o l d w i t h o u t b o u n d a r y .
a closed
Suppose
q - m > 3,
—> K i s a h o m o t o p y e q u i v a l e n c e , a n d t h e following
diagram
(of c o n t i n u o u s m a p s ) i s h o m o t o p y c o m m u t a t i v e : -> Q Mm a K
Then
f is h o m o t o p i c to a n e m b e d d i n g . Proof .
position,
Let
T r . ( N ; N - K ) = 0 for
implies that retract.
N b e a r e g u l a r n e i g h b o r h o o d of i < 2.
ir (9N)
is a homotopy equivalence, as
> ir (N) N\K.
Q.
By g e n e r a l
The g e n e r a l i z e d annulus t h e o r e m
N - K S SN X [ 0 , o o ] , a n d s o
Therefore
K in
N-K
has
9N a s a d e f o r m a t i o n
is an i s o m o r p h i s m .
J^: M —> N
H e n c e t h e t h e o r e m a p p l i e s to
In t h i s c h a p t e r w e a r e going to find a c o n d i t i o n o n
f: M —5> Q
which
i m p l i e s t h e e x i s t e n c e of a h o m o t o p y c o m m u t a t i v e d i a g r a m a s in t h e corollary.
-219-
Definition . Let
Let
f: X —> Y be a c o n t i n u o u s m a p of t o p o l o g i c a l s p a c e s . (X X I) ^ Y f = —^^ {(x,0)~f(x)}
C = m a p p i n g c y l i n d e r of ^
identifying
xeX
w i t h (x, 1).
T h e n define
k T h e o r e m IZ. 1; complex,
8Q =
Let
f; K
k
.
Identify
X C C
by
TT Jf) = ir^lC^; X),
q —> Q
be c o n t i n u o u s ,
Suppose
Tr.(f) = 0 for
i < 2 k - q + l.
t h e r e is a h o m o t o p y c o m m u t a t i v e d i a g r a m in w h i c h c o m p l e x , ^ a ( s i m p l e ) h o m o t o p y e q u i v a l e n c e , and K — i
K a finite
K'
is a finite
simplicial Then simplicial
d i m K' < k ;
>Q
K'
2.
L e m m a o n H o m o t o p y G r o u p s of a T r i a d . k
L e m m a 12. 3. M
a manifold,
Let
9M =
•Tr.(M; M - K ; U) = 0
for
K C U C M T h e n if
Proof. f:(B,F^;F^)
Note that Let
, K a simplicial complex, U open,
TT.CM-K; U - K ) = 0
for
i < r,
then
i
(Compare Blakers & Massey, 55, (1953).
M.
H o m o t o p y G r o u p s of a T r i a d , A n n a l s of M a t h ,
Tr^(U; U-K) = 0 for
i < m - k - l , by g e n e r a l p o s i t i o n . )
o t e Tr.(M; M - K ; U), i < r + m - k - l . > (M, M - K , U)
represent^
a r e ( i - l ) - b a l l s , F ^ o F ^ = SB, F F ^
, where =
Let B = i - b a l l , F ^ and F ^
= dFSince
M-K
and
a r e o p e n , we m a y a s s u m e , a f t e r a s m a l l h o m o t o p y if n e c e s s a r y , t h a t P . L. n o n - d e g e n e r a t e a n d
f(B)
is in g e n e r a l p o s i t i o n with r e s p e c t to
U f
K.
is
-220-
Let
X = f"^(K).
Then
=
and
dim X < i+k-m.
For
engulfing in a b a l l , c o d i m e n s i o n h y p o t h e s e s a r e n o t n e c e s s a r y ; a polyhedron
C C B with
X C C \ C n F ^ ,
dim C < i+k-m+1 < r.
-1
be a p o l y h e d r o n in C w i t h P^ = F r „ P . 0 ^
Pn
So fP„ C U. 0
so t h e r e i s a h o m o t o p y of
K = ^
and
P
U C Int^P.
Let
is r - c o n n e c t e d and d i m P < r,
M - K , fixed on
T h i s e x t e n d s to a h o m o t o p y of f
C - f
(M-K, U-K)
P , in
Let
-1
f
Now
so t h e r e
Pq
carrying
P
into
> M, M - K , U c a r r y i n g
f
U-K. onto
where
Let
(1)
(f)'^K = f"^K.
(2)
f(C)
CU.
R b e a s e c o n d d e r i v e d n e i g h b o r h o o d of
F^ u C^F^ .
So R i s a n i - b a l l i n
strong deformation retraction and
f'/3(B)CM-K.
So f'^
Say
> B-R.
f'(R) C- U.
So t h e r e i s a
f ^ f'^ : B, F ^ , F ^ — M , M - K , I -ir.lM; M - K ; U - K ) .
m
K C M
a manifold.
Let
i
-rr.(M, N, N - K ) = 0 if
Then
B with
B, R n 9B i s a f a c e .
r e p r e s e n t s z e r o in
k Lemma 12.4.
F ^ 'J C i n
, k<m-3,
K a finite c o m p l e x ,
N b e a r e g u l a r n e i g h b o r h o o d of
K in
M.
M
Say ^ ^ ( M ^ K ) = 0,
i
P r o o f . T h e following s e q u e n c e i s e x a c t : Tr.(M-K; N - K ) > -n-.(M, N) > '7r.(M,- M - K ; N)
->Tr.
1-1
fM-K;N-K)
\n trXM, K) '
So ( M ; M - K ; N ) (N,M-K,N)
is
i - c o n n e c t e d , i < r+1 = > (M-K, N-K) ( i - l ) + m - k - l ^ 1+1 c o n n e c t e d .
(i-l)-connected
=>
So by i n d u c t i o n , t h e r e s u l t
-221follows. N
( O b s e r v e t h a t in a p p l y i n g 1 Z . 3 we c a n r e p l a c e
N by N
because
> N is a homotopy equivalence. )
3.
P r o o f of T h e o r e m 12. 1.
Let complex.
ftX^-
-> q'^ , q > k + 3 , 9 0 = 0 ,
T h e n we w a n t to find
and a h o m o t o p y e q u i v a l e n c e f:X
Tr.(f) = 0 for
i<2k-q+l,
X' 9. Q> ^ s u b p o l y h e d r o n , X —> X'
such that
X a finite
d i m X' < d i m X,
—> Q
and
> Q are homotopic. We p r o c e e d by i n d u c t i o n .
of i n c r e a s i n g d i m e n s i o n .
Let
Let
~ s i m p l i c e s of
K,
K
K. = {A. | j < i) » a s u b c o m p l e x .
the following i n d u c t i v e s t a t e m e n t i
= X, in o r d e r T h e n we u s e
f is h o m o t o p i c to f ^ : K — > Q, w h e r e
f.(K.) C L. C Q, L. a s u b p o l y h e d r o n , d i m L . < k , and : i i 1
f. K . : K . 1 1 1
> L. i s 1
a homotopy equivalence. When i = 0, K^ = a p o i n t , a n d t h e r e is n o t h i r g to p r o v e . h a s b e e n c o n s t r u c t e d , and l e t A = of L. in Q. L e t r = d i m A. . T h e n 1
Therefore
1
•Tr^(K; K^) = 0 for
So a s s u m e
. L e t N be a r e g u l a r n e i g h b o r h o o d K. c o n t a i n s t h e ( r - 1 ) - s k e l e t o n of K. 1
j < r - 1 , by the c e l l u l a r a p p r o x i m a t i o n t h e o r e m
(cf S p a n i e r , A l g . T o p o l o g y , p. 4 0 4 ) . Let
C = m a p p i n g c y l i n d e r of f^ .
Tr^(K, K.)
> TT.iC, K.) J 1 II
f.
Then
-> ^^(C, K)
-> -rr^ ^(K, K.)
is e x a c t .
-222-
So
'Tr^(Q, L^) = 0 for
of
L.
i < min(2k-q+l, r-l).
i n Q, w e h a v e
•Tr^(Q-L., N-Li^) of N - L ^ , so
If
N, N - L ^ ) = 0 for
5> Tr^(Q, N)
is onto.
Tr^(Q-N, 9N)
N is a r e g u l a r neighborhood j < m i n [ r + q - k - 2 , k].
So
9N i s a s t r o n g d e f o r m a t i o n
>-Tr^(Q, N) i s o n t o .
Furthermore,
retract from the
e x a c t s e q u e n c e of t h e t r i a d , -ir.(Q-L.,N-L.) J ^ ^
-> Tr.(Q,N)
= 0 whenever So, in p a r t i c u l a r , w h e n e v e r j2f:A,8A
-> Q - N , 3N
j < min(2k-q+l, r - l ) j < 2r-2+l.
such that
, we m a y a s s u m e
extension property
f^ S l|;: K
so
LJJIK^ U A : K ^ U A
N\L.
say.
If
define
where or : N u ^A
^^^^ I
>Q
> N u ^A
> ^i+i
~
A =
and
j + 1 ^ m i n ( r + q - k - 2 , k).
and choose 1+1 5> Q, N . By t h e e m b e d d -
f to be a n e m b e d d i n g . where
By t h e homotop^
iJJ|A = J2^A, ip | K^ S f J K^: K ^ — > N .
is a homotopy equivalence.
J2(A H. N C T , d i m T ^ k .
° v e r t h e w h o l e of 1+1
Let
j 2 ( s f j A : A , 8A
ing t h e o r e m S . ' ^
Then
-> T r . ( Q , N , N - L . )
Now N^^L. ,
So N u J^A^L. u T U
^ corresponding deformation
=
retraction
using the homotopy extension property extend K with
f. , , ^ f. 1+1
This completes the inductive step.
-223H a n d l e - B o d y T h e o r y and t h e s - C o b o r d i s m T h e o r e m
Introduction. A cobordisnn is a manifold aw =
\J 9 W, C W and
W w i t h b o u n d a r y the d i s j o i n t union
An h - c o b o r d i s m
W s a t i s f i e s the f u r t h e r
requirements
8 W C W a r e homotopy equivalences.
T h e m e t h o d of S m a l e c o n s i s t s of r e p r e s e n t i n g a c o b o r d i s m a s the u n i o n of h a n d l e s and s l i d i n g t h e s e h a n d l e s a r o u n d to o b t a i n a p r o d u c t s t r u c t u r e on c e r t a i n h - c o b o r d i s m s of d i m e n s i o n an h - c o b o r d i s m written
> 6.
T h a t i s , for s u c h
W, t h e r e is a P . L . h o m e o m O p p h i s m of W onto 9 W X I,
W S 9_W X I.
In t h i s p r o c e s s an o b s t r u c t i o n c a l l e d t o r s i o n o c c u r s n a t u r a l l y . h - c o b o r d i s m w i t h no t o r s i o n is c a l l e d an s - c o b o r d i s m .
An
Alternatively,
an s - c o b o r d i s m i s defined a s a c o b o r d i s m s a t i s f y i n g t h e r e q u i r e m e n t s : d^W C W and
9 W C W are simple homotopy equivalences.
A s i m p l e definition of s i m p l e h o m o t o p y e q u i v a l e n c e is g i v e n a s t h e e q u i v a l e n c e r e l a t i o n on c o m p a c t p o l y h e d r a g e n e r a t e d by c o l l a p s i n g ( K ^ L ) and by P . L . e q u i v a l e n c e K ^ ^ K ^ ^K^ ^ K^
(K = L).
F o r e x a m p l e , t h e finite s e q u e n c e
defines a s i m p l e h o m o t o p y e q u i v a l e n c e of K^ and K^ .
^ i t h any s u c h s e q u e n c e we c a n a s s o c i a t e a s e q u e n c e of m a p s of one t e r m into t h e n e x t , t h e c o m p o s i t i o n m a p is w e l l - d e f i n e d up to h o m o t o p y and is called a simple homotopy equivalence.
-
-
T h e o b j e c t of t h e s e l e c t u r e s i s to o b t a i n t h e following Theorem:
1.
If W i s an s - c o b o r d i s m ,
Suppose
W^ i s g i v e n and s u p p o s e
P L embedding.
Let
W = W Ut
a t t a c h i n g a n r - h a n d l e to 9 W = 9 W,
W,
6, t h e n
itSB^XB^^ ^
Suppose
i^, i^, , . . , i^: B
P L embeddings with disjoint i m a g e s .
and w e s a y
W
i^,!^,
is got b y
We w i l l f r e q u e n t l y b e a t t a c h i n g s e v e r a l r
c o r r e s p o n d i n g to
> 8 , W is a +
is still r e g a r d e d as a c o b o r d i s m with
= 9W' - 9 W .
handles simultaneously.
W S a_W X I.
X B, n - r , t h e n we s a y W
B
W
dim W
9^W
are
T h e n we c a n s t i c k a l l t h e h a n d l e s
on at o n c e ,
is obtained from
n- r XB
say
W by a t t a c h i n g
r-handles.
A s t a n d a r d h a n d l e body d e c o m p o s i t i o n of W is a s e q u e n c e W C W r 0 1
... C W
obtained from
^ where n+1
0
^ 9 W X I, we i n s i s t t h a t "
W^ by a t t a c h i n g i - h a n d l e s and
^ W.
W.
is
1+1
The main ques-
t i o n of t h e t h e o r y m a y be s t a t e d : w h a t h a n d l e body d e c o m p o s i t i o n s give the s a m e manifold? L e m m a 1. Proof.
Let
Every cobordism
K be a s i m p l i c i a l c o m p l e x t r i a n g u l a t i n g
a subcomplex triangulating of K) and w r i t e derived
L" of 1
W has a standard decomposition.
9 W.
Let
W with
K^
L^ = K^ , L^ = K^ u ( ( i - l ) - s k e l e t o n
W. = N(L^' , K"), t h e s i m p l i c i a l n e i g h b o r h o o d of t h e 2nd L. in t h e 2nd d e r i v e d K" of 1
K.
-225-
Now
W^
i s a r e g u l a r n e i g h b o r h o o d of
9_W
in W ( C h a p t e r 11)
but by t h e c o l l a r n e i g h b o r h o o d t h e o r e m ( C h a p t e r I ) a r e g u l a r n e i g h b o r h o o d of
9 W in W, P L
t h e r e is
h o m e o m o r p h i c to
so by the uniqueness of regular neighbourhoods,
9 WXI
and
S 9 W X I. The
proof w i l l b e c o m p l e t e d after establishing the following assertions. Assertioni;
Let
W. =
U ere L.
St(o^, K")
A be an i - s i m p l e x of St(A,K")^W. =
Let
L = { s i m p l e x e s of
having A as a face} we c a n w r i t e
K' =
L
^ = b a r y c e n t r e of
(1)
(r.
K, t h e n S^(A, K") n N(A., K") .
(2)
w h o s e v e r t i c e s a r e b a r y c e n t r e s of s i m p l e x e s
{B^B^. . . B ^ | A < B^ < B^ < . . . < B^ } .
B^ = AC^ w i t h
a PL homeomorphism
where
C^ e l i n k ( A , K ) , t h e n t h e m a p >link(A,K)
Alternatively,
B . — > C^
induces
called pseudo-radial projection. A
We c a n m a k e t h e s a m e c o n s t r u c t i o n a g a i n ; l e t b e t h e p s e u d o - r a d i a l p r o j e c t i o n defined by AC
«
p : l i n k ( A , K " ) —> A L
> C for
C £ link(A,K')
(2)
A'L [ l i n k ( A , K " ) r \ W.]
link(A,K")
(1)
(2)
-226T h e fact t h a t
p sends
link(A, K") O W . —> d e r i v e d n e i g h b o r h o o d of A' •
in A ' L
follows f r o m s t a n d a r d c o n s i d e r a t i o n s (cf C h a p t e r II).
i s full in A ' L , p[link(A, K") n W ^ ]
Since
A'
is a r e g u l a r n e i g h b o r h o o d if A' in
A'L
( s e e C h a p t e r II). The r e m a i n d e r of t h e p r o o f d i v i d e s into two c a s e s . C a s e 1.
A /
In t h i s c a s e , L = link(A, K')
i s a P L s p h e r e so A is an u n k n o t t e d
( i - l ) - s p h e r e in t h e ( n - l ) - s p h e r e
AL.
T h u s by u n i q u e n e s s of r e g u l a r • i n 1
neighborhoods t h e r e is a P L homeomo rphism
06:AL—»9(B
XB
),
Now e x t e n d oc c o n i c a l l y to give a P L h o m e o m o r p h i s m f r o m S t a r ( A , K") —> s e n d i n g A —> X 0) a n d s e n d i n g p[link(A, K") n W . ] — > SB. X B XB
.
Thus attaching
C a s e 2.
A e
star (A,K")
to
W. i s a t t a c h i n g a n i - h a n d l e .
«
Here L is a ball, thus
AL
»
*
i s a b a l l and A C 9(AL)
a s an u n k n o t t e d
(i-l)-sphere. Let
9B^ ^ = F
u F X
where ci
i n t e r i o r s , and o b s e r v e t h a t (b'' X
a : AL
(B^ X F ^ ) u (9B^ X B^"^) = cl[9(B^ X B^"^) -
^^ ( n - l ) - b a l l w i t h
the b o u n d a r y .
F ,F a r e ( n - i - l ) - b a l l s with disjoint l ^
9B^ X ^
a s a n u n k n o t t e d ( i - l ) - s p h e r e in
Thus there exists a P L h o m e o m o r p h i s m
> (B^ X F^) o ( 9B^ X B^"^) s e n d i n g
r i v e d n e i g h b o r h o o d of
A —5> 9B^ X B ^ ^ .
A —> 9B^ X
a n d s e n d i n g a de-
(* is a n i n t e r i o r point of ^^ • )
-227-
T h e n a p : l i n k ( ^ , K") —> (B^ X F ) U
X b'^"^)
e x t e n d s c o n i c a l l y to
a PL homeomorphism h : I t i ; ( A , K " ) — > I ; - [ ( B ' X F)
(as'x
B ' X B"""' ,
w h e r e t h e l a s t P L h o m e o m o r p h i s m e x t e n d s the i d e n t i t y on t h e b a s e of t h e cone.
T h u s w e h a v e a g a i n a t t a c h e d an L - h a n d l e . 2.
We now c o n s i d e r m e t h o d s of a l t e r i n g
the s t a n d a r d handlebody 9
d e c o m p o s i t i o n so a s to e l i m i n a t e h a n d l e s .
The f i r s t c r u c i a l w a y of m o d i -
fying a h a n d l e b o d y d e c o m p o s i t i o n u s e s t h e b o u n d a r y c o l l a r to s l i d e h a n d l e s a r o u n d a s in t h e following L e m m a 2. 1.
lemma.
If f, g: 9B^ X b " " ^ — > d^W a r e P L a m b i e n t i s o t o p i c
i m b e d d i n g s , t h e n W J^ (B^ X b " ' ^ ) ^ W Ug (B^ X b " " ^ ) . Proof. That i s , H:
Let
c be a b o u n d a r y c o l l a r of W ( r e s t r i c t e d t o
c:a_^WXI—with X I —»
XI
c(x, O) = x for a l l x € 9 _ ^ W .
be a P L a m b i e n t i s o t o p y w i t h
a : W — > W b y Q'C(X, t) = c(H.^ t^'^^ a
Let
H^f = g.
and by o- = id. o u t s i d e
Define
Im c.
Then
e x t e n d s to a P L h o m e o m o r p h i s m W
X B"""')
W Ug ( B ' X B ^ ' ^ ) .
We w i l l now l o o k at h o m o t o p y c l a s s e s . imbedding, then
]
If f: 9B^ X B ^ ^ —>
i s an
f{9B^ X 0) C 8_|_W is c a l l e d t h e a - s p h e r e of t h i s h a n d l e and
is s a i d to r e p r e s e n t t h e e l e m e n t
| eir.
the a - s p h e r e t o t h e b a s e p o i n t in
9 W we obtain a m a p r e p r e s e n t i n g
i
is d e t e r m i n e d to w i t h i n t h e a c t i o n of
if by h o m o t o p i n g a point on
on tr^
^ = 2, t h i s a c t i o n of tt^ on -rr^ i s an i n n e r a u t o m o r p h i s m .
If
-228W e i n t r o d u c e t h e followin g n o t a t i o n . then
i s t h e e l e m e n t of
around the path 3.
co.
If
TT^
If
^ nK
and
i n d u c e d by c a r r y i n g the b a s e point
i = 2,
= oj ^ ^ go.
We w i l l now l o o k at t h e following m a i n c o n s t r u c t i o n .
If we h a v e
two h a n d l e s a t t a c h e d to a c o b o r d i s m , b o t h a t t a c h e d to t h e s a m e l e v e l , t h e n we c a n s l i d e o n e h a n d l e o v e r t h e o t h e r . T h e o r e m 3. 1 (Handle a d d i t i o n t h e o r e m ) : and l e t
W'=W
u.' h f f 1
u
disjoint embeddings
9B
g represents
TT^
Then 8B
r
in
W ^ W
h^ w h e r e g Z XB
£ ^^^
Suppose
f
2 i r c n-3. with
f, g'
Let
a n d f, g
represents cj 6
d i s j o i n t i m b e d d i n g s of
X B
in
and
g'
f . cC If i =P 2r o owe a nh ocohsoe o s ex €g'
representing
b o u n d a r y c o l l a r of
- f(aB
f(9B^ X 9B®) X I —> a w .
r ± ^
with p r e s c r i b e d sign.
x '^^co h ^ . o r L e t coc ^^be a ] to r e pand r e s elnet eDi t h=e rB^ X co 1*
Let
n r XB
).
c
is an i m b e d d i n g of
c be c h o s e n so t h a t
I
let
be c o n n e c t e d
h?^ S b"^ X B ^ " ^ , i = i , 2 1
—• and
Let
D' = D
Im(c) n h
= jll a n d ^
c[(9B^ X x ) X l] = D ^ c[9D X l]. 3.
1*
S^ f r=o m g(9B9D'X to 0). S^S i n cwei t h still cF o no nr e cc toendv. e n iLeentc e P in bneo taa tpiaotnh winr i t e9_^W f(9B^ X = P I"' h^^ with
h^^ By g e n eXr a0)l pof o s ictoi odni m , ePn s icoann 3beinc h9^W, o s e n a9^W s an -e m b e dr d W e d ipsa t h
P OD = P ^ S ^ = Ct
-229-
Let
N be a Z ' ^ ^ - d e r i v e d n e i g h b o r h o o d of P
in
so t h a t
N
is an ( n - l ) - b a l l and N n B D ' j N '-S^^ a r e both p r o p e r l y e m b e d d e d (r-l)-balls
(3).
We now a p p l y I r w i n ' s e m b e d d i n g t h e o r e m ( C h a p t e r 8)
to e m b e d a c y l i n d e r
S^ ^ X I in N j o i n i n g the b o u n d a r i e s of t h e two r-2
{r-l)-discs.
S i n c e we a r e e m b e d d i n g
S
X I in an ( n - l ) - b a l l , r-2 c o n n e c t i v i t y c o n d i t i o n s r e d u c e to t h e c o n d i t i o n that S X I be 2 ( r - i ) - ( n - l ) connected, that is, r - 2 > 2 r - n - l
or
n - 1 >r.
Irwin's
The condition is
r-2 satisfied, onto
so let
9N ^ 9D'
i: S and
XI — N
be an e m b e d d i n g m a p p i n g t h e b o u n d a r y
dN n S^^,
(3)
Let
g ' : SB^ X 0 —^ d W
i./r.n-2 ( S " X I) u (3D' - N)
(4).
send Let
X 0 onto S ^ - ( S ^ n N) ^^
W^ = W
h^ .
Claim
g ' , g ;aB
a r e a m b i e n t i s o t o p i c in
g' = g
/ N'
XO
-230-
First subdivide fiirther with N a subcomplex. Let N' = 2nd derived neighborhood of D' - D' n Int N
- Int N. N' is an (n - 1) ball
meeting SN in an (n - 2) ball, therefore NUN' is an (n - 1) ball, g' and g| aB^ X 0 agree outside N U N ' .
In (N U N' ) we have two properly embedded
balls which agree on the boundary. By Zeeman's "Unknotting balls" (Chapter 5), g' is isotopic to g in (NUN'), keeping the boundary fixed. Any ambient isotopy of gives an extension g" : SB^ x B^"''^
throwing g|
x 0 onto g'
x O)
of 5' / ambient isotopic to g in
By uniqueness of regular neighborhoods there exists an ambient isotopy of
fixed on g' (SB^ x O) and throwing
-231-
g'(9B^ X b'^"^)
onto a
c a n a r r a n g e for
g ' ( 9 B ^ X 0).
d e r i v e d n e i g h b o r h o o d of
g'(9B^ X b "
to b e d i s j o i n t f r o m
Thus we
h^^.
We have two i m p o r t a n t c h o i c e s (1)
The path
P
(2)
T h e o r i e n t a t i o n s of t h e h o m e o m o r p h i s m s - 9D' 1
Then
g'
r e p r e s e n t s a n e l e m e n t of t h e f o r m
r + |
00
where
P
determines
w and the o r i e n t a t i o n s d e t e r m i n e the sign. 4.
We n o w c o n s i d e r t h e p r o b l e m of c a n c e l l i n g h a n d l e s .
prove a simplifying L e m m a 4 . 1. MA M .
Then
lemma. Suppose
M
c o l l a r of
^ ^ Q
X
(Using regular neighborhood theory):
M , then 1
M
Z
M \ M 1
b o t h r e g u l a r n e i g h b o r h o o d s of
o
= cl[M
M
in O
Definition. and in
Let
M
N a r e t r a n s v e r s e at
,N x
ZQ
1
-Imc]
M
Thus w
If
c
is a boundary
and hence M
M ,M 1
^
are
S M X
be P L manifolds.
o
We s a y
if t h e r e e x i s t s a c l o s e d n e i g h b o r h o o d
M U of
Q a n d a P L h o m e o m o r p h i s m U, U n M , U n N — b " ^ X b"^, B ™ X 0,
0 X B^. of
^^^ compact P L manifolds,
S M ^
Proof.
We f i r s t
M and
M o N.
N
a r e t r a n s v e r s e if t h e y a r e t r a n s v e r s e at e a c h point
x
-232Note:
If M, N a r e t r a n s v e r s e at x, then Q),'itir^(x, M ) , star(x, N)
S b"^ X b",
b " ^ X 0, 0 X
b"^
( R e c a l l t h a t t h e s t a r of a point is w e l l - d e f i n e d up to P L h o m e o m o r p h i s m . ) Now s u p p o s e
W = W
^ ^ i n t r o d u c e t h e following
notation: S^^ = gOB^""^ XO) C
.. h ^ ^ ) .
s j " = OX a s ' ' ' ' ' C 9 fw .... h / ) 1
+
1
J
D = O X B ^ - ^ C h^" . T h e o r e m 4. 2.
If S^, S^ i n t e r s e c t t r a n s v e r s a l l y in a s i n g l e point
t h e n W ^ W.
(5)
Proof.
We s h a l l p r o v e
F i r s t note that collapse ^^
B
W ^ W and a p p l y L e m m a 4. 1.
b"""^^ X b ' ' " ' " ^
XB
^dB
,r+l r+1 .. „ n - r - l 9B" " X B " " ' u B" ' '
X
B"
\
XB ^^ . . . \
X b''"''"^
u-o
Xis
, r + i .. „ n - r - l 9B^ ' ^ X B'
/
(6)
.
(b"""^^ X
0) by the
\ ... b'^'^^XO.
(6).
/
/
/
/
/
/ r+1 .. ^ n - r - 1
(B""^^ X 0) =
_
r+1
(B""""^ X
0).
-233-
Let Let
W^ = W ^ ^ h ^
Uj^ = s t a r (x, W ^
D-U^
N , away from 1
so
N^
U^
b a r y c e n t r i c d e r i v e d of
- U = the
N \ BN i i
-(N i
D = s t a r ( x , D), so
Hence
U^
as subcomplexes.
barycentric derived
U = a n ( n - l ) b a l l in
N^aW-U; 1
an ( n - r - 1 ) ball . =
Note
S - U in
Notice that
with
and l e t N^ = t h e
in W^ - Uj^ .
n e i g h b o r h o o d of
and t r i a n g u l a t e
^
-U) = Fr i
U^
U u Fr
N ^. (N ~ U ). ^ ^-U^ ^ i i i N
D ^^ D - U^ = l i n k ( x , D)
N^ = Z^*^ d e r i v e d n e i g h b o r h o o d of
d e r i v e d n e i g h b o r h o o d of a b a l l = a n ( n - 1 ) b a l l . U^
Now c o l l a p s e
U^
D - U^^
T h i s b a l l is a face of
U^^,
U^ .
F r o m the above r e m a r k s ,
W^^ W^-N^
W^-N^-U^
- U.
By t r a n s v e r s a l i t y t h e r e e x i s t s a P L h o m e o m o r p h i s m U, U n. S^, U Now
S^
aU
> B^ X
so
(U is the s t a r of
N^ = 2^^ d e r i v e d n e i g h b o r h o o d of
is a r e g u l a r n e i g h b o r h o o d of assume
B^ X 0, 0 X
0 X a B ^ ^ ^ in
b(aU ^ N^) = B^ X 3 6 (U rN S^) u ( F r
n-r-1
.
., Also
a u ^ S^ and
a(B^ X b " ^
-D^ -on-r-l B X B
x).
b(aU^> N^)
so we c a n X 0) o l a B " " X B"""^"^)
U) . aw-N
1 w e h a v e now s h o w n t h a t b y a s e q u e n c e of c o l l a p s e s W^ ,r+l (B^"^^ X 0) and W., Vj (B^"^^ X 0 ) V w - N - U , u 1 g * 1 1 1 g t u r b e d d u r i n g t h e s e q u e n c e of c o l l a p s e s . we c a n c o l l a p s e N^
b""^
X 0 \ S^ - S^
Since
so
r+1 B^"^^ X 0 h a s b e e n u n d i s -
a S rN U i s a face of
U so W^ ^^(b""^^ X O)
is a r e g u l a r n e i g h b o r h o o d of D in W^
b o r h o o d of D in W^
W^ - N^ - U^ ^
-N^^ -U^ ^ S^,
W^ - h^
B
r+1
X0
-N^-U^^ .
and h^^^ i s a r e g u l a r n e i g h = W.
-234The first application of T h e o r e m 4, 2 will be in (7)
removing the 0 - h a n d l e s . L e m m a 4. 3. W
^
Let
W
= W w k^ w k^ o . . .
W ^
J.
1
= W O h ° w h^^ u . • .. 1 2 k ^ .
J.
If (W
^
^
h ^ p
and
W) i s 0 - c o n n e c t e d ,
W o (a n u m b e r of 1 - h a n d l e s ) . Proof .
By i n d u c t i o n on t h e n u m b e r of 0 - h a n d l e s .
of t h e t r i p l e (W^, W^, Wq)
shows that
W^)—^
The exact sequence ^o^^l^O^
T h u s for e a c h p a i r of p o i n t s x , y in two different c o m p o n e n t s of find a n e x p l i c i t 1 - c h a i n h a v i n g k^. s a y , w i t h one e n d p o i n t in
x-y
as boundary.
i s t h e w h o l e of i t s b o u n d a r y
h*^
By T h e o r e m 4 . 2 , W pletes the inductive step.
B^ X B^
S^ = 0 X 9 B " .
a - s p h e r e is a p a i n of p o i n t s
m e e t s t h e b - s p h e r e of
is onto.
W^ w e c a n
T h u s t h e r e e x i s t s a 1-hand:
h^.
Note t h a t a 0 - h a n d l e h a s t h e f o r m
the
then
so the b - s p h e r e of a 0 - h a n d l
S i m i l a r l y , for a 1 - h a n l d e B^ X B"
S^ = 9B^ X 0, so a n a - s p h e r e of h^
always
transversely. S Ww(p-l)
0-handles o l - h a n d l e s .
This c o m -
-235§ 5.
We now w a n t to d e l i b e r a t e l y add on an e x t r a p a i r of h a n d l e s for
cancellation. Theorem 5.1.
Suppose
W is g i v e n w i t h r
in
r < d i m W - 1 and
U
open
r+1
T h e n W S W = W ^ h^
h^
, where
(1) (h^ o- h^) ^ W C U (2) S ^
and
S^
Li Proof.
m e e t t r a n s v e r s e l y in one p o i n t .
1 In V. B ^ , l e t C,^ = {Xv + (1 -X )x : x € B ^ , x < ^ } C ^ = { \ v + ( l - X ) x : X e B^ , x
}
Observe that
v B ^ X B ^ ^ ^ is an n - b a l l and v(9B^) X B ^ ^ ^ i s a f a c e ,
say F .
i : F —> U b e a n e m b e d d i n g , t h e n W S W U. (vB^ X
Let
n-r-1 N WS SB^B X ^ X ^ " ^ h^ "^ = , C^ 9 B ^XX B I X Now C^ I, I sXo Bput ^ ' ^B" ^ . T hTehnu s C^ ^ v B ^ S B^"^^ , a n d if h
n (W u h ) = 8C Ld
(8)
^
= C^ X b ' ^ " ^ " ^
X b " ' ^ " ^ , so h L^
hj^ is a n r - h a n d l e ,
is a n ( r + l ) h a n d l e a t t a c h e d t o Cd
W u h X
-236-
n
e
t
an
i n t i o n s k
L e m m a 6. 1. E" ~
Suppose
and s u p p o s e g i v e n
i
K ,L
c e K,
a r e c o m p a c t c o m b i n a t o r i a l m a n i f o l d s in
T e L,
d i m (cr
T) ^ d i m cr + d i m T= k + 1
(i. e, , s i m p l e x e s m e e t at m o s t in i s o l a t e d p o i n t s in t h e i r i n t e r i o r ) .
T h e n , K, L
m e e t t r a n s v e r s e l y in a finite n u m b e r of p o i n t s . Proo f.
T h i s is c l e a r f r o m g e n e r a l p o s i t i o n c o n s i d e r a t i o n s .
C o r o l l a r y 1.
If
B
,B
C B
a r e p r o p e r l y e m b e d d e d balls with
t h e n t h e r e e x i s t s an a r b i t r a r i l y s m a l l P L h o m e o m o r p h i h: b " ^
> b"^ ^ fixed on t h e b o u n d a r y w i t h
T^
T^tn+n
Proof.
Suppose
m+n
B
,
B™, h B ^
.
,
and triangulate
l i n e a r l y e m b e d d e d in
„m
B
transverse. „n
,B
so t h e y a r e
Now shift t h e v e r t i c e s by a s m a l l a m o u n t into
g e n e r a l p o s i t i o n ( C h a p t e r 4). C o r o l l a r y 2.
If
M^, N ^ C q " ^ ^ a r e m a n i f o l d s w i t h o u t b o u n d a r y a n d
M compact, then t h e r e is an a r b i t r a r i l y s m a l l P L h o m e o m o r p h i s m with
M, hN Proo f.
h: Q —> Q
transverse. By g e n e r a l p o s i t i o n a s s u m e
M n N is a finite s e t of p o i n t s .
Now a p p l y C o r o l l a r y 1 in d i s j o i n t n e i g h b o r h o o d s of t h e s e p o i n t s . §7.
G e o m e t r i c and a l g e b r a i c i n t e r s e c t i o n s .
Let
W
suppose and let
r = Ww h/vj ... u i i
-Tr^(W) = Tr^(W^). W p
covering space.
W^
where
Let
h
r r+1 , W = W^ U k , u p ^ i i
W C W^
p: W^ —5> W^
... U k
r+1 q
be t h e u n i v e r s a l c o v e r s of
and W.W^
is t h e n a t u r a l p r o j e c t i o n m a p of t h e
-237-
Now for e a c h h a n d l e a lift
k
of k . J
j
h. c h o o s e a lift h . of h . and for e a c h j 1 1 1 Given x e ir, (W) we r e g a r d x a s a t r a n s f o r m a t i o n of t h e 1
c o v e r i n g s p a c e and w r i t e
xh.
a s t h e h a n d l e o b t a i n e d by a p p l y i n g the t r a n s -
f o r m a t i o n to h . c h o s e n a b o v e . 1 r>mf
Let
generate
W), ^ be t h e c o r r e s p o n d i n g g e n e r a t o r of
S i m i l a r l y , define
r]. a s a g e n e r a t o r of r*^
write
r|.
rsj
a s t h e c o r r e s p o n d i n g g e n e r a t o r of rv^
t h e g r o u p r i n g of ir J W ). X ^
Now
W) rsj
r. W).
rw
rsj
•. . ^ A p
generate
and
Let
A
be
roj
H ( W W) a s a f r e e r i.
A
m o d u l e s i n c e e v e r y h a n d l e in t h e c o v e r i n g i s got by a t r a n s l a t i o n of one of t h e 1'^'s.
Similarly
generate
as a free A module
a n d w e o b t a i n a m a t r i x r e l a t i n g t h e s e g e n e r a t o r s f r o m t h e b o u n d a r y o p e r a t o r 9., writing
^
^ = ^
X..
w i t h X.. € A .
We w i l l now s e e h o w t h e s e e l e m e n t s of t h e g r o u p r i n g a r e tied up w i t h t h e i n t e r s e c t i o n s of t h e a - s p h e r e s a n d t h e b - s p h e r e s .
Let
S^ = a - s p h e r e of k . C 9 , W, J ^ J + 1 S^ = b - s p h e r e of h . C d W 1
1
^
D^ = u s u a l d i s c s p a n n i n g Notice ~ in W
a b S ,S bound d i s c s in W^
~ and D. s p a n n i n g
+
S^^
(O X b "
so we h a v e a l s o c h o s e n lifts
^ a S^ , S^
b S. .
T h e f i r s t t h i n g to o b s e r v e is t h a t a b xS. , yS a r e t r a n s v e r s e in J ' 1
^ 9, W, + 1
S^^, S^^ t r a n s v e r s e in
for a l l
t h e c o n d i t i o n of t r a n s v e r s a l i t y is l o c a l a n d
x, y e TT", {W_). 1 Z
implies
T h i s is t r u e s i n c e
p is a local h o m e o m o r p h i s m .
-238-
Further,
W
i s o r i e n t a b l e , s o to e a c h t r a n s v e r s e i n t e r s e c t i o n w e m a y g i v e
a sign. In g e n e r a l if (9)
and N.n" a r e s u b m a n i f o l d s of a n
m"^
,nnL+n which meet t r a n s v e r s e l y Q
o r i e n t a b l e manifold at a point
x, t h e r e is a h o m e o m o r p h i s m
h : U , U r \ M , U n N —^ B"^ X B^, B"^ X 0, U i s a n e i g h b o r h o o d of x choose
h
so
in Q.
UHM, Ur\N
OXB'^,where
G e o m e t r i c a l l y , w e can
a r e m a p p e d with the natural
o r i e n t a t i o n and give i n t e r s e c t i o n sign + 1 a c c o r d i n g a s w h e t h e r U is m a p p e d with c o r r e c t o r i e n t a t i o n . M o r e p r e c i s e l y , in t h e d i a g r a m H
H
(M) m
H
m
^
(M, M -
W
1=1
H
m
( Q , Q - N) A
[U.OM]) 1
( U . A M , a u . " ^ M)i 1
1=1
for e a c h onto
i t h e g e n e r a t o r of
+ t h e g e n e r a t o r of
H
^ M, aU^O M) m a p s (Q, Q - N )
by t h e l o c a l p r o -
m d u c t s t r u c t u r e , t h e s i g n ± i s p r e c i s e l y t h e s i g n of the intersection. ~ a We define t h e a l g e b r a i c i n t e r s e c t i o n of S. w i t h ~ b xS^
by taking the signed i n t e r s e c t i o n s and adding.
T h e n t h e a l g e b r a i c i n t e r s e c t i o n i s t h e coefficient of in
X.. Ji
.
x
-239P Lemma 7.1. and
If
Q
B*"^, B
P'^Q C B
( b P ' ^ ^ b'^) u n k n o t t e d w i t h
with opposite sign, then Proof.
9B
B^, B ^ m e e t i n g t r a n s v e r s e l y at two p o i n t s is i n e s s e n t i a l in B'^^
BB^ is h o m o l o g o u s to z e r o in
c o b o r d a n t to two s p h e r e s e a c h l i n k i n g is t h e r e f o r e i n e s s e n t i a l s i n c e TT - 1 If p ^ p + q - 3
Proof .
is
B ^ o n c e in o p p o s i t e d i r e c t i o n s ] a n d
p-i
and t h e a b o v e h y p o t h e s e s hold, 9B
P B
- B .
B^^^^ - B*^ [ b e c a u s e
p-i
Corollary.
a p-disc
a r e p r o p e r l y e m b e d d e d b a l l s , p, q > 1
•nP'^q p r o p e r l y P L e m b e d d e d in B
spans
T-> 1 - B .
T h i s is a d i r e c t a p p l i c a t i o n of I r w i n ' s e m b e d d i n g t h e o r e m .
Note t h a t 2p - (p+q) + l < p - 2 , t h u s t h e c o n n e c t i v i t y c o n d i t i o n on t h e i m a g e s p a c e is s a t i s f i e d . Theorem 7.3. and
Let
Tr^(9^W) S n - ^ ( W ) .
W^ = W u h^ , W^ = W^ u k^"*"^ Let
b - s p h e r e of h r e s p e c t i v e l y ,
with 2 < r < n - 4
a b S ,S r e p r e s e n t t h e a - s p h e r e of k and the a b in Assume S ,S meet transversely. a b
Now lift to t h e u n i v e r s a l c o v e r a n d a s s u m e with o p p o s i t e s i g n (plus s o m e m o r e ,
S , xS
m e e t in two p o i n t s P^ , P ^
possibly).
T h e n we c a n a l t e r t h e a t t a c h i n g m a p of k by a n i s o t o p y to an a t t a c h i n g a' b m a p k' so t h a t S ( c o r r e s p o n d i n g to k ' ) is t r a n s v e r s e to S and m e e t s it a r+1 in two f e w e r p o i n t s t h a n S and so t h a t W^ s W^ o' k' Proof. position not m e e t
T b e p a t h s in S^, S^ f r o m 1 ^ ( r > 3, n - r - 1 > 3 ) w e c a n a s s u m e t h a t S^
Let
S^
T
e x c e p t in t h e i r end p o i n t s .
P
to 1
P . By g e n e r a l iC e m b e d d e d and do
-240-
We now h a v e to n o t i c e t h a t
F , F lift to p a t h s in t h e u n i v e r s a l X L*
rsj
cover P, , P^ 1 2
h a v i n g the s a m e e n d p o i n t s . we c a n lift
in
F
1
in S ^ ,
F
2
In fact,
in S .
So,
by t h e c h o i c e of F u F is i n e s s e n t i a l L c
. We w i l l s p l i t t h e proof into two c a s e s :
C a s e 1.
r > 3.
Let
D be a d i s c in
general position, a s s u m e
spanning
- d i m S^ = n - 1 - r > 3), and s i m i l a r l y
(dim
- d i m S^ = r > 3).
a ball with
X
sign.
By= F,
D ' S^ = F^
N be the Z^d d e r i v e d n e i g h b o r h o o d of F ,F
F^.
D i s e m b e d d e d ( d i m 9_j_W > 5), D r S
(dim
Let
F^
D in
then
N is
p r o p e r l y e m b e d d e d , m e e t i n g in two p o i n t s w i t h o p p o s i t e ^
By C o r o l l a r y 7. 2, we c a n shift
N
S^ off
N
S^
k e e p imi g
- N fixed. C a s e 2.
r = 2.
H e r e , t h e s p a n n i n g d i s c u s e d in t h e p r e v i o u s a r g u m e n t
might hit
S^ in a n u m b e r of p o i n t s .
Notice that
9 W, . S^ ^ d W^ - (h, T 1 + i i. But now, if (S-)^ is the a - s p h e r e of h, So,
- S^) =
(10) T i - ( S ' f ^ 9^W - (h
- ( S ' f ) = -Tr^(9_^W) =
w h e r e the
i s o m o r p h i s m i s i n d u c e d by i n c l u s i o n . Let in
9 W T i
be a s b e f o r e , with
N^ =
derived neighborhood
F , F , S^, and S^ a s s u b c o m p l e x e s . i
= r^ . (r^ - N^),
e n d p o i n t s of
F^' .
of
F^
Let
9N^ - (9N^ '
( n - 2 ) s p h e r e - ( n - 4 ) s p h e r e and i s t h e r e f o r e c o n n e c t e d .
So l e t
S^) = F^
be a
-241-
pt
in
o m t o
(10)
F r o m t h e d i a g r a m ( l l ) it i s c l e a r t h a t to
T^ u r ^
and i s t h e r e f o r e i n e s s e n t i a l in
- S^ b y t h e p r e v i o u s i s o m o r p h i s m . 8 W - Int N - S^ I X 1 assume
S i n c e N^
spanning
D is embedded,
Now l e t N ^ meets
T^ v j ^ ^
T' u T ' , X ^
hence in
Thus t h e r e is a disc
D
in
By g e n e r a l p o s i t i o n w e c a n
D O S^ = F^' and D H
= F^'.
b e a Z^^ d e r i v e d n e i g h b o r h o o d of N^
i s h o m o t o p i c in
i n a c o m m o n f a c e , N = N^^
D in
- Int N ^ .
N^ i s a n ( n - l ) b a l l
(12).
Notice that N i ^ S i s a r e g u l a r n e i g h b o r h o o d of F^ in S and N A S^ = N n S^ i s a r e g u l a r n e i g h b o r h o o d of F in S^. F o r , 1 ^ N.^ n S^ = d e r i v e d n e i g h b o r h o o d of F^ i n S'', N^ H S " -= 27nd ^^ d e r i v e d 3,
n e i g h b o r h o o d of
I^' in S
- N^ , so N
2L S is an r - b a l l .
Similarly,
-242-
U s i n g t h i s c o n s t r u c t i o n we m a y m a n i p u l a t e
S^ a n d S^ to get t h e m to
i n t e r s e c t t r a n s v e r s e l y in a s i n g l e p o i n t , p r o v i d e d we know s o m e t h i n g about t h e i r a l g e b r a i c i n t e r s e c t i o n . r
Corollary 7.4. and
2 < r < n-4. rsj
and
Let
Suppose
k
, ir^(a^W) = -rr^(W)
H (W , W), TI g e n e r a t e s r i
r^j rs^
a r e lifts g e n e r a t i n g rsj
If
= W^^
^ generates
rsj
^ , r|
r+1
W^ = W o h ,
rsj
h, h r W)
rsj r^
and
H ,, (W W) r T1 ^
r>>j
k.-^ W^)
respectively.
rsj
a T) = ^ , t h e n
Proof.
W^ S W.
We h a v e to l o o k at how t h i s a l g e b r a i c c o n d i t i o n t i e s up w i t h v: • V
rs^
intersection numbers.
We know
9 r| =
^ ^
rs^
a x 6 w h e r e the integer a X
X € IT,
t h e i n t e r s e c t i o n n u m b e r of
S
w i t h xS .
i So if
9 ri = ^ , a
X
is
= 0 if x f 1 X
and
a^^ = 1.
So by r e p e a t e d a p p l i c a t i o n of L e m m a 7. 3, o b s e r v i n g , for e x a m p l e ,
a that
S
b meets
xS
in p a i r s of p o i n t s w i t h o p p o s i t e i n t e r s e c t i o n s i g n and
c a n c e l l i n g t h e s e p a i r s , it follows t h a t W
= W
(k') w h e r e
t r a n s v e r s e l y in a s i n g l e point a n d c a n c e l l i n g t h e h a n d l e , We now show how to c a n c e l r h a n d l e s by a d d i n g
S^ ' c u t s
S^ '
W^ = W. (r+1) and (r+2)
handles. Lemma 7.5.
Suppose
W
= W Oh
, W
i Tr^(9^W) = -n:^(W), 2 < r < n - 4 . W^ ^ W ^ (r+1) Proof. r^
^~ ^ i =1
If
= W ^ k ^ i i
r+1
^
...
r+1
k '
(W^ , W) is r - c o n n e c t e d t h e n
h a n d l e s u a n (r+2) h a n d l e .
9: H ,, ( W_, W, ) —3> H ( W, , W) is onto and so we c a n w r i t e r+1 c L r 1 r^ where
t^ e A and T) ^ g e n e r a t e
rv/
We w i l l i n t r o d u c e a c o m p l e m e n t a r y p a i r of h a n d l e s (14).
r +l . ^^
"W^).
The attaching spheres
-243-
of kj^ . . . k
do not c o v e r
So c h o o s e
t h e r e f o r e t h e a t t a c h i n g m a p s do not c o v e r
U C
with
U disjoint from
a t t a c h a p a i r of t r i v i a l l y c a n c e l l i n g h a n d l e s in
U.
k^ . . . k ^ .
We may-
Let
(14) r+1
r+1
I
r+2 r+1
U r+1
W
r+2 S W
(k X
K
be t h e p a i r of c o m p l e m e n t a r y h a n d l e s a t t a c h e d in 1
k
,,) q+1
.
i s n u l l h o m o t o p i c in W ' . r^/
i .
Let
W' r W, 2 1
U.
So, q+1 •
Thus under the boundary m a p
rs./
We w i l l now a p p l y t h e h a n d l e a d d i t i o n T h e o r e m 3 . 1 .
Since the t h e o r e m
is s t a t e d in t e r m s of h o m o t o p y c l a s s e s , we m u s t p a s s f r o m t h e s p h e r i c a l homology class
r\ to t h e c o r r e s p o n d i n g h o m o t o p y c l a s s .
h: TT (9 W ) —> H (9 , W, ) be t h e H u r e w i c z m a p . r + r + l sents
or. 6 TT
= -rr
Let
If t h e a - s p h e r e of k. 1
(up to t h e i n d e t e r m i n a t e
o;^ — o c ^ )
o b t a i n f r o m t h e following d i a g r a m
w the relation k' q+1
li
j h a . = 9 T). .
By t h e h a n d l e a d d i t i o n t h e o r e m we c a n c h o o s e
so t h a t i t s a - s p h e r e r e p r e s e n t s ^
a ' , = a ,, + q+1 q+1
X.or. . i i
So
reprewe
-244-
^ We c a n now u s e 7. 4 to c a n c e l
1=1 the r - h a n d l e in W^' = W^ W u (r+1)
k^ ^ • . .
and hence
q+1
W^ ^ W^ ^ I
S
h a n d l e s ^^ an (r+2) h a n d l e .
T h e following h a n d l e r e a r r a n g e m e n t l e m m a is s o m e t i m e s u s e f u l . L e m m a 7. 6 . W^ S W^ „ k '
s
If W^ = W ^ h'^ , W^ = W^ - k® , s < r , t h e n
where
k'
s
is disjoint from
Proo f.
F i r s t of a l l , if
2L
b
dim S
+ dim S
r h .
S^ = a - s p h e r e of k a n d S^ = b - s p h e r e of
h,
3. =(s-l)+(n-r-l)
By g e n e r a l po sit ion S
can
be m o v e d ,boff . S^ by an a m b i e n t i s o t o p y . L e t N^^ be a derived neighbornot m e e t i n g S (15). T h e r e e x i s t s an a m b i e n t i s o t o p y hood of S in of
throwing
of S^ in
N^
onto
So S^ i s now d i s j o i n t f r o m
If f: 3B® X B""® —^ let
N^
h which is also a r e g u l a r neighborhood
i s t h e a t t a c h i n g m a p of k w i t h
be a 2^^ d e r i v e d n e i g h b o r h o o d of
T h e r e e x i s t s an a m b i e n t i s o t o p y c a r r y i n g t h e two h a n d l e s a r e d i s j o i n t .
(15)
h.
S^
in
f(9B
S^n
B+W^^ not m e e t i n g X B
) onto
h^ h.
^nd now
-245-
C o l l e c t i n g a l l o u r r e s u l t s , we h a v e L e m m a 7. 7.
= W . h / h ^ , W^ = W, 1 1 p 2 1 1 = TT^CW), 2 < r < n - 4 and ( W ^ . W ) i s r - c o n n e c t e d , t h e n
W
If
W
. .. ^ '
, q
s W u (r+1) h a n d l e s L (r+2) h a n d l e s . Proof.
By i n d u c t i o n on
look at t h e e x a c t s e q u e n c e
p.
Let
W' = W 1
h,^^ ^ . . . 1 -
ir (W' , W) —^ -rr (W Z*
1
^
Z*
conclude that
ir (W W ) = 0. 1* ^ 1
By i n d u c t i o n ,
WJ ^ ( r + l ) h a n d l e s ^ W ^^ ( r + l ) h a n d l e s
§8. r ^ 2.
^
h^ , . p-1
W) —> -rr (W
X*
By 7. 5, W
'
Now we
W' ) —> 0
and
1
S W' _ ( r + l ) h a n d l e s j (r+2) h a n d l e s . ' 1 „(r+2) handles.
We h a v e now done a l l t h e g e o m e t r y n e c e s s a r y to c a n c e l r - h a n d l e s ,
In t h i s s e c t i o n w e s h o w how to c a n c e l 1 - h a n d l e s . L e m m a 8. 1.
Let
TTj^ (9_j_W) = 7rj^(W) a n d W^ S W
2-handles
W
1
= W ^ h\
(W^, W)
W^ = W, u k / - . . . 2 1 1
1-connected.
Under these conditions
3-handle.
T h e p r o o f w i l l be v e r y m u c h like t h e c a s e Xe 9B
.
k ^ , n > 5, q —
r ^ 2.
Let
P = B X x C h',
We can a s s u m e that
P
is disjoint from all 2-handles,
we c a n m o v e t h e a t t a c h i n g s p h e r e s off
P
since
by g e n e r a l p o s i t i o n and u s e r e g u l a r
n e i g h b o r h o o d t h e o r y to m o v e the 2 - h a n d l e s off P . S i n c e (W^, W) 1 - c o n n e c t e d , P is h o m o t o p i c in W^ k e e p i n g e n d p o i n t s fixed to a p a t h in So t h e r e i s a n e w p a t h P ' in - h' w i t h 9P' = 9P
and
P U P'
a s s u m e that
P u P'
b - s p h e r e of
h'
i n e s s e n t i a l in W^
(16 ).
i s an e m b e d d e d 1 - s p h e r e in
t r a n s v e r s e l y in a s i n g l e p o i n t .
By g e n e r a l p o s i t i o n we m a y , which cuts the
-246(16)
a t t a c h i n g s p h e r e of a n o t h e r 2-hand3.e
We w i l l now i n t r o d u c e
k^ ,, , i a p a i r of c o m p l e m e n t a r y h a n d l e s and q+1 s l i d e t h e a t t a c h i n g m a p of the 2 - h a n d l e a r o u n d to t h r o w it onto P u P ' . Let S^ = a t t a c h i n g s p h e r e of k
, by c o n s t r u c t i o n (§5) S^ is i n e s s e n t i a l in d W q+1 So by Z e e m a n ' s u n k n o t t i n g t h e o r e m , P u P ' , S^ a r e a m b i e n t i s o t o p i c in
2 Thus
W^ S W^ u k^
s p h e r e of k ' , , i s q+1
2 u •••
P - P'.
^ 3 - ^'
k q v.
So we c a n c a n c e l
w h e r e the attaching
h a n d k ' ^ . , , by 4. 2. q+1
c a n c e l a w h o l e lot of 1 - h a n d l e s by u s i n g t h i s t e c h n i q u e r e p e a t e d l y .
We c a n
Collecting
t h e v a r i o u s p r e c e d i n g t h e o r e m s we o b t a i n T h e o r e m 8. 2. r-connected,
r < n-3.
Proof .
Let
W be a c o n n e c t e d c o b o r d i s m , w i t h (W, 9 W)
Then
W & (9 W X I)
h a n d l e s of i n d e x > r.
C h o o s e a s t a n d a r d h a n d l e d e c o m p o s i t i o n and a p p l y v a r i o u s
l e m m a s above. One of the i m p o r t a n t t h i n g s a b o u t c o b o r d i s m i s t h a t w e c a n t u r n t h e m u p s i d e down. If let
W
0
By t h i s p r o c e s s , an r - h a n d l e b e c o m e s a n ( n - r ) h a n d l e . W
1
W
n+1
i s a s t a n d a r d h a n d l e body d e c o m p o s i t i o n ,
W' = W o (9_^W X I) and identifying
X 0 with
d^W, l e t
9_|_W' = 9 W,
-247-
9 W =
X 1.
N o t i c e t h a t a t t a c h i n g a n i - h a n d l e to
(n-i) handle from
W - W^.
That is, B X B
W^ r e m o v e s an
is a t t a c h e d to W^ by
9B^ X B^ ^ and so i s a t t a c h e d to t h e c o m p l e m e n t by B^• X 8B W' = W - W , then i n-i+1 decomposition.
W' 0
W' 1
...
If
W ' , , is a s t a n d a r d h a n d l e body n+1
T h i s e n a b l e s u s to s t a t e a s t r o n g e r f o r m of
T h e o r e m 8. 2'.
.
If W i s a s in 8. 2, 2 < r ^ n - 3
and
T h e o r e m 8. 2.
(W,
is
( n - r - 2 ) connected, then W S a W X I u r-handles Proof. ^ n-r-2.
(r+l) handles.
T u r n i n g u p s i d e down we m u s t c a n c e l t h e h a n d l e s of i n d e x
T h i s i s p o s s i b l e by o u r l e m m a s p r o v i d e d n - r - 2 < n - 4 , i. e. , r > 2.
Now s u p p o s e
W^ = W ^ h^^
. . . ^ h^^
, W^ = W^ rsj
TT /A W) = TT, (W) a n d 1 + 1
2
Let
•• •
_ ,
rs-«
E • ^ H (W W), -q. € H , fW , W ) be 1 r 1 1 r'T'i c 1
generators chosen as before. T h e n the b o u n d a r y matrix
M =
H^lW^,"^
is r e p r e s e n t e d b y a
where 9 Ti. = > 1 ^
m.. ij
J
with
m..i'A. iJ
F i r s t of all we know t h a t i (1) If •ir.(W^,W) = 0 for a l l
i, t h e n
Yi^i^^,^ ^
Thus
M has an
i n v e r s e a s it r e p r e s e n t s a n i s o m o r p h i s m b e t w e e n two f r e e A - m o d u l e s . p a r t i c u l a r , M i s s q u a r e , p = q.
In
-248-
(2)
M i s not c o m p l e t e l y d e t e r m i n e d by t h e h a n d l e body d e c o m p o s i t i o n ;
t h e r e i s an e l e m e n t of c h o i c e in t h e o r i e n t a t i o n s of the of lift
—5>
.
^^ and in t h e c h o i c e
M is d e t e r m i n e d by t h e h a n d l e body d e c o m p o s i t i o n up to
left m u l t i p l i c a t i o n of a r o w o r r i g h t m u l t i p l i c a t i o n of a c o l u m n by e l e m e n t s i X where (3)
x € ir^^ . If
2 ^ r < n - 4 , t h e n by C o r o l l a r y 7 . 4 , W ^ S W.
M = 0
1 :
We a r e going to look at w a y s of a l t e r i n g a h a n d l e body d e c o m p o s i t i o n by a d d i n g c o m p l e m e n t a r y h a n d l e s and s l i d i n g h a n d l e s a r o u n d to get
M in t h i s
form.
over
§9.
W h i t e h e a d t o r s i o n of a h a n d l e body d e c o m p o s i t i o n
Let
R be a r i n g w i t h i d e n t i t y .
Let
GL^(R) = n X n i n v e r t i b l e m a t r i c e s
R and note
M € G L (R) n
GL (R) C GL , , ( R ) u n d e r t h e n a t u r a l i d e n t i f i c a t i o n n n+1 , , ( R ) . L e t GL(R) = l i m GL (R). T0M 1D e GL n+1 n w _
A m a t r i x M € GL(R)
1
is c a l l e d e l e m e n t a r y if it a g r e e s w i t h I =
_o e x c e p t for at m o s t one off d i a g o n a l e l e m e n t .
Let
E(R) C G L ( R )
• 1
be t h e s u b -
g r o u p g e n e r a t e d by e l e m e n t a r y m a t r i c e s . T h e o r e m of W h i t e h e a d : Thus
Kj^(R) = G L ( R ) / E ( R ) Consider
K^(R)
and let
E(R) = c o m m u t a t o r s u b g r o u p of
GL(R).
is an abelian group, usually written additively.
( -1) e G L ^ ( R ) C G L ( R ) . K ^(R) = K ^ ( R ) / [ - 1 ].
Let
0
1
[ - 1 ] be t h e i m a g e of ( - 1 )
in
|
-249-
If map
n is a group, write
n—>
We have a n a t u r a l
2 n ) , s i n c e e v e r y e l e m e n t of 11 h a s an i n v e r s e in 11 and
is h e n c e a unit in h: n
Zll
Zn)
and t h e r e f o r e a non s i n g u l a r GL( ^n) —»
W h i t e h e a d g r o u p of 11 = If
.111 = g r o u p r i n g of H.
7W)
1 X 1 matrix.
7X\).
We have
T h e n Wh(n) = the
rn)/hll.
M i s the m a t r i x a s s o c i a t e d with a h a n d l e body d e c o m p o s i t i o n a s
in §8 with W^ = W u r - h a n d l e s and T = [M] e Wh(n).
W^ = W^ u ( r + l ) h a n d l e s , l e t
T is c a l l e d the W h i t e h e a d t o r s i o n a s s o c i a t e d with the h a n d l e
body d e c o m p o s i t i o n .
The m a i n t h e o r e m of t h i s s e c t i o n e n a b l e s u s to c a n c e l
the h a n d l e s of t h i s p a r t i c u l a r d e c o m p o s i t i o n in c a s e w e l l d e t e r m i n e d by the h a n d l e body d e c o m p o s i t i o n . if we p e r m u t e the r o w s of a . = 1 and ij
M we do not c h a n g e
a , = 0 o t h e r w i s e , for ki
m e n t a r y given
a e Z 11.
Let
[M].
T = 0.
Write
E . . = [a ] with IJ K. X I + a E . . is eleij
-
+ E^.).
of t h i s p o s m u l t i p l i c a t i o n i s to add the f i r s t c o l u m n to the f r o m the f i r s t and add the new f i r s t c o l u m n to the
T is
In fact, f i r s t note that
i / j, and o b s e r v e
M' = M(1
Note that
The effect
s u b t r a c t the
Write
T-i M" = M' i
^ , 1
i
All t h e s e e x t r a f a c t o r s go to z e r o in K^
M" = M w i t h t h e f i r s t and
columns interchanged.
and we h a v e
A similar argument
u s i n g p r e m u l t i p l i c a t i o n s h o w s that we c a n i n t e r c h a n g e the r o w s of
M.
-250-
o alter
f
T.
i
a
w
c o m n a n
ed
F o r , w e m a y p e r m u t e c o l u m n s , p o s t m u l t i p l y by
and then p e r m u t e again.
T h e o r e m 9. 1. = TR^(W), as above.
Then
0 in Wh{n).
The m a t r i x
Let
W^ = W
h^ .
2 < r < n-4
and
T = 0 implies
W
...
r
(W^, W) (R+1) c o n n e c t e d .
r+1 Let
...
.k'+l.
T b e defined
S W, Cd
Proof.
T = 0 m e a n s that
M —> 0 u n d e r t h e m a p
G L ( z^n) > GL( z n ) Wh(n) n g e n e r a t e d by e l e m e n t a r y m a t r i c e s ,
M T h e n for s o m e
matrices
and
k e r o ( i s t h e s u b g r o u p of G L ( 2 n) n 1— n"~ and
where
E = finite p r o d u c t of e l e m e n t a r y
0 = EU
N, 0
where - 1, ,
I
N with
U =
F i r s t of a l l we c a n c h o o s e a n e w lift N p a i r s of c o m p l e m e n t a r y h
P
k, 1
r
and
to e l i m i n a t e
U.
Introduce
(r+1) h a n d l e s , a l l d i s j o i n t f r o m
r+1 k
P position r e p r e s e n t e d by the m a t r i x e^ = (I + a E y ) .
X e n.
.
T h i s gives a new handle body decomk E= n e^ w i t h e^ e l e m e n t a r y . Let
-251If we now h a v e I—I
W
= W
k
r+1
r+1
V+N
r^
and
T]. c h o s e n to give
one of t h e h a n d l e s W where
^ Vi
W^' - W •. h^
E , we a p p l y t h e h a n d l e a d d i t i o n t h e o r e m to s l i d e
o v e r t h e o t h e r s to get r+1 r+1 r+1 k ' k k'
^ W
9T).' = 9(ri. - a r ) . ) J J ^
r+1 V+N
k
(see 7,5).
The m a t r i x of the n e w h a n d l e b o d y d e c o m p o s i t i o n is the i^^ r o w s u b t r a c t e d f r o m t h e e. ,
m a t r i x is
r o w , i. e, , is
We r e p e a t t h i s p r o c e s s
i =2
E with
(I - a E . j E , iJ
a
times
So t h e n e w
u n i t l we get a n e w h a n d l e body
1 T h i s e n a b l e s u s to c a n c e l l a l l t h e
decomposition with m a t r i x 0 handles. §10. Let If F
n
Whitehead torsion. R be a r i n g w i t h i d e n t i t y .
= free module over
R with
n
We a l s o m a k e t h e following a s s u m p t i o n : generators, m ^
T h i s a s s u m p t i o n is c e r t a i n l y t r u e for g r o u p r i n g s make
11 operate,
R module.
Then
t r i v i a l l y on t h e r a t i o n a l s Q<S> F R
implies
F . m ' n Definition. Let
R =
m
^ F . n
F o r , we c a n
Q and r e g a r d
= v e c t o r s p a c e of d i m e n s i o n
F
Q as a right
n over
Q and so m
n
F
fo r s o m e
A
be a n R m o d u l e , A is s - f r e e if
A©F
n
is f r e e
n.
Lemma 10.1. s-free,
n implies
If
0 —5> A — > B —5> C — > 0
then A is s - f r e e .
i s e x a c t and
B,C
are
n
-252-
oof enough n , B © F
and
C © F^
is
n
n a r e free,
act
o
l e
so the s e q u e n c e s p l i t s and
n B©F
n
SA©(C©F
Definition. for s o m e
n.
n
), t h e r e f o r e
A
If A i s s - f r e e ,
iss-free.
an s - b a s i s for
A i s a b a s i s for
We w i l l u s e a s i n g l e l e t t e r u n d e r l i n e d for a b a s i s .
f r e e , and b = (b ^^. . . b ^ ) , where the
a r e b a s e s for
form an invertible m a t r i x .
ASF
b a s e s for define
m
, c i s a b a s i s for —
A©F
n
[ b/c] = [ ——
where
A, w r i t e
b^ = ^ ^
K.(R). ij 1 In g e n e r a l , if b i s a b a s i s
a r e s t a n d a r d b a s e s for
F
k-m
In p a r t i c u l a r ,
,F
k-n
,
+1 ] e K, (R). k-n i
T h i s e l e m e n t d o e s not d e p e n d o n t h e c h o i c e of k, and we w r i t e if [ b / £ ] = 0.
is
A © F , and b + f, , c + f, a r e free n — —k-m — —k-n
f, ,f, — k - m —k-n
'^-'k-m/c '—
If A
n
Write [ ^ c . ] =
ij We c a n do the s a m e t h i n g for s - f r e e b a s e s . for
A© F
if b i s o b t a i n e d f r o m
adding m u l t i p l e s of o n e e l e m e n t to a n o t h e r , t h e n
b ~ £
£ by p e r m u t a t i o n o r
b ~ £.
Note t h a t
[ a/b] + [V£] = [a/£]. Let
0 — > A —->B—£> C — > 0
be exact,
AB,C
s-free.
Then the
following s e q u e n c e i s a l s o e x a c t : 0 Let
A© F
» B © F m
a , c be c h o s e n a s b a s e s for
m m
© F
A©F
C © F
nn
m
n , C®F
n
0.
respectively,
a = (a . . . . a ) , c = (c .. . . c ). G i v e n i ^ s, s u p p o s e ^cl = c . . T h e n • — 1 r — 1 S ' ru' 1 1 ( \ a , . . .Xa , c ' . . . c ' ) is a b a s i s for B © F © F . C a l l t h i s s - b a s i s for I r i s ' m n Then
ac —
is defined up to a c h o i c e of t h e
cl .
If cl' 1 1
B
is a n o t h e r c h o i c e w i t h
ac —
-253-
uc" = c , then 1 1
cl' - c. e I m X and we c a n w r i t e down a m a t r i x c o m p a r i n g 1 1
t h e s e as follows:
^ Xa
1
where
Xa r
=
c" 1 1
r
M
M.
M i s of t h e f o r m
I
0 e q u i v a l e n c e c l a s s of
^
, so
[M] = 0 in K^(R).
Thus
the
s
is w e l l d e t e r m i n e d .
S u p p o s e now a , a ' choose related s - b a s e s
a r e s - b a s e s for
ac , a ' c '
for
B.
A,
£,£'
a r e s - b a s e s for
C
and
We would now l i k e to c o m p a r e
these s - b a s e s . Lemma 9.2. Proof. 0 —» A B =
[ ac/a'c' ] = [a/a'] + [c/c'].
Assume
^ > B
A,B,C
^ > C
free;
> 0, c h o o s e
are actual bases. a:
C —> B w i t h \ia = i,
We h a v e then
KA ® aC. We c a n s u p p o s e
ac = { X ^ , a c ) , M^
where
0
a'c' "M,
=
Then OI^I
0 with a = M^a' ,
M of of t h e f o r m 0
b = M^b'.
So in
M
0
IJLO
M J
K^(R), [M] = [M^] + [M^].
We w i l l now define t o r s i o n for a g e n e r a l c h a i n c o m p l e x o v e r 0 -—> C
—> C n
a£ = M a'c' ,
, —> • • • —> C n-1 o
R.
Suppose
> 0 i s a c h a i n c o m p l e x of f r e e R m o d u l e s .
-254-
Given
i, l e t
c. be a b a s i s for "1
C.. 1
If e i t h e r
(1) H ^ ( C ) = 0 (2)
let
H.(C) is s - f r e e for e a c h i w i t h g i v e n b a s i s h . , 1 I ^ 0 — B —-> Z. —5> H. —» 0 and 0 - Z - C B . - 0 1 1 1 i i i-1
exact sequences associated with and
Z.
C.
Now by i n d u c t i o n on
be t h e s h o r t i and 1 0 . 1 ,
B^
are s-free.
1
Choose s - b a s e s
b
for
B
— 1
b.h.
for
Z,
(b.h.)b. ,
b: i s a n o t h e r b a s i s for —1
and c h o o s e in t h e u s u a l m a n n e r s - b a s e s 1
for
C..
Define
^
(b.h.)b. , / c . ] .
B., [(b!h.)b: , / c . ] = [ ( b . ' h j b ! V ( b . h . ) b . , ] 1 _i..._i - 1 - 1 1 1 - 1 ..1 1
[(b.h.)b. ^ / c . ] = [ b ! / b . ] + [b^ ^ / b . s u m the t e r m s
T=
[bl^/b^] c a n c e l ,
+ [ ( b . h ^ ^ ^/c.]
+
and in t h e a l t e r n a t i n g
T is t h u s i n d e p e n d e n t of t h e c h o i c e of b ^
is c a l l e d t h e W h i t e h e a d t o r s i o n of t h e b a s e d c h a i n c o m p l e x L e t u s now c o n s i d e r the a c t u a l g e o m e t r i c s i t u a t i o n . p a i r of finite s i m p l i c i a l c o m p l e x e s w i t h If K
If
and
(C,£^). Let
K ^ C K be a
•Tr^(K^) = Tr^(K) by i n c l u s i o n .
- K is a h o m o t o p y e q u i v a l e n c e , l e t
K^ C K be t h e u n i v e r s a l
c o v e r , t h i s h a s a s t a n d a r d s i m p l i c i a l s t r u c t u r e g i v e n by t h a t on K^ :1 K. Consider ... Given
—$.C.(K,K^) a e K - K
w h i t h i n an a c t i o n of
o
, let
tt^ .
->C. cr be a lift of
/—I r^ C^(K, K^)
with g e n e r a t o r s of the f o r m
->••• o" to
•
K , er i s d e t e r m i n e d to
i s a finitely g e n e r a t e d f r e e
cr , d i m c r = i , c r e K - K
jn
module
. °
Since
^ K is a h o m o t o p y e q u i v a l e n c e , t h e c h a i n c o m p l e x a b o v e h a s
!
j s
no h o m o l o g y and
T(C) is defined in
ZLL) and d e p e n d s on the c h o i c e s of
!
-255the lifts {o- }
. A
different
cr
differs by an e l e m e n t of
T(K, K^) = [T] e Wh(n), t h e n i s w e l l d e t e r m i n e d . T(K, K ) e l e m e n t of Wh(n) o
.ill.
Let
We will show that t h i s
d o e s not d e p e n d on the t r i a n g u l a t i o n , i. e. , is
invariant under subdivision. M o r e g e n e r a l l y , if define
T(K,K^), now d e p e n d i n g on the c h o i c e of s - b a s e s
a n o t h e r s - b a s e of then
H.(K, K ) i s s - f r e e with s - b a s e s
H.(K,K^)
and [ b ' . / b . ] —> 0 u n d e r
T(K, K^) i s not c h a n g e d by r e p l a c i n g ^
by
b^.
b^ we c a n s t i l l If bl^ i s
K.(:.:n) —> Wh(n),
b\
S u p p o s e we h a v e a s e q u e n c e of i n c l u s i o n s of R m o d u l e s G —> G, ^ G , —> G , —> o 1 2 3 • we a t t a c h s y m b o l s a, b, c . . . to the a r r o w s -^G ->G o —> w h e r e a is an s - b a s i s for G ^ / G ^ , e t c . —> 1 b 2 c 3 In the s h o r t e x a c t s e q u e n c e 0 —>G, / G —> G / G Cy / G, 0 ^ o Z o 1 the s - b a s e s
a and b of
G^/G a
G^/G 2 o
.
We w r i t e
define
be ^ and finally
r i s e to an s - b a s e
b > G, —> G^ —>
.
a b for
By e x a c t l y the s a m e p r o c e s s , we
ab
[a(bc)V(ab)c J Proof. bases.
G
and
Let
a (be)
(ab)c ^ .
Then
a(bc)^ ~
(ab)c^ , i. e . ,
= 0.
We c a n a s s u m e a l l q u o t i e n t s f r e e and all s - b a s e s a r e a c t u a l ( x , . . . x ) be a b a s i s for ^ 1 r'
( x , . , . X ) for I s '
G^/G such that 2 o
L e t (x , , . . . X ) —3> c in G^/G_ . s+1 n' 3 2 a(bc) a n d
and
(ab)c.
GVG 1' o
which e x t e n d s to a b a s i s
(x , , . . . x ) —> b, the given b a s i s for G ^ / G , . r+1 s ^ 2' 1 Now
(x, . . . x ) is e q u i v a l e n t to both ' 1 n' ^
-256-
This p r o c e s s is therefore a s s o c i a t i v e . reasonable sense.
It i s a l s o c o m m u t a t i v e in a
S u p p o s e we h a v e a d i a g r a m of i n c l u s i o n s A + B
V /
/ A
w ith A, B, C C
say,
B•
A+B = {a+b | aeA.be
B}.
We h a v e t h e n a t u r a l 1
isomorphism A + B
A A ^ B Thus
A " B
a
5>A g i v e s
L e m m a 10. 2.
b
B
> A + B.
S i m i l a r l y for
b.
ba ~ ab in the d i a g r a m .A + B. B
ab I A a\
Proof.
ba
.-b
R e c a l l t h a t t h i s e q u i v a l e n c e is defined in K^(R), h e n c e e v e n and
odd p e r m u t a t i o n s of the b a s i s e l e m e n t s a r e a l l o w e d .
We h a v e got
A + B A B — © ^ , a n d going one w a y we get the b a s i s A ij A Xj A id way
(b,a).
We c a n t h u s c h o o s e
a b , ba
(a,b), the other
to be the s a m e b a s i s p e r m u t e d .
Now s u p p o s e we h a v e a s h o r t e x a c t s e q u e n c e of c h a i n g r o u p s (finitely generated free R-modules) 0 —> C ' Let
c.,cl 1 1
and
-> C
-> C "
-> 0 .
c!' b e g e n e r a t o r s for 1 ^
C.,C1 1 1
We a l s o want to s u p p o s e t h a t the h o m o l o g y g r o u p s
and
CI' 1
respectively. '
H^ = H^{C), HI^ = H . ( C ' )
-257-
a r e all stably free with given s - b a s e s
H!'= H.(C")
we r e g a r d length <
H' —> H —> H " — > H! , —> • • '
b^, bl^ and bV .
as a chain complex
; '
Here of
3n.
T h e o r e m 10. 3.
If
c. - c l c ! ' 1 11
for e a c h
T ( C ) = T ( C ' ) + T ( C - ' ) + r{1:
i, t h e n
).
T h i s i s t h e m a i n l e m m a u s e d to p r o v e c o m b i n a t o r i a l i n v a r i a n c e of torsion.
T h e f i r s t t h i n g we w i l l p r o v e i s t h a t t h e t o r s i o n d o e s n ' t c h a n g e if
the b a s i s for
H^ i s c h a n g e d . 0 — > 0
"We h a v e t h e s h o r t e x a c t s e q u e n c e s
XI — >
H: — >
1
1
> X.
-> H .
1
1
X"
XI = k e r (HI —> H ^ , e t c .
s-bases
T=
(-l)^[b.h.b. Vc.] 1 1 1-1 1
T(K) = Z
-> X ! '
0 > 0
-> X !
, —> 0
1 1-1 To f o r m t h e t o r s i o n we c h o o s e a r b i t r a r y
x . , h . , e t c . , and b . , b l , b ' l 1 1 1 1 1
B C C t h e b o u n d a r i e s in i i
X. — >
1
-> HI'
1 where
1
C , etc. 1
for
B.,BI 1 1
and
B'l r e s p e c t i v e l y w i t h 1
T h e n t h e g e n e r a l f o r m u l a for t o r s i o n
becomes
{[^'L^./H".]
T(C) - T(C') - T(C") =
( - l f { [ b . h . b . _ / c j - [b:h'.b>_^/CL] -
(1) N o t i c e t h a t c h a n g i n g b a s e s T(C) - T(C') - T(C")
SO l o n g a s
e x p r e s s i o n for
).
- [x.x'l/h.] + [ x l x / h l ] } ,
cl
or
c^ ~ '^i*^!'
cV d o e s not a l t e r '
' ^ i ' " ^ i ' a p p e a r
in t h e
-25 8 -
(2) C h o o s i n g a d i f f e r e n t b a s i s for t h e b y h. , a d d s to
T{)L) a f a c t o r
a+1,[ h . / h . ]
(-1)
[x.x'l/h.] = [x.xl'/h.] + [ h . / h . ] , and adds 1 1"' ' • 1 1 1 ' " 1 1 = (-1)' [b.h.b._^/b.h.b._J Thus changing b a s e s T(C) - T(C') -
H^'s , t h a t i s , r e p l a c i n g = (-1) [ h./h.]
h^
since
(-1)^ [ b . h . b . , / c . [ - [ b . h . b . , / c . ] ' • 1 1 1-1 1 1 1 1-1 1
= ( - L ) ' [ h . / h j to
T ( C ) - T(C>) -
h^, h^, h'^ a d d s e q u a l q u a n t i t i e s to
T(C").
r{%),
T(C").
So l o n g a s we c a n p r o v e
T(C) = T(C') + T(C") + T ( / { ) for o n e b a s i s ,
we w i l l h a v e s h o w n t h e e q u a l i t y for a l l b a s e s .
Choose
h . = x.x'l 1 11
c . = blh'.h! , 1 1 1 1-1
h! = x l x . 1 11
c ! ' = b'lh'lb': , 1 1 1 1-1
hi' = x'lxl 1 11 (This choice will make
T(C') = T(C") =
) = 0. )
We a r e now going to d r a w
a n e n o r m o u s d i a g r a m of s u b g r o u p s a n d q u o t i e n t g r o u p s of t h e
and
-259-
C O^B
Here
m e a n s t h e b a s i s r e p r e s e n t e d by
B is e q u i v a l e n t
A to t h e b a s i s r e p r e s e n t e d by
j . A
All t h e a r r o w s in t h e d i a g r a m r e p r e s e n t Q
inclusions: note that
CI , C C . 1-1
,<
C. .
1-1
C
-> C N o t e t h a t x € |j.
C
if and o n l y if t h e r e is a
if and o n l y if x - 9y e
, so
|JI
We a l s o h a v e t h e d i a g r a m
1
^
-$> C"
> 0
-5> C "
> 0
y e
B!^ = B. + C^ .
w i t h |J.9y = |J.x, i. e. , We t h u s get
-260Z. r (B. + C!) 1 1 1 B.
Z.r (1)
1
X. = k e r ( H . —> H-: ) =
1
B.
z:1 B; r z I 1 1
z: r B. (2)
x:
= k e r ( H ! —> H.) =
'
'
B.
B. + Z: 1 1 B.
»
c:
1
B'
1
(Z' i
(3)
B = C " B. i 1 1
X'^ = I m ( H . ^
Hp
s i n c e e v e r y t h i n g in B. is a c y c l e ) 1
=
B1 + c:1 '
Z. o ul'^BI' 1 1
(4)
B" i
=
B. = B. n
i+1
c:
B n 1
z! 1
F r o m (1), (2), (4) and L e m m a 10 . 2 we h a v e
(since ^
1
C.^^ —$> B. —^ 0). 1+1
1
-261-
n
,
an
m a
e
/
A 1-1 X'
i-l
c:1 + z.
1.
. i-l
c:1 + B.1 1-1 X
"Z'
r :
r 1
Z' + B
i
1
triangles commute.
h. 1
^ J x>.
We c a n c h o o s e
I
X
\
B
/
b = bl x l b ' l so t h a t a l l t h e r e m a i n i n g s q u a r e s and 1 1 1 1 So
c^ ~ ^ i ^ i ^ i 1
therefore
T(C) = 0.
We h a v e now
proved T(C)
=
T(C') + T(C") +
T(H).
Now s u p p o s e we h a v e a c o b o r d i s m and a d d on a w h o l e lot of h a n d l e s . We w i l l c o m p a r e t h e t o r s i o n of t h e r e s u l t i n g c o b o r d i s m w i t h t h a t of the original one. r L e m m a 10.4. Let
Suppose
K^C. K be a s i m p l i c i a l p a i r t r i a n g u l a t i n g K
W C W^,
be the c o r r e s p o n d i n g u n i v e r s a l c o v e r s .
= """^(K)
and l e t
K d o
a free
^IXi m o d u l e w i t h g i v e n g e n e r a t o r s in e a c h d i m e n s i o n . (1) E a c h c o m p o n e n t of
r . . . . „ h^ .
W i s a c o b o r d i s m , W^ = W ^ h^
(K
Now
is s i m p l y c o n n e c t e d ,
K
H
*
(K , K ) i s o
If and
o (2) E a c h g i v e n g e n e r a t o r of
is r e p r e s e n t a b l e b y a c h a i n in
-262-
one component of K - K^ , i. e. , a chain which is a combination of closed s i m p l e x e s w h o s e i n t e r i o r s a r e in one c o m p o n e n t of
K^,
T h e n T(K, K ) = 0. o Proof. I
Let
F . . . . F be the c o n n e c t e d c o m p o n e n t s of 1 r
be lifts of
r
r_,...F I r
.
If b , . . . b € H ^ ( K , K ) 1 S - + 0
K - K , let o
a r e the g i v e n
generators, let ^
€ C(K, K ) be c y c l e s r e p r e s e n t i n g t h e m , X s o is c o n t a i n e d in one c o m p o n e n t of K - K^ . Choose
( F . }.
The g e n e r a t o r s
J
free Z" IT b a s i s .
1 1
O
T since multi-
Choose free
C^(K, K^) a n d s t a b l y f r e e g e n e r a t o r s of
In fact,
all lying
T a r e done w i t h i n t e g e r
C.(K, K ) s C . ( K , K ) (g) 211 w h e r e the i s o m o r p h i s m 1 o 1 o 2
T(K, K^) 6 Im {
I )
So
->
H n)
^ Wh(n)} .
77 ) - 0, i. e . , e v e r y i n v e r t i b l e m a t r i x with i n t e g e r coefficients
is e q u i v a l e n t u n d e r e l e m e n t a r y o p e r a t i o n s to the i d e n t i t y m a t r i x let
Zn
{ F. }.
s e n d s g e n e r a t o r s onto g e n e r a t o r s .
But
JF
M o r e o v e r , t h i s b a s i s g i v e s r i s e to t h e s a m e
Now all o p e r a t i o n s done in c a l c u l a t i n g coefficients.
is
{x.b.} e H (K, K ) a r e a l s o a
p l i c a t i o n by x^ d o e s not a l t e r an e l e m e n t in Wh(n).
in one of the
^
X e tr^, r e g a r d e d a s a c o v e r i n g t r a n s f o r m a t i o n so that x^^
c o n t a i n e d in one of the
g e n e r a t o r s of
each
M be a n m X m m a t r i x with i n t e g e r coefficients.
I.
In fact,
F i r s t add r o w s until
the s m a l l e s t non z e r o eleme nt of the f i r s t c o l u m n d i v i d e s a l l the e l e m e n t s in the f i r s t c o l u m n ( t h i s u s e s the d i v i s i o n a l g o r i t h m i n d u c t i v e l y ) . the o t h e r e l e m e n t s in the f i r s t c o l u m n .
C a n c e l out
R e p e a t with the o t h e r c o l u m n s .
-263-
So
M = TE
matrices.
Now
m e n t s of of
T
with
T u p p e r t r i a n g u l a r and
M invertible implies
are
± 1.
Therefore,
W
2
= W ^ 1
1
...
^
generators H
Suppose k
of
f-N-/
(W ,
In K^, M i s t h e n e q u i v a l e n t to
W^ = W v.' h^
h . , h. n W) C
V-—S
pressing
d e t M = + 1, t h u s t h e d i a g o n a l e l e -
, r ^ 2 and
respectively.
a p r o d u c t of e l e m e n t a r y -
we can cancel the u p p e r right hand c o r n e r
T by e l e m e n t a r y r o w o p e r a t i o n s . C o r o l l a r y 10. 5.
E
I.
... _ h
•Tr.(W^, W) = 0, a l l W^, W),
i.
, k.
Choose W^)
Now t h e n , we know t h a t we h a v e a m a t r i x e x -
rsj
d, 9'Hj = > . m . . ,
Suppose that Then
W^
is t r i a n g u l a t e d with € Wh(TR^W).
T(W^,W) =
Proof.
as subcomplexes.
We l o o k a t t h e e x a c t s e q u e n c e of c h a i n c o m p l e x e s /N^
0 —> C(W^, W) —> 0 —» C
W) —>
> C
rs^ NO -> C"
0 > 0 .
By 1 0 . 3 a n d 10. 4, T(C) = T(C') + T(C") For
^
we h a v e
0
r-u ^ T) - a n d . J , > C ,, > r+1 '
with b a s e s 0
—5> Z r
0 —> 0
) = 0 + 0 + T( K ) .
• • • —> 0 —>
W^) —
^
> rsu < • for t h e two n o n z e r o t e r m s . . 1. C > 0 > ••• > 0 r
a n d s p l i t up t h e s e q u e n c e , 0 —5> B
+ T(
We w r i t e t h i s a s
obtaining exact sequences
- ^ 0 —> 0
r > Z ,, r+1
—> 0 -> ••• -> 0
0
> Z
—» C r
> 0
> 0
> 0 r
5> 0
-264and so 0 —^ Z , , —» C —3> B — 0 r+1 r+1 r
becomes
0 —> 0 —» C
, , —> B -S> 0. r+1 r I,
We c o m p a r e the n e w b a s e s w i t h t h e o r i g i n a l o n e to get
= (-l)VjJ. To c o m p l e t e t h e proof t h a t T h e o r e m 10. all
i and
aK
.
T i s i n v a r i a n t u n d e r s u b d i v i s i o n we h a v e
Let
K be s i m p l i c i a l c o m p l e x e s ,
a s u b d i v i s i o n of
K.
Then
= 0
T(AK, ORK ) = T(K,K ). o o rsj
Proof.
Let
L. = K vj i - s k e l e t o n of 1 o
K.
of K with t h e s t a n d a r d t r i a n g u l a t i o n , a n d l e t
Let
K be t h e u n i v e r s a l c o v e r
L ^ be t h e c o v e r of
L^ in
K.
We c o n s i d e r c h a i n c o m p l e x e s defined a s f o l l o w s : Let
C be t h e c h a i n c o m p l e x
, ^ ^ ->H. a L . , a L . 1
1
,
d
-> H.
1-1
1-1
y (aL.
H (aK , Let
C
r
-> • •
H [ah
J 11 m o d u l e .
By s t a n d a r d a r g u m e n t s
aKj.
be t h e c h a i n c o m p l e x r^
0 —^ H (FFL , A L J r r r-1 with
H (C^) = H
> H
A ah , , ah r-1 r-1 r-2^
the g e n e r a t o r s for 0"
rsj
H (o-L , aK ) —> 0 o o' o
(aL^.o-K^).
We s h a l l p r o v e i n d u c t i v e l y t h a t
lift of
,aK)—^Q
1-2
with e a c h t e r m a finitely g e n e r a t e d f r e e H (C)
, d
aL. 1-1
C
in K and let
T(C ) = T{aL
c h o s e n as follows:
Given
^^ be a g e n e r a t o r of
T h i s gives a s e t of f r e e g e n e r a t o r s for
, orK ) in
Wh('Tr)
cr^ e K - L^ ^ l e t , d{a cr )) C
ccL^
with be a orL^
-265-
We now p a s s f r o m
L
to r
0 r
, aK ) o
> C(aL r+1
The bases definition.
c,c',c"
So
= T{aL^,aKj
homology exact sequence
/I
0 —> H
-> H
, aK
r+1 r+1 F o r the sequence
)
C
./ C r+T r
(aL
r+l C , we h a v e -> C
c ~c'c"
+ T{ah
by the u s u a l
ah
+ T(
r+1
r^ ) -> H {ahrsj , aK r r o
,, , aL ) r+1 r
-> C
r+1
/C
r
0
C^) + T(
)
-> 0 .
-> 0 ,
i s z e r o e x c e p t for a g r o u p in d i m e n s i o n ( r + l )
= T( C^) + T( C^^^/
The
is
o
C but
, ^ and l o o k at t h e e x a c t s e q u e n c e r+1 ) > C(aL , aL ) -> 0 . o r+1 r
satisfy the condition
,
(ffL
L
where
and we h a v e
is the exact sequence
-> H
(C ) -> H ^ ( C ^ J C ) r+1^ r + 1 r+1 r+1 r By t h e i n d u c t i v e h y p o t h e s i s r{aLj , aK ) = T( C ).
H ( C ) —> 0 r r R e c a l l that
rsj
H ( C ) = H ( a L , ofK ) w h e r e t h e g e n e r a t o r s a r e c h o s e n to c o r r e s p o n d s u n d e r the n a t u r a l i s o m o r p h i s m . the chain c o m p l e x
Further,
0 —5>
H , .(C / C ) can be calculated from r+1 r + 1 r , a L ^ ) —> 0.
So /!_ ,
are isomorphic
b y a n i s o m o r p h i s m s e n d i n g g e n e r a t o r s to g e n e r a t o r s . Now s i n c e t h e c h a i n c o m p l e x T( C
C ) = 0.
0 —5> H . . (orL a h ) —5> 0 is t r i v i a l , r+1 r+1 r All we n e e d to p r o v e to s h o w the i n d u c t i v e s t e p is that rv
rsj
a L ^ ) = 0 u s i n g t h e g e n e r a t o r s a l r e a d y c h o s e n for r+1
r
t h e d i s j o i n t u n i o n of s i m p l y c o n n e c t e d s e t s .
r\J
, aL^), ah r+1
is r
-266S t a r t i n g the i n d u c t i o n w i t h TCC).
^
T(C>'K, o-K^) =
NOW
r+1
r+1 112 « C ,,(K,K ) r+1 o
-> where
we h a v e p r o v e d
a?
So
r
r
r C
a lift of a n (r+1) s i m p l e x of
r-1 112 or
(K,K
)
>
K - K^), i s a g e n e r a t o r of
C = C ( K , K ) by an i s o m o r p h i s m s e n d i n g t h e g e n e r a t o r s u i t a b l y .
Therefore
T( C ) = T(K, K^).
We i n t r o d u c e t h e n o t a t i o n
T(W) = T(W, 9 W). h
L e m m a 10. 7.
Let
W
W
h a simplidal homeomorphism. Then Proof .
be h - c o b o r d i s m s w i t h Let
W =
'
T(W) = T(W^) + T(W^).
We h a v e the e x a c t s e q u e n c e of c h a i n g r o u p s
—$> C(W^, 9 W^) —» C(W, 9 W^)
Now t h e h o m o l o g y e x a c t s e q u e n c e i s z e r o ,
5> C(W, W^)
so
T(W, 9 W) = T(W 9 W ) + T(W 9 W ). 1 - 1 z, - ^ L e m m a 10. 8. Proof.
9,W
Put
T(MXI,
M X 0 )
= 0.
W^ = W^ = M X I in 10. 7.
Then
T ( M X I) = T ( M X I) + T ( M X I).
> 0
S
9_W
-267-
Lemma 10.9.
If K
o
' K . ' . K_ a r e c o m p l e x e s , •Tr.(K K ) = 0 , 1 ^ 1 1 o
all
i and K \ K t h e n T(K , K ) = T(K K ). ^ J. ^ O i o Proof. Suppose K \ K by one e l e m e n t a r y p o l y h e d r a l c o l l a p s e , Lt X s a y , w i t h B O K^ a face F of B, and so K ^ - K ^ is a P L b a l l B
(K^-K^ , K ^ - K ^ n K^) ^ ( F X I , F X O). We h a v e t h e e x a c t s e q u e n c e 0 —>
K^ ) —>
K^) —> C(K^. K^) —> 0.
These complexes have zero homology, = Now
K^ - K^
+ rlK^.K^).
i s s i m p l y c o n n e c t e d so by L e m m a 1 0 . 4 ,
L e m m a 10. 10.
If
n > 6 , W^
W S 9 W XI Proof. if n > 6
and
handles with
so
Certainly
b y 10. 8,
is an h - c o b o r d i s m ,
if and o n l y if W ^ A W X I
then
T(W) = 0. implies
W i s an h - c o b o r d i s m , W S (8 W X I) 2 < r < n-4.
= 0.
T(W)
= 0.
By §§7,
r-handles U (r+l)
In §9, we s h o w e d how to c a n c e l t h e s e h a n d l e s if rs^
rsj
the m a t r i x r e p r e s e n t i n g the b o u n d a r y m a p
rsj
r>j
—^
from
t h e h o m o l o g y of t h e ( r + l ) h a n d l e s to t h e h o m o l o g y of the r - h a n d l e s w a s e q u i v a l e n t to
z e r o in Wh(Tr).
We h a v e now shown (lO. 5, 10.6 ) t h a t t h e
e q u i v a l e n c e c l a s s of t h i s m a t r i x i s L e m m a 10. 11.
T(W, 9 W).
If n > 6 , w "
if and only if t h e r e i s a P L s p a c e
i s an h - c o b o r d i s m , t h e n W ^ 8_W X I
X with
WCX,
X\W
and X \ 9 W.
-268-
Proof. then
W S a_WX I i m p l i e s
w\a_w.
If
W C X \W,
X\d_W,
T(W, d_W) = T(X, a_W) = T(9_W, d_W) = 0 by 10. 9, a n d so
W ^ 3_W X I by 10. 10.
§11.
How m a n y h a n d l e s do w e n e e d in t h e c a s e of a n h - c o b o r d i s m
with non zero t o r s i o n ? Theorem 11.1. 2 < r < n-4, let
Let
W
j : GL ( /tt^CW))
r-handles C P {r+l)-handles Proof. Let
h., K
be a n h - c o b o r d i s m , n > 6.
We k n o w
if a n d o n l y if
W ^ (9 W X I) -
be lifts of h^, k^ ; l e t
H , , ( kRO. , krsj. r+l J J
rsj
W.) 1
-> Wh(Tr^(W)).
plies
h.^u . . . ^ h i q
T(W) E I m
K. ^J
, we know
T € Im i
t h e r e is an
h. , h . ^ 9 W X I),
W^) —5>
[X..] = T(W) e Wh(Tr). ^J
Thus
9 WXI) q < p
M e GL
0
U r
s u c h t h a t for s o m e
N,
P
0 EU
m a t r i c e s and
p
r+l
.
M N-qJ
r+l k,^ 1
h^ ,
^P
Lo
W S 8_WX I ,
respectively,
rsj V—v 9 rj. = J
Now if
r,
T(W) € I m J^.
Tj^ g e n r a t e
With W^ = (9 W X I) L h j J . . . given by
Then
Given
where
E
i s a p r o d u c t of e l e m e n t a r y
I, N-p-i i-1
with
X. 6 n. 1
im-
-269We f i r s t a d d
N-q
c o m p l e m e n t a r y p a i r s of rsu
r, (r+l) handles.
By
rsu
a l t e r i n g t h e c h o i c e of the g e n e r a t o r s
"n. we c a n get t h e m a t r i x r e p r e ^ ^ fM 0 ^ E . Sliding s e n t i n g t h e n e w h a n d l e b o d y d e c o m p o s i t i o n e q u a l to 0 I n-p
t h e ( r + l ) h a n d l e s o v e r e a c h o t h e r a c c o r d i n g to t h e h a n d l e a d d i t i o n t h e o r e m we c a n find a n e w h a n d l e b o d y d e c o m p o s i t i o n of
So of the l a s t
N-q
one point.
LO
^N-p
W with m a t r i x
( r + l ) h a n d l e s cut the b - s p h e r e s of t h e l a s t
Im
j1,=
S u p p o s e now t h a t
0 and
r-handles
( r + l ) - and =
Wh(n).
^
3 ^ r ^ n - 3 , and
i = r. rsj H (W, 9 ^V) we c a n define
9 W) a d d s a n e l e m e n t of
T(W) « W h ( n ) / l m
H.(W, a_W) = 0 for
i / r
and
m o d u l e if
G i v e n a f r e e b a s i s for rs^ rsu
Theorem 11.2.
r-handles.
W i s a c o b o r d i s m , Tr^(W) = -rr^(a_W) = rsj RO
p as a Z n
f r e e b a s i s of
N-p
I J I m pj P
by t h e n a t u r a l i n c l u s i o n s , f r e e of r a n k
N-q
T h u s we c a n a r r a n g e t h a t t h e y i n t e r s e c t t r a n s v e r s e l y in
So we c a n c a n c e l the l a s t
Note that
Thus
0
W ^ (a W X I) u N r - h a n d l e s ^-'N ( r + l ) J i a n d l e s and t h e a - s p h e r e s
algebraically once.
define
'M
Im
to
T(W).
Altering this
T(W) .
So we c a n
.
W S (9 W X I) u p r - h a n d l e s
if and o n l y if T = 0.
T i s an o b s t r u c t i o n w h o s e v a n i s h i n g i m p l i e s w e c a n e l i m i n a t e a l l but
the r - h a n d l e s . W
P r o o f . We know W S r(9_W X I) +l = 9 W X I, W, = W u. h, ... o ' "1 "o'
(, r - rl )- l h a n d l e s w r - h a n d l e s . h and
Let
-270k U C h o o s e g e n e r a t o r s for in Wh(n).
Then
T(W
W
(w ^ w). Ci S
) = T(W
Z O the homology exact s e q u e n c e
W
i
W^), so T is defined
)+T(W
O
W
u
where
) + T ( ; 0
^
is
V
0 —> H^lW^, w^) — > H^lW^. w^) — > Let l . r i
be b a s e s for
H^
^r^^Z'^l^
lifting t h e h a n d l e s in the u s u a l w a y .
Then
r e s p e c t i v e l y , c h o s e n by
T (W^ , W^) =
W^) = 0, by
L e m m a 10.4. Let b a c k into
h be c h o s e n a b a s i s for H (W,,, W ), a lift of t h e b a s i s | r Z o H ( W ^ , W , ) . If h ' = ih, ( h ' , ! ' ) f o r m a b a s i s for H ( W . , W j . r Z 1 X L \. I—t
Write
r| = M ( h ' ,
a n d [M] = ± T
in
where
Wh(n).
M is an invertible
Now w r i t e
= J
where a
B is a t X s m a t r i x o v e r
tX p
, i. e. ,
=
i Since
t > s,
M = (A, B) with A
matrix.
Now M
'211.
t X t matrix over
'^
0
) ^ "M'
jp
^^
where _0
N,
0
= EU 0
o n l y if for s o m e M'
is
N-p
oi e l e m e n t a r y m a t r i c e s a n d
p X p,
E
is t h e p r o d u c t
o'
U =
X. 6 TT, . 1 1
So
0 M
M'
0
0 by t h e e l e m e n t a r y r o w
c a n be c o n v e r t e d to n-t -
0
L N-p ^
11
-271-
operations:
(l) permuting rows , (Z) m u l t i p l y i n g a r o w b y
+ x w i t h x € TT^^ ,
(3) adding one r o w to a n o t h e r . Notice that
B i s given by t h e l a s t c o l u m n s of
confuse the c o l u m n s . ~M
T h u s , b y e l e m e n t a r y row o p e r a t i o n s 'A
0
B
0
'
0
I n-t^
" M'
0
0
I
5>
=
0
M, and row o p e r a t i o n s do not
0
I
I-
n-t-
n-p
p columns 0
0
"B
.
c a n be c o n v e r t e d to
and so 0
I
Lr
Recall
n-p-
9 r| = B ^ .
Add in N - t
p a i r s of c o m p l e m e n t a r y ( r - 1 ) "B
r-handles,
0 Now e a c h r o w o p e r a t i o n
so B w i l l be r e p l a c e d by 0 B
N-t
0 can be effected by a l t e r i n g t h e c h o i c e of
of type (1) o r (2) on 0 generators
and
I N-t
T) , e i t h e r by p e r m u t i n g , a l t e r i n g sign o r t r a n s l a t i n g by a c o v e r -
ing t r a n s f o r m a t i o n .
T y p e (3) r o w o p e r a t i o n s a r e effected by a l t e r i n g t h e
h a n d l e body d e c o m p o s i t i o n by h a n d l e a d d i t i o n . So we get W S W' ^
with
W = W 1
h O
r-1
J.
r-1 ; h^, N-p
'
and
rs^ r»j
W^ = W ^ U kj^ ' u • • • u k ^ ' where -> (W^ ' , W^) is 0 T h e n w e m a y c a n c e l t h e l a s t (N-p) r - h a n d l e s r e p r e s e n t e d by ^ N-pJ with t h e ( r - 1 ) h a n d l e s .
-272This proves the first part o£ the t h e o r e m .
The converse follows
from a previous argument. We now look at d u a l i t y .
If we h a v e a c o b o r d i s m and t u r n it o v e r ,
what effect is t h e r e on the t o r s i o n ? Suppose
W
W2 = W^ that
o
= a WX I, W = W ^ h,^ ^ . . . ^ h ^ and 1 o 1 p r+l is a n h - c o b o r d i s m W. S u p p o s e to s t a r t ... o
W is o r i e n t a b l e . r\j
nsj
To g e t the t o r s i o n w e c h o o s e g e n e r a t o r s W^) where
a
^q^'
r e s p e c t i v e l y and l o o k at t h e b o u n d a r y m a p
= a l g e b r a i c i n t e r s e c t i o n of X
ii^ of
^
xS^ = b - s p h e r e of xh^
S.
w i t h xS.
J
1
.
^ "Hj ~ X
.
S . = a - s p h e r e of J
^
(1'7).
( F I G U R E 17 WITH ACCOMPANYING T E X T IS ON N E X T P A G E )
k., J
-273(17) If we t u r n the whole p i c t u r e a r o u n d , the a - s p h e r e s rr{ X
L,-' /
2'Xb O
b e c o m e b - s p h e r e s and the b - s p h e r e s b e c o m e a-spheres.
So the t o r s i o n is given by a m a t r i x
v . , X'. = ij ij
> a' X , w h e r e a ' = a l g e b r i a c i n t e r X ' X ^ xeiT^ ~b ~ a s e c t i o n of S. with xS. = a l g e b r a i c i n t e r s e c t i o n of 1 J
X
S. 1 So
s
with b. . J T(W,
= (-L)"""^
Wh(n) —> Wh(n)
sends
j u g a t e , with c o n j u g a t i o n in X —> X
(\=1 +X- X )
W)
,
where
M into i t s t r a n s p o s e c o n 11 i n d u c e d by s e n d i n g
^ i n d u c e s an a n t i h o m o m o r p h i s m
G L ( Z'll) —> GL (2''n) and so i n d u c e s a h o m o m o r p h i s m n n Wh(n) > Wh(n), s i n c e Wh(n) is a b e l i a n . In the non o r i e n t a b l e c a s e we define a:
—>
11
-1
^ I•
by X—> X
if X i s o r i e n t a t i o n p r e s e r v i n g and
X —5> -X ^ if X is o r i e n t a t i o n r e v e r s i n g . duces a map T(W,
j^': Wh(ll)
= (-l)"""^
This in-
> Wh(n) and we get
T(W, 9 W).
-274-
c o o i
wih
Theorem 12.1.
If
i n t o n
M i s a connpact c o n n e c t e d P L naanifold of
d i m e n s i o n > 5, given a n y e l e m e n t W with
T E Wh(-TR^(M)), t h e r e i s a n h - c o b o r d i s m
9 W S M and T(W) = T.
Theorem 12.2. 8 W^ ^ A W^
and
If
W ,W
a r e h - c o b o r d i s m s of d i m e n s i o n
T(WP = T(W^) t h e n
Proof that 12.1 i m p l i e s 1 2 . 2 . T(W) = -T(W^). and
W^ S W^ .
Choose
9 W
So f o r m
W
W^) = 0.
U
X I) ..
So
W L
^9
"'2
W X I.
9_W =
and
So W U W^ ^ 9_W^ X I
= W u W CW
!
w
T(W
W with
T h e n by 1 0 . 7 , T{ W U W ^ ) = 0.
9 W S 9 W ^
^ 6,
^2
I
So W^ S W^ 0
X I) S
W^ S
w ^^ w
In o r d e r to p r o v e T h e o r e m 12. 1 we f i r s t n e e d a l e m m a : L e m m a 12. 3.
If
M"^ is a P L m a n if old, l e t
be d i s j o i n t P L e m b e d d i n g s r e p r e s e n t i n g e l e m e n t s t h e r e is a P L e m b e d d i n g to
^ + Tj
k: S^ X b"^
i, j : S ^ X r; e
—5> M If " e 'n'j^(M),
> M representing the element
e TT M. Ct
Proof .
Let
x e S^, y e a B ^ ^ " ^ , l e t
i(x, y) to j ( x , y) not m e e t i n g d e r i v e d n e i g h b o r h o o d of
P
I m (i) o r
P
be a P L p a t h in
Im(j) again.
in c l [ M - I m i - I m j ] .
Let
M from
N be a s e c o n d
II -2 75-
T h e c h o i c e of the path
P
w i l l d e t e r m i n e the e l e m e n t
oj.
By the
u n i q u e n e s s of r e g u l a r n e i g h b o r h o o d s we m a y a s s u m e that i
= j ^N=UXV,
where
U is a r e g u l a r n e i g h b o r h o o d of x in
and V i s a r e g u l a r n e i g h b o r h o o d of U X V: U X V
> aN ,
y in
9B™
S^
Now t h e e m b e d d i n g s
j I U X V: U X V —?> 8N a r e a m b i e n t i s o t o p i c to
" s t a n d a r d " o n e s , s i n c e a n y two o r i e n t a t i o n p r e s e r v i n g e m b e d d i n g s of a P L b a l l in a c o n n e c t e d m a n i f o l d of t h e s a m e d i m e n s i o n a r e i s o t o p i c . is a P L h o m e o m o r p h i s m
h: N —5> U X V X I w i t h
h j j U X V: U X V —» U X V X I s i d e r b"^ ^ as V = V
1
X V , where Z
V
i
0 in
fftlm
such that
l i e s in
R^,
y lying in
i s a r e g u l a r n e i g h b o r h o o d of
a r e g u l a r n e i g h b o r h o o d of i ^ Im j o N R " ^
hi|UXV:UXV—>
e q u a l to t h e n a t u r a l i d e n t i f i c a t i o n s .
B^ X b " ^ ^, w i t h the point
B^
So t h e r e UXVXO,
Now c o n -
9B^ X 0, and t a k e y in
9B\
and
V
^
T h e n t h e r e is a P L e m b e d d i n g a[i(S^ X B^ ) ^^
X B^ ) . h"^ (U X V^ X I)]
is
-276-
f
i
a
a
2 = i(S^X 0) - Y^ u where
ih
ini
X Oy) U
Oy d e n o t e s t h e s e g m e n t of
duct n e i g h b o r h o o d in M.
2
R^
B'
I) from
a n d so in R"^, so
will r e p r e s e n t
0 to
S
y.
Then
has a pro-
has a product neighborhood
Given
A e GL ( ^ i r ^ ) f o r s o m e ^ be f o r m e d by t a k i n g ( M X
M a n d X e Wh(-n-^(M)).
by a m a t r i x
p. P
Let
T. 1 ^ ( M X I).
h, , . . . , h , w h e r e 1 p
X Oy) o j S^ X 0 - VJ
^ + T)" p r o v i d e d we c h o o s e a s u i t a b l e p a t h
Proof.of T h e o r e m 1 2 . 1 .
W
le
h. connects 1
T . to 1
Let
P.
Represent
T
T . ^ S® X B ' ^ ' ^ f o r i = 1 , 2 , . . . ^ and a t t a c h i n g p 1 - h a n d l e s ,
—
Now in T. S S^ X b"^ X . 6 9B ij
.
c h o o s e a s e t of d i s j o i n t s p h e r e s
= S^ X
,
We m a y a s s u m e t h a t t h e s e do n o t i n t e r s e c t t h e h a n d l e s h, , ... , h . 1 P
T h e s e a l l h a v e p r o d u c t n e i g h b o r h o o d s in Now l e t
M b e t h e u n i v e r s a l c o v e r of
ing c o v e r i n g s p a c e of
. M and let
W be t h e c o r r e s p o n d -
W. Now every element of H^CW^M x C) can be repre-
-277-
ent
-
the s p h e r e s
i
S..
e
i n
h
in a c c o r d a n c e with L e m m a 1 2 . 3 .
Let
IJ
generate
H2(T.), w h e r e
^^ j=l
a..
^
generate 1
If t h e m a t r i x a . : S^ X B ^
a ini
5>
T. is a lift of
T.
in
of H (T.), Z
A = ( a . . ) , we c a n find, a s a b o v e , d i s j o i n t P L e m b e d d i n g s i = 1, 2, . . . , p, r e p r e s e n t i n g t h e h o m o l o g y c l a s s e s
A t t a c h i n g 2 - h a n d l e s by t h e s e m a p s g i v e s r i s e to t h e r e q u i r e d ^
h-cobordism
1
W.
W with t o r s i o n
T.
278
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mathematics lecture note
series
LECTURES ON FORMS IN MANY VARIABLES Marvin J. Greenberg / University of California, Santa Cruz The author surveys the many different coefficient fields for which a homogeneous polynomial in many variables has a nontrivial zero. He gives a complete treatment of the elementary part of the theorem and includes discussions, without proofs, of the more advanced results.
ALGEBRAIC K-THEORY , Hyman Bass / Columbia University This book represents thefirst attempt to give a systematic and comprehensive treatment of algebraic K-theory. Many of the results and points of view are published here for thefirst time.
PERSPECTIVES IN NONLINEARITY An Introduction to Nonlinear Analysis Melvyn S. Berger and Marion S. Berger / University of Minnesota The authors introduce important mathematical ideas without a surplus of new concepts and cumbersome notations. The work presents the qualitative approach to nonlinear problems in—and applications to mathematical analysis.
INDUCED REPRESENTATIONS OF GROUPS AND QUANTUM MECHANICS George W. Mackey / Harvard University This book is an expanded version of lecture notes delivered before a group of mathematicians and physicists at the Scuola Normale, Pisa, in April 1967. The author explains some of the principal features of the theory of induced representations and how they apply to quantum mechanics.
w. a. benjamin, inc.
new york M A T H 4551