EXCHANGE
ELECTROMAGNETIC OSCILLATIONS FROM A
BENT ANTENNA
ROBERT CAMERON COLWELL
/
ELECTROMAGNETIC OSCILLATIONS
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EXCHANGE
ELECTROMAGNETIC OSCILLATIONS FROM A
BENT ANTENNA
ROBERT CAMERON COLWELL
/
ELECTROMAGNETIC OSCILLATIONS
FEOM A BENT ANTENNA
A DISSERTATION PRESENTED TO THE
FACULTY OF PRINCETON UNIVERSITY IN CANDIDACY FOR THE DEGREE OF DOCTOR OF PHILOSOPHY
BY
ROBERT CAMERON COLWELL
PRESS OF THE NEW ERA PRINTING COMPANY LANCASTER. HA.
1920
Accepted by the Department Physics, February, 1918
! '.
'.;',
f
,'r
' t
;
-',
of
ELECTROMAGNETIC OSCILLATIONS FROM A BENT
ANTENNA The purpose
of this investigation
is
to find the mathematical
equations for the electromagnetic oscillations tenna, which
used
is
is
known
that of Pocklington
Abraham2 and
from a bent an-
to send out directed waves.
particularly
1
The method
which has been developed by M.
by G. W.
Peirce 3
who has
recently
published a remarkable research on the radiation resistance of a flat top antenna. This article is based upon the work of Peirce
and Abraham, but the equations are worked out for the fundamental and not for the forced vibration. The application of the formula
is
new.
The following assumptions are made: 1. That any antenna may be considered to be made up of a large number of Hertzian doublets placed end to end. 2. That the earth is a perfectly conducting plane. 3. That the waves propagated high into the air eventually return to the earth. The reason for this assumption will be shown in the section dealing with the horizontal part of the antenna.
Let a part
d,
top antenna have a vertical part h and a horizontal It will be necessary to discuss the effect of the Fig. 1. flat
EARTH'S SURFACE
FIG. 1
radiation from this antenna in three parts. I. The radiation due to the vertical part h and
its
image
h.
Pocklington H. C., Camb. Phil. Soc. Proc., 1898, p. 325. 2 Abraham, Theorie der Electrizitat, Vol. II. 3 G. W. Peirce, "Radiation Characteristics of an Antenna," Proc. Am. Acad. Arts and Sciences, Vol. 52, No. 4, October, 1916. 1
3
ELECTROMAGNETIC OSCILLATIONS d. The 'radiation from the horizontal part d and its image and horizontal The mutual action between the vertical parts.
II.
III.
I.
RADIATION FROM THE VERTICAL PART
Let the point where the vertical part enters the ground be the origin of co-ordinates, and choose the axes as shown in Fig. 2
FIG. 2
where the x axis
which the free antenna points and the vertical antenna coincides with the direction OZ. The azimuth and co-latitude
end
is
parallel to the direction in
of the horizontal
angles have their usual designations. Let P be any point in space whose polar co-ordinates are r, , 6, where r is very great
compared to the height h of the vertical part of the antenna. P lies at a distance r from the point P which is the position of r
one of the Hertzian doublets postulated in the first assumption. The effect of the doublet at P f on the point P is given by the 1 theory of Hertz
CD where f(t)
V=
=
the
moment
velocity of light.
E
is
PP
f
and and H in and 6', as is
of the doublet edz, r
length
expressed in electrostatic
electromagnetic units; r Q and 6 appear in place of r legitimate because of the great magnitude of r in comparison
with OP. If
the total length of the antenna
a node of current at 1
+
/
and
/.
is
/
=
h
+
d there must be
For the fundamental vibra-
Hertz, Electric waves, Chap. IX, Trans. D. E. Jones; Bateman, Elec-
trical
and Optical Wave Motion,
p. 8.
FROM A BENT ANTENNA tion, the current i at
mum
current
any time expressed
in
5
terms of I the maxi-
must be i
=
I sin pt cos -r
(2)
A
where X
=
the
wave length p
= 2x7. r is A
of the system,
the angular velocity
No w
and the current doublet, that
i is
the rate of change of the charge
e
on any
is
=
l
de
di
dt'
Tt
=
d2 e
df
Therefore d>e
2x71
di
2x7*
^ = ^ = -r~ ^r cos
Substituting (3) in (1)
dE
a
which -r A
in
=
p/sinfl
tyi is
we
get
cos
p (t
/
--r
2x2 cos
(3)
ir
zcos0\ -
y
1
2xz
,
cos -r- dz
given the shorter form p, and
(4)
z cos 6 is
r
written for r as these are approximately equal. z and this doublet The doublet1 at OP f has an image at will
have an
effect at
pi sin dEi = p
The
effect
adding
(4)
P
given by the equation
6
cos
( p [t
--r + z cos 6 -
y
\
Icos
2x2 -y-
dz
(5)
due to the two doublets on the point P is found by and (5), and the action of all the doublets and their
Theory of Images: Jeans, Electricity and Magnetism, Chapter VIII; Maxwell, Electricity and Magnetism, Chapter XI; Webster, Electricity and Magnetism, p. 303. 1
ELECTROMAGNETIC OSCILLATIONS
6
images,
by
integrating from
ind C h
to
Then
h.
2irz[ -
\
r
(
\
pz cos 6
,
-y~ &
The terms
in the square brackets are of the
cose
form [Cos
(x
+ y)
y)] may be simplified by use of a well-known trigonometrical formula: then
cos (x
/
2plsm8
r
Ch
\
2vz cos-r-ds
pzcosd
,
~^^y The
integral in (7)
a standard form and
is
is
found
any table
in
Integrating and putting in the limits
of integrals.
(7)
we
get for
the integral of (7) in
fph cos0
2Trh\
y
I
r
sm
1
( I
2Trh\ r-
,
ph cos
H
I
This reduces to sin
-^- (cos
sin
1)
~ (cos 0-1) Adding these fractions we get X
J
^rx 2 sm 0[ i
_\
cos (2
\X
)
(cos
vA (cos 0+1)
A
2?r
-^
sm ^v-.
\
/27T/J
27T/1
X
/
term
for the integrated
sln
"T~ cos
\X
I
)
/
27T/1
cos "T~ cos
X
Substituting in (7)
27
Vhmt".
X
v
I
Equation
(8)
is
cos
Iy
cos
sin
(
\
~~ cos
)
V X
^^:
.
s
/ i
cos z__-
L
(8)
the basis for the following brief discussion Poynting's Vector Theorem states that
of a vertical antenna.
FROM A BENT ANTENNA
7
the power radiated along the radius at any point of a sphere is V/4:Tr(E H) per unit area. In the case of the vertical E = H.
X
The energy radiated
is
equal to 4&.
is
length cos2 2ir/\(Vt
E The wave The average value of
directly proportional to
27/Fr
is
constant.
.
Therefore the expression for the power radiated at an angle 6 takes the simple form TQ) is |.
P.
(COS (fcosfl) '
= K
(9)
sin 6
The is
angle at which the greatest
amount
of energy
is
radiated
given by cos
7p "
n
fir I
\ cos 6
\
T7
dS
\
/
sin B
sin
^^
(
cos
^ /2 )
2
(
^ cos
8 } cos
\_?
sm
L
cos
sin 6
=
)
.
6
]
ir/2 makes d P ldd negative, and therefore the direction of maximum radiation of energy. represents Therefore a vertical antenna sends out its maximum energy
The
solution B
2
2
K
along the horizontal.
Table 1 is developed from (9), being given an arbitrary value. Diagram A is a graph of Table I, showing the approximate energy distribution. The distribution is such that nearly all the radiation lies within the 30 angle with the horizon. These equations (8) and (9) throw some The radius of action is light on the action of tall antennas.
of energy
increased as the antenna height is increased for two reasons. First, because the lengthening of the antenna automatically increased the wave length and the earth is a better conductor for
long waves than for short ones. Secondly, because the waves from a high antenna are not brought to earth so quickly (see assumption three) as those from a short one. Just as soon, however, as the wave length is reached for which the earth is a perfect conductor, no further effected
by
improvement
increasing the wave.
in
conduction
Similarly there
is
is
a limit to
ELECTROMAGNETIC OSCILLATIONS
8
the second action, so that there is no reason for increasing the height of the sending antenna indefinitely.
TABLE
I
V
Angle
0.00
*$ 0.00
15
.078
30 45 60 75 90
.144
.42
.422
.65
.672
.82
.902 1.00
II.
.22
.95 1.00
THE HORIZONTAL PART
In order to apply Hertz's theory to the horizontal antenna, necessary to measure the co-latitude from the axis X. The
it is
The designated by \[/ and the azimuth by % where the the vertical at antenna enters point origin remains the earth, Fig. 3. It should be noticed here that the action of co-latitude
is
FIG. 3
the horizontal part is dependent upon the length of the vertical for the latter determines the phase of the current at any point
Neither in theory nor in practice can the action of the horizontal be dissociated from the vertical. The positions in the former.
of the doublets
and doublet images are denoted
in Fig. 4.
The
small letters x, y, z (or x, o, h) refer to the doublets, while the position of the point in space P is given by large X, Y, Z.
FKOM A BENT ANTENNA Hertz's theory may now be applied to the effect at doublets at Q and Q'. Then
P
of the
(10)
Now
n= V(X At
(ID 2
z)
+ p+
(Z
+
(12)
great distances (13)
FIG. 4
From
(11), (12), (13)
-
2Zh (14)
2r
-
2Xx (15)
2r
As before
in (3)
2irV -
_
/ cos
27T. rr -^-
Vt
\
2ir
.
(16)
Also,
w(* fit \
r2
^ T7I= V )
pi
COS p I(^t
\
27T
cos
-
M 57
I
V J
cos
ELECTROMAGNETIC OSCILLATIONS
10
2ro
&-j- (i+*)
j
(17)
Substituting (16) and (17) in (10), simplifying by the trigonometrical formula for the sum of two cosines; neglecting a;2 h2
+
in
comparison with 2Xx, we obtain the expression
Jrt
dEj,
47r7 sin
T7 = = dHy ,
A7*o
-
integration of (18)
2irZh
sin ~T
VA
Vt
The
.
\//
T^T TQ
+ x cos ^}
r
is
(h
cosy
+ x)dx 1
very similar to that of
(18)
and gives
(7)
finally
E* =
21 TZ r<>V
.
2wZh [ 2ir sm-r sm-r- (Vt A .
7
sm ^
cos
Xro
X
f
r
s ) i
cos-^-
|_
cos
-T
(
2nd X
f
.
cos
j
\l/
}
H-
^ sm
cos
-r-
2^
)
/2^
sm
-T-
r
(Vt
I
-r
\11 cos
^
(19)
1
equations (8) and (19) are based all the conclusions regarda bent antenna. The total flux of force is obtained by coming pounding EQ of (8) with the E^ of (19) in such a way as to get
Upon
the complete electric intensity E, and the corresponding magnetic intensity H. Although the doublets which give rise to E e are perpendicular to those producing E$,
it
by no means
follows that
E e are at right angles; in fact, they make an angle (a) with one another which varies for every point on the particular sphere under consideration. Professor Peirce, of Harvard UniE# and
versity, has
shown that
this difference in direction gives rise to
a third term in the power radiation of the form (8) and (19)
from
{
the other two
come
of course
}
2 cos
aE & E&,
The average value
where
cos
a.
=
sin 1
1
of this term,
when
\{/
cos 8 cos
r-^-r 2 8 sm
multiplied
<j>
x
cos 2
by
4>
F/47T,
he
FROM A BENT ANTENNA calls the
In the problem under discussion
mutual power.
2K cos sin
4?r
cos
sin
0(1
2
4>
.
sm ""
2irhZ J
L
cos
\r Q
)
sin
where
--- cos
2irh 2wh cos ^: T cos
X
A
A
for convenience
11
K
is
2irh
-r-
A
.
sm
2 put equal to 7 /7rFr
-
ir2h cos
2 .
true only for the average value of (V/2ir) cos the term
-T-
A
(Vt
r
)
=
\ and sin
A
(Vt
r
(9
/rtm (20)
.
r-
f
A
This equation
aE e E^
cos r- (Vt
)
sin
cos
(
is
cos2
cos
[
so that
r
A
)
=
SECOND PART NUMERICAL CALCULATION The power
radiated per unit area in certain zones at distances
and 9,000 meters above the earth's surface, and at a distance 10,000 meters from the origin will now be calculated by means of equations (8), (19) and (20). In these equations = 440. Then let h = 10 meters, d = 100 meters, X = 4(& d) the power radiated from the vertical part may be expressed by (8) in the form 2,000, 6,000
+
:
V E? 47T
= K jcosf
-r-
COS0J 10,000
sin-r-
cos
sin
(
~- cos
0)
cos
~^-
M. jwoo
jr.
"^6000
M.,
ASOOOM.
FIG. 5
The
values in Table II are calculated from this equation:
12
ELECTROMAGNETIC OSCILLATIONS TABLE
VERTICAL
II
Height
X h r
= 440M = 10M = 10000M
9000M 6000M
.0049K .0160
5000 2000
.0164 .0196 .0196
The calculations of E 9 (V/4:ir) for the horizontal part are by no means as simple as this. The value of the angle in formula (19) 2
changes for every point on the zone at the height 9000, 6000 and so on. This change must be calculated. In Fig. 6 ABC
FIG. 6 is
a spherical triangle with sides 8, \l/, irj'2 and angle given. a well-known formula in the trigonometry of triangles: <
Then from
Cos
=
\l/
sin 6 cos
The power radiated from the zone that
<j>
horizontal antenna through the
Z= is,
9000, 6000, etc., will vary for different angles of <j>, the bent part of the antenna has a directive effect on the
oscillations.
In equation (19)
VW = K 47T
5in
,
f
2rZh Xrn
I
sin
}
f
cos 2
r
-T-
j
1
+ cos
2 \l/
2ird 2 sin -r
\l/
\
2ird
2 cos -r
2nd
I
2
cos
cos
1
2 cos
\f/
sin
XX sm
cos
From this equation the values of Table III are calculated for the different zones and different directions. The operations are long and tedious but not
difficult.
The
horizontal part of the
FROM A BENT ANTENNA
13
antenna has a
slight directive effect perpendicular to the direc-
tion in which
it
contrary to what one would show a directive effect in the expect: experiments direction away from the free end of the antenna. However, it has been shown by Pocklington that a circular wire radiates more power perpendicular to its area than in any other direction and the form of equation (19) shows that Pocklington's method of doublets applies to this problem and that the solution is correct to the approximations made.
because
points.
This
is
all
HORIZONTAL PART
TABLE
III
now be shown
that the power arising from the mutual modify the directive effect at high points in the atmosphere in such a way as to give a fore and aft directive It will
effect (eq. 20) tends to
effect.
The
values of Table
IV
are calculated from equation (20).
MUTUAL EFFECT TABLE IV
14
ELECTEOMAGNETIC OSCILLATIONS
Adding up the
vertical, the horizontal
and the mutual
effects
II, III and IV, we obtain the complete power radiated through unit area of the zones. The results are given in Table V, in which K has been set equal to an arbitrary value. Plate B is plotted from Table V. In Plate C, the dis-
contained in Tables
tribution at 9000
M
is
compared
mentally by Fleming. TOTAL EFFECT
The symmetry
to a curve obtained experi-
TABLE
V
developed from the theory can be reconciled with the asymmetrical curve found in the experiof the curves
ments by supposing that the electrical waves brought back to the earth from high in the atmosphere are more intense toward the bend in the antenna than at the free end. Zenneck (Zenneck, Phys. Zeitsch., Vol. 9, p. 553, 1908) has shown that this difference may be due to imperfect conductivity in the earth's surface.
SUMMARY First
:
The equations developed by
Pocklington,
and Peirce have been applied to an antenna with
Abraham
vertical
and
horizontal parts in such a way as to find the energy given out for the fundamental vibration:
X
=
4(fc
+
d)
Second: The intensities so obtained are plotted and are shown to have a fore and aft directive inclination. The intensity fore
and
aft is
symmetrical and not asymmetrical as required by the
experiments.
FROM A BENT ANTENNA
15
Close to the antenna the intensities are symmetrical azimuth agreeing with experiment. Fourth: The conclusion is that the fore and aft asymmetry
Third: in
antenna is caused by the difference in conductivity between the atmosphere and the earth for the electromagnetic of a bent
oscillation.
The forms
Fifth:
of the resulting equations
show that
Peirce's
assumptions regarding the current satisfy Pocklington's criterion for the use of Maxwell's Equations.
ADDENDUM The Integration of Equations
The
sin
I
Expand and
{
n.
Vt
rQ
r
)
A
2irx
sm
r2ir A
A
cos
The
27r /T _ -T-
A
(p
t
(h
+ x)dx
rQ)
fo)
2irh sin 2ir
--
27rxCost~] A
--
2irx
Cos
r
A
-Cos
2irx
\[/
2irx
2irx
\l/
.
COS-T ax A
(21)
,
(22)
Cd 2wx Cos -^ 2wx cos 7 sm-^r- dx A A J A
(23)
,/Q
r
sm -r-
2irh
A
is
r
A
--
27rh
sin^r
integration of (21)
sin
cos -T" dx
A
.
.
sm
)
2
cos^r cos A
cos -r-
TQ)
)
.
r
A
2wh
,.
.
sm^r- (Vt A
-r-
,
A
(Vt
2ir
.
r
2wh C d (Vt
cos
\//}
-- -- + cos 27r.__ (Vt
-sm
2ir -r-
x Cos
27rxCost
cos
cos-^cos^ [2irh
cos
-f-
multiply, thus:
27T. . T sin-r- (Vt
+
(18), p. 10.
integrable part of (18) is
A
.
r sm 2jrxCos\l/- sm 2wx dx .
.
r
t/o
(24)
A
A.
the same as that of (7) on page 4 and
gives
X
2wdcos\l/ 2
2ir sin
The
\//
\_
X
.
2wd X
.
2wdcos\l/^
27rd~\
X
integration of the integral part (22) comes under
X J
Form 360
16
ELECTROMAGNETIC OSCILLATIONS
in Peirce's
Table of Integral and simplifies into
2wd cos
.
+ (23)
comes under form
The complete
To
2irh
.
sin
sin
(360) but in a different
-
cos
(26)
way from
integration follows:
find
r
2irx
Cos
2irx
cos
sin
(Form 360) sin
mx
cos nx ax
cos
cos
(m n)x 2(m n)
=
(m 2(m
+ ri)x
Let 2ir
Then
2ir
cos
integration gives
47T
(1
+
COS
\l/)
\
COS
COS
A
,
2nd
+ sm ^A
_X 47T
2nd (1
cos
\p)
\
A
sm
COS
2wd -r
A
sin'
\I/
r
A
.
sin
2irdcos\l/ -
T
A
2ird cos
cos -r- cos
2w
---
27T(Z
-
^
2ir sin
A
.
sin
2ird cos
\1/
2
(22).
FROM A BENT ANTENNA 2ird cos
2ird
2ir sin
The
2
\p
cos
2ird sin -r sin
\f/
.
(27)
2nd cos ^ r
1
A
A
integrable part of (24)
Cos
r2wx sin
is
,
.
+
17
also a standard
sin
A
form and becomes
>s^cos
2ird cos r
\l/
A
2irx
.
\l/
r
finally
2ird
.
,
dx
A
.
sm
sm^r
A
2ird cos
2nd
\L
COS-T
A
]
)
A
Then
Substitute 25, 26, 27 and (28) in (21), (22), (23) and (24). and obtain:
insert the result in (18)
4wl f-^Ji
,
~~~
2irh
27T
sm -T-
r Q)
(Vt
sin
\//
cos
,
27r /T .
y (Vt
2irh r
)
COS -r
,
2<jr
sin
.__
(Vt
COS
j
+
+
I
)
2irh sin -r
f
sin
T
^~
2nd Cost A
Ivd]
cos -r
f
A
J
2nd cost COS ^
-- cos -- sin 2wh--
2,ird
.
sin
,
r
\l/
a
2ird
.
sin
j
cos
COS
.
7%
2nd cos ^
I
cos
^
X
27rZh
.
Sin
Tr-\
.
\[/
r-
cos
\[/
--r
j
+ cos t sin ~" sin --r 2ird
+ cos
f
2ird cos
2<7rd
cos -r- cos
2ir ,-:-
(Vt
.
TO) sin
2irh
^
f
,
cos
2ird cos
.
cos
2nd cos ~
\l/
~Y~
\l/
j
sm -,
--t COS
2ird cos
^
1
.
2wd
sm "T~ 2<jrd
~X
(28)
J
{~] |
ELECTROMAGNETIC OSCILLATIONS
18
Now X
.
2irh
TT
=
=
2wd
2'T~
4'''T~ so that 2irh
cos -T
=
sin -r
=
2nd sin -T
A
A
When
2ird
cos -r
A
A
these expressions are substituted in (29), the terms in r ) may be TO) and those in cos (2ir/\)(Vt
sin (2irl\)(Vt
added together and give the simple form: 21 r
T7
.
,
..
V sin ^ 1
cos -r
A
which
is
f J
27r 27rZh[ sin Xr L
+ cos
f
.
sin -T
27r. -r-
A
equation (19), page
(
T
L
TO)
cos
.
Vt
(9).
2wd cos ^
.
r
)
j
cos
\f/
sin
i
S
o
3
s I
s
/
S
g
8
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