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t. Hence
Jr
r(t) ::; r(s)
oo r(t) ::; L(~, 7)). Now let y E X and let 'IjJ(t) = Ly((J(t), 7)), b(t) = Lcr(t) (y, 7)) and c(t) = Lcr(t)(y, (J(O)). Then c(t) --+ 0 and 'IjJ(t) --+ Ly(~,7)) for t --+ 00. Now
'IjJ(t)
+ b(t)
::;
Jr
and
c(t)
+ b(t) + r(t) 2: Jr,
hence 'IjJ(t) ::; c(t) + r(t), hence Ly(~, rl) ::; limt--->oo r(t). This proves the assertion about r(t). Now Jr -
t. D 4.3 Exercise. Let~, 7) E X(oo) and assume ~ =1= 7). Let (Jo and rays from x to ~ and 7) respectively. Define angles X is hyperbolic if there are real numbers a < band constants c > 0 and ,\ < 1 such that any geodesic segment r : [a, b] ----> X with r(a) E Bc(O"(a)) and r(b) E Bc(O"{b)) satisfies d(r(a; b), 0")
Prove:
Jr -
OCs,t - (3s,t
(Jl
be the unit speed
is monotonically increasing as s, t increase and L(~, 7))
= s,t------'tCX; lim Jr
-
OCs,t - (3s,t.
The second assertion also follows from the monotonicity and Theorem 4.4 below. 4.4 Theorem. Let ~ =1= 7) E X(oo) and a,b > O. For x E X let (Jo and (Jl be the unit speed rays from x to ~ and 7) respectively. Then c = limhoo d( (Jo (at), (Jl (bt)) It is independent of the choice of x. In the Euclidean triangle with sides a, b, c and angles oc, (3, r in the opposite vertices A, B, C, see Figure 1, we have r = L(~, 7)) and
Chapter II: The boundary at infinity
34
For s E (0,1) given and E the point on c with d(E, B) = sc we have .
1
lIm -d(x, Pt(s)) = e := d(C, E),
t
t--->oo
where Pt : [0,1] -+ X is the geodesic from ao(at) to al(bt). Furthermore, if e i- 0, then the geodesics as,t : [O,et] -+ X with as,t(O) = x and as,t(et) = Ps(t) converge, for t -+ 00, to a unit speed ray as from x such that Pt (s) -+ as (00 ), and ( = as (00 ) is the unique point in X (00) with L(C 0
=
Lc(E, B),
L((, ry)
=
Lc(E, A).
Moreover,
lim L pt (8)(ao(at),x) = a' := LE(B, C),
t-----+CXJ
lim Lpt(s)(al(bt),x) = ,B':= LE(A,C).
t --->00
A ex (1- S)C
b I
~
S
X
E SC
~
B
FIGURE 1
Proof. The independence of c from x is immediate from the definition of asymptoticity. For IJ = Lx(~, ry) and c(t) = L(at) = d(ao(at), adbt)), we have (a
2
+ b2 -
= Ct,E cos( at - at,E)
= (a 2 + b2
c(t)
1
2ab cos IX) 2 ~ -t- ~ a cos (3t
-
=
+ b cos at
Ct,E cos({3t - (3t,E) ~ Ct,E
2abcos(Jr - at - (3t)) ~ ~ (a 2
+ b2 -
2abcos L(C ry)) ~,
where the inequalities in the first line follow from the Cosine Inequalities, see Proposition 1.5.2, the equalities in the second line from Proposition 1.5.3, where
The cone at infinity and the Tits metric
35
at,E and f3t,E are the angles and Ct,E is the length of the third edge in the Euclidean triangle with two edges of length a and b subtending an angle 7r - at ~ f3t, and the inequality in the third line since 7r
~ O't -
/3t <::: Lcr,(bt) (CTo(at), r])
+ Lcro(at)(CT1(bt),~)
-
7r
<::: Lcro(at) (~,TJ) <::: L(~, TJ),
Now c(t)lt tends to c and is independent of x. Since L(~, TJ) =
and therefore
L(~, r])
=
f. Furthermore, we have
Ct,E ----> C as t ----> 00. Now c -# 0 and hence at,E at ----> a, !3t ----> ;3 as t ----> 00. We also have
---->
SUPxEX
Ix we get
----> L(~, r]) and ,6. We conclude that
at - f3t
7r -
a, ,6t,E
---->
where Pt : [0,1] ---->]R;.2 is a line of length c(t) and d(x,pt(O)) = at, d(x,pt(l)) = bt. Now d(x, Pt (s)) It ----> e as t ----> 00, therefore . 1 ll1nsup -d(x, Pt(s)) <::: e. t--+oc
t
On the other hand, we have
d2(x,pt(S)) 2 >a t2 ~
c
(t)2 + S2 -2~ t
by the Fin.,t Cosine Inequality. Since at
----> 0
-
c(t) () 2as - t cos at.
and c(t)lt
---->
c we conclude that
and hence that d(x,Pt(.'))lt ----> e at t ----> 00. We now prove that the geodesics CT s,t converge to a ray as claimed. Given c > 0, there is T 2: 0 such that
C(t)2
It2 -
c
2
I,
1
c(t) . c 2as - - cos at - 2asccos al < '2 t
for all t 2: T. Then we obtain for t
d2(CTo(at'), Pt(s)) t2
>
t;
> t' 2: T and r
= t'lt,
(a 2(t - t')2 + s2c(t)2 - 2a(t - t')sc(t) cos at)
> a 2(1- r)2 + s2 C2 - 2a(1- r)sccosa -
c.
Chapter II: The boundary at infinity
36
Now denote by at the angle in the Euclidean triangle with side lengths a, b, c(t)lt corresponding to at. Then at 2: at and at ---> a. By enlarging T if necessary, we also have
c(t) E 12as- cos at - 2asccosal < t 2 for all t 2: T. Since triangles in X are CATo we obtain, for t > t l 2: T, d 2 ( 0'0 ( at l ), Pt (s ))
t2
t~ (a 2(t -
<
t l )2 + s2 C (t)2 - 2a(t - tl)sc(t) cos at)
< a2(1 - 1)2 + s2c2 - 2a(1 -
I)sccosa + E.
An analogous estimate holds for d( 0'1 (btl), Pt (s)). Euclidean comparison for the triangle (O'o(at l ),O'l(btl ),Pt(s)) shows that d(p~(s),Pt(s)) ::; ((1-
I)e + E)t
for all t, t l sufficiently large, where 1 = tilt. On the other hand, d(x, Pt (s)) It and hence the triangle inequality implies
--->
e
d (p~ (s ), Pt (s )) 2: (( 1 - I) e - E) t for all t, t l sufficiently large. In particular, up to the term Et (and E can be chosen arbitrarily small), the concatenation of the geodesic from x to pds) with the geodesic from Pt' (s) to Pt (s) is a shortest connection from x to Pt (s). By comparison with Euclidean geometry we conclude that for any R 2: 0, the distance d(O's,t(R),O's,dR)) is arbitrarily small for all t, t l sufficiently large. Hence the geodesic segments O's,t converge to a ray O's. Note that O's has unit speed since d(x,pt(s))lt ---> e and that Pt(s) ---> 0'09(00) = (by the very definition of the topology of X. For t large, the triangle with vertices x, 0'0 (at), Pt (s) has sides of length approximately equal to at, set, et. By comparison we get
Similarly Lx (1], () ::; Lc(A, E). Clearly, ( is independent of the choice of x and hence L(~, ()
< Lc(B, E),
L(1], () < Lc(A, E).
Now L(~,
()
+ L(1], () 2:
hence we have equality in (*). Suppose now that (' E X
(00)
L(~,
1]) = Lc(A, B),
is a point with
L(~, (') = Lc(B, E),
L(1], (') = Lc(A, E),
The cone at infinity and the Tits metric
37
and let (J' be the unit speed ray from x to ('. If ( i=- (', then there is an E > Osuch that d((J' (et), Pt (s)) 2 Et for all t sufficiently large. By comparison with Euclidean geometry we get that at least one of the following inequalities holds: c6 = lim t--->oo
ci
~d2((Jo(at),(JI(et)) 2
t
s2 c2 + E2 or
= lim ~d2((Jl(bt),(JI(et)) 2 (1- s)2 c2 + E2. t--->oo
t
However, by the first part of the proof we have
L(~, (') = a
2
2
2
\eae - Co ,
L(
2 ,>/) = b T), "
+e
2
2
- c1 .
2be
Hence (**) implies c6 = s2 c2 and ci = (1- s)2 c2. We conclude (= ('. As for the last claim, let
Then O'(t) + (3(t) 2 7r. By comparison with Euclidean geometry, applied to the triangles t:.(Pt (s), x, (Jo (at)) and t:.(Pt (s), x, (Jl (bt)) we get limsupO'(t):::;
0"
and
Now
0"
+ (3'
=
7r,
hence the claim.
lim sup (3(t) :::; (3'. t---+cx:::>
t---+CXJ
D
4.5 Exercise. Use the notation of Theorem 4.4 and assume that e i=- 0. Let F be a point on the edge of length a on the Euclidean triangle such that d( C, F) = ra for some r E (0,1). Prove: 1
d(E, F) = lim -d(pt(s), (Jo(rat)) t--->oo t and corresponding assertions about the angles at F. 4.6 Corollary. If~,T) E X(oo) are points with L(~,T)) < 7r, then there is a unique minimizing geodesic in X(oo) (with respect to L) from ~ to T).
Proof. The existence of a geodesic from ( to T) follows from Proposition 1.1.5 and Theorem 4.4, where we put a = b = 0, s = 1/2. The uniqueness follows from the uniqueness of the point ( in Theorem 4.4. D The cone at infinity, Coo X , is the set [0,(0) x X(oo)/ "', where {O} x X(oo) shrinks to one point, together with the metric d oo defined by
(4.7)
Chapter II: The boundary at infinity
38
That is, (Ccx;X, d oo ) is the Euclidean cone over X (00). We may also think of CooX as the set of equivalence classes of geodesic rays, where we do not require unit speed and where we say that geodesic rays (Jo and (J1 are equivalent if d((JO(t),(J1(t)) is uniformly bounded in t. In the notation of Theorem 4.4 we have
d oo ((a , 0, (b , ry))
=
1
lim -d((Jo(at), (J1 (bt)).
t~oo
t
In this sense, the geometry of X with respect to the rescaled metric d/t converges to the geometry of CooX as t ---+ 00. Given :r E X and a sequence of geodesics (In : [0, t n ] ---+ X with speed Un 2: 0 and (In(O) = X, we say that (In ---+ (u , O if t n ---+ 00 , if Un ---+ a and, if a i=- 0, if (In(t n )
---+~.
Theorem 4.8. (Coo X , d oo ) is a Hadamard space.
Proof. Note that CooX is simply connected since we can contract CooX onto the distinguished point Xoo = [{O} x X(oo)]. The metric doo is complete since L is a complete metric on X (00 ). We show now that doo is a geodesic metric. To that end , let (a, 0, (b , T)) E Coo X . We want to show that there is a minimizing geodesic between these two points. The only non-trivial case is U , b > 0 and 0 < L(~, T)) < 7f. Choose X E X and let (Jo, (J1 be the unit speed rays from :r with (Jo (00) = ~ and (J1 (00) = ry. Then, in the notation of Theorem 4.4, the geodesics (Js,t converge to geodesic rays (Js of speed e s > 0, 0 ::; s ::; 1, and, by Theorem 4.4 and the definition of doo1 the curve p(s) = (es,(JS(00)),0::; s::; 1, is a minimizing geodesic form (a,~) to (b,ry). It is immediate from Corollary 4.6 (or Theorem 4.4) that P is the unique minimizing geodesic from (a,~) to (b,ry). It remains to show that CooX is nonpositively curved. By Lemma 1.3.4, it suffices to consider triangles in CooX with minimizing sides. Let D. be such a triangle and let (Ui 1 ~i) 1 1 ::;i ::; 3, be the vertices of D.. The only non-trivial case is ai > 0 and 0 < L (~i 1 ~j) < 7r for i i=- j. Recall that the minimal geodesics Pi: [0 , 1] ---+ CooX from (ail~i) to (ai+11 (i+d are unique (indices are counted mod 3). Let (e1,(d = pi(sd and (e21 (2) = Pj(S2)' where i i=- j and 0 < 131,132 < l. Let (J1 and (J2 be the unit speed rays from a given point .r E X to (1 and (2 respectively. By Theorem 4.4,
Let Crk be the unit speed ray from x to ~k:, 1 ::; k ::; 3. If Pk.t : [0,1] ---+ X denotes the geodesic from Crk(Ukt) to Crk+1(ak+1t) 1 and if Cru respectively Cr2,t are the geodesics from x with Cr1,t(e1t) = Pi,t(sd respectively Cr2,t(e2t) = Pj,t(S2), then , by Theorem 4.4 ,
The cone at infinity and the Tits metric
39
For t large, the triangle (PI,t, P2,t, P3,t) has sides of length approximately tlk, where lk = L(Pk)' Now let (7h ,75 2 , (3) be the Euclidean comparison triangle of (PI, P2, P3) andlct dE = d(Pi (sd, Pj (S2))' Since X is a Hadamard space we conclude
where
E:
> 0 is given and t is sufficiently large. Hence 1 1 I/(uI(eIR), u2(e2 R )) = t~~ lid(o-l,t(eIR), o-2,t(e2 R )) 1 ::; lim sup -t d(pi,t(sd, Pj,t(S2)) ::; dE. t~'X;
It follows that triangles in CocX are CATo and hence that CocX is a Hadamard
space.
D
4.9 Corollary. (X (00), L) has curvature::; 1. More pr'ecisely, (i) geodesics in X (00) of length < 1T are minimal; (ii) triangles in X (00) of perimeter < 21T are C ATI .
PT'Oof. The relation between distances in C ocX and angles in X (00) is exactly as the relation between distances in Euclidean space E 3 and angles in the unit sphere 52. D 4.10 Lemma. Let X be a locally compact Hadamard space. In the notation of Theorem 4.4 let a = b = 1 and assume that there is no geodesic in X fT'Om ~ to T/. Let Pt(St) be the point on Pt closest to :r. Then d(x, pt(sd) --+ 00. If ( E X(oo) is an accumulation point of Pt (.'id for t --+00, then L(~,()
= L((,r/) = ,/2.
PT'Oof. Since X is locally compact and since there is no geodesic from ~ to r/ we have d(x,Pt) --+ 00 for t --+ 00. From Theorem 4.4 we conclude d(x,pt(l/2))/t --+ cos(,/2) < 1 and hence St # 0, 1. Therefore
Since (in the notation of Theorem 4.4)
Qt,
f3 t
--+
(1T -,)/2 we get
The triangle inequality implies that we must have equality in these inequalities.
D
Following Gromov, we denote by Td, the Tits metric, the interior metric on X (00) associated to the angle metric L. The name derives from its close relationship with the Tits building associated to symmetric spaces. By definition, we have Td(~,T/) 2: L(~,T/) for all ~,T/ E X(oo).
Chapter II: The boundary at infinity
40
4.11 Theorem. Assume that X is a locally compact Hadamard space. Then each connected component of (X(oo), Td) is a complete geodesic space with curvature :::; 1. Furthermore, for ~,7) E X (00) the following hold: (i) if there is no geodesic in X from ~ to 7), then Td(~, 7)) = L(~, 7)) :::; Jr; (ii) if L(~, 7)) < Jr, then there is no geodesic in X from ~ to 7) and there is a unique minimizing Td-geodesic in X(oo) from ~ to 7); Td-triangles in X of perimeter < 2Jr are CAT!; (iii) if there is a geodesic a in X from ~ to 7), then Td(~, T)) 2: Jr, and equality holds iff a bounds a fiat half plane; (iv) if (~n), (7)n) are sequences in X (00) such that ~n -+ ~ and 7)n -+ 7) in the standard topology, then Td(~, 7)) :::; lim infn-->CXJ Td(~n, T)n). Proof. The first assertion in (ii) and (iii) respectively is clear since L(~, 7)) = Jr if there is a geodesic in X from ~ to 7). If there is no geodesic in X from ~ to 7), then, by Lemma 4.10, there is a midpoint (in X(oo) between them with respect to the L-metric. Now the L-metric on X(oo) is complete, see Proposition 4.1. Hence we can construct an L-geodesic from ~ to 7) by choosing midpoints iteratively. Since Lgeodesics are Td-geodesics, we obtain (i). The uniqueness assertion in (ii) follows from the corresponding uniqueness assertion of midpoints in Theorem 4.4. The completeness of Td also follows since the L-metric is complete, see Proposition 4.1. We now prove (iv) and that each connected component of (X(oo), Td) is geodesic. By the corresponding semicontinuity of L, see Proposition 4.1, we conclude from (i) that (iv) holds if liminfn-->CXJ Td(~n, 7)n) < Jr. From (ii) we also get that for any pair of points ~,7) E X(oo) with Td(~,7)) < Jr there is a minimizing Td-geodesic from ~ to 7). By induction we assume that this also holds when we replace Jr by h, k 2: 1. Now suppose lim infn-->CXJ Td(~n, 7)n) < (k + l)Jr. By th definition of Td, there is a point (n almost half way between ~n and 7)n. Passing to a subsequence if necessary, we assume (n -+ ( in the standard topology and obtain, by induction,
+ Td((, 7)) :::; liminfTd(~n, (n) + liminfTd((n, 7)n)
Td(~, 7)) :::; Td(~, () n~~
In particular,
Td(~, 7))
n~~
:::; liminfTd(~n, 7)n). n~~
< (k + l)Jr. There exists (another) sequence ((n) such that
hence, by the semicontinuity, there is a point ( with Td(~, () = Td(7), () = Td(~, 7))/2.
By the inductive hypothesis, there are minimizing Td-geodesics from ~ to ( and ( to T). Their concatenation is a minimizing Td-geodesic from ~ to 7). Hence we conclude (iv) and that the components of (X(oo),Td) are geodesic spaces.
The cone at infinity and the Tits metric
41
As for the statement about flat half planes in (iii), let ( be a point with = Td((,T/) = 7f/2. Since
Td((,~)
for any x on the geodesic (in X) from
~
to T/ and Lx ::; Td, we have
for all such x. Now the rigidity part of Lemma I.5.8(i) applies. The claims about the curvature bound and about triangles in (ii) are immediate from Corollary 4.9. 0
CHAPTER III
Weak Hyperbolicity One of our main objectives in this chapter is the discussion of transitivity properties of the geodesic flow and related topics. The first two sections are greatly influenced by the work of Eberlein on geodesic flows in [Eb2, Eb3]. The third section deals with the main results of the author's thesis (published in [Bal]) , but here in the context of Hadamard spaces instead of Hadamard manifolds. The fourth section deals with applications to harmonic functions and random walks on countable groups, compare [Ba3, BaLl]. Many of the ideas in Section 4 go back to Furstenberg [Ful, Fu2, Fu3]. Let X be a Hadamard space. We say that X is geodesically complete if every geodesic segment of X is part of a complete geodesic of X, that is, a geodesic which is defined on the whole real line. For X geodesically complete, we denote by X the set of unit speed geodesics of X, equipped with the topology of uniform convergence on bounded subsets. The geodesic flow (gt) acts on ex by reparameterization, l(a)(s) = a(s + t).
e
If X is a smooth manifold, then
ex
----+
SX; a
----+
&(0)
defines a homeomorphism from ex to the unit tangent bundle SX of X. With respect to this homeomorphism, the geodesic flow above corresponds to the usual geodesic flow on SX (also denoted gt),
l(v) = 1v(t), v
E
SX,
where Iv denotes the geodesic in X with 1v(0) = v. 1. The duality condition
In our considerations it will be important to have a large group of isometries. Let X be a Hadamard space and r a group of isometries of X. Following Eberlein [Eb2]' we say that ~,T) E X (CXl) are r -dual if there is a sequence ('Pn) in r such that 'Pn(x) ----+ ~ and 'P~l(X) ----+ 77 as n ----+ CXl for some (and hence any) x E X.
Chapter III: Weak hyperbolicity
44
Duality is a symmetric relation. The set of points f -dual to a given point in X (00) is closed and f-invariant. We say that f satisfies the duality condition if for any unit speed geodesic a : lR -+ X the endpoints a( -00) and a( 00) are f-dual. The duality condition was introduced by Chen and Eberlein [CE1]. The condition is somewhat mysterious, at least as far as Hadamard spaces are concerned (as opposed to Hadamard manifolds). May be it is only reasonable for geodesically complete Hadamard spaces. 1.1 Lemma [Eb2J. Let X be a geodesically complete Hadamard space, and let a, p : lR -+ X be unit speed geodesics in X. Let (CPn) be a sequence of isometries of X such that cP;; 1(x) -+ a( 00) and CPn (x) -+ p( -00) as n -+ 00 for some (and hence any) x E X. Then there are sequences (an) in ex and (t n ) in lR such that an -+ a, t n -+ 00 and CPn 0 gt n (an) -+ p as n -+ 00. 1.2 Remarks. (a) The converse to Lemma 1.1 is clear: let a, p E ex and suppose there are sequences (an) in ex, (t n ) in lR and (CPn) of isometries of X such that an -+ a, t n -+ 00 and CPn 0 gtn(an ) -+ a as n -+ 00. Then cp;;l(X) -+ a(oo) and CPn(x) -+ p(-oo) as n -+ 00 for one (and hence any) x E X. (b) Note that the assumption on the sequence (CPn) in Lemma 1.1 only specifies a( 00) and p( -00). Thus we may replace a by any asymptotic a' E ex and p by any negatively asymptotic p' E ex, keeping the sequence (CPn) fixed. Since an -+ a and cp;;l 0 gtn(an ) -+ p we have
tn-d(a(O),cp;;,-l(p(O))) -+0
as
n-+oo.
For a' asymptotic to a we also have
d(a'(O),cp;;,-l(p(O))) - d(a(O),cp;;,-l(p(O))) -+ b(a(oo),a(O),a'(O)) as n
-+
00. Hence we may replace the sequence (t n ) by the sequence
(t~.)
given by
t~ = tn+b(a(oo),a(O),a'(O)), nEN,
when replacing a by a'. A similar remark applies to geodesics p' E asymptotic to p.
ex negatively
Proof of Lemma 1.1. For m ;::: 0 and n E N let an,m : lR -+ X be a unit speed geodesic with an,m( -m) = a( -m)
and
an,m(tn,m
+ m)
= cp;;,-l(p(m)) ,
where
tn,m = d(a(-m),cp;;,-l(p(m))) - 2m. Set N(O) 1 and define N(m), m > 2, recursively to be the smallest number > N(m - 1) such that 1 1 and d(CPn 0 an,m(tn,m - m), p( -m)) :::: m m for all n ;::: N(m). Note that such a number N(m) exists since cp;;l(p(m)) -+ a(oo) and CPn(a( -m)) -+ p( -00). Now set an := an,N(m) for N(m) :::: n < N(m+ 1). D
d(an,m(m), a(m)) <
The duality condition
45
1.3 Corollary. Let X be a geodesically complete Hadamard space and f a group of isometries of X satisfying the duality condition. Let rY, p : ffi. --+ X be unit speed geodesics in X with rY(oo) = p(oo). Then there are sequences (rY n ) in ex, (t n ) in ffi. and ('Pn) in f such that rY n --+ rY, t n --+ 00 and 'Pn 0 gtn(rY n ) --+ p as n --+ 00. Proof. Since f satisfies the duality condition, there is a sequence (?/In) of isometries in f such that ?/In(x) --+ p(oo) and ?/J;;l(X) --+ p(-oo) as n --+ 00. Now rY(oo) = p(oo), and hence Lemma 1.1 applies. D We say that a geodesic rY E ex is nonwandering mod f (with respect to the geodesic flow) if there are sequences (rY n ) in ex, (tn) in ffi. and ('Pn) in f such that rY n --+ rY, t n --+ 00 and 'Pn 0 gt n (rY n ) --+ rY. The set of geodesics in ex that are nonwandering mod f is closed in ex and invariant under the geodesic flow and f. It is clear that the endpoints of a geodesic rY E ex are f-dual if rY is nonwandering mod f. Vice versa, Lemma 1.1, applied in the case where X is geodesically complete and rY = p, shows that a geodesic rY E ex is nonwandering mod f if the endpoints of rY are f -dual.
1.4 Corollary. Let X be a geodesically complete Hadamard space and f a group of isometries of X. Then f satisfies the duality condition if and only if every rY E ex is nonwandering mod f. D We say that a geodesic rY E ex is f-recurrent if there exist sequences (t n ) in ffi. and ('Pn) in f such that t n --+ 00 and 'Pn 0 gt n (rY) --+ rY as n --+ 00. The set of f-recurrent geodesics in ex is invariant under the geodesic flow and f.
1.5 Corollary. Let X be a geodesically complete, separable Hadamard space and f a group of isometries of X. Then f satisfies the duality condition if and only if a dense set of geodesics rY E ex is f -recurrent. Proof. Since X is separable, the topology of X,and hence also of ex, has a countable base. Now Corollary 1.4 implies that the set of f-recurrent geodesics is a dense e,,-subset of ex if f satisfies the duality condition. The other direction is clear. D If X is a Hadamard manifold, then the Liouville measure on SX is invariant under the geodesic flow. Hence, if f is a group of isometries of X that acts properly discontinuously and such that vol(X/r) < 00, then f satisfies the duality condition by the Poincare recurrence theorem and Corollary 1.4. However, for a general Hadamard space X, there is (so far) no natural invariant measure on ex with good properties.
1.6 Question. Let X be a geodesically complete Hadamard space and f a group of isometries of X. Does f satisfy the duality condition if it acts properly discontinuously and cocompactly? 1. 7 Problem/Exercise. Let X be a geodesically complete Hadamard space. Construct measures on ex which are invariant under isometries and the geodesic flow of X.
Chapter III: Weak hyperbolicity
46
In the case of 2-dimensional polyhedra with piecewise smooth metrics, the answer to Question 1.6 is affirmative, see [BB3]. In this reference, one also finds a natural generalization of the Liouville measure for geodesic flows on polyhedra with piecewise smooth metrics. The following lemma and proposition are taken from [CEl] and [BBE] respectively. 1.8 Lemma. Suppose ~,rl E X(oo) are the endpoints of a geodesic (J:]R;. ---> X. Let ('Pn) be a sequence of isometries of X such that 'Pn (x) ---> ~ and 'P~ I (x) ---> ( E X (00) as n ---> 00. Then 'P~l (7)) ---> ( as n ---> 00.
Proof. Let x
= dO).
Then Lx(~, 'Pn(x))
--->
0 and hence
By comparison with Euclidean geometry we get, for the metric dx,R as in (11.2.3),
where R > 0 is arbitrary. Since 'P~I(X)
--->
(we conclude 'P~l(rl)
---> (.
D
1.9 Proposition. Suppose X is geodesically complete and f satisfies the duality condition. Let ~ E X(oo). Then f operates minimally on the closure f(~) of the f-orbit of~, that is, f(() = f(~) for any ( E [(0.
Proof. It suffices to show that ~ E [(() for any ( E f(O. Since X is geodesically complete, there are geodesics (J, P : ]R;. ---> X with (J( (0) = ~ and p( (0) = (. Let = (J( -(0) and (' = p( -(0). Since f satisfies the duality condition, is f-dual to ~ and (' is f-dual to (. Now ( is f-dual to because the set of points f-dual to is f-invariant and closed. By Lemma 1.8 this implies that E [(('). Choose a sequence ('Pn) in f with 'Pn ((') ---> For rn > 0, let (J m be a complete geodesic with (Jrn(O) = (J(rn) and (Jrn(~oo) = 'Pn(('), where n = n(rn) 2: rn is chosen so large that d ((J m, (J (0)) :s; 1. Then (Jrn ((0) ---> ~ and (J m ( - (0) is f-dual to (Jm(oo). Therefore (Jm(oo) is f-dual to (' = 'P~I((Jm(-oo)). Hence (' is f-dual to ~ = lim m---> 00 (Jm(oo). Now Lemma 1.8 implies ~ E [((). D
e
e
e
e
e
e.
1.10 Remark. The duality condition has other useful technical properties. (1) Let Xl and X 2 be Hadamard spaces with metrics d l and d2 respectively and let X be the Hadamard space Xl x X 2 with the metric d = Jdr + d~. If f is a group of isometries of X satisfying the duality condition such that any 'P E f is of the form 'P = ('PI, 'P2), where 'Pi is an isometry of Xi, i = 1,2, then
and the corresponding group f 2 satisfy the duality condition. This is clear since geodesics in X are pairs ((JI, (J2), where (JI is a geodesic of Xl and (J2 is a geodesic
Geodesic flows on Hadamard spaces
47
of X 2 . See [Ebl0,16] for applications of this property in the case of Hadamard manifolds. Note that r 1 and/or r 2 need not act properly discontinuously even if r does. Thus a condition like cocompactness + proper discontinuity does not share the above property of the duality condition. (2) Clearly the duality condition passes from a group r of isometries of a Hadamard space X to a larger group of isometries of X. Vice versa, if X is geodesically complete and separable and if t. is a subgroup of finite index in r, then t. satisfies the duality condition if r does [EblO]. To see this, let a E GX be a rrecurrent geodesic. Choose sequences (t n ) in lR and ('Pn) in r such that t n ---> 00 and 'Pn 0 gt n (a) ---> a. Now t. has finite index in r. Hence we may assume, after passing to a subsequence, that 'Pn = 'l/Jn'P, where 'P E r is fixed and 'l/Jn E t. for all n E N. Then and
arn,n = ('l/Jrn'I/Jr~l)ogtm-tn(a~) = 'Prnogtm(a) --->a. Choose rn = rn(n) convenient to get that am(n),n ---> a. This shows that a is nonwandering mod t.. Now the set of geodesics in GX which are nonwandering mod t. is closed, and the set of r-recurrent geodesics in GX is dense in GX, see Corollary 1.4. Hence t. satisfies the duality condition. We come back to the beginning of this section. We said there that we will be in need of a large group of isometries, and we made this precise by introducing the duality condition. One might think that the isometry group of a homogeneous Hadamard manifold X is large; however, it is not in our sense, except if X is a symmetric space (sec [Ebl0], Proposition 4.9).
1.11 Definition/Exercise/Question. Let X be a Hadamard space and r a group of isometrics of X. The limit set L(r) c X (00) of r is defined to be the set of all ~ E X (00) such that there is a sequence ('Pn) in r with lim n -+= 'Pn (x) = ~ for one (and hence any) x E X. Show L(r) = X(oo) (i) if there is a bounded subset B in X with UcpEl'P(B) = X or (ii) if X is geodesically complete and r satisfies the duality condition. In many results below we assume that X is geodesically complete and that r satisfies the duality condition. Can one (you) replace the duality condition by the assumption L(r) = X (00). 2. Geodesic flows on Hadamard spaces 2.1 Definition. Let X be a geodesically complete Hadamard space and r a group of isometrics of X. We say the geodesic flow of X is topologically transitive mod r if for any two open non-empty subsets U, V in G X there is t E lR and 'P E r such that gt(U) n 'P(V) -# 0.
Chapter III: Weak hypcrbolicity
48
2.2 Remark. If X is separable, then the topology of X, and therefore the topology of ex, has a countable base. Hence the geodesic flow is topologically transitive mod f if and only if it has a dense orbit mod f: there is a a in ex such that for any a ' in ex there are sequences (t n ) in JR and If!n in f with If!nlna ---+ a ' . After all our preparations we are ready for the following result from [Eb3]. 2.3 Theorem. Let X be a geodesically complete, separable Hadamard space, and let f be a group of isometries of X satisfying the duality condition. Then the following are equivalent: (i) gt is topologically transitive mod f; (ii) for some ~ E X(oo), the orbit r(~) is dense in X(oo); (iii) for every ~ E X(oo), the orbit f(O is dense in X(oo); (iv) X (00) does not contain a non-empty f -invariant proper closed subset. Proof. Clearly (iii) {::} (iv) and (iii) =} (ii). The implication (i) =} (ii) is immediate from Remark 2.2 above. The implication (ii) =} (iii) follows from Proposition 1.9. It remains to prove (ii) =} (i). We let U(oo) respectively V(oo) be the set of points a(oo) in X(oo) with a E U respectively V. Then U(oo) and V(oo) are open and non-empty. Applying (ii) we can assume U(oo) C V(oo). Let a E U. Then there is a geodesic p E V with p(oo) = a(oo). Now Corollary 1.3 applies. D 2.4 Theorem. Let X be a geodesically complete and locally compact Hadamard space, and let f be a group of isometries of X satisfying the duality condition. Then the following are equivalent: (i) the geodesic flow (gt) of X is not topologically transitive mod f; (ii) X (00) contains a non-empty f -invariant proper compact subset; (iii) the geodesic flow (gt) of X admits a non-constant f -invariant continuous first integral f : ex ---+ JR such that f (a) = f (p) for all a, pEeX with a(oo) = p(oo) or a( -(0) = p( -(0). Each of these conditions implies that every geodesic of X is contained in a flat plane, that is, a convex subset of X isometric to the Euclidean plane. Proof. X is separable because X is locally compact. Hence (i) {::} (ii) by Theorem 2.3. The implication (iii) =} (ii) is clear since we assume the integral to be continuous, non-constant and f-invariant and since X(oo) is compact. It remains to show (ii) =} (iii) and the existence of the flat planes. To that end, let C C X(oo) be a non-empty f-invariant proper compact subset. For a E ex we set (2.5)
f(a) = minL,,(o)(a(oo),(). (EC
We claim that the function f is an integral of the geodesic flow as asserted. Note that f is f-invariant since Cis.
Geodesic flows on Hadamard spaces
49
The continuity of angle measurement at a fixed point, see 1.3.2, implies that for any a E GX there is ( E G with f(a) = Lo-(O)(a(oo),(). Obviously, or by Proposition 11.4.2, we have that f(gt(a)) is monotonically not decreasing in t. Suppose first that a E GX is r-recurrent. Choose sequences (t n ) in lH. and «Pn) in r such that t n ----+ 00 and 'Pn 0 gtn (a) ----+ a. By the r -invariance of f and the monotonicity we have
The semicontinuity of angle measurement, see 1.3.2, implies liminf f('Pn n--+oo
0
in(a)) ~ f(a).
We conclude that f (gt (a) = f (a) for all t ;:::: 0, and hence for all t E lH. since gS (a) is r-recurrent for all S E R We also conclude that there is a point ((a) E G such that
f(i(a)) = Lo-(t)(a(oo),((a)) = L(a(oo),((a)) = minL(a(oo),(). (EC
rt
In particular, a bounds a flat half plane Ho- with ((a) E Ho-(oo) if a(oo) G. Now let a E GX be arbitrary. Let (an) be a sequence of r-recurrent unit speed geodesics converging to a. Passing to a subsequence if necessary, the corresponding half planes Ho- n and points ((an) converge to a flat half plane Ho- along a respectively a point ((a) E Ho-(oo). We conclude
f (a) = lim f (an) = L (a (00 ), (( a)) . n--+=
Therefore f is continuous; now Lemma 1.1 implies that f(a) = f(p) if a(oo) p( 00) respectively if a( -00) = p( -00); f is non-constant since G is proper. Let a E GX and let Ho-, ((a) be as above. Let Pt : lH. ----+ X be a unit speed geodesic with Pt(O) = a(t) and Pt(oo) = ((a). For S E lH., let as : lH. ----+ X be a unit speed geodesic as(t) = Pt(s) and as(oo) = a(oo). Then clearly
f(a)
=
f(a s )
=
Lo-s(t)(((a), a 8 (00)).
Therefore ptl [s, 00) and as I [t, 00) span a flat cone Gs,t. This cone contains aUt, 00)) if s < O. Now X is locally compact. Hence we obtain a flat plane containing a as a limit of the cones GSn,t n for some appropriate sequences Sn ----+ -00 and t n ----+ -00. 0 2.6 Problem. Suppose X is geodesically complete and irreducible with a group r of isometries satisfying the duality condition. Assume furthermore that every geodesic of X is contained in a flat plane. Claim: X is a symmetric space or a Euclidean building. This is known in the smooth case, which excludes the case of Euclidean buildings. In Chapter IV we will discuss the proof. In the singular case, if dim X = n and every geodesic of X is contained in an n-f1at, that is, a convex subset of X isometric to n-dimensional Euclidean space, then X is a Euclidean building [KI].
Chapter III: Weak hypcrbolicity
50
3. The flat half plane condition In this section we assume that X is a locally compact Hadamard space. Then, if a : III --> X is a geodesic which does not bound a flat half plane, there is a constant R > 0 such that a does not bound a flat strip of width R.
3.1 Lennna. Let a : III --> X be a unit speed geodesic which does not bound a fiat strip of width R > O. Then there are neighborhoods U of a( -(X)) and V of a( (0) in X such that for any ~ E U and T) E V there is a geodesic from ~ to T), and for any ,mch geodesic a' we have d( a', a(O)) < R. In particular, a' does not bound a fiat strip of width 2R. Proof. If the assertion of the lemma docs not hold, then there are sequences (x n ) and (Yn) in X with X n --> a( -(X)) and Yn --> a( (0) such that the unit speed geodesic segment an from X n to Yn, parameterized such that an(O) is the point on an closest to z:= a(O), satisfies d(an(O),z) :::: R for all n E N. Let Zn be the point on the geodesic from z to an(O) with d(z, zn) = R. By the choice of an(O), 7f
"2'
Lan(O)(z, x n ), Lan(O)(z, Yn) ::::
Hence also
7f
Lzn(z,xn ), L zn (Z,Yn)::::"2'
Passing to a subsequence if necessary we assume Zn and
-->
z=. Then d(z, z=)
=
R
We also have Lz(a( -(0), z=)
+ Lz(a(oo), zoe) >
7f.
Applying Proposition I.5.8(i) we conclude Lz(a(-oo), zoe)
7f
= Lz=(a(-oo),z) = Lz(a(oo), zoe) = Lz=(a(oo),z) ="2'
Hence the unit speed rays w_ respectively w+ from z= to a( -(X)) and a( (0) respectively span flat half strips with al (-00,0] respectively al [0, (0), sec Proposition I.5.8(i). In particular, a( -t) respectively a(t) is the point on a closest to w_(t) respectively w+(t), t > O. Hence d(w_(t),w+(t)) :::: 2t, and hence w_ and w+ combine to give a geodesic w from a( -(X)) to a( (0) through z=. Therefore w is parallel to a and wand a span a flat strip of width R. This is a contradiction. 0
3.2 Lemma. Let a : III
--> X be a unit speed geodesic which does not bound a fiat half plane. Let ('Pn) be a sequence of isometries of X such that 'Pn (x) --> a( (0) and 'P~1 (x) --> a( -ex)) for one (and hence any) x EX. Then fOT n sufficiently large, 'Pn has an a.Tis an such that an(oo) --> a(oo), an(-oo) --> a(-oo) as n --> 00.
Proof. There is an R> 0 such that a docs not bound a flat strip of width R. Let x = a(O) and choose c > 0, r > 0 such that U
=
U(x,a(-oo),r,c) and V
=
U(x,a(oo),T,c).
The flat half plane condition
51
are neighborhoods as in Lemma 3.1. By comparison with Euclidean geometry we find that there is an R' > r such that for any y E X we have
d(CJ(r), CJx,y(r)) < c or ifd(y,CJ)
d(CJ( -r), CJx,y(r)) < c
~Randd(y,x)
'2R'.
By the definition of U and V this means that y E U U V if d(y, CJ) ~ Rand
d(y, x) '2 R'. Assume that l{!n, for any n in a subsequence, fixes a point X n E X outside U U V with d(x,x n ) '2 2R'. Let CJ n = CJx,x n be the unit speed geodesic (or ray respectively if X n E X (00 )) from x to x n . Then the displacement function d( l{!n (z), z) is monotonically decreasing along CJ n . Let Yn = CJn(R') and y~ = CJ n (2R'). Then
L Yn (y~, l{!n (Yn)) + L Yn (y~, l{!;; 1 (Yn)) L Yn (y~, l{!n(Yn))+L'Pn(Yn) (l{!n(Y;,), Yn) ~
7r
since
(consider the quadrangle spanned by Yn,Y;"l{!n(Yn),l{!n(Y~)).Now
and therefore
We also have
and hence rp,,(Yn) ----+ CJ(oo) and l{!;;l(Yn) ----+ CJ(-oo) (for the given subsequence). After passing to a further subsequence if necessary, we can assume Yn ----+ y. Then d(y,CJ) '2 R by (*) since Y tt U U V and d(y,x) = R'. By (**), the rays from Y to CJ( -(0) respectively CJ( (0) combine to give a geodesic parallel to CJ. Therefore CJ bounds a fiat strip of width R, a contradiction. Hence we obtain that, for n sufficiently large, any fixed point of l{!n is contained in U U V U B(x, 2R'). Using Lemma 3.1 it is now easy to exclude that l{!n is elliptic or parabolic (for this compare Proposition 11.3.4) for all n sufficiently large. For large n, the endpoints of an axis CJ n of l{!n have to be in U U V by what we said above. It is clear from Lemma 3.1 that not both endpoints of CJ n are in one of the sets, U or V. Hence the lemma. 0
Chapter III: Weak hyperbolicity
52
3.3 Lemma. Let rp be an isometry of X with an axis u : lR - t X, where u is a unit speed geodesic which does not bound a fiat half plane. Then (i) for any neighborhood U of u( -(0) and any neighborhood V of u( (0) in X there exists N E N such that rpn(x \ U)
c
V,
rp~n(x
\ V)
c
U
for all n 2: N ;
(ii) for any ~ E X (00) \ {u( oo)} there is a geodesic UE, from ~ to u((0), and any such geodesic does not bound a fiat half plane. For K C X (00) \ {u( 00)} compact, the set of these geodesics is compact (modulo parameterization).
= u(O). We can assume that
Proof. Let x
U
= U(x,u(-oo),R,c) and V = U(x,u(oo),R,c).
By comparison with Euclidean geometry we find that rp-l(U)CU
and
rp(V)cV.
If (i) is not true, there is a sequence nk - t 00 and, say, a sequence (Xk) in X \ U such that rpn k (Xk) ¢ V. Passing to a subsequence, we may assume Xk - t ~ E X \ U. From (*) we conclude rpm(Xk) ¢ V for O:S m:S nk, and hence we get
In particular, ~ E X (00). Now the set K of all ~ E X ((0) \ U satisfying (**) is compact and invariant under rpm, m 2: 1. By our assumption K i= 0. Now choose ~ E K such that La(o) (u(oo),O is minimal. Since rp(u(oo)) = u(oo),
where a
>
°
is the period of rp. By the choice of
~
we conclude
hence the rays from u(O) and u(ma) to rpm(o together with ul[O, ma] bound a flat convex region. Since m is arbitrary and since rp shifts u, we conclude that u bounds a flat half plane, a contradiction. Thus (i) follows. Now (ii) is an immediate consequence of (i) and Lemma 3.1. 0 Let f be a group of isometrics of the Hadamard space X. We say that a non-constant geodesic u in X is f-closed if it is an axis of an axial isometry rp E f.
The flat half plane condition
53
3.4 Theorem. Assume that X is a locally compact Hadamard space containing a unit speed geodesic a : ~ --+ X which does not bound a flat half plane and that r is a group of isometries of X satisfying the duality condition. Then we have: If X (=) contains at least three points, then X (=) is a perfect set: for any ~ E X (= ), there is a sequence (~n) in X (= ) \ {O such that ~n --+ ~. Furthermore, for any two non-empty open subsets U, V of X(=) there is a 'P E r with
'P(X(=) \ U) c V, 'P-I(X(=) \ V) c U. More precisely, there is a r -closed geodesic a with a( -=) E U and a( =) E V such that a does not bound a flat half plane. Proof. By Lemma 3.2, there is an isometry 'Po in r with an axis ao which does not bound a flat half plane. Since X (=) contains more than two points, there is a point ~ E X(=) \ {ao(±=)}. By Lemma 3.3, 'P~n(~) --+ ao(±=), hence the first assertion holds for ao (±=). Again by Lemma 3.3, there is a geodesic al from ao( -=) to ~ and this geodesic does not bound a flat half plane. By Lemma 3.2, any two neighborhoods of the endpoints of al contain endpoints of an axis a~ of an isometry 'PI in r and a~ does not bound a flat half plane. Then a sufficient high power of 'PI maps ao (+=) into the given neighborhood, hence the first assertion also holds for ~. If U, V are non-empty and open in X (=), there is, by the first step, a point ~ E U - ao (=). By Lemma 3.3, there is a geodesic half plane. By Lemma 3.2 there is a f -closed geodesic a2 with a2 (-=) E U such that a2 does not bound a flat half plane. Again by the first part, there is a point 7] E V - a2 ( -=) and, by Lemma 3.3, a geodesic a3 from a2 (-=) to 7] which does not bound a flat half plane. By Lemma 3.2, there is a f-closed geodesic a as claimed. D 3.5 Theorem. Let X and f be as in Theorem 3.4. Suppose X (=) contains at least three points. (i) If X is geodesically complete, then the geodesic flow is topologically transitive mod f. (ii) f contains free non-abelian subgroups.
Proof. (i) This is immediate from Theorem 2.4. Alternatively we can argue as follows: Theorem 3.4 and Lemma 3.3 imply that the f-orbit of any point ~ E X(=) is dense in X (=). Hence the geodesic flow of X is topologically transitive mod f by Theorem 2.3. (ii) By the first assertion of Theorem 3.4, X (=) contains non-empty open subsets WI, W 2 with
By the second assertion of Theorem 3.4 and Lemma 3.3, f contains isometries
'PI, 'P2 with axis aI, a2 which do not bound flat half planes such that ai (±=) E Wi and
Chapter III: Weak hyperbolicity
54
for all k =1= o. Let ~ E X(oo) \ (WI U W 2 ). It follows from (*) and (**) that a non-trivial word w in
<
~(d(r(a), 0") + d(r(b), 0")).
It is unclear whether a geodesically complete Hadamard space X (with reasonable additional assumptions like local compactness and/or large group of isometrics) contains a hyperbolic unit speed geodesic (in the above sense or a variation of it) if it contains a unit speed geodesic which does not bound a flat half plane. Let X be a geodesically complete and locally compact Hadamard space. Then the set GhX of hyperbolic geodesic is open in GX and invariant under isometries and the geodesic flow.
3.8 Corollary. Let X be a geodesically complete and locally compact Hadamard space and r a group of isometries of X satisfying the duality condition. If X contains a hyperbolic geodesic, then the set of hyperbolic r -closed geodesics is dense in GX.
Harmonic functions and random walks
55
Proof. By Lemma 3.2, any hyperbolic geodesic (J is the limit of a sequence ((In) of r-closed geodesics. Since GhX is open in GX, (In is hyperbolic for n large. Now Theorem 3.5(i) implies that GhX is dense in GX. 0 4. Harmonic functions and random walks on
r
Let X be a locally compact Hadamard space containing a unit speed geodesic lR ----+ X which does not bound a flat half plane and r a countable group of isometrics of X satisfying the duality condition. Assume furthermore that X (00) contains at least three points. Suppose 11 is a probability measure on r whose support generates r as a semigroup. We say that a function h : r ----+ lR is l1-harrnonic if (J
:
(4.1)
h(lp) =
L
h(lp1/J)I1(1/J)
for alllp E r.
,pEr Our objective is to show that r admits many l1-harmonic functions. We define the probability measures ILk, k ~ 0, on r recursively by 11() := 15, the Dirac measure at the neutral clement of r, and
(4.2)
I1 k (lp) =
L
k IL -
l (1/J)I1(1/J-llp)
k ~ 1.
,pEr Then III = 11. An easy computation shows that h : r ----+ lR is 11k-harmonic if his l1-harmonic. Now the support of 11 generates r as a semigroup and hence for any lp E r there is a k ~ 1 such that I1 k (lp) > O. For k, l ~ 0 we also have ILk * III = I1 k +l , where
11 k
(4.3)
* I1 I (lp) =
L
11 k (1/J)11 1(1/J-llp) .
.pEr For a probability measure v on X (00) and k ~ 0 define the convolution 11 k
where
*v
by
f is a bounded measurable function on X(oo). Then
(4.5) Since the space of probability measures on X (00) is weakly compact, the sequence 1
~~ (v
n+1
+ 11 * v + 11 * IL * V + ... + (11* Y' v)
Chapter III: Weak hyperbolicity
56
has weakly convergent subsequences, and a weak limit D will be stationary (with respect to JL), that is, JL * D = D. Thus the set of stationary probability measures is not empty. Now let 1/ be a fixed stationary probability measure. By (4.5) we have
(4.6)
JLk
* 1/ =
1/
for all k 2: 0 .
If there is a point ~ E X(oo) such that 1/(0 > 0, then there is also a point ~o E X (00) such that 1/( ~o) is maximal since 1/ is a finite measure. For k 2: 1, the definition of JLk * 1/ implies
I/(~o) =
L 1/('P~l~O)JLk('P), r
and thus 1/('P~l~O) = I/(~o) for all 'P in the support of JLk by the maximality of I/(~o), But for any 'P E r there is k 2: 1 such that JLk('P) > O. Hence 1/('P-l~O) = I/(~o) for all 'P E r. But this is absurd since the orbit of ~o under r is infinite. Hence
(4.7)
1/ is not supported on points.
Thus for any ~ E X ((0) and E > 0 there is a neighbourhood U of ~ such that I/(U) < E. Let 1 be a bounded measurable function on X (00). Define a function h f on r by
(4.8)
hf('P) =
J
X(oo)
Since we have JL
* 1/ =
1('P~)dl/(O
=
J
X(oo)
I(Od('PI/)(~).
1/ we obtain
and therefore hf is a JL-harmonic function. We will show now that hf('Pn) ----> 1(0 if ~ is a point of continuity of 1 and if 'Pn(x) ----> ~ for one (and hence any) x E X.
4.9 Lemma. Let Xo E X, R > 0 and E > 0 be given. Let ('Pn) C r be a sequence such that 'PnXO ----> ~ E X (00 ). Then there is an open subset U C X (00) with I/(U) < E: and a 'P E r such that for some subsequence ('Pnk) of ('Pn) we have 'Pnk'P(X \ U) C U(xO,~,R,E).
Proof. After passing to a subsequence if necessary we may assume 'P;;-lXO ----> TJ E X(oo). By Theorem 3.4 there is a 'Po E r with an axis (J which does not bound a flat half plane and with open neighborhoods U~ of CJ( -(0) and U+ of (J( (0) in X such that TJ E X \ U+ and U~ n U(xO,~,R,E) = 0.
Harmonic functions and random walks
57
By increasing R and diminishing E and U- if necessary we can assume Xo r:f- Uand v(U-) < E. By Lemmas 3.1 and 3.3 there is a neighborhood V- of 0"(-00) in U- such that for any two points y, z E X \ U- and any x E V- the geodesics O"x,y and O"x,z exists and d(O"x,y(t),O"x,z(t)) < E/2 for 0:::; t:::; R. Now choose N so large that
and let 'P = 'Pr:. If n is large, then 'P;;:lxO E X \ U+ since 'P;;:lxO ----7 "I. Then x = 'P-1'P;;:lxO E V- and for y E X \ U- arbitrary we get, for 0 :::; t :::; R,
d( O"xQ,~ (t), 0" ,'Pn'P(Y) (t)) XQ
:::; d(O"xQ,~(t), O"xQ,'Pn'P(xQ) (t)) + d(O"XQ,'Pn'P(XQ) (t), O"XQ,'Pn'P(y) (t)) . The first term on the right hand side tends to 0 as n tends to 00 since 'Pn ('Pxo) ----7 ~. The second term is less than E /2 for n sufficiently large since Xo, Y E X \ U-. Hence 'Pn'P(X \ U-) c U(xo,~, R, E) for all n sufficiently large. 0
4.10 Theorem (Dirichlet problem at infinity). Let X be a locally compact Hadamard space containing a unit speed geodesic 0" : ffi. ----7 X which does not bound a fiat half plane. Assume that X (00) contains at least 3 points. Suppose that r is a countable group of of isometries of X satisfying the duality condition and that J-L is a probability measure on r whose support generates r as a semigroup. Then we have: if f is a bounded measurable function on X (00) and ~ E X (00) is a point of continuity for f, then h f is continuous at L that is, if ('Pn) C r is a sequence such that 'PnX ----7 ~ for one (and hence any) x EX, then h f ('Pn) ----7 f (~). In particular, if f : X (00) ----7 ffi. is continuous, then h f is the unique J-L-harmonic function on r extending continuously to f at infinity. Proof. Without loss of generality we can assume 1(0 = O. If there is a sequence ('Pn) C r such that 'PnXO ----7 ~ and such that hf('Pn) does not tend to f(~), then there is such a sequence ('Pn) with the property that lim sUPn---> 00 Ihf('Pn)1 is maximal among all these sequences. We fix such a sequence and set 8 = lim sup Ihf('Pn)l. n--->oo By passing to a subsequence if necessary we can assume that the lim sup is a true limit. Since ~ is a point of continuity of f, there are R > 0 and E > 0 such that
If(TJ)1 < 8/3 for all "I E X(oo) n U(xO,~,R,E). By Lemma 4.9 there is a'P E r and an open subset U of X(oo) such that v(U) < E and 'Pnk'P(X(OO) \ U) C U(xO,~,R,E) for a subsequence ('Pnk) of ('Pn). Then
Ihf('Pnk'P)I:::;
I
r
}X(oo)\U
f('Pnk'PTJ)dV(TJ)!
+
11
U
f('Pnk'PTJ)dv(TJ) I
:::; v(X(oo) \ U) ·8/3 + v(U) sup If I·
Chapter III: Weak hyperbolicity
58
Hence Ihf('Pnk'P)1 :::; 8/2 for all k if we choose E > 0 small enough. Now there is a k 2: 1 such that J1k ('P) = a > O. We split r into three disjoint parts G,L and {'P}, where G is finite and J1k(L) sup IfI < a8/2. Since h f is J1k-harmonic we get lim sup Ihf('Pnk)1 k---'ooo
= limsup!L: hf('Pnk 'l/J)J1k('l/J)J k---'ooo
r
:::; limsuplL: hf('Pnk 'l/J)J1k('l/J)!+ lim sup Ihf('Pnk'P)la + a8/2 k---'ooo
G
k---'ooo
< J1(G) ·8+ a8/2 + a8/2 :::; (1 - a)8 + a8 = 8. This is a contradiction.
D
We now consider the left-invariant random walk on r defined by J1; that is, the transition probability from 'P E r to 'l/J E r is given by J1('P- 1 'l/J). For 'l/Jl, ... ,'l/Jk E r, the probability P that a sequence ('Pn) satisfies 'Pi = 'l/Ji, 1 :::; i :::; k, is by definition equal to
Since the support of J1 generates r and since r is not amenable (r contains a free subgroup), random walk on r is transient, see [Fu3, p.212], that is, d(x, 'Pnx) -7 00 for P-almost any sequence ('Pn) cr. An immediate consequence of Theorem 4.10 and the Martingale Convergence Theorem is the following result. 4.11 Theorem. Let X, rand J1 be as in Theorem 4.10. Then for almost any sequence ('Pn) in r, the sequence ('Pnx), x EX, tends to a limit in X (00). The hitting probability is given by v. In particular, the stationary measure l/ is uniquely determined.
Proof. If h is a bounded J1-harmonic function, then Md('Pn)) := h('Pk), k 2: 1, defines a martingale and hence M k(('Pn)) converges P -almost surely by the Martingale Convergence Theorem, see [Fu3]. Let ~ i= 'rJ E X(oo) and let U, V be neighborhoods of U and V in X(oo). Then there is a continuous function f on X (00) which is negative at ~, positive at 'rJ and 0 outside UuV. Applying the Martingale Convergence Theorem in the case h = h f we conclude that the set of sequences ('Pn) in r such that ('Pn (x)), x EX, has accumulation points close to both ~ and 'rJ has P-measure O. Now X(oo) is compact, hence the first assertion. Let f : X(oo) -7 JR be continuous and set Mk(('Pn)) = hf('Pk), k 2: 1. If 7r denotes the hitting probability at X (00), then
Harmonic functions and random walks
59
On the other hand, since (Mk ) is a martingale,
J
(lim Mk)dP =
J
MkdP
hf(e) =
Hence v =
7r
and the proof is complete.
J
fdv
0
We may ask whether (X (00), v) is the Poisson boundary of (f, /1,). By that we mean that the assertions of Theorem 4.11 hold and that every bounded pharmonic function h on f is given as h = hf, where f is an appropriate bounded measurable function on X (00). This is true if X, f and p satisfy the assumptions of Theorem 4.10 and (i) f is finitely generated and p has finite first moment with respect to the word norm of a finite system of generators of f; (ii) f is properly discontinuous and cocompact on X. For the proof (in the smooth case) we refer to [BaLl]; see alsox [Kai3, Theorem 3] for a simplification of the argument in [BaLl]. We omit a more elaborate discussion of the Poisson boundary since the relation between cocompactness on the one hand and the duality condition on the other is unclear (as of now). For the convenience of the reader, the Bibliography contains many references in which topics related to our random walks are discussed: Martin boundary, Brownian motion, potential theory ... for Hadamard spaces and groups acting isometrically on them.
CHAPTER IV
Rank Rigidity In this chapter we prove the Rank Rigidity Theorem. The proof proper is in Sections 4-7, whereas Sections 1-3 are of a preliminary nature. The initiated geometer should skip these first sections and start with Section 4. In Section 1 we discuss geodesic flows on Riemannian manifolds, in Section 2 estimates on Jacobi fields in terms of sectional curvature (Rauch comparison theorem) and in Section 3 the regularity of Busemann functions. 1. Preliminaries on geodesic flows
Let M be a smooth n-dimensional manifold with a connection D. Let T M be the tangent bundle of M and denote by 7r : T M ----+ M the projection. Recall that the charts of M define an atlas for T M in a natural way, turning T Minto a smooth manifold of dimension 2n. Namely, if x: U ----+ U' C jRn is a chart of M and
are the basic vector fields over U determined by x, then we define
(1.1 )
x: 7r- 1 (U)
----+
U' x
jRn;
x(v) = (x(p), dx Ip(v)) ,
where p = 7r(v). If we write vasa linear combination of the Xi(p),
then (~1, ...
,C) -'
~(v)
and hence
where x = x 0 7r. It is easy to see that the family of maps X, where x is a chart of M, is a COO-atlas for TM.
Chapter IV: Rank rigidity
62
The connection D allows for a convenient description of TTM, the tangent bundle of the tangent bundle. To that end, we introduce the vector bundle [; ---+ TM, [; = 7r*(TM) EB 7r*(TM). The fibre [;v of [; at v E TM is (1.2) where p = 7r( v) is the foot point of v. We define a map I : TT M (1.3)
I(Z) = (c(O),
---+ [;
as follows:
~~ (0)) ,
where V is a smooth curve in TM with V(O) = Z and c = 7r 0 V. To see that (1.3) defines a map TTM ---+ [;, we express it in a local coordinate chart i: as above. Then i: 0 V = (0",0, where 0" = x 0 c and V = L ~i Xi. Hence
is represented by
(1.4) where r denotes the Christoffel symbol with respect to the chart x and where we use i: EB i: as a trivialization for [;. We conclude that I is well-defined, smooth and linear on the fibres. It is easy to see that I is surjective on the fibres. Now I is bijective since the fibres of TT M and [; have the same dimension 2n. Therefore: 1.5 Lemma. The map I : TTM
---+ [;
is a vector bundle isomorphism.
1.6 Exercise. For a coordinate chart x and a tangent vector v = the beginning of this section show that
0
LeXk (p)
as in
and
e
where V = L X k is the "constant extension" of v to a vector field on the domain of the coordinate chart x. Henceforth we will identify TTM and [; via I without further reference to the identification map I.
Geodesic flows
63
For v E TTM and p
= 1f(v),
the splitting
singles out two n-dimensional subspaces. The first one is the vertical space
(1.7)
Vv
= ker1f*v = {(a, Y) lYE TpM}.
The vertical distribution V is smooth and integrable. The integral manifolds of V are the fibres of 1f, that is, the tangent spaces of M. Here we visualize the tangent spaces of M as vertical to the manifold ~ a convenient picture when thinking of TM as a bundle over M. The second n-dimensional subspace is the horizontal space
(1.8)
Hv
=
{(X,D) I X E TpM}.
The horizontal distribution H of T M is smooth but, in general, not integrable. By definition, a curve V in T M is horizontal, that is, V belongs to H, if and only if V' == 0, where V' denotes the covariant derivative of V along 1f0 V; in other words, V is horizontal if and only if V is parallel along c = 1f 0 V. The map, which associates to two smooth horizontal vector fields X, Yon T M the vertical component of [X, YJ, is bilinear and, in each variable, linear over the smooth functions on TM. Hence the vertical component of [X, YJ at v E TM only depends on X(v) and Y(v). To measure the non-integrability of H, it is therefore sufficient to consider only special horizontal vector fields. Now let X be a smooth vector field on M. The horizontal lift XH of X is defined by
(1.9)
XH(v) = (X(1f(v)),O),
V
E
TM.
By definition, X is 1f-related to XH, that is, 1f* 0 XH = X 0 1f. This allows us to express the Lie bracket of horizontal lifts of vector fields X, Y on M in a simple way. 1.10 Lemma. Let X, Y be smooth vector fields on M. Then
where p = 1f(v) and the index p indicates evaluation at p. Proof. Since X and Yare 1f-related to XH and yH respectively, we have
This shows the claim about the horizontal component.
Chapter IV: Rank rigidity
64
Since the vertical component only depends on X p and Yp , it suffices to consider the case that [X, Y] = 0 in a neighborhood of p. Denote by 'Pt the flow of X and by 'ljJs the flow of Y. Then the flows
Since [X, Y] = 0 in a neighborhood of p, V(t) E TpM for all t sufficiently small and 1 [X H, yH](v) = lim -2 (V(t) - v). t--->O
t
The RHS is precisely the formula for R(Yp, Xp)v using parallel translation.
0
1.11 Exercise. Show that [XH, Zj = 0, where XH is as above and Z is a smooth vertical field of T M.
Recall that the geodesic flow (l) acts on T M by (1.12) where D v denotes the maximal interval of definition for the geodesic "'Iv determined by 1'v(O) = v. By definition, the connection is complete if D v = ~ for all v E TM. To compute the differential of the geodesic flow, let vETM and (X, Y) E TvTM. Represent (X, Y) by a smooth curve V through v, that is, C(O) = X for c = 7r 0 V and DV (0)
dt
=
Y. Let J be the Jacobi field of the geodesic variation "'IV(s) of "'Iv.
By the definition of the splitting of TTM we have
g;v(X, Y) =
:sgt(V(S))ls=o (:s "'IV(s) (t), (J(t),
~
:s
~ 1'V(s) (t)) Is=o
"'IV(s) (t)) Is=o
(J (t), J' (t)) , where the prime indicates covariant differentiation along "'Iv. Hence: 1.13 Proposition. The differential of the geodesic flow is given by
g;v(X, Y) = (J(t), J'(t)), where J is the Jacobi field along "'Iv with J(O) = X and J'(O) = Y.
0
We now turn our attention to the case that D is the Levi-Civita connection of a Riemannian metric on M. By using the corresponding splitting of TT M, we obtain a Riemannian metric on TM, the Sasaki metric,
(1.14)
Geodesic flows
65
There is also a natural I-form
0:
on TM,
O:v((X, Y)) = < v, X>
(1.15)
Using Lemma 1.10 it is easy to see that the differential w = do: is given by (1.16) The Jacobi equation tells us that w is invariant under the geodesic flow. The I-form 0: is not invariant under the geodesic flow on T M.
1.17 Exercise. Compute the expressions for 0: and w with respect to local coordinates i = (x,~) as in the beginning of this section. Note that w is a nondegenerate closed 2-form and hence a symplectic form on TM. The measure on TM defined by Iwnl is proportional to the volume form of the Sasaki metric. It is called the Liouville measure. The Liouville measure is invariant under the geodesic flow since wis. Denote by SM c TM the unit tangent bundle. We have (1.18)
TvSM
=
{(X,Y) I X,Y E TpM, Y 1.. v},
where v E SM and p = 1f(v). The geodesic flow leaves SM invariant. The restrictions of 0: and w to S M, also denoted by 0: and w respectively, are invariant under the geodesic flow since < 1v, J >= const if J is a Jacobi field along '"'Iv with J' 1.. 1v. The (2n - I)-form 0: 1\ w n - 1 is proportional to the volume form of the Sasaki metric (1.14) on SM. In particular, 0: is a contact form. The measure on SM defined by 0: 1\ w n - 1 is also called the Liouville measure. It is invariant under the geodesic flow on SM since 0: and w = do: are. A first and rough estimate of the differential of the geodesic flow with respect to the Sasaki metric is as follows, see [BBB1].
1.19 Proposition. For v E SM set RvX
IIg~ (v) I
:::;
exp
(~
R(X, v)v. Then we have
=
I Ilid t
Rgs(v) lidS)
Proo]. Let J be a Jacobi field along '"'Iv. Then
((1, J)
+ (J', 1'))'
2 (1', J 2
+ JII)
\1', (id -
Rgs(v))
J)
< 211JII ·IIJ'II·llid - RgS(v)11
< ((J, J) + (1', J')) Ilid - Rgs(v) II
o We finish this section with some remarks on the geometry of the unit tangent bundle.
Chapter IV: Rank rigidity
66
1.20 Proposition [Sas]. A smooth curve V in SM is a geodesic in SM if and only if V" = ~ < V', V' > V and e' = R(V', V)e,
where c =
7f 0
V and prime denotes covariant differentiation along c.
Proof. The energy of a piecewise smooth curve V: [a, b]
E(V) =
~
l
b
IIel1 2 dt + ~
l
----+
SM is given by
b
11V'11 2 dt.
The second integral is the energy of the curve V in the unit sphere at c(O) obtained by parallel translating the vectors V(t) along c to V(O). Assume V is a critical point of E. By considering variations of V which leave fixed the curve c of foot points and V(a) and V(b), we see that V is a geodesic segment in the unit sphere. Hence V satisfies the first equation. Now consider an arbitrary variation V(s,·) of V with foot point c(s,·) which keeps V(-, a) and V(·, b) fixed. Then
o ~~ =
l l
b
l
=
[(
~ e, c) + ( ~ V', V')] dt
~ ~: c) + (~ ~ V, V') + ( R ( ~:' ~~) V, V') ] dt [~ (~:' c))- (~:' e') + :t ((~ V, V') ) '
[( b
b
(
Note that
l
b
:t
(~:' c) dt
(~ V, V" ) = 0 =
l
+ ( R(V', V)e,
b
:t
~:) ] dt .
(~ V, V' ) dt
since c(s,a),c(s,b), V(s,a), and V(s,b) are kept fixed. Also ((D/ds)V, V") = 0 since V" and V are collinear by the first equation and (( D / ds) V, V) = 0 because V is a curve of unit vectors. Hence the second equation is satisfied. Conversely, our computations show that V is a critical point of the energy if it satisfies the equations in Proposition 1.20. 0 1.21 Remarks. (a) The equations in Proposition 1.20 imply
(V', V')' = 0 = (e, c)' and therefore
IIV'II
= const.
and
Ilell
= const.
(b) The great circle arcs in the unit spheres SpM, p EM, are geodesics in SM. In particular, we have that the Riemannian submersion 7f : SM ----+ M has totally geodesic fibres. (c) If V is horizontal, then V is a geodesic if and only if c = 7f 0 V is a geodesic in M.
Jacobi fields and curvature
67
1.22 Exercise. Let M be a surface and V a geodesic in the unit tangent bundle of M. Assume that V is neither horizontal nor vertical. Then V' =/=- 0 and c =/=- 0, where c = 7f 0 V, and
-IIV'11 2 . V(t) IIV'II WK(c(t))
VI/ (t)
k(t)
where k is the geodesic curvature of c with respect to the normal n such that (c, n) and (V, V') have the same orientation and K is the Gauss curvature of M. Use this to discuss geodesics in the unit tangent bundles of surfaces of constant Gauss curvature. 2. Jacobi fields and curvature
In Proposition 1.13 we computed the differential of the geodesic flow (gt) on TM in terms of the canonical splitting of TTM. We obtained that
g:,JX, Y) = (J(t), J'(t)),
(2.1)
where J is the Jacobi field along the geodesic Iv with J(O) = X and J'(O) = Y. In order to study the qualitative behaviour of (gi) it is therefore useful to get estimates on Jacobi fields. 2.2 Lemma. Let I : lR ----> M be a unit speed geodesic, and suppose that the sectional curvature of M along I is bounded from above by a constant f'. If J is a Jacobi field along I which is perpendicular to 'Y, then IIJIII/(t) 2: -kIIJII(t) for all t with J(t) =/=- O.
Proof. The straightforward computation does the job:
II J 1
1/
= =
o
J',J »'
«
IIJ
IIJII
I1
3 (-
=
1
(
IIJI1 2 < J
< R(J, 'Yh, J
>
1/
II I
,J > J
+<J
" I I I < J',J >2) , J > ,J IIJII
11111 2 + IIJ'11 2 11J11 2 - <
J', J
>2)
2:
-kIIJII.
The same computation gives the following result. 2.3 Lemma. Let I : lR ----> M be a unit speed geodesic and suppose that the sectional curvature of M along I is nonpositive. If J is a Jacobi field along I (not necessarily perpendicular to 'Y), then II J( t) I is convex as a function of t. In particular, there are no conjugate points along I. 0
For f' E lR denote by sn K respectively cS K the solution of (2.4)
j"
+ f'j =
0
with snK(O) = 0, sn~(O) = 1 respectively csK(O) = 1, cs~(O) = 1. Then sn~ = cS K • , sn K cS K and cS K = -f'sn K. We also set tg K = and ct K = - . Lemma 2.2 Implies the cS K sn K following version of the Rauch Comparison Theorem.
Chapter IV: Rank rigidity
68
2.4 Proposition. Let 'Y : JR. ----+ M be a unit speed geodesic and suppose that the sectional curvature of M along 'Y is bounded from above by a constant K. If J is a Jacobi field along 'Y with J(O) = 0, J'(O) 1- 1'(0) and IIJ'(O)II = 1, then
IIJ(t)11 2: sn,,(t)
and
IIJII'(t) 2: ct,,(t)IIJ(t)11
for 0 < t < 7r/...[K,. Proof. For any Jacobi field J along 'Y and perpendicular to of (2.4) we have by Lemma 2.2
l' and any solution j
(11JII'j - II Jill)' 2: 0 wherever j and IIJII are positive. For J as in Proposition 2.4, lim 1IJ11(t) = lim IIJII'(t) = 1 sn,,(t) t-+O+ sn~(t)
hO+
by I'Hospital's rule. Hence IIJII'(t) 2: ct,,(t)IIJ(t)11
and
IIJ(t)11 2: sn,,(t)
for t small and then, by continuation, for all t as claimed.
0
The proof of the estimates for Jacobi fields in the case of a lower bound on the curvature is different. 2.5 Proposition. Let 'Y : JR. ----+ M be a unit speed geodesic and suppose that the sectional curvature of M along'Y is bounded from below by a constant A. If J is a Jacobi field along 'Y with J(O) = 0, J'(O) .1 1'(0) and IIJ'(O)II = 1, then
IIJ(t)11 :::; sn,\(t)
and
IIJ'(t)11 :::; ch(t)IIJ(t)11
if there is no pair of conjugate points along 'Y I [0, t]. For the proof of this version of the Rauch Comparison Theorem we refer to [Kar], [BuKa]. In the rest of this section we deal with manifolds of nonpositive or negative curvature. The infinitesimal version of the Flat Strip Theorem I.5.8(ii) is as follows. 2.6 Lemma. Let M be a manifold of nonpsitive curvature and 'Y : JR. ----+ M a unit speed geodesic. Let J be a Jacobi field along "(. Then the following conditions are equivalent: (i) J is parallel; (ii) IIJ(t)11 is constant on JR.; (iii) IIJ(t)11 is bounded on JR.. Each of these condition implies that < R(J, i'h, J >== O.
Proof. Clearly (i) =} (ii) =} (iii). Now (iii) Lemma 2.3. If IIJ(t)11 is constant, then
and hence (i). 0
=}
(ii) since IIJ(t)11 is convex in t, see
o = < J,J >" = 2 « J',J' > - < R(J,i'h,J ». J'(t) == 0 since the sectional curvature is nonpositive.
Hence (ii)
=}
Jacobi fields and curvature
69
2.7 Definition. Let M be a manifold of nonpositive curvature and 1 : JR -. M a unit speed geodesic. We say that a Jacobi field J along 1 is stable if IIJ(t)11 :::; 0 for all t 2': 0 and some constant 0 2': O. 2.8 Proposition. Let M be a manifold of nonpositive curvature and 1 : JR -. M a unit speed geodesic. Set p = 1(0). (i) For any X E TpM, there exists a unique stable Jacobi field J x along 1 with Jx(O) = X. (ii) Let (1n) be a sequence of unit speed geodesics in M with 1n -. 1. For each n, let I n be a Jacobi field along 1n. Assume that In(O) -. X E TpM and that IIJn(tn)11 :::; 0, where t n -. 00 and 0 is independent of n. Then I n -. J x and J~ -. J'x. Proof. Uniqueness in (i) follows from the convexity of IIJ(t)ll. Existence follows from (ii) since we may take 1n = 1 and I n the Jacobi field with In(O) = X, In(n) = 0 (recall that 1 has no conjugate points). Now let 1n, I n , t n and 0 be as in (ii). Fix m 2': o. By convexity we have IIJn(t) II :::; 0,
0:::; t :::; m,
for all n with t n 2': m. By a diagonal argument we conclude that any subsequence (nk) has a further subsequence such that the corresponding subsequence of Un) converges to a Jacobi field J along 1 with IIJ(t)11 :::; 0 for all t 2': o. Now the uniqueness in (i) implies J = J x and (ii) follows. 0 2.9 Proposition. Let M be a manifold of nonpositive curvature, 1 : JR -. M a unit speed geodesic and J a stable Jacobi field along 1 perpendicular to "y. (i) If the curvature of M along 1 is bounded from above by /'i, = _a 2 :::; 0, then
IIJ(t)11 :::; IIJ(O)lle- at
and
IIJ'(t)11 2': aIIJ(t)11
for all t 2':
(ii) If the curvature of M along 1 is bounded from below by ,\ = _b
IIJ(t)11 2': IIJ(O)lle-
bt
and
IIJ'(t)11 :::; bIIJ(t)11
2
:::;
for all t 2':
o. 0, then
o.
Proof. Let I n be the Jacobi field along 1 with In(O) = J(O) and In(n) = 0, n 2': l. Then I n - . J and J~ -. J' by the previous lemma. If /'i, = -a 2 :::; 0 is an upper bound for the curvature along 1, then by Proposition 2.4
IIJn(t)11 < sinh(a(n - t)) IIJn(O)11 sinh(an) and IlJnll'(t) :::; -acoth(a(n - t))lIJn(t)ll, where we have sn,,(s) =
~ sinh(as) a
0
< t < n,
(:= s if a = 0) and ct,,(s) = acoth(as) (:=
1 if a = 0). Hence (i). In the same way we conclude (ii) from Proposition 2.5.
0
The following estimate will be needed in the proof of the absolute continuity of the stable and unstable foliations in the Appendix on the ergodicity of geodesic flows.
Chapter IV: Rank rigidity
70
Proposition 2.10. Let M be a Hadamard manifold and assume that the sectional KM of M is bounded by -b 2 ::; K M ::; -a 2 < O. Denote by d s the distance in the unit tangent bundle SM of M. Then for every constant D > 0 there exist constants C = C(a, b) ~ 1 and T = T(a, b) ~ 1 such that
where v, ware inward unit vectors to a geodesic sphere of radius R with foot points x, y of distance d( x, y) ::; D
~
T in M
Proof. Since the curvature of M is uniformly bounded, the metric
is equivalent to ds and therefore it suffices to consider d1 . For the same reason, there is a constant C 1 > 0 such that the interior distance of any pair of points x, y on any geodesic sphere in M is bounded by C 1 d(x, y) as long as d(x, y) ::; D. Now the interior distance of IV(t) and IW(t) in the sphere of radius R - t about p = Iv(R) = Iw(R) can be estimated by a geodesic variation Is, 0::; s ::; 1, such that 10 = Iv, 11 = IW' Is(R) = P and IS(O) E Sp(R), 0 ::; s ::; 1. Arguing as in the proof of Proposition 2.9, we conclude that there is a constant C 2 such that the asserted inequality holds for 0 ::; t ::; R - 1 (recall that we are using the distance dd. Now the differential of the geodesic flow gT, 0 ::; T ::; 1, is uniformly bounded by a constant C 3 = C 3 (b), see Proposition 1.19. Hence C = C 2 C 3 ea is a constant as desired. 0
3. Busemann functions and horospheres We come back to the description of Busemann functions in Exercise II.2.6.
3.1 Proposition. Let M be a Hadamard manifold and let p E M. Then a function f : M ----+ lR is a Busemann function based at p if and only if (i) f(p) = 0; (ii) f is convex; (iii) f has Lipschitz constant 1; (iv) for any q E M there is a point ql EM with f(q) - f(qd = 1. Proof. Let f: M ----+ lR be a function satisfying the conditions (i)-(iv). Let q E M be arbitrary. Set qo := q and define qn, n ~ 1, recursively to be a point in M with d(qn, qn-l) = 1 and f(qn) - f(qn-d = -1. Let IJ n : [n - 1, n] ----+ M be the unit speed geodesic segment from qn-l to qn, n ~ 1. Since f has Lipschitz constant 1, the concatenation IJ q := IJI * IJ2 * ... : [0, (0) ----+ !vI is a unit speed ray with
f(q)-t,
t~O.
Busemann functions and horospheres
71
We show now that all the rays a q , q E M, are asymptotic to a p ' We argue by contradiction and assume that a q(00) -I- a p (00). Let a be the unit speed ray from p with a(oo) = aq(oo). Then d(a(t),ap(t)) ---> 00 and there is a first tl > 0 such that d(a(td,ap(td) = 1. For t;::: tl we have 1 2t 1 '
a=-
by comparison with Euclidean geometry. Hence the midpoint Tnt between a(t) and ap(t) satisfies
Now
f
is convex and Lipschitz, hence
f(Tnt) ::;
1
"2 (f(a(t) + f(ap(t))) 1
::; "2 (J(aq(t)) +f(ap(t)) +d(p,q)) < -t+C, where C = (d(p,q) + f(q))/2 This contradicts (*). It follows easily that f is a Busemann function. The other direction is clear.
o
The characterization in Proposition 3.1 implies that Busemann functions are cf. [BGS, p.24]. Using that Busemann functions are limits of normalized distance functions, we actually get that they are C 2 . For ~ E M ((0) and p E M let ap,E, be the unit speed ray from p to ~ and set vE,(p) = o-p,E,(O).
Cl,
3.2 Proposition (Eberlein, see [HeIH]). Let M be a Hadamard manifold, p E M and ~ E M(oo). If f = b(~,p,.) is the Busemann function at ~ based at p, then f is C 2 and we have gradf = -vE,
and
D x gradf(q) = -J~(O), q E M ,X E TqM,
where J x is the stable Jacobi field along aq,E, with Jx(O)
Proof. Let (Pn) be a sequence in M converging to
~
= X.
and let
Then fn ---> f uniformly on compact subsets of M. The gradient of fn on }vf \ {Pn} is the negative of the smooth field of unit vectors V n pointing at Pn. Now
By comparison with Euclidean geometry, the right hand side tends to 0 uniformly on compact subsets of M as n ---> 00. Hence f is C 1 and grad f = -vE,'
Chapter IV: Rank rigidity
72
Now let X be a smooth vector field on M. Then
DX(q)gradfn = -J~(q,O), where In(q,.) is the Jacobi field along (Jq.Pn with In(O) = X(q) and In(q, t n ) = 0, where t n = d(q,Pn). By Proposition 2.8, J~(q,O) tends to J~(q)(O) uniformly on compact subsets of M. Hence f is C 2 and the covariant derivative of grad f is as asserted. 0 3.3 Remark. In general, Busemann functions are not three times differentiable, even if the metric of M is analytic, see [BBB2]. However, if the first k derivatives of the curvature tensor R are uniformly bounded on M and the sectional curvature of M is pinched between two negative constants, then Busemann functions are C k +2 . For v E SM set v(oo) := T'v(oo). We define
WSO(v) For v fixed and
~ =
= {w
E SM I w(oo)
= v(oo)}.
v( 00), WSO(v)
=
{-gradf(q) I q E M}.
where f is a Busemann function at ~. Proposition 3.2 implies that WSO(v) is a C 1_ submanifold of SM. The submanifolds W so ( v), v E S M, are a continuous foliation of SM. By Proposition 3.2, the tangent distribution of W So is
ESO(v)
= {(X, Y) I Y =
J~(O)},
where J x is the stable Jacobi field along T'v with Jx(O) the foliation WSo is a very intricate question.
=
X. The regularity of
Remark 3.4. The following is known in the case that M is the universal cover (in the Riemannian sense) of a compact manifold of strictly negative curvature: (a) For each v E SM, WSO(v) is the weak stable manifold of v with respect to the geodesic flow and hence smooth. (Compare also Remark 3.3.) (b) The foliation W so is a smooth foliation of S M if and only if M is a symmetric space (of rank one), see [Gh, BFL, BCG]. (c) If the dimension of M is 2 or if the sectional curvature of M is strictly 1 negatively :i-pinched, then the distribution ESO is C 1, see [HoI, HiPu]. If the
dimension of Mis 2 and ESO is C 2, then it is Coo, see [HurK]. (d) The foliation WSo is Holder and absolutely continuous, see [Anol], [AnSi] and the Appendix below.
Rank, regular vectors and flats
73
4. Rank, regular vectors and flats
As before, we let M be a Hadamard manifold and denote by 8M the unit tangent bundle of M. For a vector v E 8M, the rank of v is the dimension of the vector space .:JP(v) of parallel Jacobi fields along "(V and the rank of M is the minimum of rank(v) over v E 8M. Clearly we have rank(w) ~ rank(v) for all vectors in a sufficiently small neighborhood of a given vector v E 8M. We define R, the set of regular vectors in 8M, to be those vectors v in 8M such that rank(w) = rank(v) for all w sufficiently close to v. The set of regular vectors of rank m is denoted by R m . The sets Rand R m are open. Moreover, R is dense in 8M since the rank function is semicontinuous and integer valued. If k = rank(M), then the set R k is nonempty and consists of all vectors in 8M of rank k. For v E 8M we can identify TvTM with the space .:J(v) of Jacobi fields along "(V by associating to (X, Y) E TvTM the Jacobi field J along "( with J(O) = X, J'(O) = Y. We let F(v) be the subspace of Tv8M corresponding to the space .:JP(v) of parallel Jacobi fields along "(v' That is, F(v) consists of all (X,O) such that the stable Jacobi field J x along "(v determined by Jx(O) = X is parallel. The distribution F is tangent to 8M and invariant under isometries and the geodesic flow of M. Note that F has constant rank locally precisely at vectors in R. On each nonempty set R m , m ::::: rank(M), F has constant rank m, and we shall see that F is smooth and integrable on R m . Moreover, for each vector v E R m the integral manifold of F through v contains an open neighborhood of v in the set P (v) of all vectors in 8M that are parallel to v. 4.1 Lemma. For every integer m ::::: rank( M), the distribution F is smooth on R m
.
Proof. For each vector v E R m , we consider the symmetric bilinear form
where X, Yare arbitrary parallel vector fields (not necessarily Jacobi) along "(v' Here R denotes the curvature tensor of M, and T is a positive number. Since the linear transformation w ----+ R( w, "'tv)"'tv is symmetric and negative semidefinite, a parallel vector field X on "(v is in the nullspace of Q'T if and only if for all t E [-T,T] Hence such a vector field X is a Jacobi field on "(v [- T, T]. It follows that for a small neighborhood U of v in R m and a sufficiently large number T the nullspace of Q'T is precisely .:JP(w) for all w E U. For a fixed T the form Q'T depends smoothly on w. Since the dimension of the nullspace is constant in U, F(w) also depends smoothly on w. 0 We now integrate parallel Jacobi fields to produce flat strips in M.
Chapter IV: Rank rigidity
74
4.2 Lemma. The distribution F is integrable on each nonempty set R m C SM, m 2': rank(M). The maximal arc-connected integral manifold through v E R m is an open subset ofP(v). In particular, ifw E P(v) nRm ) then P(v) and P(v) are smooth m-dimensional manifolds near wand Jr( w) respectively. Proof. To prove the first assertion we begin with the following obeservation: let cr : (-E, E) ---+ R m be a smooth curve tangent to F. Then cr( s) is parallel to cr(0) = v for all s. To verify this we consider the geodesic variation 'Ys (t) = (Jr 0 gt) (cr( S )) of 'Yo = 'Yv· The variation vector fields Y. of ('Ys) are given by Ys(t)
=
(dJr
0
d dgt)(ds cr(s)).
The vector fields Ys are parallel Jacobi fields along 'Ys since (djds)cr(s) belongs to F. For each t the curve at : u ---+ 'Yu(t) has velocity (djdu)at(u) = Yu(t), and hence, since each Yu is parallel, the lengths of the curves at (1) are constant in t for any interval I C (-E, E). Therefore, for every s the convex function t ---+ d("(o (t), 'Ys (t)) is bounded on JR and hence constant. This implies that the geodesics 'Ys are parallel to 'Yo and cr(s) = 18(0) is parallel to cr(O) = v. Now let v E R m be given, and let X, Y be smooth vector fields defined in a neighborhood of v in R m that are tangent to F. Denote by ¢~ and ¢~ the flows of X and Y respectively. The discussion above shows that if w E R m is parallel to v then so are ¢~ (w) and ¢~ (w) for every small s. Hence cr( s2) = ¢;;s 0 ¢Zs 0 ¢~ 0 ¢~ (v) is parallel to v for every small s. Therefore, [X,Y](v) = (djds)cr(s)ls=o belongs to F, and it follows that F is integrable on R m . The third assertion of the lemma follows from the second, which we now prove. If Q denotes the maximal arc-connected integral manifold of F through v, then Q C P(v) by the discussion above. Now let w E Q be given, and let o C R m be a normal coordinate neighborhood of w relative to the metric in SM. We complete the proof by showing that
Onp(w)
=
Onp(v) C Q.
If Wi EOn P (v) is distinct from w, let cr( s) be the unique geodesic in M from cr(O) = Jr(w) to cr(l) = Jr(w ' ). The parallel field w(s) along cr(s) with w(O) = w has values in P(v) since either 'Yw = 'Yw ' or 'Yw and 'Yw ' bound a flat strip in M. Hence w[O, 1] is the shortest geodesic in SM from w(O) = w to w(l) = Wi and must therefore lie in 0 C R m . Since the curve w(s), 0 ~ s ~ 1, lies in P(v) n R m it is tangent to F and hence Wi E w[O, 1] C Q. D
4.3 Lemma. Let N* be a totally geodesic submanifold of a Riemannian manifold N. Let 'Y be a geodesic of N that lies in N*) and let J be a Jacobi field in N along 'Y. Let J 1 and h denote the components of J tangent and orthogonal to N* respectively. Then J 1 and J 2 are Jacobi fields in N along T Proof. Let R denote the curvature tensor of N, and let v be a vector tangent to N* at a point p. Since N* is totally geodesic it follows that
R(X, v)v E TpN*
if X E TpN*
Rank, regular vectors and fiats and hence, since Y
Since
J~'
--+
75
R(Y, v)v is a symmetric linear operator, that
is tangent and
Jf
perpendicular to N* we see that
is the component of
0= J"
+ R(J,-rh
tangent to N*, and hence must be zero.
0
4.4 Proposition. Suppose the isometry group of M satisfies the duality condition. Then for every vector v E R m ! the set P(v) is an m-fiat, that is, an isometrically
and totally geodesically embedded m-dimensional Euclidean space. Proof. Let v E R m be given. By Lemma 4.2 for any v' E R m the sets P( v') n R m and P(v') are smooth m-manifolds near v' and 7f( v') respectively, and 7f : P( v') n R m --+ P(v') is an isometry onto an open neighborhood of 7f(v') in P(v'). We can choose a neighborhood U C R m of v and a number E > 0 such that for every v' E U the exponential map at 7f( v') is a diffeomorphism of the open E-ball in T7f(v')P(v') onto its image DE(v') C P(v'). Let q E P(v) be given. We assert that q E DE C P(v), where DE is the diffeomorphic image under the exponential map at q of the open E-ball in some m-dimensional subspace of TqM. Let w = v(q) be the vector at q parallel to v. By Corollary 111.1.3 we can choose sequences Sn --+ 00, V n --+ v and (cPn) in r such that (dcPn 0 gSn )(vn ) --+ was n --+ +00. For sufficiently large n, V n E U and
If DE(v') c P(v') for some v' C R, then clearly DE(gSv') C P(v') = P(gSv') for any real number s since P( v') is the union of flat strips containing IV" Hence
for sufficiently large n. Therefore, the open m-dimensional E-balls DE; (dcPn ogSn (v n )) converge to an open m-dimensional E-ball DE; C P(w) = P(v) as asserted. We show first that DE = BE(q) n P(v), where BE(q) is the open E-ball in M with center q. Since q E P(v) was chosen arbitrary this will show that P(v) is an m-dimensional submanifold without boundary of M, and it will follow that P(v) is complete and totally geodesic since P( v) is already closed and convex. Suppose that DE: is a proper subset of BE(q) n P(v). Choose a point q' E BE(q) n P(v) such that the geodesic from q to q' is not tangent to DE at q. The set P(v) contains the convex hull D' of DE and q' and hence contains a subset D" C D' that is diffeomorphic to an open (m + I)-dimensional ball. Similarly P(v) contains the
Chapter IV: Rank rigidity
76
convex hull of D" and p = 1T(V), but this contradicts the fact that P(v) has dimension m at p. We show next that P( v) has zero sectional curvature in the induced metric. By a limit argument we can choose a neighborhood 0 of v in Trr(v)P(v) such that o C R m and for any w E 0 the geodesic Iw admits no nonzero parallel Jacobi field that is orthogonal to P( v). Let w E 0 be given, and let Y be any parallel Jacobi field along Iw' If Z is the component of Y orthogonal to P( v), then Z is a Jacobi field on Iw by Lemma 4.3, and IIZ(t)11 :::; IIY(t)11 is a bounded convex function on R By Lemma 2.6, Z is parallel on IW and hence identically zero since wE O. Hence
Trr(w)P(w)
= span{Y(O)
: Y E J"P(w)} C Trr(v)P(v).
Since P( v) and P( w) are totally geodesic submanifolds of M of the same dimension m it follows that P(v) = P(w) for all wE O. The vector field p -> w(p) is globally parallel on P(w) = P(v). Since this is true for any w E 0 we obtain m linearly independent globally parallel vector fields in P(v). Hence P(v) is flat. 0 5. An invariant set at infinity In this section we discuss Eberlein's modification of the Angle Lemma in [BBE], see [EbHe]. We will also use the notation Pv for P(v). Since the distribution :F is smooth on R, we have the following conclusion of Proposition 4.4. 5.1 Lemma. The function (v, p)
f---+
d(p, Pv ) is continuous on R x M.
0
5.2 Lemma. Let k = rank(M), v E R k and ~ = IV(-oo), 1] = Iv(oo). Then there exists an c > 0 such that if F is a k-fiat in M with d(p, F) = 1, where p = 1T( v) is
the foot point of v, then L(~,F(oo))+L(1],F(oo)) ~
c.
Proof. Suppose there is no c > 0 with the asserted properties. Then, by the semicontinuity of L, there is a k-flat F in M with d(p, F) = 1 and ~,1] E F( 00). Since F is a flat and L(~, 1]) = 1T this implies Lq(~, 1]) = 1T for all q E F. Hence F consists of geodesics parallel to Iv and therefore F C Phv) = Pv . But Pv is a k-flat, hence F = P v . This is a contradiction since d(p, F) = 1. 0 5.3 Lemma. Let k = rank M. Let v E Rk be r -recurrent and let 1] = Iv (00). Then there exists an a > 0 such that L(1], () ~ a for any ( E M( 00) \ Pv (00).
Proof. Let c > 0 be as in Lemma 5.2. Choose 15 > 0 such that any unit vector w at the foot point p of v with L(v, w) < 15 belongs to R k and set a = min{c, 15}. Let ( be any point in M (00 ) \ P v ( 00) and suppose L (1], () < a. In particular, L(1],() < 1T and hence there is a unique L-geodesic a: [0,1] -+ M(oo) from 1] to (. Let v(s) be the vector at p pointing at a(s),O:::; s:::; 1. Note that L(v(s),v(t)) :::; L(a(s),a(t))
=
It -
sIL(1],()
77
An invariant set at infinity
by the definition of the L-metric on M(oo). Hence
L(v,v(s))
~
L('T],a-(s)) < 8
and hence v(s) E R k , 0 ~ S ~ 1. Let w = v(l) be the vector at p pointing at (. Note that 'T] Pw(oo). Otherwise we would have IV C Pw since Pw is convex and p E Pw. But then Pv = Pw , a contradiction since ( Pv(oo). We conclude that (the convex function) d(rv(t),Pw ) ----; 00 as t ----; 00. Since v is f-recurrent, there exist sequences t n ----; 00 and (IPn) in f such that dIPn (gt nv) ----; v as n ----; 00. By what we just said, there is an N E N such that d(rv(tn), Pw ) 2:: 1 for all n 2:: N. By Lemma 5.1 there exists an Sn E [0,1] with d(rv(tn),PV(Sn») = 1, n 2:: N. We let Fn = IPn(P(V Sn ))' Then d(p,Fn ) ----; 1. Passing to a subsequence if necessary, the sequence (Fn ) converges to a k-flat F with d(p, F) = 1. Let In be the geodesic defined by In(t) = IPn(rv(t + t n )), t E R Then d(rn(t), Fn ) is convex in t and increases from 0 to 1 on the interval [-tn,O]. By the choice of t n and IPn we have In ----; Iv and hence d(rv(t), F) ~ 1 on (-00,0]. We conclude that IV(-oo) E F(oo). Therefore L(rv(oo)),F(oo)) 2:: c, where c > 0 is the constant from Lemma 5.2. Let (n = a-(sn). By passing to a further subsequence if necessary, we can assume that IPn((n) E Fn(oo) converges. Then the limit ~ is in F(oo). Also note that IPn ('T]) = In (00) converges to 'T] = IV (00) since In ----; Iv' Hence
rt
rt
c ~ L(rv(oo), F(oo)) ~ L(rv(oo),~) ~ liminf =
This is a contradiction.
L(IPn('T]), IPn((n))
liminf L('T], (n) ~ L('T], ()
< a.
0
For any p EM, let IPp : M (00) ----; SpM be the homeomorphism defined by where v~(p) is the unit vector at p pointing at ~.
IPp(~) = v~(p),
5.4 Lemma. Let v, 'T] and a be as in Lemma 5.3, and let F be a k-fiat with 'T] IV(oo) E F(oo). Then
Bo:('T])
= {( E
M(oo)
I L('T],() < a} C
=
F(oo)
and for any q E F, IPq maps B o ('T]) isometrically onto the ball B o (v'l) (q)) of radius a in SqF.
Proof. Lemma 5.3 implies Bo('T]) C Pv(oo). For q E F, IP;;l maps SqF isometrically into M(oo). In particular, IP;;l maps Bo(v'l)(q)) isometrically into Bo('T]). Hence IPpOIP;;l : Bo(v'l)(q)) ----; Bo(v) is an isometric embedding mapping v'l)(q) to v. Since both, B o (v'l)(q)) and B o (v), are balls of radius a in a unit sphere of dimension k-l, IPp 0 IP;;l is surjective and hence an isometry. The lemma follows. 0
Chapter IV: Rank rigidity
78
5.5 Corollary. Let V,7) and ex be as in Lemma 5.3. Then L q((1,(2) all q E M and (1, (2 E B a (7)).
= L((1,(2) for
Proof. Let q E M and let '"'( be the unit speed geodesic through q with '"'((00) = 7). By Proposition 4.4, '"'( is contained in a k-flat F. By Lemma 5.4, we have B a (7)) C F(oo). Since F is a flat we have Lq((l, (2) = L((l, (2) for (1, (2 E B a (7)). 0 5.6 Proposition. If rank(M) = k ?: 2, if the isometry group f of M satisfies the duality condition and if M is not fiat, then M (00) contains a proper, nonempty, closed and f -invariant subset.
Proof. Suppose first that M has a non-trivial Euclidean de Rahm factor Mo. Then M = M o X M l with M l non-trivial since M is not flat. But then every isometry of M leaves this splitting invariant, and hence M o(00) and M l (00) are subsets of M(oo) as asserted. Hence we can assume from now on that M has no Euclidean de Rahm factor. Let X 8 be the set of ~ E M (00) such that there is an 7) E M (00) with Lq(~, 7)) = 8 for all q E M. Corollary 5.5 shows that X8 -I- 0 for some 8 > 0. Clearly, X 8 is closed and f-invariant for any 8. Let {3 = sup{81 X 8 -I- 0}. Then X{3 -I- 0. We want to show X{3 -I- M(oo). We argue by contradiction and assume X{3 = M(oo). Suppose furthermore (3 < 1f. Let v E R k be f-recurrent, 7) = '"'(v(oo) and let ex be as in Lemma 5.3. Choose 8 > with (3 + 8 < Jr and 8 < ex. Since X{3 = M(oo), there is a point ( E M(oo) with L q (7), () = {3 < Jr for all q E M. Let (Y : [0, (3] -+ M(oo) be the unique unit speed L-geodesic from (to 7). Now the last piece of (Y is in B a (7)) and B a (7)) is isometric to a ball of radius ex in a unit sphere. Hence (Y can be prolongated to a L-geodesic (Y* : [0,{3 + 8] -+ M(oo). Let q E M. Since L('Pq(6),'Pq(6)) :s; L(6,6) for all 6,6 E M(oo), where 'Pq(~) E SqM denotes the unit vector at q pointing at ~ E M(oo), and since L q (7), () = (3 = L(7), (), we conclude
°
L('Pq((Y(s)), 'Pq((Y(t)))
= L(rr(S), (Y(t)) = Is - tl
for all s, t E [0, {3]. Hence 'Pq 0 (Y is a unit speed geodesic in SqM. The geodesic '"'( through q with '"'((00) = 7) is contained in a k-flat F, and hence 'Pq 0 (Y* : ({3 - ex, {3 + 8] is also a unit speed geodesic in SqM. Therefore 'Pq 0 (Y* is a unit speed geodesic in SqM of length {3 + 8 and hence
Since q was chosen arbitrary we get X{3+8 -I- 0. This contradicts the choice of {3, hence {3 = Jr. But X7l" -I- 0 implies that M is isometric to M' x R This is a contradiction to the assumption that M does not have a Euclidean factor. Hence X{3 is a proper, nonempty, closed and f-invariant set as claimed. 0 5.7 Remark. The set X{3 as in the proof catches endpoints of (certain) singular geodesics in the case that X is a symmetric space of non-compact type.
Rank rigidity
79
6. Proof of the rank rigidity
From now on we assume that M is a Hadamard manifold of rank ~ 2 and that the isometry group of M satisfies the duality condition. In the last section we have seen that there is a f-invariant proper, nonempty compact subset Z C M(oo). By Theorem III.2.4 and Formula III.2.5.
f(v) = L(V,Z) := inf{Lrr(v)bv(oo),~) I ~ E Z}
(6.1)
defines a f -invariant continuous first integral for the geodesic flow on S M and
(6.2)
f(v) = f(w)
6.3 Lemma. f : SM
-+
if IV(OO) = IW(OO)
or
IV(-OO) = IW(-OO).
IR is locally Lipschitz, hence differentiable almost every-
where. Proof. Instead of the canonical Riemannian distance ds on SM, we consider the metric d1(v,w) = dbv(O)"w(O)) +dbv(1)"w(l)) which is locally equivalent to ds. Let v,w E SM and p = 1f(v),q = 1f(w). Let Vi be the vector at q asymptotic to v. Then f(v ' ) = f(v) by (6.2). Now
/ d1(w,v )
= dbw(l),'v,(l)):::; dbw(l),'v(1)) +dbv(l)"v,(l)) :::; dbw(1),'v(l))
+ dbv(O)"v'(O)) =
d1(v,w)
since v and Vi are asymptotic and IV/(O) = IW(O). By comparison we obtain
If(v) - f(w)1
If(v / ) - f(w)1
< LV, w ( ')
. (d1(V'W)) :::; 2 arcsm 2
o
Recall the definition of the sets W 80 (v), v E S M, at the end of Section 3,
WSO(v) = {w E SM I w(oo) = v(oo)}. Correspondingly we define
WUD(v) = {w E SM I w(-oo) =v(-oo)}. Note that WUO(v) = -WSD(-V). One of the central observations in [Ba2] is as follows. 6.4 Lemma. Let v E SM. Then TvWSO(v)
+ TvWUO(v)
contain the horizontal
subspace of TvSM. Proof. Note that TV W 80 (v) consists of all pairs of the form (X,B+(X)), where B+(X) denotes the covariant derivative of the stable Jacobi field along Iv determined by X. It follows that Tv W Uo ( v) consists of all pairs of the form (X, B - (X) ),
Chapter IV: Rank rigidity
80
where B- (X) denotes the covariant derivative of the unstable Jacobi field along "tv determined by X. Observe that B+ and B- are symmetric linear operators of T 1r (v)M, and Eo = {X E T 1r (v)M I B+(X) = B-(X) = O} consists of all X which determine a parallel Jacobi field along "tv. (In particular, v E Eo). Since B+ and B- are symmetric, they map T 1r (v)M into the orthogonal complement Et of Eo. Given a horizontal vector (X,O), we want to write it in the form
which is equivalent to
Because of the fact that
it suffices to solve B+(Xr) - B-(Xr)
= -B-(X).
Since B- (X) is contained in Et and (B+ - B-)(Et) c Et, the latter equation has a solution if (B+ - B-) I Et is an isomorphism. This is clear, however, since (B+ - B-)(Y) = 0 implies that the stable and unstable Jacobi fields along "tv determined by Y have identical covariant derivative in "tv(O); hence Y E Eo. 0 6.5 Corollary. If f is differentiable at v and X is a horizontal vector in TvSM, then dfv(X) = O. Proof. By (6.2), f is constant on W80(V) and WUO(v). By Lemma 6.4 we have X E T v W80(V) + TvWUO(v). 0 6.6 Lemma. If c is a piecewise smooth horizontal curve in S M then f oc is constant. Proof. Since f is continuous, it suffices to prove this for a dense set (in the 0 0 _ topology) of piecewise smooth horizontal curves. Now f is differentiable in a set D c SM of full measure. It is easy to see that we can approximate c locally by piecewise smooth horizontal curves c such that c(t) E D for almost all t in the domain of c. Corollary 6.5 implies that foe = const. for such a curve C. 0 Let p E M. Since the subset Z C M(oo) is proper, the restriction of f to SpM is not constant. Lemma 6.6 implies that f is invariant under the holonomy group G of M at p. In particular, the action of G on SpM is not transitive. Now the theorem of Berger and Simons [Be, Si] applies and shows that M is a Riemannian product or a symmetric space of higher rank. This concludes the proof of the rank rigidity.
Appendix. Ergodicity of the geodesic flow
M. BRIN
We present here a reasonably self-contained and short proof of the ergodicity of the geodesic flow on a compact n-dimensional manifold of strictly negative sectional curvature. The only complete proof of specifically this fact was published by D.Anosov in [Anol]. The ergodicity of the geodesic flow is buried there among quite a number of general properties of hyperbolic systems, heavily depends on most of the rest of the results and is rather difficult to understand, especially for somebody whose background in smooth ergodic theory is not very strong. Other works on this issue either give only an outline of the argument or deal with a considerably more general situation and are much more difficult. 1. Introductory remarks
KHopf (see [HoI], [Ho2]) proved the ergodicity of the geodesic flow for compact surfaces of variable negative curvature and for compact manifolds of constant negative sectional curvature in any dimension. The general case was established by D.Anosov and Ya.Sinai (see [Anol], [AnSi]) much later. Hopf's argument is relatively short and very geometrical. It is based on the property of the geodesic flow which Morse called "instability" and which is now commonly known as "hyperbolicity". Although the later proofs by Anosov and Sinai follow the main lines of Hopf's argument, they are considerably longer and more technical. The reason for the over 30 year gap between the special and general cases is, in short, that length is volume in dimension I but not in higher dimensions. More specifically, these ergodicity proofs extensively use the horosphere H (v) as a function of the tangent vector v and the absolute continuity of a certain map p between two horospheres (the absolute continuity of the horospheric foliations). Since the horosphere H (v) depends on the infinite future of the geodesic '"Yv determined by v, the function H (.) is continuous but, in the general case, not differentiable even if the Riemannian metric is analytic. As a result, the map p is, in general, only continuous. For n = 2 the horospheres are I-dimensional and the property of bounded volume distortion
82
Appendix: Ergodicity of the geodesic Bow
for p is equivalent to its Lipschitz continuity which holds true in special cases but is false in general. The general scheme of the ergodicity argument below is the same as Hopf's. Most ideas in the proof of the absolute continuity of the stable and unstable foliations are the same as in [Anol] and [AnSi]. However, the quarter century development of hyperbolic dynamical systems and a couple of original elements have made the argument less painful and much easier to understand. The proof goes through with essentially no changes for the case of a manifold of negative sectional curvature with finite volume, bounded and bounded away from 0 curvature and bounded first derivatives of the curvature. For surfaces this is exactly Hopf's result. The assumption of bounded first derivatives cannot be avoided in this argument. The proof also works with no changes for any manifold whose geodesic flow is Anosov. In addition to being ergodic, the geodesic flow on a compact manifold of negative sectional curvature is mixing of all orders, is a K-flow, is a Bernoulli flow and has a countable Lebesgue spectrum, but we do not address these stronger properties here. In Section 2 we list several basic facts from measure and ergodic theory. Continuous foliations with C1-Ieaves and their absolute continuity are discussed in Section 3. In Section 4 we recall the definition of an Anosov flow and some of its basic properties and prove the Holder continuity of the stable and unstable distributions. The absolute continuity of the stable and unstable foliations for the geodesic flow and its ergodicity are proved in Section 5. 2. Measure and ergodic theory preliminaries A measure space is a triple (X, 2(, JL), where X is a set, 2( is a O"-algebra of measurable sets and JL is a O"-additive measure. We will always assume that the measure is finite or O"-finite. Let (X, 2(, JL) and (Y, 23, v) be measure spaces. A map 7j; : X ----+ Y is called measurable if the preimage of any measurable set is measurable; it is called nonsingular if, in addition, the preimage of a set of measure 0 has measure O. A nonsingular map from a measure space into itself is called a nonsingular transformation (or simply a transformation). Denote by A the Lebesgue measure on R A measurable flow ¢ in a measure space (X, 2(, JL) is a map ¢ : X x JE. ----+ X such that (i) ¢ is measurable with respect to the product measure JL x A on X x JE. and measure JL on X and (ii) the maps ¢t(.) = ¢(', t) : X ----+ X form a one-parameter group of transformations of X, that is ¢t 0 ¢s = ¢HS for any t, s E R The general discussion below is applicable to the discrete case t E Z and to a measurable action of any locally compact group. A measurable function f : X ----+ JE. is ¢-invariant if JL({x EX: f(¢t x ) if(x)}) = 0 for every t ERA measurable set B E 2( is ¢-invariant if its characteristic function IE is ¢-invariant. A measurable function f : X ----+ JE. is strictly ¢-invariant if f (¢t x) = f (x) for all x EX, t ERA measurable set B is strictly ¢-invariant if IE is strictly ¢-invariant.
Measure and ergodic theory preliminaries
83
We say that something holds true mod 0 in X or for fL-a.e. x if it holds on a subset of full fL-measure in X. A null set is a set of measure O.
2.1 Proposition. Let ¢ be a measurable flow in a measure space (X, 2l, fL) and let f : X ~ ~ be a ¢-invariant function. Then there is a strictly ¢-invariant measurable function J such that f(x) = J(x) mod o.
Proof. Consider the measurable map cI> : X x ~ ~ X, cI>(x, t) = ¢t x , and the product measure v in X x R Since f is ¢-invariant, v({(x,t) : f(¢t x ) = f(x)}) = 1. By the Fubini theorem, the set Af
= {x EX: f(¢t x ) = f(x) for a.e. t E ~}
has full fL-measure. Set J(x)
= { ~(y)
if ¢t x = y E A f for some t E ~ otherwise.
If ¢t x = Y E A f and ¢sx = Z E A f then clearly f(y) defined and strictly ¢-invariant. D
= f(z). Therefore J is well
2.2 Definition (Ergodicity). A measurable flow ¢ in a measure space (X, 2l, fL) is called ergodic if any ¢-invariant measurable function is constant mod 0, or equivalently, if any measurable <,b-invariant set has either full or 0 measure. The equivalence of the two definitions follows directly from the density of the linear combinations of step functions in bounded measurable functions. A measurable flow ¢ is measure preserving (or fL is ¢-invariant) if fL(¢t(B)) = fL(B) for every t E ~ and every B E 2l.
2.3 Ergodic Theorems. Let ¢ be a measure preserving flow in a finite measure space (X, 2l, fL). For a measurable function f : X ~ ~ set 1 f:j(x) = T
iT . 0
1 f(¢t x ) dt and fi(x) = T
iT
f(¢-t x ) dt .
0
(1) (Birkhoff) If f E L1(X, 2l, fL) then the limits f+(x) = limT->oo f:j(x) and f-(x) = limT->oo fi(x) exist and are equal for fL-a.e. x E X, moreover f+, f- are fL-integrable and ¢-invariant. (2) (von Neumann) If f E L 2 (X, 2l, It) then f:j and fi converge in L 2 (X, 2l, fL) to ¢-invariant functions f+ and f-, respectively. D
2.4 Remark. If f E L 2 (X, 2l, fL), that is, if j2 is integrable, then f+ and f- represent the same element J of L 2 (X, 2l, fL) and J is the projection of f onto the subspace of ¢-invariant L 2-functions. To see this let h be any ¢-invariant L 2 -function.
Appendix: Ergodicity of the geodesic flow
84
Since ¢ preserves fJ we have
r(J(x) - f(x))hdfJ(x) = Jrx f(x)h(x)dfJ(x) - JXrTlimooT~ Jro f(¢tx)h(x)dtdfJ(x) Jx = r f(x)h(x)dfJ(x) - r lim -T r f(y)h(¢-ly)dtdfJ(Y) Jx Jx T oo h T
-+
T
1
=
L
f(x)h(x)dfJ(x) -
L
-+
f(y)h(y)dfJ(Y) =0.
In the topological setting invariant functions are mod 0 constant on sets of orbits converging forward or backward in time. Let (X, 2l, fJ) be a finite measure spaee such that X is a compact metric space with distance d, fJ is a measure positive on open sets and 2l is the fJ-completion of the Borel a-algebra. Let ¢ be a continuous flow in X, that is the map (x, t) ---> ¢t x is continuous. For x E X define the stable VS(x) and unstable VU(x) sets by the formulas
(2.5)
VS(x)
=
{y EX: d(¢tx,¢t y ) ---> 0 as t
--->
oo},
VU(x)
=
{y EX: d(¢t x , ¢t y ) ---> 0 as t
--->
-oo}.
2.6 Proposition. Let ¢ be a continuous flow in a compact metric space X preserving a finite measure fJ positive on open sets and let f : X ---> lR. be a ¢-invariant
measurable function. Then f is mod 0 constant on stable sets and unstable sets, that is, there are null sets N s and N u such that f(y) = f(x) for any x, y E X \ N s , y E VS(x) and f(z) = f(x) for any x, z E X \ N u , z E VU(x). Proof. We will only deal with the stable sets. Reversing the time gives the same for the unstable sets. Assume WLOG that f is nonnegative. For C E lR. set fdx) = min(J(x), C). Clearly fe is ¢-invariant and it is sufficient to prove the statement for fe with arbitrary C. For a natural m let h m : X ---> lR. be a continuous function such that Ife - hml dfJ(x) < Tk. By the Birkhoff Ergodic Theorem,
Ix
exists a.e. Since fJ and fe are ¢-invariant, we have that for any t E lR.
~> m
r Ifdx) - hm(x)1 dfJ(x) hr Ifd¢t y ) - hm(¢ty)1 dfJ(Y)
h
=
=
L
Ife(Y) - hm(¢ty)1 dfJ(Y)·
Absolutely continuous foliations
85
Therefore
Note that since h m is uniformly continuous, ht(y) = ht(x) whenever y E VS(x) and ht (x) is defined. Hence there is a set N m of J.1.- measure 0 such that ht exists and is constant on the stable sets in X \ N m . Therefore, f;j(x) := limm--->CXJ ht(x) is constant on the stable sets in X \ (UNm ). Clearly fc(x) = f;j(x) mod o. D For differentiable hyperbolic flows in general and for the geodesic flow on a negatively curved manifold in particular, the stable and unstable sets are differentiable submanifolds of the ambient manifold Mn. The foliations WS and W U into stable and unstable manifolds are called the stable and unstable foliations, respectively. Together with the I-dimensional foliation WO into the orbits of the flow they form three transversal foliations W s, WU and WO of total dimension n. Any mod 0 invariant function f is, by definition, mod 0 constant on the leaves of W O and, by Proposition 2.6, is mod 0 constant on the leaves of W S and WU. To prove ergodicity one must show that f is mod 0 locally constant. This would follow immediately if one could apply a version of the Fubini theorem to the three foliations. Unfortunately the foliations WS and W U are in general not differentiable and not integrable (see the next section for definitions). The applicability of a Fubini-type argument depends on the absolute continuity of W S and WU which is discussed in the next section. We will need the following simple lemma in the proof of Theorem 5.1.
2.7 Lemma. Let (X, 2t, J.1.), (Y, 23, v) be two compact metric spaces with Borel (Jalgebras and (J-additive Borel measures and let Pn : X -> Y, n = 1,2, ... , P : X -> Y be continuous maps such that
(1) each Pn and P are homeomorphisms onto their images, (2) Pn converges to P uniformly as n -> 00, (3) there is a constant C such that v(Pn(A))::; CJ.1.(A) for any A E 2t. Then v(p(A)) ::; CJ.1.(A) for any A E 2t. Proof. It is sufficient to prove the statement for an arbitrary open ball B in X. For 8 > 0 let B o denote the 8-interior of B. Then p(B o) C Pn(B) for n large enough, and hence, v(p(B o)) ::; v(Pn(B)) ::; CJ.1.(B). Observe now that v(p(Bo)) / v(p(B)) as 8'\.0. D
3. Absolutely continuous foliations Let M be a smooth n-dimensional manifold and let Bk denote the closed unit ball centered at 0 in ~k. A partition W of M into connected k-dimensional C 1 _ submanifolds W(x) 3 x is called a k-dimensional CO-foliation of M with C 1 -leaves (or simply a foliation) iffor every x E M there is a neighborhood U = Ux 3 x and a homeomorphism w = W x : B k X B n - k -> U such that w(O,O) = x and
86
Appendix: Ergodicity of the geodesic flow
(i) w(B k , z) is the connected component Wu(w(O, z)) of W(w(O, z)) n U containing w(O, z), (ii) w(·, z) is a Cl-diffeomorphism of B k onto Wu(w(O, z)) which depends continuously on z E Bn-k in the Cl-topology. We say that W is a Cl-foliation if the homeomorphisms W x are diffeomorphisms. 3.1 Exercise. Let W be a k-dimensional foliation of M and let L be an (n - k)dimensional local transversal to W at x E M, that is, TxM = TxW(x)EBTxL. Prove that there is a neighborhood U :1 x and a C l coordinate chart w : B k X B n - k ----+ U such that the connected component of L n U containing x is w(O, Bn-k) and there are Cl-functions fy : B k ----+ Bn~k, y E Bn~k with the following properties: (i) fy depends continuously on y in the Cl-topology; (ii) w(graph (fy)) = Wu(w(O, y)).
We assume that M is a Riemannian manifold with the induced distance d. Denote by m the Riemannian volume in M and by mN denote the induced Riemannian volume in a Cl-submanifold N.
3.2 Definition (Absolute continuity). Let L be a (n - k)-dimensional open (local) transversal for a foliation W, that is, TxL EB T x W(x) = TxM for every x E L. Let U c !vi be an open set which is a union oflocal "leaves", that is U = UxEL Wu(x), where Wu(x) ~ B k is the connected component of W(x) n U containing x. The foliation W is called absolutely continuous if for any Land U as above there is a measurable family of positive measurable functions 6x : Wu(x) ----+ JR (called the conditional densities) such that for any measurable subset A c U
Note that the conditional densities are automatically integrable. Instead of absolute continuity we will deal with "transversal absolute continuity' which is a stronger property, see Proposition 3.4.
3.3 Definition (Transversal absolute continuity). Let W be a foliation of M, Xl E M, x2 E W(xd and let L i :1 Xi be two transversals to W, i = 1,2. There are neighborhoods Ui :1 Xi, Ui eLi, i = 1,2, and a homeomorphism p : U l ----+ U2 (called the Poincare map) such that p(xd = X2 and p(y) E 'W(y), Y E U l . The foliation W is called transversally absolutely continuous if the Poincare map p is absolutely continuous for any transversals L i as above, that is, there is a positive measurable function q : U 1 ----+ JR (called the Jacobian of p) such that for any measurable subset A C U l
Absolutely continuous foliations
87
If the Jacobian q is bounded on compact subsets of U 1 then W is called transversally absolutely continuous with bounded Jacobians.
3.4 Exercise. Is the Poincare map in Definition 3.3 uniquely defined? 3.5 Proposition. If W is transversally absolutely continuous, then it is absolutely continuous.
Proof. Let Land U be as in Definition 3.2, x ELand let F be an (n - k)dimensional C 1 -foliation such that F(x) ~ L, Fu(x) = Land U = UyEwu(x)Fu(y), see Figure 2. Obviously F is absolutely continuous and transversally absolutely continuous. Let <5y (-) denote the conditional densities for F. Since F is a C 1 _ foliation, <5 is continuous, and hence, measurable. For any measurable set A c U, by the Fubini theorem,
~(s)
~(y)
FIGURE
2
Let Py denote the Poincare map along the leaves of W from Fu(x) = L to Fu(Y) and let qyC) denote the Jacobian of Py. It is not difficult to see that q is a measurable function (see the exercise below). We have
88
Appendix: Ergodicity of the geodesic flow
and by changing the order of integration in (3.6) we get
Similarly, let Ps denote the Poincare map along the leaves of F from Wu(x) to Wu(s), s E L, and let lis denote the Jacobian of Ps. We transform the integral over W u (x) into an integral over W u (s) using the change of variables r = Py (s ), y =
p;l(r)
The last formula together with (3.7) gives the absolute continuity of W.
0
3.8 Exercise. Prove that the Jacobian q in the above argument is a measurable function. 3.9 Remark. The converse of Proposition 3.5 is not true in general. To see this imagine two parallel vertical intervals hand h in the plane making the opposite sides of the unit square. Let C 1 be a "thick" Cantor set in h, that is, a Cantor set of positive measure, and let C 2 be the standard "1/3" Cantor set in 12 . Let a : h --> h be an increasing homeomorphism such that a is differentiable on h \ C 1 and a(C1 ) = C 2 . Connect each point x E h to a(x) by a straight line to obtain a foliation W of the square which is absolutely continuous but not transversally absolutely continuous. It is true, however, that an absolutely continuous foliation is transversally absolutely continuous for "almost every" pair of transversals chosen, say, from a smooth nondegenerate family. 3.10 Exercise. Fill in the details for the construction of an absolutely continuous but not transversally absolutely continuous foliation in the previous remark. The absolute continuity of the stable and unstable foliations for a differentiable hyperbolic dynamical system, such as the geodesic flow on a compact Riemannian manifold of negative sectional curvature, is precisely the statement that allows one to use a Fubini-type argument and to conclude that since an invariant function is mod 0 constant on stable and unstable manifolds, it must be mod 0 constant in the phase space. 3.11 Lemma. Let W be an absolutely continuous foliation of a Riemannian manifold M and let f : M --> lR be a measurable function which is mod 0 constant on the leaves of W. Then for any transversal L to W there is a measurable_subset L C L of full induced Riemannian volume in L such that for every x E L there is a subset W(x) C W(x) of full induced Riemannian volume in W(x) on which f is constant.
Proof. Given a transversal L break it into smaller pieces L i and consider neighborhoods Ui as in the definition of absolute continuity. Let N be the null set such
Absolutely continuous foliations
89
that f is constant on the leaves of W in M \ N an~ let N i = N n Ui . By the absolute continuity of W for each i there is a subset L i of full measure in L i such that for each x E Li the complement W Ui (x) of N i in W Ui (x) has full measure in the local leaf. D Two foliations WI and W 2 of a Riemannian manifold M are transversal if T x WI (x) n T x W 2 (x) = {O} for every x E M. 3.12 Proposition. Let]\;1 be a connected Riemannian manifold and let WI, W 2 be two transversal absolutely continuous foliations on M of complementary dimensions, that is TxM = TxWI(x) EEl T x W 2 (x) for every x E M (the sum is direct but not necessarily orthogonal). Assume that f : M ----+ lR is a measurable function which is mod 0 constant on the leaves of WI and mod 0 constant on the leaves of
W2 ·
f is mod 0 constant in M. Proof. Let N i C M, i = 1,2, be the null sets such that f of Wi in M i = M \ N i . Let x E M and let U 3 x be a Then
is constant on the leaves small neighborhood. By Lemma 3.11, since WI is absolutely continuous, there is y arbitrarily close to x whose local leaf W U, (y) intersects M I by a set MI(y) of full measure. Since W 2 is absolutely continuous, for almost every z E ]\;11 (y) the intersection W 2 n M 2 has full measure. Therefore f is mod 0 constant in a neighborhood of x. Since M is connected, f is mod 0 constant in M. D The previous proposition can be applied directly to the stable and unstable foliations of a volume preserving Anosov diffeomorphism to prove its ergodicity (after establishing the absolute continuity of the foliations). The case of flows is more difficult since there are three foliations involved - stable, unstable and the foliation into the orbits of the flow. In that case one gets a pair of transversal absolutely continuous foliations of complementary dimensions by considering the stable foliation WS and the weak unstable foliation WUo whose leaves are the orbits of the unstable leaves under the flow. Two transversal foliations Wi of dimensions di , i = 1,2, are integrable and their integral hull is a (d I + d 2 )-dimensional foliation W if
W(x) = UyEW,(x) W 2 (y) = UZE W2 (x) WI (z). 3.13 Lemma. Let Wi, i = 1,2, be transversal integrable foliations of a Riemannian manifold M with integral hull W such that WI is a CI-foliation and W 2 is absolutely continuous. Then W is absolutely continuous.
Proof. Let L be a transversal for W. For a properly chosen neighborhood U in M the set L = UxEL W w (x) is a transversal for W 2 . Since W 2 is absolutely continuous, we have for any measurable subset A C U m(A)
=! r L
}w2 u(Y)
lA(y, z)8y (z) dmW2U(Y)(Z) dmL (y).
Appendix: Ergodicity of the geodesic flow
90
Since L is foliated by WI-leaves,
~
h
drnL(x)
=
rr
j(x,y)drnW(x)(y)drnL(x)
}L}Ww(x)
for some positive measurable function j. The absolute continuity of immediately.
~V
follows 0
We will need several auxiliary statements to prove the absolute continuity of the stable and unstable foliations of the geodesic flow.
4. Anosov flows and the Holder continuity of invariant distributions For a differentiable flow denote by WO the foliation into the orbits of the flow and by EO the line field tangent to ~VO.
4.1 Definition (Anosov flow). A differentiable flow ¢/ in a compact Riemannian manifold !vI is called Anosov if it has no fixed points and there are distributions K" E 1I c TM and constants C, A > 0, A < 1, such that for every x E !vI and every t 2': 0
(a) E'9(.7:) E8 E"(x) E8 EO(x) = TxM, (b) Ild¢~vsll ::s; CAtllvsl1 for any (c)
Ild¢;t vll ll ::s; CAtllv,,11
for any
Vs
E E"(:r) ,
V 1l
E
E"(x)
It follows automatically from the definition that the distributions ES and E U (called the stable and unstable distributions, respectively) are continuous, invariant under the derivative dq} and their dimensions are (locally) constant and positive. To see this observe that if a sequence of tangent vectors Vk E T!vI satisfies (b) and Vk ----> vETM as k ----> CXJ, then v satisfies (b), and similarly for (c). The stable and unstable distributions of an Anosov flow are integrable in the sense that there arestable and unstable foliations WS and W" whose tangent distributions are precisely E S and E 1I • The manifolds WS(x) and W"(x) are the stable and unstable sets as described in (2.5). This is proved in any book on differentiable hyperbolic dynamics. The geodesic flow on a manifold NI of negative sectional curvature is Anosov. Its stable and unstable subspaces are the spaces of stable and unstable Jacobi fields perpendicular to the geodesic and the (strong) stable and unstable manifolds are unit normal bundles to the horospheres (sec Chapter IV). If the sectional curvature of M is pinched between _0,2 and -b 2 with 0 < a < b then Inequalities (b) and (c) of Definition 4.1 hold true with A = e- a (see Proposition IV.2.9). For subspaces HI, H 2 C T x N1 define the distance dist(H I ,H2) as the Hausdorff distance between the unit spheres in HI and H 2 . We say that H 2 is ()transversal to HI if min IlvI - v211 2': (), where the minimum is taken over all unit vectors VI E HI, v2 E H 2 · Set E'90(X) = ES(x) E8 EO(x), E"O(x) = gU(x) E8 EO(x). By compactness, the pairs ES(x), EUO(x) and E"(x), ESO(x) are ()-transversal with some () > 0 independent of x.
Holder continuity of invariant distributions
91
4.2 Lemma. Let qi be an Anosov flow. Then for every () > 0 there is C 1 > 0 such that for any subspace H C T x "TVI with the same dimension as Es (x) and ()-transverssal to EnO(x) and any t ;::: 0
Proof. Let v E H, Ilvll = 1, v = v, + V uo , V s E ES(x), V uo E EUO(x). Then IIv 8 1 > const . (), d¢-t(x)v s E ES(¢-t x ), d¢-t(x)1I uo E E710(¢-t X ) and Ild¢-t(x)vuoll :::; const ·llvnoll, Ild¢-t(:r)1I s ll;::: C- 1 A- t I11l s ll. 0 A distribution E C T!vI is called Holder continuous if there are constants A, ex > 0 such that for any :r, y E Al
dist(E(x),E(y)) :::; Ad(x,y)" , where dist(E(x), E(y)) denotes, for example, the Hausdorff distance in TM between the unit spheres in E(x) and E(y). The numbers A and ex are called the Holder constant and exponent, respectively. 4.3 Adjusted metric. Many arguments in hyperbolic dynamical systems become technically easier if one uses the so-called adjusted metric in !vI which is equivalent to the original Riemannian metric. Let ¢t : M ---t !vI be an Anosov flow. Let f3 E (A, 1). For Vo E EO, V 8 E ES, V71. E E71. and T > 0 set
111 0
Note that since f3 For t > 0 we have
+ V + 11 8
2
71
1
> A, the integrals
=
2
111 0 1
fo=
+ Iv 12 + 11171.1 2 . 8
Ild~>, I dT and- fo = Ild¢~>, I dT converge.
For T large enough the second integral in parentheses is less than the first one and we get and similarly for V71 . Note that ES, En and EO are orthogonal in the adjusted metric. The metric 1·1 is clearly smooth and equivalent to 11·11 and in the hyperbolicity inequalities of Definition 4.1 A is replaced by f3 and C by 1.
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Appendix: Ergodicity of the geodesic flow
In the next proposition we prove the Holder continuity of g' and EU. This was first proved by Anosov (see [An02]). To make the exposition complete we present a similar but shorter argument here. It uses the main idea of a more general argument from [BrK1] (see Theorem 5.2). To eliminate a couple of constants we assume that the flow is C 2 but the argument works equally well for a C1-flow whose derivative is Holder continuous. 4.4 Proposition. Distributions ES, E U, ESo, EUO of a C 2 A nosov flow der continuous.
q}
are H ol-
Proof. Since EO is smooth and since the direct sum of two transversal Holder continuous distribution is clearly Holder continuous, it is sufficient to prove that ES and E U are Holder continuous. We consider only E S , the Holder continuity of EU can be obtained by reversing the time. As we mentioned above, the hyperbolicity conditions (see Definition 4.1) are closed, and hence, all four distributions are continuous. Obviously a distribution which is Holder continuous in some metric is Holder continuous in any equivalent metric. Fix (3 E ('\,1) and use the adjusted metric for (3 with an appropriate T. We will not attempt to get the best possible estimates for the Holder exponent and constant here. The main idea is to consider two very close points x, y E M and their images qrx and ¢m y . If the images are reasonably close, the subspaces ES(¢/,'x) and Es(¢m y ) are (finitely) close by continuity. Now start moving the subspaces "back" to x and y by the derivatives d¢-l. By the invariance of ES under the derivative, d¢-k Es(¢m x ) = Es(¢m-k x ). By Lemma 4.2, the image of Es(¢m y ) under d¢"'x¢-k is exponentially in k close to Es(¢m-k x ). An exponential estimate on the distance between the corresponding images of x and y allows us to replace d¢-l along the orbit of y by d¢-l along the orbit of x. To abbreviate the notation we use ¢ instead of ¢l. Fix, E (0,1), let x, y E M and choose q such that ,q+l < d(x, y) ~ ,q. Let D :::: max Ild¢11 and fix E > 0. Let m be the integer part of (log E - q log,) / log D. Then
Assume that , is small enough so that m is large. Consider a system of small enough coordinate neighborhoods Ui =:> Vi 3 ¢i x identified with small balls in T¢ixM by diffeomorphisms with uniformly bounded derivatives and such that ¢-l Vi CUi-I. Assume that E is small enough, so that ¢i y E Vi for i ~ m. We identify the tangent spaces TzM for z E Vi with T¢i x Jvl and the derivatives (dz¢)-l with matrices which may act on tangent vectors with footpoints anywhere in Vi. In the argument below we estimate the distance between ES (x) and the parallel translate of ES (y) from y to x. Since the distance function between points is Lipschitz continuous, our estimate implies the Holder continuity of E S • Let v y E Es(¢m y ), Ivyl > 0, Vk = d¢-k Vy = vI:: +v ko, Vs E Es(¢m-k x ), Vno E Euo(¢m-k x ), k=O,l, ... ,m,. FixKE (V73,1). We use induction on ktoshowthat if E is small enough then Ilvkoll/llvl::ll ~ 8K k for k = 0, ... m and a small 8 > 0.
Proof of absolute continuity and ergodicity
93
For k = 0 the above inequality is satisfied for a small enough E since ES is continuous. Assume that the inequality holds true for some k. Set (dq,~-kx4»-l = Ak, (dq,~-ky4»-l = B k . By the choice of D we have IIAk-Bkll :::; const·'YqDm-k =: T)k :::; const· E, where the constant depends on the maximum of the second derivatives of 4>. We have
Vk+l
= BkVk = AkVk + (Bk - Ak)Vk = Ak(V k + vkO) + (B k - Ak)Vk.
Therefore
By the choice of m and D above, T)k = const· 'YqDm-k :::; const· ED- k , and hence the inequality for k + 1 holds true provided D is big enough, E is small enough, v7J < r;, and {) is chosen so that the last factor is less than 1. For k = m we get that Iv~I/lv~1 :::; {)r;,m and, by the choice of m,
Iv uOI < const . Iv;"I -
-'2':..-
'Y I
(q+ 1~ ) log D < const . dist (x y) -
Note that by varying v y we obtain all vectors
~ log D
.
,
Vm
E E"(y).
o
5. Proof of absolute continuity and ergodicity We assume now that M is a compact boundaryless m-dimensional Riemannian manifold of strictly negative sectional curvature. For v E 8M set E S (v) = {(X, Y) : Y = J~(O)}, where Jx is the stable field along 'Yv which is perpendicular to -rv and such that Jx(O) = X. Set EU(v) = -ES(-v). By Section IV.2, the distributions E" and EU are the stable and unstable distributions of the geodesic flow gt in the sense of Definition 4.1. By Section IV.3, the distributions E S and EU are integrable and the leaves of the corresponding foliations W S and WU of 8.M are the two components of the unit normal bundles to the horospheres. 5.1 Theorem. Let 1\,£ be a compact Riemannian manifold with a C3- metric of negative sectional curvature. Then the foliations WS and WU of 8M into the normal bundles to the horospheres are transversally absolutely continuous with bounded Jacobians.
Proof. We will only deal with the stable foliation W S • Reverse the time for the geodesic flow gt to get the statement for WU. Let L i be two Cl-transversals to WS and let Ui and p be as in Definition 3.3. Denote by I: n the foliation of 8M
Appendix: Ergodicity of the geodesic flow
94
into "inward" spheres, that is, each leaf of 2: n is the set of unit vectors normal to a sphere of radius n in ]1.;1 and pointing inside the sphere. Let Vi C Ui be closed subsets such that V2 contains a neighborhood of p(Vd. Denote by Pn the Poincare map for 2: n and transversals L i restricted to V1 . We will usc Lemma 16 to prove that the Jacobian q of P is bounded. By the construction of the horospheres, Pn ===l P as n ----> 00. We must show that the Jacobians qn of Pn are uniformly bounded. To show that the Jacobians qn of the Poincare maps Pn : L 1 ----> L 2 arc uniformly bounded we represent Pn as the following composition
(5.2)
Pn =
g~n 0
Po
0
gn ,
where gn is the geodesic flow restricted to the transversal L] and Po : gn(Ld ----> gn(L 2) is the Poincare map along the vertical fibers of the natural projection 7r : SM ----> M. For a large enough n, the spheres 2: n are close enough to the stable horospheres WS, and hence, are uniformly transverse to L 1 and L 2 so that Pn is well defined on V1. Let Vi E Vi, i = 1,2, andpn(vd = V2. Then 7r(gn v d = 7r(gn V2 ) and po(gnvd = gn V2 . Let Jk denote the Jacobian of the time 1 map gl in the direction of Tl; = Tgk vi L i at gk vi ELi, i = 1,2, that is Jic = Idct(dg 1(gk Vi ) ITJ I. k If J o denotes the Jacobian of Po, we get from (5.2)
(5.3)
n-1 n-1 n~j qn(vd= rr(J~)-l·Jo· rr(J~)=Jo(gnvd·rr(JUJ~). k=O k=O k=O
By Lemma 4.2, for a large n the tangent plane at gn v1 to the image gn(Ld is close to Eso(gnvd, and hence, is uniformly (in vd transverse to the unit sphere SxAI at the point x = 7r(gn v d = 7r(gn V2 ). Note also that the unit spheres form a fixed smooth foliation of SNI. Therefore the Jacobian J o is bounded from above uniformly in Vj. We will now estimate from above the last product in (5.3). By Proposition
IV.2.1O, d(gk v1 , gk V2 ) :::; const . exp( -ak) . d(V1, V2) . Hence, by the Holder continuity of EVa,
Together with Lemma 4.2 this implies that dist(T~, T~) :::; const· exp( -jJk)
with some jJ > o. Our assumptions on the metric imply that the derivative dg 1 (v) is Lipschitz continuous in v. Therefore its determinants in two exponentially close
Proof of absolute continuity and ergodicity
95
directions are exponentially close, that is IIJ~ - J~II ~ const· exp(-rk). Observe now that IIJ':.II is uniformly separated away from 0 by the compactness of 1\;1. Therefore the last product in (5.3) is uniformly bounded in n and VI. By Lemma 2.7, the Jacobian q of the Poincare map p is bounded. 0 We will need the following property of absolutely continuous foliations in the proof of Theorem 5.5.
5.4 Lemma. Let ~V be an absolutely continuous foliation of a manifold Q and let N c Q be a null set. Then there is a null set N I such that for any x E Q \ N I the intersection ~Y(:r) n N has conditional measure 0 in W(x). Proof. Consider any local transversal L for W. Since W is absolutely continuous, there is a subset L of full mL measure in L such that mw(x)(N) = 0 for x E L. Clearly the set UxEi lY(x) has full measure. 0
5.5 Theorem. Let 1\;1 be a compact Riemannian manifold with a C 3 metric of negative sectional curvature. Then the geodesic flow gt : SM -+ SM is ergodic. Proof. Let m be the Riemannian volume in 1\;1, Ax be the Lebesgue measure in SxM, x E M and M be the Liouville measure in SM, dM(X, v) = dm(x) x dAy (v). Since M is compact, m(M) <x and ~l(SM) = m(M) . Ar(SxM). The local differential equation determining the geodesic flow l is ;j;
= v,iJ = O.
By the divergence theorem, the Liouville measure is invariant under gt (see also Section IV.l). Hence the Birkhoff Ergodic Theorem and Proposition 2.6 hold true for gt. Since the unstable foliation ~Vll is absolutely continuous and the foliation W O into the orbits of gt is C I , the integral hull 1:V"o is absolutely continuous by Lemma 3.13. Let f : S1\;1 -+ lE. be a measurable g-invariant function. By Proposition 2.1, f can be corrected on a set of Liouville measure 0 to a strictly g- invariant function .f. By Proposition 2.6, there is a null set N" such that J is constant on the leaves of Wll in S1\;1 \ N". Applying Lemma 5.4 twice we obtain a null set N I such that N u is a null set in W"O(v) and in Wll(v) for any v E SM \ N I . It follows that f is mod 0 constant on the leaf Wll (v) and, since it is strictly g- invariant, is mod o constant on the leaf W1l0 (v). Hence f is mod 0 constant on the leaves of W 1lO . Now apply Proposition 3.12 to WS and W1lO. 0
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Index L(O"j,0"2),18 rl), 32
L(~,
absolutely continuous foliation, 86 adjustcd mctric, 91 Alexandrov - curvaturc, 17 - curvature, nonpositive, triangle, 15 angle, 18, 32 Anosov condition, 6 Anosov flow, 90 asymptotic ray, 25, 28 axial function, 31 axis, :31 baryccntcr, 26 Busemann function, 28
CAT", 15 circumccntcr, 26 comparison triangle, 15 cone at infinity, 37 convcx function, 24
Hadamard manifold, 22 Hadamard space, 1, 22 horizontal - curvc, 63 - lift, 63 .- space, 63 horoballs, 28 horospheres, 28 hyperbolic geodesic, 54 integrable foliation, 89 integral hull, 89 interior metric space, 12
:J(v),73 :JP(v),73 Jacobian, 86 Kx <:::t>,,1, 17 k-flat, 4 lcngth, 11 limit set, 47 Liouville measure, 65, 95
displaccment function, :31 duality condition, 5, 44
M~, 15 Il-harmonic function, 55 measure preserving flow, 83
elliptic function, 31 ergodic flow, 83 Euclidean cone, 3, 38
nonwandering geodesic mod f, 45 nonwandering mod f, 5
¢-invariant function, 82 foliation, 85
GX,43 f -closed geodesic, 52 f-dual, 4:3 f -recurrent geodesic, 45 geodesic, 1, 11 - flow, 4, 43, 64 - space, 12 , minimizing, 11 geodcsically completc, 3, 2:3, 4:3
parabolic function, :31 parallel ray, 25 Poincare map, 86 Poisson boundary, 59 R, 7:3 random walk, 58 rank of a vector, 73 ray, 13, 28 regular vectors, 73
Sasaki metric, 64 semisimple function, 31
Index
112 speed, 11 stable - distribution, 90 - Jacobi ficld, 69 - set, 84
topologically transitive geodesic flow mod r, 47 transversal foliation, 89 transversally absolutely continuous foliation, 86 triangle, 15
standard topology, 32 stationary weak limit, 56 B-transversal subspace, 90 Tits metric, 39
U(x,f"R,c),29
unstable distribution, 90 unstable set, 84 vertical space, 63