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=1i2n(n + I) - 1i2m2 "T 1i2m = 1i2 {(n"T m) (n ± m + I)}, where we used the fact that (A:I:) * =A", and equations (25. 14) for A ;:A:I:' Taking the square root, one finds that N:I: (q, n, m) = eiali {(n"T m) (n ± m + I )P and in the arbitrary phase factor e!a we have taken a = O. VI.3. We have, from equation (25.31 ), that
[
ncr
�
= L..n,(J, ,_1
] [;
- [nl n3+ ln,. 2, nl -- inn32]
_
•
VI.S. The general 2 x 2 Hermitian matrix can be written in terms of four real numbers a, h, c and d as
a
h - ic
h + iC d
=
;
a d a d +
h - ic
241
];
h + ic a d_a d
;
HINTS FOR SOLVINO THE EXERCISES
VI.6. (i) Since the direction of the z-axis is in no way preferred, it follows that the component of 0' in any direction has the eigenvalues ± I . We must find two eigenfunctions Ul and U2 such that (H 2 1 ) u"ul = u" a,P2 = - U2' Since a and {J fonn a basis in S , U l and U2 must b e linear combina tions of a and {J, (H 22) and (H 23) IA I 2 + I B I 2 = 1 , ICl z + IDI 2 = 1 so that Ul and U2 are nonned. From (25.3 1 ) and (26.7) one finds that a,.a ={J a:/a = i{J a,a = a a,,{J = a a� = - ia a� = - {J and since a,. = em = a,. sin 8 cos qJ + a:/ sin 8 sin qJ + u, cos 8 the eigenvalue equation for u" (H 2 1 ), becomes (A{J + Ba) sin 0 cos qJ + i(A{J - Ba) sin 0 sin qJ + (Aa - B{J) cos 8 =Aa + B{J, and taking the inner products with a and (J in turn we get B sin 8 e-ito + A cos 8 =A A sin 0 e}'r - B cos 8 =B. One can easily check that these two equations are consistent, i.e. AlB has the same value calculated from either of them. From the first equation, one finds that B sin 8 e-i" =A( 1 - cos 0) B =A tan (812)ei", and from (H 23) 8 IA I = cos 2 ' We choose the phase factor in A as unity, i.e. o A = cos 2 so that and Ul = a cos
; + {J sin ;ei".
(H 24)
We could similarly find U2t but we determine it more easily from the fact that it must be orthogonal to u" i.e. (Uh uz) = 0, 242
HINTS FOR SOLVING THE EXERCISES
which, with suitable choice of phase factor in "2, easily gives "2 = a sin
� - P cos �e;9'.
(H 25)
The above calculation admits a simple interpretation. Starting with a coordinate system (x,y, z) we have rotated it about the origin to form a new system (x', )", z') so that the new z-axis, i.e. the z'-axis, points in the direction of the unit vector D. The component of the spin vector (J in the direction of the z'-axis is (Jc' = (J" and "1 and U2 are its eigenfunctions. (ii) To find the probability of observing ±1i/2 when measuring s" =1i(J1I/2 on a system in a state = 'PI (r) a + 'P2(r) p we must expand this state in eigenfunctions of (JnI i.e. since . O o . 0 a = "1 cos + "2 sm ' p = "1 sm - "2 cos 2 e-'9', 2 2 2 0 . 0 0 o . ITI r = " 1 'PI COS 2 + 'P2 sm 2 e-'9' + "2 'PI sm 2 - 'P2 cos 2 e-'9' The probability of measuring + 1i/2 for SIlO irrespective of the position of the electron, is then (} (} . O . (} -'.9' 'PI cos 2 + 'P2 sm r-'9'. 'PI cos 2 + 'P2 sm 2e
'P
.} {
{
(
0) .
(
}
•
)
•
�
�
.
= cos 2 ( 'Ph 'PI) + sin 2 ('P2' 'P2) + sin (} Re [ ('Ph 'P2)e- '9I] ,
where Re(z) denotes the real part of the complex number z = x + V', i.e. Re(z) =x. One similarly finds the probability of measuring - li/2 to be sin2
g('Ph 'PI) + cos2 g(V'2. 'P2) - sin
(} Re [ ( 'Ph 'P2) e-i9'] .
These two probabilities add up to unity as required. (iii) We do not know the wave function of the system completely but only that it is of the form tP = '1 a + '2ei3P, where ei3 represents an undetermined phase factor. Though multi plying the wave function as a whole by a phase factor does not lead to a physically new situation, multiplying part of a wave function by a phase factor does lead to observable differences. Carrying out the same analysis for tP which we did for in (ii) , we find for the prob ability of s" having the value ±1i/2,
IClli��:}; IC2I i::}� +
243
'P
±sin ORe['l c2ei(9'-�)] .
HINTS FOR SOLVING THE EXERCISES
We must now average over the unknown phase 8 which can assume all values 0 <8 <2". Since
d"Llne-i3d8 = 0,
the probabilities, after averaging over 8, become Jsin2 ).!! JCOS2� IC1 1 1.sin 2 J2 + IC2 1 1.cos2J2 ° Cases (ii) and (iii) show an interesting difference. In case (iii) we are dealing with a problem which is axially symmetric about the z-axis. Hence the azimuthal angle rp cannot occur in any physically observable quantities, such as the above probabilities. The wave-function lJI in case (ii), on the other hand, is not axially symmetric on account of the phase relationship between the two parts '1'1 a and 'I'zfJ of the wave function lJI, which we assumed known. In a symmetric case we would have (Sit) =0; for 'IJ' one easily finds that Ii (Sit) = 2 (['PI a + 'P2ft] , (tlt['PI a + 'P2ft]) Ii
= 2 ('P1 a + tpzfJ, 'PIP +'P2 a) = 1iRe[ ('Ph 'P2) ] :/=0, showing at once that there is no symmetry about the z-axis. Conse quently physically observable results, such as the probabilities we calculated, will in case (ii) depend on both 0 and rp. Thus, a know ledge of the wave functions '1'1 and 'P2 gives one much more informa tion about the system than a knowledge of ICl l and IC2 1 only. V1.7. From equations (2 7.3) and (2 7.4), it follows that
Since
[Mit' M.1] = [MIt( I ) + M.. (2) , M.1(I) + M,(2)] = [M.( l ), M,( l ) ] + [M.(2), M.1(2)] = i1i {M�(I) + M� (2)} = iliM" etc. M2 =M2 (1) +M2 (2) + 2M(I)M(2),
and from (27.3) and (25.7)
etc, it follows that
[M2 (k), MIt(l)] =0, (k, 1 = 1, 2)
[M2, Mit] = 2[M(I)M(2), M ( l ) + MIt(2)] ; ..
and
[M (2)M(I), MIt(I) ] = M,(2) [M,(I), MIt(I)] + M�(2)[M�(I), Mil ) ] = i1i { - M,(2)M�(1) + M( 2)M,(I)} ,
and similarly
[M(1)M(2), MIt(2)] = i" { - M,(1) M� (2) + M( 1 )M,(2)}, 244
HINTS FOR SOLVING THE EXERCISES
so that
[M2, M..] =0,
etc, proving relations (25.6-7) . We need not derive equations (25. 12-14) anew, as in obtaining these, equations (25.6-7) only were used. VI.8. We are combining the three orbital angular momentum eigenfunctions of a p-state (I ml ) ' (m, with the The resultant 6-dimen and spin states decomposes into a 4-dimen sional product manifold x sional manifold corresponding to j and a 2-dimensional manifold corresponding to j Using the methods of section 27, we obtain for the eigenfunctions I , j, i.e) :
= I), Y'1 ( 1, = - 1 , 0, I) Y'2(!, -!) =p IDl1 Y'2(!,6!) = a. (I) 2 =3/2 IDlt IDli = !.
Y'{a IDlt:t; () (H 26a) Y'(I , ! ; i, i) = Y'1 ( 1, I) Y'2{!, t) = Y'l(l, I)a, Y'(I, ! ; i, t) = y1 3 {V2Y'I(I , 0) Y'2(!, !) + Y'1 ( 1, 1 ) Y'2 {!, -!)} (H 26b) = y1 3 {'V'2Y'I(I , O) a+ Y'1 ( 1, I)P} ; Y'{I , ! ; i, -!) = y1 3 {'V'2Y'I(I , 0) Y'2{!, -!) + Y'I(I , - I)Y'2{!, !)} (H 26c)
t; ) 1Y' (I, P(I, t, ! Y'( I , ! ; t), A + {a Y'I(I , 0)Y'2{!, t) + hY'I(I, I) Y'2 (!, -!)} =0
(H 26d)
by choosing a linear combination of (b) IDli : We obtain 1, equation (H 2Gb), and I )P orthogonal to or so that A+ operating on it vanishes :
Y'1 ( l, O) a
i.e.
hence
Ifl(l, !; t, !) = y1 3 {Y'1 { 1, 0)Y'2 (t, t) - y 2 P1 (l, 1) Y'2 (t, -t)} (H 27a) = y1 3 { Y'1 ( 1, O) a - V2Y'1 ( 1, I)P} 1 1JI( I , t; t, -t) = 3 { - Y'l (l, 0)Y'2 {!' -t) + y 2 P1(I, - 1 )Y'2(!, tn y .r
. /-
(H 27b) 245
HINTS FOR SOLVING THE EXERCISES
VI.9. To see how the 8-dimensional spin space 61 x 6z X 63 decom poses into manifolds corresponding to given eigenvalues of SZ, we firSt combine 61 and 62 according to the scheme of Example 2, section 2 7 :
61
x
6z =IDll ( I 2) +IDlo( 12)
(where we have written IDll(12) and IDlo(1 2) to indicate that these are product spaces of particles I and 2), and then we combine each of these with 63, according to the schemes
IDll( l2) IDlo( 12)
X
x
63 =IDlt +IDli'
(H 28a)
63 = IDli""
(H 28b)
where we have used primes to distinguish the two doublet manifolds. We span the manifold IDll( 1 2) by the eigenfunctions (27 . 1 6a--c) and IDlo ( 1 2) by (2 7 . 1 6d) . In the decomposition (H 28a) we then combine an angular momentum I with an angular momentum t. This is exactly the problem we treated in Exercise VI.8, and the results we obtained in that exercise hold here. For in considering the addition of angular momenta in section 27 we were not interested in what the actual wave functions are, but only that they should satisfY certain eigenvalue equations. Hence we obtain the eigenfunctions !P( I , !- ; !, m) and !P( l , 1; !-, m) spanning the manifolds IDl. and IDli' in (H 28a) by com bining equations (H 26a-d), (H 27a-b) and (27. 1 6a--c) :
(a)
IDlt :
!PH, !) = al aZa3
(H 29a)
1
!P(t, t) = v3 {at azP3 + aZaJPl + a3alPZ}
(H 29b)
- = � {alPzP3 + aJJ3Pl + a3PJP2} !P(t, - i) = PIPzPJ ; !P(!,
t)
(b) IDlt' :
!P(t,
t)
(H 29c)
3
=
!PH, - !-) =
(H 29d)
� {�2 ( atPZ + azPt ) aJ - V2at azPJ} )3{ - )2 ( a1Pz + azPl) P3 + V2PlPz a3}' 3
We easily obtain the other 2-dimensional manifold combining the singlet state (27. 1 6d)
I v2 ( alPZ - a2P1 ) 246
IDlt
(H 30a) (H 30b) arising from
with aJ and PJ : (e) IDlt" :
HINTS FOR SOLVING THE EXERCISES
'P(!, !) = v21 ( aJP2 - a2PJ) a3 'P(!, -!) = v1 2 ( alP2 - a2PJ)P3'
(H 3 I a) (H 3 I b)
If we again consider the symmetry under the permutation of particles, it follows from the fact that the triplet states of particles I and 2 are symmetric and that IDl: and IDlt' are derived from these, that °IDlt and IDlt' contain only wave functions symmetric in 1 and 2. Furthermore, IDl, contains only wave functions symmetric in all three particles, as one sees from equations (H 29a-d) . Similarly IDlt· con tains only wave functions antisymmetric in particles I and 2 as it is derived from the singlet state
�2 { a1P2 - a2P1} '
We could of course equally well have combined the spin states of any other pair of particles to begin with. This corresponds to per muting the suffixes 1 , 2 and 3, labelling the particles, in the above equations. This does not affect IDl: which is completely symmetric, but the resultant 2-dimensional manifolds IDlt' and IDlt" are different. Together they, of course, span the same 4-dimensional manifold
61 x 62 x 63 -IDlI•
In practice, this ambiguity ofstates does not usually arise. On account of the Pauli principle (section 28) , the symmetry properties of the wave functions are usually prescribed. VI. 10. By simply interchanging the labelling 1 and 2 of the particles we have H(2, 1 ) '1'(2, 1 ) = EV'(2, 1), and since H( l , 2) = H(2, 1 ) the result follows. VI. I l .
Substituting (28.3) into (28.4) gives
(l a I 2 - lbI 2) I V' ( I, 2 ) 1 2 + ( lbI 2 - l a I 2) I V' (2, 1 ) 1 2 + (ab - ba ) V' ( I , 2) '1' (2 , I ) + (b a - ab) V' (2, I ) V' { I , 2) = 0. Since V'{ I , 2) is an arbitrary wave function, this equation is only satisfied if la l 2 = lbl 2 and ab = bii.
b
H ence, if a =Aeia and = Bei(J (A, B, a, P real and A >0, B >0), we require ei(a-(J) = eiCJl-a), A =B
i.e. (a - P) = nn, (n = 0, 1 , 2, . . . ) ,
so
247
that a = ± b, and (28.5) follows.
HINTS FOR SOLVING THE EXERCISES
2
VI. 1 2. Let I and denote the protons, and 3 the neutron. There are two doublet spin states which we obtained in Exercise VI.9, equations (H 30) and (H 3 1� ; we write them
= J2 {a1fJ2 - alfJl) a3 1 E"-0'2; 3) = ...j2 ( alfJ2 - alfJl) fJ3
E"+ ( � ; 3)
and
= J3{J2( alfJ2 + a2fJl) a3 -v'2alalfJ3} E,- ( f2 ; 3) = J3{ -�2 ( alfJ2+alfJl ) fJ3+V2fJlfJ2a3}.
E,+ ( rn ; 3)
The total wave function must be antisymmetric in the proton co ordinates, but there is no restriction as far as the single neutron is concerned. If q>,( � ; 3) and q>,,( i2 ; 3) denote spatial wave functions of the indicated symmetry properties then the total wave function is of the form
4}:I: ( � ; 3) =aq>,(rn ; 3) E,,:!: ( i1! ; 3)
q>
+ h ..( f2 ; 3) E,:!:(T2 ; 3), = ±1i/2. 28.)
As for the
where the ± signs indicate the spin states with SJ; a-particle, one finds that tendency to be in a singlet state. (Gj end of section
Ihl
CHAPTER VII
VII.2. The perturbation of any energy level En, equation given by equation
(29.13). VM = af:..,X3 1V'n(X) \ 2dx. V(x) =ax3 is V',,(x), l 'fn( -X)l 2 = I ",,,(x) 1 2, V",, = O.
Since the perturbation and the oscillator wave function definite parity, so that
(11.15),
is
V( - x) = - V(x),
an odd function, equation ( 1 1 . 23), has always a it follows that
This result is generally true for states of definite parity and perturba tions of odd parity. Second-order perturbation theory will, in general, give a displacement of levels.
11, 1 .1 ) (29.13) E.=(n + �)1iQ).+ V..
VII.3. Using the notation of section levels are, according to ( 1 5 and
,
248
the perturbed energy
HINTS FOR SOLVING THE EXERCISES
f.
where v_ - .
{X''P,(X)) 2tfx -
� f. {E'to, (m 'dE.
where we have used the fact that the oscillator eigenfunctions, equation ( 1 1 .23), are real functions. Applying the recurrence relation ( 1 1 . 19) twice, one obtains E2Hn( E) = 1 Hn+- 2 (E) + ! (2n + I)H,, ( �) + n (n l } H,, 2(E) , -
-
and using the orthogonality relation ( 1 1 .22), one obtains
V
""
=3
(
)
a1i2 4 m 2cu02 ( 2n 2 + 2n + l ) .
VIlA. To carry out the second-order perturbation calculation, we must solve equation (29.8c), as well as (29.8a-b). Taking equations (29.5) to (29. 14) over unchanged and putting CD
f/'x(2) � b,f/',(O), 1 =
,-
equation (29.8c) gives on substitution co
co
co
co
� b,E,(O}f/',(O) + V� a,f/',(O) = Ex(O)� b,f/',(O) + Ex(l)� a,rp,(O) + EX(2)f/'x (0) ; , -1 ,-1 ,- 1 ,-1 and taking inner products with rp,(O) : CD
b,E,(O) + � a, V.. = b,Ex(O) + a,Ex(1) + EX(2)8x,. ,-1
Separating the cases s = N and equations (29. 1 3- 1 4), and
s :pN,
the last equation gives, using
� ' Vx, V,x Ex(2) = L. , Ex(OJ _ E,(0)'
(s = N) ,
axVIN Vxxv'x V"V,x �, b, = f (Ex(O) _ E,(O» (Ex(O) - E,(O» - (Ex(O) _ E,(O» 2 + Ex(O) _ E,�O)'
(�:pN)
where, as before, the term r =N is excluded from the summation
2:'.
aN and bx from the normalization condition IIrpNCO) + ef/'x( l) + elrpX(2) II = I which must now be satisfied up to terms in 62• In this way, we obtain
We again determine
the two conditions
aN+ aX= O bN + hN = - 1:/0,.1 2•
,
These two equations again fix the real parts of aN and bx• As in section 29, we can again put the imaginary parts of ax and bx equal to 249
HINTS FOR SOLVING THE EXERCISES
zero, corresponding that
to
a particular choice of phase factor for
tpN, so
aN =O bN= - t2:l a,1 2. ,
Using these results, we finally obtain the following expression for the energy levels and the energy eigenfunctions according to second-order perturbation theory:
12 ," ' I(OVN, EN = EN(0) + 8 VNN + 82 £.. (H 32) ) EN - E,(O) ' V,N ,"' (0) , tpN = tpN(0) + 8£.. , tp EN(0) _ E,(O) V" V,N V,NVNN ," ' tp,(0) ,"' + 82� � (EN(O) E,(O») (EN(O) _ E,(O») - (EN(O) E,(O») 2 2 (H 33) - �"'ItpN(0) (E (O)I V-,NIE (O») 2 ' , N
{
VIi.5.
e/e.
[
The matrix H -
Under the
}
_
r'
1>,
J
El + eEl '·
u]'
where
[g]
,
A and p
m m [�] m:] m [gl } (H + e V)
-+-
-
+e
The eigenvalue problem
(E, + eE, ')
i.e. to first order in e:
Hence
]
has the eigenvectors �, -
E perturhation, H � H H V, ¥, �
are of the first order in e, and El becomes
_
-E'
+ sE' '
El ' = Vl 1 E E A( I - 2) = 8 V21 ' P(EI - E3) = 8 V31
[s]
which is just what we should expect from equations (29. 1 3-14). If El = E2, the above method breaks down: A is no longer small. This is b
250
[�],
eigenval ue EI • eigenvector
HINTS FOR SOLVING THE EXERCISES
Hence we now write the corresponding perturbed where only . i• •mall, of order e. To first order in _,
}.
the eigenvalue problem now gives (denoting the perturbed eigenvalue by El + eE')
e ( Vll " + V1 2l') = eE'). e ( V21" + V22I') = eE'1' E3v + e ( V3 1 " + V321') = E1v
The last equation gives
e V3 ). + V321') V= ( 1 E. - E3
•
The first two equations are homogenous in ). and I' and only possess a nontrivial solution if
V1 2 1 = 0. I Vll - E' V22 - E' V21
This is the secular equation which is quadratic in E' and thus gives two solutions EI ' and E2'. Corresponding to each of these, we obtain a value of "II' and hence, apart from normalization, an eigenvector (if sections 22 and 30). CHAPTER VIII
VIII. I .
For a solution depending on the radial coordinate
V 2 reduces to
only,
V2 = .!.2 �(r2 !!..) . r dr
dr
Hence
so that
r
( V2 + k2) ( -
::) = eib( -;nV2�) = eib8(r)
,
(H 34)
from equation (33.2) . We can omit the exponential factor eUr from the right-hand term of equation (H 34), since 8 (r) vanishes, except at r = O, and in that case the exponential becomes unity, proving the required result. The result for the second solution ( - e-lkr/4nr) follows at once by taking complex conjugates throughout the above proof. 251
HINTS FOR SOLVING THE EXERCISES
VIII.2. From the discussion leading to equation (33.16), we expect the required transition probability per unit time to be
�1(eiklr9',{q), VCr, q)V'(r, q»1 2(;!)3 8(E' - E) ,
( H 35)
where E is the initial energy of the system, equation (36.3) , and E' the final energy :
E' = ' + 2}'Ti2k 2 E
I •
35)
One easily verifies this by integrating (H over tIk, to eliminate the 8-function, and dividing by the flux of incident particles, Tiko/p, to give the same expression for the cross-section as before, equation (36.1 4). VIII.3. To obtain the first Born approximation, we replace the true wave function by the zero-order approximation
'P(r, q)
tfkor9'o(q)
[if equation (36.4)] on the right-hand side of equation (36.6). gives for the function F, defined in equation (36.8),
W(r)
{r), F,(r) = eikor!dq9',(q) U(r, q)9'o(q) =eikor� W(r) .
This
represents a mean potential, averaged over the internal coordi nates of the scatterer, which the incident particle experiences. The cross-section then becomes, from equations (36. 1 2) and (36.1 4) ,
= (hl(2�2rl!W(r) eiCk.-kllrdr r, [if equation (34. 1 )]. Ti (ko - k,) again represents the momentum which the incident particle has transferred to the target during the a(O, 9')
collision. VIII.4. If and are the position vectors of the two particles, then the wave function of the two-particle system can be written (if Exercise III.3)
rl
r2
rl + r2) x(r) (r = rl -r2), 'P(r" r2) =IP(2-
the wave function tP which describes the motion of the centre of mass of the system being symmetric in the coordinates of the two particles (since they have the same mass) , and describing the relative motion. If we treat the two particles 1 and as different, and hence dis tinguishable, to begin with, then the asymptotic form of the wave function in the C.o.M. system
2
is
x(r)
ei" + !d4" f(O, 9'), r
252
HINTS FOR SOLVING THE EXERCISES
( r, 0, rp) being the polar coordinates of the vector r giving the position of particle relative to particle Since the polar coordinates of the vector r (corresponding to interchanging the two particles) are (r, n 0, n + 9'), [if equation the asymptotic forms of the wave functions, symmetric and antisymmetric in the spatial coordi nates respectively, are
-
-
2. (13.24) ]
1
-
( ei" ± e -i.t�) + db[J( O, rp) ± /(n 0, n + 9') ]. r Hence we obtain for the cross-section, by arguments analogous to those in section a(O, tp) 11(0, 9') ±/(n - 0, n + 9') We can also see this result in another way. If particle is scattered through angles n 0, n + 9', particle flies off in the opposite direction, 0, 9" Hence the scattering amplitude corresponding to this process must also be included in the cross-section a(O, 9'} if the two particles are identical. VIII.5. A qualitative justification for neglecting exchange effects in the case of fast electrons was given at the end of section Since we are dealing with fast electrons, the validity criterion for the Born approximation is satisfied, so that we shall describe incident and scattered electrons by plane waves. To calculate the cross-section, we use the method of section Equations and then give for the case of elastic scattering in the Born approximation
32,
' 2.
=
-
2
I
36.
(36.12)
/(0) =
36.
(36.8)
- 4�Ie-i"rdrIds9'(s) ��( -� + Ir: s ,) rp(s) eikor,
for an electron to be scattered from a state with momentum liko to one with momentum lik (both states having the same kinetic energy the wave function of the atomic electron in the ground state of the hydrogen atom being
E=n2ko2/2m =1i2k2/2m),
I
rp(s) = vn ate-
(r, s are position vectors of incident and atomic electrons relative to the nucleus.) We can write this expression for the scattering amplitude
= - 2:n2IV(r}ei(ko-klrdr where e2 } 1 VCr} = - - + e2 Irp (s} 1 2 _r 1r - s I ds . Comparison with equation (34.1) shows that VCr) represents the mean potential which the hydrogen atom presents to the incident electron. This is physically reasonable. The first term ( -e 2/r) represents the 253 /(0)
HINTS FOR SOLVING TilE EXERCISES
Coulomb field of the nucleus, the second term (the integral) represents the Coulomb field of the atomic electron whose charge density dis tribution is _ eltp(s) 12. Evaluating V(r), we obtain V(r) = -e2 (� + a) e-2"', showing that we are dealing with a spherically symmetric potential as we indicated by writing V(r) rather than VCr). We can now use equations (3'1,.3) to (34.5) directly, rather than repeat the angular integration, and obtain /(0) -
;.':;f U + aje-'. sin(K,),d,
2me2(Saz+ K2) = fi2(4a 2 + K2) 2 . Hence we obtain for the differelllial cross-section (H 36) where K=2k sin(OJ2), equation (34.5). Integrating equation (H 36) over all scattering angles we obtain Ihe total cross-section,
L"a(O) sin 0 dO
u,c, ,,," 2n = 271: so that
I
I
KdK a(O)"""'I2 '
K_.
_� (me2) 2(12a4 + ISa2k2 + 7k4) a2(a2+kz)J 3 li2
Vrn.6. From equations (38.29) and (32.12) atOI
2l + 1 ) (2l + l )ej{�J--d,') sin 8/ sin 81' - 1.�i2.2.( / /' •
'
x
•
f
271: +l p/(x)Pr(x)dx. -I
From ( 1 3 . 1 6-17) tlus integral equals 2811'/(2l+ I ) , giving at once (38 .30) .
VIlLS. Consider the potential ).V(r), with ). a continuously varying parameter: 0,).<1. The phase shirts SI will then be functions of )..
254
HINTS FOR SOLVING THE EXERCISES
Correspondingly, we write instead of (38.38) :
[
d2 v,(r, i.) + k2 - i.U(r) dr2
-
1)]
1(1 + � v,(r, i.) =0
and a similar equation with ()' + .1 i.) instead of ).. section 38, one finds
d sin 8,().) di.
=
-
Proceeding as in
1 r = U( r) [v,(r, i.) ] 2dr kJo
which is always <0 or �o, according as U�o or U <0 respectively.
VIII.9. We can solve the wave equation (38.38) explicitly for the case under consideration (if. section 8 and Exercises 111.4. and III.5 where similar problems are treated) : if r
vo (r) = A sin kir,
vo(r) = sin (kr + 80), if r>a,
where k and k.. are related to the bombarding energy E and the potential depth Vo by
!i2k·2 E = 1i2k2 2", ' (E + Vol = 2� .
The two constants A and 80 are to be chosen so that Vo and dvo/dr are continuous at r = a. This gives tan
k (ka + 80) =f. tan (kjil), ,
yielding 80• As E, i.e. k tends to zero, 80 _ o. The corresponding cross-section is given by 0'0 = (4n sin2 80) Ik2• The last equation gives
0'0 = 4na2 since
[tan koa - 1 ] 2, koa
CHAPTER IX
IX. I . For n = 2, 62 consists of only two elements, the identity E and the permutation Pu, and hence is Abelian. (The same argument proves that the inversion group is Abelian.) For n >2 , we need only consider 63• For the permutations of 6) all occur in 6n and hence if these are not commutative, 6n cannot be Abelian.
255
HINTS FOR SOLVING THE EXERCISES
A, B, C PJ2P13(ABC) =P12(CBA) = (BCA) P13P12(ABC) =Pu (BAC) = (CAB),
PiJ
arranged in definite order, let be the Given three objects operator which exchanges the objects in the ith and jth places. Then
so that63, and hence
6" with n >3
as
well, are not Abelian.
IX.2. Carrying out the permutation is simply a relabelling of the variables of integration in the integral defining the scalar product, and this is hence invariant. We illustrate it for n = 2 :
(f(r., r2), g(r., r2» = (f(r2' rl), g{r2, rl» = (P12f{r., r2), Pug (r., rz».
IX.3. The proofS are closely analogous to that o f section 4 1 for spinless particles. We shall indicate the proof of one of the three results only, namely for the operators T, of the total function space. From the first of equations (42.6) and (42.8), it follows that for any wave function
{S, • • • }
{9'I(r)a+9'2{r)p} Tr(r, a) {9'I(r)a + 9'2(r)P} =r(t-Ir, 1-1 0) {9'1 (t-Ir) [ci a +C2P] + 9'2(1-lr}[Cl a +C4P]} = r(r, 0) {9'I(t-Ir)[Cl a+ czP] +9'2(t-Ir)[C3a+C4P]} =r(r, 0) T{9'I (r)a + 9'2(r)P} T-t T-I[9'l(r)a + 9'2(r)P] = 9'1 (tr)[Ct 'a +C2'P] + 9'2(tr)[Cl'a +C4'P] c/ a' {J': a' =cI' a+ c2'p, {J' =c3'a+ c/{J. S S •
The converse follows exactly as equation (41 .4) if we define the inverse operator appropriately. From equation (42Aa) this definition is
where the
are the coefficients of the solution of (42.2) for
and
IXA. For two particles is a good quantum number. So we still have a pure triplet state. L is no longer a good quantum number, = 1 to though J = 1 is. The L values which can combine with give J = 1 are L = 0, 1, 2. However, parity is a good quantum number, and for two particles with relative orbital angular momentum L the parity is - ) ) L ; i.e. the and states have opposite parity to the P state. Hence the ground state becomes a mixture of and states when tensor forces are present.
(
S
D
3S1
T-1V'1
V'I (V'., Ttpz) TV' 2
3Dl
is any vector in 9Rh then is in 9RI (since 9n 1 is in IX.5. If = variant under &). Hence, iftpz is any vector in9R2J then 0, i.e. =0. Hence Ttpz is orthogonal to and since is any vector of 9n., is orthogonal to the whole space But 9R is invariant and '1'2 a vector ofIDl, hence lies in 9R and therefore in 9R2•
T'P2
256
T-IV'h 'P V'h ( V'I z) IDlI•
HINTS FOR SOLVING THE EXERCISES
IX.G. The theorem is proved, if we can prove that any invariant manifold £In of the group & = {S, T, } is completely reducible into one-dimensional invariant manifolds. Let £In be such an n-dimensional manifold. Since the operators of OJ all commute with each other, they possess a set of orthonormal mutual eigenvectors tp h 11'2, • • • spanning the whole function space � : •
Stpi = S;9'b Ttpi = litp;,
•
•
(i = I , 2 ,
,
). We can decompose each vector tpi uniquely into two parts •
•
•
•
.
.
tpi = Ei + 7]i
such that Ei and 7]i lie in the invariant manifolds £In and � -£In (if Exercise IX.5) respectively. Hence the equation
TEi = tiEi + (Ii - T)7]i
implies that
TEi = liEi' T7]i = 'i7]i (since TEi must lie in £In, and ( Ii - T)7]i is orthogonal to £In), i.e. the
manifolds £In and � -£In are separately spanned by orthonormal sets of mutual eigenvectors of the group &, and each such vector defines a one-dimensional invariant subspace.
IX. 7. 1 and (J are pseudo-vectors under total rotations and inversion. Hence we at once find the selection rules :
(i) no change of parity; (ii) IJJ J' J = 0, ± 1 (not 0
-
-
0) .
Let us next again assume that total spin and orbital angular momenta by themselves are good quantum numbers. The orbital and spin parts lead to different selection rules for L and S. (J and 1 are of course invariant as far as rotations in orbital and spin space respec tively are concerned. Hence we obtain these selection rules : (a) orbital part of interaction :
.1S= O IJ L = O,
(not 0 _ 0) ;
± 1,
(b) spin part of interaction :
.1S =O, ± 1, (not 0 _ 0) . IJL = O.
IX.B.
We must show that
f-
- ilie
11"
ax
is proportional to (45.19) . I f E and and 11" then
II'
257
a
tpdr
E'
(H 37)
are the energies of the states
HINTS FOR SaLVINO THE EXERCISES
V2rp 2m(E - V)rp V21rp 2m{E' - V) rp , 2 fdr(rp'- xV2rp -rpxV2rp') - m(E' - E)frp'xrp - dr. ""
""
and hence
- 1i 2 -
"2
-;
=
,,2
(H 38)
The right-hand term is proportional to the electric dipole term (45. 19). We need only show that the left-hand term i s proportional t o equation (H 37). We can replace the left-hand term in (H 38) by
fdr{qi'V2(Xrp) - (Xrp)V2q?} - 2f"rpI!:dr.
(H 39)
(This
follows, since one easily proves from equations (A4), (A5) and (A6) in Appendix A, that
V2(Xrp) = xVlrp + 2:.)
The first term in (H 39) can be transformed into a surface integral, by Green's theorem, equation (Al l ) , over a surface at infinity, which vanishes. The second term is proportional to (H 37), proving our result. IX.9.
The operator
� P.(k) 4 c(k» 2.(�4 4-1 + x p
occurring in the matrix element of the quadrupole transitions has parity 1), and it was so chosen as to transform according to under rotations. Since
(+
il2
.1L12 X;&Ij = { ilt.i)22'+j + . . . + ilI2-jl
tr'\
tl'>
if ] =0
1. if] >"l"'
we at once have these selection rules (with the same notation as in section 45) :
(i) (ii)
L1] = O, ± l , ± 2 ;
)
(
nat o -+ 0 not 0 -+ 1 not 1 -+ 0
no change in parity,
If L and 8 are also, separately, good quantum numbers, one obtains the additional selection rules :
(iii)
L18 = 0 ;
(iv)
L1 L = L1]
[as under
(i)]
258
HINTS FOR SOLVING THE EXERCISES
CHAPTER
X.2. 0 a.t = [ (I.t
X.3. (46.9) . X.4.
c,.t =
X
(I.t] 0
- i"1 "2"3 ".t, from which (46. 1 8) at once follows, using
From the Dirac equation : 0", 0", ".t- + "4 � + M", = O. oX.t I tlXo
Taking complex conjugates, transposing and postmultiplying by
"4 :
0",* 01J'* -Y.tY 4 - . - Y42 + MV' *Y 4 = 0 18xO OXk
and since
and Vi = "'*"4, equation (46.21 ) follows.
".t Y4 = - " 4Yk
X.5. Differentiating (46.24b) and using the two Dirac equations (46.7) and (46.2 1 ) , (46.25) follows at once. X.6. (u" u,)
4
= L U,(4) ·U,(4) ; a- I
l1,u,
=
•
L
at 6-1
u,(0) · " 4Q6 U,<").
The desired results follow directly, using (46 . 1 4) and (48.4) . X.7. (i) For half the cases this follows from the orthogonality of the spinor parts (if Exercise X.6.) ; for the remaining cases it follows since the spatial parts of "'1 and 1J'2 are orthogonal to those of "1'3 and ( ii) = (u" u,) = Ep/mc2, from equations (48.4), i.e. tp, is normalized to a density of Ep/mc2 particles per unit volume. In the rest system of the particles this reduces to the usual density of 1 particle per unit volume. (iii) The reason for the normalization to a density (! = Ep/mc2 particles per unit volume is that this is Lorentz invariant. To see this, consider a volume V containing N particles having energy Ep. Under a Lorentz transformation to a new coordinate system having a relative velocity v = {Jc, V - V' = V( I - {J 2)�, Ep _ Ep' =Ep(I - {J2)4. Hence
tp4 '
(tp" tp,)
(!
,
_
N N _
- V' - V
V
_
N EP'
V' - V
Ep EP' EP' E-p - mc2 Ep - mc2' _
_
X.8. We must prove [ap, H] = 0 . This follows at once from equa tion (47.8), which gives [ aP, H] = 2CY 4P (Y " P) = 0. X•9 • If XA - xI'I = apAxA and xI'i - Xpll = bpp.xp.I, then x" _ X." = cpAx,., where C.A = bppa/
HINTS FOR SOLVING THE EXERCISES
Also IC,JI = Ib,,,l laIlJI = 1, showing that the composite transformation is also a proper Lorentz transformation. From C•.t = b."a".t and (49. 1 0) one sees that CII and C44 are real, Cf4 and C4� are pure imaginary. For in the former case the factors a and b are both real or both imaginary. In the latter case, one factor is always real but the other imaginary.
260
APPENDIX A :
VECTOR ANALYSIS
IN this appendix we give a brief summary of the definitions and theorems of vector analysis required in this book. The reader not familiar with these will find clear and simple expositions in the books by Abraham-Becker6 or Hague 7. (1) If A is a vector with components (Ax, A" A.c) we define its magnitude A = IA I = Y {A..2 + A.,2 + A.c2} . (A 1 ) (2) If A and B are vectors, components (A.., A" A,) and (B.., B" B,) respectively, we define (a) the scalar product AD =A..Bx +A,B, + A)1.c = AB cos 8, (A 2) where 8 is the angle between the vectors A and B ; in particular AD = 0, if A is orthogonal to B; (b) the vector product A A B as the vector C with components C.. = A,B, - A)1, C, = A.cB.. - A..B, C.c =A..B, - A,B... If i, j, k are unit vectors in the directions of the coordinate axes, so that A =iA.. +jA, + kA.c, and i2 =j2 = k2 = 1 , ij =jk =ki = O, we can write the vector product as a determinant j k C = AAB = i (A 3) A.. A, A, B" B, B, . C is a vector of magnitude AB sin 8, whose direction is normal to the plane containing A and B, such that A, B and C form a right-handed coordinate system. (3) Let tp(r), tp(r) , x(r), . . . be scalar fields (e.g . temperature, electrostatic potential, etc), and let F(r), G(r), be vector fields (e.g. fields of force), we then define (a) the gradient of tp(r) as the vector .8tp .8tp . 8tp grad tp = 1 x + +k (A 4) v t[ . 8 J(!y 8;; ' (b) the divergence of F(r) as the scalar 8F.. 8F, 8F.c " � t- : d'IV F = - + - + (A 5) " 8x 8y 8t '
}
•
2 61
•
•
APPENDIX A: VEOTOR ANALYSIS
(e)
the curl of F(r) the vector curl F (r) = i as
j a ay F,
a ax F.
If, in
k a aZ. F�
particular, F=grad rp, we obtain dlV grad rp=V2rp = aPxrp", + Piryrp2 + PaZ.rp" ; (A 6) ifF=rpG, then (A 7) div (rpG) = rp div G + G grad rp ; ifG=grad V' (A 8) div (rp grad V') =rpV"tp+ grad rp grad V'. (4) We state Gauss's theorem for a vector field F(r) : (A 9) fy(div F)dT= fSFAdS. Here is the surface bounding the volume V. The left-band integral is a volume integral over V, the right-hand integral is a surface integral over S, being a surface element of S and Fn the component of the vector F in the direction of the outward normal to dS. Ifwe take F= rp grad V', then FA = rpatp/an, where a/an denotes differ entiation with respect to the outward normal, and Gauss's theorem assumes the form (A 10) grad V + : 'vdr �grad 9' Ipd.. Interchanging rp and V' in this equation and subtracting the resulting equation from (A 10), we obtain (A 11) -,,!!}ISEquations (A 10) and (A 1 1 ) are known Green's theorem. •
S
-
dS
L'P� - f fJ'P!:
f
L('Pvz,p-"V"P)d" as
262
BIBLIOGRAPHY following bibliography, which is clearly in no way exhaustive, is merely a list of books helpful to the understanding of this book or suggestions for further reading.
THE
A.
Mathematics (eigenvalue problems, spedalfuTl&tions, etc) Fourier Series and Boundary Value Problems McGraw
1 CHURCHILL, R. V.
Hill, 194 1 . (Eigenvalue problems, Fourier series and integrals, Legendre and Bessel functions.) 2 COURANT, R. Differential and Integral Calculus Blackie, 1942. (Vol 1 , chap. IX : Fourier series ; vol. 2, chap. IV : Fourier integrals.) .
3
MatheT1UJticalIy advQTI&ed comprehensive treatments are the following : COURANT, R. and HILBERT, D. Methoden der mathematischen Physik vol. 1 ,
Springer, 193 1 (and Interscience, 1 943) . There exists now an English translation, with additions, of this work : Methods of Mathematical Physics vol. 1 , Interscience, 1953. 4 SOMMERFELD, A. Partial Differential Equations in Physics Academic Press, 1949. 5 VON NEUMANN, ]. Mathematische Grundlagen der Qjlantenmechanik Springer, 1932 (and Dover, 1943) . English translation by R. T. BEYER, Prince ton University Press, 1 955. (A rigorous abstract treatment of the mathematical scheme of quantum mechanics and its interpretation.)
B. 6
7
Vector analysis
M. and BECKER, R. Classical Theory of Electricity and Magne tism Blackie, 1 946 (chapters I and 2). HAGUE, B. An Introduction to Vector Analysis Methuen, 1 950.
ABRAHAM,
C.
Q,uantum mechanics 8 BORN, M. Atomic Physics 3rd ed., Blackie, 1944. II HEITLER, W. Elementary Wave Mechanics Oxford University Press, 1 945.
(An elementary introduction to the physical interpretation of wave mechanics. ) 1 0 MOTT, N. F. and SNEDDON, I. N. Wave Mechanics and its Applications Oxford University Press, 1940. 1 1 PAULING, L. and WILSON, E. B. Introduction to Qpantum Mechanics McGraw-Hill, 1 935. 1 2 S CHIFF, L. I. Qpantum Mechanics McGraw-Hill, 1 949. (This book, which contains many applications, approaches quantum mechanics from a viewpoint rather similar to our own.) 1 3 SOMMERFELD, A. Atombau und Spektrallinien vol. 2, 2nd ed., F. Vieweg, Brunswick, 1 944.
263
BmLIOORAPHY
1 4 SOMMERFELD, A.
Wave Mechamcs Methuen, 1930. (This is the English translation of the first edition ( 1 929) of Ref. 1 3. Hence 1 3 is much more up-to-date and gives a better and more detailed treatment of many topics.) TIllfollowing are more advanced treatises on quantum mechanics :
1 5 DIRAC, P. A.
M. TIll Principles oj Qpantum Mechanics 3rd ed., Oxford University Press, 1 947. 1 6 HEISENBERG, W. Physical Prindp/es oj the Q;uzntum Theory University of Chicago Press, 1 930. 1 7 PAUU, W. Die allgemtinen Pri�ipien tier Q;uzntenmechanik, lIandbuch dtr Physik vol. 24, part 1 , Springer, 1 933. 18 VON NEUMANN, J. See reference 5.
Applications oj quantum mechanics to particularfields 1 9 BETHE , H. A. and MORRISON, P. Elementary Nuclear Theory, 2nd ed., Wiley, 1 956.
D.
J. M., and WEISSKOPF, V. F. Tlltoretical Nuclear Physics Wiley, 1 952. 11 CONDON, E. U. and SHORTLEY, G. H. Theory oj A tomic Spectra Cam bridge University Press, 1 95 1 . 1 1 MOTT, N. F . and MASSEY, H. S. W. Theory oj Atomic Collisions Oxford University Press, 1 949. 2 3 VAN DER WAERDEN, B. L. Die gruppentheoretische Methode in der Qpanten mechanik Springer, 1 932 (and Edwards, ( 944) . 1 4 WENTZEL, G. Wellenmechanik dtr Stoss- und StrahlungsIJorgiinge, Handbuch der Physik vol. 24, part 1 , Springer, 1 933 (and Edwards, (943). 25 MASSEY, H. S. W. Theory oj Atomic Collisiolls, Handbuch der Physik vol. xxxvi (Atoms II), Springer, 1 956. 10 BLATT,
264
INDEX· Adjoint, 72-73, 95 Allowed transitions, 201 Angular momentum, 14, 25, se, also Spin addition of, 27, 128-130, 245-247 classically, 54 conservation of, 8 1 , 1 82 operators, 34, 54, 1 04, lOS, 229 commutation relations for, 79, 84, 89, 104, lOS, 130, 237-238, 239, 244-245 eigenfunctions and eigenvalues of, 5455, 67-ti8, 104, 105-108, 130 .total, 1 16, 1 2 1 Associated Legendre functions, 50-53 se, Matrix representation, Group representation Bessel functions, 166-168 Bohr magneton, 141 Born approximation, 34, 160, 1 75, 252 Boson, 127 Bra vector, 102
Basis,
Centre-of-mnss coordinate system, 35 Clebsch-Gordan coefficient, 120 Commutation relations, 79, 84, 86, 89, 104 Commutator, 72, 77 Commuting observables (or operators), 7778 complete set of, 80, 8 1 , 1 15-1 16 Compatibility of several observables, 7578, 82 Complete orthonormal set, 4, 1 0 Compton wave-length, 204 Constant of the motion, 69, 8 1 , 1 0 1 , 1 151 16, 126, 182, 185, 186 Coulomb scattering, 1 51-153 Cross-section, 144, 145, St, also Scattering, Born approximation Current-density vector, 3 1 , 35, 209 Delta function, 1 7-19, 1 45 Density of states, 42-43, 148 Dirac equation for free particle, 46 for particle in electro-magnetic field, 2 10-21 2 negative energy states, 2 1 2, 2 16 non-relativistic limit, 2 1 1-212, 2 1 3-215 plane-wave solutions, 48 relativistic invariance, 49 Eigenfunctions, 6, 12, 27, 32, 62-ti3 complete set ofsimultancous, 75-78, 1 00 completeness of, 12-13, 34, 62-ti3 degenerate, 13-14, 63 expansion in, 13, 1 7, 34, 62-ti3 interpretation of, 27, 55, 66-68 linearly independent, 13 orthogonality of, 9, 33-34, 40, 63, 100, 102, 238-239 •
Eigenvalue, 6, 12, 27, 32, 62-63 degenerate, 1 3-14, 100 interpretation of, 27, 55, 63, 66-68 problem, 6, 12, 27, 32 in matrix form, 97-100, 103, 239-240 reality of, 33, 63, 100, 102, 238 spectrum continuous, 4, 17, 62 discrete, 14, 32-33, 62 mixed, I6 Electro-magnetic transitions, 197-200 Electron magnetic moment, 26, 47 spin, 26, 47, 204 Exchange integral, 139 operators, 126, 184 Exclusion principle, 127 Expectation value, 63, 66-68, 7 1 , 8 1 , 1 15 Fermion, 127 Forbidden traruitions, 201 Four-vector, 220 Fourier integral, IS, 19, 20, 87 series, 7, 20 Function even and odd, 8, 39 length of, 9 magnitude of, 9 space, 10, 1 1 , 60, 76-77 complex, I I dimensionality of, 10 manifold of, 13 product, 1 1 3-1 15, 1 16-1 1 7, 183 subspace of, 1 3 Gauss's theorem, 262 Green's theorem, 262 Ground state of alpha particle, 129-130 deuteron, 201, 256 lHe, 130 helium atom, 57, 136, 234 hydrogen atom, 57, 233 Group, 1 78 Abelian, 1 79, 189, 201 , 255-256 axial rotation, 1 78-1 79, 189-190 inversion (or reflection), 1 79, 1 88 Lorentz, 2 1 8 permutation, 1 79, 1 89, 201 , 255 representation, 43, 1 87 basis for, 187 decomposition of, 187 equivalent, 187 irTeducible, 187, 202 product, 189 reducible, 187-188 reduction of, 1 87
The DWDbe.. ill heavy type refer 10 the IeCIlcma
265
INDEX Group-eonld. rotation, 40, 1 79, 189 transfonnations (or operators), of, 39, 178 invariants of, 41, 186 unitary, 180, 201 256 velocity, 30, 35, 23 0
Measurement, 65-70 complete (maximal), 80 one observable, of, 65-68, 70-71 several commuting observables, of, 19 several non-commuting observables, of, 20 state of system, of, 79-80 state of system after, 68-70
Hamiltonian function, 27, 59, 64 invariancc under in�ion, 56, 182, 185, 186, 1 93 pennutations, 125, 137, 1 77, 194 rotations, 105, 1 25, 1 77, 181, 182, 185, 186, 194 spherically symmetric, 47, 54, 68, 104, 105, 1 15-1 16, 125, 140, l ol l , 181, 182 Hamilton's equations, 59, 88, 234 Hankel funCtiOns, 166-168 Heisenberg, Ste also Uncertainty principle equations of motion, 101, 103, 240 picture or representation, 100-101 Hermite polynomials, 45-46 HenocUtian, 62-63, 72-73, 95 Hilbert apacc, 1 1, 60, 76-77
Non-commuting o£Cl'll tors, let! Operators Nonn, �, 41 5, 9, 12 Nonnalized, 2, 9 Nucleon, 129 Observable, 25-28, 61-63 Operator, 26-28, 6 1--63 commuting with the Hamiltonian, 80-81, 101, 1 15-1 16, 126 equations of motion of, set Heisenberg inverse, 74 unit, 73 Operators commutability of, 77-78, 100 complete set of commuting, 80 functions of, 18, 78 non-commuting, 82 Optical theorem, 1 72 Orthogonal, 3, 4, 9 Orthonormal, 3, 9
Identical particles, 28, 130, 137-140, 160161 , 247-248 Inner product, 2, 4, 9, 1 1 , 9 1 , 1 14 invariance under unitary transformations, 73 Intercombination lines, 198 Invariancc, Stl Hamiltonian function Invariants, Stl Group of transformations Inversion, 39, 56, 177, 182, 185, 2 1 7, 23 1 Ket vector, 102 Klein-Gordon equation, 203 Kronecker 8 symbol, 3
Laboratory coordinate system, 35 Laporte's rule, 198 Legendre polynomials, 50-51 Life-time, 86 Linear independence, 4, I I Lorentz transformation, 49
Magnetic moment, 47, 1 1 1-1 12 Manifold, 4, 13, 76-77, 79-80, 98, 100 decomposition of, 187 invariant, 186 irreducible, 187 reducible, 187, 188 reduction of, 1 87 Matrix, 92 diagonal, 94, 102 eigenvectors and eigenvalues of, 97-100, 102 multiplication, 9 1 , 93-94representation, 21, see also Group representation basis of, 90 change of basis of, 95-97 eigenvalue problem in, 97-100 of an operator, 92 of a vector, 9 1 transposed, 95 unit, 94Mean square deviation, 67-68, 82
Parity, 39-40, 45, 5 1 , 53, 56, 88, 182, 185, 193, 230-231 . Partial wave analysis, 38 Pauli matrices, su Spin matrices principle, set! Exclusion principle Permutation operator,ste Exchange operators Perturbation theory time-dependent, 37 time-independent, Chapter VII ( 1 3 1 -141) applications, 31 first-order degenerate, 30 first-order non-degenerate, 29 second-order non-degenerate, l ol l , 249250 Phase factor, 28, 60, 61, 108, 109, 120, 133, 243-244, 250 vclocity, 29 Phase-mift, 1 7 1 Planck's constant, 22, 23 Plane wave, 10, 23, 28, 29 Positron, 2 16 Probability current, 3 1 , 35 interpretation of quantum mechanics, 28-29, 65-68, 70-7 1 , 1 15 Pseudo-scalar, 221 Pseudo-vector, 182-183, 221, 222 Quantum number angular momentum, 55 good, 182, 198 magnetic, 55, 141 Radiative transitions, 197-200 Reduced mass, 1 43, 157, 232 Relativistic invariancc, 49
266