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=CpW. It can be easily verified that 6, is a distribution. Example 2. Any Radon measure p on Rn may be viewed as a distribution if we take by theorem 1.2. Hence 9 * T T = T and 9 9 * T = T for every T E9'.So fl is a linear automorphism of 9' and 9-l=S Take *. a finite number of elements pl,..., pmin 9 and a positive number E , and and put
For, the inequality
I <~ p , p > I 5 I l ~ l l - l(Bmh ~l which holds for p in gm, proves that p is continuous on 9". Example 3. A measurable function f on Rn is called locally summable iff is integrable with respect to the Lebesgue measure dm(x) on every compact set. Then f defines a distribution Tf by <(D,
S.I
Tf > =
f ( x ) y(x) dm(x),
because the measure p j defined by dp (x)=f(x)dm(x) is a Radon measure (Example 2). Since the mappingfi+Tf is an injection of the space of locally summable functions into g',f is identified with T,.
Definition 2. If T is a distribution on R" and a ... then the linear form i axl i ax,, p+(- 1)'"'
(- -)"'
D m= i
(IL)",
152
FOURIER TRANSFORM AND UNITARY REPRESENTA~ONS OF R"
Example 4.
<9,Dm6,> =(- 1)Irn1(Drn(p)(a). Proposition 5.1. Let 9 = 9 ( R n ) be the space of rapidly decreasing functions (cf. Definition 1 in $1). Then we have: 1) The injection i : d + y is continuous. 2) d is dense in 9'. 3) If T is a continuous linear form on .9' (i.e. T E.Si"), then TwToi is an injection of 9'into g'. = g ( B , ) , then Proof. 1) If p belongs to drn PL,N(V)=SUP I(1-k lXI')N(DXp) s ( 1 +m')NIIDkv!lfor any k E N" and N E N. So the injection i, : gm+9 is continuous for every m. Hence i is continuous by Proposition 4.2. 2) Choose a function (0 in g such that $(x) = 1 if 1x1 5 1. For any function f i n 9, put &(x) =f(x)$(rx) for r > 0 and x E R" Thenf; belongs to 9.Now we prove that fi converges to f in 9 when r-+ +0. If P is a polynomial and m E N" is a multi-index, then by Leibnitz' law of differentiation we see that (5.1)
P(x)Dm( f - f i ) ( x ) = P ( x )
,C8(Dm-kf)(x)r'"Dk(l-$ (rx)).
esm
1 By the choice of (0, Dm(l-$(rx)) =0 if 1x1 5 - for every rn E N".Sincef r belongs to 9, P(x) (Dm-Lf)( x ) is bounded on R" and the right hand side of (5.1) converges to 0 uniformly on R" when r++O. Hence we have proved that fr converges to f in 9. 3) By l), Toi is a continuous linear form on 9.Therefore the mapping I: THToi is a linear mapping of 9' into 9'.I is injective by 2).
Definition 3. If T Ey',then the distribution Toi defined in Proposition 5.1 is called a tempered distribution. Since I : T w Toi is an injection of 9'' into g',we identify T E9' with Toi a 9'. Example 5 . The Dirac measure 6, and its derivatives D6, are tempered distributions. Example 6. A positive Radon measure on R" is called slowly increasing if
TEMPERED DISTRIBUTIONS AND T H ~ R FOURIER TRANSFORMS
153
for some N E N . A slowly increasing measure p is a tempered distribution. In fact, we see that
I <(D,
lu > IS
Po, N ( d J R n ( + l Ixl2>-"4 (4.
Definition 4. The Fourier transform f ' = T T of a tempered distribution T is the tempered distribution defined by (5.2) cp, f'> = for all p E 9. Since the Fourier transform N : C ~ H is Q a topological isomorphism of 9 onto 9 '(Theorem 1.2), the linear form f defined by (5.2) is continuous and is actually a tempered distribution. Similarly the conjugate (or inverse) Fourier transform N * T of T is defined by <(D, N
* T > = <**ID,
T> for all p E 9.
Example 7. Iff E L', the space of summable functions, then we have f,=T;. Namely, the Fourier transform off regarded as a distribution (Ex. 3) is equal to the Fourier transform of the functionf. In fact, by Fubini's theorem we get
Example 8. Let 6=a0. Then 6 = 1 and I = S . In fact,
= <@, 6>
and <$D,
I > = <@,1>
=@(O)=
s
s
y(x)dm(x)= c v , I >
= @(x)dm(x)=(O(O)=
a>.
Theorem 5.1. The Fourier transform N is a topological automorphism of 9 '' equipped with the weak*-topology (Appendix F). The inverse of fl is the conjugate Fourier transform fl*. Proof. 5 and N*are linear mappings of 9' into 9".Moreover for any T E9" and p E 9, we have <(a,
and
5 X * T > = < X * 5 p , T> =
154
FOURIER TRANSFORM AND UNITARY REPRESENTATIONS OF
R"
T * X T > = < T T * p , T> =
.
&I, ..., p m : E ) = { T E ~ I
-
pm: e)) = V ( T * V ~..., , F * V m : 81, and 5 is an automorphism of 9, both 9and X - l = S *are cononto itself. q.e.d* tinuous and hence homeomorphisms of 9' T(v(~1y
y
CHAFTER IV
The Euclidean motion group
In this chapter, we study harmonic analysis on the motion group M(2) of the Euclidean plane Ra. The group M(2) is the simplest example of a non-commutative, non-compact Lie group. First we construct a series of irreducible unitary representations Ua parametrized by a positive real number u>O. A function on M(2) can be expanded with respect to the set of representations { U“}. More precisely, if we introduce the Fourier transformf of a functionf i n L1(M(2))by means of the formula {(a)=/
arm
f(x)U,-P dg,
0-0,
then the analogues of theorems of Schwartz (Ch. 111. Th. 1.2), Plancherel (Ch. 111. Th. 2.1), and Paley-Wiener (Ch. 111. Th. 4.1) are valid for the “Fourier transform” on M(2). For example, iff is a “rapidly decreasing” function on M(2) (for the precise definition, see 43), the inversion formula Ng)= p f ( u ) U , a ) a h and Parseval equality
I f(g)12&=/;-I1
P(U)lls2U~
hold. These formulas are natural extensions of the corresponding formulas for a compact, non-commutative group (Ch. 1I) and for the non-compact, commutative group R” (Ch. 111).
$1. Construction of irreducible representations The Euclidean plane R3 is identified with the complex plane C by the mapping ( ; ) n x + y i .
The Euclidean inner product
given by 155
(2,
w)=xu+yv is
156
EUCLIDEAN MOTION GROUP
(z, w) = Re(z@)
for z = x + y i and w=u+vi. The mapping of C into itself which keeps invariant the distance d(z, w) = Iz - wI between any two points z and w in C is called an isometry of Rz = C . The group Z(R2) of all isometries of C is generated by three kinds of transformations: 1) translations t(z) : W H W + Z , 2) rotations r(a) : wHeiuw, and 3) the reflection s : wnw. The isometry group Z(Ra)is a 3-dimensional Lie group with two connected components. The connected component G containing the identity 1 is generated by the set of all translations and rotations. The group G is the motion group of R 2 = C . In matrix notation, the motion group G can be given in the following way.
Definition 1. The subgroup G of GL(2, C ) consisting of the matrices (1.1)
h(Z,a)=(c
f>
for any a € R
and any Z E C
is called the motion group of the Euclidean plane and is denoted by M(2). Since
h(0, a) represents the rotation r(a) and h(z, 0 ) represents the translation t(4.
Proposition 1.1. Put h(0, a)=r(a) and h(z, O)=t(z). Then we have the following relations 1) r(a)r(B)=r(a+p),t(z)t(w)=t(z+w), 2) r(a)-l=r(-a), t(z)-'=t(-z), 3) h(z, a )= t(z)r(a>, 4) r(a)t(z)r(a)-l=t(r(a)z), 5) h(z, a)-'=h(-r(-a)z, -a), 6 ) h(z, a)h(w, B)=h(z+r(a)w, a+@. Proof. These relations are easily proved by direct calculation of products of matrices. For example, 6) is proved by the relation
1) and 3) are particular cases of 6). 2) follows from 1). As transformations on C, these elements satisfy the relations
CONSTRUCTION OF IRREDUCIBLE REPRESENTATIONS
157
+
r(a)t(z)r(a)-lw=r(a)(r(a)-'w+z ) = w r(a)z=t(r(a)z)w for any w E C. So we have 4). 5 ) is proved by using 2), 3) and 4).
q.e.d.
Remark. Proposition 1.1, 5 ) and 6) show that G=M(2) is actually a subgroup of GL(2, C ) . Proposition 1.2. Let T = {t(z)JzE C) and K = {r(a)laE R} Then 1) T and K are subgroups of G= M(2) and we have T=Ra, KrU(1)zT. 2) G=TK, T n K = { I ) . 3) T is a normal subgroup of G. 4) G is the semidirect product of T and K. G is homeomorphic to each of the product spaces T x K and Rax T. Proof. Proposition 1.2 is a direct consequence of Proposition 1.1.
.
To construct the irreducible unitary representations of G= M(2), we use the method of induced representations. This technique was discovered and effectively used by Frobenius for finite groups. This is a method of constructing a representation of a group from a representation of some subgroup of it. The theory of induced unitary representations of locally compact groups was initiated by G. W. Mackey [3]. We shall give a brief account of induced representations of topological groups in the last part of this section. Here we construct directly the irreducible unitary representations in the form most convenient for later use. The representation to be constructed is induced by an irreducible unitary representation za :t(z)I+ efCXsa) of the subgroup T. This fact will be proved later. Since K G U(1)z T =R/2xZ, (1 -2) dr =da/2n is the normalized Haar measure of the compact group K. In this section, the Hilbart space La(K)=L3([0,2x],da/2x) is denoted by H.
Theorem 1.1. Let a be any element in Ra. Then there exists a unitary representationU" of G=M(2) on H = La(K)defined by (U,"F)(s) =ef(*.'"'F(r(a)-'s), (1.3) where g=f(z)r(a)=f(z)rand F E H. Proof. Since
158 ( 1.4)
EUCLIDEAN MOTION GROUP
(Ug"F,UguF')=
F(r-ls)F'(r-'s)ds
SR S K
=
~ ( s ) ~ m=d(F,s F')
for any F, F' E H , UgUis a unitary operator for every g E G. If gt = firi, fr=t(zt)ET, r t E K ( i = l , 2), then glgs=t(zl +r1z2)r1ra. Thus we have (uVl92"F)(s) =ei(si+riza, s@)F(ra-lrl-ls) -eKX1, IU),+a. ~ l - l ~ u ) F ( r ~ - l ( r ~ - l ~ ) )
UgaUF) (r1-ls) = [uol'(ug,uF) I($> and =ei(zls'u)(
Uglgaa= UglaUgza* It remains to prove that the mapping U" :g n Uguis strongly continuous. It is sufficient to show that for any I; in H and any E>O, there exists a neighborhood N of 1 in G such that
(1.5)
(1.6) IIU,"F-F\I<E for any g E N . If F=O, (1.6) is trivial. We assume that FzO. There exists a continuous function p E C ( K ) satisfying
IIF-v11
IILrp-pll..<e/6
for any r E V .
Similarly since I(x, sa)l d 1x1 )a1 for any s E K (1.9) there exists a neighborhood W of 0 in Ra such that
(1.10) let(a,ra)- 11<~/61[p11for every x E Wand every s E K. Let N = t ( w ) x V. Then N is a neighborhood of 1 in G. If g = t(z)rE N , then we have (1.11) 11Ug"p- yII.. =sup ler(*. '")p(r-ls)-&)I 5 Iletcx*au)(p(r-ls) -p(s))llm Il(e*(". m - l)p(s)ll, d IILp - pll- + Ile'('. 1 ll~llpll<€16 el6 =€13
+
-
+
159
CONSTRUCTION OF IRREDUCIBLE REPRESENTATIONS
by (1.9) and (1.10). The inequalities (1.7) and (1.11) together with the relations \IUgaFII= llFll and llplls Ilpll.. prove that
IIUgaF-FII IIIU9"F- Up"pll+ IIuaa(4-$4f Ilp-FII <&/3+&/3+&/3=&.
Theorem 1.2. Then we have
q.e.d.
Let R, (r E K) be the right regular representation of K .
R, Uga Rr-'= Ugra for any r E K,g E G and a E Ra . In particular if la1 = Ibl, then U a g Ub. Proof. For any roE K, g =f (z)rE G and F E L2(K),we have (1.12)
0
0
(RroUgaRro-'F)(s) =(UgaRr0-'F) (sro)=et(** TO - l F ) (r-lsr0) =&(Zs rroa)F(r-ls)=(Ug'oaF)(s1.
If la1 =lbl, then there exists a rotation r E K such that b=ra. Hence we get Ugb=R,UaaRr-l for any g E G. Since R, is a unitary operator on L2(K),we have proved that U a is equivalent to U'. q.e.d. By Theorem 1.2, it is sufficient to study the representations U a for aLO.
Proposition 1.3. If we identify L2(K)with L2([0,24, da/2a), the unitary operator Uga(ar0) for g = f(pe(p)r(a)is represented by (U,aF) (0) =etapcos(p-e)F(e -a) . (1.13) Proof. Since (z, a) = Re(zri), we have (z, r(0)a)= Re(apet(p-8))=apcos(~ - 0) . Hence (1.3) can be rewritten in the form given by (1.13). Proposition 1.4. 1) Let F be an element in H=LZ(K).Then UTaF=F for every r E K if and only if F=co for some constant CO. 2) Let pa(g)=(Ugal, 1) for U E R and gEG. Then we have p a ( g ) = Jo(ap), for g = t(pe")r(a), where Jo is the Bessel function of order 0. Proof. 1) Since Ura=L, for each r E K, we get
1
urcm>a(
ne2
Cnxn)
(0) =
1c n e - ~ n ~ x n (.~ ) nci
Hence F= CC,,~,, E H satisfies UraF= F for every r e K if and only if F= cox0 =cO.
160
EUCLIDEAN MOTION GROUP
2) By (1.13), we get
=L/ax etap eosede
277 0 =Jo(ap). The last equality is the definition of the Bessel function Jo. (Bessel's integral formula). Theorem 1.3. Let a, b B R1.Then Ua is equivalent to U bif and only if la1 = lbl. Proof. By Theorem 1.2, it is sufficient to prove that if U a s U e for a, b z O , then a=b. If U az Ub, there exists a unitary operator T on H such that Tuga= /. UgBTfor every g E G. Therefore UTbT1= TUral = T1 for any r E K, hence T1= c by Proposition 1.4. Since T is unitary, IcI = 1. So we have pa(g) = (Ug'l,
1)=(Tuga 1, T1) =(UgbT1,T1)=lcla(Ugbl,1) = q ~ b ( g ) for any g E G.
Thus we have (1.14) Since
Jo(ap)=Jo(bp) for every
oER
.
we have (1.15) Let fa(x)=Jo(ax).Then we have
.
(1.16) fa"(0)=aaJo"(0) Therefore (1.14) implies that aaJo"(0)=baJo"(0),hence, aa=bs by (1.15). So we have proved that if U a sU band aLO, b z O , then a=b. q.e.d.
Theorem 1.4. If la1 >0, the unitary representation U a is irreducible. Proof. We can assume that a>O by Theorem 1.3. It is sufEcient to prove that if a projection operator P on H=L'(K) satisfies
CONSTRUCTION OF IRREDUCIBLE REPRESENTATIONS
161
Puga = UgaP for any g E G , then either P=O or P = 1 (Ch. I. Proposition 2.3). For any integer n, put Xn(e)= eine and Px,=f n . Then we have Sn(8-a) = (Ur(m)aPXn) (8) = (PUr(a)aXn)(8) -P(efn(e-u)) =e-tnufn(e) for any a
.
Hence we have fn(a) =cnetnu
i.e. (1.17)
for almost all a ,
PI,,=cnzn for every n E Z .
(Ch. I. (3.15)). If x E R, then
P(etascoseetne) =(PUt(.)'Xn)(B)=(Llt(=)"PXn)(8) =Cn(Ut(rlaXn)
(0) = Cneiaf
coseeins
.
Hence
Since
by Taylor's theorem, we have
(1.20) =cniacosBetne,so that (1.18)and (1.20)prove that P(iu cos8etn@) P(cos8 ein8)=cn cose efne; (1.21) considering t(xi) instead of t(x), we get similarly P(sin8 erne)=cn sin&P . (1.22) (1.21) and (1.22)prove (1.23) Pxn+l =CnXn+l for every n E Z (1.17) and (1.23) prove that Cn+l=Cn and hence Cn =CO for every n E 2. Since (x,,),,,~ is an orthonormal base of H, we have
162
EUCLIDEAN MOTION GROUP
P=col.
(1.24)
Since P a=P,coa= co and co= O or 1. We have proved that P=O or 1.
q.e.d.
Definition 2. The set of representations P= {U"la>O} is called the principal series of irreducible unitary representations of M(2).
Induced representations There exists a canonical method of constructing a representation T of a group G from a representation r of a subgroup H of G. The representation T is said to be induced by T. In its essence, the induced representation T is the natural representation of G on the space r ( E ) of sections of the homogeneous vector bundle E associated with T. Let V be the representation space of r. Then E is constructed as follows. An equivalence relation R is defined on the product space G x V defining (g, x)R(g', x') if and only if there exists an element h in H such that g'=gh and x'=r(h)-'x. Let E= (G x V ) / R be the quotient space of G x V by R . If H is a closed subgroup of a Lie group G and r is a continuous representation of H , then E is a vector bundle over the homogeneous space G/H associated with the principal bundle G(G/H, H ) . But here we are giving the description of the induced representation in an abstract setting and we make no such additional assumptions. Let ( g , x ) be the equivalence class containing (g, x) E G x V under the relation R and p : (g, x) W g H be the canonical projection of E onto G/H. G acts on E from the left by the rule
mo,
g(g0, x>= x> * A section f of E is, by definition, a mapping f:G/H+E satisfying paf = Ido,x. Let r ( E ) be the set of all sections of E. Then r ( E ) has the structure of a vector space. If fi,& E r ( E ) and fi(gH) = ( g , xi> (i= 1,2), then fl+fa and ufl (a is a scalar) are defined by
(fi+fa)
= ( g , xi
+xa>,
(ah)( g H )=
G acts on r ( E ) canonically from the left and r ( E ) is a G-module in virtue of the representation T of G on r ( E ) defined by ( T d )(goH)=g *f(g-lgoH). The representation T of G is said to be induced by the representation t of H. The induced representation can be realized in another way. Let W be the space of all mappings F: G-, V satisfying F(gh)=~(h)-lF(g) for any g E G and any h E H . Then a representation S of G on W is defined by
setting
CONSTRUCTION OF IRREDUCIBLE REPRESENTATIONS
163
-
( S l a (go)=F(g-lg0) The representation S is equivalent to the induced representation T. Let F E W and r be the mapping of G into G x V defined by 7 ( g )=( g , F(g)). Then r(gh)= (gh, r(h)-lF(g)) is equivalent to r(g) for any g E G and h E H. Hence we get a mapping f : G/H+E by passing to the quotient:
G - G xI V
4-
Ip
G/H
f
E
-
f k H ) =( g , F O ) The mapping 0 : F H f is a linear isomorphism of W onto r ( E ) . In fact it is clear that 0 is injective. Let f be an element in r ( E ) and put f ( g H ) = ( g , x ) . Then an element F in W is defined by putting F ( g ) = x and it satisfies 0 ( F ) = f . Hence 0 is surjective. The linear isomorphism 0 is an intertwining mapping between T and S, i.e. 0 satisfies O O S , = T , O O forevery
gEG.
In fact, we see that "0 SJFI(goH)= (go9 (&F) (go)) =g(g-lgo, Fk-'go)> =&W) 1(g-'goH) = U l 7 @IF1 (gem. O
O
Detailed studies of the induced representations have been made under the assumption of additional conditions on G , H and r by taking a suitable subspace ro of r ( E ) . For the case where G is a finite group, see, e.g., Curtis-Reiner [11. For the case where G is a compact group, see Weil [l]. For the case where G is a complex Lie group and rois the space of holomorphic sections, see Bott [l] and Kostant [2]. For the case where G is a Lie group, see Bruhat [l]. For the case where G is a semisimple Lie group and rois the space of square-integrable sections, see Okamoto-Ozeki [11, Narashimann-Okamot0 [l], and Hotta [l]. Here we give the definition of unitary induced representation of a locally compact group due to G. W. Mackey [3]. Definition 3. Let G be a locally compact group, H a closed subgroup of G and assume that GIH is o-compact and that there exists a positive Ginvariant Radon measure AL, # O on G/H. Let r be a unitary representation of H on a separable Hilbert space V
164
EUCLIDEAN MOTION GROUP
and let H be the space of all functionsf on G with values in V satisfying the following three conditions: 1) gt+(f(g), v) is measurable for every v E V, 2) f(gh)=r(h)-'f(g) for every g E G and h E H,
where g=gH. Then W is a Hilbert space with the inner product
(fi,fa)= ~ G , H ( x ( g ) . $ d ( g ) ) d P ( 9 ) *
A unitary representation T of G on H is defined by setting (1.25) ( T d )(go) =f(g-'go). The unitary representation defined by the last equality is called the representation induced by r and denoted by T=Ind t. HtQ
Proposition 1.5. The principal series representation U aof the motion group M(2) is equivalent to the representation Ta induced by the irreducible unitary representation
x a : t(z)i+ef(s.a) of the translation subgroup T. Proof: Define the linear mapping A of La(K)=H(Ua)into H = H(Ta) by setting (AF)(t(z)r)=xa(t(-r-'z))F(r) for F E L s ( K ) .
Since (AF)(t(z)r t(zo))=(AF) (t(z+rzo)r) =xa(t( -r-'z-zo))F(r)= Xa(Zo)-'(AF)(t(z)r) A F actually belongs to H. Moreover, since dr is the G-invariant measure on K = G / T , we see that
Thus A is an isometry of La(K)into H. A is surjectivebecause A C ( K ) is dense in H. A is an intertwining operator between U aand T a ,i.e. A satisfies A 0 U g a = T g a o A forany g e G . In fact, if g = t(w)s and s E K, then
CLASSIFICATIONS OF IRREDUCIBLE UNITARY REPRESENTATIONS
165
In the above definition of unitary induced representation, we assume that-there exists a positive G-invariant measure p # O on G/H. However no such a measure p exists in many important cases. In general case, a quasi-invariant measure p plays the same role as the invariant measure in the above discussion. A positive Radon measure p on G / H is called quasi-invariant if the measure gp ( ( g p ) (A) = p(g-lA)) is absolutely continuous with respect to p for any g E G. It can be proved that there always exists a quasi-invariant measure # 0 on G/H where G is a locally compact group and H is a closed subgroup (cf. Bourbaki [3] Ch. VII. $1. no 9). The measure gp has the density (Radon-Nykodimderivative) d(gp)/dp with respect to p. Using the quasi-invariant measure p, we can define the induced representation T o n the space H in Definition 3 by setting
(Tuf)ko)=(dp(g-'b)/~p(80) )'f(g-lgo) .
52. Classification of irreducible unitary representations There exist irreducible unitary representations other than the principa) series representations constructed in $1. Let p :G H K be the projection of G= T K onto K : p(t(z)r)=r. Then p is a homomorphism of G onto K whose kernel is T. Since G I T z K , any irreducible unitary representation x of K defines an irreducible unitary representation x op of G. We know that 12- ( ~ ~ : r ( c u ) ~ e ' " - I n ~ ~ ) is the set of all irreducible unitary representations of K (more precisely l? should be called a complete set of representatives of the set of classes of irreducible unitary representations).
Theorem 2.1. (It0 [I]-Mackey [3]). Any irreducible unitary representation U of the motion group G=M(2) is equivalent to one of the elements in the set
e=(U"la>O) u (XnoplnE21. No two elements in
6 are equivalent to each other.
166
EUCLIDEAN MOTION GROUP
Proof. Since Ua is infinite-dimensional and zn op is one-dimensional, Ua is not equivalent to zn op. Hence the last part of Theorem 2.1 is clear
from Theorem 1.3 and Ch. I, Theorem 4.2. Let U be an irreducible unitary representation of G=M(2) on a Hilbert space H and put Urtr)=V, and
Urta)=W,
.
Then V is a unitary representation of R a g T.Hence by Stone's theorem (Ch. I11 Theorem 3.2), there exists a unique spectral measure E on the family B of Borel sets in R1such that
For any Borel set A E: b and any x E Ra, we have (2.2) V,E(A) =E(A)v, (cf. Ch. 111. Theorem 3.2). Since r(a)t(x)r(a)-l=t(r(a)x), we get
s
e"". W (W,E(y)W,-I) = W, V , W,-'
= Vr(a)s = = /e'(*.
s
e"".r(a,-'ff)&(y)
u)dE(r(a)y).
Hence for any Borel set A E 23 and a E R,we have WaE(A)Wm-'=E(r(a)A) (2.3) by the uniqueness of E. In particular, we see that (2.4) if r ( a ) A = A , then W,E(A)=E(A)W,. By (2.2), (2.4) and the irreducibility of U, we see that (2.5) if r(a)A= A for every a E R, then E(A)=O or 1. In particular an open disc Br= { X E R21 1x1 < r } of radius r>O is invariant under every rotation, and we get (2.6) E(B,)=O or 1 for any rZO . Since u Bn=Ra and E(Ra)= 1, E(B,)= 1 for sufficiently large c by the n
strong continuity of E(Ch. I11 Proposition 3.9.). Put a = sup [r IE(B,) =01 . Then we have O$a< + a. Since u Ba-l,n=Ba, we have n
CLASSIFICATIONSOF IRREDUCIBLE UNITARY REPRESENTATIONS
(2.7)
167
E(B,)=O.
Put Dr= { x e Ral I x l s r } . Then E(Dr)=l if r > a . Since n Da+l,n=D,, we have n
(2.8) E(D,) = 1 by Ch. 111, Proposition 3.9. (2.7) and (2.8) show that the spectral measure E is concentrated on the circle S,= { x e RaI Ixl=a). There exist two possibilities: a=O and a>O. We examine the two cases separately.
Case I, a =0. In this case, we get ”
for every X E R a . Hence the kernel of U contains the subgroup T and U can be regarded as an irreducible unitary representation of K. Therefore U is equivalent to xn o p for some n E Z by Ch. I. Theorem 4.2. Case 11, a>O Since W is a unitary representation of the compact group T E K, W is a direct sum of irreducible unitary representations (Ch. I. Theorem 3.1). In particular there exists an integer n and the representation space H of W contains a unit vector u satisfying (2.9) Wau= einau for any a E R . Let 9 be the mapping r(a)nae*”.Then 9 is a homeomorphism of the group K onto the circle S,. Put F(B)=E($(B)) for B E b(K), where b(K) is the set of all Bore1 sets in K. Then F is a spectral measure on B(K). (2.1) can be re-written as
Let p be the measure on b(K) defined by p(B)= IIF(B)ull’ for B E b(K). Then by Ch. I11 Proposition 3.12, for each function f E La(K,p ) , there exists a linear operator
defined on the space
168
EUCLIDEAN MOTION GROUP
The mapping CJ : f ~ H ( fis) an isometry of La(K,p ) onto a subspace M = M ( u ) of H {Ch. 111. Proposition 3.12). M is isometric to L'(K, p) and is complete, hence is closed. Now we prove that the closed subspace M is invariant under the representation U.By (2.3) and (2.9), we see that ( ~ u ~ ( f )v)u=,r>(n)dA(waF(l)u, v) =
J)(~)Mw +a) ~ . u v) ,
=/ ; e t n q f ( l
-a)d(F(R)u, V) .
Putting
f=W=etm-f(A-a) , we get (2.11) W , H ( f ) u = H ( f " ) u for any a E R and f E La(K,p ) . We recall here that the integer n in (2.11) depends on the choice of u in (2.9). (2.10)
If we put ~ ~ ( r ) = e ~ ( * .then ' " ) ,we may write V,=H(x.). Hence if we put g,(r) = ~.(r)f(r) = e((".ra)f(r then by Ch. 111, Proposition 3.12, 7), we get 1
9
.
V,H(f)u=H(g,)u for any z E C and f E L'(K, p ) (2.12) (2.11) and (2.12) prove that M = { H ( f ) u l f L2(K, ~ p)) is invariant under U. Since U is irreducible, M must be 0 or H . Since M contains u= H(l)u+O, M must be the whole space H. Put e(l)=e6n2;then since emn(;c)= efnaeinCa-a' =&), (2.1 1) shows that uo=H(e)u satisfies (2.13) Wuuo=uo for all a E R . Hence we can take uo instead of u in (2.9). Starting from uo, the above argument shows that the isometry CJ is the desired intertwining operator between U and U".In fact, the measure po(B)=IIF(B)uoll' is invariant under the translation r ~ r o rin the group K by (2.3), (2.13) and satisfies p o ( K ) = 1. Hence dpo(l)=dR/2n. Furthermore, the isometry CJ : f ~ H ( fis) an isometry of L'(K) =La([O,2x1, d2/2n) onto M(u0)=H. Moreover, the function fqo(l) in (2.10) for uo is given by fa0(A) =f(l -a) =(U,c.)"f)(A). Hence (2.11) and (2.12) can be re-written as KO-1
urCu, WI (8) = f ( e ) = (urcU)af) (0) a
[(CJ-l o
Utca)o @)f](0) =g.(8) = =
e'("9
r(s)a)
(utca)af) (0) .
f(e)
d
FOURIER TRANSFORMS OF RAPIDLY DECREASINGFUNCTIONS
So we have proved that O-l.UvaO=Uga forevery g E G , and U is equivalent to Ua.
169
q.e.d.
$3. Fourier transforms of rapidly decreasing functions In the following three sections, we discuss the Fourier transform on the group M(2) which is always denoted by G. In this section, we introduce the space Y(G) of rapidly decreasing functions on G=M(2). It turns out that any rapidly decreasing functionf has an expansion with respect to the principal series representations Ua(a> 0). It is a remarkable fact that the one-dimensional irreducible representations x,, ap of G play no part in the expansion. It is also noteworthy that there exists a close relation between the Fourier transform on G=M(2) and the ordinary Fourier transform on R'. For a function f on G =M(2) we write f ( g ) = f ka )= f kr )
if g = t(z)r(a)= t(z)r. Proposition 3.1. Let g = t(z)r(a)= t(x+yi)r(a). Then dg =dzdr =dxdyda is a left invariant Haar measure on G =M(2). It is also right invariant and G is a unimodular group. Proof. Since t(zo)rot(z)r= t(zo+r0z)rOr and the Lebesgue measure dz on Ra is invariant under the rigid motion zHroz+zo,and since dr is the Haar measure of the group K, we have d(gog)=dg. So dg is a left invariant Haar measure on G =M(2). Similarly we have d(ggo)=dgo and G is unimodular. q.e.d. Definition 1. The measure on G given by dg=dzda =dm(z)dr (2d' is called the normalized Haar measure on G. In the following dg always denotes the normalized Haar measure given by (3.1). Definition 2. The Fourier transformf of a functionf E L 1 ( Q is a function on R*+=(O, + a) with values in the Banach space B(L'(K)) of aU bounded linear operators on L1(K)defined by
170
EUCLIDEAN MOTION GROUP
{(a) =
(3.2)
1
f(g)Ua,-,dg for a> 0 ,
Q
where U ais one of the principal series unitary representations of G =M(2) constructed in $1. Proposition 3.2.
Iff and h are integrable functions on G, then we have
1) IIf(~)lldllflllfor any a>O,
2)
and
(f*W=v,
3) (I*)* (a)=tf(a))*, where f * ( g ) = f j . Proof. 1) For any vector u E H, we have
Ilf(a)ull.~ ff If(s)l II~"0-144?
5 llflll llull * 2) By Fubini's theorem, we have
= h(a)f(a). 3) For any two vectors u, v E H,
Definition 3. A complex-valued C"-function f on G = M ( 2 ) is called rapidly decreasing if for any N E N and m E N 3 we have
(3.3)
where
m,m(f)=
SUP I(l+lZl')"(~"f)(Z,
arR, a c C
all < +
9
FOURIER TRANSFORMS OF RAPIDLY DECREASING FUNCTIONS
171
The vector space of all rapidly decreasing functions on G is denoted by
9=.y(G). 9 is a Frdchet space in the topology given by the family of seminorsms { p N , , I N ~N,m E N 3 }
.
Proposition 3.3. 9(G)cLp(G) for any p 2 1. Proof. Since f E 9 ( G ) satisfies
Ifk a>lIpiv.o(f)(1 + I z l Y for any N E N, Proposition 3.3 is a direct consequence of Proposition 3.1. q.e.d. Proposition 3.4.
Iffis a rapidly decreasing function on G,then we have
(3.4)
for any u>O and F E La(K), where
.
(3.5)
f ( z , rs-')e-*(".ra)dm(z)
Proof. If F and F' belong to La(K)and g = t(z)r, then g-l= r l t ( -z ) = t( -r-lz)r-l and n
n
,
.
n
n
Since F' is arbitrary element in La(K),we have proved that (3.4) is valid for almost every s E K . In the above proof of Proposition 3.4, we actually prove the following corollary.
COROLLARY 1 to Proposition 3.4. If YE Ll(G), then (3.4) is vaIid for almost all s E K. Proposition 3.4 shows that i f f € g ( G ) , thenf(a) is an integral operator on La(K)whose kernel k, is given by (3.5). COROLLARY 2 to Proposition 3.4. We denote the ordinary Fourier transform off(z, r ) , regarded as a function of z E Ra, by f ( f , r ) :
172
EUCLIDEAN MOTION GROUP
(3.6) Then the kernel k&; s, r ) is given by (3.7)
kf(a;s, r ) =f(ra7rs-l) .
Definition 4. A bounded linear operator A on a separable Hilbert space H is said to be of truce cZms if for any orthonormal basis ( p n ) n rof ~ H, the series
-
(3.8)
C
(On)
n-0
converges to a finite sum which is independent of the choice of (lon). The sum of (3.8) is called the truce of A and is denoted by TrA. If A is of trace class, the series (3.8) converges absolutely, because the sum is invariant with respect to any change of ordering among the pn's.
LEMMA1. Let H be a separable Hilbert space. If a bounded linear operator A on H satisfies (3.9)
for a fixed orthonormal base then A is of trace class. Moreover, if U and V are two bounded operators on H, then UAV, AVU and VUA are of trace class and have the same trace. Proof. Let urnn=(A~rn,pn), urnn=(Uprn, pn)7 and Vrnn=(Vprn, pn)Then we have
Hence we see that (3.10)
UA Vprn =
~(rnn&kvkl(bL n. k. 1
The Schwarz inequality in 1 9 proves that
-
FOURIER TRANSFORMS OF RAPIDLY DECREASING FUNCTIONS
by the assumption (3.9). Hence the series C
&nankVLm
173
converges abso-
m.n.k
lutely and we can change the order of terms without affecting the sum. So we have by the Parseval equality
Let (+,,),,.N be another orthonormal basis of H. Then the linear operator W on N defined by Wp, =$,, is a unitary operator. By (3.12) we have
Hence UAV is of trace class. In particular, putting U = V = 1, we see that A is of trace class. Similarly A VU and VUA are of trace class. (3.12) shows that Tr(UAV)=Tr(AVU)=Tr(VUA). LEMMA 2. If k(0, p) is a C2-functionon T', then the Fourier series m
(3.13)
C
um,nei(m8+n+
m.n---
converges absolutely and uniformly. Proof. Let
of k
174
EUCLIDEAN MOTION GROUP
Then the Fourier coefficient's bm,, of h satisfy bm,n =(Ak,e(m,n)) = (k, Ae(m,n)) = -(ma+n3)am,,.
Since h =Ak E C ( T a )c La(T),Bessel's inequality shows that
-
1 Ibm, s llhllsa< + n12
m. n---
Hence by Lemma 1 in Ch. 11, $8 we have
q.e.d. Proposition 3.5. If k(e, v) is a Ca-functionon K a=K x K s T a, then the integral operator L on La(K)defined by
satisfies the assumption of Lemma 1 for an orthonormal basis (x,,)~.z. Hence L is of trace class and has the trace
Proof. Let Xn(B)=eine.Then ( p J n r zis an orthonormal base of La(K). Lemma 2 proves that the Fourier series (3.13) of k converges absolutely and uniformly. Since
-am,
-n
it follows that
C
I(Lxm, xn)I < + 00, i.e.9
m ,n=--
L satisfies the assumption of Lemma 1 for (&.Z. Hence Lemma 1 proves that L is of trace class. Since the series k(B,O)=
C m . n=--
am,
FOURIER TRANSFORMS OF RAPIDLY DECREASING FUNCTIONS
175
converges uniformly on T,we can integrate it term by term and get
=Tr L by (3.14). Theorem 3.1. (Inversion formula) Any function f in p ( G ) may be recovered from its Fourier transform f,by the formula f ( g ) = r m T r (Ugaf(a))adu.
(3.15)
0
In particular, Uguf(a)andf(a) are of trace class. Proof. Since f ( u ) is an integral operator with C"-kernel (Proposition 3.4), it satisfies the assumption of Lemma 1 by Proposition 3.5. Hence Ugaf(u)and f ( a ) are of trace class. Let g=t(z)u, u E K. Then Ugaf(a) is an integral operator with kernel m f ,#(a;s, r ) =e"Z8 aa)f(ru, rs-1 u ) . In fact, we have (u,~~(u)F) (s) =e"'".a a ) ( f ( u ) ~ (u-1s) )
=J
e*('.Ja)f(ru,rs-1u)~(r)dr
by Proposition 3.4 and Corollary 2 to it. Hence by Proposition 3.5, Tr(u.mf(a))=J
X
mf.g(f.2;Y r r)dr
=j-ne".'"'f(ra, u)dr . If r is fixed, then the functionf, :zl-.f(z, r ) is a rapidly decreasing function on Ra. Since
f ( u , r )=
j-
f ( z , r)e-f(z+)dm(z)
Ra
is the Fourier transform of A E 9 ( R a ) on Ra, the inversion formula for
f7 E 9 ( R s )gives
176
EUCLIDEAN MOTION GROUP
=fm
Proposition 3.6. Iff and h belong to 9 ( G ) ,thenf * h and f * (g) belong to 9 ( G ) . Proof. Since(r(z)r)-l=t(-r-lz)r-l,f*(z,a)=f(-r(-a)z, -a). Hence f * E 9 iff E 9.Since f E 9is bounded and h E 9is integrable (Proposition 3.3), f(ggl)h(g1-') is integrable with respect to gl. Hence
(f* h) k ) = J
fkgl)h(gl-l)&l (I
is defined and has a finite value for all g E G. If g=t(z)r and gl =t(zl)rl, then ggl =t(z rzl)rrl Hence for any m E N 8and N E N,we have
+
.
l(1 +Izl')NDc,,r,mf(z+rZI, rrl)h( -r1-lzIy r1-91 JPN.m(f)Ih(-rl-'zl, rl)l * Thus we can differentiatef * h under the integral sign and have
(3.15)
(1 + Izl')"D"(f*
=so
4(g)
(1+ IZl")"(a"f)(ggl)hkl)&
*
Since
(1 + IZl')"l(D"f )(ggl)t s ( 1 + IZI')-'PN+%m(f) we see that (3.15) tends to zero when lzl++ m by Lebesgue's theorem. Hence the left hand side of (3.15) is bounded andf*h belongs to 9 ( G ) . q.e.d. 9
Definition 5. Let Hand H' be two separable Hilbert spaces. The set of bounded linear operators from H into H' is denoted by B(H, H'). Let (pn).,.,v be an orthonormal basis of H. For any element A of B(H, H'). Put
-
(3.16)
IIAII~~= 1IIApnIIf n=O
-
FOURIER TRANSFORMS OF RAPIDLY DECREASING FUNCTIONS
177
The value of (3.16) is independent of the choice of (+). In fact, if ( @ J n r N is an orthonormal basis of H', then, by the Parseval equality, we have
Hence the value of (3.16) is independent of equality shows that
Moreover, the last
(cp,).
(3.18) llAll2= IIA*llz An operator A E B(H, H') is called a Hilbert-Schmidt operator (abr. H-S operator) if IIAlla< 03. Let
+
+
(3.19) Ba(H, H')= { A E B(H, H')I llAlla< 00) . be the set of H-S operators from H into H'. Then Ba(H, H') is a subspace of B(H, H') and llAlla is a norm on Ba(H, H') which is called the Hilbert-Schmidt norm (abr. H-S norm). Moreover if A and B belong to Ba(H, H'), then the inner product (3.20) is defined. With the inner product (3.20), Ba(H, H') is a Hilbert space. A bounded operator A E B(H, H') is an H-S operator if and only if A*A is an operator of trace class on H. If A and B are H-S operators in Ba(H, H'), then B*A is an operator of trace class and we have (A, B) =Tr(B*A) .
(3.21)
Theorem 3.2. (Parseval equality) Iff belongs to 9 ( G ) , thenf(a) is a Hilbert-Schmidt operator on H = La(K)and it satisfies (3.22) Proof. Put h= f *f *. Then h belongs to 9 ( G ) by Proposition 3.6. Since &a) is of trace class (Theorem 3.1 1) and Tr &a) =Tr ((f*>"(a)f(a)) =
Tr(f(a) *f(a))= IIf(a)l12' by Proposition 3.1 and (3.21),f(a) is a HilbertSchmidt operator. Moreover, Theorem 3.1 proves that
:1
h( 1) =
Tr (&(a))a& =J:-Il
f(a)llAzda
.
On the other hand, by the definition of the convolution product, we have
h(l)=j-@fk)E)&=J We have proved (3.22).
Q
Ifk)l@r. q.e.d.
178
EUCLIDEAN MOTION GROUP
The image 9= { f If€ g ( G ) } will be determined in $5. As an application of properties of the Fourier transform on G we calculate the character of U a . As we have seen in Chapter 11, the characters determine the unitary representations of compact groups. The characters play the same role for the non-compact group G =M(2). However, here is a difficulty in defining the character of U",because an infinite-dimensional unitary operator U," does not belong to the trace class. In fact, the series "
(3.23) does not converge. This difficulty is overcome by considering (3.23) as a distribution on G. Definition 6. Let g ( G ) be the space of all complex-valuedC"-functions on G with compact supports. For any 00, put B5= {t(z)rE GI lzlsa} and
a u = g ( B u ) = { f ~ s ( G ) l f ( z ,a)=O if lzl>a} . a(&) is a Frkchet space with respect to the family of seminorms:
(3.24) IPm(f)= IP"f Il-lm w Then g ( G ) = 6 s ( B n ) is topologized as the strict inductive limit of n=1
9 ( B n )(cf. Ch. 111. Definition 6). A continuous linear form on the topological vector space a(G) is called a distribution on G. The space of all distributions on G is denoted by m G ) . Example 1. Iff is a continuous function on Raand p is a Radon measure on K E T,then the linear form f@,u on =(G) defined by
P H (lo, f @ p )
f (z)lo(z, a)dm(z)dl*(a)
=
(lo
Es
( G ))
S R J K
is a distribution on G. Now we consider (3.23) as a distribution x5 on G. This means that the character xu is the linear form on s ( G ) defined by
C J f(g)(Ugaxn, Xn)dg= C
Xu :fH
s---~l
where
Q
n--*
(U/axn,
Xn)=TrU/"s
PJANCHEREL THEOREM
179
Theorem 3.3. (Vilenkin) For any fixed 0-0, the linear form xu :fe Tr Ufais a distribution on G. In fact, xa is equal to JO(alzl)@(a) (cf. Example l), where JO is the Bessel function of order 0 and 6 is the Dirac measure at 0 on T z K. Proof. By Proposition 3.4 and 3.5, Ufais oftrace class and 1
Tr UfU=&J
Par
kh(a;8, e)de 0
q.e.d. Remark. From Theorem 3.3, we obtain another proof of Theorem 1.3. In fact, if U u z U b then we have U I u t z and X l o l = X l b l by Theorem 1.2. Hence we have la1 = lbl by Theorem 3.3.
$4. The Plancherel theorem In this section, we discuss the Fourier transform of the square-integrable functions on the group G=M(2). We shall prove an analogue of the Plancherel theorem which asserts that the Fourier transform fl ;f-f on G can be extended uniquely to an isometry of La(G)onto LaB,(R*+,ada) =/ : @ H ,
a&, where H , = Ba(La(K))is the Hilbert space of H-S opera-
tors on La(K)(Theorem 4.2). The analogue of the Plancherel theorem can be interpreted as the decomposition of the regular representation into irreducible representations (Theorem 4.3).
LEMMA1. Let H=La(X,p ) , H'=L'(Y, v ) , and let @ be the mapping of H"=L3(Xx Y, p x V ) into the space Ba(H', H) of H-S operators (cf. $3, Definition 5) which maps k E H" =L2(Xx Y, p x V ) into the integral operator K with the kernel k. Then @ is an isometry of H I onto Ba(H', H) = Ba. Proof. Let (p,,) be an orthonormal basis of H'. Then applying the Parseval equality to k(x, y), regarded as a function of y, we get
180
EUCLIDEAN MOTION GROUP
= CI(Ki2 (x)l'
*
I
Integrating the last equality over X,we get llkli2'=/
X
1
~ ~ ~ & b ' = ~ ~ ~ ~ ~
Ik(x, Y)l'dp(X)dp(Y)= f
Y
(G)
because is an orthonormal base of H'. The last equality proves that 0 is an isometry of H" into Br. Now we prove that Q, is surjective. Let K be an element of B, and define an operator K,, for each n E N by putting
Then K n is an H-S operator and ~~K-Knllzl= IlKv#+O
(4.1)
if n--r
+ . Q)
p>n
The operator Kn is an integral operator with the kernel n
kn (x, Y )=
C
*
(KPP)
P-0
in fact, since any f in H' can be written as
f= C ( f ,$Dk)$Dk ,
we see that n
c n
=
(f,v k ) ( K n p k ) ( x )
k-0
=(Kaf ) (4*
Since (4.2)
Ilkn-knrll,"~~Kn-Knrlln'=
IIKvkll'
if n > m ,
k-m+l
(K,) and (k,) are Cauchy sequences in Br and in H" respectively. Let k =lim k,, be the limit of (k,,) in H" and KO=@(k).Then since @[kn)= n-oD
K,, we have
181
PLANCHEREL THEOREM
limIIK~-KnII,=limIlk-knll,=O.
(4.2)
n--
(1-01
(4.1) and (4.2) prove that K = KO=Q(k).
q.e.d.
Definition 1. Let X and Y be two sets and T ( X ) , S ( Y ) , and ~ ( X Y)Xbe respectively the vector spaces of all complex-valued functions on X,Y, and X x Y. For any two functionf E f l ( X ) and g E .F(Y), Put ( f o g )(x, Y )=fW g ( Y ) * Then f o g E S ( X x Y). Since the mapping cf,g)Hf o g is a bilinear into ~ ( X Y), X there exists a linear mapmapping of x ( X ) x x(Y) ping @ : f l ( X ) @ T ( Y ) 4 f l ( X x Y)such that Q(f@d=fOg. Q is injective. In fact, let Q(h)=O. Then h can be written as
h=
Camnfm@gn
5
m. n
where
and (g,Jn are two linearly independent families in x ( X ) and
X(Y).Since
Cam.nfm(x)gn(Y)=o
for all x E x,Y E Y,
m. n
we have Cam,n fm=O for all n, by the linear independence of (gn).Hence U ~ , ~ = for O all m,n and h=O.
LEMMA 2. Let H=L2(X, p ) , H’=L’(Y, v), and H”=La(Xx Y, p x v ) . Then the mapping Q in Definition 1 can be extended uniquely to an isometry 0‘ of the Hilbert space tensor product H@H’ (cf. Ch. I11 53 Definition 2) onto HI‘. Proof. IfS, k E H and g , h E H’, then by Fubini’s theorem, we have
(fOg, k O h )=JX JYf(x)g(Y)koh(y)dp(x)dv(Y) = (f,k ) ( 8 9 h)
=(f@g, k0.h). Hence, if ((0,) and (+,) are orthonormal bases of H and of H’ respectively, (cpn@$m)n,m is an orthonormal system in H”. Since ( ~ n @ + m ) n . m is an orthonormal basis of H B H ’ , any element h in H@H’ can be developed in a series, (4.3)
h=
1(h, yn @ n. m
+m)pn
@ (In,
and
182
EUCLIDEAN MOTION GROUP
IW=
(4.4)
C~ ( h ,
-
pn@+m)Ia
n. m
The mapping 0,originally defined on the algebraic tensor product of H and H‘ can be extended to a linear mapping Of of H@H’ into H” by setting
~ ’ ( h=)
C(h,
pn 8 +m)vn
o
+m
n, m
for any h in H@H‘ (cf. (4.3)). The we have
z
IIO’(~)II~~= ~ ( hv,n B + m ) P
(4.5)
-
n, m
(4.4) and (4.5) prove that Of is an isometry of H@H‘ into H”. It remains is to prove that 0’ is surjective. It is sufficient to prove that (pn @,,,,q,m,) complete. To show this, it suffices to prove that if k E H” satisfies (k, (on @ +,J =O (4.6) then k=O. If k satisfies (4.6), then
for all n, m,
(k,f @g)=O for all f E H and g E H , because f = 2 anpn and g = C bm+m . Let K be the integral operator mapping H’ into H having kernel k. Then by Lemma 1 and (4.7), we see that llkllaa= llKIIaa=
1IIKG~II~= C IW+~,
vn)~2
n. m
7n
=
1
R.
I(k~n@+m)l’=O
m
q.e.d.
and thus k=O in H”.
By the isometry @’ in Lemma 2, we identify f @ g with f o g . So we write
(f@ g ) (x, v)= f (XI
*
With this notation, the following Corollary has been proved in the course of the proof of Lemma 2. COLLORARY to Lemma 2.
1) Iff, k E H and g, h E H ’ , then we have
(f@g,k@hh)=(f,k)(g,h), (4.7) 14.8) IIf@gIIa= llflla Ilglla 2) If ((on)n and (+m)m are orthonormal bases of H and of H’ respectively, then (cpn@gm),,, is an orthonormal basis of HI‘.
-
PLANCHEREL THEOREM
183
Theorem 4.1. Let G = M(2). Then 9 ( G ) is dense in La(@. Proof. By Lemma 2, La(Ra)@La(K)=La(G); hence, it is sufficient to show that for any f E La(Ra),g E La(K)and E >0, there exists an element h in p ( G ) such that (4.9)
Ilf@g-hIla<E
-
We can assume that f # 0 and g # 0. Since the set of trigonometric polynomials R(T) is dense in La(T)(cf. Ch. I. Theorem 4.3), there exists an element glE Cm(K)such that (4.10)
I I ~ - ~ i l l a < ~ / O l l f l l a ).
We can assume that ~/(211f11a)< Ilglla. Then we have gl #O. Moreover, since 9 ( R a )is dense in La(Ra)(Ch. 111. Theorem 1.4), there exists an element fi E . y ( R a ) such that
-
Ilf-fib <E/(2Ilgilld Let h =fl@gl. Then h is a C”-function on G = Ra x K and belongs to 9 ( G ) . By (4.8), we see that (4.1 1)
IIf@ g-hlli 5 If@ g-f@giIIa + IIf@ gi -fi @ gills = Ilf Ila Ik-gilla + IIf-fiII2 llgilla <E/2+€/2=E.
q.e.d.
Theorem 4.2. (Plancherel Theorem for M(2)). Let Ba = Ba(La(K))be the Hilbert space of all Hilbert-Schmidt operators on La(K). Put Ha=Ba for all a>O and H =
s:p
@Haadz. Then the Fourier transform
fl :fwfon .9’(G‘) (cf. 3.2)) can be extended uniquely to an isometry F of La(G)onto H. Proof. Theorem 3.2 proves that fl is an isometry of .9’(G) into H . Since g ( G ) is dense in La(@ (Theorem 4.1), 9can be extended uniquely to an isometry I; of La(G)into H . It remains to prove that F is surjective. Let L be an element in H . Then L is a function on R+* = (0,+ a) with values in B,. Since the value L(a) of L at a is an H-S operator on La(K), L(a) is an integral operator with kernel ka E La(Kx K) by Lemma 1. Put ka(s,r ) =k(a; s, r). Then we have
= / : 7 n J ~ / c ( u ;s, r)l’hdruh. Hence 0 :L w k ( a ; s, r ) is an isometry of H onto La(R+*x K x K). We identify H with La(R+*x K x K ) by the mapping 0.
184
EUCLIDEAN MOTION GROUP
Let (P :R+* x K+RP be the transformation (u,r)k+ru. Then the mapping gt+gov is an isometry of Ls(Rs)onto L2(R+*x K ) (the transformation to polar coordinates). We identify L’(R’) with L2(R+*x K ) and LS(R1 x K ) with Ls(R+*x K x K ) = H. Since F is an isometry, the image Im F is closed in H.Hence to prove the surjectivity of F,it is sufficient to show that Im 9is dense in If.Moreover since Im fl is contained in Im F, it suBces to prove that for any k E H =L’(R1 x K ) and E >0, there exists an elementf in P(G) such that
Ilk-k/Ila
I ~ u-Vila <E . Let y * v = w be the inverse Fourier transform of v on Rs. Then w E 9 ( R a ) (Ch. 111. Theorem 1.2). Hence f=w@X-n belongs to Y ( G ) . This function f = w @ ~ - , satisfies , (4.12) for k=g&,,. In fact, since k/(a;S, r ) = ( X w ) (ra)X-n(rS-l) =v(ra) X-n(r)Xn(s)
(3.7)
9
we have
Ilg@Xn-k/lIx=II(X-nU)@ =IIX-n(U-~)llr
Xn-(X-nv)@ ~nll, IIXnlls=II~-~lll<E.
q.e.d.
Definition 2. The isometry F in Theorem 4.2 is called the FourierPluncherel transform on G =M(2). The Plancherel theorem for M(2) gives the irreducible decomposition of the regular representation in the same way as the original Plancherel Theorem gives the irreducible decomposition of the regular representation of Rn (cf. Ch. 111. Theorem 2.2). First we give a general proposition.
185
PLANCHEREL THEOREM
Proposition 4.1. Let U be a unitary representation of a topological group G on a separable Hilbert space H. Let Ba= B,(H) be the Hilbert space of all Hilbert-Schmidt operators on Hand define a unitary representation V of G on Bs by setting (4.15) V,(A)=U,A for A E B ~and g E G . Then V can be decomposed as the direct sum of countable copies of U. More precisely, let (pn),,*~be an orthonormal basis of H, P, be the projection on Cp,,, and B P = { AE BsIAP,=A). Then we have
-
B I = @ Bsn and
(4.16) (4.17) Proof.
n-0
V I B l n z U forall n e N . V, is a unitary operator on B,, because
-
c
(VAA), v~(B))= (UJpn,
uJ+n)
n-0
=
f (Ah, BPR)
n-0
= ( A , B) for any A, BE Ba. It is obvious that VPlrt= V,,V,, for any gl and g3 in G. Now we prove the strong continuity of V. It is sufficient to prove that for any A E Bl and E >0,there exists a neighborhood N of the identity e in G such that (4.18) IIV,(A)-AIIs<~ for any g e N .
Since 11 U,All, = llA1la< + m , there exists an integer m such that IIAqrllS= e l m
c II
U,Aq#.C (&/4Y*
klm
Then we have
(4.19)
1IW,A
Lam
--)pklla
5 2(
c II
klm
Uo4klls+
c
llAq*lI’)
klm
<Es/2. On the other hand, since U is strongly continuous, we can take a neighborhood N of e such that the m inequalities (4.20) IIU,Apk-Apkll<e/2 I/;;; for any g E N
186
EUCLIDEAN MOTION GROUP
are valid for each k E {0, 1,2,
..., m - 1).
c II
(4.19) and (4.20) prove that
0
I1 VAA)-AIl2
<m ( ~ / 2&$ + 212 = 2 .
=
U,Aw 44'
k-0
We have proved (4.18) and therewith the strong continuity of V. It is clear that Bsn is a closed subspace of Bat. Since for all n,k E N , B," is orthogonal to Barnif n#m. In fact, if A E Ban,B E B P and n#m, then Pnffk=
6n.kpn
c
m
m
1
(A, B ) =
( A v k , &k)=
k-0
( A P n v k , BPrnvk)
k-0
eu
= c6n,k&n,k(Aqon,
&m)=O
*
k-0
+ ...
Let An =A(Po+PI +Pn) for any element A E Ba. Then it is clear that lim IIA-A,IIa=O. Since A P , belongs to Ban, this shows that (Ban),cN n*-
generates Ba. So we have proved (4.16). The mapping On : Ba"+H defined by @,(A)=Avo, is an isometry, because if A E Ban,then llAllaa=
c-
m
IIAvklla=
L=O
= IIOn(A)IIa
C
IIAPnvtIIa
= IIAVnII'
k-0
.
Let P k n be the linear operator on H defined by P k n v m = 6 m , n ( o k . Then Pen belongs to Ban and @ n ( P k n ) =P k " v n = p a for every k E N. Hence On is an isometry of Ban onto H. Moreover, we have (A) for any A E Ban. We have proved (4.17), and hence (4.15) by virtue of (4.16). ( a n
0
Vg)( A ) = UgAvn = (up
0
@n)
Theorem 4.3. Let R be the right regular representation of G =M(2). Then R is decomposed as follows: R - I +- @Vaada (4.21) 0
187
and V5 is the direct s u m of countable copies of U": V 5 a $ U 5 forall u>O. (4.22) nrZ
ProoJ Let V5 be the unitary representation of G on Ha=B,(L'(K)) defined by Vg5(A)=Ug5A for A E H 5 and g E G . Since (x,,),,.z is an orthonormal basis of La(K), V" is decomposed as in (4.22) by Proposition 4.1. Let F be the Fourier-Plancherel transform on G. Then we have (4.23)
a [ (
Vgaudu) F for every g E G .
Fo R , =
0
0
Since both sides of (4.23) are isometries of L'(G) onto H =
1:'
$H5ada
(Theorem 4.2) and y ( G ) is dense in LYG) (Theorem 4.1), it is sufficientto show that (4.24)
( F oRa)f =
[(/+-a Vgaadu) F ] f 0
for anyf E 9 ( G ) .
Hence (4.24) is proved.
q.e.d.
$5. Determination of 9 ( G ) and &(G)
In this section, we determine the images 9 ( G )= {fIf E .9(G)] of (fIf E .g(G)) of . g ( G ) under the Fourier transform
9 ( G ) and &(G)=
188
EUCLIDEAN MOTION GROUP
fl on G=M(2). We shall see that the analogues of the Theorems of Schwartz (Ch. 111. Theorem 1.2) and of Payley-Wiener(Ch. 111. Theorem 4.1, 4.2) are valid for the non-compact, non-commutative solvable Lie group G=M(2). In $3, we have defined the Fourier transform{ off E L1(G)as a function on R+*=(O, + a). In this section, we regardf as a function on R'. Definition 1. The Fourier transformf of a functionf in L1(G)is defined for any C E R2 as
f(C)=/ f(g)Ucq-l&, C E R a 9
(5.1)
(i
where UC is the principal series representation corresponding to the parameter value c (i.e. (UCt(.)$)(s)=et(x.*c)F(r-ls)). If C=u>O, then.f(c) = f ( u ) coincides with the value given under the original definition (3.2). The extended Fourier transform f(C) satisfies the following functional equation. Proposition 5.1. Let f be an integrable function on G. Thenf satisfies R, o f ( C ) RV-I=f(rC) for any r E K and C E R9 . (5.2) Proof. Since U,C satisfies 0
R, U,' R,-I = UqrC for any g E G and r E K by Theorem 1.2, we get (5.2). 0
0
q.e.d.
Proposition 5.2. Let f E 9 ( G ) and E R*. 1) Then f ( C ) is an integral operator with the kernel k / ( s , r)=k,(C :s, r ) given by r
=f(rc, rs-9 Y
where f ( C , r ) is the ordinary Fourier transform of the function ZH f ( z , r ) on R f . k , is a C"'-function on R' x K x K. 2) The inversion formula (5.4)
fk)= J B f T r ( u q m1M
C )
holds. 3) (5.5.)
kf(uC;s.r ) = k,(C; su, ru) for any r, s, U E Kand CER'.
DETERMINATION OF
P ( G ) AND
&(a
189
Proof. 1 ) is Proposition 3.4. The proof of Proposition 3.4 is valid for any U E Ra. The expression (5.3) shows that k, is a C"-function on R a x K x K. 2) Put =ra, a 2 0, r E K. Then we have Tr( U,cf(C))=Tr(R,UgaRr-' R,f(a)R,-l) =Tr( U g a f ( a ) )
by Proposition 5.1. Hence by Theorem 3.1, we get f ( g )=["Tr(
Ugaf(a))ada= /:-SKTr( Ugraf(ra))adadr
0
-
= S R a T r ( U g m)dm(C)
=(f(c)R,-lF) (su) =
1
k,(C ;su, ru)F(r)dr.
kf(C;su, r)F(ru-l)dr=
K
S K
for any F in H = La(K).Hence we get 3). 4) Putting r = 1 in (5.3) and using the Fourier inversion formula on
R2
(Ch. 111. Theorem 1.2.), we have f(z, s-l) =
1
k,(C ;s, I)ei('.C'dm(C)
.
' R
q.e.d. In the sequel we always use the following notation. For function F on
K,we write F(r)=F(r(a))=F(a). Let Do be the differential operator Do=--I d i da' As an operator on 9'(G), Do should be interpreted by the formula Do= i-l a/aa. Then Do satisfies (DO& Fa)= (FI,DoF2) for any Fl, Fa E C 1 ( K ) . (A) Moreover, put Xp(a)=efpn for any p E 2. Then we have (B)
DOXP "PXP
-
190
EUCLIDEAN MOTION GROUP
Proposition 5.3. Let L be an integral operator on the Hilbert space H = La(K) with a continuous kernel k. Then the following five conditions 1)-5) are mutually equivalent. 1) The kernel k is a C"-function on K x K. 2) For any m and n in N, there exists an integral operator L,,,,, with a Cm-kernelk,,, such that
(Dorn L Don)F=Lm,,F for any F E Cm(K). 3) For any m,nE N, there exists a constant Cm,,2 0 satisfying II(Dom L Don)xpII5 Cm,n for any p E 2. 0
0
0
0
4) For any m,nE N, m
C I((DomoLoDo")~p,x31< +
-
PA=-"
5 ) For any m,nE N, the linear operator DornoLoDon on Cm(K)can be extended to a bounded linear operator L,,, on H = L2(K). Proof. Since the implications 2)==-5)*3) are obvious, it is sufficient to prove that the conditions l), 2), 3) and 4) are mutually equivalent. 1)*2). If k@, a) is a C"-function on K x K a T x T,then for any m,n E N, (5.7)
is well-defined. Let Lm,,,be the integral operator with the kernel k,,,. By differentiation under the integral sign and integration by parts, we easily see that
(Dom L Do")F= L m,nF for any F E C m ( K ) . 2)*3). It is clear that 0
0
II(Dom L Do")xpll= IILm.nxpllS IILm.nll= Cm,n for any p E 2. 3)+4). If L satisfies 3), then for any m,nE N, there exists a constant am,,,2 0 such that 0
0
~~(l+Doa)Dom~L~Don(l+Doa)~p~~Ium,n for any P E 2. (We can take Urn,, = Cm,n Hence we have
+ Cm+a.n + Cm.n+a +
Cm+2.n+a
-1
m
1 I(DomLDonX*,X J l P.P--" m
=
1 I(DomLDo"(l+Doa)xp,(1+Do')xq)I/(1+~')(1+q') 9,P-m
DETERMINATION OF
Q(G) AND &(G)
191
because
f p.q---
= (1
+ 43-'=(
(1 + P T ' (1
+ n2/3y < +
1 p---Ol
+2
P-1 2
09.
4) =-1). If L satisfies 4), then for any m,n E N, we have lim
Ipl--,lqi
SO
--I(DomLDon~-p,
Xq)l
=o
that for some positive b m , n I(Dom~Dony-p, ~31 S b m , n for any p , q E 2.
Since l(~omL~onX--9, X J I =IP"4"l KLX-p, X P ) l = IP"4"l I(k, X P 8 X q ) l 9
the last inequality implies that the Fourier coefficient LCp, q)= (k, xP@xq)of k is rapidly decreasing. Then k may be expanded in a uniformly convergent Fourier series
c ca
k=
(k,XP€3Xxp)XP€3XXo
p.q=--
and the series can be differentiated term by term arbitrarily many times. Hence k is a C"-function on K x K E T x T. q.e.d.
Remark 1. Since C ( K ) ,is dense in La(K),the bounded linear operator
Lm,,, in the condition 5) is uniquely determined by L and is equal to the with integral operator Lm,,,with the kernel (5.7). We identify DOmoLoDon Lm,,,.With this convention, the condition 5) can be written as follows: For any m,nE N,we have (5.8) 1 p o m L Don\( < + ca . Remark 2. By the equalities (A) and (B) in p. 183, the condition 4) in Proposition 5.3, can be written as follows: 0
(5.9)
c-
0
For any m,nE N, IP"4"(LXP, X 3 1 <
+ 00 -
Po I=--
Hence the condition 4) in Proposition 5.3 is equivalent to the following one :
3
192
(5.10)
EUCLIDEAN MOTION GROUP
For any m,n E N ,
c Go
l((1 +Doa)mL(l+ D o T x p ,
xq)l
c+
.
P. 'I=--'
Therefore the condition (5.8) is equivalent to the following one: For any m,n E N, (5.11) 11(1+Doa)"oLo(l+Do~)*1)<+to .
Proposition 5.4.
Iff is a rapidly decreasing function on G, then we have
(5.12) (Do"fnf)*(C) =(- 1)mDom o m =(- l)"f(C) Dom for all m E N and for all C E Ra. Proof. By Proposition 5.2, the operatorf(C) has the C"-kernel k,(C; s, r). Hence the operator DOm~J?(C)~DOn on C"(K) can be uniquely extended to a bounded linear operator on H = L 2 ( K )by Proposition 5.3. The middle and right sides of (5.12) represent the extended bounded operators on H following the convention made in Remark 1 above. It suffices to prove that three operators in (5.12) are equal to each other on the space C"(K). We note fist that (5.13) Ud=Lk for all k e K. The differential operator iDo=a/& is regarded as an element in the Lie algebra t of K. Put xt =exp itDo. Then we have 0
c
c
Hence if I:is a C"-function on K,we have r(R=,S)*tc)q (u) =m F )(x-tu) by (5.13). Differentiating the above equation at t = O , we get ((DOfY ( C ) F ) (4 = -( 0 0 (DofY (0= -Do Repeating differentiation, we get (~ot"f)*
(c) = (- I)'DP
o
9 (u) 3
m
of(c)
*
for a~ rn E N.
of(c>
Similarly, we get and
( L t f Y tc)=f(c)U=,-lc (Do"f)* (C)=(
=f(C)&,
- l)"'f(C)
0
Dom.
Proposition 5.5. Let k(C;s, r ) be a C"-function on R' x K x K and let
DETERMINATION OF
Q(G)
AND
193
&(G)
L(C) be the integral operator on H = L a ( K )with the kernel k(c;s, r). Then the function L :c=(cl, C*)HL(C)is a C"-function on R' with values in the Hilbert space BI of H-S operators on H. The partial derivative ( P L ) (c) is the integral operator with the kernel (Dmk)(C;s, r) for all m E A'*. Proof. Let h ( C ) be the integral operator with the kernel ak(C;s, r)/aCl. Then by Lemma 1 in $4 and the mean value theorem, we see that IW'W(C+h)-L(C) -Li(C)IIaa = Ilh-'(k(C +A) -k(C))- ak(C)/aCilla2
when h=(h, O)+O, where A is a compact neighborhood of C. Hence L(C) is differentiable with respect to C1 under the H-S norm and aL(c)/aCl is equal to Ll(C). Since k is a C"-function, the same argument as above is applicable to any partial derivative of L. Hence L is a C"-function under the H-S norm. Proposition 5.6. have
Iff@, r ) is a rapidly decreasing function on G, then we
(A*f) Yc) =( - 1)" ICl""fC)
(5.14)
and (5.15)
Proof. we get
for all EN and Cs R'. We write k,(C; s, r ) = k ( f ; C; s, r). Using integration by parts,
(A"f)(C)=(-l)"(l~1~"f)~(C)
n
=(rC)(l*O)k(f; I; s, r ) .
Similarly we get (5.16)
k(D(OB1)f;c ; s, r)=(rC)(osl)k(f;c; s, r ) W " fC;; s, r ) = W " k ( f ; C; s, r )
and
for every multi-index n E N*.Hence for the Laplacian A = we have (5.17) and (5.14).
k @ f ; C; s, r ) = -ICl*k(f; C; s, r )
-(D('.O' +
194
EUCLIDEAN MOTION GROUP
Since f belongs to 9(@we , can differentiate (5.3) with respect to ( under the integral sign arbitrarily many times. Hence we get the equality (5.18)
Dc"kcf; [; s, r) = k((- r-'z)"f; C; s, r).
Hence by Proposition 5.5, we get (5.15).
q.e.d.
Definition 2. Let H = L2(K)and B = B ( H ) be the Banach space of all bounded linear operators on H and B, = B2(H)be the Hilbert space of all Hilbert-Schmidt operators on H. Then a function L on R2with values in B2 is called a rapidly decreasingfunction with C"-kernel if it satisfies the following two conditions 1) and 2). 1) L is a C"-function on R2 with values in B,. 2) For any integers, j, k,n E N and m E N Z (5.19)
qj.k,m,n(L)
= sup(lDdo(1 CfR2
+ IC12)k(pL)(5)oDo"II < +
-
03.
The space of all rapidly decreasing functions L; R2 B, with C--kernels is denoted by 9 ( R 2 ,B,). The subspace consisting of all functions L in 9(R2, B,) satisfying the functional equation R, 0 L(5) R,-I = L(r0 for any r E K and T€Rz, 3) is denoted by Y ( R 2 ,B,). The vector spaces Y ( R 2 ,B,) and Y ( R 2 , B,) are topologized by the family of seminorms: 0
(1 5.20)
{qj,k,m,nlj,
k, n € N , m € N 2 j
Proposition 5.7. Both Y ( R z ,B,) and 3'-(R2, B,) are Frdchet spaces. Proof. Since the topology of Y ( R 2 ,B,) is defined by a countable family of seminorms, .9'(R2, B2) is a metrizable, locally convex, topological vector space. It is complete. In fact if (Ln)nfNis a Cauchy sequence in 9(R2, B,), then for any CE R2, the sequence (L,(r)) is a Cauchy sequence in B,. Since B, is complete, the sequence (L.(r)) has a limit L(5) in B2. Since (1 I 2)"(PL,(5))converges uniformly to (1 I('1 ')" (DmL)(5)for any m E N 2 and n E N , L is a C"-function and is rapidly decreasing. Similarly, it has a C"-kernel. Hence L belongs to Y ( R 2 ,B,) and 9 ( R Z ,B,) is complete. For any fixed r in K,the mapping L c-, M,where M(5) = R,-'oL(rr) 0 R,, is a continuous mapping of .9'(R2,B,) onto itself. Hence Y i s a closed q.e.d. subspace of 9 ( R Z B2) , and is complete.
+
Theorem 5.1. The Fourier transform F:f*f on the group G induces a topological isomorphism of 9 ( G ) onto S ( R 2 ,B,).
+
= M(2)
P(G)
DETERMINATION OF &(G) AND
195
Proof. Let f be a rapidly decreasing function on G: f€.Y(G). Then the Fourier transform = S f is a B,-valued C--function on R2 with C"-kernel by Propositions 5.2 and 5.5. Moreover by Propositions 5.4 and 5.6, we have
fl
llDd O (1 =11(~0""(1
(5.21)
5
ss K
+ I Cl3'(o"fl)(O
O
D0"lI
- d)'z2"f(2,r))"(Oll
IDo'+"(l - d)'(z"f(z,r ) ) Idm(z)dr.
12
By proposition 1.5. in Chapter 111, the last integral is smaller than a linear combination with positive coefficients of the integral of the type
sKJR,
Iz I I( ~ O " " D b (z, f ) r ) Idm(z)dr
(5.22)
'O
< + 03,
= cPo+Z.c b . I + m ( f )
where C =
s..(l +
121z)-2dm(z)<
+
03
andp,,,,
(b.j+n)
is the seminorm
(3.3). Hence we have proved thatfl belongs to 9 ( R 2 ,B,). By means of the inequalities (5.21) and (5.22) we see that the Fourier transform Finduces a continuous mapping from 9 ( G ) into 9 ( R 2 , B2).Since belongs to S ( R 2 ,B,) by Proposition 5.1, T induces a continuous mapping from 9 ( G ) into Y ( R z ,B,). We next prove that the image F ( 9 ( G ) ) coincides with .7-(R2,B,). Let L be an element in 9-(R ,, B,) and put
fl
(5.23)
c-
M l ;8 9 4 =
(L(r)X,, X P M P m J
PSI---
The series converges absolutely and uniformly on R2 x T x T.More generally, for any m E N Z and n E N , the series (5.24)
(1
+ IC l 3 "
f (PWOXI,
X P ) X P < S ) ~
p.,---
converges absolutely and uniformly on R2 x T x T. In fact since L belongs to 9 ( R 2 ,B,), there exists a constant C,,,," 2 0 such that 11(1
+ lC13"(1 + Do2)(D"L)(O(l + Doz)ll 5 C,,,,,, for
we have the inequality
any CER,,
196
EUCLIDEAN MOTION GROUP
PtP'--
1 + I C I 2y((1 + D o 2 X P w 3 0 + Do21X4,
I I(1
XP)
I
P, 4
x ((1 +p2)(1
+q2)}-'
5 cm,n
(1
+
p2)-1(1+
421-1
<+*
PIP---
for any C=R2. Hence k(C;8, a) is a C"-function of C. For any j , k N , we can replace ( P L ) (0by Ddo(D"L)(r) o D,,'in the above argument. So the series (5.23) can be differentiated termwise with respect to a and 8 arbitrarily many times and k is a C"-function on R2 x T x T. Moreover k satisfies the functional equation (5.5): (5.25)
MuC; s, r) = 1 ( L ( U O X P , x , l x p ( r ) x , ( s ) PIP
=
1 1(~(OXP,
(L(0Ru-'X4,
Ru-1XPlXP(42J3
PIP
=
XPlXP(4*)
= k(C; su,
PI 4
The integral operator Lo(o with the kernel k(C; B, a) is equal to L ( 0 , because for any FE L2(K),we have (5.26)
= L(C)F.
Put (5.27)
f(z, r ) =Ja2 k(c; r - l , l ) e ' ( z * C ) h ( o .
(cf. Proposition 5.2, 4).) By replacing L ( 0 by D,'oL(o in (5.24), we see that for any integers j, n e N and m E N 2 there exists a constant C,,",,,,such that l(1
+ I C12YJ(DrmD~'k) (C; 8, all 5 Cj,n.m
for all (C, a,B)€R2 x T x T. Hence the function ~ ( cr ,) = k(C; r - l , 1) belongs to the function space 9(G'). Therefore the function f which is the
DEITRMINATION OF
.@(a AND p(G)
197
inverse Fourier transform of Q, on Rz belongs to 9 ( G ) by Theorem 1.2 in Chapter 111. Moreover by the functional equation (5.25) of the kernel k(C; s, r ) and by (5.27) we have
k(r-1C; s, r ) = k ( < ;sr-1, I)=$
f ( z , rs-1)e-s(s*c)citn(z) lt=
Replacing C by rC, we get (5.28) =ki(C;s, r). Hence by (5.26) and (5.28), we have
.
f ( c )=L(C) for all c E Ra We have proved that S ( . . Y ( G ) ) = Y ( R * ,Ba). Since the mapping f l is a continuous mapping from a FrCchet space 9 ( G ) onto another Frkhet space . T ( R a , Ba), the inverse mapping f l - l is continuous by the open mapping theorem. q.e.d. Now we prove the analogue for M(2) of the Paley-Wiener theorem which gives a characterization of C"-functions with compact supports by means of their Fourier-Laplace transforms. Definition 3. The space of all complex valued C"-functions on G with compact supports is denoted by g ( G ) . Let B,= {t(z)rE GI IzJ$ a and r E K ] and g a = a(&) be the subspace of g ( G ) consisting of all functions in g ( G ) whose supports are contained in B,. For any m E Na,a seminormpm on g(G)is defined by (5.29)
pm(f>=SuPIDmf(g)l 3
iW
The space g,,is topologized by the family of seminorms {pmlmE W }. Then g , is a Fr6chet space. The space g ( G ) = ;gnis topologized n-1
as the strict inductive limit of g,,(cf. Ch. 111. &I. Definition 6). We have seen in Ch. 111. &I that g ( R " ) is characterized by its FourierLaplace transform. Similarly g ( G ) is characterized by its Fourier-Laplace transform. To define the Fourier-Laplace transform off in g ( G ) , it is necessary to complexify the parameter Z E R a of the principal series representation. The inner product (z, w) on Ra is extended to a bilinear form on Cax CS.
198
EUCLIDEAN MOTION GROUP
Then for any C E P,the function x C :t(z)wei(x.C)is a one-dimensional continuous representation of the translation group T. xC is not unitary unless C belongs to Ra. However, we can define the representation UC induced by xC in the following way. Proposition 5.8. Let g=t(z)r E G=M(2) and F E H = L a ( K ) and C E Cz, and put (UgcF)( ~ ) = e { ( * * ~ C ) F ( r - l s ) . Then U,C is a bounded linear operator on the Hilbert space H and the mapping U c : g ~ +U,C is a strongly continuous representation of G on H. Proof. Since Z E Ra, we have (,+a, rc)l =&x-11,ImC)jelxl - Ixmct . Hence we have (5.30) 11 UgCII5 e1.1 I X r n C l for g = t(z)r . So U,C is a bounded linear operator on H. The proof of the equality Ug,CU,,C = U,,,,C is same as in Theorem 1.1. Although UC is not a unitary representation in general, the strong continuity of UC may be proved in the same way as in the proof of Theorem 1.1, because the function gIIU,Cll is bounded on every compact set in G, as is seen from (5.30). q.e.d.
Definition 4. The Fourier-Laplace transform S c f on G of a function
e g ( G ) is the function on Ca with values in B=B(La(K)) defined by r
(5.31) Since U,C is a bounded continuous function andf is a continuous function f ) (C) is well-defined and is a bounded operator with compact support, (.Fc on H. In the same way as in Proposition 5.2, (.Fc f ) (C) is an integral operator with the kernel (5.32)
k,(C; s, r ) = [
f ( z , rs-l)e-i(','C'dm(z)=f(rC, rs-1) It=
for any C E Csand s, r E K, where f is the Fourier-Laplace transform on
R=. Theorem 5.2. A complex-valued function k(C; s, r ) on C ax K x K is equal to the kernel k,(C; s, r) for a certain function f in 9.= s ( B , ) if and only if k satisfies the following three conditions:
DETERMINATION OF
P(G)AND &(G)
199
1) k is a C"-function on Cax K x K. 2) For any m E N a , the function Ct+Cmk(C;s, r ) is an entire function on Caof exponential type Sa, i.e. there exists a constant CmrO such that (5.33) ICmk(C;s, r)lS CmealIrnCI. for any 5 E Ca and s, r E K. 3) k satisfies the functional equation (5.34) k(uC; s, I ) =k(C;su, ru) for any C E Ca and s, r, u E K. Proox Let f be an element in sa. Then k,(C; s, r) is an integral over the compact set B,, (5.35)
f (z, rs-l)e-s(z* +C)dm(z).
k,(C; s, r ) = !B
a
Since e-t(z*rc) is an entire function and the integral is over a compact set, the function Ct-+k,(C;s, r) is an entire function on C1.Moreover, since (5.16) is valid for f E g ( G ) and the complex vector variable C E Ca, we have (5.36) l(1 + lCla)nkf(C;3, r)l 1(1-A)"[ f ( r z , rs-l)]lea~lrn~~dm(z) 5S . a I;CealIrnCl for any C E Ca. Since I ~ ~ l d+ICla)lml (l for any m e N a , we have proved (5.33) in virtue of (5.36). Since the integrand of (5.35) is a C"-function of (s,r), k, is a Cfunction on Cax K x K. Moreover, UC satisfies R, U,' R7-l = UVrC for any 5 E Ca 0
0
and g E G and r E K in exactly the same way as in Proposition 5.1. Hence the Fourier-Laplace transform ( f l c f > ( C ) satisfies (5.37) ( X c f ) ( r z ; = ) R, ( X c f ) ( C ) Rr-l for all r E K and for all C E Ca 0
0
c
So the kernel k , satisfies (5.34),just as (5.5). Conversely let k satisfy the three conditions in Theorem 5.2, and define a function f ( g ) = f ( z , r ) on G by
Since for any m E N2,the function p+Cmk(C; r-l, 1 ) is an entire function of exponential type 5 a on Cay and f ( z , r ) is the inverse Fourier transform of the function &+k(C;r-l, 1) on Ra, the function zt-+f(z,r)is a C--function whose support is contained in B, by the Payley-Wiener theorem
200
EUCLIDEAN MOTION GROUP
(Ch. 111. Theorem 4.1). Since k satisfies (5.33) for any m E W , (5.38)can be differentiated under the integral sign, and we get (5.39)
(D*f)(z, r ) = /
<mk(C; r-1,l)e~(z.c)dm(c). R '
By (5.39), (D*f)(z,r) is a C"-function of r E K for any m E N'. Hencef is a C"-function on G and belongs to g a . By the condition 3) in the theorem, (5.38) can be written as
The two continuous functions Cnk(r-1C; s, r) and z n f ( z , rs-l) belong to L1(Ra)and the latter is the inverse Fourier transform of the former. Hence the inversion formula for (5.40), namely, (5.41)
k(r-lc; s, r ) =
SD.
f ( z , rs-l)e-<(*.c)dm(z),
is valid by Ch. 111, Theorem 1.8. Replacing ( by rC in (5.41), we get
k(C; s, r ) =
f ( z , rs-')e-"'. W m ( z )
/R%
= k f ( ( ; s , r ) forany C € R a and s , r E K .
Since Ct+k(C;s, r ) and Cwkf(c;s, r ) are entire functions on Caand coincide with each other on the real space R', they coincide on C* (Ch. 111. 54, Lemma 1 ) . Hence we have proved that k = k f for somef E 9.. q.e.d. We have defined the meaning of complex-valued holomorphic function on a domain D in Cn in Ch. 111. $4. In the same way we can define a holomorphic function on D c C n with values in a Banach space B. A B-valued functionf of n complex variables is called entire iffis holomorphic on Cn. A B-valued function L on C" is said to be of exponential type 5 a if there exists a constant C such that IIL(C)lld CeUlIrnCl for all E C" . Definition 5. Let a> 0 and Ba = BI(La(R)). Then the space of all functions L : Ca-+ Ba satisfying the following two conditions 1) and 2) is denoted by p a : 1 ) L is an entire function on Ca. 2) For any m E N a , C*L(C) is of exponential type 5 a, i. e., there exists a constant C,,, such that lIc"L(C)ll~ CmealIrnCl for all c E C'
.
DETERMINATION OF
p(G)AND
&(a
201
The subspace of g@, consisting of all functions L with C”-kernels k(c;B,a) is denoted by pa.For any m E N aand j , n E N , we define the seminorm (5.42)
qm,j,n(L)= SUP e-ailmCI1lDOjOCmL(C) oDonll E d 3
on P a pais topologized by the family of seminorms
(5.43) (qm,j,nlmEN a and j , n e Nl . For any m, n, j E N , put sm.j,n(L)=supe-allmC1llDoj(1 l ~ l * ) ~ L (Donll c) . (5.44) 0
Er 0
+
0
Then smn.j,n is a seminorm on p a . The topology of p a defined by the seminorms (5.44) is clearly equal to the topology defined by the seminorms (5.43). pais a metrizable, locally convex, topological vector space. It is complete, because the uniform limit of a sequence of entire functions is entire. Hence pais a Frkhet space. The subspace of paconsisting all functions L satisfying the functional equation R, o L(c)o R,-l= L(rC) for all r E K and C E Ca (5.45)
is denoted by go. As a closed subspace of p a , %a is a Frkhet space. The strict inductive limit of ( s n ) n z l is denoted by s. Definition 6. A function f on U with values in a Banach space H is called weukZy unulytic if the function x n ( f ( x ) , y ) is analytic for each ‘p in the dual space H* of H. LEMMA 1. Let M be a real or complex analytic manifold and U be an open set in M and H be a complex Banach space. A strongly continuous H-valued function f on U is analytic if and only iff is weakly analytic. Proof. The “only if” part of the lemma is trivial. A power series f ( x ) of real variables x = (xl,..., x,) converges for any real numbers x4 satisfying Ix,-atl
202
EUCLIDEAN MOTION GROUP
for any rectifiable closed curve C in U.Since p is an arbitrary element in H*, the above equality implies that
scl.),=o for any rectifiable closed curve C in U. Hence by Morera's theorem, f is analytic on U.
Theorem 5.3. The Fourier-Laplace transform X c on G=M(2) is a topological isomorphism of g aonto xufor every a>O. Hence 9" is a topological isomorphism of 9 =s ( G ) onto Proof. Let f be a function in Saand k,(<; s, r ) be the kernel of the integral operator ( X f c)(C). Then k,(C; s, r ) is a C"-function on Ca x K x K and an entire function of 5. Hence for any Fl and F2in H=La(K),
x.
is an entire function of C. Therefore X c f is weakly analytic on C a and hence analytic on Ca by Lemma 1. Namely X c f is an entire function. f is exponential type 5 a, because for any F in H = La(K) Moreover Tc and for any C E C2,we have by Schwarz inequality
=W(B,)~ llfllaaeaalIbCl ,
-We note that Proposition 5.4 is valid for any complex vector variable E C a and that (5.14) is valid for any E Ca when f belongs to g(@. Hence by (5.46), we have (5.47)
Po'
0
(1
+ I Cl2)"(~=n(r) Do71 O
= l l ~ c ( ( l - 4"Db ")(r)ll
$rn(Ba)ll(l - A)"Do'+"fllz@'*mC' 5m(BJ2 I I( 1 - d)"D$+"flI-@' ImC'.
Hence X cf belongs to pa.Since .Fc f satisfies the functional equation (5.37), S C f belongs to xu.Moreover the inequality (5.47) proves that Tc f induces a continuous mapping from gainto z,. Conversely let L be an element in xa.Then the series (5.23) converges
DETERMINATION OF
p(c)AND &(G)
203
absolutely and uniformly on Cax K x K.The proof of this fact is same as the corresponding part of the proof of Theorem 5.1. Since i is an entire function on C a , the function b k ( C ; p , a ) is an entire function on Ca, because the sum of a uniformly convergent series of entire functions is entire. Replacing L(c) by Do"oL(C)o DoRfor any m , n E N , we see that p, a ) is an entire function. In particular the function Cw(dm+nk/aandBm)(c; k is a C"-function on C 2x K x K. Since cmL(c) is an entire function of exponential type 5 a, the function cwgrnk(C;p, a ) is an entire function of exponential type 5 a. Since L satisfies the functional equation (5.37), k satisfies (5.34). Hence k satisfies the conditions of Theorem 5.2, and there exists a function f in g asuch that k = k , . Thus we have proved that L(c)= ( S c f ) ( c )for any c E C aand that Y eis a surjection of gaonto %a. Since Y e is an injection by the inversion formula (Theorem 3.1), F C is a continuous bijection of g aonto %a. Hence YC-l is also continuous on .Fa by the open mapping theorem. is a topological isomorphism of Therefore, we have proved that .FC 9 a onto %aSince 9 is the strict inductive limit of gn and % is the strict inductive limit of %, X C is a topological isomorphism of 9 onto X (cf. Ch. 111, Proposition 4.2). q.e.d.
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CHAPTER V
Unitary representations of SL(2, R)
51. The Iwasawa decomposition In this section, we give some group-theoretical preliminaries which will be necessary later. First we introduce the subgroups K,A,N, and show that any element g of SL(2, R)is uniquely and continuously decomposable in the form g = kan, k E K, a E A , n E N . This is the Zwasawa decomposition of g which plays an important role in the construction of unitary representations. Second, we show that SL(2, R) is isomorphic to another linear Lie group SU(1,l) by means of the Cayley transform. SL(2, R) acts naturally on the upper half-plane, while SU(1, 1) acts on the unit disc. The realization of SL(2, R)as SU(1, 1) is convenient and will be used frequently in the later sections. In the last part of this section, we show that SL(2, R) is the two-fold covering group of the 3-dimensional proper Lorentz group G+(2). Definition 1. The multiplicative group of all 2 x 2 real matrices with determinant 1 is denoted by SL(2, R). Proposition 1.1. 1) The Lie algebra GI(2, R) of SL(2, R) is given by 11(2, R)= { X E Ma(R) I TrX=O}. 2) The elements
form a basis of ~ l ( 2R). , 3) The Lie products among Xo, XI, and Xa are given by (1.2)
1x0,X1I=Xo-X2,
[Xo, X*]=X1, [XI, X,]=X,.
Proof. 1) Ch. 11. Proposition 5.7. 2) is clear from 1). 3) is easily obtained by direct calculations. 205
206
UNITARY REPRESENTATION OF
SL(2,R)
Definition 2. Let 8, t, E be arbitrary real numbers and put
ue=exp 0x0, at=exp t X l and nE=expEX%. Then the subgroups K,A,N of SL(2, R ) are defined by
K=
{uh9 E R ) , A = {atltE
R} and N = {nEIEE R } .
Proposition 1.2. We have
K E R/4sZ E T , A = R, N = R . Proof.
Since xS3=0, nF=exp C X= ~1
+ EX^ = (o1
1>. 5
Hence N E R by the isomorphism &me. We have
Hence A z R by the isomorphism ?Hat. Since Xoa= - 1,
cos el2 sin 812 -sin 812 cos 812
n-0
n-0
=
Hence, by the isomorphism eHUe, K G R/4nZ T. Remark. K is a maximal compact subgroup of SL(2,R).
Proposition 1.3. Any element g E SL(2, R ) is uniquely decomposable in the form (1.4) g =U d Z t n ( . If g=
(:
i)
E SL(2, R), then the triple (8, t, E ) in (1.4) is given by the
relations
Proof. Taking the product of matrices we have
e
e
Hence we get a= ella cos- c = -ella sin-, from which we derive a - ic = 2’ 2
207
IWASAWA DECOMPOSITION
e(tlS)+(‘@I2).
Hence la- icl
and we get
a-ic = --=== Jaa
+
and et =a’
CS
+ca.
On the other hand, we also have ab +cd= etE from the matrix calculation above, and this gives us [=
ab + cd
~
aa+ca
*
We have proved that every element g in SL(2, R ) can be written uniquely as in (1.4) where (0, t, E ) is given by (1.5). Proposition 1.4. The mappingf:(u, a, n ) ~ u a is n an analytic diffeomorphism of K x A x N onto SL(2, R ) . In particular, SL(2, R ) is connected. Proof. f is a bijection of K x A x N onto SL(2, R ) by Proposition 1.3. The mapping f is real analytic because the operation of multiplication is a polynomial mapping. The inverse mapping off is also real analytic as is seen by (1.5). (Note that if g belongs to SL(2, R), then (a, c) # 0 and aa+ ca>0.) Since K, A , and N are connected, SL(2, R ) is connected. Proposition 1.5. For an element g in SL(2, R ) and 0 E R,let (1.6)
W e =Ug.eat(p.
e ) k g , el
be the Iwasawa decompositicjn of gue. Then the following holds: 1 ) For g, g‘ in SL(2, R ) we have (1.7)
(gg’).O=g.(g‘.O) mod 477,
(1.8) (1.9)
t(gg’, 0) = t(g, g’-e>+ t(g’, 8) g . ( e + 2 K ) = g . e + 2 ~mod 477,
2) If g =
I;]E SL(2, R), then we have e
(a- ic)cos(1.10)
2
e((~.e)12 =
1-8=0,
t(g, e + 2 ~ ) = t ( g 0). ,
+(- b +id)sin-62
e
e s
I(a-ic)cos-+(-b+id)sin--l 2
e
2
e ,
(1.11)
et(QSe)=I(a-ic)cos-+(-b+id)sin-~a
(1.12)
E(g, e) =e-‘(p.
2
2
1 {(ab+ cd)coso +z(u3
-b2+c2-ds)sin8}.
K
N (because N is normal in AN).
A
By the uniqueness of the Iwasawa decomposition, we have (gg') 8 = 8" = g - 8' =g.(g'. 8) mod 411,
-
t(gg', 8) =t"
+t'= t(g, g'4) +t(g', 8).
To get the second half of l), we observe that uB+lr=-uI, and hence that guo+s.= -gu.9=
-Ug-eat(g,~)nt(g,e)
=U g . s + a P t c g , a+il)nc(g, e+ad,
so that again by the uniqueness of the Iwasawa decomposition, we have g . ( 8 + 2 7 ~ ) = g . 8 + 2 ~mod 411 and t(g, 8 + 2 a ) = t ( g , 8). 2 ) The assertion 2 ) is obtained by a straightforward application of Proposition 1.3. to
3) From 2) we obtain the relation ef(g.@)lPet(& @)is
" +(-b +id)sin-.2
= (a- jc)cos-
0
2
Differentiating the both sides of this equality with respect to 8, we obtain
By taking the imaginery parts of the both sides of this relation equal, we obtain
IWASAWA DECOMPOSITION
209
To construct a realization of SL(2, R), we consider the group SL(2, C) operating on the Riemann sphere C = C u [ 00 ] (the one point compactification of the complex plane C). As is well known, an element g =
[:: "d]
of SL(2, C ) acts on C as a linear fractional transformation (D(g),defined bY az+b +(g) : ZHgZ=( zE C ) . cz+d It is easy to see that, for g,g' E SL(2, C ) and z E C , we have {(gg') z=g(g'z), lz=z.
The map $ is a homomorphism from SL(2, C) to the group A ( C ) of automorphism of C,where, by an automorphism of C, we mean a bijective holomorphic transformation of C whose inverse is also holomorphic. One can prove, that 4 is surjective (cf. H. Cartan, Elementary theory of analytic functions of one or several complex variables, Hermann-Addison-Wesley, 1963, pp. 180-181). Hence, we have SL(2, C ) / { + l ]EA(C). If we let C+ denote the upper half-plane, { z=x + iy E C Iy >01, then, for g E SL(2, C ) , we have g c + = c + s g E SL(2, R ) and sL(2, R)/ { 11 EA(C+) (ibid. pp. 182-183). Let D = { z E CI IzI < l} be the unit disc. The Cayley transformation z-i c :Z H C Z = z+i transforms C+ onto D. [Observe that Z E C + o l z - i l < l z + i l . ] We have an isomorphism from A(C+)onto A ( D ) given by gncgc-'. Let C be the 2 x 2 unitary matrix given by c=-[1 1 E U(2). a1 We now have the following proposition.
*
-3
Proposition 1.6. 1) Let G=C-SL(2,R).C-l. Then G =
dl
If C[C a b C-l=["
B
"1, @
then
I["
"]I B @
la12-1p12=1).
210
SL(2,R)
UNITARY REPRESENTATION OF
a=
1
+
{(a+d) i(b-c)}
1
p = [(a- d )- i(b +c)] 2) We have G=SU(l, l), where SU(1, I ) = { g E M 2 ( C )I g * e g = e l , and
[:
det g= 1) and el=
-3
If H is a Hermitian form on C’, given by H(z)=zli-l-zzlzs,
.=“‘I
za
E C’,
then we can write G=SU(l, 1)= { g E M 2 ( C )I H(gz)=H(z) for all Z E C’,det g=l}. 3) By the isomorphism h :gnCgC-’ from SY2, R ) to G, we have
Proof. 1) Let g=@
[:ii, -it].
:] A
ne=[:
E
i]
E M2(R).Then we have
=-[ 1 (a+ d ) + i(b -
c)
2 (a-d)+i(b+c)
Hence CgC-1 is of the form lolalz-
i],
3
E SL(2, C), we have
+
(a- d ) - i(b c)
(a+d)-i(b-c)
1 ’
where a, B E C. We have det g =
1 ~ 1 ’ = 1. The assertion 1) follows.
2) For g =
1-iy
21 1
IWASAWA DECOMPOSITION
1;
p
-l 6 6 1 = L
-/I a1
Using this, we can easily deduce (g*elg=el and det g = 1) o (a=& ,8=p and
Ia12 -I,811=1).
Hence we have the first assertion in 2). The condition g*elg = el is nothing but the matrix form of the condition H ( g z ) = H ( z ) for all Z E Ca, so the second assertion in 2) follows. The assertion 3) follows directly from the truth of assertion 1). q.e.d. Proposition 1.7. Identifying corresponding object by the isomorphism h : SL(2, R)+SU(l, l), we write h(ue)=ue, h(a,)=ac, h(ne)=ne and
.
h ( g 4 = u, eat(,, 8) nt(,.e).
If g = [ "
1'
B a
E SU(1, l), then we have
(1.13) (1.14)
etQ*
= lac
+
a = Id
+pCla, where
= ete.
Proof. The proposition can be obtained from Proposition 1.5,2) via the conversion formula of Proposition 1.6, 1). It can also be proved by observing that from Proposition 1.6, 1) we get a - ic = a ,9; so Proposition 1.3 now reads
+
(1.15)
Now we calculate and obtain (in SU(1, l), using Proposition 1.6, 3))
Then we apply (1.15) to a'=aereIa, $=,!?e-telato obtain (1.13) and (1.14).
Definition 3. The 3-dimensional Lorentz group G(2)= O(2, 1) is the subgroup of GL(3, R) defined by G(2)= ( g e GL(3, R)l'gBg=B} where B=
(- 0 la ). The connected component G+(2)of G(2) containing
identity 1 is called the 3-dimensional proper Lorentz group.
212
UNITARY REPRESENTATION OF
Proposition 1.8.
SL(2,R)
Let
and eo=X(l,O,O), el =X(0,l ,O), e, =X(O,O,1). For any g E SL(2, R ) let s(g) be the matrix of the linear transformation x w g 2 g in W with respect to the basis (e,). Then s is a continuous homomorphism of SL(2, R) onto G+(2) with the kernel Z = { -+ 1). Proof. The vector space W is the subspace of M,(R) consisting of all symmetric matrices. Therefore, s(g)x=gxtg belongs to W for any x E W. Hence x-gx’g is a linear transformation on W. Since - det X(xo,xl, x,) = -xoa + xlS+xsa is invariant under s(g), s is a continuous homomorphism of SL(2, R) into G(2). Since SL(2, R) is connected, the image s(SL(2, R)) is connected, and contained in G+(2). To find ker s, we let g =
(z ”d>
E ker s.
Then the equations eo =s(g)eo=gcg =
(.I +” ac+ bd
c2+ d a
and
show that a’+bz=l, a’-.bS=1 ca+dS=l, cS-d’= - 1, from which we derive b=c=O, a = k 1, d= k 1. Since det g=1, we conclude g = k 1. Since s(- 1)= 1, ker s is actually equal to { k l}. It is easily seen that the kernel ker s’ of the differential representation s’ (Ch. 11. 55) is equal to the Lie algebra of ker s= { k 1). Hence ker s‘= {0} and s’ is a linear injection of Bl(2, R) into the Lie algebra g(2) of G+(2). Since dim g(2) = 3 =dimBK(2, R),s‘ is a linear isomorphism of GK(2, R) onto g(2). Since expg(2) is a neighborhood of 1 in G+(2) and the connected group G+(2) is generated by every neighborhood of the identity, every element h in G+(2) can be written in the form h =exp tl Yl ......exp tr Yk where YrE g(2) and tr E R. Since s’ is surjective, there exist k elements Xl, ..., Xk in Gl(2, R) such that s’(Xt)= Yt (1 S i S k ) . Put g=exp tlXl ... exptXXk.Then g belongs to SL(2, R ) and s(g)=h, because s(exp t X ) = exp rs’(X) for every XEBI(~,R), by Ch. 11, Proposition 5.9. We have proved that s is a continuous mapping of SL(2, R) onto G+(2),with kernel q.e.d. equal to Z = { k l}.
PRINCIPAL CONTINUOUS SERIES
213
Remark. Let g,,(O 5 i, j g 2) be the (i, j)-element of g E G(2). Then the relation lgBg=B yields goo'=l +g,O2+g~o2~1 and det g= & 1. Hence either gooZ1 or good - 1. It can be proved easily that G+(2) consists of all elements g in G(2) satisfying (1.16)
det g= 1 and goal 1.
$2. Irreducible unitary representations
I. PRMCIPALCONTINUOUS SERIES Let G= KAN be the Iwasawa decomposition of G = S U ( l , 1) (Proposition 1.3). We can identify K with the torus T = R/4 7~ Z by ue= btela e-,@:] we (mod 4 ~ ) .As we have seen in Proposition 1.5, G x K-tK, defined ~, (gg').e =g.(g'-O) and 1.8 = 0, hence, by identifying by (g, U ~ ) H U ~ . satisfies K with T, we can say that G acts on K from the left. On the other hand, we can map K onto U = {C E C I = 1) by (I, :ubw e(@.The map (I, is a homomorphism from K onto U with ker (I,= { t l } = {uo,ua.}, or we can say that (I, is a homomorphism from T onto U with ker Q = (0,27~(mod 47~)).If we deiine the action of G on U so that the following diagram: GxT+T
. 1 1 G X U-+U
is commutative, then we have
In fact, if C=efo, then using Proposition 1.5, 2) we have
We define a function t ; G x U+R by t(g, t;) = t(g, 81, where I: =(I,(us). This function is well-defined, because t(g, e +2n) = t(g, 19)(Proposition 1.5, 1)). By Proposition 1.7, we have e"g*C)= IbC+al'. Let the function u : G x U-+U be defined by
2 14
UNITARY REPRESENTATION OF
and for s E C and j = O ,
SL(2,R)
1 -, set 2 vf. 8 ( g ,
c) =u(g, @Ve-st(g*C).
Let p be the normalized Haar measure of the compact group U,i.e., 1 dp(C)=-dO 2z
We usually denote the integral
(C=ete).
1
f(C)
dp(C) by
1
f(C) dC.
U
U
Then we have the following proposition.
Proof. By Proposition 1.7, we have
Taking the complex conjugate of this relation, we get
from which we derive u(g, <)=e'(-o.@+@)/a,for =el@. Using (gg')-O=g-(g'-8)mod 4a, the first assertion of the proposition now follows from the simple calculation -(gg')-8+8= { - g . ( g ' 4 ) + g ' - e ] ( - g ' - e + e } mod 4 ~ , and from g'C =e*(g'.@). The second assertion follows from the first and from r(gg', 8) = t(g, g ' 4 ) t(g', 8 ) (Proposition 1.5, 1)). By Proposition 1.5, 3) we get
+
+
Proposition 2.2.
Let Q=La(U,p ) and j E
and s E C. For any
g E G, we define the operator Vgf.'on $j by
(vg$. af) (c) =e i.e.,
-a'(g-l,
C)
(uk - l ,
C) "(g-'.C)
(fe$1,
PRINCIPAL CONTINUOUS SERIES
215
Then the following hold: 1) V/' is a bounded linear operator on 9.For any compact subset A = A-' in G, there is a positive constant C(A), such that llVgj**ll IC(A)IRe*l+lla for all g E A, where Re s denotes the real part of s. 2) The mapping Vj.' :gt-+Vgj.* is a representation of G on 8 : * = v,j,* V,J. * and Vlj. = 1. a) vgoJ~ b) V'.* is strongly continuous. 3) V'pa is a ~ n i t a r yrepresentation of G if and only if Res= 1/2. V&' is a unitary operator for any k E K and for any j, s. 1
4) Let ~ ~ ( u ~ ) = (e~* E ~ z~ Z , andf,(c)=p(pE ) Z).
Then V./ 'fp = xp+f(ub)fp. Proof. 1) Since e-t(9-1*C)is a positive continuous function on G x U, it follows that for any compact subset A of G, there exists a constant C(& 1, such that C(A)-' ge-L(g-l.C) 5 C(A), for all g E A, c E U. Then, for any s E C,we have (2.1) le-*t(g-l. C ) I 5 C(A)lReal. We compute the norm of V,J."f: IIVpj.'flla=
le-rC(g-l*C)laIf(g-lc)la J U
dt:
216
UNITARY REPRESENTATION OF S42,R)
IIVg’.”l5 C(A)’=e*’+l’a (2.2) 2) a) By Proposition 2.1, we have
kE 4
(VOOJ.If)(C) = vJ*“(gg’)-’C)f((gg’)-’C) = v’* a(gI-1,g-10 v’, yg-1, C) f(g‘-’(g-’C))
C) (VO.’.’f)(g-’C) i.e., =( Vg’l’( VOJ* f)) (C),
= v’qg-1,
VgrA = V,j. * V,J. I. J
From the definition of t(g, 8 ) (Proposition 1.5) and u(g, C), we have t(l,c)=l andu(l,C)=l, so weget V1jpJ=l. b) We fix j and s and first prove, that Vjl * is strongly continuous at 1, i.e., (2.3)
for given f E 8 and E >O, there is a neighborhood W of 1 in G, such that
i
IIVgJ.If-fll<~ for g E W. Iff=O, then (2.3) is trivial. So we assume llfll +O. Let N be any compact neighborhood of 1 in G and let C=C(N), the positive constant for the compact set N,given in 1). The set of continuous functions is dense in 8 (for example, by the Peter-Weyl Theorem), so there exists a continuous function $ on U,such that
Ilf- $11 <Min ( ~ / ( 4 C i ~ ~ *1,l llfll, + l ’ ~44). (2.4) Note that, in particular, (2.4) means $+O, ll$ll+O. We shall prove that there is a neighborhood M of 1 in G such that
-=
1 vj,‘(g-l,c) - 11 ~/(411$]1).for any g E M and any C E U. (2.5) In fact, since vj. ’(g-l,c) is continuous on G x U,for any c’ E U,there are an open neighborhood Bc# of c’ in U and a neighborhood ME’ of 1 in G, such that, if c E BE,and g E Mcl, then (2.6) Iv’*’(g-l,0- 11-=~/(411$11). Since U is compact, there exist a finite number of elements CI,
such that
..., Cn,
u” B,, = U.Let M = n” Mci;then M is a neighborhood of 1 in
i-1
i-1
G, satisfying (2.5). Since the function (g,c)l-.$[g-lC)is continuous, this function is uniformly continuous on the compact set N x U. So there exists a neighborhood L of 1 in C, such that Il$(g-1C)-$(t;)ll.,<E/(4Clse’1), f o r g e L and C E U. (2.7) Since I1 II 5 II I\-, we get
217
PRINCIPAL CONTINUOUS SERIES
~~~(g-'C)-~(c)ll<&/(4CIRea1), f o r g e L and C E U.
(2.8)
Let W = N n M n L (a neighborhood of 1 in G). If g s W, then, by (2.1), (2.2), (2.4), (2.5) and (2.8), we have
II V,j.Y-fll s II V,j* Y-
V,'* *#I1
+ llvj~a(g-lY C ) K C ) -
+ Ilv'* "g-',
C)qW1C)
- Wg-l, C)KC)II
#(C>ll+ 119-fll
- CIReal+l/a Ilf-~II+C!Realll~(g-lc)-KC~ll+Maxlv~~*(g-l, 5 0- 11 11dI C*U
+Ilf-411
<44+ &/4+ &I4+ €14=E . Hence VJ.' is strongly continuous at 1. Now let go E G and consider
II V,,r*'f- V,'* Yll = II V,,J*Tf- V170-'Pj'Y)ll 5 C({go})'Rer'+I'4 Ilf- V,o-ld.Yll * If g is in goW, where W is the neighborhood of 1 obtained above, then go-lg E W,-so ]If- Vg0-1,j~ 'fll < E , and we get
IIV,,J.'f- V*j*yll
(2.9)
€2
which shows that Visais strongly continuous at go. 3) Since d(gC)=e-f(g.C) dC (Proposition 2.1) and t(1, C)=O (Proposition 1.5), we have, f o r f s 8,
e-sReWo-l.
oF)-tCu. c)I f(c)l'dc
=~;G'R~~-L)I(L% C)lf(,")lsdc,
Since any non-negative function $ in L1(U) can be written as &)= If(C)ll for somefe L2(U),and any function in L1(U)is a linear combination of non-negative functions in L1(U),we have the following equivalences :
IIV,'*YIl=IIfll
for a l l f s L 2 ( U )and g e G
r
(by (2.10) below) ee(*Re*-1)t(g*
c)=
1 for almost all 5 E U and g E G- K.
218
UNITARY REPRESENTATION OF SL(2,R)
(Note that the dual space of L1is the space of essentially bounded, measurable functions.) Moreover, we have that the last condition holds -(2Res-l)t(g, C)=O for all C E UandgEG-K -2Res= 1. This equivalence, together with 2), shows that V'.' is a unitary representation of G if and only if Re s= 1/2. We have (2.10)
t(g,C)=OforallCEUogEK. In fact, if g E K , then t(g, C)=O is clear from the definition of t(g, c). Conversely, suppose t(g, C) = O for all C =eie E U for an element g=
[z i]
in SU(1, 1). Then by (1.14), we have
for all 8 E R . Putting e = O andnin(*), we get la+fi12=I-a+p13 andhence Re(aB=O. [ aet0 + 8 1 2 =ett(g. 8) = 1
(*)
Putting
e=- 2R
and
--n2
in (*), we get lia+fila=[-ia+p[z and hence
+
Im(aS>=0. Therefore we have afl= 0. Since la[a = 1 [ p[a 2 1, we can conclude that ,8 =0 and g E K. From (2.10) it also follows that V&* is a unitary operator for any k E K. 4) We have (V,,@j. a f p ) (c) =e-rt(ue-', c) (u(ue-', c))aYP(ue-lc). Since ue-l E K, from the Iwasawa decomposition we have t(ue-l, c) =O. From the definition of the function u, we have u(ue-l, c)=ede'2. Further-
ac+p we get ue-lc=e-tec. Putting this in the right more, from g.c=----pc+a member of the relation above, we get (V,,j*.S,)(0= e j f e + p r e ~ - p = x P + j ( u e l f P ( C ) . Definition 1. The set of unitary representations 1 1 {Vj.a(j=O,-; s ~ C , R e s = - } 2 2 is called the principal continuous series. The subset { Vo,t+i2117 E R} forms E R} forms subseries called the first series, and the subset {V***+t21R subseries called the second series. To study the irreducibility of the representation W a ,we introduce a representation (Vj*a)'=dVj.*of the Lie algebra g of G which can be obis a generalization tained by differentiating W The representation of the differential representation U' of the finite-dimensionalrepresentation U defined in Ch. 11, $5. However for an infinite-dimensional representation V " s 8 , the derivative dVj*a(X) =(dVe,,r,j.*/dt)t,o is an un#.
PRINCIPAL CONTINUOUS SERIES
219
bounded operator and its domain cannot be the whole space 8.Hence it is necessary to introduce a sufficiently large subspace of 4 which will be contained in the intersection of the domains of the operators dVj*'(X) for all X E g. Several subspaces of 8 are suggested as the representation space of dVj.'. We use the space of differentiable vectors. Definition 2. Let U be a strongly continuous representation of a Lie group G by bounded operators on a Banach space H. Such a representation is called a Banach representations. A vector v in H i s called a dr;trerentiable vector or a C"-vector if the mapping gHU,v is a C"-mapping on G with values in H. Proposition 2.3. The space H, of C"-vectors for U is invariant under
U, for any g E G and under U,=
So
f(g)U,dg for any complex valued
C"-function f with compact support. Proof. Let go E G. Then the mapping g H U,V,,v is the composition of the right translation gt+ggo and the mapping v" :gHU,v. Hence if v is a Cm-vector,then U,,v is also a C"-vector. Iff is a C"-function on G with the compact support C, then (2.1 1)
g H u g u f v = J f ( g o ) U , ~ , ,v dgo
is a C"-function on G . In fact, gHU,U,,v is a C"-function by the first half of the proposition and f is integrable on C, hence, (2.11) can be differq.e.d. entiated arbitrarily many times and is a C"-function on G. Definition 3. Let U be a Banach representation of a (linear) Lie group G on the space H. Then for any X E g (the Lie algebra of G) and v E H, (the space of C"-vectors for U ) , a linear mapping U ' ( X ) = d U ( X ) of H , into H i s defined by d (2.12) U'(X)v= [-dt u e x p txvlt-0. Since the mapping tHUexpt x v is a C"-mapping of R into H, the derivative in (2.12) exists. Clearly U ' ( X ) is a linear mapping of H, into H. As the following Proposition 2.4 will show that the mapping XI+ U ' ( X ) is a representation of the Lie algebra g of G on H,, the representation U' of G is called the dzferential representation of U and is denoted by U' or dU. The representation U' of the Lie algebra g may be uniquely extended to a representation of the universal enveloping algebra U(g) of Q. The extended representation of U(g) is also denoted by U' or dU.
220
UNITARY REPRESENTATION OF
SL(2,R)
Proposition 2.4. U'(X), defined by (2.12), is a linear transformation on H,, i.e. U'(X)H,cH,. Moreover U' is a representation of the Lie algebra g on H,. Proof. Let v E H,. Then 9 :gHU,v is a Cm-function.Since the mapping p : (g, t ) n g exp tXis a C"-mapping from G x R into G, it follows that the composed function 9 =v" p and its partial derivative a9/at(g, 0) = U,U'(X)v are C"-functions. Hence we have proved that U'(X)H,c H, for any XE g. Now we prove that U' is a Lie algebra homomorphism of g into gI (H,). Let XI, .., Xnbe a basis of g and v be an element of H, Put U,= U(g) to avoid complicated suffices, and put 0
.
.
n
p(t) = p(ti,
..., tn) = U(exp CtJt)v. $=I
Then p is a C"-function on Rn and
%O)
(2.13)
atr
= U'(Xf)V.
n
Let X=
1t&.
Then we have
f-I
f-1
by (2.13). We have proved that U' is a linear mapping of g into gI(H,). In particular, for any fixed v E H,, the mapping XHU'(X)V is a C"mapping of g into H. Now we prove that U' preserves the Lie product. Let X and Y be elements in g and x(t)=exp tX. Since the differential representation of the adjoint representation Ad (Adg :XHgXg-') of G is the adjoint representation ad (ad X : Yt+[X, y1) of g (cf. Ch. 11, $5, Example 4), we have (2.15) Ad (exp t X ) =exp (t ad X ) (Ch. 11, Proposition 5.9). We see that for any v E H,, d W A d g ) W = LxU(exp(t(Ad g) Y))VI~.=O
PRINCIPAL CONTINUOUS SERIES
d =[,U(g)U(exp
and (2.16)
221
tY)U(g)-lv]r=~= UgU'(Y)U,-l v
[ U'(X), U'(Y)]v=(U'(X)U'(Y) - U'(Y )U'(x))v
d =[-U2~t~U'(Y)U2(-t)vlt=o dt
d =[xU'((Ad x(t))Y)v]t-o. By (2.15), we have (Ad x(t))Y= Y + t [ X , Y J + O ( t a )
(t+O).
Hence t-' { U'((Ad x(t))Y)v- U'( Y)v) = U'([X, Y])v+ U'(O(t))v.
Since XI+U'(X)v is continuous, we have lim U'(O(t))v=O.
(2.18)
8.0
(2.16), (2.17) and (2.18) prove that [ U'(X), U'(Y)]v= U'([X, Y])v
and U' is a representation of the Lie algebra g on H,.
q.e.d.
Proposition 2.5. Let Vj.' be the principal series representation of G = SU(1, 1) on the Hilbert space 8 = L a ( U ) . Then the space g = C " ( V ) is a #) (c) = contained in the space 8, of C"-vectors for Vj.a. Put (Vexpcxf~ @(C, t ) for # E 9 and X E g(C E U and t E R). Then the differential repre* is defined by sentation d V d ,a = (Vr**)'(X)of Vf. (2.19)
"m)(0=a@/at(c,0).
(dVj-
Proof. Since the Iwasawa decomposition is an analytic diffeomorphism of G onto K x A x N (Proposition 1.4), et(g,C) and u(g, c)=e'(-g'@+e)'*are C"-functions on G x U. Hence the function Ol(C, g)=(V,j.* #) (c) is a C"function on U x G if q3 E 9.So it is sufficient to prove that if V(c, t ) is a complex-valued C"-function on U x Rn and if the function Tt: t;wV(r;, t ) belongs to 8 for each fixed t E Rn, then the function t w T t is an 8valued C"-function on Rn. Let el =(1,0, .., 0), ,.., en=(0,..., 0, 1) and Put
.
222
UNITARYREPRESENTATION OF SU2,R)
Then by Taylor's theorem, we have
ava c , t, h) =2-'h+c,
t
+o w
for some 0 E (0, 1). Since 7P is a C"-function, for any a>O, there exists an M > 0 such that
;1
%C,
s)l4
M for any c E U and s E [t -a, t +a].
Since IF&, t, h)l6 Mahaif Ihl $ a and lim F&, t, h)=O L-0
for any (C, t),
we can apply Lebesgue's theorem and get
s
limllFn(C,f, h)llz=lim h-0
h*O
27
IF&, t, h)lzdC=O.
Hence the function t-?FPLis differentiable with respect to tk and the derivative is equal to the function &4?F(C, t)/af,. In particular (2.19) is proved. Similarly we can prove aa?Ft/atcat,exists and is equal to c-aa?F(c, t)/at,at, and so on. We see that V t has derivatives of any order and is an 8valued C"-function on U. q.e.d.
where
3) If # E 6-belongs to a closed subspace 8' of 8 which is invariant under V.',then dVx'.*# belongs to 8' for all X E g. 4) We can extend the definition of ~ V ~ . ' ( g) X to E X E gc formally by
PRINCIPAL CONTINUOUS SERIES
dVd.' =dV&'+idVd.', Then we have
223
where Z = A + i B e go, A, B E 8.
dJ'Z'. ' f p =(S + p +j)fp+l, dVz'*'f,= ( s - p -j)fp-iy for Z = X l + i Y and z = X l - i Y . Proof. 1) Let ar=exp tXl, then we have
(2.20)
(Vex,tg,l*J#) (C) =e-Jr(5~-'~c)u(at-l, C)2j#(at-1C)
and Ch-
t
ShT
at =exp tXl =[ s h i
chi]'
We want to differentiate (2.20) with respect to t and set t=O. We first observe that the product of the first two factors of the right member cf (2.20) is equal to &J+j ) r ( 5t - 1,C)
(-
C sh- t
+ch-)Xj. t
2
2
(cf. (1.14) and the definition of u). We have
'
To deal with the third factor of the right
member of (2.20), we first calculate
If we set at-'. C = etB(')and write #(ar-l-C)=f(O(t)), then we have d
1
x#(ar-l-~)
We note, thatf'(e(0))
= (D#) (C).
t-0
=f(e(o))e'(o).
We obtain e'(0) from
d ( ~ ~ ' c ) l r - O = e gie'(O)=i@'(O), @(o) which, combined with the result
224
UNITARY REPRESENTATION OF
SL(2,R)
above, gives us 8 ' ( 0 ) =2i3 . Putting these together, we have
(~v,,,~.B)(c)=o.+s~+(c)+2i(-~)+(c)-~~-c-') c+rl
(09)(0,
giving the first formula in 1). If we replace the at above by
and make the corresponding changes all the way through, then we arrive at the second formula of 1). 2) To obtain the results in 2), we apply 1) to =fp and use
Cfm
+
=fp-l(C),
m P t r )
c-YP(c) =fP+l(C), =
- @fP(C).
3) If # E 8- n @', then t-l(Vexp t X j s * # - #) belongs to 8'. Therefore, the strong limit lim t-l( Vex,t x j * - +)=dVxjS8# t.0
+
belongs to 8'. 4) Obvious. LEMMA 1. Every element g in G = S U ( l , 1) or Go=SL(2, R) can be written as follows: g= ucatu+. Proof. Since G is isomorphic to Go, it suffices to prove the lemma for the group Go. Let g be an element in Go, and P be the set of all positive definite real symmetric matrices of order 2. Then Igg belongs to P.So there exists an element p in P such that 'gg=pa. Let u=gp-'. Then we have $uu=p-ltggp-'= 1, i.e., u is an orthogonal matrix. Since detg= 1, we have detp = detu= 1, i.e., p, u E Go= SL(2, R). Since p E P n Go, there exists a v E SO(2) =K such that p = v-latv for some t. Since the elements uv-l and v in K can be written as uv-l = u+ and v = u+, we have g= uv-latv= u+atu+. q.e.d. Remark. Concerning a direct proof for the group G and the uniqueness of the expression for g, see Proposition 5.2.
Theorem 2.1 1 1 1 1) If Re s =- and (j,s) # (- -), then Vjl is an irreducible unitary repre2 27 2 sentation of G.
225
PRINCIPAL CONTINUOUS SERIES
2) Let $3' (resp. 8-) be the closed subspace of 8 spanned by { fp I p r o ) (resp. { fp I p
Proof. 1) By Proposition 2.2, if Res=-, then Vjs a is a unitary represen2 tation of G. Let K be, as before, the maximal compact subgroup of G given
Eefs,#ElI
by K = [ u ~ =
0 5 0 <4z}. The restriction Wj.a = Vj,* I K of
the unitary representation VJt8to K is decomposed into a direct sum of irreducible representations (cf. Ch. I. Theorem 3.1 .) and any irreducible for some p E 212. unitary representation of K is given by xp(ue)= Actually, we have seen in Proposition 2.2, 4) that Vue'*'f,=xn+j(ueYn, wherefn(C)= C-",
n E 2. Since [fn I n E Z } is a complete orthogonal system of functions in .ij= L2(U,dC) (cf. Ch. I. Theorem 3.3 and Theorem 4.1), we have WJ*'=V'*' I K = exn+,. n.8
Let 8' be any non-zero, closed subspace of .ijinvariant under P**. We shall show that 8' contains at least one fn. Since Wj.*I &'= there is an f E 8' (f#O), such that Vuef.'f(C)=
xn+j(ue)f(C)
@
xn+j, nrAc2
=erns+*jef(C).
Since Vuejva f ( c ) = l e * @ l a l - s ( * + j ) (efela)Xff(e-*@c) =e*j@f(e-*@c), we have
f(e-'")
= e'"@f(C)
for almost all C.
Hence we have
f=cfn for some c E C. Hence,f, E 8' n 9.We now note (Proposition 2.6, 4)), that (2.21)
V d *yn +n +j)fn+i, {ddV$*"f,=(s-n-j)f,-i, =( S
belong to 8' (Proposition 2.6, 3)).
and dV&% and dV$% 1) If we assume Res=-
(2.22)
1
2
t
and (j,s)#(-
1 1 -), then we see that
2' 2
(s+n + j ) # 0, (s-n - j ) # 0.
1 andj=O, 2 E 8'. Repeating so again (2.22) is clear. From (2.21) and (2.22) we the argument we get fn*S E a', and so on and we have, finally, fp E 8' for
In fact, if ImszO, (2.22) is clear, while if Ims=O, then s=-
226 all p
UNITARY REPRESENTATION OF E 2.Hence,
1 2) If (j,s)= (?
8’=Q and
Vj.
SL(2,R)
1 1 is irreducible if (j, s) # (- -). 2’ 2
y1),then (2.21) becomes
’* lllfn =(1 +n)fn+i,
If
llz,llafn
= -nfn-l.
This shows, that 8’ n 8- is invariant under dVz1Ia.lIaand d V ~ ~ l ’ *hence ~l’, and dV+ I f a . Since V,,j.”f,= xp+j(ul)fp,Q* invariant under dVXllla*lla is invariant under VVej* ‘. Since @*n Q- is invariant under ~ V X ~ we ~ ~ ~ * ~ ‘ see that Q* is invariant under VexptX1lla,lla= Vat 1fa,112. (This fact is proved by Proposition 6.9 and Proposition 6.11 below). Furthermore and any g E G can be written in the form since Q* is invariant by VUeJ.* g=ulutu+ (Lemma l), we see that Q’ is invariant under VO1l*,lla for every g E G. If Q’is any non-zero closed invariant subspace of @+ (resp. Q-), then, as in l), there is some fn E Q’,n r O (resp. n
q.e.d.
Now we may characterize the representation Vj**from a general stand) the unitary representation of G=SU(l, 1) inpoint. Vj.8 ( s = & + i ~is duced by a one-dimensional unitary representation of the minimal parabolic subgroup r =Z A N of G . Definition 4. Let g be a Lie algebra. Define Wkg(k=1,2, 3, ...) by W1g= rg, s3, w 3= [ * ? 3 , gl. A Lie algebra g is said to be nilpotent, if there is some k E N,such that
.
%=g = {O} Let g be a Lie algebra. A subalgebra Jj of g is called a Curtan subalgebra of g if Jj is nilpotent and the normalizer n(!j)= { X Eg I [ X , Jj] c !j} of lj
is equal to 8. Let G be a connected semi-simple Lie group and g its Lie algebra. If Jj is a Cartan subalgebra of g, then the subgroup H defined by
H = {g E G 1 (Adg)X= X for all XE Ij] is called the Cartan subgroup of G corresponding to Jj. The Cartan subgroup H has Lie algebra lj and is not necessarily connected. Let Ij,!j’ (resp. H,H‘) be two Cartan subalgebras (resp. subgroups) of g (resp. G). Then $(resp. H) is said to be conjugate to J$’(resp. H ’ ) , if there exists an element g in G such that (Adg)E]=!j’ (resp. gHg-l=H’).
227
PRINCIPAL CONTINUOUS SERIES
Proposition 2.7.
Let G=SU(l, 1) and g = l u ( l , 1).
1'
1) Let Xl=z[l 1 0 0] 1 and Xo=-!-[i 2 0 -i
and let
Q1=RXl and Q s = R X o .
Then Q1 and Qs are Cartan subalgebras of g. 2) Let Hi be the Cartan subgroup of G corresponding to rjr(i= 1,2). Then H i = Z A , Ha=K, where Z = { k l}, and A = {at) and K = {u8) are the subgroups of G appearing in the Iwasawa decomposition KAN of G (cf. Proposition 1.2). 3) Every Cartan subalgebra [resp. subgroup] of g[resp. GI is conjugate to either QI or Qa [resp. Hl or Ha].The Cartan subalgebras [resp. subgroups] Q1 and Qa [resp. Hl and H2] are not conjugate. Proof. 1) Since Qi is 1-dimensional, Q, is abelian, hence nilpotent (i= 1,2). By the isomorphism eK(2, R ) ~ l u ( l 1) , (cf. Proposition 1.6), Q, can be identified with the subalgebra { H =
[:
-1131
U E
R} of H(2, R).
~
E SI(2, R). Then, for H E Q1, we have [H, XI=
, so [H, XI E q1 ( H # O ) o x l a = x a l = O o X E Q1, and we
-b X , l have tt(Ql)=rjl.
Hence ljl is a Cartan subalgebra. Similarly,
identified with the subalgebra { H =
[-5: t] I
X is as above and H E Q2 we have [H, XI=
U E R}
can be
of lK(2, R). Then if
VXa1
-2ax11
1
-a(x1a+xa1) ' and we have n(ljn)=
-22aX11 +xla)
so [H, x] E Qa(H#O)axll=O and x12= - x X a l o X eQa,
Qa
Hence Qa is a Cartan subalgebra. 2) By the isomorphism SL(2, R ) z S U ( l , 1) (cf. Proposition 1.6), we consider H I as being contained in SL(2, R) and Q17 in lK(2, R). For g E SL (2, R), we have Qa.
g E HI- (Adg)H= H for all H E Q l
o g H = Hg for all H E Q1 e g = [ "0 Since A = (at=[:I2
"1
u-1
for some a E R - (0).
e-t:]}, the latter condition holds if and only it
g E ZA. For the case of Ha (considered as being in SU(1, I)), we let g E SU(1, 1) and observe, as before, that g E H z o ( A d g ) H = H for all H E rjaagH=
228
UNITARY RHPRESENTATION OF
SL(2,R)
3) If Q and Q' are two Cartan subalgebras of g and H and H' are the wrresponding Cartan subgroups of G, then we have, for g E G,
(Adg)Q =kj'*gHg-l= H' So it suffices to prove the statements in 3) for the Lie algebra g . Identify g with GI(2, R). First we shall show that a Cartan subalgebra Q of g must have dimension 1. Let { H , X , Y ) be the base of g given by
Then we have [H, E]=2E, [H, I;]= -2F, [E, F]=H, so that W g = [ g , g] = g, which shows that g is not nilpotent. Hence dim Q
and there is some g E SL(2, R ) , such that gXg-l=
-3;
thus we
have gIjg-'= I j l = R X I . (ii) a=ci, b = -ci, c E R , c#O. In this case there is a g E SL(2, R ) , such that gXg-l=
["- G],
SO
gIjg-l= Qa =RXo.
(iii) a=b=O. In this case, there is a g E SL(2, R ) , such that gXg-1=
[:
i],
for H =
so gQg-'= 8' where Jj'=RX2,X2=
['0
-1
"1
i].
But Ij'#n(fj'), because
we have [H, X3]=2X2,so that H E n(Ij'). Hence fj' is not
a Cartan subalgebra, and so neither is Q =g-lJj'g.
229
PRINCIPAL CONTINUOUS SERIES
It is clear that a real matrix of the type appearing in case (i) cannot be conjugate in SL(2, R ) to a real matrix of the type appearing in case (ii), hence fil and 6%are not conjugate. q.e.d.
COROLLARY to Proposition 2.7. Every Cartan subalgebra of g= H(2, R)E h ( l , 1) is a maximal abelian subalgebra consisting of diagonalizable (i.e., semi-simple) matrices. Remark 1. The converse of this Corollary is also true. Remark 2. Every semi-simple element g e G is contained in a conjugate of Hl in G or a conjugate of Ha in G, that is, every semi-simple element of G is contained in a Cartan subgroup of G. The union of all Cartan subgroups of G (=the set of all semi-simple elements of G) is an open and dense subset in G. In fact if g E G is not semi-simple, then the eigenvalues of g are equal, so g E {h E GlTrh = f2). (cf. Proposition 7.8). Proposition 2.8. The set Z?< of all irreducible unitary representations of H&= 1,2) is given as follows: 1 f i =~ *'Z{ u(zat)= xj(z)eiv' Ij = 0 , ; Y ~E R } ,
where j(z) =zaj for z E { f I}.
KL= { I , I j E 2/21, where x,(us) =eve. Proof. 1) We have H2= {us=
Lie''
"I
e-is,l
I O S O < ~ The ~ } .mapf:
B + ~ ~ Z +is Uan~isomorphism from R/4& onto K=H,, and the map g : ?+Z + 4 ~ ? + 4 x Zis an isomorphism from T = R / Z onto Rl4r2, so we have the composition of isomorphisms
TARI f ~~z-H~. It was proved in Ch. I, Theorem 4.2 that f = { ~ ~ ( f + Z ) = eI n~E~Z}. ("~ Thus we obtain I%= {unog-lof-l I n E Z } so we can write But (unOg-lof-l)(us)=un((B/4x) 2)=eSnbfa =
.
+
fi2=
{x,
ljE
2/21.
2) Since Hl is abelian, every irreducible unitary representation of H I is I-dimensional. Since H l = Z x A, we have 1
f i l = 2 x i f = { x , I j = 0 , - } x {at++e*Y*IV E R } , 2 because A s R and hence i f s & ~ R .
q.e.d,
230
UNITARY REPRESENTATION OF
SL(2,R)
Let G =KAN be the Iwasawa decomposition of G = SL(2, R ) z SU(1,l) and let r = Z A N , where Z = { k l } , and U={CECI ICl=l}. Weidentify the three manifolds G/roK/ZxU
by means of the diffeomorphisms grwueZwe‘e= C,
where g=ue at ne. Recall that K = {
[t’’’
e-t8:]
I 05 0 <4a}
and that
the homomorphism uswe‘efrom K onto U has kernel Z . Proposition 2.9. 1) Let of Hl = Z A defined by
11.”
be the irreducible unitary representation
1 Ij*y(zat)=xj(z)e*ut ( j = O , -; 2
Y
ER).
Let Lj.” be the function on r =ZAN defined by N). Then Lj.’ is an irreducible unitary representation of r. 2) We can extend LjsUto a function on G by putting = xr(ue)L f *.(we). Ljs Y(uoatne) (2.23) The extended function LjSy satisfies Lj.y(gh)=Lj.y(g)LjSv(h) for all g e G, h e r . Lj*qhx)=lj*qh)( h E H 1 , X
E
Proof. 1) The first part of this proposition is almost evident. In fact, N is a normal subgroup of r and we have r / N z Z A = Hl. Ifp is the natural map from r to r / N , then L 5 . ~ = l j o. ~p is a unitary representation of r, and it is irreducible because ljv’ is irreducible (in fact 1-dimensional). 2) Let h=zb, where z E 2, b E AN, and g = ueatncthen Lj.u(gh)=Lj*y(uoatnczb) =Ljsv (uezatnpb) = xj(ueZ) Lj**(atnEb) =xj(uo) Xj(z) LjS’(atnc) LjSu(b) =L’*’(ueatnp)LjSu (zb)=Lj*’(g)Lj.’(h).
q.e.d.
Let L,I be the measure on U defined by dp(C)=dy=de/2a (C=e*e). The Jacobian of the transformation CwgC is equal to e-“V*C) (Proposition 2.1). We have, therefore,
PRINCIPAL CONTINUOUS SERIES
23 1
where the left-member is a Radon-Nikodym derivative. The measure g p on U defined by (A is a Bore1 set in V) ( g p ) (A)=p(g-’A) is absolutely continuous with respect to p . Hence p is a quasi-invariant measure on U with respect to the action of G. The induced unitary representation ULj.yon the Hilbert space Q(Lj.y) is defined as follows (cf. Ch. IV, $1): is the set of all functions f on G satisfying The Hilbert space Q(Lj.#) l), 2) and 3): 1) f :G-X is measurable. 2) f(gh) =Ljlu(h)-lf(g) for all g E G and h E r.
3) / ; f ( g ) ] ’ d c c co (where c = g r E G / r = U). From 2) we have If(gh)l= If(g)l for g E G,h E r. It is clear that Q(L’*”) is a Hilbert space with inner product
The induced representation ULjPyon Q(Lj.v)is now defined by setting, w), forfe Q(LJ.
-
( UOL’.yf)(g1)=(~p(g-’g1)/dp(E))+ f(g-lg1)
-e-t(Q-l.C)IZf(g-lgl), where C = g J . We can check easily that ULjsuis a unitary representation of G. For anyf E @(L’*y) we definefi by (2.24) Thenfi satisfies (2.25) In fact we have
f i ( g )=~ ’ W f ( d .
fi(gh) = f i ( g ) for all g E G,h E r. fi(gh)=L ’ ” ( g ~ l f ( d 4 =V * ’ ( g )L’. h) L’, h)-’f(g) p(
y(
f ( g )=fiw So fi is actually a function on G / r = U.Let =L’.W
(2.26) d c ) = f i W =L’*’(glf(g)7 where C = g r E U = G / r . Then the mapping (2.27) A :f t . 4 is an isometry from @(Lj..) onto @=L’(U, dc). In fact, since
1$(c)l2=
232
UNITARY REPRESENTATION OF SL(2,R )
Ifk)tP,we have ll$ll'=[
U ig(C)PdC=/ U If(g)l'~C=IlfII'.
Hence A is an isometry of $j(LjlY)into 8 =La(U,dc). Let $ be an arbitrary element in 8 and put f(g) =Lj.'(g)-l$(c) for = g r . Then it is easily seen that f belongs to $j(L'.y) and $ =A$ Therefore A is an isometry of 8(Lj.') onto 8 =La(U,dc).
Proposition 2.11. 1) Let M be the centralizer of A in K and MI the normalizer of A in K. Then we have M = {+1} =z,M1= {uelO=O, z, 2%327).
2) u,utu*-l= Q-t. 3) Let W =M1/M= { 1, w } (w' = 1, w =u.M( = us.M)) and let r'r.~(h)=z'.~(h")=zj.~(u.hu.-l) ( h E Hl).
PRINCXPAL CONTXNUOUS SERIES
233
Then we have 1'1,
=11.-u
.
Proof. 1) By definition we have M = { U s E K 1 u8aub-l = a for all a E A}, MI= {Us E K 1 usdus-'=A). We calculate the product uratue-' and obtain (2.30) t
=[::h 2 l We now see that, for 0 5 e <4r, we have U s E Meusatus-' =at for all t E R e e f @ = 1e B =0, 2 x and U s E MloFor each t E R , there is some t ' E R such that u,atu-l=at, e e i @ = fl d = o , K, 2 ~3, ~ , hence the first assertion of the proposition is proved. 2) Putting e = K in (2.30), we get u. at u,-l=a-:. 3) The final assertion follows from /'J**(za,) =lj. U(u.zatu.-') =Zj.'(za-t) (by 2)) = Xj(z)e-"' =1'. -'(zat). Theorem 2.2.
If Res-i, then we have VA a g vj. 1-8.
Proof. Since Vj*++'uz UL'.' by Proposition 2.10. It sufiices to prove that u L j v w uLj.-u. Let $ E $j(LjSy)and let f= Bq5 be defined by f(g) =(4) (g) =L'."(U.)$(g)-
Then f belongs to Q(U.-'). In fact we can show that f satisfies the three conditions for a function on G to be in $(Lj.-') as follows: 1) It is clear that f is a measurable mapping from G to C.
234
UNITARY REPRESENTATION OF
SL(2,R)
2) For every g E G , h E H and n E N,we have f(ghn)=L~*’(u.)(b(ghn> =Lj. qu,)Ljqvz)-’ 4(g) =Lj.qu.)Lj.*(h)-’Lj.u(u*)-’Lj.Y(u.)4(g) =l j *quXhux-1)-’f(g)
(by Proposition 2.11)
=Z j p -*( h)-’f(g) =Lj*-”
(hn)-lf(g).
3) Since IU+(u.)l= 1 we have If(g)l= l@(g)land
Moreover, from this it is apparent that B : (b+f is an isometry of 8(Lj.”)onto Q(LJ.-y).F o r f s Q(LJ*-’),let B-’f=(b( E Q(Lj.y)).Then ( B UgLJsyB-lf) (gi)=Lj*’(u.) (UgL’*”$) (gl)
Proposition 2.12. The representation Vj,‘(s E C ) defines a representation of the proper Lorentz group G+(2)if and only if j = O . Proof. Since G+(2)E G/ { rt l } (Proposition 1 4 , Vjs8 defines a representation of G+(2) if and only if Vj.’( - 1) = 1. Note that - 1 =ua.. By Proposition 2.2,4) we have V d :fp Hence we have
=
xP+ j(udfp, where .fp(C) = C - p ( ~ E 2)
Vj.*(- 1)= loX,+j(uax)=1 for all p
EZ
(using x,,(ub)=e‘”‘) e e a j “ (= 1
oj=O,
because j = O or
-.21
235
PRINCIPAL DISCRETE SERIES
53. Irreducible unitary representations 11. PRINCIPAL DISCRETE SERIES 1 Let n E 32.Then
is an irreducible unitary representation of K=Ha. xR can be extended to a (rational) holomorphic representation of K C=
bY
Proposition 3.1. The group G=SU(l, 1) acts on the unit disc D =
{c E C I IcI < 1) by the linear fractional transformations c-gc=- ac+p
where g = [ " E G. /3c+a' B E The action of G on D is transitive. The isotropy subgroup of G at 0 is equal to K. By the canonical mapping f : g K e g 0 , GIK is homeomorphic to D . Proof. Let C + be the upper half-plane and c the Cayley transformation z-i c : ZH-, which transforms C + onto D . We have seen in Proposition Z+l
1.6 that SU(1, 1)= CSL(2, R)C-l, where C = -
A[:
-:I.
We can
check easily that the following diagram commutes: g
D -D
Tc c+-c+
CT
g'
where g'= C-lgC (g E SU(1, 1)).
Hence g D = D (gE G=SU(l, 1)) followsfromg'.C+=C+(g'ESL(2,R)). and the latter can be checked by direct calculation: Let z = x + i y (y>O) and g ' = E
f;]E SL(2, R).Then
Y Im gz =Im- az+b = cz+ d (cx +d)a+ caya The transitivity of G=SU(l, 1) on D follows from the transitivity of
236
UNITARY REPRESENTATION OF
SL(2,R)
SL(2,R) on C+. In fact, the subgroup AN=
acts in simply transitive fashion on C+, as can be seen from the following calculation:
.
1=--
For g =
["
"1
ai+b -ab a-l
+ia'.
E G, we have g0 =,;B and therefore
B a
g*O=O*,9=O*gE K: Let p : G-+G/Kbe the canonical projection. It is continuous and open. Let @ : G-D be the continuous map defined by qj :g w g . 0 . Since G is locally compact and has a countable base, and since D is a locally compact HausdorfTspace, @ is open (we use Baire's category theorem to show this). Sincefis 1 :1 andf=@op-',fis a homeomorphism from G/Konto D.
Proposition 3.2. Let g =
i]
E G,
C E D, and J(g, C)=jC+a. Then
1 ) J is an automorphic factor, i.e., C)=J(gi, a < ) J(ga, C) and
{J(1, c)= 1 J h i ,
hold. In particular, J&', gCF'
=Jk, C) z 0.
2) 1% C)P (1-lgCl')=1-ICl2. 3) Let C =x iy and let dm(C)=h ( x , y) =&dy. Then d,1(4)=U ( x , y ) = ( 1 lCli)-2 h ( x , y) is a measure on D invariant under G.
-
+
J(1, C)= 1 is clear from the definition, and the rest of 1 ) follows easily. 2) We have
PRINCIPAL DISCFLElT SERIES
237
ax’ ay‘ a ( ~ ’y’) , - ax a(x,y)
ax’ ar
ax
aY
1 1) Let n E -2 and
Proposition 3.3.
2
(using the Cauchy-Riemann equations)
nr 1. Then
is a Hilbert space and 1 E sn, 11111= 1. Every bounded measurable function f on D belongs to 9,and satisfies
I l fII4 1 1 1 1 1 . where
II f II,=ess sup If(C)l. LrD
2) For any g E G, we define the operator Tanon 9% by
(Tan@)(C) =J(g,-’, C)-’”@(g-’C)
where g - l = g
on 9 n Proof.
i].Then T n
:g H T a n is a unitary representation of G
1) Since p,is ,an La-spacewith respect to the positive measure
238
UNITARY REPRESENTATION OF SL(2,R)
2n- 1 d m n ( C ) = x ( 1 - IC1s)2"-adm(C)on D ,
of 1 in
Z
n
is a Hilbert space. The norm
is equal to 1 because
(3.1)
=(2n-1)
s:
(l-f)a"-adt=l.
Therefore, the constant 1 belongs to 9 , By . (3.1), every bounded measurable function f on D satisfies
Using Proposition 3.2, l), the latter expression becomes
which by Proposition 3.2, 2) and 3) becomes
= IlW.
Thus, each operator T," is an isometry. Furthermore, we have (Tglgan
0)(C) =J((g1gJ-1L)-2m @((gig&10 =J(ga-', gi-lC)-amJ(gi-l, C)-an@,(ga-lgi-lC) =J(g1-1, C)-an (Toan0)(g1-'C) = T,,"
V9an
@I(C).
In particular, an isometry T," is invertible and hence a unitary operator. If the mapping T n :gHT gnis strongly continuous, then T" is a unitary representation of G on 2". Now we shall prove the strong continuity of T". In virtue of the equality
11 Thgn f- Th"f l l = IIr g n f - f k it suffices to prove strong continuity at g=1, i.e., to prove that for any f E p,, and E >0, there exists a neighborhood W of 1 in G such that the
239
PRINCIPAL DISCRETE SERIES
inequality
IITLlnf-fll< 6
(3.2)
holds for all g E W. Iff =0, then (3.2) is trivial. So we can and shall assume that f +0. Since dm,(C) is a Radon measure on the locally compact space D , the set L ( D ) of all continuous functions on D with compact supports (cf. Appendix D.5).Therefore, there exists a function # is dense in p,, in L(D) satisfying
Ilf- $11 < min(llfll9 43). (3.3) (3.3) implies, in particular, that #+O. Let L be a compact neighborhood of 1 in G. Since J(g-', I)-an is a continuous function of (g, t;) on L x D , there exists a constant M>O such that IJ(g-l, t;)1-an5MMoreover, since J(g-', <)-an and #(g-l t;) are uniformly continuous functions of (g, c) on the compact set L x L-'C, where C is the support of #, there exists a neighborhood W of 1 in G contained in L such that the inequalities (3.4)
(3.5)
IJ(g-l, Wan- 11<(6ll#ll=)-'e
and (3.6) l#(g-lc)- #(C)l<(6M)-le hold for all g E W and r; E C. Then we have for all g E W and C E C, [(To"#) (C)-#(C)l=
IJ(g-', C)-an#(g-lC)-#(C)I
s; I Jk-', t;)l-anl#(g-lc)- d C ) l
+ I J(g-',
Y - 1ll#(C)l
C
< M E + E II#II-=<, i.e., 6M 611#11= (3.7) IIT.J"#- 411-43. By Proposition 3.3, 1) and (3.7), we have (3.8) IIT,"# -#I] < ~ / 3 for all g E W. Since T," is a unitary operator, we get, by (3.3) and (3.8), IIT,nY--fl16 IIT~"f-T,"~ll+IIT~"#-#II+II#-fll <€13+€I3 4- €13= c for all gtz W. Thus we have proved the strong continuity of T".
q.e.d.
22-1
The representation Tn of G on e n = L a ( D ,-(1- Irla)a"-a dm(C)) R
is not irreducible. In what follows, we shall show that
an=[fe pnlf
240
UNITARY REPRESENTATION OF
Sq2,R)
is holomorphic on D } is a closed subspace of pn and that the restriction U" of Tnto anis an irreducible unitary representation of G.
Proposition 3.4. I) Let f be a holomorphic function on D = {C E Cl I ~ l < l )and let Z E D and e>O be such that D.(z)= {Cl IC-zl<e) cD. Then f satisfies
2) For any compact subset B of D, there is a constant C(B) >0, such that the inequality
If01s C(B)llfII holds for all f E 8" and all z E B. 3) For each fixed z E D , the map f t-+f(z) is a bounded linear form on
8". 4) &, is a closed subspace of gn. Proof: 1) Expand f into a power series convergent on D.(z):
-
C
~xc)= am(C-zP m-0
and set fm(C) =(c -z)". Then
Hence
The left member is equal to
1
If(C)I1dm(C),
while the right member
D&)
is L laol*llf~ll,~. Since Ilfoll.2=nt' and ao=f(z),we conclude that
2) Let dist(B, aD) =d >0 and let t =d/2>0. Let
B'= ICE CJdist(B,C)Sc}. Then B' is a compact subset of D . For any z E B, D.(z) c B'. Let
PRINCIPAL DISCRETE SERIES
24 1
Then
3) The third assertion is clear from the second. m-om be a sequence in $n converging to f in g n . Then by 2), [fm} ,,, is convergent to some function #(on D) uniformly on every compact subset B in D. Since # is a uniform limit of a sequence of holomorphic functions, q5 is holomorphic on D. We have 4) Let [fm}
# ( I ) =lim fm(C), m-lim Ilfm-fll=O. m-m
Some subsequence {fm,} of Ifm} converges to f almost everywhere. (This fact is contained in the usual proof of the completeness of Ls(D,mn)= gn.) So f and # are equal almost everywhere, and +=fin gn. Hence # E -pn and f=# E Qn. Therefore, Qn is closed in 9%.
Theorem 3.1. LetnE*Z,n>l.Then 1) Q n + 1 EQn 2) Every closed subspace 4 ' 2 {0} of Qn which is invariant under T", contains 1. 3) Let U;= T," IQn be the restriction of Tonto 8.. Then Unis an irreducible unitary representation of G. ProoJ 1) We have seen that 11 1II = 1< Q) ,n 2 1 (Proposition 3.3, 1)). (Remark: If n < l , then 11111'= a.) Hence 1 E $n and Qn # {O}. 2) LetfE 8.. We can write
-
242
UNITARY REPRESENTATION OF
SL(2,R)
in D. We have
Hence we have (3.9)
+-/re'ne(
If f belongs to
then #=-
uZef)(c)cio =a0 =f(o). eine(U&f)d8 also belongs to 4'. In
's"
2K
0
tnek
8k+l-@k , and 2n k since by the invariance of 8' we have U; f E 8' for each k, each such ek sum is also in 8'. Since 8' is a closed subspace of 8, we conclude that the limit of the sum is also in 8'. But $(C;)=f(O)for all f E D, as was shown in (3.9), hence q5 is a constant and # =f(O) E 8'. If 8' # {O], then there is an f E Q', f#O, and there is some point co E D such that f(Co) it 0. Since G acts transitively on D (Proposition 3.1), there is a g E G such that g-l.O=c0. Hence we have fact, # is the limit of the Riemann sumz e
(Uiekf)
( U , " f )(0)=a-znf(g-1.0)=a-2nf(To) #O, where g-l=
CBa :I*
By the invariance of 8' we have U ; f E Q ' ; by what was said above, ( U ; f ) (0) E 8'; and since (U;f)(0) # 0, we conclude that 1 E 8'. 3) Let 8'2 {0} be a closed invariant subspace of 8%.If @'#$jn7 then the orthogonal complement 8" of 8' is not {O} and is a closed invariant subspace of 8".Hence, by 2), 1 E 8' n @'l= {0], a contradiction. q.e.d. 1 Let n E 32, n2 1 and let Qn (resp. 8-n)be the subspace of g,,of holomorphic (resp. antiholomorphic)functions in 9" Let. u be the map from p,, onto itself given by u :~ ITheJmap u is an isometric antilinear Define the operator T;" on 9% by mapping and we have o(Qn)=&. Tpn=u T ; u and the operator U;" on 8 - n by U - ; = u U;(I=T-;18-,,. 1
Theorem 3.2. Let n E -2, n 2 1. Then .Q-" is a closed subspace of sn, 2 which is invariant by T-". U-"is an irreducible unitary representation of G on Q-,,.
PRINCIPAL DISCRETE SERIES
243
Proof. Via the isometry u : Qn-&,, the first assertion follows from Proposition 3.4, 4), and the second assertion follows from Theorem 3.1,
3). 1 2, Definition.1. The set of irreducible unitary representations { UnI n E 7 In1 2 1) is called the discrete series of G.
Then {O; I p E N } (resp. {@ 1 p E N})is a complete orthonormal system n in 8 n (resp. 8 - n ) >
k
2)
i.
(ue)O;
U&@;=X-n-p
( n 2 1, p
CJi:e = X n + p
€
N)
(~g)?
Proof. Let n 2 1. We have
Letting r s = t this becomes (2n- 1) ,&,,q/l(l
-t)2n-s fPdi
0
=6,,,(2n-
1) B(2n- 1, p + 1)
Hence {O; I p E N } is an orthonormal system. The system is complete. In fact, if f ( C )
amCm E Qn is orthogonal to Opn for all p E N , then
= m=O
am=O for
all m E N , and hence f=O. Replacing C P by Q', we can use the same argument to show that p E N } is a complete orthonormal system in &n. 2) We have (Uugn O p n )(c) =e-"e Opn(e-(@C) = e-t(n+p)@ Opn(C) =X-n-p(ue)
(U,,g-n@
@pn(C)
{el
9
(c) =U(e+@ OPn(e-*@C)) =er(n+p)@ (c) =Xn+p(ue)
@(C)
-
1 1) If n, m E -2 and In[,Imlr 1 and n#m, then Unand 2 Urnare not equivalent. Theorem 3.3.
244
UNITARY REPRESENTATION OF SL(2,R)
2) Un is not equivalent to V'.'. 3) YO.' is not equivalent to V1IrJ. Proof.
1
1) Let I E 72, 12 1. Then the sets of weight functions on K
associated to the representations U', U-'of G are respectively A'= { z - i , A-'= { X I ,
x-i-1,
X-1-a,
~ i + i X, I + S ,
...I , ...I .
1 if n, m a - 2 and In!, lml2 1, then U n z U" implies An=A"; but the 2 description of A', A-' above shows that if An =A", then n =m. 2) From Proposition 2.2,4), we know that the set Aj*' of weight functions on K associated to the representation Vf.' of G is
A'*'= { X p + j I p a 21 . Since Aj-*# A', A-l, we conclude that Un is not equivalent to Vj.*. 3) Finally, Ao.*= { x P I ~ 2 1 E is not equal to A 1 f a - c ={ X p + l l l I P E 21, so Yo*'is not equivalent to V1la.t. q.e.d. The representation Tn can be regarded as an induced representation. We I
shall explain this fact. For n E -2,n2 1, 2 pn (ue)=efne gives an irreducible unitary representation of K. By the isomorphism of
,,7-
K onto U ( l ) = { a ~ Clal=l}, l defined by us= Eel8 ef81a, we identify K with U(1). Then pn is the unitary representation of U(1) defined by pn(u)=aXn . pn can be extended to a holomorphic (rational) representation the complexification U(l)c= C* = { z E C I z#O] by putting pnC(z) =ZZ"
pnC
of
.
Let V" be the unitary representation of G induced by the representation pn of K. The representation space g,, of ' Vn is the set of all functions f satisfying the following three conditions. 1) f : G+C is measurable. 2) f ( g k ) = p 4 k ) f ( g ) , for all g E G, k E K. 2n- 1 3 ) 1 1 f 1 1 2 = y / G , KIf(g>l' dR@)< Q),where dR(C)=(l -Kll)-adm(O is the
245
PRINCIPAL DISCRETE SERIES
invariant measure on G / K = D . Then g',, is a Hilbert space with norm given by 3). The representation Vn is given by (VL7o"f 1 ( g ) =f(go-lg),
fE P ' n
Propsition 3.6. The representations V n and Tn are equivalent: Vn E Tn. Proof. 1) Let A :pn-+g',, be the operator defined by (SO)
(A$) (g)=pnc(J(g, O))-l)#
Note that since J(g, C)= jC+ a, for g =
($ E -Yn)*
[- i], we have J ( g , O ) = n E
C*. We want to show that A# =f thus defined is indeed in PI,. Of the three conditions for elements of 1) is clearly satisfied f o r 5 To check 2) we calculate as follows:
f k k ) = p n c ( J ( g k , O))-l $(gkO)
(by Proposition 3.2) = PnC((J(g, WJ(kO))-') #(go) = P*(W PnC(Jk,0))-' #(go) = P.(k)f(t?)
and find that 2) is satisfied. For 3) we calculate again: 2n-1
l l f l l % = ~ [
Ipnc(Jk, fflK
o>-l)l~ I#W)I' dA(g) (gO=E=C E D )
=lI$lP< *. So condition 3) is verified. Furthermore, the above shows that A : g,-. 9'is . an isometry. We shall now show that A g , , = g t n . Letfs g',, and let
fi(d=pnc(J(g, 0 ) ) f k ) . Thenf l is constant on each coset of G modulo K. In fact, f l k k ) = pnC(J(gk, O)lf(gk)= pnc(J(g, kO))pnC(J(k,O))pn(klf(g). Since M) =0, and since J(ue,0) = e-tbla gives pn( J(k, 0)) = p,,(k)-l, we get fi(gk)=fi(g). Hence fi defines a function # on G / K z D by #(go)=
246
UNITARY REPRESENTATION OF s u 2 , R )
Propsition 3.7. The representation U n(I n I 2 1) defines a representation of the Lorentz group G+(2) if and only if n E Z . Proof. U"defines a representation of G+(2) if and only if Un(-1) = 1. We have - 1 = u2* and for n 2 1 Uu2=QPn = e - i ( n + p ) 2 n U&nq
@ n
P
= e-2nnI
@ n
P
= &("+P)Zn p - = elnut P
@:
Hence U n ( - 1) = 1 e n n ~ Z (for In1 2 1).
111. THE LIMITOF DISCRETE SERIES As we saw in 52, the representation V3v3 is the direct sum of two irreducible representations. In this subsection we shall construct these two irreducible representations on the Hardy space H 2 (0). For each holomorphic function f on the unit disc Definition 2. D and real numbers p > 0 and r (0 S r < l ) , put (3.10) Let Hp = H p (0)be the set of all holomorphic functions f: D fying (3.1 1)
MP
-
C satis-
( r , f > IM
for some constant M and for all r E [0, 1) = { r E RIO 5 r < 1 }. Hp is called a Hardy space. We need only H2. H 2 is a Hilbert space as is shown in the following proposition. Proposition 3.8. The following two conditions (a) and (b) for a holomorphic function m
(3.12)
f ( z )=
1anzn n-0
247
LIMIT OF DISCRETE SERIES OD
are mutually equivalent: (a) f = H 2 , (b)
I a, I < + 00. H 2 is a Hilbert
n-0
space with the norm (3.13) n-0
forfas given in (3.12). Let B be the mapping which maps the functionf OD
in (3.12) to the “boundary function”
4 (ele)= 1andhe.Then B is an n-0
isometry from H 2on to the closed subspace $0 of the Hilbert space $ = L2 (U, dp) spanned by {f-p (&) = dPeIp 2 0). Proof. The orthogonality of the family {elnejneNin $ leads to the equality
n-0
Hence M 2(r,f) is a monotone increasing function of r. We have DD
(3.15)
lim M~(r,f12 = rtl
1 Ia, I ’. n-0
Therefore (a) implies (b). We shall prove the converse. Let A be the mapping which sends the function f in (3.12) to the sequence (a,). Then A is a mapping from H 2 into f2 (N). If we define the norm in HZby (3.13), then A is a norm preserving mapping. cu
Conversely let (a,) be a sequence in f2 (N)and put f(z) =
1a j n . n-0
Then, by Schwarz inequality, we have
Thus the power series UJ” converges on D and the convergence is uniform on any disc lzl S p with p < 1. Hencef(z) is holomorphic on D
248
UNITARY REPRESENTATION OF
sL(2,R)
and belongs to H 2 by (3.15). Therefore (b) implies (a). We have proved that (a) is equivalent to (b). Moreover A is an isometric mapping from H 2 onto the Hilbert space l2 (N). So H 2 itself is a Hilbert space with the norm (3.13). Let C be the mapping which maps (a,) in 1’ (N)to
- a, f-. in $
=
“-0
L2 (U)where I.(&B) = e-me. Then C is an isometry from l2 (N) onto the closed subspace &j0-= 0 Cf-.. Hence the mapping B = C 0 A is an isonZN
metry from H 2onto $;. q.e.d. .and @. for each Previously we have defined two Hilbert space 9 1 1 - n 2, ~ n 2 1. But 9, and 8. are defined for each real number n > 2 2. and 4, with a real parameter n > 1 Propositions 3.3 and 3.4 hold for 9 and no alteration of the earlier proof is needed. The following Proposition shows that the Hilbert space HZis the “limit” of the space $r as t tends to 1 2‘ 1y Proposition 3.9. For each real number t > T let $r be the space of all holomorphic functionsf o n D which belong to the Hilbert space Yr= L2 (D, n - l ( 2 t - 1) (1 - IzI 2 ) 2 r - 1 dm(z)). Then $r is a Hilbert space and contains H2. Moreover we have
llfll zr?g llfllr
(3.16)
forf€H2,
llJlll is the norm in H 2 consists of all elements f in fl 8, for t>l/Z which the limit lim l l f l l r exists and is finite. rll/2 Proof. Let PP( z ) = (r(2t + p ) / T (2t) T ( p + l))l?zP forp E Nand t >
where
1 Then { PPI p E N }is a complete orthonormal system in $r (Proposition -
2‘ 3.5.1)). We remark that
(3.17)
r(P
+ 1)r(2t) -
+ p)
P 2t+p-l
-
P-1 2t+p-2
1 . . . -< 2r
Hence a holomorphic function f (z) = c a n t ” in $r satisfies n-0
1.
249
LIMIT OF DISCRETJ2 SERIES 0)
1
I
luR12=
~lfllz
for all t > 1/2.
R-0
Therefore we have
H Zc at
for all t
> 1/2.
Moreover, iffbelongs to HZ, then the series in the right side of (3.18) is convergent. Hence the series in the left side converges uniformly on the range t 2 1/2. Conversely let f b e a function in n $t for which lim l l f l l r exists and is t>1/2
r11/2
finite. Then the inequality
implies
llfllf 2
(3.19)
-
1
1u,12rzp
= M~( r , n z
for r = ( 2 t ) - l / z .
R-0
llfllt exists and is finite thenfbelongs to a2.We have proved that H 2 consists of all elementsfin r,l/f% for which lim Ilfllt exists and r1112 Hence if lim
r1112
is finite.
q.e.d.
Delinition 3. Let C = e'e be a fixed point on the unit circle U and a be a non negative real number less than 7r/2 (0 5 a < 4 2 ) . Then the angular domain A , (0= {re', I 1 arg (1 I < a} is the domain indicated in Fig. 5. Note that /3 = arg (1 - re'(#-e))=
Fig. 5
250
arg
UNITARY REPRESENTATION OF
SL(2,R)
(F)L
Ocz, where z = rer+'. If a function f(z) has a finite
=
limit c when z approaches to a point c on U along a curve in an angular domain A, (0,then c is called the non-tangential limit off at c. Proposition 3.10. 1 ) Let f be a function in H2and 4 = Bf be the ''boundary function" off(cf. Proposition 3.8.). Then f is represented as the Cauchy integral of 4:
(3.20) 2) f is also represented as the Poisson integral of
for any z
= reie E
4:
D ; and
3) f has a non-tangential limit 4 (&r) at almost every point ( = erron the unit circle U. m
C OD
4 (0= anpfor c = e". Since n-0 n-0 4 belongs to L2(U)(Proposition 3.9), 4 belongs to L1(U).For any fixed Proof. 1) Let f ( z ) =
ad". Then
m
Z E D ,(( - z)-l
= zr"C-'"+"
converges uniformly on U.Hence we have
n-0
The integral in the right side of the above equality is the inner product of 4 and f-,, (e'? = elnrin L2( U ) . Hence the expression on the right side of the last equality is equal to the following:
= n-0
wherefn (0= C-" = e-lnr 2) Similarly the series
u#Jn
=f (z),
LIMIT OF DISCRETE SERIES
25 1
converges uniformly on U for a fixed Z E D . We have
Substract (3.22) from (3.20) we get
for z = refe, C = e" and d( = icdt. 3) Sincefis represented by the Poisson integral (3.21),f(rde) has a nontangential limit 4 ( & I ) for almost every t by a well known theorem of Fatou on the Poisson integral. See Appendix G for the proof of Fatou's theorem. q.e.d. Proposition 3.11. 1) Let j = -T, SEC and f E $ = L2 (U).Put
for g-'
=
6:)
E G = SU(1,I).
Then VJo"is a bounded representaion
of G. In particular, if Re s = 1/2, then Vj.' is a unitary representation of G. 2) Put (3.23)
(m(0= Cf(0
Then T is a unitary operator on (3.24)
8.
f o r f a T satisfies
T OV;' = V-l;. o T
for all gEG.
Hence we have (3.24)'
V-1IZ.r - VlIZ,.
for all SEC.
Proof: 1) The proof of 1) is same as that of Proposition 2.2. 2) Since I 61 = 1, T is a unitary operator on $ = L2 (U).We have the equalities
252
UNITARY REF'RESENTATION OF SL(2,R)
= [(V:/z,' o 2")f ] We have proved (3.24) and (3.24)'.
for all g E G .
(0
Remark. The explicit expression of the operator V;1/2,112 is as follows:
P I W ~ W ~3.~ 12.~ O 1) ILet I f~ H Z ,g-' =
:)
E G = SU(1,l) and put
(3.27) Then U:I2f belongs to H 2 and U1t zis a unitary representation of G. 2) Let B be the mapping which sends f E H 2 to its "boundary function" 4 = Bf (cf. Proposition 3.8). Then we have (3.28)
B o U:I2 = V;1/21/2 o B
for a l l g ~ G .
Put S = T 0 B where T is defined by (3.23). Then we have (3.29)
S
o
UiIz = V:/2.1/z 0 S
for all g E G .
The closed subspace 8; of 8 = L2(V)spanned by { f-,(c) = P ' ( p 2 0} is invariant under V-1/2~1/2. The closed subspace 8- spanned by If-,! p > 0 ) is invariant under V1/z*1/2.We have (3.30)
u1/2
v-1/2.1/2
Proof. 1) Put w = g-l
18;;
y1/2.1/2
.z. Then we have
1 - Iw12 = I/Jz
h ( w )=
1/92
I @-.
+ aI-2 (1 - lzl') + h(z)
and
4 - 4
by Proposition 3.2. Since g E G induces a complex analytic automorphism of the unit disc D, U:/2f is holomorphic on D. Moreover U:/2f belongs to n ,fjt along withf. So we have r>ln
LIMIT OF DISCREIE SERIES
(3.31) lim IIU:/2ffl = lim I 11/2
Ill/2
= lim
111/2
Ilfll:
=
253
n
Ilfl12 < +
03.
When t decreases monotonicaly, then 11 U:12fllIis monotone increasing. Hence lirn 11 U:/2fll,exists and is finite. Therefore U:l2f belongs to H2 by I
I1/2
Proposition 3.9. Moreover we have (3.32)
IIU:/2fII 5 llfll for allfEH2 andgEG.
It is easily verified that (3.33)
U:/2 Uij2 = U:i2 for all g and h in G.
(cf. Proposition 3.3). By (3.32) and (3.33) we have and
llfll = lu:!3 u:/2fll5 IIU:/2fll 5 llfll IIU:/2fll = l l f l l for allf€H2 and gEG.
Hence U:I2 is a unitary operator on H2.The continuity of the mapping U:/2f is proved similarly as in Proposition 3.3. So U1I2is a unitary representation of G. 2) Since the linear fractional transformation
g-
(3.34) induced by g-' EG is a conformal mapping which transforms a circle to a circle and leaves the circle U invariant, the transformation (3.34) maps a diameter of U passing e'e to a circle orthogonal to U. Hence the limit
is a non-tangential limit. So, by Proposition 3.10,3), the non-tangential limit lirnf(g-' rt 1
exists. We have,
re'e) = (Bf)(g-l
do)
254
UNITARY REPRESENTATION OF
SL(2,R)
[(B o U:l2)fl ( 8 6 ) = lim (U:I2f) (refe) r11
= [(V;1/2~1/zo B ) f ]
(89.
(3.27) is proved. Put S = To B. Then S is an isometry from H Z into
8 = Lz (U). By Proposition 3.8, we have (3.35) BH2 = 8; and SH2 = @-. Hence U'I2
V--1/2.1/21@0 -2: V 1 / 2 * 1 / 2 ~ ~ -
by (3.28) and (3.29). Proposition 3.13.
q.e.d. 1) Let u be the complex conjugation on functions
(uf)(z)=fin
Put uH2 = H2 and Q U : / ~Q = U;1/2. Then U-'I2 is a unitary representation of G on F . 2) Let 8' be the closed subspace of 8 = Lz (U) spanned by { f. (89 - .-id? In h 0). Then the mapping B = uBu is an isometry from HZ onto 8'. We have
B o U;1/2 = V:/2,1/2 o B for all g E G
(3.36) (3.37)
u-1'2
v1/2,1/2
and
18'.
Proof. 1) If we introduce an inner product in H2 by (a-ag) = (f,g) for any f and g in H 2 , then ZP is a Hilbert space, and U;'l2 is a unitary operator on F , and U - 1 / 2is a unitary representation of G on H2. 2) First we have the equality (3.38)
for all gEG,
=
O V ; ~ / Z * ~ / ~ UV1/z,1/2
because
(0= (st + a1-1 f(g-1 0 = (/?t+ 6)186 + zI -"(g-'
(u~;1/2.1/2~f)
r ) = ( v y 2 f ) (0.
Multiplying the equality (3.28) by u on both the left and the right, we get (3.36). Since of-,,=I. we have
B (H2) = uBH' Thus B is an isometry from (3.36).
= 08; = @
Cf-. = 8'.
.SO
P onto 8'. Hence (3.37) follows from
255
COMPLEMENTARY SERIES
Remark. H 2 consists of all antiholomorphic functionsf on D for which
M z(r,f) is bounded on the range 0 S r < 1. The operator U;'Iz is expressed as follows :
Theorem 3.3. U1l2 and U - l l 2 are irreducible unitary representations of G on H 2 and F respectively. They are equivalent to two irreducible components of the unique reducible representation V1/2*1/z in the principal continuous series: u1/2E V1/2.1/21$- and lJ-112 E Vl/z.l/z 1 8 ' 9 (3.40) where
6-= Q Cfp, @+ = @ Cf,and& (0=
C-P
= e-rpe.
PSO
P
Proof. In Propositions 3.12 and 3.13, we have proved (3.40). In Theorem 2.1 we have proved that V1/z*l/zl$-and V1/z.1/21$+are irreducible. Definition 4. The set of irreducible unitary representations { UIIz, U - 1 / 2 )is called the limit of the discrete series of G. $4. Irreducible unitary representations
IV.
COMPLEMENTARY SERIES
In 52 we have constructed the representation Vj.*(j=O, 112; s E C ) of G on a= L1(U,dc), where dC=de/2x and
The operator V / * is a unitary operator with respect to the inner product ($9
if and only if s=-
1
@)=I U
$(C)lO(r)dC
+
iv (v E R) (Proposition 2.2). However, if j = O , then 2 for some values of s there exists a positive definite Hermitian form
which is invariant under VUo.*for all g E G. We can prove that if we impose the conditions ($, @)* is Hermitian, ($, 9). is positive definite, ($, (l)*is invariant under V,,O.*for all g e G,
UNITARY REPRESENTATION OF
256
SL (2,R)
then we get 1 &(c, 7)=C(1-Re(~q))'-1 a n d p < l
(cf. V. Bargmann, [l] p. 617). In what follows we start from the kernel O,(C, 0)=(1 Re(Cg))"-' and show that the Hermitian form (4.1) is defined 1 on 8 x 8 and positive definite if and only if 2 <s< 1.
-
Proof.
(Set
2.
e-O)
1 1
2-1
=-B
+=-
(a-y,
x
z)
Remark. It is easily seen, by considering the expression (*), that I 1 diverges for u 5-. 2
Proposition 4.2. 1 Let u > and
and put
257
COMPLEMENTARY SERIES
(4.2)
and by Schwarz's inequality this is S~11#11 lI+lf
0
(1-cosaY-l da
(by Proposition 4.1) = llill 11+11<
1
Q)
if o>--.2
We shall now show that ($, +), is positive definite for 1/2<0<1. (($, +)$is not positive definite if 0 21.) LEMMA 1. Let Tn(x) be the Tschebyscheflpolynomial of the first kind, i.e.,
T, ( x )=cos(n arccos x), T, (cos 8)=cos n8 . Then we have
T ~ +( ~I ) = 2 x T n ( x ) - T n - l (XI, To (x)= 1, Ti (x)=x,
1)
2)
where (2n- l)! != Proof.
{
*
"'
(2n - 1)
+
1) Since cos (n+ l)@cos (n- l)@ = 2 cose cos ne, we get
258
UNITARY REPRESENTATION OF
SL (2,R)
Tn+l(x)+Tn-1 (x)=2xTn( x ) for all X E R . By the definition of Tn,we have To(x)= 1, Tl(x)=x. 2) Let Dn(x) denote the right member of the equality in 2) of the proposition. Then we have Do(x)=1, D1 ( x ) = x , and Dn(x)is a polynomial in x of degree n. If we can show that it satisfies
(*I
Dn+l (x)=2xDn (x)-Dn-l
(XI,
then, since Tn(x)and Dn(x) both satisfy the same recursion formula and To(x)= Do(x), Tl(x)=Dl(x), we can conclude that Tn(x)= Dn(x). To show (*) we calculate as follows: dn-1 x-dn (1 -X~)n-l~~=zn{X(l dn -Xa)n-lly -n-&l - x a)n-iia
dx"
dn-1
=-,-,[{-nx"(n-
dn-1 dn-1 ( - 1 ) (2n-l)-(l-x~)"-a'a=-&3{(-2n+l) dxn-'
l)}(l-xay-y,
(l-x2)n-a/a}
.
These relations show that
+(-
1 ) (2n- 1)-
dn-1
(1-xa)n-aI'
from which (*) follows immediately.
Proposition 4.3. 1)
I Let fp (C)=C-p(p E 2).Then we have, if a>-, 2 (fn,fm)e=
an,,
An(o)=A-n(o), n
&&(a)= 17 L-I
Proof. We have
where Ro(o)=l
Rn(o),
k-o if n > 1. k+o-l
259
COMPLEMENTARY SERIES
=&so I0 .ar
(fn,
fm).
ar
(1 -cos (e - ~
ded@
p - e-*n@+tm* 1
Let
Since cos(-n$)=cos n# we get R n ( ~ ) = ~ - n ( ~ ) and RO(a)=1 is clear from the definition of C, (cf. the proof of Proposition 4.1). If n 2 1, let x =cos#. Then we have
(by Lemma 1)
(Integration by parts n times)
Letting t=-
1-x we see that the latter equals 2
1 1 The definite integral of the last expression is equal to B(a---, n+-). 2 2 Using the value of C, given in Proposition 4.2, we now have Rn(a)=
(- l)"&r(a) 2.+"-l(u - 1) ... (a -n) r ( u - 4) r ( n 2-1r ( a - 4 ) ?r(2n-l)!! r(a+n)
+4)
We have proved 1). The statement in 2) now follows from the formula for ]"(a) given in 1). 1, then Rn(u)$O for at least one n. Hence (#, +)# is Remark. If not positive definite if a h 1.
260
UNITARY REPRESENTATION OF
SL (2,R)
Proposition 4.4. If ) < a < 1, then (#, 4). defined by (4.2) is a positive definite Hermitian form on 8 =Lq(U,dc). Moreover, we have m
(4.3)
C
($3
n:--m
where fn(ete) =cine. Proof. Since Ifn)
nrZ
An(O)
I ($,fn)I2
9
is a complete orthonormal set in 8, we have m
m
Since (#, 9). is continuous on 8 x 8 (Proposition 4.2), we have
m. n---
(Proposition 4.3)
Putting
+ =# we get m
($9
$)n=
C An(o)I(+,fn)12rOn=-m
If (4, #).=O, then (9, fn)=O for all n~ 2, so #=O. Remark. The formula (4.3) is valid for a 2 1. If 0 21, ($, +)#is a Hermitian form on .@ x .@ which is invariant under Yo,.and is not positive definite. In particular, if a is equal to a positive integer I, An(u)=O if and only if In1 &Z. So the kernel N = @ E .@I($, $)0=01 has codimension 21+ 1. In this case, the representation Yoszinduces a finite-dimensional representation on the factor space Q/N. (cf. Theorem 7.5 and Remark after it.) Proposition 4.5.
Let l+i-E -i- E 2 2 :i l-izE
261
COMPLEMENTARY SERIES
be the Iwasawa decomposition of gu,. Then, for g=ut, we have et
-
-cht + shtcos e ,
cos (ar e)=e-tcat")(sht+cht.coso)
,
sin (at .e) =e-t(at*')sine . Proof. By Proposition 1.7,we have for g =at = et(at, r )
-
b3
-laC+BI t
+sh-1'2t
= lch-ete
2 t
=cha-
2
+ s h t' +~ 2ch-2t sh-2t cos e
=cht+shtcos 0.
By Proposition 1.7 we have for g =at -e-t(at,d) -
+ +
(cht cos8 sht i sine) ,
from which follow the second and third equalities in the proposition. Proposition 4.6.
1
Let 7 < O X 1 and let .$&be the completion of 8 with
can be extended uniquely to respect to ($, +)#.Then, for any g E G, VU0p8 a unitary operator Vu@on 8.. The map P : g w V u eis a unitary representation of G on 4.. 1
Dewtion. The set of representations { PIz
(V:lu
C, V,".'+).=(C,
for any $, (o E $3 and g E G.
(o),
Since we have g=u, at u, ($2 Lemma 1) and Vuuro,"= Vuo,~Vuto,e (Proposition 2.2), it suffices to prove (4.4) for g=u, E K and g=ut E A. From the definition it is clear that t(u., 8) =0. Hence we have (
~
(c>=e-""uu-l'
~ u C~ ) 0
,
C)
=$(et
C(u.-'C>
262
UNITARY REPRESENTATION OF
SL (2,R)
- e - ~ t ( a L - l 8), $h[aL-le1. and furthermore (4.6)
-
1 cos(aLe-aL@) = 1-cos ale cos uto -sin ate sin aLw
(Using Proposition 4.5) =e
- ( t ( a L , e)+r(a,,
0))
(1-cos(e-o))
holds. Hence, by (4.5), we have ( Va:.'$h, Vato."+>o
From Proposition 1.5, I), we have t(at-l, at8)+t(at,8)=t(l, O)=O, and from Proposition 1.5, 3), we have d(ut8)/d8= e-L'at'e' (and similarly for 0). Using these relations and (4.6), the above expression becomes
So (4.4) is proved. V ~ may ~ ' now be extended uniquely to an isometry V / of the completion QUy of $ with respect to ( , onto itself. Moreover, since Vvo'"J7v-10.'=Vv-10.'VgO.@= 1, )uy
we get Vv~Vv-l'=Vg-l'Vv'=l
.
Hence, Vvuis a unitary operator on 8.. Since ygo*y,. 0 . = ygg, 0.0 0
3 .
,
263
COMPLEMENTARY SERIES
We can show, as before, that Yo,.is strongly continuous (cf. proofs of Propositions 2.2 and 3.3), and since Q is dense in Qo,' V is also strongly continuous. Hence V.is a unitary representation of G.
Remark. The Hermitian form (#, 9). is invariant under V0*#even if 1, as the above proof shows. We shall now show the irreducibility of V . We always assume & < u < 1.
u>
Theorem 4.1. For any u satisfying Q
11#11.411#11 for all + € @ . Hence if # E Q is a C"-vector for Yo,. then # is also a C"-vector for P and dVu(X)# = dVo.q ( X ) # for all X E g . In particular the functions f p ( C ) = C - p Hence by Proposition 2.6,4) we get
belong to
Qme
for all p E 2.
EfP =(P+ U ) f P + l
for all p E 2,
(4.7) FfP =(P - U l f p - 1
+
+
where E= d P ( X l ) idP( Y) and F= -dV.(X,) idP( Y). Now we prove that a vector f in !& satisfies (4.8) V,,f= Xp(ua)f for all 0 E R and some p E 2-'2 if and only if f = c f p where c is a constant. First, a function satisfying the latter condition satisfies (4.8). Conversely, we assume that f E Q . satisfies (4.8). f can be expanded in terms of the orthonormal basis (& = i n (O)-tfn)nrZ say, (4.9)
f=
C
Cn$n nrz
.
Then operating with V U b e on both sides of (4.9), we get (4.10)
For each n + p , there exists a real number 0 such that X ~ ( U ~ ) # X , , ( U ~ ) . Hence (4.9) and (4.10) show that cn=O if n # p and thus f = ~ ~ ~ ~ = c f , .
264
UNITARY REPRESENTATION OF
SL (2,R)
After these preparation, we prove the irreducibility of V.Let Q' be a invariant under P,and W be the unitary non-zero closed subspace of representation of the compact group K = {ue[OE R} defined by Wu,= Vue[Q'. Then W is decomposed into a direct sum of irreducible representations x,,'s. In particular @' contains a vector f#O satisfying (4.8). Then f is proportional to f p as was proved above. Hence f p belongs to Q'. Then Enf, and Fnfp belong to 8' for all n E N. Since p is an integer and 4
and
Vueufn=Xn(Ue)fn
VUIIy= @ xn nrZ
.
On the other hand, Proposition 2.2.4) shows that
v~I~@ . ~Xn+lll I Y.= nrZ
Hence, P and VIJ'.* are inequivalent. We also have from Proposition 3.5 that, for n 2 1, u"IK= @ X-n-p, U-"IK= @ Xn+p P ~ N
P ~ N
Hence, P is not equivalent to Un(n E 2/2,lnl> 1). (cf. Theorems 6.4 and 6.5). Remark. V' is not equivalent to Vo*++*u Proposition 4.8.
P(3 < u c 1) defines a representation of G+(2). proof. This is clear from the fact that VU2; = 1.
Proposition 4.9. If O= 1, then the Hermitian form (#, +)1 is positive semi-definite. The completion of 8 with respect to (4, +)1 is isomorphic to @//8(0),where @(O)= {#I(#. #)l=O). Moreover dim&= 1. The representation V1 induced by VOJ on Q1 is the (trivial) identity representation I of G. Proof. By Proposition 4.3, Ro( 1) = 1 and In 1) =0 ( for n # 0. Hence we have
-
($9
+)I=
C
( # , f n ) W = ( # , f ~ )
n--O
from which the first statement follows. Since
(+,fa>,
K-FINITE VECTORS
265
(VgO*'$,V17°*14)1=($,$91, + E Q, g e G, holds (cf. proof of Proposition 4.6), Q(0) is invariant under VgO*l,g E G. Let $o =f& Q(0)E Q/Q(O). We have $9
Vvl$o = (Vv0*'h,h)$o. Hence, in order to prove that V1 is the identity representation of G, it suffices to prove that ( V g ' J ~ l ~ , f 0 )for = l ,allgEG.
By $2, Lemma 1, any g e G can be written in the form g=u,atuo, and since V,,O*lfo=fo ,
we have
(v,O*lfo,fo)=(vat OJvqO.'foo,
vu+-1O J f O ) = ( v a , O * ' f ~ o , f O ) (Proposition 4.5)
$5. &finite vectors The present section is in preparation for the classification of irreducible unitary representations. In this section we shall prove that each irreducible unitary representation U of SL(2, R) contains each irreducible unitary representation xm(mE 2-lZ) of its maximal compact subgroup K at most once. Then the representation space 8 of U is decomposed as the direct sum of one-dimensionalsubspaces am(mE M) :a=@ am,where UIQm= mriY x,,,. The elements of the algebraic sum Q K = C Qm of the subspaces Qm m t I
are called K-finite vectors for U.It will be shown that QK is contained in the space 8.. of C"-vectors and is invariant under the differential representation U' of U.The restriction U,(x> of U ' ( X ) to Q K for X E 11(2, R) defines a representation UK of the Lie algebra 11(2, R) on The classification of irreducible unitary representations U of SL(2, R) can be reduced to the classification of Ug.This process is carried out in the next section.
ax.
266
UNITARY REPRESENTATION OF
SL (2,R)
First we calculate the Haar measure on G=SU(l, 1).
Proposition 5.1. The left-invariant Haar integration on G=SU(l, 1) (or Go= SL(2, R)) is given by
for any continuous functionf with compact support, where g =uoatne is the Iwasawa decomposition of g (cf. Proposition 1.3). Proof. Put dg =e’dedtdt. We shall prove that d(gog)=dg for any goE G. By Lemma 1 in $2 (or the following Proposition 5.2), every element go in G can be written as go=u,a,u,. Hence it is sufficient to prove d(g0g) =dg for go= u, and ar. u,ueatnt = u,+oat nt, we get d(u,g) =etd(p e)dtdc=etdedtdE=dg. By a simple calculation we get
Since
+
atneat-’=nett. Put t’=t(a,, 0 ) and €’=€(a,, 0 ) in the notation of Proposition 1.5. Then we have
a,ueatnc=u,, .eat+zclatnt - ua,.eatlatat-lnetatne = U,,.+tne-tt.+t
Hence we have by Proposition 2.1, 3), d(a,g)=et+t’d(a,-B)d(t+t’)d(E+e-tE’) -et+t‘e-t’dedtdE=dg.
q.e.d.
In the following, the Haar measure dg of SU(1, 1) (or of SL(2, R))is fixed by the normalization given by (5.1). Proposition 5.2. Any element g in G=SU(l, 1) (or in Go=SL(2, R)) can be written as (5.2)
g=u,atu#, O s p < 4 n 7 Ost, 05$<2n.
If
g=(i
[) E G,
then
a =e*(,++)/2 ch(t/2), B= e*(p-+)/S sh(t/2). (5.3) (5.4) ch(t/2) = lal, sh(t/2)= IBI, et/’= la1 I& In particular if g belongs to G -K,then
+
K-FINITE VECTORS
267
(5.5)
and (9, t, 9) is uniquely determined by g. If g E K, then t=O and p + + is uniquely determined modulo 4r by g. Proof. By the multiplication of matrices, we get ei(r++)lach(t/2), eg(9-+)/2 sh(t/2) u,acu+= (ei(-p++)lash(t/2), e-i(p++)la ch(t/2)).
Hence we have (5.3). There exists a unique tz0 such that sh(t/2)=(,9(. Then ch(t/2)=(1 +181a)t=lal and et/a=lal+lpI. We get (5.4). IfgEG-K,thenp#O. Since lala=l+IBI'r-l,aisalways #O. Wecan find p and 9 satisfying o s p <4r, -2r <$<2T, and the first two equations in (5.5). If -2n <sl, <0, then we can replace u+ by #++a. = - u+. Hence we may assume that 0 5 $ <2n. Assume that an element g in G -K can be written as g = u 9 a t u + = u , ~ a t ~ u,+ ~ where p, t, 9, p' t', $' satisfy the inequalities in (5.2). Then we have t = t' because sh(t/2) = 181= sh(t'/2). By (5.5), we get eK9++)/2 =e i ( p ' + + ' ) I a and e<(q-g)/a =e<(p'-@')15 . (5.6) Dividing the first equality by the second bne, we get e*+=et+'.Since 0 5 9, 9' <2r, we get $ = 9'. Moreover, by (5.6) we have ei91a=etQ'laand p/2 = y'/2 and p = p'. If g = U e E K, then ue=u,++. In this case t -0 and the sum p ++ is uniquely determined modulo 4 r by g. q.e.d. The decomposition (5.2) is called the Cartan decomposition. Proposition 5.3. The Haar integration (5.1) is given by the formula
(5.7)
1
f(g)dg=2~/=/;
/
X
f(katk')shtdkdtdk' ,
where dk is the normalized Haar measure (44-lde of K = {ue1050<4n). Proof. Let g=u,atu+=uea,nt, where o j y , e < 4 r , o j t < + c 0 , 0 j + < 2 ~ , --<s,E<+co. Then (t, $) and (s,E ) can be regarded as two systems of coordinates on the right coset space K\G= { g =Kglg E G) . The relation between (t, 9)
268
UNITARY REPRESENTATION OF
SL (2,R)
and (s, E ) is given as follows: Put
Then we have a =e*+lp ch(t/2) and
p =e-l+rn sh(t/2).
By Propositions 1.3 and 1.6, the parameters s and t in (5.8) are given by e*=la+BIa=cht+shtcos qlt, Im{(a+I) ( a - I ) } = -e-# shtsinqlt . Now we calculate the Jacobian E=e-*
The second factor in the right hand side of the above equality is equal to e-as, because it is the inverse of
The first factor is given by
Hence we get D = -e-# sht and e8dsA dE = sht dqlt A dt. Transforming the Haar integral (5.1) by means of (5.9), we get (5.9)
=IK/:1; =;IK/.1:'
f(kue-'atu+)shtdkdtd+
f(katu,)shtdkdtdqlt
=2r.l K . l o
Jf
(katk')shtdkdtdk'
K
where we use the relation atuI =~ ~ , a ~ u + + ~ . . COROLLARY to Proposition 5.3. The left invariant Haar measure dg
269
K-FINITE VECTORS
given by (5.1) is also right invariant. Hence G=SU(l, 1) is unimodular. Proof. Using the identity u.a-tu.-l=ar and (5.7) we get
/
f(g-l)dg =2 x 1 ff
K r
=2xJ
/+-IK
f(k'-la-tk-l)shtdkdtdk'
O
roo
K J 0
r
r
J
f (k'ark)shtdk'dtdk = K
Hence we get
where f(g) =f(g-l). Definition 1. The vector space of all complex-valued continuous functions with compact supports on a topological space X is denoted by L(X). For each n E 2-'2, the character X n of K = {uelOS8 <4n} is defined by Xn(ud)=einS . (5.10) The subspace of L(G) consisting of all functionsf satisfying
(5.1 1) f(uogu+)=xn(u~lf(g)Xn(u,) for any 8, (O E R and g E G=SU(l, 1) is denoted by A,. Proposition 5.4.
(5.12) and
1) A function f in A, satisfies ~ ( w L ~ s= ) xn(up+(a)f(at>
(5.13) f(at)=f(a-t). 2) The mapping f++fIA of restriction to the subgroup A = {atIt E R) is a linear bijection of A, onto L.(A)= { fL(A)lf(at)=f(a-,)}. ~ The m a p ping f E A , H F E L([l, m)) defined by f(at)=F(cht) is a linear bijection of A, onto L([l, a)). Proof. 1) (5.12) is trivial. Since u.atu.-l=a-t, we get (5.13) from (5.12). 2) By (5.12) and (5.13), the mappingfHflA is a linear injection of A, into L,(A). Let 9 be an element in L,(A). Then we can define a function fonGby
-
f ( u v a 4 = Xn(Up+,) ( O ( 4 The Cartan decomposition g=uputz+ is not unique when g belongs to K. But in this case 9++ is unique modulo 4~ and the function is well
270
UNITARY REPRFSENTATION OF
SL (2,R)
defined on G. It is easily seen that f belongs to A,. Hence the mapping fwfIA is a bijection of A,, onto L,(A). Since the function cht maps the
interval [0,
+ a) homeomorphically onto [l,+ a), the second part of
2) is easily obtained from the first part. Definition 2. In the following, we denote the quantity F(x) appearing in Proposition 5.4,2) by f [ x ] :f(ut)=f[cht]. Proposition 5.5. The set A, is a commutative algebra over C for every n E 2-lZ. The product is defined by the convolution on G. Proof. Let fl and fi be two elements in A,. Sincefi and fa belong to L(G),the convolutionfl*h is defined. Moreover, we see that
n
=d
andfi*h E A,,. To provefi*h=$&,
Up>
(fi*f) (h)~n(u+)
it suffices to show that
(h*f) ( u t ) = ( f * f ) (at)
(5.14)
for all c E R
.
Put (5.15) Then we have
+
a = e * p l a ch(r/2)ch(s/2) e-*sla sh(t/2)sh(s/2),
p =e*pla ch(r/2)sh(s/2)+e-<,lash(t/2)ch(s/2).
By Proposition 5.2, we have
(5.16) and (5.17)
cht'=21ala- 1=chtchs+shtshscos(p e*b'+#')lZ=
dial
+ sh(t/2)sh(s/2) +chrchs+shtshscos(p)lla
=J Z e * ~ 1 ch(r/2)ch(s/2) 2
(1
e-tp'a
27 1
K-FINITE VECTORS
X
+
(ch(t/2)ch(s/2) e-'p sh(t/2)sh(s/2))'" shsdpds. [2-1(1 +chtchs+shtshscosp))
Similarly we have (5.19)
(fi*h) (at)=
X
+
(ch(s/2)ch(t/2) e-'+ sh(s/2)sh(t/2))'^ shsdsd+ {2-'(1+ chscht+ shssht C O S ~ ) )
.
Cornpairing (5.18) with (5.19), we get (5.14) q.e.d. Proposition 5.6. A function f in L(G')belongs to A , if and only iff= where convolution is taken over the group K :
x,,*f*x,,,
Proof. I f f belongs to A,, then f=x,,*f*x,, by (5.20). Conversely if a functionf in L(G)satisfiesf= x.*f*x,,, then n
n
LEMMA1. Let A be a *-subalgebra of the algebra B ( H ) of bounded linear operators on a Hilbert space H, A s and A w be the strong and weak closures of A and R(A) be the smallest von Neumann algebra containing A . Then we have A'= Aw and R(A)=A" = C1+ As.
212
UNITARY REPRESENTATION OF
SL (2,R)
Proof. Since the strong closure of a convex subset of B ( H ) coincides with the weak closure (cf. Dunford-Schwartz [l] p. 477), we have A * = A". Since A""=A" by Ch. I, (2.9), A" is a von Neumann algebra (loc. cit.). From A c R ( A ) , we get A"cR(A) hence A"=R(A). Let D=C1+ A'=Cl + A w . Then D is a weakly closed *-subalgebra of B ( H ) containing 1. Hence D is a von Neumann algebra. Since A" 3 A , we have R(A)= A" =A"* 3 C1 + A * = D 3 A . Hence by definition of R(A), we get R(A)= D. (cf. Dixmier [l], p. 44) q.e.d.
Proposition 5.7. Let U be a unitary representation of a locally compact group G and A be a bounded linear operator on H = H ( U ) . Then A commutes with U, for any g E G if and only if A commutes with U f for every f E L(G). Proof. If AU,= U,A for any g E G, then for any f E L(G), we have AUf =
S.
f ( g ) A U , d g = / f(g)U,Adg= U f A . D
Let V be an element in the set !Jl of all compact neighborhoods of the identity e in G. Then there exists a function f v in L(G) such that fvLO and
1
fv(x)dx= 1 and supp (f v ) c V. For any g in G, put gv(h)=fv(g-l
h). Then s-lim U,,= U,.Hence if A U f = U f A for every YEL(G), then AU, = U,A for every g E G. Proposition 5.8. Let T be a strongly continuous representation of a locally compact unimodular group G by bounded operators on a Banach space H. Such a representation is called a Banach representation. Let k be the set of equivalence classes of (finite-dimensional) irreducible representations of a compact subgroup K of G. For any 2 E k,put &)= TrU2(k)(U2E I), d(I)=deg U2and E(I)=d(I)
Tkmdk.
S K
Then E(1) is the projection on the subspace H(I) of H consisting of all vectors x E H such that the set {T& E K } spans a finite-dimensional subspace H , on which T induces a direct sum of a certain number of copies of U2. Proof. Since x ~ * K=~d(;C)-lx2,E(I) satisfies =E(I). Hence E(I) is a projection onto the subspace E(I)H. If x belongs to H(;C),then there exists
..., V, such that x E 1Vc (direct sum) and to the class 2 E k.The vector x can be written
subspaces Vl,
6-1
TklVt belongs
273
K-FINITE VECTORS
where (tp,(k)) is a unitary matrix. Hence we have P
d(1)
by the orthogonality relations (Ch. I, Theorem 3.2). So we have proved that x E E(2)H and H(R)c E(R)H. Conversely if x belongs to E(R)H, then x = E(R)x satisfies ‘ d(i)
Tkox=
1 t0~(kO)~P,0 3
9.0-1
T m x d k . Hence x belongs to H(1) and E(A)H
where x,.,=d(R)/ K
c H(R).
q.e.d.
Proposition 5.9. The notations are same as in Proposition 5.8. For any 2,let
2E
L(R)= If€ L(G)ld(R)’XI *f* 2 2 =fI .
J.
1) Then H(R) is invariant under T , =
f(g)Tgdgfor anyf E L(R).
2) For any f E L(R),put T,A = T,IH(,I).Then T, =O if and only if T f 2=O. Proof. 1) As is easily seen, E(R)T,=~(R)TF~,,,;, =d(R)T,,;A= T,E(R) forfe L(r7). Hence T,H(R)= T,E(R)H= E(R)T,Hc E(R)H= H(R). 2) Since E(R)T,E(R)= T,, if T I A=0, then T / H = E(R)T,E(R)H=E(A)Tf’H(R)=O q.e.d. and T,=O. Conversely if T,=O then T,l=T,IH(R)=O. Definition 3. If dimH(R)=pd(R), then we shall say that R is contained T.p is called the multiplicity of a in T.
p times in
Theorem 5.1. Let U be an irreducible unitary representation of GSU(1,l) on a Hilbert space H. Then each irreducible unitary representation
274
UNITARY REPRESENTATION OF Xn(us) =e(nu
SL (2,R)
(n E 2-’Z)
of K is contained at most once in U. Proof. Put En=E(Xn)=S K x,OU&. Then the conclusion of the theorem is expressed by dim E , H $ l . The algebra A-n coincides with L(Xn)= {fsL ( G ) l f , * f * ~=f} , . Hence E,H=H(n) is invariant under A n = [UfIH(n) ‘IfEA-n}. Put L = { U , l f s L(G)}. Then by Lemma 1, we have (5.21) Cl+L’=L”.
Put M = { U J g E G}. Then by Proposition 5.7 and Schur’s Lemma (Ch. I, Theorem 2.1), we have L’ = M f= C1. Hence (5.22) L“= M“ =B(H). (5.21) and (5.22) imply c 1 L*= B(H). (5.23) For any f~ A,,,let V(f) be the restriction of U, to the subspace E,H. Every element A in B(EnH) can be extended to a bounded linear operator A. on H by (5.24) A,x= AE,x for x E H.
+
If x belongs to E,H, then by (5.23) there exist nets (or filters) (jJreI and ( u ~ )in ~ L(G) . ~ and C respectively such that Aox=lim (url+ U,,)x. (5.25) I
Put g,= x,, *f,* 2.. Then g, belongs to A-, by Proposition 5.6. By (5.24) and (5.25), we have lim (a,l+ V(gr))x=lim (udl+ Ui,*~,*:)~=lim (uJ +EnUf,E,)x I
=
lim Em(utl + U~,)x=E,Aox=E,AEnx=E,Ax= Ax. I
Hence we have proved that B(EnH)= C1+ A,” = An” (5.26) by Lemma 1. Since the algebra A-, is commutative, so is the algebra A,, Hence we have ,Anc A,’ and A n ’ 2 Am” (5.27)
.
By (5.26) and (5.27), we have
275
K-FINITE VECTORS B(EnH)c A,"C An'cB(EnH).
Hence An"=&' and A,"'",''. The last identity implies that the algebra A," = B(E,H) is commutative. Since B(H) is not commutative q.e.d. if dimHz 2, we can conclude that dimE,HS 1. Definition 4. Let g(G)be the set of C"-functions with compact supports on a Lie group G and let U be a Banach representation of G on H. The subspace Ho of H consisting of all the finite linear combinations of the vectors of the type
-1.
U a-
'
f(g)U,adg
for f E g ( G )
and aE H
is called the Gdrding subspace (for U). Proposition 5.10. The GBrding subspace Ho is contained in the space H , of C"-vectors. Both Hoand H, are dense in H . Proof. Any element X in the Lie algebra g of G is regarded as a left invariant differential operator by the formula
To the element X in g, there corresponds a right invariant differential operator X' defined by
Let f E d ( G ) , X E g and a E H and put f-(g)= U,Ufa and xt=exptX. Then by the left invariance of the Haar measure dg, we have
Wf %xt) -f -(g)) =
1
I3
t-'(f (x-tg-'go) -f (g-'go)) U d g a
+ULsx,fa as t+O. We have proved that f-(g exptX) is differentiable at t = O for any g E G . Since x ~ + ~ = xf-(g ~ x exptX) ~, is a differentiable function of t. And we have
We can repeat the differentiation and prove that for any ,'A ..., X , E g, XI ... X,f- is defined as a continuous H-valued function on G . Hence f - is an H-valued C--function on G . (cf. Ch. 11, $6, Lemma 1. This lemma is stated for a complex-valued function, but is valid for a Banach-valued function without changing the proof.) It remains to prove that Ho is
276
UNITARY REPRESENTATION OF
SL (2,R)
dense in H. Since U is strongly continuous, for any a E H and E >0, there exists a compact neighborhood V of the identity e in G such that IIU&--all<e for a n y g e V. r Let f g o be a C"-function on G satisfying supp(f) c Vand f(g)dg= 1.
Iff
Then we have
IIU1a-alld
L
f(g)ll~&-allds9
Hence we have proved that Ho is dense in H. Since H, =I Ho, H, is dense in H. In the course of the proof, we have proved the following corollary. COROLLARY to Proposition 5.10. For any a E H and E>O, there exists a C"-function f E g ( G ) such that IIU,a-all<&.
Proposition 5.11. Let K be a connected compact Lie group and 2 be the set of equivalence classes of irreducible unitary representation of K. For any Banach representation U of K on H and R E 2,put (5.28)
E ( I )=d(R)/ K
u*imdk,
where x 2 is the character of 1 and d(J)=xl(e)is the degree of R . Then for any C"-vector v E H for U,the series
converges absolutely to v. Proof. Since U is strongly continuous, the set { Ukxlk E K} is compact and hence bounded for each x E H. So by the uniform boundedness theorem (cf. Appendix A), the function p(k) = I I Ukllis bounded on K. Let C be an upper bound of p ( K ) . Then (5.29)
IIE(mlld Cd(R)llXll/ K IX.l(k)l& 5 cdQ)llxll.
Let (Xr)lrldnbe an orthonormal basis of the Lie algebra t of K with respect to an inner product (X,Y) on t invariant under Ad K, and put
K-FINITE VECTORS
277
Then D is the Casimir element of U(1). If v is a C"-vector for U,then for each R E R we have E(R)O'(X)v=/
K &(k)U&'(X)V
(na(k eXp(-tX))-Rz(k))Ukv dk
=Em t-' (-0
=
-1
dk
J K
(Xxl) ( k )Ukvdk
K
.
where X E is~ interpreted as a left invariant a differential operator of order 1 in the last term of the above sequence of equalities. Since the matricial elements of 1 are eigen-functions of the Casimir operator 9 with eigenvalues o ( A ) = ( A , A+26) (Ch. II, Proposition 8.1), the last equality proves that
(5.30)
E(I)U'(L?)V=J K
(Gl)(k)ukV dk
= o(,I)E(R)v
for any C"-vector v and A E k (5.29) and (5.30)imply that lIE(lz)~lI=o(R)-nlIE(OU'(Ja~.)vlI 5 Cd(R) o(R)-"llU'(Jam)~ll. Since d(2) is a polynomial function of the highest weight R (cf. Ch. 11, d ( ~ ) o ( R ) converges -~ if m is sufficiently large. Hence we have EjS), 1+0
E(R)v converges absolutely (normally).
proved that 1.R
Now we prove that its sum is equal to v. Let H* be the dual space of H and p E H*. Then
vl(k)= < U ~ Vp ,>
is a C"-function on K for any v E H,. And we have
278 put
UNITARY REPRESENTATION OF
C E(I)V=
W.
SL (2,a)
Then
2.2
w,(k)=C< UxE(R)v,Q>
=
c
4 2 ) (v, * %l)(k)
l e t
1
is the Fourier series of a complex-valued C"-function v, (Ch. I, Proposition 3.4). Hence its sum w, is equal to v, for any (O E H*. In particular, we have < E ( I ) V (p, = w,(e) = v,(e)= < Y , (0 >
C
=-
1
for any
cp E H*
and
q.e.d.
E(R)v=v. ki?
Remark 1. Put t(k)= Unv.Then we have (E(;Ov)-(k)=d(I)(t*x,)(k). Hence Proposition 5.11 is a generalization to a vector valued C"-function of Ch. 11, Theorem 8.1 (cf. also Ch. I, Proposition 3.4). COROLLARY to Proposition 5.1 1. The result of Proposition 5.1 I still holds when U is a strongly continuous representation of G on a Frkhet space. Proof: Let (P,,),,.~ be a countable family of seminorms defining the topology of H. Then, after replacing the norm with the seminormsp,, the above proof of Proposition 5.11 is valid when H is a Frdchet space.
Proposition 5.12. Let U be a Banach representation of a Lie group G on H, let K be a connected compact Lie subgroup of G and let E(I) be the projection defined by (5.28). Then the space (H, n E(I)H) is dense in H . 1.R Proof. We prove that for any a E H and E > 0, there exist a finite subset F of K and an element alE E(I)H n H, for each I E F such that I a, -a1 I
Ic
.arF
We can assume a#O. By Corollary to Proposition 5.10, there exists a C"-function f E g ( G ) such that <E.
(5.31)
I1 U,a-all< 4 2 .
Let C be a compact subset of G such that C = CK and supp(f) c C. For x,. Put M=supllU,all. Then we any finite subset F of 2, put
xF=C ICF
oco
have O < M < + co . Any function f E s ( G ) is a C"-vector for the right regular representation of G on L1(G). This fact can be proved in a manner similar to the proof of Proposition 2.5. Proposition 5.11 proves that there exists a finite subset F of R such that
K-FINITE VECTORS (5.32) 1lf-f. (5.31) and (5.32) show that
XPI 11
279
<€/2M.
IIU,*ZPa- 4 I 5 I I U,*,p - Ural I + IIU,a-all 5 M IIf*X P -flIl + 1 Iufa-al I <
9
because supp(f * 2). c CK= C. Since Uf*Z,a belongs to the Garding subspace Ho of H, Proposition 5.10 shows that Uf*lpa belongs to (Ha n E(R)H).Hence we have proved the proposition. q.e.d.
1
,
Definition 5. The notations are the same as above. If K is a connected compact subgroup of G, an element in the subspace H K = cE(I)H is 2rr2 called a K-finite vector. Proposition 5.13.
1) Let H(R)=E(R)H and H,(R) =Ha n H(R). Then
H&) is dense in H(;O.
2) If dimH(R)< + m for every R E I?, then H,(R)= H(R) for all R E I? and is contained in H,. H K is invariant under U‘. Proof. 1) Let R and be two elements in I?. Then
H K
E(R)E(~) = K
1
~~~~X~(k)X,(k~)dkdk~
K
by the orthogonality relations of characters (Ch. 11, Proposition 2.2). then E(R)b E H,(R). Let a be an element in H(R). Hence if b E
c
Pfb
Then there exists a sequence ( U ~ ) , , ~ Nin
1H,(R)
such that liman=a by
led
Proposition 5.12. Then we have limE(R)a, =E(R)a=a. Since E(R)a, E n-== H,(R), we have proved that H,Q) is dense in H(2). 2) If dimH(2)< + w , then the dense subspace H,(R)=H, n H(R) coincides with H(R). Hence we have Ha 2H(R). Therefore if dimH(R) < + 00 for every I E I?, we see that H, 2 HK = H(2). Let x be a K-finite vector
c
ieI?
and X be an element of g. Then U’(X)x is K-finite, because U,U’(X)x= U’(AdkX)Ukxand g is finite-dimensional. q.e.d. Definition 6. Suppose that Hg c Ha and let UK(X) be the restriction of U ’ ( X ) to the subspace HK(XE 9). Then UK is a representation of the Lie algebra g on H K . UK may be uniquely extended to a representation
280
UNITARY REPRESENTATION OF
SL (2,R)
of the universal enveloping algebra b of the complexification gc of g. The extended representation of b on HK is also denoted by UK.UK is called the K-jinite diflerential representation of U.
Theorem 5.2. If G = SL(2, R)and K = S0(2), then for every irreducible unitary representation U of G, the space H, of C"-vectors contains the space HKof K-finite vectors. Proof. By Theorem 5.1, dimH(n)5 1 for every n E 2-'2 =15. Hence the assumptions of Proposition 5.13. 2) are satisfied by G=SY2, R) and q.e.d. K= SO(2). Remark 2. As a generalization of Theorem 5.2, the following general theorem holds: Let G be a connected linear semisimple Lie group and K be a maximal compact subgroup of G. Then every irreducible representation 1 E I? of K is contained at most d(2) times in every completely irreducible representation of G (cf. Godement [4]).
$6. Classification of irreducible unitary representations In this section we prove that any irreducible unitary representation
U of Go=SL(2, R) and G=SU(l, 1) is equivalent to one of the representations constructed in 92, 93 and & Our I. method of classification is based on the classiiication of the representations UK of the Lie algebra go= BK(2, R) on the spaces of K-finite vectors. The differential representation U' of a unitary representation U is obtained by differentiating the one parameter group UeIptxof unitary operators. First we give preliminary results on the self-adjoint operators which appear as the infinitesimal generators of one parameter groups of unitary operators. Then we shall show that the classification of unitary representations U of G can be reduced to that of the representations Ug of go. Since the Lie algebra go=81(2, R) has very simple commutation relations (Lie products among the elements of a basis of go), the classification of the representations Ug can be accomplished easily. Comparing these results with the differential representations of the unitary representations constructed in the preceding sections, we get the theorem stated at the beginning of this section.
Definition 1. Let A be a linear operator in a Hilbert space H withdense domain D(A). Let D(A*) be the set of all elements y in H for which there exists an element y* E H such that
CLASSIFICATION OF IRREDUCIBLEUNITARY REPRESENTATIONS
28 1
(Ax,y ) =(x, y*) for every x E D(A).
Then, since D(A) is dense in H, the element y* is uniquely defined by y. Put y* =A*y. Then A* is a linear transformation from D(A*) into H and is called the adjoint of A. Let A and B be two linear operators in H. Then B is called an extension of A, and this relationship is denoted by Ac B, if D ( A ) c D ( B )and Bx= Ax for any x E D(A). A linear operator H is called symmetric if H c H*. A linear operator H is called self-adjoint if H = H*. Propition 6.1. Let %=%(R) be the o-algebra of all Bore1 sets in R and E be a spectral measure on % in a Hilbert space 8. (cf. Difinition 3 in Ch. 111, 93) Put D(H)= {x E QlJ- PdllE(A)Xll’<
(6.1)
-m
+
00
1
Then there exists a unique linear transformation H from D ( H ) into 8 which satisfies (6.2)
( H X ,y)=lend(E(l)x, Y
)
for any x E D ( H ) and y E 8. Moreover the domain D ( H ) is dense in 8 and the operator H i s self-adjoint. ?‘roo$ The domain D ( H ) is dense in 8. In fact, for any x E H and E>O, there exist Q and b in R(a
bl>xlI <E (Ch. 111, Proposition 3.9,7)). And E([a,b])x belongs to D(H), because
IIx-
+
AldllE(1)E([a,b ] ) x l ~ z = j;c~ll~(A)xll’< ~ co a
-0
By Ch. 111, Proposition 3.12, a linear transformation H from D(H) into Since X =A,
8 is defined by (6.2).
(Hx, y ) =(x, Hy) for any x, y E D(H). Hence D(H)c D(H*) and H c H*, thus H is a symmetric operator. Now we prove that H I H * . Let y be an element in D(H*). Then for any a,b E R (a
E([Q,b])H*Y)=(HE([Q,b])z,V )
282
UNITARY REPRESENTATION OF
SL (2,R)
is a bounded linear form on 8. Hence the strong limit F=lim Fu.a: Z H U--*
/I-
rJ++-
~ d ( E ( l ) zy ,) is also a bounded linear form on 8. Therefore
(6.3) 1 ~ ~ z ) l S l l FIIzII<+CO ll for any Z E 8 . In particular, let x ~ be ~the . defining ~ ~ function of the interval [a, b]. Then (6.4)
z= T(Xr.,*&=r ldE(lllY
satisfies E([a,b])z=z and (6.5)
=r
F(z)=/ : i d ( E ( l ) z , y ) =
s:
Ad(E(l)z,y )
k q z , E(l)y)=IIzlla.
a
By (6.3) and (6.5), the element z in (6.4) satisfies llzlls IlFll. Hence
/:
l2~llE(Alyll2= IlzllasIIFIP
+ m , we get ladllE(l)yllasIIFIISC+ CO
for any a, b E R(a< b). Letting a+ - co and b-.
s_
and y E D(H). Since y is an arbitrary element of D(H*), we have proved that D(H*)c D(H). Since
v)=/I;d(E(l)z, v)
(2,H*y) = (Hz,
=S_-d(z,E(Rly)=(z, H r ) for any Z E D ( H )and y e D ( H * ) , we have proved that H*y=Hy and H*cH. q.e.d.
Definition 2. The self-adjoint operator H in Proposition 6.1 is denoted by (6.6)
H=
/--
ldE(R),
and is said to be associated with the spectral measure E.
Remark. Conversely, any self-adjoint operator H can be written as in
CLASSIFICATION OF IRREDUCIBLE UNITARY REPRESENTATIONS
283
(6.6). This fact is the well known spectral representation theorem of J. von Neumann.
Proposition 6.2. Let U be a unitary representation of the additive group R of real numbers on a Hilbert space 8. Then by Stone's theorem (Ch. 111, Theorem 3.2), there exists a spectral measure E on B=B(R) in 8 such that (6.7)
Let H=
1:-
ndE(;c)be the self-adjoint operator associated with E. Then
the following three conditions l), 2), and 3) for an element x E: H are mutually equivalent: 1 ) x E D(H). 2) lim t-l(UC- l ) x exists. c-0
3) The function tHUtx is differentiable everywhere on R . If x satisfies these conditions, then Ucxbelongs to D(H) and satisfies d -( Ucx)= iHUcx= iUcHx. (6.8) dt Proof.
1)*2).
First we observe that lei2c-ll$Inl It1 for any 2 , t E R .
(The length of a chord of a circle is shorter than the corresponding arc.) If x belongs to D(H), then I[(t-l(Ut- 1) - iH)xlls = /:mlt-1(e6tr - 1) - i2I2 d(lE(2)xlla
tends to 0 when t-0, because the function under the integral sign tends to 0 and is smaller than the integrable function 22' when It1 5 1. We have proved that 1 ) implies 2) and (6.8) for t=O. 2) => 1). Conversely, if x E H satisfies the condition 2), then lim Ilt-l(Uc- l)xlla=lim t-0
t-0
1-
It-1(et2c- l)lzdllE(R)xlla
-m
exists. Since the function under the integral sign has the limit P,it follows from Fatou's lemma that Ra is integrable with respect to ~ ~ ~ E ( ~ ) x ~ hence that x belongs to D(H). 1)53). If x satisfies the condition l), then Ucxis a differentiablefunction oft, because d Ucx)= lim s-l( Uc+,- Uc)x= Uc lim s-l( U,- l)x
x(
8-0
.
8-0
284
UNITARY REPRESENTATION OF
SL (2,R)
exists for any t E R. Since 2) is equivalent to 1) and 1) implies (6.8) for t=O, the right hand side is equal to iUtHx. 3)*2). This implication is trivial. Since UtE(A)=E(A)Ut for any A E 23,we have
S;n'dlls(n)u:xIl.
=
/I,
ladl I UtE(2)xlI S
=/~>2dIIE(4xI12.
Hence if x belongs to D(H), then U t x belongs also to D(H) (cf. (6.1)).
Definition 3. The self-adjoint operator H is called the infinitesimal generator of U. Proposition 6.3. Let U t =
R , T=/I:dE(I)
/I.
e"'dE(1) be a unitary representation ot
and xo be any element of D ( T ) . Then the function
x ( t )= Utxois the unique solution of the differential equation
2
---iTx
(6.9)
which satisfies the initial condition (6.10) x(0) =xo. Proof. It has been proved in Proposition 6.2 that x ( t ) = Utxosatisfies (6.9). (6.10) is trivially satisfied because x ( t )= Utxo.Let x l ( t ) be a solution of (6.9) satisfying (6.10). Then
=O
for any t E R .
q.e.d.
Proposition 6.4. Let U and V be two unitary representations of a connected Lie group G on the Hilbert spaces H and L respectively, and let U' and V' be the differential representations of U and V on the spaces H , and L, of C"-vectors for U and V respectively. Then U is equivalent to V if and only if there exists an isometry A of H onto L such that AH- = L, and AU'(X)x= V'(X)Ax (6.1 1)
CLASSIFICATION OF IRREDUCIBLEUNITARY REPRESENTATIONS
285
for any x E H, and X E g (the Lie algebra of G). ProoJ If Uis equivalent to V, then there exists an isometry A of H onto L satisfying A U,= V,A for any g E G. If x belongs to H,, then Ax belongs to L, and satisfies (6.11), because gHV,Ax=AU,x is a C"-function and AU'(X)x=lim A.t-l(Ut- I)x=lim t-l(Vt- 1)Ax= V ' Q A x . t-0
t-0
Conversely assume that there exists an isometry A of H onto L satisfying AH,=L, and (6.11). Put W,=A-'V,A for any g e G. Then W is a unitary representation of G on the Hilbert space H. Because of the assump tion AH, =L,, H, is seen to be the space of C"-vectors for W.Moreover, W'(X)x=A-'V'(X)Ax= U'(X)x €or any x E H, and X E g. Let XE Q and xo E H, and put iT= W'(X) = U'(X). Then both x(t) = Uexptxxo and y ( t )= WexptxXo are solutions of the differential equations (6.9) satisfying the initial condition (6.10). Therefore, by Proposition 6.3, we have x(t)=y(t) for all t E R. We have proved that UexptXX=A-l Je'rptxAX for any X E 0, any t e R and any x E H,. Since G is a connected Lie group, any element g in G can be written in the form g=exp Xl ... exp X,,, for Xi E Q Hence we have proved that U,x =A-1 V,Ax for any g E G and x e H,. Since U, and A-*V,A are unitary operations on H and equal to each other on a dense subspace H,, U,=A-lV,A for any g E G. q.e.d. Our classification of irreducible unitary representations of SL(2, R) is based on the following proposition. Proposition 6.5. Let U and V be two irreducible unitary representations of G=SU(l,l) (or Go=SL(2,R)) on W and L respectively, and let Ug and VK be the K-finite differential representations of U and V (cf. $5 Definition 6). Then U is equivalent to V if and only if there exists an isometry A of H onto L such that AHK =LK and AUK(X)x= VK(X)Axfor any x E HK and X E g . (6.12) Proof: By Theorem 5.2, we have H, 2 HK and L, 2 Lg and the restrictions UK(X)and V K ( X ) of U'(X) and V ' ( X ) to HK and LK respectively are defined. If U is equivalent to V, then there exists an isometry A of H onto L
286
UNITARY REPRESENTATION OF
S L (2,R)
such that AU,= V,A for any g E G. Then AHK=LK, because HK consists of all x E H such that dim(UexlkE K} < CO. Since Ug(X) and V g ( X ) are the restrictions of U‘(X) and V’(X) to Hg and Lg,we have A uK(X)x= VK(X>Ax for any x E HK and X E g by Proposition 6.4. Conversely, assume that there exists an isometry A of H onto L satisfying AHg=& and (6.12). Then again by Proposition 6.3, we get
+
A UexpgxX= VexptxAX for any x E Hg, X E g and t E R. The last equality implies that AU,= U,A for any g E G in the same way as in the proof of Proposition 6.4, because Hg is dense in H. Hence U is equivalent to V. q.e.d.
Proposition 6.5 is valid for any connected semisimple Lie group (Note that Theorem 5.2 is valid for any such group). Moreover, the following proposition was proved by Harish-Chandra [3], I.
Proposition. Let U and V be two irreducible unitary representations of a connected semisimple Lie group G and K be a maximal compact subgroup of G. Then U is equivalent to V if and only if Ug is equivalent to VK* Proof. Since we do not use this proposition later, we give an outline of proof. Let H and L be the representation spaces of U and V respectively. The “only if” part of Theorem can be proved similarly as in the proof of Proposition 6.5. Suppose that there exists a linear isomorphism A of HK onto Lg such that AUg(X)v= Vg(X)Av for all v E HK and X E g. Then for each R E g, we have A H K ( I )=LK(I).Since the representations of K induced on HK(R) and Lg(R) are unitarily equivalent each other, there exists an isometry B, of Hg(R) onto Lg(R) such that B , U k X = vkB,x for every X E Hg(R) and k E K. Since H&) (resp. L&)) is orthogonal to H&) (resp. LK(p))if # p , and since Hg (resp. Lg) is dense in H (resp. L), there exists an isometry 3 of H onto L whose restriction to H&) is equal to B, for each E I?. Let S be a linear isomorphism of HK onto itself defined by Sx=B-IAx (XE Hg). Then S and S-I leave Hg(R) and &(A) invariant respectively. Since dimHg(R) c + co , there exists a linear transformation S* of Hg into itself satisfying (S*x,y)=(x,Sy) for all x and y in Hg.Furthermore S*-1 exists and S* and S*-’ leave Hg(R) invariant. Put T= S*S. Then we claim that TUg(X)T-lx= Ug(X)x for all X E g and x E HK (*) First we notice that if X E g and x , y E Hg, then we have ~
(uK(X)X,Y)= -(x,uK(X)y) .
CLASSIFICATION OF IRREDUCIBLE UNITARY REPRESENTATIONS
287
Similar equality holds for VK.SinceBSVK(X)S-' =A UK(X)A-'B= Vg(X)B, we have for all x , y E HK and X E g (TUg(X)T-'x, y ) = (S*SuK(X)S-'S*-'x, y) =(SUJ?(X)S-1S*-'x, Sy) =(BSUg(X)S-'S*-'x, BSy) = (VK(X)BS*-lx, Ay) = -(BS*-'x, Vg(X)Ay)= - (BS*-'x, A UK(X)Y) = - (S*-'x, B-'A UK(X)Y)= - (S*-'x, SU,(X)y) = -(x, UK(X)Y)= (UK(X>X,Y ) . We have proved (*). Now choose xo E H&o) such that xo# 0 and TXO= cxo for some C E C . Since cIIxolla=(S*Sxo,xo)=IISx~l12>0,c is positive. Let U be the universal enveloping algebra of 9". Then it can be proved that the closure FV of W = UK(lI)xois invariant under U, for any g E G (cf. Prop. 6.9). Hence, by irreducibility, we get P = H . Since dim HK(R) c + co ,we have wn HK(R)=H&) for any R E 2 and W =HK. For each x E HK, there exists an element b E U such that x = U K ( ~ ) X Hence O. we have Tx=TUK(b)xo=U ~ ( b ) T x ~ = by c x (*) and IIAxll'=IISxll'=(Tx, x ) = cllxllp for all x E HK. Hence A is bounded on HK and can be extended to a bounded operator A on H. A satisfies llAxlla=cllxlla for all x E H . Hence c-lIaA= R is an isometry from H onto L. Moreover R satisfies RUK(X)x= VK(X)Rxfor all X E HK and X E g. Now we can prove that U is equivalent to V in a similar way as in the proof of Proposition 6.5. q.e.d.
Definition 4. Let U be a Banach representation of a Lie group G on a Banach space H. Then a vector x in H is called an anaIytic vector for U if the function ,t : gt-+U,x is an analytic function on G. Since U is strongly continuous, a vector x is analytic for U if the function g w c U,x, 'p > is analytic for each 'p in H* (Ch. IV, $5, LEMMA 1). The set of analytic vectors for U is denoted by H,. H , is a linear subspace of H contained in the space H, of C"-vectors for U. Proposition 6.6. The space H , of analytic vectors is invariant under U and U'. Proof. Let go be an element of G and x be an analytic vector. Then since the right translation Roo:g-rggo is analytic, the mapping RgOoR: gwU,,,x is analytic. Hence U,,x belongs to H,. Since the adjoint representation Ad is analytic on G, the mapping gwU,U'(X)x= U'(AdgX) U,x is analytic and U'(X)x belongs to H . for any X E g. q.e.d. Definition 5. For any XE g, we denote the restriction of U ' ( X ) to H . by U-(X). Then U, is a representation of the Lie algebra g on H.. U. can be extended to a representation of the universal enveloping algebra of g. U. is called the analytic diferential representation of U.
288
UNITARY REPRESENTATION OF
SL (2,R)
LEMMA 1. Let D be an elliptic differential operator with analytic coefficients on a real analytic manifold M and g be an analytic function on M. Iff is a C"-solution of the differential equation ( D- a)f= g, (6.13) for a constant a,then f is analytic on M . Moreover iff is a C"-solution of (6.14) (D ='")a 0 for some n E N,then f is analytic on M. Proof. By a classical theorem of S. Bernstein, a C"-solution of (6.13) is analytic. (For the proof of Bernstein's theorem, see F. John [I] p. 144.) The analyticity of a C"-solution of (6.14) is proved by induction on n. If n = 0, then f = 0 is analytic. Assume that n 2 1 and any C"-solution of (6.14) for n - 1 (in place of n) is analytic. Put g = ( D - a)J Then the function g satisfies ( D - a)"-'g = 0. Hence g is analytic by assumption. The original function f satisfies (6.13) and is analytic on A4 by the first q.e.d. half of the lemma.
2. Let G be a Lie group, K be a compact subgroup of G, and LEMMA
U be the universal enveloping algebra of g regarded as the algebra of left invariant differential operators on G. Then there exists an element D of U such that D is an elliptic differential operator on G and (Adk)D=D for every k E K. Proof. Since K i s a compact subgroup of G, there exists an inner product (X, Y) on the Lie algebra g of G which is invariant under AdK. Let X I , ..., X , be an orthonormal basis of g with respect to this inner product and put D=Xi'+ ...+X n 2 . Then (Adk)D= D for every k E K and D is an elliptic differential operator on G.
Proposition 6.7. Let U be an irreducible Banach representation of a Lie group G on a Banach space H, and K be a compact subgroup of G. If there exists an element 20 in (the set of equivalence classes of irreducible unitary representations of K ) satisfying Ocdim H(R0)c+ 00, the space H. of analytic vectors for U is dense in H. Proof. Since H. is invariant under U (Proposition 6.6), the closure I?, is also invariant under U because of the boundedness.of U,.Since U is irreducible, it follows that if H, f {0), then p-=H. Hence it remains to prove that H . # (0}. By Proposition 5.13, we have H, n H(lo)=H(Ao) and H , ~ H ( R ~Let ) . D be a differential operator on G as in Lemma 2.
CLASSIFICATION OF IRREDUCIBLE UNITARY REPRESENTATIONS
289
Since U'(D) commutes with Ukfor any k in K, the subspace H ( h ) is invariant under U'(D). Since dimH(Ro)c+ 00, there exists a basis XI, ..., xn of H(l0) such that for each i there exists at E C and an integer n > O satisfying (U'(D)-at)"xt=O ( l $ i $ n ) (Jordan normal form theorem). For any element q in the dual space H* of H, put A(g) =
'
Then since xrE H(Ao)c H,, we have
for any X in the Lie algebra g of G and
[(D- at)$] ( g )= < Ug( U'(D)- a$%,
q > =O
.
Hence the functionfi is analytic by Lemma 1. So the vector xi is a weakly analytic vector and hence an analytic vector by Ch. IV, $5, Lemma 1. q.e.d. Remark. It can be proved that for any Banach representation U of a Lie group G, H. is dense in H (Nelson's theorem). Cf. Nelson [l], GArding [2] and Warner [l]. Proposition 6.8. (Taylor's formula). If v is an analytic vector for U,then there exists an open neighborhood N of 0 in the Lie algebra g of G such that (6.15)
for any X E N . Proof. If we regard an element X of g as a left-invariant vector field on G, then for any H-valued analytic function f on G, we have
for any m E N. Hence the Taylor expansion of the function ti+f(gexp t X ) around t = O is given by
Sincef is analytic at e (the identity element of G), there exists a star-shaped of g and open neighborhood N of 0 in g with respect to a basis (Xr)lstrn
290
UNITARY REPRESENTATION OF
SL (2,R)
a power series P(xl,...,xn) convergent on N such that n
f(exp
(1XZJ)
...
=P(x~, ,xn)
I=1
for each X = c xtX, in N. Then we have f(exp tx)=P(txl,..., txn)=
- 1 1 -amt m!
m-0
for any t E [0, I]. Since dm
am=[&(exP
tx)lt-0=(Xmf) (e),
we get (6.16)
f(exp X ) =
1- Z1 ( X (e) ~J for)any x
E N.
me0
Now let v be an analytic vector for U.Then applying the formula (6.16) to the function 5 :gHUgv, we get (6.15), because
q.e.d. Proposition 6.9. Let G be a connected Lie group, U, the universal enveloping algebra of the complexification Q“ of the Lie algebra g of G, and let U be a Banach representation of G on a Banach space H. 1) If x is an analytic vector for U,then the closure U,(U)x of the orbit of x is invariant under U. 2) If L is a subspace of H , invariant under U,,then the closure I? of L is invariant under U. ProoJ 1) Let be an element in the dual space H* of H satisfying
< U,(z)x, (D> =O for any z E U. Let a be any element in U,(U)x; then a belongs to H,(Proposition 6.6) and there exists a symmetric open neighborhood N of 0 in g such that
uer, a =
- 1 1 -U,(x)ma m!
m-0
for any XE N.
CLASSIFICATION OF IRREDUCIBLE UNITARY REPRESENTATIONS
29 1
for any XEN. We can assume that the exponential mapping is a homeomorphism of N onto an open set Win G by taking a smaller neighborhood if necessary. Since the real analytic function f(g) = ( Uga,p) on G is equal to 0 on a non-empty open set W, f is identically zero on the connected group G. Hence we have U,a E -for all g E G by the Hahn-Banach theorem. 2) Let x be an element of L and g be in G . To prove that UgxE t,it is sufficient to show that for any E > O there exists an element y in L satisfying IIU,x-yll<s. Put M=IIU,II. Since U, is invertible, we see that M>O. Since x belongs to E, there exists an element z in L such that -=4(2M).
IIX-ZII
By l), we have
-~
u,z E U,(U)ZC
U,(U)LC
L.
Hence there exists an element y in L such that
I I u,z -A I <€12. So we have proved that
II ~ & - Y l l I;IIUP-
UozlI + IIU,Z-YII
<€124- €12=E. q.e.d.
3. Let H be a Banach space,f be an H-valued analytic function LEMMA on a Lie group G , and h be a complex-valued continuous function on a compact subgroup K of G . Then the function p(x) =
1
f (xk)h(k)dk
K
is analytic on G . Proof. Let xo be an element of G and {xl,..., x,) be a system of local coordinates on an open neighborhood N of xo.Since the function ( x , k ) t+ f(xk) is analytic on G x K there exists a finite set (U,),,A of open coordinate neighborhoods in K whose union is equal to K and a set of power series (Pa),cAsuch that
f(Xk)=P,(xi,
..., xn, kl, ..., k p ),x E N , k E U.,
where {kl,..., k p ) is a system of local coordinates on U,.Let 1 =Eva ucA
be a continuous partition of unity subordinate to the covering (U,)r.d. Then
292
UNITARY REPRESENTATION OF
SL (2,R)
is analytic on G.
q.e.d.
Propition 6.10. Let U be a Banach representation of a Lie group G on a Banach space H and K be a compact subgroup of G. Assume that the space H , of analytic vectors for U is dense in H (cf. Proposition 6.7). Then the subspace Arf
is dense in H. Proof. Let x be an element in H and E >0. Then, since H, is dense in H, there exists an analytic vector y E H, satisfying
I Ix -YI I <42. Moreover since the analytic vector y for U is a C"-vector for the restriction UlK of U to K, y can be expanded in the form Y=
c
EOlY
As2
by Proposition 5.1 1. There exists a finite subset I:of R such that
Put z=E(R)y. Then the function Z : gHUgz is analytic on G because I is given by the formula
io= /K 9 k 4 X.l(k)dk (Lemma 3). Hence E(R)y belongs to H , n H(I) for any R E E. We have E ( R )in ~ (He nH(n)) such proved that there exists an element w =
1
A
that Ilx-wll<e.
1 A
q.e.d.
Definition 6. Let K be a compact subgroup of a topological group G. A Banach representation U of G on H is called K-finite if dimH(;O is finite for every R E k An irreducible unitary representation of SL(2, R) is S0(2)-finite by Theorem 5.1. Proposition 6.11. Let G be a Lie group, K a compact subgroup of G and U be a K-finite representation of G on a Banach space H. If the space
CLASSIFICATION OF IRREDUCIBLEUNITARY REPRESENTATIONS
H. of analytic vectors for U is dense in H, then the space HK=
293
C H(R) 162
of K-finite vectors is contained in H , and HK is invariant under U,. Pro05 Since C ( H . nH(R)) is dense in H (Proposition 6.10), we can 1
prove that Ha n H(R) is dense in H(I) for each R E I? in a fashion similar to the proof of Proposition 5.13,l). Since dimH(2) is finite, H , n H(R)= H(A) and H , 3 H(R) for each 17 E I?. We have proved that
H,DC H(R)=HK. A
Since H g is invariant under U ' ( X ) by Proposition 5.13, it is invariant q.e.d. under Ua(X)= U'(X)lHI.
Theorem 6.1. Let U be a unitary representation of G = SL(2, R ) and K be SO(2). Then the following two conditions for U are mutually equivalent. 1) U is irreducible. 2) UK is (algebraically) irreducible. Proof. 1) 3 2 ) . Let L # 0 be a subspace of HK invariant under UK.Then we have (6.17)
In order to prove (6.17), it is sufficient to show that if a=
C
aj (a, E H(n,))
j-1
belongs to L, then each ar belongs to L . Since
Uexp tx,,aj=e
ttnj
aj ,
we have Ua(H)aj=njaj,
where H = -iXo.Since nj#nr ( j z k ) , there exists a polynomial PkE C[z] such that Pk(nj)==jr (1 rj,k s n ) .
Hence we have a / = UK ( P j (H))aE L for all j . (6.17) is proved. Since U is an irreducible unitary representation, U is K-finite (Theorem 5.1), and H. is dense in H (Proposition 6.7), the space HK is containcd in H, by Proposition 6.11. Hence Proposition 6.9 can be applied to L and
294
UNITARY REPRESENTATION OF
SL (2,R)
the closure 1 of L is invariant under U. Since U is irreducible and L # 0, we have E= H. Now we prove that L=Hg. Assume that L#Hg. Then by (6.17) there exists an element Ro in I? such that L n H(Ao)# H(Ro). Put L ( A ) =L n H(A) for each 1 E R. Then there exists a non-zero element x in H(&) satisfying W O ) ,x ) =o.
(6.18)
If R # , ? ~ then , H(R) is orthogonal to H(Ro)and we have (L(R),x)=O.
(6.19)
The equations (6.17), (6.18) and (6.19) prove that (L, x)=O. Since E=H, the last equation implies x=O, a contradiction. We have proved L = HK and Ug is irreducible. 2)=>1). Let L#O be a closed, U-invariant subspace of H and put Lg= ( L n H(A)). Then Lg is invariant under UK, because Lg is the
c
1.f
space of K-finite vectors in L for the representation UJL. Since UK is irreducible, Lg is equal to {0} or HK. Since L = @ LQ) by Ch. I , Theorem 2
3.1, L K = c L(A)is dense in L # {O). Hence Lg# [O} must be equal to 1
Hg. Since L g = H g = c H(A) is dense in H = @ H(A), L is dense in H. 1
1
Since L is closed, we have L =H. The irreducibility of U is proved. q.e.d. By Proposition 6.5 and Theorem 6.1, the classification of irreducible unitary representations U of G=SU(l, 1) can be reduced to the classification of the representations UK of the Lie algebra g of G. Now we start a closer study of irreducible unitary representations U and their infinitesimal representations UK. Proposition 6.12. Let g = Sn(1, 1). Then g consists of all the matrices of the form
’ ) aER,bEC.
(fi b -aiy
(6.20) The three elements (6.21)
form a basis of g. The Lie products between them are given by (6.22)
[Xo, X1]= - Y, [Xo, Y ] = X , ,
[Xl, Yl=Xo.
CLASSIFICATIOrJ OF IRREDUCIBLE UNITARY REPRESENTATIONS
295
The element o0=2-l( - X o a + X l a + Y a ) is the Casimir element of the universal enveloping algebra of g. ProoJ Since the Lie group G=SU(I, 1) consists of all matrices g e GL(2, C) satisfying g*elg=el
and det g = l
(cf. Proposition 1.6), the Lie algebra g=lu(l, 1) consists of all matrices X E M a ( C )such that X*elfelX=O and Tr X=O (cf. Ch. 11, Proposition 5.6.). Since el=
(A
_“l), this condition implies
(6.20). Hence the three elements in (6.21) form a basis of g. (6.22) can be proved by direct calculation. From (6.22) we get the matrix expressions of ad Xo, ad Xl, and ad Y with respect to the basis {XO, Xl, Y}.We see that (6.23)
-B(Xo,Xo)=B(Xl, Xl) =B( Y, Y)=2
and
B(X1, Y )=B( Y, Xo) =B(X0, Xl) =0
Hence 2-l( -Xoa+ Xla + YS) is the Casimir element of enveloping algebra of g. Definition 8. In the following, we let o=Xo’-X12-
Y2.
Proposition 6.13. Let U be an irreducible unitary representation of G = SU(1, 1) on a Hilbert space Hand put O = U‘(o).Then Q is a scalar operator on H,, i.e., there exists a real number q such that sZx=qx
ProoJ
for any
XE
H,.
Since U is a unitary representation, we get
(6.24) (U’(X)u,v) = -(u, U’(X)v) for any u, Y E H, and XE g by differentiating the relation, (Uexptxu,
Uexptxv)=(u,
v)
at t = O . Hence we have (6.25)
(Ou, v) = (u, Ov) for any u, v E H,
,
Thus O c O* and O is symmetric. For any g E G, the automorphism Ad g of g can be extended to an automorphism of the universal enveloping algebra ll of g. The extended automorphism of ll is also denoted by Ad g. Then
296 (6.26)
OF
UNITARY REPRESENTATION
SL (2,R)
(Ad g)w=(gXog-')' -(gXig-')' -(gyg-')' =gag-'="
because [X, 0]=0 for any X E g (Ch. 11, Proposition 5.14). On the other hand, we have (6.27) WgW'(X)Wg-lV= U'(Ad gX)V for any XE g, g E G and v E H,, because g(exp tX)g-'=exp(t AdgX). The equalities (6.26) and (6.27) prove that for any g E G and Y E H,. Let D be the set of all elements x in H such that there exists a sequence ( x ~ ) in~ .H,~ converging to x and for which the limit limQx,=y U,QUa-lv=Sav
n*+m
exists. Then a closed linear operator 0 is defined on D by setting 0 x = y . 0 is the so-called closure of Q. For any element g in G, we have (6.28)
U,D=D and U,Ox=OUax for any X E D .
In fact, let x , ( x ~ and ) y~ have ~ the ~ same meaning as above. Then the following limits exist: lim W,x, = Waxand lim OU,x, =lim UaSaxn= Uay = n*-
n-m
n--
UaBx.Hence Waxbelongs to D and QUax= U,Bx. Let W be the Cayley transform of the closed symmetric operator Q. W is defined as follows. The domain D( W ) of W is given by D(W)= (z=(B+i)xIxE D}
and W is defined by
+
-
W(O i)x= (0 i)x . Since (Ox, ix) = - (ix, a x ) by (6.25), we get (6.29) Il(a+i)xll2= I l D X l l ~ + IlxlJa=II(B-i)xll" Hence W is an isometry of D( W ) into H. By (6.28), we have Waz= Ua(O+i)x =(a+i ) Uax
for any z = (0+i)x E D( W ) , hence UaD(W )=D(W ) for any g E G . Moreover, we have (6.30) WUaz=W(B+i)U,x=(D- i)Uax = Ua(a-i)x= WaWz, for any z E D( W). If ( x ~ ) is~ a. sequence ~ in D( W ) converging to x , then (WX,,),,,~ is convergent because W is an isometry. Hence x belongs to D(W) and
CLASSIFICATION OF IRREDUCIBLE UNITARY REPRESENTATIONS
297
lim Wxn= Wx. This shows that D( W) is a closed subspace of H. Since U is n-oo
an irreducible unitary representation, the closed invariant subspace D( W) is either {0} or H. By (6.29), if (D+i)x=O, then x=O. Since D2D(L?)= Hm# {0}, D(W ) is not equal to {0} but is equal to H. Hence by (6.30) and Ch. I, Theorem 2.1 (Schur's lemma), W = C1 for some complex number c of absolute value 1. If we assume that Wz=z, then by writing z =(a+i)x, we see that (D-i)x = Wz=z =(a+ i)x and x =0, z =0. Hence c # 1. Then for any x E D, z =(0 + i)x satisfies
(a- i)x= Wz= cz=
c(B +i)x .
Hence we get
a x=q x for any X E D where q=i(l +c)(l -c)-l=Zj is a real number. In particular, for any q.e.d. x E H,c D, we have Px=qx.
Remark. Since the image Im W of W is a non-zero closed Ginvariant subspace, Im W is equal to H and W is a unitary operator on H. Hence 0 is a self-adjoint operator. Proposition 6.14. Let U be an irreducible unitary representation of G = S U ( l , 1) and put
H = -iUK(&), E= VK(XI)+I'UK(Y) and F= V K ( - X I ) + ~ U K ( Y ) . Then we have (6.32) [H,E ] = E [H,F]= -F and [E,F]=2H. (6.31)
Put (6.33) p m =q+ ( R +m- 1)(R +m) and urn=q+(R -m+ 1)(R -m) for m e N where q is defined by Q = q l (cf. Proposition 6.13). If X E HR satisfies Hx =Ax, then we have (6.34) HEmx= (2 +m)Ernx, HFrnx=(2 -m)Frnx, (6.35) FEmx=pmx, EFmx= amx and (6.36) IIEm+l~II' = ~ ~ + I ~ ~ IIFm+l~II2 E ~ x I I= ~ ~ m,+ l l l ~ " ' X I I
-
Proof. Since Ug is a representation of the Lie algebra g (Proposition 2.5), (6.32) is a direct consequence of (6.22). Using (6.32), (6.34) is proved by induction on m. Since 2Q= -2Ha+(EF+FE) and [E,F]=-2H,
we have
298
UNITARY REPRESENTATION OF
SL (2,R)
'
(FE+EF)x=2(q+la)x, (FE-EF)x =2Rx . Hence (6.37) (6.38) Replacing x in (6.37) with E*-'x and R with R+m-1, we get the first equality in (6.35). Similarly we get the second equality in (6.35) by replacing x in (6.38) with Fm-lx and R with R -m+ 1. By (6.24), we have (Eu, v)=((U=(Xl)+iU=(Y))u, v ) = - (u, (UK(Xl)- iUg( Y))v)= (u,Fv) for any u, V E Hg,. Hence IIFrn+lxlla =(Fm+lx,Fm+lx)=(F"x, E P + l x ) = o ~ + I ~ ~ F *" ' ~ I I ~ Similarly we have IIEm+l~IIa = pm+lllEmxI12. Definition 9. An eigenvalue of the operator H = -iUK(Xo) is called a K-weight of the representation U. Proposition 6.15. There exists no finite-dimensional unitary representation of G = S U ( l , 1) other than the identity representation. Proof. First we show that the Lie algebra g=Gu(l, 1) is simple, i.e., g has no ideal other than {0} and g. Let a be a non-zero ideal of g. Then a contains an element Z = a X o+ pXl + r Y# 0. If a #O, then a contains a-l [Xo, [Xl, Z]] =XI, hence it contains [Xl, Y] = Xo and [Xl, XO]= Y (cf. (6.22)). So a coincides with g. Similarly if p # 0 or r ;t0 we can conclude that a = g. Let U be a finite-dimensional unitary representation of G = SU(1, 1). Then the kernel ker U' of the Lie algebra homomorphism U' (the differential representation of U ) is either [0} or g. But it is impossible that ker U'= (0). In fact, if we assume that there existed a unitary representation U such that ker U'= {0}, then U' would be an isomorphism of g onto g1= U'(g). The identity U'([X, Y]) = [U'(X), U'(Y)] implies that ad U'(X)= U'oad XoU'-l. Hence the Killing form B, of g is transformed to the Killing form BS1of gl. Namely, Bp(X, Y )=Tr(adXad Y) =Tr(ad U'(X)adU'( Y)) =Be,(U'(X), U'(Y)). Hence the signature of B, is equal to that of BB1.The relations (6.23) show that the signature of B, is ( 2 , l ) . O n the other hand, since U is a
(6.39)
CLASSIFICATION OF IRREDUCIBLE UNITARY REPRESENTATIONS
-
299
unitary repesentation, U'(g) g1 consists of skew-Hermitian matrices. Hence every element X of g1 has purely imaginary eigenvalues. If the degree of U is equal to n, then ad,,X is the restriction of ad,l(,,oX to g,. Thus the eigenvalues of adQ,Xare differences of two eigenvalues of Xand are therefore purely imaginary. In particular we see that the quadratic form B,, is negative definite, i.e., the signature of Bo, is (0, 3). This con/ tradicts the equality (6.39). So our assumption is false and we have proved that ker U'= g for any finite-dimensional unitary representation U of G=SU(l, 1). Then by Ch. 11, Proposition 5.9, we have UeXptH=exptU'(X)= 1 for any t E R and X E g. Hence U,= 1 for any g E G .
q.e.d.
Theorem 6.2. Notation is the same as in Proposition 6.14. Let Ube an irreducible unitary representation of G=SU(l, 1) and M be the set of K-weights of U.Then M is equal to one of the following sets:
1) 2, 2)
1
+ 2,
3) Mn+= {n+plp E N )
4) M n - = { - ( n + p ) I p E N )
( n ~ 2 - ' N n>O), ,
There exists an orthonormal basis satisfying
(6.40)
Hym =mqJrn,
Fp,
= o,-'(q
(nE 2-'N, n>O),
((pm)mrM
Epm = wm+l(q
5 ) (0} .
of the representation space H
+ rn(m+ 1))'~m+l,
+m(m- l))tcpm-l
for any m E M ,
where q is determined by Q=ql and loml= 1. In case 5), U is the identity representation I . Proof. Since K z U(1) is a compact subgroup of G, the restriction UIK of U to K is decomposed into a direct sum of irreducible unitary representations 1% : ue-etne (n E 2-lZ). Each irreducible unitary representation zn is contained in UIK at most once (Theorem 5.1). Hence we have UIK= @ X n . nrM
If a non-zero vector x E H satisfies Uuex=etnexfor all e E R , then Hx= nx. Since H # {0} by the definition of irreducible unitary representation (Definition 4 in Ch. I, $2), the set M is not empty and there exists an element A E M and a unit vector x E H such that Hx = Ax. There are four possibilities for the vanishing of Emx and Fmx. A) Emx#O and Fmx#O for all m E N . B) Ekx=O for some k s N and Fmx#O for all m e N . C ) E*x#O for all m e N and Fkx=O for some k e N .
300
UNITARY REPRESENTATION OF
SL (2,R)
D) E%=O for some kE N and Fnx=O for some n E N . In any case, the subspace L of HK spanned by {Emx,F " x } , , ~ is invariant under UK and must be equal to HK because UK is irreducible by Theorem 6.1. Since H K is dense in H, the non-vanishing vectors in {Emx, F m ~ } m ,form N an orthogonal basis of H. Hence we have M = [2+ml Emx#O} u [R-mlFmx#O}. Since 22 is an integer, we divide the case A) above into two subcases A.l) and A.2) according to whether 22 is even or odd. The case A.l) Since R is an integer and Emx#O and Fmx#O for all m E N, we have M = { J f m l m E N } = Z (the set of all integers). Since p,#O and am#O for all m E N in the case A), we can replace x with E2x if A
(6:41)
rm=
npn+and
n-1
m
tm=
nun+,
n-1
where pa+ and a,,+ are the positive square roots of pn>0 and in (6.33). Since 2=0 in our case, pm=q m(m - 1) = urn (cf. (6.33)) and r, = t , . (6.42)
un>0
given
+
The condition that rm>O for all m E N implies that q+m(m- 1)>0 for all m E N. The latter condition is equivalent to (6.43) q>o. Now we introduce an orthonormal basis ( P , ) ~ ~ Zin the following way. mX, (mE N , m l l ) , (6.44) ( D O = ~ O X~, m = r m n - l ~ m E+m=tm-l~-mFmx where 71m may be an arbitrarily chosen complex number of absolute value 1. By Proposition 6.14 and (6.42), the basis (p), satisfies the equations (6.40). The case A.2) 1 In this case the set M of K-weights is equal to - 2. Hence we can 2 1 assume that R =-. The equalities (6.41) remain unchanged. But the values 2 of p,,, and urnare given by
+
(6.45) p m = ( q - 71) + m 3
and a m = ( q - + ) + ( m - l ) a
Since Emx#O and Fmx#O for all mE N , p m > O and a,>O Hence we have
for any mL1. for all m E N.
CLASSIFICATION OF IRREDUCIBLE UNITARY REPRESENTATIONS
301
(6.46)
in this case. We obtain an orthonormal basis (pm)mtYby means of the following definitions: (6.47)
pi=viX, vt+n=rn-'vi+nE"x,
vi-n=tn-lvi-nFnX
(n E N , nr 1).
The relations (6.40) still hold in this case. The case B) There exists an integer k>O such that Ekx=O. Then Ehx=O for all h z k . Let h + l be the smallest integer for which this occurs. Then x, Ex, ..., Ehx are not equal to 0 and p l > O , ..., p h > O , p h + l = O by (6.36). Hence FmEhx#O for all m E N.So we can replace x with Ehx and assume that Ex =0. We have pl =0 and hence (6.48) q=-1(A+l) by (6.33). The value of urnis given by (6.33) and (6.48). urn=m(m - 1 -21) The condition that u,>O for every rnz 1 is equivalent to the condition (6.49) 1
v-n=v-nX,
p-(n+p)=tp-lv-(n+p,FPX.
The equations (6.40) still hold with the following convention: The equation for E p n containing the undefined vector p-(n-l) should be interpreted as E p n=0. This convention is justified because the coefficient of is equal to 0 by (6.48). In this case, we have (6.51)
q=n(l-n)
.
The case C) The case C) can be treated in the same way as the case B). We can start with x satisfying Fx=O. Then we have u1 =0, q= -1(A - 1) and prn= m(21+ m - 1) >0. Hence (6.52) 1>0. Put ~ = n .Then (6.51) still holds. The set M of K-weights is equal to {n+plp E N) . An orthonormal basis (pm)mnrM is defined by (6.53)
( ~ n = p n ~p n, + p = r p - l p n + p E P X
-
302
UNITARY REPRESENTATION OF
SL (2,R)
The equations (6.40) remain valid with the convention that the equation for Fp,, is interpreted as Fp,, =0. The case D). In this case, the subspace V spanned by the vectors {Emx( O $ m i k - l), Fmx (0 5 m 5 n - 1)) is a finite-dimensional subspace of H invariant under UK.Since VKis irreducible (Theorem 6.1), V must be equal to HK. Since HR= V is dense in H and a finite-dimensional space V is closed, we have V = H. Hence U is a finite-dimensional, irreducible, unitary representation of G=SU(l, 1). So U is the one-dimensional identity representation by Proposition 6.15. The cases Al), A2), B), C) and D) correspond to the cases 1), 2), 4), q.e.d. 3) and 5) in the theorem respectively.
In the course of the proof, we have proved the following corollary. COROLLARY to Theorem 6,2. The eigen-valueq of thecasimir operator $2 satisfies the following conditions in each of the correspondingly num-
bered five possible cases 1) to 5) in Theorem 6.2: 1) q>o, 2) q>+, 3) q=n(l-n), 4) q = n ( l - n ) ,
5) q=o.
An important consequence of Theorem 6.2 is the following fact: An irreducible unitary representation U of G = SU( 1, 1) is uniquely determined up to equivalence by the set M = M(U) of K-weights and the eigen-value q =q( U)of the Casimir operator SZ. In fact, we have the following theorem. Theorem 6.3. Let U and V be two irreducible unitary representations of G = SU( 1, 1). Then U is equivalent to V if and only if M( U )=M( V) and q(U)=q(V) where M ( U ) and M ( V ) are the sets of K-weights, and q ( U ) and q(V) are the eigenvalues of the Casimir operator SZ for U and V respectively. Proof. It is clear that if U is equivalent to V, then M( V )= M( V) and q(U)=q(V) (as to the second equality, cf. Proposition 6.4). Conversely, assume that M ( U )=M( V) = M and q( U )=q( V )=q. Then by Theorem of H ( U ) and of 6.2, there exist orthonormal bases (p,JmrMand (v'~),,,~~ H ( V ) satisfying the relations (6.40) with the family of constants ~ ~ any ~ family . ( c ~ ) of ~ .complex ~ numbers Cm of absolute and ( o ' ~ )For value 1, an isometry A of H ( U ) onto H ( V ) is defined by
-
(6.54) Apm=cmpm' (m E M ) Since A satisfies A UR(- iXo)pm=mcmpm'= VK(- iXo)Apm AU=(X~+iY)p,=om+icm+i(m(m+ 1)+q)'pm+i'
CLASSIFICATION OF IRREDUCIBLEUNITARY REPRESENTATIONS
Vg(Xi + i Y ) A p m = w m + l ’ c m ( m ( m +
and
A Uk( -XI + i Y ) p r n = w m - ’ c m - l ( m ( m VK(
303
1)+q)+vi+l’ 1)
+ q)*pm-<
-XI + i Y ) A y m = wm’-lCnr(m(m - 1) +q)+ym-i’,
the operator A satisfies (6.55)
AUK(X)vm= Vg(X)Aym
for any X E a and m E
if and only if (6.56)
Cm+l/Cm=~m+l’/wm+l
for every m E M
.
Hence if we fix an element m o E M and choose a complex number cmo with the absolute value 1 and define the other cm’s by (6.56) and the operator A by (6.54), then A satisfies (6.55). Therefore U is equivalent to V by Proposition 6.5. q.e.d. In the following Theorem 6.4 we give M and q for the irreducible unitary representations constructed in $2, $3, and &I.
Theorem 6.4. The sets M of K-weights and the eigenvalue q of the Casimir operators Sa for the irreducible unitary representations of $2, $3, and $4are given by the following table:
*t
s(1 -s)
n(1 -n) n(1 -n) u(l - u ) 0 Proof. Let n be an element in $2.Then n is a weight of U if and only if there exists a vector x#O in the representation space H of U such that
UUex= etnex. 1) V’.’. Since an orthonormal basis { fn(<) =C-” In E Z } of &? satisfies t6.57) VuBJ*S fn =et(n+f)@f n , the set M of weights is equal t o j + Z (cf. Theorem 2.1). By Proposition 2.6, we have (6.58)
Hence
Efn= { Vg’.’(Xl)+iV~’.‘(y)~fn=(n+j+s)fn+l Ffn = { - Vg’s’(X1) iVg’J( Y ) )fn =(n + j - s) f n - 1
+
.
304
UNITARY REPRESENTATION OF
(6.59)
SL (2,R)
2Qfn=(-2H2+EF+FE)fn = {-2(~~+j)~+(n+j-~)(n+j-l+~)+(n+j+~)(n+j+l-~)}fn =2s(l - S ) f .
2) PI+. By (6.58), the set of weights for V+*+IQ+ is ++N, because 8' is spanned by {fnln E N ) Similarly, since 8-is spanned by { f - J n E N, n z l } , the set of weights for ?".+1@is equal to - 4 - N . By (6.59), D=dY'**(W)=+l. 3) U".Let n E +Z (n2 1) and let Unbe the discrete series representation of G on the Hilbert space Qn or Q-,,described in $3. Then {@,"(C)= {r(2n+p)/(r(2n)r(p+l))}*CpJpE N ) is an orthonormal basis of Qn and {@lp E N} is one of Q-n. By Proposition 3.5,
.
Uu8nQjn =e-t(n+p)rQj n,
u,,#-ne=eNn+pM-n@P .
Hence the set M of weights is equal to - n - N for U n and n+ N for U-". By the definition of Un,we have Uexptgln@pn(C) = { r ( 2 n+ p ) / ( r ( 2 n ) r ( p+ l))} +( - sh2-ltc +~h2-lt)-'~-p x (ch2-ltt;- sh2-lt)p and V,"(X,)@pn =2-'J(2n + p ) ( p+ l)@p+P-2-'J(2n + p - 1)pOp-l.
*
Similarly
U",( Y p p n = -i2-'J(2n +p)(p + 1)Op+P-2-'iJ(2n + p - l)pQjp-ln. Hence we have (6.60)
EQjP"
=J ( h + p ) ( p
+ 1)
@P+ln 9
Fopn= J ( h+ p - I)p Qp-1"
-
We have
+
+ +
2QQp"= { -2(n +p)' (2n +p)(p 1) (2n + p - 1)p)OPn =2n( 1-n)Op" .
For the representation U-n=dJn~, put q = K - P n . Then we have U,-~(Xl)K-p* =2-1J(2n +p)(p + 1)K-p-ln -2-'J(2n + p - l)pK--p+ln Y)K-," =i2-1J(2n +p)(p + 1)K-p-1n +i2-'J(2n + p - 1)pK-p-ln
u,-q and (6.61)
Therefore
EB-," = -J(2n+ p - 1)p K-p+l. FK-p" = -J ( b+p)(p + I) V-p-1.
CLASSIFICATION OF IRREDUCIBLE UNITARY REPRESENTATIONS
+
+
305
+
252Y-," = { - 2(n + p y (2n + p - 1)p (2n + p ) ( p I)) K-," =2n(l -n)!F-p".
P.Since VgU=V:*' on HK which is spanned by (fn(C)=C-nln E 23, the results in 1) hold in this case. Hence the set of &weights is equal to 2 and Q=u(l -u)l. 5) I. If l i s the identity representation gi-1, then M = (0) and q=O. q.e.d.
4)
Theorem 6.5. (Bargman) Any irreducible unitary representation U of G = S U ( l , 1) (or of SL(2, R ) ) is equivalent to one and only one of the following representations. 1) 2) 3) 4) 5) 6)
Vj*';;j=O,8, s = & + i v , v ~ ifj=O, O v > O i f j - 4 (cf. $2), V***l.jj+ (cf. Theorem 2.1), V'*'I@-, un;n E gz, In1 e 1 (cf. 43), v-;+ < u < 1 (cf. @I), Z (The identity representation).
Proox Let U be an irreducible unitary representations of G =SU(1,l). Then by Theorem 6.2, the set M of K-weights of U coincides with one of the following sets.
*
i) z, ii) + Z , iii) M,,+ = {n+pip E N } (nE )N,n>O), iv) M n - = ( - ( n + p ) I p ~ N ( ) n ~ i N , n > O ) ,V) (O}. i) If M = Z , then q > O by Corollary to Theorem 6.2. We divide the case i) into two subcases La) and i.b) according to whether qz&or O f . In this case there exists a unique real number Y >0 such that q= 4 +v2. Put s = + + i v . Then M(U)=M(V+**)and q(U)=q(V+.*). Hence U is equivalent to V+s0by Theorem 6.3. iii) M =M,+, q =n( 1 -n) (n E 2-lZ, n >0). We divide this case iii) into two subscases iii.a) and iii.b) according to whether n = 8 or n > &. iii.a) M=M++,4 = f . In this case M(U)=M(V*.*&j+)and q(U)=q(V+**IQ+). Hence Uis equiva-
+
306
UNITARY REPRESENTATION OF
SL (2,R)
lent to V*.*1$+by Theorem 6.3. iii.b) M=Mn+, q=n(l -n) ( n ~ 2 - ' 2 ,n>)). In this case, M(U)=M(U-n) and q(U)=q(U-^) (cf. Proposition 6.10 and Corollary to Theorem 6.1). Hence U is equivalent to U-". iv.a) M = M , - , q = ) . In this case U is equivalent to V**+ I$-. iv.b) M=M-,-,
-7.
q=n(l -n) (.E 2-'2, n < y
In this case U is equivalent to Un. v) M = {O}, q=o. In this case, U is the identity representation as was proved in Theorem 6.2. Since the pair (M(U), q(U)) takes different values for the different representations enumerated in Theorem 6.4, no two of them are equivalent to q.e.d. each other by Theorem 6.3.
$7 Thecharacters The character of an irreducible unitary representation of the Euclidean motion group M(2) was defined as a distribution on the group. (Ch. IV, $3.) Similarly, the character of an irreducible unitary representation U of G = SU(1, 1) is defined as a distribution on G.Namely, for any complexvalued C"-function f on G with compact support, the operator n
(7.1) belongs to the trace class, and the mapping fHTr U, is a distribution on G. We shall calculate the characters of the representations of G which belong to the principal continuous series, the complementary series, and the discrete series. It turns out that the characters of these representations are functions on G. Proposition 7.1. Let 9 ( G ) be the space of all complex-valued C"functions with compact supports on a Lie group G, U be a Banach representation of G on a Banach space H and V be the uniform closure of the subspace ( UfI f € a ( G ) ) in B= B(H) (the Banach algebra of bounded operators on H). 1) Put f,(A)= U,A and r,(A) = A U,-l
for g B G and A E V. Then I and r are Banach representations of G on V.
307
THE CHARACTERS
The operator U, (f E 9 ( G ) ) is a C"-vector for the representations I and r. Let L and R be the left and right regular representations of G and I', r', L', R' be the differential representations of I, r, L,R respectively. Then we have
l'(Ddr'(D4 U,= U L * C D ~ ) R , C D ~ > ,
(7.2)
for every f in d ( G ) and for all D1and Da in the universal enveloping algebra U(g) of the Lie algebra g of G. 2) Let K be a compact subgroup of G, let A be an element of the dual R of K, and let d(A) and x1 be the degree and the character of 1. Let E(R) be the projection defined by
sg
E(R)=d(A)
(7.3)
xA(k-l)U&
and let Et(A), &(A) be the similarly defined projections for the representations I and r. Then we have B ( I ) ( A )=E(A)A and Er(R)(A)=AE(A'),
(7.4)
where 1' is the class contragredient to A. Proof. 1)The operators I, and r, leave the subspace Vinvariant because W
(7.5)
1
f =
f(g1)U,,,dg1=
ULgf
and
1 0
r a ( u f ) = / f(gl)Ug1o-'dgl= u R g / . Since ~ ~ l , ( A ) l 1 5 ]IIAll, / U g ~I,~ is a bounded operator on V. It is clear that I and r are representations of G on V. Now we prove that I is strongly continuous. Take an element A in V and a positive number E . Then there exists a functionfin S ( G ) such that
(7.6) IlU,-4I<~ * Let N = N-1 be a compact neighborhood of the identity e in G and put M = sup 11 Ugll.Then for every element g in N, we have arN
ll~g(A)-~g(~f)ll 5 IIugll ~ ~ 6Mf ~. ~ f (7.7) Since the support C off is compact, f is uniformly continuous on G. Hence, if the neighborhood N of e is sufficiently small, we have
(7.8)
[f(g-'g1)- f(gl)l < S
for all g E N and gl E G.
For any g in N , the function p(gl)=f(g-'gl)-f(gl) vanishes outside of the compact set NC. Put D = sup ]~Ugl~l. Then we have 91cNC
~
~
308
UNITARY REPRESENTATION OF
SL (2,R)
for every g in N. By (7.6), (7.7) and (7.9), we have
5 IIUuA- U,U,ll+ l l ~ u ~ , - ~ A l +I1u,- All
ill,(A)-All
$(M+l)E+BE.
Hence 1 is strongly continuous at e. Hence, by the inequality
l l ~ , o ~ ~ ~ - ~ 5, ~II U, ~ ll~ llll,-1,o(~)--~Il l and by the fact that G is locally-compact, 1 is strongly continuous on G. Similarly r is strongly continuous. A C"-function f in g ( G ) is a C"-vector for the regular representations L and R.Hence by (7.5) we see that U, is a C"-vector for 1 and r and that U, satisfies (7.10) I'(X)U,= ULl(H), and r'(X)U,= URlta,, for every X in g. Hence we have (7.2). 2) For each element A in V, we have E(l"
= d ( q xJC-l)b(A)dk K
= d(,?)s x1(k-l)UkAdk=E(,?)A and K
SK
Ev(A)(A)=d(A)
xA(k-')A Uk-ldk
=d(;l)
~r(k-')AUxdk=AE(I').
S R
Proposition 7.2. Let G = SL(2, R),K = S0(2), and U be a Banach representation of G. Then the series
(7.1 1)
2
IIE(n)U.rE(m)ll
n.rn.2-12
converges for every f in 9 ( G ) . Proof. Let n be a half-integer, i.e. n E 2-lZ. Then x,, : uBHeinois an irreducible unitary representation of K and the dual k of K is identified with 2-'2 naturally. Let V be the uniform closure of the subspace [Ufl f E g ( G ) } and W be the Banach representation of G x G on V defined by W(,,,,(A)=U,AU,-' If n and m belong to 2-'Z=k, then
for A E V.
THE CHARACTERS
309
is the projection corresponding to the irreducible representation x,,&,,, of K x K. By Proposition 7.1, we get (7.12) F(n, m)(A)=E(n)AE(-m) . Iff belongs to g(Q, then the operator U, is a C"-vector for W.Hence the series
converges absolutely (normally) by Proposition 5.11. The equality (7.12) and the last stated result imply that the series (7.11) converges. q.e.d.
Definition 1. Let G be a a-compact Lie group, g be the Lie algebra of G, and U=U(g) be the universal enveloping algebra of g. Then for any DEU,
P d f 1 = SUPl(Df >(4l arG 9
fE9 ( G )
be is a seminorm on 9 ( G ) . Let C be a compact subset of G and the subspace of g ( G ) consisting of all functions whose supports are contained in C. Then s c ( G ) is a FrCchet space when supplied with the family of seminorms {pDIDE Ll} . Since G is 0-compact, there exists a of compact subsets of G whose union is equal countable family (QnrN to G. We give to g ( G ) the structure of topological vector space defined as the strict inductive limit of the spaces 9 c n ( G ) (cf. Ch. 111, $4, Definition 6). This topology of S ( G ) is independent of the choice of (C"). A continuous linear form on S ( G ) is called a distribution on G. Put f"(x)=f(g-'xg) for each g E G and f E 9 ( G ) . A distribution T on G is said to be central if (fa, T)= (f,T) for every g E G and f E d ( G ) .
Theorem 7.1. Let G = SL(2,R), K = S0(2), and U be a unitary representation of G on a Hilbert space H. If there exists a constant a such that (7.13) dim E(n)Hg a for all n E 2-'2= R , then, for every f in s ( G ) , the operator U f is of trace class and the linear form Ow:f w T r U f is a distribution on G. The distribution Ow is central. Proof. By the orthogonality relations, we get
310
UNITARY REPRESENTATION OF
= Gn,mE(n)
SL (2,R)
-
Hence E(n)H is orthogonal to E(m)H if n f m. Collecting the orthonormal bases (ea)x,rCn) of all non-zero E(n)H, we get an orthonormal basis (ek)ktI of H where I= u I@). Hence we have by Proposition 7.2, n
5
c c
dim E(n)H dim E(m)HIIE(n)U,E(rn)ll
n,rnr!l-lZ
sus
iIE(n)U,E(m)li-=
+ co
for all
SZ(G).
n.me2-12
Hence U, is of trace class by Lemma 1 in Ch. IV, $3. Let Xo be the element of the Lie algebra t of K such that exp 0x0 and put Do=Xo*. Since
Us=
I(ue)E(n)U, =efnbE(n)UI, we have
(7.15) I'(Do)E(n)U,= -n'E(n)U,. In this proof, contrary to our usual convention, we regard an element DO in the enveloping algebra U as a right invariant differential operator on G.Then we have (7.16) L'(DY= Df for any f E g ( G ) . Since t is commutative, Ec(n) commutes with Z'(D0). Hence by (7.15), (7.16) and by Proposition 7.1, we have (7.17)
and
E(n)UDo/=E(n)l'(DO)U/=--n'E(n)U~.
31 1
THE CHARACTERS
1
(7.19)
II~(W311SNII~Do311 3
nd-w
n-l+l)<+ m .
where N = M ( ma-1Z
n+O
By the first equality in (7.14) and by (7.19), we have
(7.20)
IT^ u315
C C nca-lZ
s
I(E(WA,
a)i
XrZCn)
1 d i m ~ ~ ~ ) ~ I I E ( W 3 cI I s IIE(n)ufII a nra-tz
nrl-12
SaNII U D ,. ~ Let C be a compact set in G and (fn) be a sequence in s ( G ) converging to 0 such that eachf, vanishes outside of C. Then, since (1 U,ll is bounded on C, we see that
I l u ~ ~ nSl I I(Dfn)(g)lIIU~ll&-iO s f 3
as n - i m for every D in U. Therefore by (7.20), we have
, ~aNll UD,,D~,II -i0 ITr U D J 5 as n-i co for every D E U. We have proved that Ow :f H T r U3 is a continuous linear form on 9 c ( G ) . Since C is an arbitrary compact set, @' is continuous on the strict inductive limit s ( G ) (Ch. 111, Proposition 4.2). Hence Ou is a distribution on G. If ((D&N is an orthonormal basis of H , then orthonormal basis of H for every g E G.
Since
Uf = f(g-'xg)U,dX J a = U,UfU,--t,
=
(Ug-1pn)nrN
is another
JQ
f(X)U,,,-ldX
by Lemma 1 in Ch. IV, $3, we have Tr U p = T r U3 for all g E G and f E g ( G ) . Hence the distribution Ow :fw Tr U3 is central.
q.e.d.
Definition 2. The distribution Ow :f H T r U3 is called the character of the representation U. Example. If U is a finite-dimensional continuous representation of G, then the (distributional) character Ow of U coincides with the usual r This can be seen from character of U, namely, the function xu : g ~ T U,. the equality Tr U3=
312
UNITARY REPRESENTATION OF
S L (2,R)
Now we proceed to the explicit calculation of the characters of irreducible unitary representations of G=SU(l, 1). First we treat the principal continuous series representations VJ.' (j=O, 4,s E C) which are not unitary unless Re s=*. We use a modified realization Wj.' of VJ.*.The realization W j .* is more convenient for the calculation of the character than the original realization Vj.*. For each s E C,there exists a Banach representation W' of G=SU(l, 1) on the Hilbert space La(K), defined by (7.21) ( Wglf)(u8) =e-*tQ-l* of(ug-1.0) . For each j E {0,41, we define a projection operator E, on H = La(K) by the formula (7.22) Clearly we have
(E,f)(u)=2-' If(4+(-l)a'f(-U)l
-
+
(7.23)
Eo E*= 1, EoE, =EiEo =O , EoH= {fe H l f ( - u ) = f ( u ) } , and E+H= (feHlf(-u)=-f(u)} .
Proposition 7.3. The equation (7.21) defines a Banach representation W * of G = S U ( l , 1) on H=La(K). For each j E (0, h), E, is a projection operator and commutes with every Woa.Hence Wg8induces a Banach representation Wj*' of G on the invariant closed subspace E,H of H. Let A , be a linear mapping from La(U)onto E,H defined by
(7.24) ( A f ) ( u e )=e-*J8f(e"). Then A j is an isometry of La(U)onto EjH and satisfies (7.25) A j o Vgf*'=Wgj$ao A , for every g E G and every j and s. Proof. It is clear that E, is actually an orthogonal projection. Since us== -1 belongs to the center Z of G,we see that guo+l. = ul.gu0 =u,~+alatco,omcg.~) .
Hence we have (7.26) g - ( 8 + 2 x ) r g . 8 + 2 ~mod 4x, t(g, ~ + 2 ~ ) = t ( gB ), . Therefore, E,oWO*=Wg'oE, forall g e G . Moreover we have u(g, 0) =ef(-W+@)lZ=u (g, 0 +2 4 (7.27) by (7.26). By (7.26) and (7.27), we have
THE CHARACTERS
313
-In the following, dg denotes the Haar measure of G-SU(1, 1) described in Proposition 5.1, i.e., 1
if g =usacne . dg =-etdedtdt 4a Moreover, du, da, and dn denote the measures (47r)-ldS,dt, and d f , respectively, where u =U s , a =at and n =ne.
(7.28)
hposition 7.4.
For every function f i n g ( G ) , the operator w3.E/of(g)wg.dg
is an integral operator on H=La(K) with the integral kernel L3(u, v) =
(7.29) Proof.
/
f(uarnV-')ea8dtdlt. AxN
It is easily seen that
(7.30)
t ( p s - ' , S ) =t
if g = vatne
is the Iwasawa decomposition of g. By a direct calculation, we have (7.31) a,-'ntat =ns-tc . Put u=ur. Then by (7.30)and (7.31), for every f in 9 ( G ) and for F in
N- La(K),we have (W3aF)(u) =[ol(g-')(Wg-'.F)(u)dg =
f(g-')e-"'"."'F(ug.~~g
I.
=
f(usg-')e-at(gu,-l*# ) F ( U ~ > ~ S
314
UNITARY REPRESENTATION OF
SL (2,R)
q.e.d.
where Lf(u,v) is given by (7.29).
Proposition 7.5. (7.32)
For every f in S ( G ) , we have
{IKxAxN
Tr (Wf'Ia) =y
+(-
f(uunu-l)e*cdudadn
1.
f(u(-u)~u-l)e*cdudadn
1)aj/ KXAXN
Proof. Put Xn(uB)=e*ne for each n E 2-lZ. Then xn belongs to EoHif and only if n E Z . We see that (7.33) TrWfjJ=Tr(EjW,*) for j = O , 4 and S E C , because
C
Tr Wf0**= (Wf'Xn,
Xn)=
C (Wj*EoXn,EoXn) nra-iz
nrl
=Tr (EoWf *Eo) =Tr (EoW fa ) ,
*.
and similarly Tr Wf * =Tr (E, W f'). By Proposition 7.4, we see that (EjWf'F)(u) =2-1 {( Wf'F)(u)+(- l)'j( Wf*F)(-U)} =2-'{/
f(uanv-l)e*tF(v)dvdadn KxAxN
+(-I)"/
f(u( -a)uv- l)e*'F(v)dvdadn KXAXN
I.
Hence EjW f* is an integral operator on H=L'(K) with the integral kernel (7.34)
MfjJ(Z4, v)=2-'
f(uamv-l)e*tdtuh {JAXN
+(-
1)"s
AXN
f(u(-o,)nlrl)e*tdtdn)
.
Since MI is a C"-function on K x K, the trace of the operator EjWf * is given by (7.35)
Tr(EjWf*)=
u)du Mfj@*(u, J K
THE CHARACTWS
315
(Ch. IV, Proposition 3.5). By (7.33), (7.34) and (7.35), we get (7.32). q.e.d. Now we shall prove that the right hand side of (7.32) is equal to the integral
IQf
(g)@j.’(g)dg
for some function @ I * a on G. This fact implies that the distribution f~ Tr ( W / J ) (cf. Theorem 7.1) is equal to the function W J . To prove this, we need some integral formulas on G. Definition 3. Let X be a locally compact Hausdorff space. Then the space of all complex-valued continuous functions on X with compact supports is denoted by L(X).
LEMMA 1. Let G be a locally compact group and H be a closed subgroup of G. For any functionf in L(G), put
f”(E)=/
f(gWh9
€ I
where dh is a left Haar measure on H and g = g H . 1) Then the mapping f H f is a linear mapping from L(G)onto L(G/H). 2) If GIH has a G-invariant measure d g f 0 , then we have O
(7.36)
for every f in L(G), where dg is a suitably normalized left Haar measure on G. Proof. 1) It is clear t h e y belongs to L(G/H). Hence it is sufficient to prove that for any F i n L(G/H),there exists a function f in L(G) such that f” =F. Let C be the support of F and V be a compact neighborhood of e in G. Then there exists a finite number of elements ( g f ) l s f s nin G n
such that the image of the set C1=u g t V by the canonical mapping r : %=1
g H g = g H contains C. Put C O = X - ~ ( n C el. ) Then COis a compact set in G satisfying n(CO)=C. Let U be an open neighborhood of Co whose closure 8 is compact. Since the underlying space of a topological group G is completely regular, it follows that for each point x in Co,there exists a continuous, non-negative function f z such that f z ( x ) = 1 and f z = O on G - U. Since fs >0 on a certain neighborhood U, of x and the compact set Co is covered by a finite number of Uz’s, there exists a function foin L(G) such thatfoZO on G andfo>O on Co.Put
316
UNITARY REPRESENTATION OF
SL (2,R)
Then f belongs to L(G) and satisfiesf " =F. 2) Since the linear form
is a positive Radon measure on G and satisfies O(L,f)=O(f) for all g E G. Hence O is a left-invariant Haar integration on G.
Proposition 7.6. Let G=SU(l, 1) and G=KAN be the Iwasawa decomposition. Then: 1) The factor space G/A is diffeomorphic to K x N by the mapping p-l, where ( ~ ( un)=unA, , u E K, n E N. If we identify K x N with G/A by the mapping p, then the G-invariant measure dg on GIA is equal to the 1 product Haar measure du dn =-dt?d[ on K x N. Namely we have 4n (7.37) for all F i n L(G/A). 2) Put H = A M = A { f l } . Then the factor space G/H is diffeomorphic to (KIM) x N and G-invariant measure dg on GIH is given by
(7.38)
Iff
lRF(g)dg=
1
F(un)dudn
=./KxNF(un)du dn .
Proof. 1) Every element g in G may be written uniquely as g =udatnF= usacneat-'at=uen,toat. Hence K x N is diffeomorphic to GIA by the mapping p : (u, n)wunA. Since both G and A are unimodular, the factor space GIA has a G-invariant measure dg. Since the Haar measure dg OD! G is given by dg =e'du dt dn, we have by Lemma 1,2)
=J
=I
KxAxN
f(uatn)etdu dt dn
f(un,tcar)ecdudtd(
KxAxN
THE CHARACTERS
/
=
317
f (uneat)dudt d t KxAxN
=/Rxfo
(twudn
for all f in L(G). Since {f”lfEL(G)} is equal to L(G/H), by Lemma 1, l), (7.37) is proved for all F i n L(G/H). 2) By the result of l), we see that G/H is diffeomorphic to ( K / M ) x N . (7.38) is proved in a way similar to (7.37). Since a function f on KIM is identified with a function f o on K which is constant on each coset of M, the last equality in (7.38) follows from
q.e.d. Proposition 7.7. If t # 0 and m = f1, then
for all f E L(HN). Proofi The element ht =atm satisfies nEhtnE-l=hrhc-lnchtn-t=htncs-t-l,c. We have e-‘ - 1>O or
q.e.d. Definition 4. An element g in G=SU(l, 1) (or SL(2, R ) ) is said to be regular if the two eigenvalues of g are distinct. The set of all regular elements in G is denoted G‘. Let B be a subset of G. Then the set B n G‘ is denoted by B‘. Proposition 7.8. Let G=SU(l, 1) (or SL(2, R)), and put
GI=UgHg-’, G I = U g K g - ’ , Ga= U g ( + N ) g - ’ ad3
ad?
UfQ
318
UNITARY REPRESENTATION OF
and Grl= Gt n G' (i= 1,2,3). Then Gal= in G. We have G=G;U G;U G ~ , (7.40)
SL (2,R)
+, and G1' and GI' are open sets
(7.41) G' = G1' u GI' (disjoint union) . G' is a dense open set in G and the Haar measure of its complement G - G is equal to 0. Pro05 Since SU(1, 1)z SL(2, R), it suffices to prove the proposition for G =SL(2, R). Let R and 2-l be the eigenvalues of g E G. Then we have (7.42)
Gi'=(gEGIAER},
(7.43) and
G s ' = { g E G I 1R1=1, R # & l }
Gs'=+. (7.44) In fact, if 17 >0 for an element g in G', then there exists t E R such that A=e"*. Since R # P , the Jordan normal form of g is equal to at. Hence there exists an element x E G satisfying g=xatx-l. Similarly if R <0, g = x ( - a t ) x l . Hence we have (7.42). If 111 = 1 A # & 1, then there exists a vector el # 0 in C' such that gel =etelaeland 1 =erela.Put C1=ea. Then gea=e-tefsez. Since A # P , el and ez are linearly independent and xl= 2-'(el ep) and xa = (2i)-l(el-ea) are non-zero real vectors. Since gx, = x1 cos 19/2-x3 sin 1912 and gxa =xl sin 1912-I-xlcosff 12, we have x-lgx =uR for the matrix x = (xl, xa). Multiplying x by a scalar if necessary, we can assume that x E G =SL(2, R). Hence we have (7.43). Since the eigenvalues of an element in Gs are both equal to + 1 or to -1, we have Gs'=+ By (7.42) and (7.43), we have G1' n Gal=+. If an eigenvalue R of g E G' is not real, then I is also an eigenvalue of g and must be equal to 1-l. Hence Inla = 12 =R R - l = 1. We have proved that G' = GI' u Ga'. Since the characteristic equation of g has the form ta-(Tr g)t + 1 =0,
+
1 is real if and only if (Tr g)a2 4. Put g =
(I: 5;).
Then we have
+
Gi' = { g E G I (a >4} , G a ' = { g ~ G I ( a + d ) s < 4 } , and G-G'= {gE G J a + d = f 2 ) .
Hence G1' and GI' are both open sets in G and G' is dense in G. G - G' consists of two analytic surfaces in the 3-dimensional manifold G. Therefore, G - G is a null set. If g belongs to G-G, then R = +. 1. Hence the Jordan normal form of g is equal to Consequently we have (7.40).
and g belongs to Gs.
319
THE CHARACTERS
Proposition7.9. PutH=AM= {+a,It.sR} andH+= {+atlt>O}.Then the mapping :G / H x H++G1' defined by +(gH, h) =ghg-' is an analytic bijection of GIH x H + onto G;. Proof. Assume that gu,g-l=g'ar~g'-l and put g'-lg=gl. Then we have glatgl-l=ae~.Taking the eigenvalues, we get {e,", e-c'a} = {et'", e-t'''}. Hence t is equal to either t' or -t'. If we assume that t>O and
+
t'>O, t must be equal to t'. If gl=
(: I;)satisfies glar=atgl, then we
have (eC-l)b=(et-l)c=O and b=c=O because t>O. In this case gl belongs to H and gH=g'H. Hence we have proved that (0 is a bijection from G / H x H + onto G1'. is also an analytic mapping. q.e.d.
+
Remark 1. Put H ' = H n G'. Then +, defined by +(gH, h)=ghg-l, is a 2 to 1 mapping from GIHx H' onto G1'. The proof of this result is clear from the proof of Proposition 7.9 and the fact that u.atu;l=a-t. Remark 2. In the following, we shall see that the Jacobian of the m a p ping does not vanish on G / H x H + . Hence is an analytic diffeomorphism of GIHx H + onto G1'. The calculation of the Jacobian of (0 is the essential part of the integral formula in Proposition 7.11 which will play a key r61e in determination of Moreover, since the method of calculation is the character Tr( W/**). used frequently in Lie group theory, we give a fairly detailed explanation.
+
+
Definition 5. Let M be a C"-manifold and 9-= T ( M )be the algebra of real valued C"-functions on M. A tangent vector of M at p e M is a linear form X on fl satisfying for every f and g in 9. The set of all tangent vectors of M at p forms a vector space T p ( M )which is called the tangent space of M at p. If p is a C"-mapping of M into another C"-manifold N , then there exists a linear ~ p ( M )into T,(,, (N)defined by mapping ( d ( ~of) T
-
[(diD)Pmf)=X(fOp) (d(0)p is called the diferential of (O at p. Let G be a Lie group and L , : x ~ g x and R , : x ~ x g
be left and right translations. We use the following notation: (dL,),X=g*X and (dRp),X=X*g for X E T,(G).
320
UNITARY REPRESENTATION OF
SL (2,R)
We identify the tangent space of G at the identity element e with the Lie algebra g. LEMMA 2. If X E T,(G) and g, h E G, then we have 1) g * (h* X ) = (gh)* X , 2) (X*g)*h= (gh), 3) g * (X*h)=( g*X)*h. Proof. These identities are proved directly using the relations L, o Lh= q.e.d. Lgh, Rh R,= R g h and L, Rh=Rh 0Lg.
x*
0
0
LEMMA3. Let X E Q = T , ( G ) and g E G . Then we have g * X * g - ' = (Adg)X. Put o(g)=g-l. Then we have (du),(g*X)= --X*g-l and (du),(X*g)= --g-l*X. Proof. Let a p : x w g x g - l . Then we have Adg=(du,),. Since ao=Lgo Ra-', we have (Adg)X=g*X*g-'. Put 8(t)=exp fX.Then we have (d8)&f/df)=x . Put 0' = o 8. Then we have 8'(t) =exp (- fX) and (dO'),(d/dt)= -X. Hence we have 0
(dU),x=(do de),(d/dr)=(de'),(d/dt)= --x. Since u o L, =R,-1o U, we have (do),(g * x> = (do dL,),X= (dR,-lo = (-x)*g-'= -X*g-'. 0
Similarly we have (du),(X*g ) = -g-l* X .
LEMMA4. Let H be a Lie subgroup of G and m: G x H+G be the mapping defined by m(g, h) =gh. Then we have (drn)(,,h,(X,Y ) = X * h + g * y for every X E Ta(G) and Y E T h ( H ) . Proof. When the element h in H is fixed, G is identified with G x {h} by the analytic injection ih :gi+(g, h). Similarly, for any fixed g E G, H is identified with [ g } x H by an analytic injection j , : hH(g, h). We see that (dih),X= (X, 0) and (c$,)~Y= (0, Y) for all X E T,(G) and Y E Th(H).On the other hand we have (m ih)(g)= m(g, h) =gh = Rh(g) and (nz oj,)(h) =L,(h), i.e. moih=Rh and m o j a = L , . 0
Therefore we have ( d m h .dX7 Y)= (hh, h)((dih)vX+ (dj,)h y) =(dRh),X+(dL,)hY=x*h+g* Y.
THE CHARACTERS
321
LEMMA 5. Let H be a Lie subgroup of G and p be a mapping of G x H into G defined by lo(& h) =gk-' * Then we have (dp)(g,h)(g *
x,h * Y)=ghg-' * (A&) ((Adh-'-l)X+
Y)
9
for every XEg and YE tj (the Lie algebra of H). Proof. Put p(g, h)=g. Then the mapping p is decomposed as m (mx (u op)): 0
p :(8,h)
- -
m x (u *PI
(gh, g-'1 Hence by Lemmas 3 and 4, we have
m
ghg-'
(P=
-
(d(O)(g,h)(g*X, h* Y>=(dm)(gh,g-l>(h d(0 oP))(o&*X~ h* r ) =(d~)(gh,l-l)(g*X*h+gh*y, -X*g-') =g*X*hg-'+gh* Y *g-'-gh*X*g-l =ghg-l* (gh-1*X*(gh-')-I -g *X*g-l +g * Y *g-1) q.e.d. =ghg-l*(Adg) {(Adh-1- 1)X+ Y}.
Proposition 7.10. Let G=SL(2, R) (or SU(1,l)) and @ be the mapping +(gH, h)=ghg-I. Then 4 is of maximal rank at every point of G / H x H'. 4 is an analytic diffeomorphism of G / H x H + onto GI'. More precisely, let (Xo, Xl, Xa) be the basis of g defined in Proposition 1.1, and put p(g)= gH=g and (dp),(X)=f ( X E T,(G)). Then we have (7.45)
Proof.
--
(&)(;.*d(g*Xo)A( g * x s )A (*at * X I ) )
Put Y=Xa-2Xo. Then (Xl, X2,Y)is a basis of Q. We have
-
Xs]=Xa and [XI,yl= Y (cf. (1.2)). Hence we have AdatX2=etXs and AdatY=e-'Y. By the relation (CI o (p x Id) =(O and by Lemma 5, we have [XI,
(d+)(i,h)((g*XO)A\)A (h*Xl)) = -2-'(d(O)
322
UNITARY REPRESENTATION OF
SL (2,R)
where h= f a t . Hence we see that det(d+)(-,,*,,,fO if t # O . Hence + is of maximal rank at every point on GIH x H'. Therefore, is an analytic q.e.d. diffeomorphism of G / H x H + onto G1'by Proposition 7.9.
+
Definition 6. Let tz" be the S-module of C"-vector fields on a C"manifold M (N = C"(M)).Then an alternating N-multilinear mapping x ... x tz" (k-times) into fl is called a k-form on M. The value of wq of o at a point q E M is the R-multilinear mapping of T,(M) x ... x Tq(M)into R defined by %((Xl),, .**, ( X k ) q ) = O ( x l , *.., X d ( q ) * Let 0 be a C"-mapping of another manifold N into M. Then a k-form + * o = o o + on N i s defined by (0
+)P(Xl,
* *.
,Xk)= O@(P)((d+)P-&,
..a,
(d+)Jk)
*
In the following, the Haar measure dh on the group H = A M = ( k u c l t E R) is normalized by requiring that
Proposition 7.11. If the support C of a functionfin L(G) is contained in GI'= ugH'g-', then we have vrQ
(7.46)
1
f(g)dg =/rec a sh-&dt
f ( ~ a m u - ~ )dn du
KxN
f(u( -ar)nu-l)du dn .
+/rec%h+t/ KxN
Proof. Let Xo, Xl, X z be the basis of the Lie algebra g of G = SU(1,l) defined in Proposition 1.1, and w0, 01, ozbe the 1-forms on G defined by ot(g*X,)=6r,. Then o1 is left invariant, i.e. O ~ L ~ for = Oevery ~ g E G. Hence B = o0A o1A is a left invariant 3-form on G. On the other hand o = ( 4 x ) - l e ~ d 1 9 ~ d tis ~ dalso ~ a left invariant 3-form on G (Proposition 5.1). Hence there exists a constant c such that D=co. Now we determine the value of c. Since the function I9 :ueatne H I9 satisfies O(u,) = 8, O(a,)= e(ne)-0, we see that
323
THE CHARACTERS
Similarly we have
Hence we have
So the Haar integration on G is given by (7.47) Similarly, let 6' (i=O, 2) be the G-invariant 1-form on G / H defined by Br(g* x,)= Then a = 00A 02 is a G-invariant 2-form on GIH. On the other hand, the manifold GIH is identified with KIMx N and p=duA dn = (2~)-lde~ d ist a G-invariant 2-form on G/H (Proposition 7.6). Hence we see in like manner as above that a =27cp and
f(usnc)d8dE.
=(47c)-'] KxN
The 1-form o1regarded as a 1-form on H satisfies (7.49)
f(h)dh=/;-
=I
f(at)dt+/m-ca f(-at)dt
f0l.
If
Finally, Proposition 7.10 shows that (7.50)
Q 0 (0 = -4( Sh-$)laA
WI
Using the formulas (7.47)-(7.50), Remark 1 and the transformation formula for multiple integrals, we have the following equalities for every function f in L(G) whose support lies in G1':
/
f (g)dg= (47c)-'/
fQ = (47~)-l Ql'
-2 1 H+
f (ghg-')dg
(sh+)'dh/ QIH
324
UNITARY REPRESENTATION OF
SL (2,R)
By Proposition 7.7, the last integral is equal to +-
f(uamu-')du dn sh-TdhS,.Nf(u(-a,)n~-l)dudn t
+I:ecla
q.e.d. Proposition 7.11 is a partial result. It is valid for the functions whose supports lie in Gl= ugHg-l. The complete integral formula is obtained by taking the integral over G, = u gK$l into consideration. Such a formula is given in Proposition 7.13. Proposition 7.12. The mapping r :(a, n)wanK is a diffeomorphism of A x N onto G* = G/K. If we identify A x N with G* = G/K, the product measure dadn gives a G-invariant measure on G* = G/K. Namely, we have (7.51)
where g*=gK. The mapping 9 :(g*, u)wgug-l is a diffeomorphism of GIK x K' onto GI' = u gK'g-' . wQ
Proof. Taking the inverse in the Iwasawa decomposition G = KAN, we see that the mapping (n,a, u)wnau is a diffeomorphism of N x A x K onto G. Since acnpac-l=n,tp,A N = N A and the mapping (a, n, u)wanu is a diffeomorphism of A x N x K onto G. Therefore the mapping is a diffeomorphism of A x N onto G/K. For eachfin L(G), put
/Kf(gu)du=f*(g*)
*
Since G and K are unimodular, there exists a G-invariant measure dg* on G* = G/K such that
The last integral is equal to
325
THE CHARACTERS
The last equality is derived from the relation neat=atnc-:F.
')
If g=(-" E G=SU(I, 1) satisfies gu,g-'=u,, we have e*@l)ly=eWaa Be and e-rerap=ecpls,8.Since l a ) s = l+],9l'#O, we have 1 9 ~ mod4x 9 and (ete-1)i3=0. If us+ -t- 1, then p=O and g belongs to K. Hence we have proved that if p(g*, ue)= (o(gl*,u,) for ue, u, E K', then ua = u, and g*= gl*. Namely, 'p is a bijection of G / K x K' onto Ga'. 'p is induced by the C"-mapping 'po :(g, u)++gug-' of G x K' onto GI1. Since the projection q :gwg* =gK is a C"-mapping and po= 9 (q x Id), (0 is a C-"mapping of GIKx K' onto Ga'. As will be seen in the proof of the next proposition, the Jacobian of the 0
mapping 9 at (g*, ur) is equal to 4(sin+)'.
e ego, 2K m o d k and sin-#O. 2
Since us E K' is regular,
Therefore, by the inverse mapping
theorem, the inverse mapping 9-l is also a C"-mapping. Proposition 7.13. we have
q.e.d.
For every Haar-integrable functionfon G =SU(1, I),
proof. Let 7' ( i = l , 2) be the G-invariant 1-form on GIK satisfying vI((g*Xj)*)=6u, where (g*Xj)*=(dq)(g*Xj). Then ~ = V I A is V ~a Ginvariant 2-form on GIK and satisfies
/G/xf(g*)dg*
=JB,a f
The 1-form o0 defined in the proof of Proposition 7.11, gives the Haar integration on K:
Let p: G / K x K+G, be the mapping (g*, u)ngug-'. Then by Lemma 5 and (6.22) we see that (dp)
* (Xl A Xa A XO). Hence we have
326
UNITARY REPRESENTATION OF
SL (2,R)
(7.53) Therefore, for any function f in L(G) whose support is contained in G%', we have Q
a'
QllCXK
Here we use the fact that the mapping (O is a diffeomorphism of GIKx K' onto G2'. Since G-G is a null set and G'=G1'u Gt' is a disjoint union (Proposition 7.8), we have
for any f in L1(G). Moreover, the restrictionflG'' is integrable on GI' (i= 1,2): f l G; E L'(Gt') (i= 1,2). Since (7.54) holds for every function f i n L(Ga'), (7.54) holds for all f in L1(Ga'). By Proposition 7.11, (7.46) holds for all f in L1(Gl'). Hence q.e.d. (7.52) holds for all f in L'(G).
Proposition 7.14. (7.55)
Let m = f1 and f be a function in L(G) satisfying
f(ugu-')= f ( g ) for all
UE
K and g s G .
Then the Radon transform Ff(mar)=et1.S f(macn)cin N
satisfies the functional equation I;&zz-O
=FArnat) .
Proof. By Propositions 7.6 and 7.7 and by the assumption (7.55), we have (7.56)
Ff(mar)=etla f(ma&€n
:IsN S N
I
= 2 sh -
f(nmatn-l)dn
THE CHARACTERS
327
f (unmucn-lu-l)dudn
=2/sh+// KXN
=2lsh$-1/
f(gmatg-')dg. UlH
Put v =u,. Then v normalizes H. More precisely, we have
(7.57) v(mar)v-l= m-c (m= zk 1) (cf. Proposition 2.11). Hence the mapping s :gH-vgv-lH defined diffeomorphism of G / H onto itself. Put
is a well
for each p in L (G). Then by Lemma 1 we have
On the other hand, by (7.57) we have (D".(g)=/
Sa
p(vghv-1)dh = H
p(vgv-'vhv-')dh
=/Hp(vgv-lh)dh.
Hence (7.59)
p~'=ID'oS.
Since the mapping p ~ p maps * L(G) onro L ( G / H ) (Lemma I), (7.58) and (7.59) imply that dg=d(sg). Then, dg =d(sg)=d@-') . (7.60)
By (7.59, (7.56), (7.57) and (7.60), we have
Theorem 7.2.
For each j
B
{0, +} and s E C, put
328
UNITARY REPRESENTATION OF
SL (2,R)
where k = O or 4. Then the character of the principal continuous series representation W' of G=SU(l, 1) (or SL(2, R)) is equal to the function W J . Namely we have
for every function f in .g(G). Remark. Since G - G' is a null set, the values of the function @ * a on G-G' can be taken arbitrarily. On the other hand, since G' is open in G, the values of @js* on G are uniquely determined by (7.62) (cf. Lemma 8 below). Similar remarks are applied to Theorems 7.3 and 7.4 below. Proof. Since W a gWjJ (Proposition 7.3), it suffices to prove (7.62) for the representation Wj** instead of Vj.' By the definition of 0 j v r and by the integral formula (7.52) (or (7.46)), we see that
Ql'
Putting f o ( g )=
f(ugu-')du,
the latter sum of integrals is equal to
d K
+(-l)sj[e8'dt/
KxN f(u(--ar)nu-l)dudn]
.
Comparing this with the expression (7.32) of Tr( W/J) (Proposition 7.5), we get
J.
f(g)Wa(g)dg=Tr ( W / J )
.
q.e.d.
329
THE CHARACTERS
Now we compute the character of the complementary series representation P(4
Theorem 7.3. Let 4
Tr V,. =Tr V f
for any f E : ( G ) . Hence the character of the complementary series representation V is equal to the function
if g E G-G1'
.
ProoJ Let Q=L'(U) be the representation space of Then the representation space 8. of V' is the completion of 8 with respect to the positive Hermitian form (+, +)u on 8 (cf. $4). Since (4, +)< is a bounded strictly positive Hermitian form on 8 (Propositions 4.2 and 4.4), there exists a bounded strictly positive Hermitian operator A. on 8 such that (#, +).=(A. 9, +) for all 4 and in 8. Put &=Ae-*. Let (9n)n.N be an orthonormal basis of 8. Then ( B u p , ) n .is~ an orthonormal basis of Q., because 8 is dense in &. Hence for everyfin we have
+
:(a,
0
C = C(AuVfo*uAe-f9n, Ao-'vn)
Tr Vj' =
(V,'&n7
&pJ.
n-0
n-0
=Tr(A.+ V fO-'A,-*) =Tr V fOo8
because the restriction of VgUto .fjis equal to V:,.. We have proved (7.63). By Theorem 7.2 and by (7.63), the character of P is equal to the funcq.e.d. tion W in (7.64). The character of a representation in the discrete series is computed in quite a different way. The method is in some sense similar to the computation of the characters of finite-dimensional representations. The idea is that we take the sum of the diagonal elements of a representation matrix, but there arises a problem of convergence. However, this difficulty is overcome by introducing a convergence factor and using Theorem 7.1. We begin by calculating the diagonal element (UnOpn,0,"). We recall that every element g in G-K can be written uniquely in the
330
UNITARY REPRESENTATION OF
SL (2,R)
form (7.65) g=upatuI,0 < ~ < 4 a , O < t , 0<9<2x. (Proposition 5.2). The element g in (7.65) is denoted by g(y, 1, 4). In the following Xo, Xly and Xa denote the elements of the Lie algebra g of G = S U ( l , 1) defined previously (cf. (6.21)). They are regarded as left invariant vector fields on G.
Proposition 7.15. As left invariant differential operators on G -K,the elements Xo,Xl, Y = Xa-Xo and the Casimir operator o =X O-~X12- Y' have the following expressions in the coordinates (9,r, @) defined by (7.65):
a +cos (0- a -cth t sin $--a Xl =-sin9 sht ay at a4 YE---C O S ~a +sin +-+cth a shr a p
Proof.
t cos 9-a 34
at
Let g = g ( y , t, g) E G-K. Then
where i(9+I)
a =e a c h -
(7.66)
2
ch-
u) t s + e sh- sh2 2 2 2
t
f(cp++)
t s sh- ch2 2
t(a-cs)
p =e a c h - 2 sh-2 +e
f
.
Hence, by Proposition 5.2, we get t
s
sh2(t(s)/2)= I,qa= (chT sh- 2
+sh-2t ch-2S cos+ S
= c h L ch s-ch2-+2-l sh t shs cos 2 2 Differentiating at s= 0, we get t'(0) =cos # . (7.67)
.
THE CHARACTERS
33 1
Again by Proposition 5.2, a= &-(p(S)+#(J)
)/a
ch(t(s)/2) @=&v(*)-#(J))/2 sh(t(s)/2) Differentiating four equations in (7.66) and (7.68) at s=O, we get (p'(O)+ g'(0) and ~ ' ( 0) +'(O), hence also ~'(0)and +'(O) : (7.68)
-
+'(O)
(7.69)
= -cth t sin
~ ' ( 0 =sin ) +/sh t .
+
By (7.67) and (7.69), we get
a
a
+ +'(O)- a+a sin+ a + cos +--cth a =-t sin +-a . sht a9 at a+
+
Xl = V ' m - aP t'(O)%
Put u,ucusexp sY=g(&), tds), +I@)). Since ~ , ~ a - ' u =exp ~ ~ sY, , ~ ~yl,tl and +1 can be expressed by means of the functions 9, t and +. Put u,utu,a, =g(&,
+), t(s, $1, +(s,
9)). Then we see that
&)=p(s,
+-+),
Therefore pI'(O), tl'(0) and
&'(O)
can be obtained from p'(O), t'(0) and +'(O)
by replacing
+
by
i7
G--. 2 Hence we have
+
cos Vl'(0) = --sht ' tl'(0) = sin , +1'(0)=cth t cos (I
+
and cos+ a a +cth t cos +-a . y = -sin sht ay at a+ The expression for o is easily obtained from those for XO,Xl and Y. q.e.d.
-+
+--
Proposition 7.16. Let p E 2-lZ and s E C. If a real analytic function f on G satisfies a) f ( w u d =XP(U,+#)f (g>9 O I =s( 1- s ) f , and b) c) f(l)=1 , then f must be equal to the function defined by (7.70)
f ( u , u C u # ) = ~ ( c h ~ ~ ' * F ( s-p, s + p ,1;
332
UNITARY REPWENTATION OF
SL (2,R)
where F(a, b, c; z) is the hypergeometric function. Proof. By the assumption a), f is completely determined by its restrictionflA to the subgroup A. By the assumption b) and because of the expression for o given in Proposition 7.15, flA satisfies the differential equation (7.71)
{-$+%-$+[s(l -s)+-
I1
2P' (ch t- 1) f ( a t )=O sh t
.
Let us introduce a new variable x related to t by the equation t x =ths-
2
and put f(at)=(l-~')'F(~). Since d d =4 3 1 -x)and dt dx da da d -dt a - x(1- x y dt y +24(1 - x ) (1-3x)- dx '
the function F(x) satisfies the differential equation (7.72)
daF
x( 1- x b
dF +[1-(2s+ l)x]d, +(p'-s')F= 0 .
This is the hypergeometric equation for which a = s + p , b=s-p and c = l (in the standard notation). As is well known, the unique solution of (7.72) which is continuous on the interval [0, 1) and takes the value 1 at x=O (the assumption c)) must be equal to the hypergeometric function F(s+p, s-p, 1; x). [Another solution Fl of (7.72) which is linearly independent of F(s+p, s-p, 1;x ) has the form
-
FI(x)= C C ~ ~ ~ + F ( S + ~ ,1;x)lOgx. .S-P, k=O
Hence Fl is not continuous at x=O.] Therefore the real analytic function q.e.d.
f on G satisfying a), b) and c) is given by (7.70).
Remark. The complex number s is not uniquely determined by b). However, the function (7.70) is uniquely determined because (7.70) is invariant under the replacement of s by 1-s. The last fact is due to an identity for hypergeometric functions: F(u, byC; z)=(l-~)C-"-~FF(c-b, C-U, C; z).
In fact, if we puts'= 1-s, then s(s-l)=s'(l-s').
333
THE CHARACTERS
Proposition 7.17. Let Un(n E 2-'Z, In1 2 1) be the discrete series representation of 53 and put
+
Opn(C) = [I'(2n+p)/r(h)r(p 111' C p
for p E N
.
Put
(7.73) upn(g)=(UgnKpn,Kpn) for each n E 2-lZ(lnlz 1)
and p E N. Then the function upn is equal to
and uP-n(g)=upn(g) for any n 2 1
Proof.
.
Since cDPn satisfies
(7.75)
Uu,nOpn =X-n-p(Us)Opn
(Proposition 3.9, it is a K-finite vector and hence an analytic vector for U" by Proposition 6.11. Therefore the matrix element upnis a real analytic function on G. Moreover it satisfies the three conditions in Proposition 7.16: First we assume that n 2: 1. a) By (7.75), upn satisfies ~P"(U,B+)
=Xn+p(UI+))Ui(g)
*
b) For any X E g, we have
=(ugnU~'(x)@p(o Op").
Hence @UP*
=n(l -n)up"
because Q = Un'(o)=n(l -n) (Theorem 6.4). c) is trivially satisfied. Therefore upn is given by (7.74) if nll. Since Ug-"=uUgnu, where u : f ~isfthe conjugation (cf. 53), we have Up-n(g)
=(uUg"u a e p n , =UP%)
U @ p 9=
(UgnOpn, cDp")
q.e.d.
*
The hypergeometnc function G,(u, c; z)=F(a+m, -m, c ; z )
(mB N)
334
UNITARY REPRESENTATION OF
SL (2,R)
is a polynomial of degree m which is called the Jacobi polynomial. The Jacobi polynomials (G,(a, c; z ) ) , , ~form an orthogonal system on the . need the followinterval [0, 11 with the weight function xC-'(l- x ) ~ - ~We ing relations for G,.
LEMMA6. Let (7.76) Gpa(~)=F(u+p,-p, 1 ; X) for a> 1 and p E N. Then we have (7.77)
1:
(l-x)u-lG,a(x)G,a(x)dx=O
if p z q
and (7.78)
[( 1 -x)u-aGpu(x)2dx=
(a- l)-l
for all p E N.
0
Proof. Gpaand Gqasatisfy the hypergeometric equations (7.79) [x(l - ~ ) ~ G ~ ~ ' ] ' + +a)(l p ( p- x ) ~ - ~ =GO ~ and ~ (7.80) [ ~ (- lx ) ~ G ~ ~+q(q+a)(l ']' =O . Integrating (7.79) x Gqm-(7.80) x Gpa from 0 to 1, we get [~(~+n)--q(q+41[ ( ~ - x ) u - l ~ p u ( x ) ~ q u ( ~ ) ~ =
- [ ~ (- lx ) ~ ( G ~ ~ ' G ~ ~ - (x)]; G ~ =O ~ G. ~ ~ ' )
Hence if p # q, we get (7.77). The hypergeometric function ab z a(a+ l)b(b 1) z2 F(a, b, c ; ~ ) = l + - - - + - +... c l! c(c+l) 2! is equal to a polynomial of degree S p if b= -p. Gpuis a polynomial of exactly degree p, because the coefficient of x p in Gpa(x)is equal to
+
c p= (- 1 )pa(a+ 1) ... (a+P-lJ,o
P!
Hence the monomial xn is a linear combination of the polynomials (Gqa)osq s n . Therefore, by the orthogonality relation (7.77), we see that (7.81)
1:
(1-x)'-lGpu(x)~(x)dx=O
for every polynomialfof degree Q-1. By the definition of GPU(x)=F(a+p,-p, 1 ; x), we have
.
(7.82) Gpu(0)=1 By (7.81), (7.82), and integration by parts, we have
335
THE CHARACTERS
1:
(1 -x)a-*Gpa(x)adx= [-(a-
1)-l(1 -x)"-lGP5(x)]:
(1 - ~ ) ~ - ~ G ~ ~ ( x ) G ~ ~ ' ( x ) d x = ( a - l ) - ~ .
+2(a-l)-l[ 0
q.e.d. Proposition 7.18. The matrix element upn(g)= (UgnKpn,Kpn) (cf.(7.73)) of the discrete series representation Un is a square integrable function on G and has the norm
lo.
(7.83)
I~,"(g)ladg=4~(21~l--1)-'
for every n E 2-lZ (In12 1) and p E N. Proof. The Haar measure dg is expressed by dg =2n sh t dkdtdk' for g = kark' (Proposition 5.3). Hence by Proposition 7.17, we have
Sr
lupn(g)ladg=2n
I(ch t/2)-51n1F(21nl + p , -p, 1; (th t/2)*)l%htdt .
Putting x=(th t/2)%, we get dr=x-*(l--x)-ldx, (ch t/2)a=(l-x)-1, sh t=2x*(l-x)-'. Hence the above integral is equal to 4x1: (1-x)al"~-~Gpa'n~(x)adx=4n(2~~l-1)-1
by Lemma 6.
q.e.d.
The above proposition determines the part of the Plancherel measure corresponding to the discrete series representations. (4~)-~(2(nl1) is called the formal degree of Un.The formal degree of a square integrable representation plays a role analogous to that played by the degree of a finite-dimensional representation of a compact group. The following lemma gives the generating function of the Jacobi polynomials Gpa(z)=F(a+p, -p, 1;z). LEMMA^. I f I w l < l a n d - l < z c l ,
-
(7.84)
1
WPF(U +p,
thenwehave
+ + 1)]1-5
-p, 1;Z)=~ - 1 [ 2 - 1 ( ~r
P-0
where R = [1-2w(1-22) + wa]+. R is a univalent analytic function in D = (w E Cl Iwl< 1) which takes positive values on the positive real axis in D. We give an outline of the proof (cf. ErdClyi [l]). Introducing a new variable u = t( 1-tz) (1-t)-l in Euler's formula
336
UNITARY REPRESENTATION OF
F(u-b, b, 1; z)=[r(b)r(l-b)]-l[
SL (2,R)
t*-1(1-r)-*(l-rz)*-mdr, 0
we get 2-'(1-u+U)=
(7.85)
1-22, U-ldu=(l-f)-ldf
and
F(u-b, b, 1 ;z)= [r(b)r(l -b)]-1/rub-1[2-1(l -u+ U)]'-"U-'du,
where U=[1 +2u(l-2z)+ua]*. The integral (7.85) is the Mellin transform of the function [2-'(1 -u+ U)]l-aU-l.Putting u=eS, the Mellin transform becomes the Fourier-Laplace transform and we get the inversion formula
(7.86) [2-'(1-~+ U)]'-'U-'=-.
21Cl
s""-
r(b)r(l - b ) F ( ~ - b , b, 1 ;z)u-*&,
p < m
where 9, is a suitably chosen positive real number. The integrand in (7.86) is a meromorphic function of b and has poles only at b= - p @=O, 1, 2, ...) in the left half-plane S= { b = x + y i l x < p } . The integral (7.86) is equal to the sum of the residues at the poles in S. This can be proved by taking a suitable contour C in 3 and letting C tend to infinity. Since Resr(b)=(-l)p/p!, the right side of (7.86) is equal to *--p
c m
(- l)PF(a+p, -p, 1 ;z)uP .
P-0
Putting u= -w, we get (7.84).
q.e.d.
LEMMA8. If (p is a continuous function on G satisfying
for every f e *I(@= {fe S(G)lsuppfc G'], then p(g)=O for every g E G'.
Proof. Let go be a point in G . By the continuity of p, for each there exists a compact neighborhood W of goin G' such that Ipk)--lo(go)l<e
r>O
for all g c W.
There exists a functionfin S1(G) which vanishes outside of Wand satisfies
fro
and
1.
f(g)dg=l.
Hence we have
Iv(go)l=I
s.
(p(g0)-
(p(g))f(g)dglS E. Since c can be taken arbitrarily small, we get p(go)=O. q.e.d.
Now we proceed to the calculation of the character of the representation U" in the discrete series. We use Abel's method of summation for
337
THE CHARACTERS
the divergent series C(UgnYpn,V p n ) and prove that the sum taken by P Abelian summation is equal to the character, i.e., the distributional sum of the series. Before stating the theorem, we recall results on the representation of the conjugate classes in G'. Every element g in GI)= u goH'g0-' may be written gocG
&?=go(-l)S'acgo-'
for a certain goE G, t E R, and j~ {0, &}. The values of j and It1 are uniquely determined by g (Proposition 7.9). Every element g in Gal= u goK'go-lmay be written VO'G
g =goUego-'
for a certain go E G and 19E [0, 4n). I9 is uniquely determined by g.
Theorem 7.4. Let U" (n E 2-'2, In[2 1) be a representation of G = SU(1, 1) in the discrete series (cf. $3). Then the character of Unis equal to the function e-(lnl-t)ltl lecrs-e-tia
I
(-l)tn9
if g = g o ( - l ) s ~ a c g ~GI', -l~
if g E G-G'
,
where j = 0 or 4 and e(n) =sign n. Namely, we have
s.
Tr U p =
(7.88)
f(g)@"(g)dg for all f E S ( G ) .
Proof. We introduce the convergence factor r (0 c r < 1) in the summa-
tion of
i
(
~
~
n
K,"). ~ ~ nPut ,
P-0
@,"(g)=
-
CrP(Ug"Kp*,vPn). P-0
Then the series converges uniformly on G for each fixed r E (0, l), because lupn(g)l5 1 for all g E G. Hence the function 8," is continuous on G. Since up-"(g)= up"(g),we have (7.89)
-
@r-"(g)=@rn(g)
Hence it is sufficient to calculate 8," for n2 1. Assume that n~ 1. Then by Proposition 7.17 and Lemma 7, we have
338
UNITARY REPRESENTATION OF
+ +
SL (2,R)
t
-In
=e-tncp+*~~-1(2-1(~ w I) )l-an P - j- )
where w=re-t(p++)and R=[1-2
,
t ( I-2th2~)w+wa]'.
Hence a finite limit exists for lim @,"(g) for every g=u,atu+ E G-K. r-1-0
Since R =R(w) takes real values on the positive real axis, we see that lim R ( r ) = ( 4 t h aty ) * =21th$/ and 7-14
By (7.89), we have
and for all n E 2-'Z, In)2 1. On the other hand, on the subgroup K,we have
and us+ f1. Hence
exists and is finite. By (7.89), we have
Hence lim @,"(g)=Oln(g)
r-1-0
exists and is finite for every g E G'. Moreover, we have
.
&"(g)=@(g) if g E H' u K' To prove eln=8" on G', it is sufficient to show that elnis invariant under inner automorphisms. This fact will be demonstrated at the end
(7.90)
339
THE CHARACTERS
of the proof. Since the operator Ufnfor eachf in 9 ( G ) is of trace class, the series
converges absolutely. Therefore, by Abel's theorem on power series, we get m
(7.91)
Tr U p = P-0
m
(UlnVPn,lPpn)= r-1-0 lirn
rP(UfnFpn, VPn) P-0
for every f s g(G'). Since
c OD
s r"llfll Ilu,"ll s [4n(214-l)-'I'
llfll(1
+
00
P-0
by Proposition 7.18, the right hand side of (7.91) is equal to n
n
Thus we have proved that r
(7.92)
Tr U," = lim
r-1-0
J f(g)@r"(g)dg Q
for every f E g ( G ) . Put R = R(r, 1 ) = (1 -2( 1-2 th$)r+
ra)+and R1= lim R(r, t) r-1-0
Then we have 0 6Ri- R= (Ri'-Ra) (RI R)-' (7.93)
+
I ;6(1 -r)Rl-'
Since R1-1=2-1(1 +e-t)ll-e-cl-l R*=R-{O}, we see that
. is bounded on every compact set in
lim R=Rl r-1-0
340
UNITARY REPRESENTATION OF
SL (2,R)
uniformly on every compact set in R - {O} . Hence 8," converges uniformly to eln on every compact set in G -K. On the other hand eraconverges to elnuniformly on every compact subset of K' because 1-r IQ~"(~o)-@i"(~a)l = I -re*tel 11 -psi * Therefore, 9," converges to elRuniformly on every compact set in G . Hence Qln is a continuous function on G . Moreover, by (7.92), we have
Tr U3"=S6'g)Q1"(g)&
(7.94)
for every f in g l ( G ) = { f ~ g ( G ) I s u p p f c G ' } . (7.94) proves that the distribution fwTr U," coincides with the function Elln on the open set G' of regular elements. For each x E G, put f.C(g)=f(x-lgx). Then we have j-/(g)@l"(xgx-')&= =Tr U;= =Tr U3"=
f"(g)@l"(g)&
/ff
1
f(g)Ol"(g)dg.
ff
By Lemma 8, we get (7.95) Ql"(xgx-l)=Ol"(g) for all g E G' and x E G
.
By (7.90) and (7.95), we have Qln(g)=@n(g) for all g E G' . Since Il-e**B111--re*~o~-1~4if O < r < l , we see that
(sin~~j@,"(u,)-e.(u,)I 64(1-r) and (7.96)
lim (sin~~(Q,"(ua)-Bn(u.))= 0
r-1-0
uniformly on K. Let ro be a fixed real number in the interval (0, 1). Then R(r0, t ) = 2 l-ro for all t E R. Hence for every r in the inter-
Val [ro,l), we have by (7.93)
THE CHARACTERS
341
We see that
uniformly on every compact set oft. Therefore, (7.97)
lim r-1-0
(sh
fa,)-@( k a t ) )=0
uniformly on every compact subset of the Cartan subgroup H = M A . By the relations (7.96) and (7.97) and the integral formula (7.52) (Proposition 7.13), we have (7.98)
lim /Gf(g)Qrn(g)dg=
r-1-0
1
f(g)@"(g)dg
for allfin d ( G ) . (7.92) and (7.98) prove the desired relation (7.88). q.e.d. Theorems 7.2, 7.3 and 7.4 show that the characters of representations in the principal continuous, discrete, and complementary series are in fact functions which are real analytic on each of the connected components Gl' and G2'of G' and are integrable on every compact set. This is a special case of theorem due to Harish-Chandra [6], [lo] stating that a central eigendistribution (in particular a character of an irreducible unitary representation) on a connected semisimple Lie group is a locally summable function which is analytic on each component of G . At the end of this section, we give a remarkable relation between the character Of*"+'of the non-unitary representation VJ,"+jin the continuous series (92) and the character 8" of the discrete series representation. In this relation, the character of a finite-dimensional representation appears.
Proposition 7.19. Let Vnbe the vector space of all homogeneous polynomials of degree n in two variables zl, z2. Let F" be the representation of G=SU(l, 1) on V, defined by (7.99)
(F"(g)9)(4=(OM*
(cf. Ch. XI, $1). Then the character En of F" is given as follows. If A and A-' are the eigenvalues of a regular element g E G , then An+l--R-(n+l)
En&)=
2-2-1
-
ProoJ Actually (7.99) defines a representation Fn of the complex Lie group GC=SL(2, C). If g is regular, then 2 # P , and there exists an element in G' such that
342
UNITARY REPRESENTATION OF
SL (2,R)
Hence we have €"lg)=TrF'(g)=TrFn(() R
O
- (In+I-R-(n+l) 1t (1-2-9 as was shown in the proof of Ch. 11, Proposition 2.5.
Theorem 7.5. For each TI E N,n r 1, and j we have (7.100) Proof.
+
E
q.e.d.
{O,g) and for all g E G ,
+
@j.n+j(g)= (a(n+J-l) (g) @"+j(g) @-"-j(g)
.
By Theorems 7.2 and 7.4, we have
and
Hence we have (7.100) for all g E G1'. On the other component GI'of G , we have OJ*"+'(goUago-') =0 ,
and (@+j
(n+j-# +@-n-')(gousgo-') = -sinsin (0/2)
0
Hence (7.100) is valid for all g E G,'.
'
q.e.d.
Remark. Theorem 7.5 reflects the following relations among the representations, VJsn+j,Facn+j-')and Un+J@U-"-j. By Proposition 2.6,4), we see that dVzf*n+jf-,-a,=dVjj.n+jf*=0
and the subspace Q(j, n+j) of Q=La(U) spanned by IfPlpzn or pS-n-2jl is invariant under V f ~ " +The j . subspace Q ( j ,n + j ) has codimension 2(n + j)-1 and the representation induced by Vfvn+j on the quotient space
343
INVERSION FORMULA
Q/@(j,n+j) is equivalent to composed thus :
The subspace Q(j,n+j) is de-
FZcn+j-l).
W, n+j) =Q+Ci, n + A @ @-(j, n + A , where Q+(j,n+j) and &(j, n+j) are spanned by {fplp>,n}and {f,lpS -n-2j} respectively. Roughly speaking, the representations induced by Vjtn+fon Q+(j,n + j ) and on &(j, n+j) are equivalent to U-"-j and to Un+jrespectively. More precisely, we get Ur("+J) after the completion of a dense subspace with respect to a suitable inner product. These circumstances are reflected in the relation (7.100). Another explanation is also possible. By Theorem 7.2, we see that (7.101) @.J=@jJ-J. (if s = + + i l , (7.101) is another expression of the result of Theorem 2.2: V j J z VJ-'). By (7.101)7(7.100) can be rewritten as a j . 1 - n - f - z(n+j-l) + @n+j + 0 - n - j (7.102) -t This relation can be interpreted as follows. The representation VjJ-"-j leaves invariant the (2n +2j- 1)-dimensional subspace Q(j, n j ) l of 8 and induces a representation equivalent to F2(n+j-1) on Q(j, n + j ) l . The representation induced by VjJ-"-j on the quotient space Q/@(j,n + j ) l is equivalent to Un+J@U-"-jafter extension to a suitable completion of a dense subspace.
+
$8. Inversion formula As for the groups SU(2), R" and M(2) treated in the preceding chapters, we can develop the theory of the Fourier transform on the group G = SU(1, 1). Let 6 be the dual of G. This means that 6 is the set of all equivalence classes of irreducible unitary representations of G . We can choose a representation U Afor each class 2 in 6. Then the Fourier transformf of a function f in L1(G)is defined by the formula n
Thus f is an operator-valued function on 6. We can expect that the original functionf may be recovered from its Fourier transform f,at least for a function f in s ( G ) . Similar inversion formulae for the groups SU(2), Rn and M(2) suggest that there exists a measure p on 6 such that
344
UNITARY REPRESENTATION OF
SL (2,R)
In fact such a measure exists and is given as follows. Put fcj, s )=
1
f ( g )V , - i W g = V f
a
and
f ( n ) = / f(g)Un,-ldg= Ufv n , where f"(g)=f(g-l). Then we have +f(g)= Tr (f(0,i (8.3)
&Io
+1
+iv) Vgo*++ru)~ th
K V ~ V
+
(2n -1) {Tr( f ( n )U,") Tr (f(-n) U,-")} nta-12 nS1-
for every f e g ( G ) . Hence the support of the Plancherel measure p is equal to the union of the principal continuous series and the discrete series. The complementary series do not contribute to the inversion formula for the functionsf in s ( G ) or L2(G).Putting g = 1 in (8.3), we get +(8.4) f(l)=&I0 Oo.*+fu(f)v thxvdv
where W'(f) = Tr( Vf
=
f(g-')W'(g)dg
and
/a
-s.
W f )=T W f 1v
"
-
f(g-l)@n(g)&
The functions W 8and 8" are the characters of W aand U n respectively (cf. $7). The general formula (8.3) is obtained from the special case (8.4) by replacingfwith L,-lf. Hence we study mainly the formula (8.4). In the study of harmonic analysis on the group G = S U ( l , l), the integral formula in Proposition 7.13 plays an essential role. This integral formula gives a decomposition of the Haar integration on the group G into two stages; one is the integral (the mean) over each conjugacy class consisting of semisimple ( =diagonalizable) elements; the other is Haar
345
INVERSION FORMULA
integration over each of the Cartan subgroups H and K with the weight functions 2(sht/2)' and 4(sin 6/2)* respectively. In virtue of this integral formula, the Fourier transform {W'cf), P c f ) } off E g ( G ) is obtained by first taking the means Ff and Ff on the hyperbolic and elliptic conjugacy classes, and then carrying out the Fourier transforms on the abelian Lie groups Hand K.We shall see later that the derivative F f ' ( 6 ) of the mean FfKgives the value f(1) off at the identity element 1, and that consideration of the jump of Ff=(6) at 6 =O gives a relation between Ff and FfK.Then these two facts and harmonic analysis on A E R and K s T give the inversion formula on G. The results and the proofs of this section are due to Harish-Chandra [2], [8]. First we give two Lemmas which will be decisive in the proofs of the above stated results.
f(6e', 6e-t)(eC-e-')dt,
g(6)=6
(820).
J O
Then g is a C-function on R - {0} with compact support and satisfies lim-(O)= dg 0-0 de
-2 f(0,O).
In particular dgld6 can be extended to a continuous function on R. Proof. Since f belongs to g ( R a ) , g is a C"-function on R - (0), and we have
ss
f (Be', 6e-')(ec-e-')dr
g'(e)=
{e%+e-'fv} ( W ,ee-')(e*-e-')dt
+\:B
=J +J
e-tf dt
( e ' f + eeslf,)dr-j 0
0
(6fv-6fs-6e-2t
fv)df for any 6 2 0,
0
lo rn
where fs = aflax and fy =af/ay. Since 1f(x, y)]g ]Ifl]-
and
we have
(8.6)
limj e-C f(Bet, Be-')dt =f(O, 0) 0-0
0
by Lebesgue's dominated convergence theorem. Similarly
e-Vr = 1,
346
UNITARY REPRESENTATION OF
SL (2,R)
Since the support off is compact, there exists a T>O such thatf(x, y)=O unless Max(lx1, Iyl)s T. Then f,(Be', Be-')=O ( t 2 0 ) unless lelet$ T. Hence
Therefore we have
J
f,(eet, ee-')dt=O,
lim 8 0-0
0
because lim 0 log 1191=0. Similarly 0-0
rm
lim 0 8-0
J
f=(Bec,Be-')dt = O . 0
Put x=Be' and y=Be-'. Then we have
and
Since +/;$(xf)dt=
B-l[(xf)(Se',Be-')];= -f(B,
0) ,
we have
Summing up these results we get Lemma 1 .
LEMMA2. The function g in Lemma 1 satisfies
Proof. Let O<e$T and Bef=x. Then
q.e.d.
INVERSION FORMULA
Since If(x, Px-')lS Ilfll-,
(8.8)
347
we get
lim 01; etfdt =/:~(x, 0)dx =/"f(x,
R*+O
o)&.
By (8.6) and (8.8), we get the first equality in (8.7). If 8<0,then e/retfit
=/->(x, 0
o)&
~x-')dx-/->(x, 0
as 8- -0.
q.e.d.
Delinition 1. We denote by go(@ the set of all functionsf in g(G) satisfyingf(x) =f(x-') =f(uxu-') for every x E G and for every u E K.
Proposition 8.1. For each functionfin g o ( G ) ,put (E
= f1)
,
where dg and dg* are G-invariant measures on GIH and G / K (cf. Proposition 7.6 and 7.12). Then the function F f K is a C"-function on R-2aZ and its graph has jumps at e =0 and 8 =28. The jumps are given by (8.9) F f K ( + O ) - F f K ( - O ) = ~ F f ( l )and (8.10) FfK(2r+ 0) -FfK(2z-0) = -A F ~-(1 ) . ProoJ Since K is an Abelian subgroup and a null set in G, we have
by Lemma 1 in $7.By Proposition 5.3, the last integral is equal to (8.11)
.
2n/~f(a,u,~~-~)shtdf
Since
and f E g o ( G ) has the compact support, there exists a constant M>O such that f(atueat-l)=O if Itl>M and e # 2 d .
348
UNITARY REPRESBNTATION OF
SL (2,R)
Hence the integral (8.11) is convergent and FIK(R) is a Cm-functionon If 0 = 2 n s (n E Z), then the integral (8.11) R - ~ ~ Tfor Z eachf in go(@. is divergent unlessf((- 1)")=0. By (8.12) and Lemma 2, we have
Ffg(+0) = lim sin (e/2)H(6) =2-1 lim 0 H(0) e-+o
8-+O
Similarly we have
FlK(e+ 2 ~ ) =-F,lK(e)
(8.13)
wherefi(x) =f(-x), we have (8.10).
Proposition 8.2.
For each f E .go(G), put d G f ( 6 ) = ~ F 7 ( 0 ) , 0 E R-2nZ.
Then Gf(R) is a C--function on R -2 x 2 and can be extended to a continuous function on R. If the extended function is also denoted by GI, we have Gf(0) = -rf( 1) and G,(27~)=sf( -1) . Proof: By (8.11), (8.12) and Lemma 1, we have d -2nf(l)=lim-(~H(~)) e-o de
d d8
=2 lim-(sin (@/2)H(@)) =2 lim GI(@ e-o
.
By (8.13) and the above result at 8=0, we have limG,(O)=zf(-l). 3-9. Hence lirn GI(@ exists and is finite for each n E 2, and G, can be extended e+'.mt
INVERSION FORMULA
to a continuous function on R.
349
q.e.d.
The derivative dG f / d e=daFfy e ) / d e 2is discontinuous at e = 2nx (n E Z ) , but it has finite limits when e tends to 2 n x 4 0 . Hence GI is a piecewise C1-function. To prove this fact, we need the notion of "radial part" of the Casimir operator. Although this notion may be defined in a general setting, we restrict ourselves to give the necessary minimum. (For the general definition and properties of the radial part of a differential operator, see Helgason [6].) Definition 2. Let w=XOa-Xl'- Y' be the Casimir operator on G = SU(1, 1). For each function 4 in g ( K ' ) , put f(gusg-')=@(ue).Then f belongs to C"(G,'). Let (of)' be the restriction of wf to K'. Then the is a linear transformation in C"(K') and mapping d ( w ) : $-(wf)supp (d(w)$) c supp (+). Hence d(w) is a differential operator on K' which is called the radial part of o on K'. For each f in g ( G , ' ) , put (8.14)
f(gusg-')dg*.
F(B)=/
GlR
Then F belongs to s ( K ' ) . Since 0 is invariant under the left and right translations La and Rg, we have i3lR
Proposition 8.3. Put a(@)= 2sin(B/2) and L= da/dea.Then we have d ( w ) =6-' L 6-4-', (8.16) where 6 in (8.16) implies the operator f~ 6f , and 0
(8.17)
0
F . f K ( ~ ) = ( ~ + 4 - 1 ) ~ f ~ ( ~ )for all f e g o ( @ and 6
E 2aR.
The second derivative daFf(@)/dB1 has finite limits as B-+2nxfOfor each n E 2.In particular, Gf(B)=(Ffg)'(B)is a piecewise C1-function on R. Proof. Since o =Xol X12 Y', A(@) is a second order differential oper-
-
-
ator on K' whose highest term is equal to Xoa=da/de'=L,i.e. (8.18)
d ( w ) =L
+lower order terms .
350
UNITARY REPRESENTATION OF
SL (2,R)
Let d ~ ( G 2 'be ) the set of all real-valued C"-functions on Gt' with compact supports. Then we have (8.19) (of,&) =(f,4) for everyf andji in d ~ ( G s ' )where , the inner product is given by (fi,A)=
lGs,fi(g)A(g)dg. ~f fi satisfies fi(gu,gg-l)=fi(u,) for every g E G and
U ~ E K 'we , have by (8.14), (8.15)and Proposition 7.13
inner automorphisms, we and products are defined by ($1,
$l(us)$a(us)6(B)2d8. The mapping fH F is a surjective
+a)=('Ir)-'J 0
mapping from d ~ ( G s 'onto ) d a ( K ' ) . (The proof is entirely similar to that of Lemma 1,l) in 97.) Hence&) is a symmetric operator. Since 6-10L06is also a symmetric operator whose highest term is equal to L, d(o)-6-10 Lo6 is a symmetric operator of order S 1. Since there exists no symmetric differential operator of order 1, d(0)-6-~oL06 must be a function c. Operating with d(0)-6-~oLo6 on the constant 1, we get c=d(o)1-6-'L(6)=(01)-+4-'=4-'
.
we have Hence we have d(0)=6-~0L06+4-'. For each f in go(@,
LK
Fe,K(e) =2 - 1 ~ ) (of)(gusg-l)dg*
+
=2-1s(e) ( A ( ~ ) F (e)) =2-1(~6 4 - 9 ) ~ ( e )
By Proposition 8.1, both F,g(B) and F-,"(e) have finite limits when e-+ 2 n r f 0 (n E Z), hence the second derivative (Ffg)"has the same property by (8.17). Thus (Fig)"is a piecewise continuous function and G, =(Fjg)' is a piecewise C1-function on R. Definition 3. For each function f in d ( G ) =
cf : G-CI f is a C"-func-
351
INVERSION FORMULA
tion with compact support},put
As we shall see later, the different parts of the inversion formula correspond to f + and f - . Hence it is convenient to study f + and f - separately. These two parts are analogous to Fourier cosine and sine series which correspond to even and odd functions respectively.
+
Put s =t i;l and
Proposition 8.4.
p*(t) =~,,(a) =e ~ / ~ / ~ ~ f * ( u t n . ) ~ .
Then for every f E go(@, we have (8.20) W'( f - ) =@'**(f+) =o , Do**(f + )=
(8.21) (8.22)
G***(f-) =
1:. S
p+(t)e*Wt and (p-(r)e"tdt
.
-0I
Proof.
By Proposition 7.5, we have
{l m
o j - s ( f )=2-1
e"tF,(ut)dt+ (- I)s~[
-m
e"CF,(--a,)dt)
-_
.
for every f s go(G), where j E {0,+} and s=++i17. Since f*(-ut)= ff(ut) and F l ( f u t ) = fF,(ut), we see that (8.20), (8.21) and (8.22) hold. Definition 4.
For each n E 2-'2 and n r 1 , and for each f E S ( G ) , put D"( f
Proposition 8.5.
(8.23) (8.24)
)=en( f ) +e-yf ) .
For each f E s o ( G ) , P ( f - ) = O if n~ 2 and Dn(f+)=O if n s f . 2 - 2 .
Put
F*(O)=
1
QlK
f*(gusg-')dg*
.
Then for every f s SO(@ and n E 2,n 2 1, we have
352
UNITARY REPRBSBNTATION OF
-2n-l
SL (2,R)
1:.
sin (n-+) e sin+c?F+(B)d@
and (8.26)
On++($) =2
e-n5p-(t)dt J
O
s:.
-27~-1
sin no sin +8F-(B)dB .
By Theorem 7.4, the distribution D" is equal to a function e-(n-+)ltllsh+tl-l(- l ) 4 n j if g=go(- l)afutgo-lE GI' , D"(g)= -sin(n-+)O(sin+O)-' if g=goueg0-l E Ga',
Proof.
lo
if g E G - G .
Hence we have by Proposition 7.13 D"(f>=2fme-(n-+)tsh +t
+ 2(-1)sn[e-(n-h)t
Hf(gatg-l)dg
sh+rdt/
f(g(-at)g-1)dg
QfR
By Propositions 7.6 and 7.7 and by the assumption that f(uxu-l)=f(x), we have
We treat the case 1 ) n E Z and the case 2) n E + Z - Z = {nlnE $2 and n 4 Z } separately. 1) n E Z . Then (- l)sn= 1 and f,(g(-a)g-l) = &f,(gatg-l). Hence for Dncf+) (or Dn(S-)), the first integral in (8.27) is equal to (or cancels) the second one.
INVERSION FORMULA
353
+
Since sin (n-3)e sin +e =+[ -cos no cos (n- 1)8] has the period 27~and f*(gUb+lxg-l)=f*(-gusg-l) = ff*(gubg-’) , the third integral in (8.27) is equal to
(8.28)
Hence we have proved (8.23) and (8.25). 2) n E 3 2 - 2 . In this case (-l)2n=-l and a(e)=sin(n.-$)ex Hence we can prove (8.24) and sin38 satisfies a(8+2n)=--a(B). (8.26) similarly.
Proposition 8.6. Put G+=GI, for each f E 9 ( G ) and
1:.
G+(O)cos(n+3)8dB,
c~=zc-’
g , = .-1[
-.
G-(8) cos n8 d8 for each n E N,
and put
Then we have
(8.29) and m
(8.30)
G-(O)=
C
6ngn
.
n=O
Proof. By (8.28), G-has the period 2n and G+has the period 4n. Hence A ( @= ) G+(B)cos38 has the period 27~.Since both Ga and A are continuous and piecewise C1-functions (Proposition 8.3), they can be expanded in Fourier series which are everywhere convergent (Ch. I. Theorem 5.1). Since G- is continuous at 8 =0 and is an even function, we have G-(0) = m
C &gn. Similarly we have
n-0
(8.31) where
354
UNITARY REPRESENTATION OF
SL (2,R)
an=x-l[G+(@) cos 319cos no do .
Since B(0) = G+(B)sin+e is an odd function with the period 28, we have m
0 =B(0)=
(8.32)
1bn ,
where
n-1
bn=r - 1 1 G+(e) sin 30 sin no de . -x
Since
an--bn=cn
-
and an+bn=cn-1 for all n2 1, we get
C
G+(~)=+co+
n=l
m
Cn=+co+
C
Cn
9
n=O
by taking the difference and sum (8.31)+(8.32). Since the series Ccn m
ca
is convergent, we conclude that co=0 and G+(O)= C cn = C cn . n-1
n-0
Proposition 8.7. For each functionfin ~ o ( G )we , have
Proof. Put Ht=F,&:lag.Then Propositions 8.2, 8.6 and 8.1 and integration by parts show that
Similarly we get (8.34) by integrating (8.30) by parts.
q.e.d.
355
INVERSION FORMULA
LEMMA 3. For any 1)
/:@+)-'sin
3)
/::thysin
A E R,we have
At dt =2n th xA ,
Atdt= 2r cthA r ,
t
t d t cthye<"dt = 2x-(cthxR), d2 1) Put I = S_(sh+)-'
Proof.
(the integral of a distribution) sin At dt and f(z) =etAg/sh(z/2). Then
f is meromorphic on the whole z-plane and has its simple poles at z=2nri (n E 2).We integratef(z) along the contour C in Fig. 6. 2 Ti
-
ir
"
c
Fig. .6
Since sh(z/2) is an odd function, we have lim
R-+m, r*O
(I:', + /;)f(x)dx
Since f(z +2 4 = -e-aslf(z), we get ( / r + l d +/ - R + l d ) lim R*+-* r-0
R+aA
= iZ .
f(z)dz= ie-'x'Z.
-r+ht
The inequality If(&R+ jy)l 5 2 ezxl2l(eRfa-e-R"1-' , 2 n 2 y h 0 , implies that
s.
R+lrt
+ .
-0
and -R+lni
when R-, co Since z =0 is a simple pole of f(z), the Laurent expansion around 0 has the form
356
UNITARY REPRESENTATION OF
f(z)=
SL (2,R)
>+ao+a1z+ .... Q
Hence the integral on the semicircle around 0 is equal to a/: id8= -da= -xiRes f ( z ) = -2wi. r-0
Similarly, the integral on the semicircle around 2xi is equal to -ni Resf(z) =2 ~ i e - ~ ~ l . .-Zd
Summing up the above results and using Cauchy's theorem,
we get
+
i(1 e-~r~)l=2ni(l-e-3*~) and t=2nthwA.
"(
2) Since a1 (sh+)-'sin
I f ) = t (sh+)-'
cos At and t
over R,we can differentiate 1) under the integral sign and get
1:-
t(sh t/2)-l cos At dt = 27cd(th nA)/dA.
Since t(sh t/2)-' is an even function, we get 2).
1:-
3) Put J=
erlccth t/2 dt and g(z)=e*llcth (42).
The poles of g(z) are same as those of f(z) in 1). We integrate g(z) along the same contour C as in 1). In this case g(z 2 4 =e-l=lg(z), Res g(z) = 2 , Res g(2)=2e-ax2
+
S-0
a-lrt
.
Hence we have (l-e-an2)J=2ai(l +e-z*2) and J=2x cth nR . 4) We can differentiate 3) under the integral sign and get 4). Proposition 8.8.
For any f in g o ( G ) , we have
357
INVERSION FORMULA
I::+*.
(8.36) ProoJ
f)R cth X R d~
++(I(
Put and @ L 2 ( f ) = @ i * + + t 2 ( f - ) .
@+l(f)=@O~++~~(f+)
Then by Proposition 8.4, we have
1-
~ f= )
pa(t)e(a'dt
.
-01
Since (p+(t)=F,,(at) belongs to s ( R ) , we get S_p.'(t)e(lldt=
-iAQal(f)
by the integration by parts. Put
+,(A)
=
1-
t-lp*'(t)e$Jtdt.
-OD
Since p+ is an even function, p*' is an odd function and t - I p+'(t) belongs to g ( R ) . Hence belongs to 9 ( R ) (Ch. 111, Theorem 1.2) and can be differentiated under the integral sign. We have
+,
#*'(A)
=i
1:-
p*'(t)eWt .
Since t - l ~ + ' ( t belongs ) to y ( R ) and t(sh$)-l
belongs to L1(R),we
can apply the Parseval equality for the Fourier transform on R (Ch. 111, Theorem 1.3), and get d t-'p+'(t) t(sh t/2)-'dt= ++(A)z(thnR)dR
/Im
jm -_
=-
1:-
j:-
++'(A)thddA = -
R th ZR ~ D + ~ ( f ) d 2 .
Similarly, we get t-'p-'(t)t cth t/2 dt = -
Proposition 8.9. For any f E go(@, we have
and
358
UNITARY REPRESENTATION OF
277f-(1)=
(8.38) Proof.
fb
SL (2,R)
m
@-'(f)IcthxRdR+ CnD"+'(f-). n-1
By Proposition 8.5 and integration by parts, we get
r-
m+l
+
1:
v+'(t)(sh t/2)-ldt
=2lrf,(l)-+f-
-m
@ + ~ ( Jth) dR d . ~
The last equality follows from Propositions 8.7 and 8.8 and the fact that q+'(t)(sh t/2)-' is an even function. Since V j .*+%a z Vj* (Theorem 2.2), we have O*^(f)=cD*-^(f). Hence the last expression in the above sequence of equalities is equal to 277J+(l)-/m@+2(f)R 0 thxRdI. We have proved (8.37).
s:
Put D * ( f - ) = 2
p-(t)dt. Then we have
INVERSION FORMULA
{
m
=2 lim (m++)(o+(O)-2n-'E m-+"
359
n r sinnOH-(e)de} n-1
-r
+jLp-'(t)cth-dtt 2
Dewtion 5. For each functionf in L1(G),the Fourier transform f of f is defined as the operator-valued function on = {(j,3 + iR) I R >0, j E {O, &I1 u {nln E 2-'Z, In1 2 1) given by
e0
f ( j , &+in)=
f(g)V,-if.*+*Adg=vjvj,++*2 So
and
f(n)=/
f(g)U,-lndg= UIvn,
1 where the Haar measure dg is normalized as dg=-eecdedtdf. 47r
Theorem 8.1. (The inversion formula for d ( G ) ) . For each function f i n g ( G ) , we have (8.39)
++a)Vgo,++*l)l thddr2
f ( g ) = z1/ " Tr(f(0,
+
Tr(f(+,+ 0
1 +-4nnr%-le E (2n-1)
+ il) V,*.*+*')A
cth n l dR
{Tr(f(n) V,")+Tr(f(-n)
V,-")} .
n2l
Proof. First we assume thatfbelongs to go(@, i.e.,fsatisfiesf(um-1) = f ( x ) =f(x-l) for all x E G and for all u E K. Then by Proposition 8.4, we have Tr(f(O,+
+ 9 ) ) =O0*+ + c l ( f=) O0* (f+) *+*l
=@+^(f).
Similarly
+
Tr(f(&, & iR)) =@ - l ( f ) By Proposition 8.5, we have Tr(f(n))+Tr(f(-n))=
.
K(f+) D
if n E Z ,
(f-) if nE3.Z-Z
360
UNITARY REPRESENTATION OF
SL (2,R)
Hence by adding (8.37) to (8.38), we get
(8.40)
f(1) =
$1:
Tr(f(O,3 +il))R th nR d2
1
1
+& n r t e . n p i
(2-
1)(Tr(f(4)+Tr(f(--n))
for all f e ~ o ( G ) . Now we turn to the general case and put f"(g)=J
K f(kgk-')clk.
Then we have Vh-lj.JV,f.*Vhj.*&.
V,OhJ= /K
Since V,j**is of trace class (Theorem 7.1),
-
(V,j**V&*fP,
=Tr
Vlj.Jfp)
V,jTJ
p--m
for every k E K and the series is absolutely convergent. Hence we have
=IK
Tr(VfVj.*)dk=Tr(Vjvji~)=Tr(f(j,s)).
Similarly, we have Now put f"(g)=f(g-l).
Trf(n)=Trf(n) . Since W(*a+) =P( +a,) ,
by Theorem 7.2, we have W(g-') =W*(g) and
By Theorem 7.4, we see that
36 1
INVERSION FORMULA
Hence we have Tr((f")W) =Tr(f(-n))
*
Put
h =.)(P +P") Then by the above results, we have Tr h(j, s) =Trfu, s) (8.41)
.
and Tr h(n)+Tr h( -n) =Trf(n) +Trf( -n)
(8.42)
.
Since h belongs to so(G), (8.40) is valid for h. Hence by (8.41) and (8.42), (8.40) is also valid for$ We have now proved (8.39) for every f in 3(@. Put (L,f)(x)=f(g-lx). Then we have
(L, f )"(j, s) = f(j,s) Vg-lf*'and (L, f )^(n) =f ( n ) V,-l . Therefore, we obtain (8.39) by replacingfin (8.40) by L,-$ q.e.d.
Tbeorem 8.2. (Parseval equality). For every f in s ( G ) , we have
where I] Proof.
[I, means the Hilbert-Schmidt norm. Put a= f * f *
where
f*k) =f(g-').
for each f ES(G)
Then u(1)=JG I f(g)lVg ,
Tr 40,s) =Tr(f(j, s ) f ( j ,s)*) = IIfG, s)ll2 for s = 2 4 + i 2
and Trd(n) =Tr(f(n)f(n)*) = Ilf(n)llla .
Hence equation (8.40) applied to u gives us Theorem 8.2.
q.e.d.
362
UNITARY REPRESENTATION OF
SL (2,R)
99 Harmonic analysis of zonal functions Definition 1. A function f on G=SU(l, 1) is said to be two-sided Kinvariant or a zonal function, if it satisfies f(kgk') =f ( g ) for each g E G and k, k' E K. The set of all complex valued zonal functions on G is denoted by A. In this section, we study Fourier transforms of zonal functions. In particular the images of the spaces of C"-functions with compact supports and of rapidly decreasing functions are determined. Let n be a half-integer (i.e. n E $2)and put xn(ue)=elne
The set of all C-valued continuous functions on G with compact supports is denoted by YG). Proposition 9.1. Let U be a Banach representation of G=SU(l, 1) on a Hilbert space H such that u k is a unitary operator for each k E K and fn andf, be two vectors in H satisfying (9.1) Utft=xi(kYi for each k E K (i=n, m)
.
Then the operator
Uf =/Gf(g)uGd.g for a functionf in L (G) n A satisfies
.
(Uff n ,f,) =0 unless (n,m)=(0,O)
Proof.
Sincef is two sided K-invariant, we have (uffn,fin) =
1
f(k-lgK-1) (u a f n fm)dg 9
Proposition 9.2. If the restriction to K of a unitary representation U of G does not contain the identity representation xo, then U,=0 for every function f in L(G) n A. In particular, f(+,s)=O for every S E C and f(n)=O for every nE+Z,InlBl. Proof: The representation space H of U has an orthonormal basis
HARMONIC ANALYSIS OF ZONAL FUNCTIONS
363
Cfr)rcr satisfying (9.1). Hence the first part of Proposition 9.2 is a direct consequence of Proposition 9.1. The last half is clear from the first half and Theorem 6.2. Proposition 9.3.
Put
fn(c)=cn
for ~ E (lCl=l). Z Then we have
( V , o ~ ~ ~=,0f unless ~ ) (n,m)= (0,O)for every f E L(G) nA and s E %. Proof. Clear from Proposition 9.1. By Proposition 9.2, the support of the Fourier transform f of a zonal functionfis contained in the set { Vo.++321120}. By Proposition 9.3, the operator valued Fourier transform f ( 0 , s) of f E L(G) n A is reduced to a C-valued function ( Vlo~*fo,fo)which will be denoted by {(s). The inversion formula for a function f in g ( G ) n A can be written in terms of the scalar valued Fourier transformf(s). In fact we have the following proposition.
el=
Proposition 9.4.
Iff belongs to s ( G )n A, then we have
+f ( g ) = k j f(++il)#(g, ++il)AthxldR for each gEG
Proposition 9.5. The function #(g, s) defined by (9.2) satisfies (9.4) #(kgk', s)=#(g, s) for every k,k' E K and g E G, P
364
UNITARY REPRESENTATION OF
SL (2,R)
Delinition 2. The function $(g, s ) is called a zonal spherical function. Proof. Sincefo satisfies (9.1) for i=O, 4 satisfies (9.4). By the definition of Vg0.*,we have
(vgO,* f)(C)=e-*t(o-'.C)f(g-'.C) * Hence +(g, s)=
e-*t(g-l.c)dC
(~>ssfo,fo)=/ l7
q.e.d. Proposition 9.6. I f f belongs to L1(G)n A, then the Fourier transform f(s) is given by (9.6)
f ( s )=
[Ff(t)e(*-'%ft for Re
s=
1 3
-m
in terms of the Radon transform Ff ( t )=et"
L-
f(atne)& .
Proof. By Proposition 9.4, we have
n
n
q.e.d. Dewtion 3. The transformation :f H f l defined by (9.3) is called the spherical transform on G. By Proposition 9.6, the spherical transform f-f on the integrable zonal functions is decomposed into the Radon transform f - F f and the
365
HARMONIC ANALYSIS OF ZONAL FUNCTIONS
ordinary Fourier transform on the real line (PA). This decomposition enables us to determine the precise image of g ( G ) nA.
LEMMA1. 1) If v E C ( R ) is an odd function, then there exists an even function E C"(R) such that
+
.
v(t)=t+(t) for every t E R 2) Iff E C"(R) is an even function, then the function,
+
g(x)= f(&) is a C"-function on [0, a). 3) The function k(x) = [log(x J k T ) ] * belongs to C"([1, 4) Iff E C"(R) is an even function, then the function h(x)=f(log ( x + J m ) ) belongs to C"([l, a)). Proof. 1) It is sufficient to put
+
+
03)).
+
+
2) It is clear that g is a C"-function on the open interval (0, a). Hence it is sufl6cient to show that g is differentiable infinitely many times at x=O from the right. Put x = P . Then we have (-$>.,(x)
=
zyf(f),
(&
for every k E N and x >0.
Sincef is an even COD-function, the right hand side of the above equation is also an even C"-function. Hence by l), the limit
exists and is finite. Hence g is differentiable k-times at x=O from the right. Since k is an arbitrary integer 20,g belongs to C"([O. 03)).
+
t
3) Put f(t)=xf. Then f is an analytic function on a neighborhood of t = O . Put
Then I(x)=f(t) and
Hence I belongs to @"([1, + a)) by an argument similar to that in 2). Hence k ( x ) = [ l o g ( x + , / ~ ) ] 2 = ( x 2 - 1 ) I ( x ) fbelongs to C"([1, a)).
+
4) Since h(x)=f(t)
=g(t ') = (g k)(x), 0
366
UNITARY REPRESENTATION OF
h belongs to C"([l,
+ a)).
SL (2,R) q.e.d.
Definition 4. Let C+"(R) be the set of complex-valued, even C"-functions on R and 9 + ( R )be the subset of C+"(R) consisting of functionswith compact supports. For each function f in C+"(R), we put f [ x ]=f(cht) for x =cht . By Lemma 1, the mapping f(t)t+f[x] is a bijection from C+"(R) onto C"([l, w)) and maps 9 + ( R ) onto 9+([1, a)).
+
+
Proposition 9.7. If the functionf belongs to C"(G)n A, then the function d t )=f(at) belongs to C+"(R). The mapping f ~p is a bijection from C"(G) n A onto C+"(R) and maps g ( G ) n A onto g + ( R ) . Proof. Since the Iwasawa decompositiongnusatncis a diffeomorphism (Proposition 1.4), (@,t, c) can be take as coordinates on G. Hence p(t)= f(at)is a C"-function on R. p is an even function by Proposition 2.11, 2). Since every element g in G can be written as g=u,at,u, (proposition 5.2), a function f in A is uniquely determined by its restrictionflA to A. Thus the mappingf-p is injective. Let p be a function in C+"(R). Put (9.7)
Then f is a well defined function in C"(G) n A. In fact, the expression g= u,atu, (O
In the following, we identify f E C ( G ) nA with (p(t),, and put f[x]= f(aJ where x =cht.
HARMONIC ANALYSIS OF ZONAL FUNCTIONS
Proposition 9.8.
367
The Radon transform R :f HFl(f)=etfa/Im f(utnt)dE
(9.9)
is a bijection from g(G) n A onto g + ( R ) . The mapping S inverse to R is given by
Proof. Since F,(t)is an even function by Proposition 7.14, F,(f) belongs to g + ( R ) .Put x=cht. Then by (9.7) and (9.8), we have
(9.11)
FZ[x]=ecia
Differentiating the above equation with respect to x, we get
Ilcnce we have
We have proved that SRf= f for each f E d ( G ) n A
.
Now let F(f) be an element in . g + ( R ) . Then F[x] belongs to d([1, + w)) by Lemma 1 and the functionf[x] defined by (9.10) also belongs to Cm ([I, a)). Hence the function f(t)=f[chf] belongs to . g + ( R ) and f can be extended to a function in s ( G ) n A by Proposition 9.7. The latter function is also denoted byf. Then we have
+
Therefore we have
RSF= F for each F E g + ( R ) .
q.e.d.
COROLLARY to Proposition 9.8. The Radon transform R maps the set { f c g ( G ) n A l f[x]=O if x>a} onto { F ~ g ( [ l+, a ) ) [ F [ x ] = O if x>u).
Proof.
The corollary is clear from (9.11) and (9.10).
368
UNITARY REPRESENTATION OF
SL (2,R)
By Propositions 9.6 and 9.8, we obtain the following analogue of the Payley-Wiener theorem for the spherical transform. Theorem 9.1. Let E be the set of all C-valued functions p(s) of a complex variable s satisfying the following three conditions: 1) p is an entire function. 2) For each m E N,smp(s)is of exponential type, i.e. there exists a constant C, and a>O such that (9.12)
l(1 -tIsl')"p(s)l
s C,,,eolBeal for all
s 6C
3) p satisfies the functional equation (9.13)
p(1 -s)=
p(s) for all s E C .
Then the spherical transform
Y : f 4 M=/S(g,4.-:
s)&
maps 9 ( G ) n A onto E bijectively. For a fixed constant a> 0, the spherical transform p=fof f in g ( G ) n A satisfies (9.12) if and only iff satisfies (9.14) f(ac)=O for Itl>a. Proof. Iff belongs to 9 ( G )n A and satisfies (9.14), then the Radon transform F&) off belongs to g + ( R ) and satisfies F,(t)=O
for Itl>a
by Proposition 9.8 and its corollary. Sincef ( s ) (more precisely (2r)ff(i(3-s)) is the Fourier-Laplace transform of I;, E g+(R)(cf. Proposition 9.6), thePayley-Wiener theorem for the real line (Ch. 111, Theorems 4.1 and 4.2) proves that f ( s ) is an entire function of exponential type and satisfies (9.12) for each m E N. Since F,(t) is an even function, we have f(+-i1) =
1
-_~ , ( t ) e =~[?(t)e-"Cdt=f(+ t
+i l ) .
Hencef satisfies (9.13) on the line Res= 1/2. Since the both sides of (9.13) are entire functions of s. f satisfies (9.13) for all s E C. We have proved that fl mapps g ( G ) nA into E. 9-is injective by Propositions 9.8 and 9.6 (or by Proposition 9.4) Now we shall prove that Y is surjective. Let p be a function in E satisfying (9.12) for a fixed a>O. Then by the Payley-Wiener theorem (Ch. 111, Theorem 4.1) there exists a function F in g , , ( R ) such that l?(l)=cp(++i;O for all 1 E R. Since cp
HARMONIC ANALYSIS OF ZONAL FUNCTIONS
369
satisfies the functional equation (9.13), F is an even function of t. Hence by Proposition 9.8 and its corollary, there exists a function f ~ g ( G ) nA satisfying (9.14) and Ff=F. Thus we have proved that f= 9. q.e.d. The next aim of this section is to establish the uniqueness of the inverse spherical transform, which will be done in Theorem 9.2. For this purpose we give some elementary properties of the zonal sphericalfunction $(g, s). Most of these properties are valid for any non-compact semisimple Lie group G and a maximal compact subgroup K of G. Proposition 9.9. The zonal spherical function $(g, s) =(Vgo.yo, yo)has the following properties: 1) For each fixed g E G, $(g, s) is an entire function of s.
2) $(g, s) =$(g, 1 -s )
for every s E C and g E G,
3) $ k , s) = $ k 9 3)
for every s E C and g E G.
4) $(g-l, s)= $(g, s )
for Re s= 1/2 and g EG.
Proof. 1) From the proof of Proposition 9.5, we see that (9.15)
$(g, ~ ) = / ~ e - ~ ~ ( dk. g-',~)
Hence $(g, s) is an entire function of s. 2) If Re s= 112, then there exists a unitary operator A on .fj=L4(U,dc) such that A V;J-' = V$'A for every g E G. (Theorem 2.2) Since V$'Afo=AV$l-#fo=Ah
for every k E K, Afo must be a scalar multiple of fo.Namely there exists a complex number c such that Afo=cJb, Icl=l.
Hence we have #(g, 1- ~ ) = ( V ~ ' - ' f o , f o ) = ( V ~Ah, ' Ah)
= ( v ; ~ y o , f o ) = ~ (s) g,
for Re s= 1/2. Since $(g,s) and $(g,l -s) are entire functions of s. $(g, 1 --s)=$(g, s ) for all s E C .
370
UNITARY REPRESENTATION OF
SL (2,R)
3) The expression (9.15) of #(g, s) gives 3) immediately. 4) Since Yo*'is a unitary representation when Res- 112, we see that
fW1,s)=(vv-~O.Jfo,fo)=(fo, V v O
~ ' h ) = ~ .
Proposition 9.10. Let s=o+i2 be a complex number in D = Is E C104 Re s$ I}. Then Proof.
ldg, s>ld ldg, dl d 1 for every g E G By (9.15) we have
1
I#(g, s>ls
.
e-*t(g-l.k)dk=+(g, a)
K
If 1/2 c a < 1, then there exists the complementary series representation V'. By Propositions 4.3 and 4.4, we have m
( Vg"fO,fO).=
1
=
~ n ( u ) (Vgo.*fo,fn)Cfn,fO)
(vo~*"f~,f~) = @(g,
0)
n=-m
Since V' is a unitary representation, +(g,0 ) is positive definite and satisfies (9.16) l $ ( g , ~ ) l s d 1 , ~ ) = 1forevery g e G (Ch. 111, Proposition 3.1). By the functional equation $(g, 1-s) = #(g, s), (9.16) is valid for O
f off
Proposition 9.11. 1) g ( G ) is dense in L1(G). 2) g ( G ) n A is dense in Ll(G) nA. Proof. 1) Smce the space L(G) of continuous functions with compact supports is dense in L1(G), it is sufficient to show that for each g E L(G) and E >0 there exists a functionf in g ( G ) such that (9.17) Ilf-gIll<E There exists a function h in a ( G ) such that Ilg-h*gll1-
*
(This part is proved in a way similar to that in the proof of Lemma 3,
HARMONIC ANALYSIS OF ZONAL FUNCTIONS
371
Ch. 111, $1.) Thenf=h*g belongs to 9 ( G ) and (9.17) is proved. 2) If g belongs to L1(G)n A and E >O, there exists a function f E 9 ( G ) satisfying (9.17). Put (9.18)
f"(x)=
11 K
f(kxk')dkdk'.
K
Then we have f" E 9 ( G )n A and
=Ilf-gll1
*
Proposition 9.12. For everyfe Ll(G) nA, the spherical transform f of f has the following properties;
IfMl r:Ilf
1) (9.19)
f(1-s)
(9.20)
111
=f(s)
for every s E D = {slog Re s g lI} 2) f ( s ) is analytic on D = [slOtRes< l} and continuous on D. Proof. 1) (9.19) is a direct consequence of Proposition 9.10. (9.20) is follows from Proposition 9.9, 2). 2) By Proposition 9.1 1, there exists a sequence (fn)nrN in 9 ( G ) nA converging to f in L1(G). Then, by (9.19), the sequence (fn)nrN converges to f uniformly in D. Hence, by Theorem 9.1, f is continuous on D and regular analytic in the interior D of D. Remark. Proposition 9.12 shows that harmonic analysis of integrable zonal functions on G is very different from the classical Fourier analysis on R. Indeed the spherical transform f off in L1(G)n A is an analytic function on D and can vanish only on a discrete set unlessf(g)=O almost everywhere. Hence in particular there exist no functions of compact supports in the spherical transform of L1(G)n A. This fact was first noticed by L. Ehrenpreis and F. I. Mautner [l]. Proposition 9.13. (The analogue of the Riemann-Lebesgue theorem) Iff belongs to E ( G ) n A, then
lim f ( a + 2)=0 uniformly on D
Ill-+-
.
372
UNITARY REPRESENTATION OF
SL (2,R)
Proof. Since 9 ( G )nA is dense in L1(G)nA, there exists a function p in 9 ( G ) nA such that
Ilf--Colll<~/2 * Then we have (9.21)
~ f ( s ) - q ( sI)<&/2 for every s E D. By Theorem 9.1, Q satisfies Iq(s)lS C(1+ Is12)-1 for every s E D. Hence there exists a constant M >0 such that (9.22) l~(u+U)l
2)
/=$(xky. s)dk = $(x, s)$(y, s ) for every x and y in G and s E C.
3) Put $.(g) = $(g, s). Then
9. * f = f ( s ) $ , for every f E g ( ~ n A ). Proof. 1) I f f E .fj=La(U,dc) satisfies VkO" f=f for all k E K,then we have f = cfo, c E C (Corollary to theorem 2.1). Sincef E 9 ( G )nA satisfies f(k-'g) =fa, we have Vkos*Vfo"fO= Vz0.*fo for every k E K. Hence there exists a scalar E C such that Vr0.'f0=l(f y o. Since V,.:J= Vfo** Vgo,*for every f and g in g ( G ) , we see that 1 is a homomorphism of the algebra 9 ( G ) nA into C. On the other hand,
4f)=(VfO,ih f o ) =
SQf
(V:s'foyfo)dg
=(fYA(s) = C W )
Since (f * g)" =gv *f 2) By l), we have
SQ
=
-
",c, is an algebra homomorphism. $S(X)$*(Ylf(x-llg(Y-')dXdY
f(s)&)= (f*dA(4
HARMONIC ANALYSIS OF ZONAL FUNCTIONS
373
for every f and g in s ( G ) n A. From Lemma 2 which follows below, we obtain 2). 3) By 2), we have
q.e.d. Remark. All the results in Proposition 9.14 are valid for every f in L1(G')n A in stead of s ( G ) n A without changing the proof.
LEMMA2. Put ( g , f )=/fff(x)g(x')dx
for each g E C(c) and f E L(G). 1) If a function g in C(G)n A satisfies (g,f ) =O ,ar every f in (G') nA, then g = 0. 2) If a function g in C(G)n A satisfies (g,f ) =O for every f in g ( G ) n A, then g =0. Proof. 1) For each f in L(G), let f" be the two-sided mean off over Kx K dehed by (9.18). Since g is two-sided K-invariant, we have (g, f ) = (g,fO)=O
for every f E L(G).
Replacingf by L,-g, we get (9.23) g*f =0 for every f E L(G) . Now we prove that (9.23) implies g=O. Let x be a fixed element in G and
374
UNITARY REPRESENTATION OF
SL (2,R)
(V,JnCNbe a fundamental system of compact neighborhood of 1 satisfy8 0 be a continuous function on G satisfying ing V,,2 Vn+l. Let f,,
supp (fn) c V,, and E
s.
f n ( x ) d x = 1. Since g is continuous at x for each
> 0 there exists an integer n E N such that Ig(xy-l)-g(y)l
<E
for every y E V,,
.
Since g*fn =O by (9.23), we have Ig(x)l= Ig(x)-(g *fn)(x)l
s
1
I(g(X)-g(xy-')l fn(y)dy 6
J'n
-
Since E is an arbitrary positive number, the last inequality show that g=o. 2 ) As in l), we have ( g ,f)= O for every f in .g(G). in .g(G) such Since for each f in L(G) there exists a sequence (f,,),,.~ that limIlf,*.f-f&,=O (cf. Ch. I11 $1, Lemma 3), we have ( g , f ) = lim(;Z *f)=0 because f n * f E s ( G ) . Hence g(x) =O for almost every n-m
~
E byG 1).
Proposition 9.15. For each s E C, the homomorphism C8 : f ~ f ( sof) g ( G ) n A into C is not zero. Namely for each s E C, there exists a function f in s ( G ) n A such that f ( s )# 0. Proof. Suppose that there exists a complex number s such that f ( s )=0 for every f in s ( G ) n A. This implies ($.,f)= O for every f e d ( G ) n A in the notation in Lemma 2. Hence we have $#=O. This is a contradiction, because $*(1)= 1. Proposition 9.16. Let OJ =Xoa-Xlz - Y a be the Casimir operator of G(cf. Proposition 6.12). Then we have (9.24)
o $ ~ = s ( ~ - - s ) ~for , every S E C .
Proof. We regard an element X in the Lie algebra g of G as a left invariant vector field. Then we have
375
HARMONIC ANALYSIS OF ZONAL FUN.CTIONS
Since Q =~ V O J ( Ois ) equal to s(s- 1) when Re s = 1/2 (Theorem 6.4), we have ~ # ~ = s ( s - l ) # ,for Re s=1/2. Since both sides of (9.24) are entire functions of s, (9.24) is valid for all s E C.
Proposition 9.17. Let cI be the homomorphism of 9 ( G ) nA into C defined by C 8 c f ) =f(s). If ca= Ct, then either t =s or t = 1 --s. Proof. Fix a complex number s. Then there exists a function h in d ( G ) n A such that &)+O (Proposition 9.15). Applying the Casimir operator o to both sides of the equation
9' * h = A(s)#8. we get I;(s)ogs=W(#a
*A)=#, * o ( h ) = ~ ( h ) ~ ( s ) g , 9
because ~ ( hE ).g(G) n A. Hence we have
(9.25)
O#I=i;(s)-'O(h)A(s)ga=Ta(O(h))ca(h)-l~a.
Therefore if C a =Cr we get
s(l-~)=Ca(~(h))Cs(h)-'=
by Proposition 9.16 and (9.25). Hence either r=s or t= 1 -s.
Definition 5. Let L= {++iJlJrO] and Co(L)be the set of C-valued continuous functions f on L which vanish at the infinity: limf (++ U)=0. .I++-
Co(L)is a Banach space with the uniform norm Ilfll..=suplf(x)l. Proposition 9.18. Let r={fly€s ( G ) n A}. Then r is dense in Co(L). Proof. Since g ( G ) n A is a subalgebra of L'(G) in which the product is defined by the convolution, it follows by Proposition 9.14 that r is a subalgebra of CO(L). r satisfies the following three conditions: 1) r separates the points in L (Proposition 9.17), 2) r is self-adjoint (i.e. if (0 E r then 3 E r),and 3) for each s E L, there exists (0 in r such that (0(s)#O (Proposition 9.17). As for 2), put f*(g)=f(g-'). Then we have ( f *>.(s)=E) for every s E L by Proposition 9.9, 4). Let E= L u { 1/2+ i 00 ] be the Alexandroff compactification of the locally compact topological space L. Then the subalgebra C1 +rof C(E) is self-adjoint, separates the points of , ! and contains 1. Hence by the StoneWeierstrass theorem, C1 +r is dense in C(z). Therefore for each f in Co(L) and E , there exist p E r and a E C such that I]f-(p+u)ll-<E. Since p and f vanish at infinity, we get la1 < E . Therefore Ilf-plI5 I]f -p--all,-t la1 t 2 e . We have proved that r is dense in Co(L).
376
UNITARY RBPRESENTATION OF
SL (2,R)
Theorem 9.2. (Uniqueness of inverse spherical transform). Let dpo(2) +i ~ ) l2n 0}.
= (2s)-lR th nl d2 be the Plancherel measure on L = {s=3 If a function h in L1(L,po) satisfies
,.
then h(s)=0 for almost every s in L. Proof. For each f in g ( G ) nA, we have
Since { f If E g ( G ) n A} =r is dense in Co(L), we have ,-
L
$(s)h(s)dpo(s)=0 for every $ E Co(L).
Hence, by a form of the Riesz representation theorem (cf. Appendix D.5), the measure h(s)d,uo(s)=0 and h(s)=0 for almost every s in L. q.e.d. In the last part of this section, we treat rapidly decreasing zonal functions Iff is a C"-zonal function, then by Proposition 9.7,f[x] =f(ut) (x=cht) is a C"-function on [I, + co) and C"(G) n A is isomorphic to C"([1, a)). Similarly, L1(G)n A is identified with L1([O, + co), 2nshtdt) by the m a p ping f n f ( t ) = f ( u t ) (Proposition 5.3) or with L1([l, -t- a), 2 n d ~ )by the mapping f n f I x ]. By Proposition 7.15, the operation of the Casimir operator o on the zonal functionf is given by
+
(of)(?) = -ctht dfli3t-i3wfldta= -(sht)-l at ( s h t 9 .
Definition 6. Let sp be the set of functionsf in C(G)nA for which t"sht(omf)(t) is a bounded function of t for every pair of integers m 1 0 and nLO. The topology of 9' is given by the family of seminorms pm,,,(f)= sup Itnsht(omf)(t)l for m,n E N. tdO,+=O)
and pm(f)=
SUP I(o"f)(t)l
trCO+")
for m c N .
Then 9 is a locally convex topological vector space. The map fnofis a
HARMONIC ANALYSIS OF ZONAL FUNCTIONS
377
continuous linear map of 9 'into 9'. If cp is a C'-function on G and both 40 and Acp are bounded, then we have
for each f in 9' (The proof is the same as that of Ch. II(6.3)). Moreover if is a zonal function, then we have
(p
(9.26)
/+-(@f)(t)P(t)h(t)
= J 0l f ( t ) ( w m W )
Where dm(t)=2xshtdt. Now we introduce a function space 9' which will be proved to be the image of 9' under the spherical transform. Delinition 7. Let 9' be the class of complex valued functions F(s) defined on the strip D = {sE ClOjRe s j I} which satisfy the following four conditions; 1) F(s) is analytic in the interior b of D. 2) F(s) satisfies the functional equation F(s)=F(1-s). 3) F(s) is a C"-function on D. 4) For all m,n E N,the function
dm -"s"(l -s)nF(s)] drm
is bounded on D. The topology of
9 is defined by the family of seminorms
I
--[S"(I--S)"F(S)] for m, n E N . dSm dm Let (Fn)nr~ be a Cauchy sequence in 9.Then (Fa)converges to a function F uniformly on D. It is easily seen that F belongs to 9 and thus 9' is complete. Therefore 9 is a Frkchet space. We shall prove in Theorem 9.3 below that spherical transform fl ; f n f i s a topological isomorphism of 9 'onto 9'. qm,n(F)=SUP
ttD
Proposition 9.19. Let @(g, s) = (Vgo*'f,fo) and m be an integer2 0. Then we have the following properties:
for all trO and s=u+iA E C. 2) There exists a polynomial P(s) of s and for each compact set C in [0, + a), there exists a constant Mmsuch that
378
UNITARY REPWHNTATION OF
SL (2,R)
for all s E D. Proof. 1) By formulas (5.8) and (9.5), we have #(ac,s) =&Sl'e-8t(at-1-@)d8=(2x)-l
.
lcht- sht cos 81-8d8
0
Hence { -s loglcht -sht cos 81) d8 fr
= ( 2 ~ ) - 1 ( -1)-1 (loglcht-sht cos0))"lcht- sht cos81-sd0 0
Since
e-'= cht - sht 5 lchr - sht cos8/5 cht + sht =el for every t 2 0, we have
= t m$ (at, u> where s = u + 2. 2) Since Icht-sht COSBI-' = (chat+ shatCOSae-shat COS~)-*/', 7
we see that am#(at7 s)/atm is equal to a sum of terms of the form
where PO@)is a polynomial of s and Q(x, y, z ) is a polynomial of x, y , z. If C is a compact subset of [0, + m), then Q(sht, cht, cos8) is a bounded function of (t, 8) on C x [0,2~]. Hence there exists a constant Mm>Osuch that
=MmIP(s)l#(at, a)
d~mlP(s)l
if s= u +i,?E D (Proposition 9.10). Proposition 9.20. The spherical transform Y : f n f l is a continuous linear mapping of 9 into 9.Moreover we have
379
HARMONIC ANALYSIS OF ZONAL FUNCTIONS
(9.27)
(w*f)"(s>=sn(l -s)*f(s)
for every f E 9 and n E N.
Proof. Iffbelongs to 9, thenfbelongs to L1(G)n A. Hence the spherical transform f ( s )=F(s) satisfies the first two properties in Definition 7 (Proposition 9.12). By Proposition 9.19, l), we have
[(am/asm)$(ac, s)] 5 t"
for each t g o and s E D
.
On the other hand, rnf(r) belongs to L1([0, + 03 ), 2 ~ s hdr) t for each f E 9. Therefore for any m E N,the integral s)dm(t)
/;f(t)(a"iasm)p(o,,
converges uniformly for s E D. Consequently the function f ( s ) is a C"function of s in D and satisfies
(d"/ds"lf(s)=S'>(t)(a-las-)$(u,, 0
(9.28)
S)dm(t).
Moreover (dm/dsn)f(s) is bounded on D. By (9.26) and Proposition 9.16, we have
1-
(~"f)^(4 = bnf)(t)$(ut, s) dm@) 0
4)dm(t)
= /d(t)(o.g(al, =sn( 1-s)nf(s)
.
Replacingfin (9.28) by d f and using (9.27), we get (9.29) and (dm/ds*)(sn(l-s>.f(s)) is bounded on D. Hence f belongs to 9. The above formula (9.29) proves the continuity of y.In fact if
Isht(l+~~+~)(o"f)(t)l5&/2n for all t 2 0 , then we have
I(d"/ds")(s"(l-s)"f(s))l
$E
(1 +tn+2)-'tmdt=Ce. q.e.d.
for all s E D.
Proposition 9.21. Iff belongs to 9,then for each integer m 2 0, there exists a constant C , such that Ix logn xf"x]l$ C,,, for all x E [ 1+ a)
.
380
UNlTARY REPRESENTATION OF
f”x] belongs to L1([l,
SL (2,R)
+ m), dx).
Pro05 Iff belongs to 9and m E N,then
s:
ZJ(t) =
Umshuf (u)du
is a bounded function of t. In fact, we have IZmf(t)I 51‘ l(1 +us)umshuf(u)l(l +u2)-1du
r-
The function Jmf(t)=
1:
umshUf’(u)du
is also bounded. For by integration by parts, we get Jmf(t)= tmshtf(t)-
and cht-sht (Itl++
a). Since
s:
(mum-lshu+u”chu)f (u)du
-sht(wf)(t)=(shtf‘(t))’, we have (u”shuf’(u))’ =murn-lshuf’(u)+ umshu(wf )(u) . Since wf belong to 9for eachf in 9, tmshtf‘(t)=mJm-l’(t)+Irnm’(t) is a bounded function oft. Then we see that tmf’(t) is bounded on R. Therefore
is bounded. Since log ( x + JxB--l) -log x, Jthat x l o g 9 * f”x]
-x(x-,
+ a), we see
+
is bounded on [l, m), for each m E N. Since (x log’ x)-1 is integrable on [2, + m), f”x] is integrable on [2, + a).Sincef”x1 is a C--function on [l, + m ) (Lemma l ) , f ” x ] is integrable on [l, 21. Hencef”~]is integrable on [l, a).
+
Theorem 9.3. (The inversion formula for 9). For every f in 9,we have fl*flf=f,
is the spherical transform f-f where the inverse spherical transform defined by
defined by (9.3) and
Y* is
HARMONIC ANALYSIS OF ZONAL FUNCTIONS
9-* ;F Hfk)=
(9.30)
381
F(s)dg, s)dpo(s)*
J L
Proof. I f f belongs to 9,then t%ht f(t) is bounded on R. Thus log*x f [ x ] is bounded on [l, + a ) and f [ x ] is integrable on [l, +a). Hence the Radon transform -m
is defined. The above infinite integral converges uniformly with respect to x in a compact set. Similarly, by Proposition 9.21,f"xl is integrable on [l, a). Therefore the infinite integral
+
/:_f'[x+t?'ld7jl convergesuniformly with respect to x contained in each compact set. Hence F,[x] is a differentiable function of x and we have
Then we have
in exactly same way as in the proof of Proposition 9.8. Put f=2sh(t/2). Then we have 1+ p = c h t , df=ch (t/2) dt, hence (9.31)
F,'[cht]chTdt t
f(l)=G[ -m
Since there exists a constant M>O such that Ixf[x]lsM for all {l, a),we have
+
Hence F,(t) is integrable on R. By Proposition 9.20 Therefore
X E
f belongs to 9.
is a bounded function of A for all m E N and f ( + + i A ) is an integrable function of A. By Proposition 9.6, {(++in) is the Fourier transform
382
UNITARY REPRESENTATION OF
SL (2,R)
of F,(t) multiplied by 4%. By Ch. 111, Theorem 1.8, the Fourier inversion formula holds for F,(t) and we have
1'
+-
=
*
o
f(+ +i
~COSA ) tdA
.
Differentiating both sides of above equality with respect to x=cht, we get
By (9.31), (9.32) and Fubini's theorem, we get
='I 2*
+-
f(++iA)AthlsAdA .
0
The last equality follows from Lemma 3 in $8. By Proposition 9.14, 2), we have
(9.34)
(9.
Remark. The proof of Theorem 9.3 does not depend on the results of 58 except for Lemma 3 of that section which gives the Fourier transform
HARMONIC ANALYSIS OF ZONAL FUNCTIONS
383
of (shr/2)-' on R and is independent of the other parts of $8. Hence Theorem 9.3 affords an another proof of Proposition 9.4.
Theorem 9.4. (Ehrenpreis-Mautner) The spherical transform 9 is a ' onto 9. The inverse mapping 9 - - l topological isomorphism of 9 of 9coincides with the inverse spherical transform 9-*given in (9.30). Proof. By Proposition 9.20, 9is a continuous mapping of 9 'into 9.And Theorem 9.3 proves that Y*Y f=f for every f E 9'. Let F be an arbitrary element in 9, and put f = Y * F . Since
+
+
+
sn( 1 -s)nF(s)$(g, s) = (1/4 Ra)"F(+ iR)$(g, 3 2)
is a bounded function of R for every n E N, and g , F(++iR)#(g, 3+iR) is integrable with respect to the spherical Plancherel measure p o . Hence f= r * F is defined. Now we shall prove the following two facts. (A) Y * F =f belongs to 9'. (B) 9-*is a continuous mapping from 9 into 9. If (A) is established, then Theorem 9.3 proves that 9-* Y f = f = T * F . we have Since 9-fand F belongs to 9, (C) Y f = F i.e. 99-*F=F by the uniqueness of the inverse spherical transform 9-*(Theorem 9.2). The assertions (B) and (C) together with Proposition 9.20 and Theorem 9.3 constitute the content of Theorem 9.4. Therefore it is sufficient to prove the assertions (A) and (B). Let F be an element of 9and put f = Y * F . Since Idm$(at,s)/atml$MmlP(s)l for all 220, m E N and s E D by Propositions 9.10 and 9.19, the infinite integral
1
lII+i"
Ira
F(s)(a "$/a t "1 (at, s)dpo(s)
converges uniformly on any compact subset of 0 4t < + a. Hence f is a C"-function and satisfies
dm
F f(0=
113
Therefore we have
By Propositions 7.16, 9.5 and 9.16, we have
384
UNITARY REPRESENTATION OF
SL (2,R)
Put t
y=sha2
and #(ar,s)=#(y, s).
Then we have #(Y, 4 = ( 1 +y)-*F(s,s, 1; Y/(l +Y))
-
Put z=y/(l +Y)
*
Then by Kunmmer's formula F(u, b, c; z)=(l-z)-aF(u, b, c ; z/(z-1)) #(y, s)=F(s, l-s, 1: -y). Now we put p ( y , s)=y-ar(1-2s)r(l
-s)-V(s,
(cf. ErdClyi [l] p. 64),
s,2s; -J+)
and p y y , s)=y*-T(2s- l)I-(s)-'F(l-s,
1-s, 2-2s; -y-l).
Then we have
.
(9.35) p y y , s)=#"'(y, 1-s) By Gauss' formula r ( ~ ) - ' I ; ( a , b , ~ : z ) = r ( b - ~ ) [ r ( b ) r ( ~ - ~ ) ] - l ( - ~l)--~"+Fa( ,a1,-~+u;z-') +F(U-b) [r(u)r(c-b)]-'(-z)-bF(b, 1-c+ b, 1--a+ b :z-l) (cf. ErdClyi [I] p. 63), we have (9.36) d Y , 8) = 5 w Y , s) +P Y Y , s) * By Euler's formula F(u, b,
C:
s:
z)=Z"(~)[I'(b)I'(c-b)]-~~*-l(l-r)e-a-l(l-r~)dr
(cf. ErdClyi [l], p. 59), we get
s:
=(2~)-'y-~tanns r*-l(l-r)'-l(l
+~y-l)-~dr
using r ( s ) r(l-s)=~/sinns. Since the integrand is an entire function of s, qP(y, s) is a meromorphic function of s in the half-plane Re s>O with simple poles at s= 1/2, 3/2, 5/2,... for y>O. Hence (y, s)= $(l) (y, 1-s) is a meromorphic function in the half-plane Re s< 1 with simple poles at s= 1/2, -1/2, -3/2,.- for y>O. Moreover
385
HARMONIC ANALYSIS OF ZONAL FUNCTIONS
Res $(a)(y,s) = -Res $(l'(y, s) a-l/a
a-111
.
Therefore q P ( y , s)+qP(y, s) is regular analytic in the interior D for y >0. Put W ) ( t ,s)=2-'i(+-s) tan x(+-s)#"(at,
b
of
s)
for j = 1,2 and
@"'(Y,
4=y-'+(y, 8 )
Then by (9.37), we have
Hence +(y, s) is regular analytic in the half-plane u =Re s >0 for y >0. If OO, O s r j l . If 1 / 8 S ~ = R e s ,then l+-sldls~(l+(2~s~)-1)S5~s~. Hence there exists a constant B, e.g. B= 5/4z such that I+(y, $1 d Blsl if 1/8d Re s By Cauchy's formula, we have
.
where contour C is a circle Jz--sl=~-l/8. If 1 / 4 1 0 S 1 we have 1/85 u- 1/8 7/8. Hence there exists a constant C,,,>0 such that
(9.38)
Put
386
UNITARY REPRESENTATION OF
1
SL (2,R)
iia+t-
f ( j ) ( y )=
F(s)@(j)(y, s)ds
(j= 1,2).
iia-to,
Then using (9.35) and the relation F(s)=F(l-s), we have (9.40) f‘a’(Y) =f‘”(v) * Hence by (9.36) and (9.443, we get
f(v)=2 - l ( f C W+f‘”(Y))
=f(’’(y)
9
namely
J
iia+i-
(9.41)
f(t)=
F(s)@“’(at,s)&.
iia-t-
For each integer n >0, we have
Since 0y,=[s(l-s)]~9J and [s(l-s)]”F(s) belongs to (9.41) for the function s”(l-s)”F(s) and get
J
9,we can apply
iia+&-
(9.43)
(o”f)(t)=
s”(l-s)”F(s)cD‘”(ae, s)&
1
iia-i-
For each y>O, F(s)O(l)(y,s) is analytic in 1/2sRe s< 1 and continuous on D s = ( s ~ C ( 1 / 2 S R e s S 1 }By(9.37)and . thefact that F e Q , wehave lim I F(s)W )(y ,s)l =0 IIm J I *-
and the convergence is uniform on D1. Hence we can shift the line of integration in (9.41) and get (9.44)
f ( t )= S1+*-F(s)@“’(u,, l-is)dr
1
1+i-
=
F(s)y-J+(at,s)ds.
l-i-
Since we have proved thatfis a C”-function, the proof of the assertion (A) at the beginning of the proof is reduced to the proof of the following assertion (A). (A) pm,n(f)<+w for m , EN. Since t
(1 + y ) l J Z =ch2
-
t
sh - and log(1+y ) - t 2
(t+
we have tmsht(wnf)(t)--y logmy(wnf)(t) (tn++
W)
+ a).
387
HARMONIC ANALYSIS OF ZONAL FUNCTIONS
By equations (9.41) and (9.43), it suffices to prove (A') for n=O, because the general case is proved by replacing F(s) by sn(l-s)"F(s). The assertion (A') for n = O and (B) are consequences of the following Lemma 3. q.e.d.
LEMMA 3. For each integer m10,we can find a constant Bms0 > O such that if
for all s E D, then IylogmYf(Y)lS BBrn.0 for all y > 0. For the purpose of proving this Lemma, we prove the more general Proposition T,,,,,,. For an m,n E N , and each function F i n 9
is bounded in y>O. Moreover we can find a constant B,,,>O the conditions IF(S)lSe(l+lSl)-',
...,
$E(~+ISI)-~ for all
such that
S ED
imply lylogLySlifmF(s)y-g,,+(y, an
5eBrn.n.
1-t-
Our Lemma 3 is the conjunction of Propositions Tm.ofor all m e N. Let W , be the conjunction of Propositions T,,,, for all n E N. Then we shall prove Proposition W , by the induction on m. Proof of Wo. For each integer n10,we have
for all s in D1={sll/4sRes g 1) and all y>O by (9.38). If F E 9 satisfies IF(s)l S e ( I + IS^)-^ for all s E D,then we have
388
UNITARY REPRESENTATION OF SL42,R)
where go,,= xC,. Proof of W,. Let m >0 and assume W , for all p <m. If F belongs to 9,then the inequality (9.45) holds for all y>O. Since d m F / h mbelongs . for every m, the repeated use of integration by parts shows that to Q
where A, and Ak are some constants. Since d m F / h mand F belong to
9,the induction hypothesis and (9.46) prove Proposition W,. q.e.d. COROLLARY to Theorem 9.4. The space 9is complete and hence a Frtchet space. Proof. 9 'is topologically isomorphic to a FrCchet space 9.
§lo. Irreducible unitary representations of SL(2,R) In sections 2,3 and 4, we have constructed irreducible unitary representations of the group SU(1,l). We have chosen SU(1,l) there instead of SL(2, R) because the behaviour of a maximal compact subgroup K in irreducible representations is easier to describ for SU(1,l). Since the group Go = SL(2, R) is isomorphic to G = SU(1,l) by the isomorphism (10.1)
y:Go
- G,
g' =
(g) = CgC-',
j ,(;
C =-
-ij)
each unitary representation V of G gives a unitary representation V' of Go. V' is defined by V' (g) = V(g'). V' is irreducible if and only if V is so. We put (10.2)
REPRESENTATION OF SL(2, a)
389
However this realization of representations for SL(2,R) is unnatural because the irreducible representations of SU(1,l) are constructed on spaces of functions on the unit disc D or the unit circle U. The group SL(2, R)/{f 1 ) is the automorphism group of the upper half-plane C+ while the group SU(l,l)/{ f1 } is the automorphism group of the unit disc. Hence it is natural to construct the representations of SL(2, R) on the space of functions on the upper half-plane C+ or its boundary, the real line R plus 00. In this section, we construct such representations for the group SL (2, R).
I. DISCRETE SERIES Let c be the Cayley transformation from the upper half-plane C+ = {z = x i y ) y > 0) onto the unit disc D = {CEC~ < 1):
+
z-i C =c(z) =z + i'
(10.3)
The inverse transformation c-l is given by (10.4)
The Cayley transformation c is a complex analytic diffeomorphism of C+ onto D. Let n E -12 and n > 112, and let 8, be the representation space of the 2
discrete series representation U" of SU (1, 1) (cf. $3). Namely sists of all holomorphic functions # on D with a finite norm
where dm (0= dudv for bY
C = u + iv. The representation
8. con-
Un is defined
(10.6)
Let H, be the Hilbert space of all holomorphic functionsfon C+with a finite norm (10.7)
where z = x
Ilfll2= (2n - l$Jc+
If ( z )I 2YZn-2dxdr
+ iy.
Proposition 10.1. 1) Let W,be the mapping from 8, into H , which maps # to f = W,# given by
UNITARY REPRESENTATIONOF SU2,R)
390
+
f ( z ) = ~ ( z i1-h I
(10.8)
z-i (m),
where A = JZ2-(*-I). Then W. is an isometry from @, onto H.. 2) Let D" be the irreducible unitary representation of SL(2, R) defined bY
0;
(10.9)
5:
Then the operator
w, u; 0
0
w;1.
0; is given by
(10.10)
for the element g-' in (10.2).
+
Proof. 1) Since the Cayley transformation C = c (z) = u iv is holomorphic, f = WnI is holomorphic on C+. Moreover we have
by the Cauchy-Riemann equations. A direct calculation gives the equality (10.11)
1
4Y
- IC12=
lz+i12'
Hence we have
X IZ
+ i14 dxdy = (2n -
If ( z ) I zyh-2 dxdy = ~
~ f ~ ~ z .
Hence W. is an isometry of @, into H.. Since (10.12)
z+i=-
2i 1 -C'
for z E C+ and
C E U,
the inverse mapping W,,-I of W. is given by (10.13)
4 (0 = (W,,-l f) (0 = A-I (2i)2n(1 - O-'"f(i l1 -+CC
).
For each function f in H,, the function 4 given by (10.13) belongs to @,, and satisfies W,, 4 =f.Hence W, is an isometry of onto H.. 2) The relations between the matrix entries of g'-I and g-' given in Proposition 1.6,l) imply that
a,,
REPRESENTATIONS OF s y 2 ,
391
R)
(10.14) Since g-' (10.15)
- C),
z = c-l ((g'-') az cz
we have
+b +d
The equalities (10.6), (10.13), (10.14) and (10.15) give
Corollary to Proposition 10.1. Let n E T1Z , n
1 and > -, 2
@-,
be the
Hilbert space on which the discrete series representation U-"is realized (cf. Theorem 3.2) and put W-, = u W,a,
where uf = f i s the complex conjugation. Then W-. is an isometry of &, onto UH,= H-,. H - , is the space of all antiholomorphic functions on C+ with the norm (10.7) finite. Thus also 0;" = W-,U>" W-,-'
(10.16)
is an irreducible unitary representation of SL (2, I?). The representation operator is given by (10.17)
11. Let 1 < u < 1 and
COMPLEMENTARY SERIES
$o
be the Hilbert space of all complex valued
measurable functions on the unit circle U with a finite norm
UNITARY REPRESENTATION OF Sa2,R)
392
where d( = (24-l d8 and & = (279-l d y for C = e'e and q = e ' y . @, is the representation space of the complementary series representation V" (cf. $4). The operator V;, for the element g' in (10.2) is given by (10.19)
Let H, be the Hilbert space of all complex valued measurable functions
f on the real line R with the norm (10.20)
Ilfll'
I X - ~ l - " " - ' " f ( ~ ) f Q d x d< y + 00.
=
PropositiOn 10.2. 1) Let S, be the mapping which maps a function to the function f = So/defined by
4 in @,
(10.21)
where A, = 2('-1)'2n-1.Then S, is an isometry of $, onto H,. 2) Put
c; = s, v;,
(10.22)
0
0
S;].
Then C" is an irreducible unitary representation of SL (2, R) on the Hilbert space H,. The representation operator C ; is given by (10.23)
for an element g - I
=
t f;).
Proof. 1) Put C = c ( x ) and q = c ( y ) (x, y Iy+ il = Iy - i l . Then it is easily verified that (10.24) (10.25)
1 - Re(Cq) =
dC = (2~)-'d8 =
E R)
21x - Y I 2
Ix
+ i I 2 Iy + il' dx
n(1
+ x')
-
and
dx nix
and note that
+ iI2'
By the equalities (10.21), (10.24) and (10.25) we have
393
onto H,. Hence S, is an isometry of 2) Since the inverse transformation S;’ : f-
4
is given by
(10.26)
we can prove (10.23) in the same way as (10.10). In fact we have
( C V )(XI
= [(SU
= Icx
v:, C’)fl(4
+ dl
-2,f
(n). m+b
111. PRINCIPAL CONTINUOUS SERIES The principal continuous series representation VJJ( j E { 0, 1/2}, s E C, Re s = 1/2) is realized on the Hilbert space @ = L2 (U,d o . The representation operator V i a is defined by
The corresponding representation PJ.’ of SL (2, R) is realized on the Hilbeit space $ = L2(R,dx). Proposition 10.3 Let j E { 0, 1/2} and Re s = 1/2. 1) Then the transformation TI,#: 4 f defined by ++
is isometry of $ = L2(U)onto H = L2 (R);and 2) if we put
394
UNITARYREPRESENTATIONOF SL(2,R)
P i J = T/.I VJ9ST-1 (10.29) r' J,r then PJUI is an irreducible unitary representation of SL (2, R). The representation operator p';* for g-' in (10.2) is given by 9
(10.30) (Pi'f) (x) = [sign (cx
+ d)I2JIcx+ dl+f(-).ax + b
Proof: 1) By (10.25) and (10.28), we have
=J- I1(x)I2dx
=
11f1I2
-0.
if Re s = 1/2. Hence Tj,, is an isometry of 8 = L2 (U)onto H = L2 (R). 2) The inverse transformation Ti,.-' is given by
By the equalities (10.14), (10.15), (10.26), (10.28) and (10.31) we have
('j'f)
= [(T,.8
'i;
T,,J-l).f]
Appendix
A. Banach-Steinhaus theorem 1. A subset B of a topological space X i s said to be nowhere dense if the closure has no inner points. A subset M of X is called meager or of the first category if M is the union of a countable family of nowhere dense subsets. If A is not of the first category, A is called of the second category. 2. A toplogical space X is called a Baire space if every non empty open subset of X is of the second category. Theorem (The Baire category theorem). A complete metric space and a locally compact Hausdorff space are Baire spaces. cf. Bourbaki [l] Ch. 9 $5. In particular a Banach space is a Baire space and of the second category. 3. Theorem (The uniform boundedness theorem). Let X be a Banach space and Y be a normed space. Let (Ta)asA be a family of continuous (=bounded) linear mappings of X into Y. If the set {TaxlaE A } is bounded for each x E X , then we have the strong limit lim T,x=O 0*0
uniformly in a E A . In particular {llTaIlla E A } is bounded. cf. Yoshida [l], p. 68, 69. Let X be a Banach space and X * be the dual space of X. X * is the Banach space of all bounded-linear forms on X with- the norm llfll= suplf(x)l. iisnsl
A Banach space Xis regarded as a subspace of the dual space X** of X * . Then Theorem A.3 implies the following theorem. Theorem (Banach-Steinhaus theorem). If a sequence ( x , ) , . ~ in a Banach space is weakly convergent, then the sequence (IIx,ll),.~ is bounded.
4.
B. Hilbert-Schmidt theorem 1. A linear mapping T of a Banach space X into a Banach space Y is called compact (or completely continuous) if every bounded subset B of 395
3 96
APPENDIX
Xis mapped onto a totally bounded subset T(B)of Y (that is, the closure T(B) is compact). Namely T is compact if the image (Tx,),,Nof each bounded sequence (x,),,*N contains a strongly convergent subsequence. 2. If H is a Hilbert space, a linear operator T on H is compact if and only if every weakly convergent sequence (X,,),,~N is mapped to a strongly convergent sequence ( T x ~ ) , , * N . The “if” part is easily proved. In fact if (x,),
k-
Hence we have y = T x and limllTx,,-Txll=limllTxnk-yII=O. The h-ar
k-or
last relation contradicts with IITx,, - TxllZ B . 3. Let T be a linear operator on a Hilbert space H and 2 be a complex number. Put
H ( l ) = {xEHJTx=;Lx}. If H(;O + {O} , then R is called an eigenvulue of T.If T is self-adjoint, then all the eigenvalues of T are real numbers and H(R) is orthogonal to H(p) if R # p . 4. LEMMA. If T is a bounded self-adjoint operator on H, then we have
Proof. The right hand side of (1) is denoted by m. Since I(Tx, x)ls IITxllllxll4IITII, we have millTII. For any two vectors x and y in H and for any a E R, we have rfr ( T ( a x f y ) ,(Rx&y))$mlllx+yllS
and ;({(Tx,y)+(Ty,x)}$m{Pllxl12+Ilylla}.Put y = T x . Then we have llTxlla5 2-lm {lllxl12 R-lllTxlla}. Put 2 = l l T x l ~ / ~for ~ xx#O. ~ ~ Then we have IITxl12jmllTxllllxll and IITxlld m\lxll for every x E H. Hence we get \]TI\ 5m . 5. THEOREM (Hilbert-Schmidt). Let T be a compact self-adjoint operator on a Hilbert space H and E be the set of eigenvalues of T.Then we have the following.
+
397
APPENDIX
1) E has no point of accumulation except R =0 possibly. 2) dim H(R) is finite if R # 0. 3) If H + {O} , then T has at least one eigenvalue. 4) H=@H(R). ACE
Proof. l), 2). Suppose that there exist sequences (Rn)nrN and (pn)nr~ such that Rn E R, pnE H, Tpn=Rnpn, (pn, Pm)=&,m, lim R n = R # O . Since IIRpnn+m
~ p , # = 2 ~ 3 > 0if n z m , no subsequence of (Rpn)nt~is strongly convergent. By the assumption lim(Rn- 2) =0 and the identity Inpn =R p n (2, -R)P,,, we see that no subsequence of (Rnpn),,.~is strongly convergent. This is a contradiction, because T is compact and TPn=Rnpn. We have proved 1). Putting Rn =2 for all n in the above argument, we see that 2) has been proved. 3) By Lemma in 4, There exists a sequence Cfn)%.~ in H such that
+
Ilfnll=l,
and liml(Tfnn,fn)l=IITII. n+m
Replacing (fn) by a suitable subsequence, we may assume that lim(Tfn,fn) = R where R=IITII or -1lTll. Assume that R=IITll#O. Then we have O$ llTfn-~fnll’=llTfnllf--ZR(Tfnn,fn)+Af42R(R-((Tfn,fn))~O, (n+ a). Since T is compact, there exists a strongly convergent subsequence (Tfn,)*.~of (Tfn). Since lim(Tfn-Rfn)=O and R#O, the sequence cfn,) converges strongly to fo. Then we have llfoll= 1 and Tfo-Rfo=lim(lly;l, k-m -nfn,)=O. Hence R=IITII is an eigenvalue of T. When R = -IITII, -1lTll is an eigenvalue of T. 4) Suppose that H#@H(R). Then we have a contradiction by applying arB
3) to the restrictions of T to the orthogonal complement of @H(R). ICE
C. Measure and integration 1. Let X be a set. A family 123 of subsets of X i s called a 0-algebra or 0-additivefamily if it satisfies the following three properties. 1) XEb, 2) AE123impliesAc=X-AEb,
3) A,Eb(nEN)implies 6 A,,€% n-0 A set A in b is called b-measurable or simply measurable. 2. A function m on a 0-algebra b with values in [0, +a] is called a measure defined on 123 if m satisfies m(#)=O and m( An)= gm(An) n-0 n-0 for every disjoint countable family an),,.^ of sets in 113. The triple (X, b,m) of a set X, a 0-algebra b of subsets of X and a measure m on 123 is
398
APPENDIX
called a measure space. We always assume that Xis a countable union of sets of finite measures. A property P is said to hold almost everywhere if the set of points where it fails to hold is a set of measure zero. 3. Let (X, 8,m) be a measure space. Put R u { k a]. Then an Evalued function f on X is called measurable iff -l((a, a])belongs to 8 every a E R . A complex valued function is called measurable if its real and imaginary parts are measurable. 4. For each A E 8,the defining function x A of A is defined as ~ . ( x ) =1 or 0 according to x E A or x 4 A. A real valued function p is called simple if it is measurable and assumes only a finite number of values. I f p is simple and takes the values cl, ..., cR,then
x=
+
n
(1)
(O =
C~X.~,
where As = { x E X I( o ( x )
=a}.
i-1
5. I f E is a measurable set and p a nonnegative simple function given by (l), then we define the integral of p over E by 11
n
II
pdm =
,,
cim(Ai nE )
.
Let f be a nonnegative h d u e d measurable function on the measure space (X, b,m) and E be a measurable set. Then the integral off on E is defined by
1
f d m = sup
B
oSPS/
1
pdm,
E
where p ranges over all simple functions satisfying Ogp$f. f is called integrable on E if
s.
fdm<
+
CO.
Let f be a measurable function on
X. Thenf is said to be integrable if both f ‘(x)=Max [f (x),0 ) and f -(x) = Max{ -f(x), 0 ) are integrable. I f f is integrable, its integral is defined by fdm= I
E
f+dm/ E
f-dm. / E
f is integrable if and only if If1 = f ’ + f - is integrable. A complex valued function f is called integrable if both Re f ( x ) and Imf(x) are integrable. 6. The following theorem on termwise integration is referred to as Lebesgue’s dominated convergence theorem or simply Lebesgue’s theorem. r~ a sequence of integrable functions on E convergTHEOREM. Let ( f n ) nbe ing to a function f ( x ) almost everywhere. Suppose that there exists an integrable function g on E satisfying 1fn(x)lS g ( x ) for all n and for almost every x. Then f is integrable on E, and
399
APPENDIX
f dm=lim
COROLLARY. (Lebesgue's bounded convergence theorem). Let (fn)nrN be a sequence of uniformly bounded measurable functions on E. Suppose that m(E)< + 00 and Cfn(x))n.~converges to f ( x ) for almost every x E E. Then f is integrable on E and
7. If (X, 8,m) is a measure space and p z 1, we denote by Lp(X, m) the space of all C-valued measurable functions for which
1
f lpdm<
+
00,
considering two functions in L p to be equal if they are equal almost everywhere. LP(X, m) is a Banach space with the norm
Ilf
IlP =
(1 X
If
IPdm)liP
8. Let (X, 8,m) and (Y, Q, n) be two measure spaces. We denote by 23 x Q the smallest a-algebra of subsets of Xx Y which contains all the sets of the form A x B(A E 8,B E 6).It is proved that there exists a uniquely determined measure m x n on 8 x Q such that
(m x n) ( A x B ) =m(A)n(B)
.
m x n is called the product measure of m and n. The integral over Xx Y of an (m x n)-integrable functionf ( x , y ) is denoted by
-
/ x s y f ( x , v) dm(x)dn(v)
THEOREM (Fubini). A (8x &)-measurable function f ( x , y ) is integrable over X x Y if and only if either of the interated integrals
is finite. In such a case, we have
Iff is integrable on Xx Y, then for almost every x E X (resp. Y E Y), the function YH f(x, y) (resp. x ~ f ( xy)) , is integrable on Y(resp. on X).
400
APPENDIX
Reference for Cl-C8. Royden [l], Halmos [l]. 9. Let (X, b,m) be a measure space and H be a Banach space. An
H-valued function 9 on X is called simple if there exists a finite number of elements al, ..., an in H and a disjoint family of measurable sets A, ..., A, such that m(Ar)< + m(1 Si$n) and ad for each X E A( q(X),= 0 for each X E X - ; IA ( .
i
(-1
The integral of q over X is defined by n
n
An H-valued function f on X is said to be m-integrable (in the sense of Bochner), if there exists a sequence (q,)nrNof H-valued simple functions which converges strongly to f(x) for almost all X C X in such a way that r
Iff is m-integrable over X,the integral off over X is defined by x q,dm.
/,fdm=Um/n-*
The strong limit in the right hand side exists and is independent of the approximating sequence (yn)nrN. cf. Yoshida [l], p. 132.
D. Radon measure 1. Let X be a locally compact Hausdorff space. We always assume that X is 0-compact, i.e., Xis a countable union of compact sets. Let R be the family of all compact subsets of X. The smallest 0-algebra containing R is denoted by b. An element of b is called a Borel set in X. Since Xis ucompact, every closed set and every open set are Borel sets. A measure m on b is called a Borel measure if m(C)< + co for every compact set C. 2. Let L =L ( X ) be the space of all C-valued continuous functions on X with compact supports. Every function f in L is integrable with respect to a Borel measure m. The integral
TW=
fdm
J X
is a linear form on L which is positive in the sense that TCf)LO.
fro
implies
APPENDIX
401
3. A Borel measure m is called regular if it satisfies m(E)=sup{m(C)ICE W, Cc E } =inf{m(U)IUc D,Ec U } where D is the family of all open subsets of X . THEOREM (Riesz representation theorem). If T is a positive linear form on L,there then exists a unique regular Borel measure m on X such that T a = sXfdm
for all f in L. cf. Berberian [l], p. 227. A regular Borel measure is also called a Radon measure. The integral with respect to a Radon measure is called a Radon integral. The Riesz representation theorem shows that Radon measures on X correspond bijectively to positive linear forms on L. 4. Let CO(X) be the space of all C-valued continuous functions on X which vanish at infinity. Namely, Co(X)is the set of all C-valued continuous functions on X such that for every E > O there exists a compact set C and If(x)l d E for each x E X- C. Another form of the Riesz representation theorem is given as follows. THEOREM. To each bounded positive linear form T o n CO(X), there exists a unique Radon measure m such that T(f)=
fdm
for all f E CO(X).
S X
cf. E. Hewitt and K. Stromberg, [l], p. 364. Tbeorem. If m is a Radon measure on X , then the space L=L(X) of C-valued continuous functions with compact supports is dense in Lp(X, m) for 16p< + 00. Proof. Since X i s a-compact, there exists an open covering (Un)n,, of X such that 0, is compact and contained in Un+lfor all neN. Then for each elementf 20 in L' and for any E >0, there exists an integer n such that 5.
Let xtl be the d e h i n g function of Un and put fn(x) = xn(x)f(X). Then we have (1)
Ilf-fnllp
<8 *
Since fn is an integrable function 20, there exists a simple function g such that
4 02
APPENJXX
We can assume that G j c Un by (3). Since X is a a-compact locally compact Hausdorf€space, Xis paracompact and hence a normal space. Therefore there exists a continuous function hj on X such that 0 5 hf 5 1 and hj ( x ) is equal to 0 and 1 on F, and X - G, respectively. Then h, belongs to L and satisfies r
By (l), (2) and (4), we get \lf-hllP<3~.Every functionfcan be written asf = c f i + - f i - ) + i G + - h - ) wherefi=Ref,ji=Imfandfif =2-' (Iff1 55). Sinceft* belongs to L p iff belongs to LP, we can drop the assumption q.e.d. f 2 0 in the above proof. 6. Theorem. Let dx=dm(x) be the right Haar measure of a locally compact (0-compact) group G. Then the right regular representation R of G on Lp=Lp(G, dx) is strongly continuous. "he same result holds for left regular representation L. Proof. The operator RP is defined by (&f) (x)=f(xg). Hence we have R,Rh=Rgh and IIR,,fllP= llf[lp for all g and h in G and for all f in LP. Since R, is an isometry of L p , it is sufficient to prove the strong continuity at the identity element e of G. By D.5,for each f in LP and E>O, there exists a function h in L(G)=L such that Ilf-hllp<e/3. Let U be a fixed compact neighborhood of e such that m( U )2 1 and C be the support of h. Then CU is compact and has the measure u=m(CU)& 1. Since the support C of h is compact, h is uniformly continuous on G. Hence there exists a neighborhood N=N-l of e such that N c U and
IIRPh-hll,<~/(3u) for all gcN. Then we have
4 03
APPENDIX
E. Spectral representation 1. Let H be a Hilbert space and b be a cr-algebra of subsets of a set X. A spectral measure E on b in H is defined in Ch. 111, $3, Definition 3. For any two vectors u and v in H, a complex measure p U J A ) = (E(A) u, v) is defined on 2' 3 (cf. Ch. 111, $3). The integral with respect to I.
pu,o is written as
Jx
f(x)d(E(x)u,v). In particular, if b is the a-algebra
b(R) of Bore1 sets in R, put E , = E ( ( - co, 21). Then this integral is a Lebesgue-Stieltjes integral with respect to the function ~ ( 2=) (EAu, v) of bounded variation and is written as [I.j(l)d(Eiu, v).
2. Let E be a spectral measure on b in H andfbe a measurable function on X . Then a linear operator Tcf) is defined on the domain D ( f ) = r
+
{UE HI1 If(x)ladllE(x)ull2< a} with values in H, by X
Id.
cf. Ch. 111, $3. T ( f )is denoted by Tcf>=
f(x)dE(x).
3. The adjoint T* of a linear operator-T with dense domain D(T)is defined in Ch. V. $6, Definition 1. T is called self-adjoint if T = T*. THEOREM (von Neumann). If T is self-adjoint operator in a Hilbert space H, then there exists a unique spectral measure E on b =b(R) in H such. that
.=Iw
RdE,.
(1)
-ca
(1) is called the spectral representation of T. If T is bounded, the integral is taken over a finite interval. 4. THEOREM. Let A be a bounded self-adjoint operator on a Hilbert
space H, and A =
SI.
;tdEi be the spectral representation of A . If M is a
von Neumann algebra (cf. Ch. I, $2) containing A, then EA belongs to., M for all R E R. In particular EAE { A }
".
404
APPENDIX
Proof. If A 2 c (or A 5 -c), then En = 1 (or El = 0) belongs to M. Assume that -c < A. < c. Let E > 0 and pa (x) be a polynomical satisfying 1--e
<pa(x) < 1
--e
--e
for - c $ x d A o ,
+e
+
for loS x 5 Lo & E 5 x 5 c. for
+
<E
For any two vector u, v in H,we have
(P (4u - Elo u,
V)
=
(P. (4 - 1) d(El u. V )
Hence we have
and IIp6
(A)u - E@ll
+ '11
5 &llull
+ (l +
&)IIELo+6
- E&ull
- EAO+6 '11.
Since lim Elo+6= El, (strongly (Ch. 111, proposition 3.9,7)), we see that 1-0
pa (A) converges strongly to EAowhen 8 tends to 0. Since p 6 (A) belongs to the algebra M and M is strongly closed, Elo belongs to M.
F. Weak*-topology Let X be a topological vector space and X* be the dual of X. X* is, by definition, the set of continuous linear forms on X. Every x E X induces a linear formsf, on X* defined by fx (4) = 4 (x) for each 4 E X*. The weak*-topology of X* is the weakest topology on X* which makes the mapping fx continuous for every x E X . The weak*-topology is a locally convex topology on X*.A sequence (#JnN in X* converges to 4 in weak*-topology if and only if lim qJm (x) = 4 ( x ) for each x E X. n-m
G. A theorem of Fatou 1. Let X be a set and '$ ( X ) be the set of all subsets of X. A mapping m* from $' 3 ( X ) to [0, w] is called an outer measwe on X if m* satisfies the following three conditions (l), (2) and (3):
+
405
APPENDIX
+
(1)
0 5 m* ( A ) 5
(2)
A c B implies m* (A)
00,
m* (+)= 0, m* (B),
Let m* be an outer measure on X.Then a subset E of X is called m*measurable if E satisfies the following condition: (4)
m* ( A ) = m* ( A fl E )
+ m* ( A n Ec)
for all A
E 3 (X),
where Ec = X - E. Let 8 be the set of all m*-measurable sets in X. Then 8 is a a-algebra and the restriction m of m* to 8 is a measure on 8.m is called the measure defined by the outer measure m*. 2. Let 9 be the set of all half-open intervals (a, b] = { x E R I a < x 5 b } : 9 ={(a,blla, b E R, a 5 b } . fcontains the empty set 4 = (a, a]. Let g be a monotone non-decreasing function on R and put
I(a,blIP=g(b)-g(a).
Then we can define an outer measure m* = mT by
where I." is the interior of I. , i.e., I." = (a, b) if In = (a, b]. It is easily verified that m* is an outer measure on R. Let 8 be the set of all m*measurable sets. The a-algebra 8 depends on the function g. But 8 contains all intervals, all open sets, all compact sets, and all Borel sets in R. Hence 8 contains the a-algebra goof all Borel sets. Let m be the restriction of m* to Bo.Then ( R , go,m) is a measure space. m is called the Lebesgue-Stieltjes measure defined by g . The integral with respect to m is called the Lebesgue-Stieltjes integral and is denoted by P
P
3. Let f be a complex-valued function on a closed interval I = [a, b]. Let P be a finite subset of I. Then P defines a partition of I into the union of subintervals whose endpoints are elements of P. We identify the partition with P. Let 9be the set of all partitions of I. If a partition P E 9 of I is defined by
406
APPENDIX
. . <x,=b.
U = X ~ < X , < .
Put "
v (p9n=
c If
(XJ
and
-f(xt-dl
1-0
V(f) = SUP ( V V , f ) l
p
E
91.
Then V(f ) is called the total variation off on I. If V (f)is finite, then f is said to be of bounded variation. A function f is of bounded variation if and onlyif bothRe fandImfareso. A real valued function f is of bounded variation if and only if f is the difference of two monotone nondecreasing functions. Hence a complex valued function g of bounded variation is written as g = (g, - gz)
(6)
+ i(g3 - g4)
with four nondecreasing functions gl(1 5 i 5 4). Let g be a function of bounded variation expressed as in (6) on an interval Z = [a. b]. We extend g to a function g* on R which is defined by
s us x 5b
g(4,x
i
g* (x) = g(x),
g (b),b Ix.
Then a complex measure m is defined by m
+ i(m3 - m4)
= (ml- mz)
where ml is the Lebesgue-Stieltjes measure defined by the function g? (1 5 i 5 4). m is called the Lebesgue-Stieltjes measure defined by g. The support of m is contained in I. A function of bounded variation is differentiable almost everywhere.
5 a < 7t12 and ( = de be a point on the unit circle U. The angular domain A , ( O is defined by
4. Let 0
& ( r ) = {ref+/IArg(1
The domain A,
(0is
LEMMA1. Let
- retc#+'))I
illustrated in Fig. 1 of Ch.V. $3.
0 _I a < n/2 and put
B,={z€A,(r))
11 - z I
=cos~}.
Then there exists a constant M such that the following two inequalities hold for all z = rete E &:
407
APPENDIX
Proof. 1) Put 1 - z = pel*. Then we have 11
- zl = p
1 - lzl = 1 - 11 - pef*l = 1 - (1 - 2pcos4
Since z is in the domain A, (l), we have Hence if 0 < p 5 cos a,then we have
-
I1 -zl
1
P
+ +
(1 2 p P2)1/2 5 1 +2cosa - cosa
s
p2)ll2.
I$( 5 a and cos 4 2 cos a > 0. -
1-(1-2pcOs#+py2
- (ZI
+
and
1 - (1 - 2 p cos 4 2cos4-p
+p 2 y
2+P cos a
2+cosa = cos a
Fig. 1
2) Let y be the angle in Fig. 1. Then the law of sines for the triangl Ozl implies that
Hence we have Isinel = I s i n y J - I l-zl
s
( 1 - z J SM(1 -r).
The function
is called the Poisson kernel and has the following properties:
q.e.d.
408
APPENDIX
(I) PI (8) = 0 and P, is a continuous function of z = refofor 0 S r < 1, and 0 5 8 5 2n;
Lr
(II)
2n
--x
P,(8)d8 = 1 for 0 5 r < 1; and
if 0 c 6 < z,then lim sup I P,(8)I = 0.
(III)
it9izd
Because P, (8)4 P, (4 if 6 S 181 5 n. LEMMA 2. Let r (s) and 8 (s) be two continuous functions defined for 0 5 s 5 1 which give a curve in the angular domain A,, (1) (0 5 a < n/2) and r(1) = 1, 8(1) = 0. Put
K, (t) = sin tP: (6' - t )
for r = r (s) and 8 = 8 (s).
Then the functions K, ( 1 ) have the following properties. If 0 < 6 < n, then
6)
lim
sup
r t l dgltl$r
IK, (t)l
= 0.
(ii)
f"
(iii)
J
K,(t) dt is bounded as s
--I
-
1.
Proof. (i) We have sintsin(t - 8) (1 - 2 r cos (0 - t ) t2)2 2rsintsin (t - 8) P,(0 - t ) . 1 - 2rcos (8 - t ) r2
sin t P i ( 8 - t ) = 2 r ( 1
- r2)
+
+
Since the first factor on the right side is bounded when I t I 2 6 and 8 is near 0, (i) follows from the above property (111) of P, (8). (ii) follows from the equality
Lr
2n -*
sin t P ; (8 - t ) dr =
cos t P, (8 - t ) dr = r cos 8.
(iii) By the addition theorem of the sine function, we have
The second integral is equal to
409
and is bounded as r
-
1. Also we have
- _ Isinel a
(--id l+r
1-r
4r Il +. r 1-r2a
because ( 1
+ r)2- 4r = (1 - r)2 2 0 and by Lemma 1,2).
q.e.d.
5. Theorem (Fatou). 1) Let m be a complex Lebesgue-Stieltjes measure on the unit circle U defined by a function g (0) of bounded variation. Put
where P,(0) is the Poisson kernel. f is regarded as a function of z = rde on the unit disc D. Let C = deobe any point on U,where g is differentiable at e,. Then a non-tangential limit limf(r, 0)
= g’
(O,)
(z = rete E A ,
(0).
x-c
exists. 2) I f f (t) is an integrable function on U, in particular i f f is square
integrable, then the Poisson integral
has a non-tangential limit f ( t ) at almost every point e“ on U. Proof. 1 ) For the proof, let us first observe that 1 ) is trivially true for 1
the ordinary Lebesgue measure dm (t) = - dt by the above property 2n (11) of P,(t). So, without loss of generality, we may assume that m (U)= 0 by subtracting a constant multiple of df. Then the function g satisfies g(a)-g(-a)=m(U)=O. Put
410
Then, by integration by parts, we have
Replacing dm ( 2 ) by dm (t - O0), we may assume without loss of generality that O0 = 0. Let r (s) ere(#) (0 5 s < 1) be a non-tangential continuous curve approaching 1 as s 1. Let K, (t) be thefunction
-
K , (t) = sin t
.P:(8 - t)
for r = r (s), 8 = 8 (s)
and put G ( t ) = -- g' (0), sin t
I(s) =
1
"
K, ( t ) dt.
-x
Then the (5)
Since G is continuous at 0 with G (0) = 0, the integral
J
It1 <6
G (0K, ( t ) dt
is small for small 6 > 0 by (iii) by Lemma 2. On the other hand triad
G (t) K , ( t ) dt is small by (i) of Lemma 2. Lastly lim I ( s ) = 1 by (ii) Sf
1
of Lemma 2. Hence we have
liml(r (s), 8 (4)= g' at 1
(0)
by (5). 2) Let f be a function in L1(U)and put
Then g is of bounded variation and differetiable almost everywhere. Moreover the derivative g' satisfies g' (t) =f(t) almost everywhere.
Hence, if we apply 1) to the Lebesgue-Stieltjes measure m = m, defined q.e.d. by g, then we have 2). The above proof of Fatou's theorem is borrowed from Hoffman [l].
Notes
Chapter I. 3 3 . For the general theory of Haar measure, see Bourbaki [3], Ch. VII, Halmos [l], Hewitt and Ross[l], I, Loomis[l], and Weil[l]. Theorem 3.1 has been proved by many authors. Here we follow the proof of S. Ito [2]. If U is a weakly continuous irreducible Banach representation of a compact group, then U is finite dimensional (cf. Shiga [l]).
0 5. Theorem 5.1 cannot be extended to arbitrary continuous functionsj: Since a continuous function f is square integrable, the Fourier series off converges almost everywhere by a theorem of Carleson [l]. On the other hand, it has been proved by Kahane and Katznelson [l] that for every set B of measure zero on T,there exists a continuous function f such that the set of divergence of the Fourier series off coincides with B (cf. Katznelson [l], p. 58). Katznelson’s book is recommended to those readers who wish to consult a more detailed study of the ordinary Fourier series and integrals. Many applications of Fourier series and integrals to various branches of mathematics and physics are explained in the book by Dym and McKean[l]. For the proof of Carleson’s theorem, see Fefferman [l] and Jgrsboe and Mejibro [l]. Chapter 11. 35. For the general theory of Lie groups, see Chevalley [l], Helgason [13], Bourbaki [4], Varadajan [2], etc.
§ 8. The representation theory of compact semisimple Lie groups was established by H. Weyl [l]. A concise summary of his results is to be found in J-P. Sene [l] and Brocker and Tom Dieck [l]. An important addition to the theory concerns the construction of irreducible representations on the spaces of sections of certain line bundles on the flag manifolds or on the higher dimensional cohomology spaces (Borel-Weil-Bott theorem). See 41 1
412
NOTES
Kostant [2], Bott [l], I. Knapp [5]. Theorem 8.1 was proved by Taylor[l]. Theorem 8.2 was proved by gelobenko[l]. See also Sugiura [4].
Chapter 111. §3. In the 194O's, harmonic analysis on locally compact abelian groups was studied by many authors. Positive definite functions and Bochner's theorem play the central role in the theory (cf. Rudin [l], Ch. I). Using positive definite functions and the Krein-Milman theorem, Gelfand and Raikov [ 11 proved the existence of suflFiciently many irreducible unitary representations for every locally compact group (cf. also Godement [3]). The uniqueness of the measure p in Bochner's theorem (Theorem 3.1) may be proved by Levy's inversion formula which expresses p explicitly by the given positive definite function p. cf. Levy [l]. 5j4. The original theorem of Paley and Wiener [l] gave a characterization of Fourier transforms of functions in Lp with compact supports. Schwartz [13 generalized their result to tempered distributions.
Chapter IV
.
§ 2. Irreducible unitary representations of the Euclidean motion group were classified by It0 [l] and Mackey ([3], I). Our proof of Theorem 2.1 is based on the theory of representations of semi-direct products due to Mackey [3]. Vilenkin [l], [2] studied unitary representations of M(2) and their relations to Bessel functions. Theorems 3.2 and 4.2 were proved by him. Other types of formulae for Bessel functions were proved by Orihara [l], [2], using the representations of motion groups of Euclidean and Lobatchevsky spaces. 55. Theorem 5.2 was proved by Kumahara and Okamoto [l].
Chapter V. § 1. The Iwasawa decomposition for general semisimple Lie groups was first given in Iwasawa [l]. See also Helgason [13].
§ 2. The principal continuous series representationsfor SL(2, R) are easily generalized to every connected non compact semisimple Lie group G with finite center. Let G = KAN be an Iwasawa decomposition and M = C,(A) be the centralizer of A in K. Then the subgroup Po = MAN and its conjugates are called the minimal parabolic subgroups of G . Let Q be an
413
NOTES
irreducible unitary representation of A4 and u be a complex linear form on the Lie algebra a of A. Then the representation a@e’@l of P o is defined by (1)
(u@e’@l) (man)= a(m)e’(*O~for meM, UEAand neN.
The representation of G induced by a@e”@l is denoted by U(Po, u,u):
U(Po,Q, u ) = ind~o(o@eu@l). (2) U(Po,a,v ) is a unitary representation if u is purely imaginary valued on a. Let W(G,A) = N,(A)/C,(A) be the Weyl group. Then each element w of W(G, A) acts on u and u by: (3)
(wa)(m) = a(w;’mwo) and ( w )(H) = u(Ad w i ’ H ) ,
where w o E N,(A) is a representative of the coset w. The representation U(Po,Q, u) (u = purely imaginary) is irreducible if wu # D and wv # u for all w # 1 in W. In general the unitary representation U(Po,a,u ) is a direct sum of finite number of irreducible components (cf. Bruhat [I] and Knapp ~51).
In the above construction we can replace the minimal parabolic subgroup P o with an arbitrary parabolic subgroup P which is a conjugate of a closed subgroup of G containing Po. For the classification of the parabolic subgroups, see Matsumoto [l] and Warner ([l] I). A parabolic subgroup P can be decomposed as follows: (4)
P = M(P)A(P)N(P)
where M ( P ) is a reductive group, A ( P ) is a vector group and N ( P ) is nilpotent. Every element x E P is uniquely decomposed as follows: (5)
x = man, m E M(P), u
E A ( P ) and
n
E N(P).
The deomposition (4) is called the Langlunds decomposition. cf. Warner ([I] I). For any irreducible unitary representation n of M(P) and a complex linear form u on the Lie algebra a(P) of A(P), there is defined an induced representation (6)
U(P, a,u) = ind:(a@e”@l).
§ 3. The representations in the discrete series are characterized by the fact that their matrix elements are square integrable on G (cf. Proposition 7.18). Harish-Chandra [ll] proved that a connected semisimple Lie group has a square integrable (i.e. discrete series) representation if and only if it has compact Cartan subgroup H. The discrete series is parametrized by the regular unitary characters of H modulo the Weyl group W(G, H). The values of characters of discrete series on H were given by Harish-Chandra
414
NOTES
[l 13. The values on arbitrary Cartan subgroups have been determined by Hirai in IV of [7l.For the realization of the discrete series representations on the concrete function space, see Harish-Chandra [5], Narasimhan and Okamoto [l], Hotta [l], Parthasarthy [l], Atiyah and Schmid [l], Flensted-Jensen [5], Knapp [5]. Using Zuckerman's tensoring functor, a certain irreducible unitary representations of G are constructed corresponding to some of the singular unitary characters of the compact Cartan subgroup H.These are limits of discrete series. (cf. Zuckerman [l] and Knapp [5]). When G / K is a Hermitian symmetric space some of the limits of the discrete series representations are realized on the Hardy space on GfK. See Knapp and Okamoto [l] and Inoue [I]. §4. If the linear form u is not purely imaginary on a, the representation
U(P,0,u) is not unitary for the usual L2inner product. But for some choices of v , there exists a positive semi-definite Hermitian form invariant under the representation U(P,6,u). The irreducible unitary representations arising from these representations form the complementary series of G. The existence of the complementary series representation is deeply connected with the analytic properties of intertwining operators between U(P, c,u) and V(OP, wo, w ) (w E W(G,A), 8 = Cartan involution). See Gelfand, Graev and Vilenkin [l], Bruhat [l], Schiffmann [3], Knapp and Stein 111, PI, 141 and K ~ ~ PPI.P §5. The GPrding subspace Ho actually coincides with the space H , of C"-vectors for a wide class of Lie groups including semisimple groups with finite center. See Dixmier and Malliavin [l].
9 6. Unitary representations of SL(2, R) were studied in the fundamental work of Bargmann [I]. The results in $9 2, 3, 4 and 6 are due to him. Our notation for irreducible unitary representations differs from that of Bargmann. The correspondence is given as follows: V0&" = C:,.:, 1 1 1 VT FV= C~+,,zZ, U" = Dn,z+, U-"= Dn/z-, V a= Ca(I-o)o. Takahashi [l], [6] gave another proof of Theorem 6.5 by classifying positive definite spherical functions. Koornwinder [5] proved it by a non-infinitesimal method.
9 7. The characters of infinite dimensional irreducible unitary representations were first defined by Gelfand and Naimark [l] for SL(2, C). Later Harish-Chandra ([3] 111) defined characters for an arbitrary semisimple Lie group G as distributions on G. Harish-Chandra [4] calculated the
NOTES
415
characters of principal continuous series representations. Hirai [a] generalized this result to cover a certain type of induced representations including
w ,.I. 0,
Q 8. The results in Q 8 are due to Harish-Chandra [2], [8]. Other proofs of Theorem 8.1 have been given by Pukanszky [l], [2], Schiffmann [l] and Takahashi [l], [6]. The inversion formula for any connected semisimple Lie group with finite center was obtained by Harish-Chandra [15]. His proof depends on a deep study of the Eisenstein integrals and wave packets. A simplified proof was given by Herb [6], [8] and Herb and Wolf [I]. See also Dufeo and Vergne [ l ] . Q 9. Theorem 9.1 and 9.4 were proved by Ehrenpreis and Mautner [l]. The Paley-Wiener type theorem for zonal (i.e. two sided K-invariant) functions on semisimple groups with finite center was proved by Helgason [4] and Gangolli [l]. Similar theorems for arbitrary K-finite functions were studied by many authors in special cases and finally proved by Arthur [4] and Clozel and Delorme [I]. Harish-Chandra [ll] introduced the Schwartzspace W((G) which plays a role for semisimple Lie groups analogous to that of the space 9 ( R ” )do for the Euclidean space R”.
Further Topics The representation theory of semisimple Lie groups bas made remarkable progress in recent years and large number of results have been accumulated. Knapp’s book [5] is recommended as a good survey of the theory. One of the fundamental problems in harmonic analysis is the determination of the unitary dual 8 of a given group G where 8 is the set of all equivalence classes of irreducible unitary representations of G. This problem has been solved for some simple Lie groups (e.g., SL(2, R)(Bargmann [l]), SL(2, C) (Gelfand and Naimark [I]), Spin(n, 1) (Hirai [2]), SL(3, C) (Tsuchikawa [I]), Sp(2, C) and G,(C) (Duflo [2]), Sp(n, 1) (Baldoni-Silva [l]), SU(2, 2) (Knapp and Speh [l]), GL(n, K ) , K = R,C,H (Vogan [13])), but not yet solved for general semisimple Lie groups. The status in 1981 of the classification problem of 8 was described in Knapp and Speh [2]. In recent years Vogan [Ill, [12] and Barbasch and Vogan [4] have made important contributions. See also Clozel [2]. An irreducible unitary representation U of a semisimple Lie group G is called tempered if its character defines a continuous linear form on the Schwartz space B(G).Irreducible tempered representations were classified by Knapp and Zuckerman [2]. They are induced representations U(P,
416
NOTES
Q, u) for which P is cuspidal and Q belongs either to the discrete series or to the limits of discrete series. The results of Langlands [l] and their results give the classification of all irreducible quasisimplerepresentations of linear semisimple Lie groups. Another fundamental problem in harmonic analysis is to decompose a given unitary representation of a group G into the direct integral of irreducible representations. The most important case occures when U is the regular representation on the space L2(G/H). If G is a connected semisimple Lie group with finite center and H is a maximal compact subgroup K,the decomposition of Lz(G/K)into irreducible components were accomplished by Harish-Chandra’s theory of spherical functions (Harish-Chandra [q,[ll]). See also Rosenberg [l] and Helgason [181. If G is semisimple and H is the fixed points subgroup (or its identity component) of an involution of G, the discrete spectrum of L2(G/H) was given by Flensted-Jensen [5] and Oshima and Matsuki [2]. Harmonic analysis on the semisimple symmetric space G/H is an important field of research which remains to be developed. If G is a semisimple group and Tis a discrete subgroup of G, then the decomposition of L y G / f )is deeply connected with the theory of automorphic forms and number theory. See the classical paper of Selberg [l] and Gelfand and Piatetskii-Shapiro [13. For recent developements and the relation to number theory, see the Corvallis Proceedings [C13] and Arthur [41. In recent years many conferences on the representation theory of Lie groups have been held. The proceedings of these conferences are useful sources of knowledge. Therefore we have listed up some of them at the end of the Bibliography as [Cl] to [C29].
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[ClO] Non-Commutative Harmonic Analysis and Lie Groups, (Marseille-Luminy, 1976,78,80,82,85), Lecture Notes in Math. 587 (1977), 728 (1979), 880 (1981), 1020 (1983), 1243 (1987). ed. by J. Carmona and M. Vergne. [Cll] Lie Theories and Their Applications (Kingston, 1977), Roc. 1977 Ann. Seminar of the Canad. Math. Congress, Queen's Papers in Pure and Applied Math. 48 (1978), Queen's Univ. Kingston. [C12] Harmonic Analysis and Representations of Semisimple Lie Groups, (Libge, 1977), Math. Physics and Appl. Math. 5 (1980), Reidel, Dordrecht, Boston, London, ed. by J.A. Wolf, M. Cahen and M. de Wilde. [C13] Automorphic forms, Representations and L-functions (Corvallis, 1977), Roc. Symp. in Pure Math. 33(1979), AMS, Providence,ed. by A. Bore1 and W. Casselman. [C14] Representation Theory of Lie Groups (Oxford, 1977), London Math. SOC. Lect. Note Series 34 (1979), Cambridge Univ. Press. [C15] Lectures on Harmonic Analysis on Lie Groups and Related Topics (Strasbourg, 1979), Lectures in Math., Kyoto Univ. 14 (1982), Kinokuniya, Tokyo, ed. by T. Hirai and G. Schiffman. [Clq Harmonic Analysis (Pisa, 1980), Supp. Rendiconti Mat. Palermo 1(1981), Palermo, ed. by F. Ricci and G. Weiss. [ClT Operator algebra and Representation Theory (Neptun, 1980), Monographs Stud. Math. 17 (1984), Pitman, Boston. [C18] 1980 Seminar on Harmonic Analysis (Montreal, 1980), Canad. Math. Soc.
448
BIBLIOGRAPHY
Conf. Proc. 1 (1981), AMS, Providence. [C191 Harmonic Analysis (Mineapolis, 1981), Lecture Notes in Math. 908 (1982), Springer, ed. by F. Ricci and G. Weiss. [C20] Harmonic Analysis (Cortona, 1982), Lecture Notes in Math. 992 (1983), Springer, ed. by G. Mauceri, F. Ricci and G. Weiss. [C21] Gr6up Theoretical Methods in Physics (Istanbul, 1982), Lecture Notes in Physics 180 (1983), Springer, ed. by M. Serdaroglu and E. Inonu. [C22] Harmonic Analysis and Group Representations (Cortona, 1980), C.I.M.E., Liguori, Naples, 1982, ed. by A.F. Talamanca. [C23] Representation Theory of Reductive Groups (Park City, Utah, 1982), hog. in Math. 40 (1983), Birkhauser, Boston and Basel and Stuttgart, ed. by P.C. Trombi. [C24] Group Representations and Systems of Differential Equations (Tokyo, Adv. Studies in Pure Math. 4 (1984), Kinokuniya (Tokyo) and NorthHolland (Amsterdam), ed. by K. Okamoto. [C25] Applications of Group Theory in Physics and Mathematical Physics (Chicago, 1982), Lect. in Appl. Math. 21 (1985), AMS, Providence, ed. by M. Flato, P. Sally and G. Zukerman. [C2qLie Group RepresentationsI, 11,III (College Park, 1982-83), Lecture Notes in Math. 1024 (1983), 1041 (1983), 1077 (1984), Springer, ed. by R. Herb, R. Lipsman and J. Rosenberg. [C27]Analyse Harmonique sur les Groupes de Lie et les Espaces Symetriques(Kleebach, 1983), M h o i r e SOC. Math. France 15 (1984), Soc. Math. France, Paris, ed. by M. Duflo, P. Eymard and G. Schiffmann. [C28] E. Cartan et les Mathematiques d'aujourd'hui (Lyon, 1984), Asterisque, numero hors serie (1985), Soc. Math. France, Paris. [C29] Representation theory of Lie groups (Kyoto-Hiroshima, 1986), Advance studies in Pure Math. 14 (1988) Kinokuniya, Tokyo. ed. by K. Okamoto and T. Oshima.
Index A adjoint operator, 281 adjoint representation, 6, 67 algebra, 64 almost everywhere, 398 analytic differential representation, 287 analytic vector, 287 approximate identity, 28 automorphic factor, 236
B %-measurable, 397 Baire space, 395 Banach representation, 219, 272 Banach-Steinhaus theorem, 395 Bargmann's theorem, 305 Bessel's inequality, 4 Bochner's theorem, 129 Borel measure, 400 Borel set, 400 bracket, 62
C Ck-function, 35 C'-vector, 219 Cm-vectorfield, 65 Cartan decomposition, 267 Casimir element, 72, 295, 299, 330 central distribution, 309 central function, 57 character, 25, 51. 178, 311 -Of VJ*',327 - o f Ye,329 - o f U",337 class function, 57 closure of an operator, 296 mmmutant, 10 commutator, 62 compact operator, 17, 395 complementary series, 261 complete orthonormal family, 3 completely continuous, 395
complexification, xv conjugate Fourier transform, 102 convolution of functions, 24, 102 cyclic representation, 12 cyclic vector, 12
D decomposable operator, 120 defining function, 398 degree of a representation, 5, 18 derivation, 64 derivative of a distribution, 39, 155 diagonal element, 122 differentiable action of a Lie group, 74 differentiable function on T,35 differentiable vector, 219 differential of a Cm-mapping,319 differential representation, 67, 219 Dirac measure, 39, 151 direct integral, 120, 121 direct sum of Hibert spaces, 8 direct sum of Unitary representations, 9 d i d set, 149 discrete series, 243 distribution, 38, 151, 178, 309 dominant G-integral form, 94 dual --of a topological group, 19 - o f R, 31 - o f T,32 --of SU(2), 58 -of R",101 - o f SL(2, R), 305 *(c), 306 9 d G L 347
E Ehrenpreis-Mautner theorem, 383 eigenvalue of a linear operator, 396 entire function, 144 equivalent unitary representation, 7 exponential of a matrix, 60 exponential type, 145
449
450
INDEX
F factor group, 5 Fatou's theorem 409 Ff,Ff",341 i k t (principal) series, 218 formal degree, 335 Fourier-Laplace transform, 146, 199 Fourier-Plancherel transform 117, 184 Fourier series, 1 --of a piecewise C'-function, 35 -of a squareintegrable function, 32 -of a distribution, 41 - o n a compact group, 22 - o n a compact Lie group, 96 - o n SU(2), 76 Fourier transform - o f a distribution on R",153 - o f a distribution on T,41 - o f a Radon measure, 126 - o n a compact group, 22 - o n M(2), 169, 188 - o n Rn,102 - o n SL(2, R),359 Fubini's theorem, 399
G GHrding subspace, 275 G-integral form, 94
H Haar integral, 14
--of M(2), 169 - o f SL(2, R),266,267,325 - o f SU(2), 56 harmonic oscillation, 2 harmonic polynomial, 85 highest weight, 69, 94 Hilber-Schmidt norm, 22,69, 177 Hilbert-Schmidt operator, 177 Hilber-Schmidt theorem, 395 holomorphic function, 143 homomorphism, 5 H-S norm Hilbert-Schmidt norm H-S operator Hilbert-Schmidt operator
-I
induced representation, 162, 164
infinitesimalgenerator, 284 integrable function, 398 integral, 398, 400 intertwining operator, 9 invariant subspace, 8 inversion formula of the Fourier-transform, 106 -for R", 106 -for M(2), 175 -for SL(2, R),359 irreducible unitary representation, 8 Ito-Mackey theorem, 165 Iwasawa decomposition, 205
J Jacobi identity, 64 Jacobi polynormial, 334
K K-finite differential representation, 280 K-finite representation, 292 K-finite vector, 279 K-invariant, 362 K-weight, 298 Killing form, 71
L Lebesque's (dominated convergence) theorem, 398 left regular representation, 7 Lie algebra, 64, 65 Lie group, 35 Lie product, 62 Lie subalgebra, 64 limit of discrete series 255 linear Lie group, 65 logarithm of a matrix, 61
M maximal compact subgroup, 206 maximal torus, 54 maximal weight, 69 measurable complex valued function 398 measurable vector valued function, 119, 120 measure, 397 -space, 398 motion group, 156 multiplicity, 30, 273
451
INDEX
N nilpotent Lie algebra, 226 normalized Haar integral, 15 nowhere dense, 395
0 one dimentional torus group, 5 orthonormal family, 3 orthogonality relations, 18 - o f characters, 51
P Parseval equality, 3, 22, 32, 107, 177, 361 Payley-Wiener theorem, 146, 150 Peter-Weyl theorem, 19 piecewise C'-function, 35 Plancherel theorem, 115 -for M(2), 183 positive definite function, 122 positive linear form, 400 product measure, 399 principal continuous series for SL(2, R) 218 principal series for M(2), 162
Q quasi-invariant measure, 165
R radial part of Casimir operator, 349 Radon integral, 14, 401 Radon measure, 401 rapidly decreasing function, 36, 79, 103, 170, 195 regular Bore1 measure, 401 regular elements, 317 representative algebra, 27 representative function, 26 representation space, 5 Riemann-Lebesque theorem, 34, 112 right Haar integral, 14 right invariant differential operator, 275 310 right regular representation, 7, 402 root of a compact Lie group, 94
S o-additive family, 397
a-algebra, 397 Schur's lemma, 11 second category, 395 second (principal) series, 218 self-adjoint operator, 281,403 spherical function, 364 semisimple Lie algebra, 72 simple function, 398 slowly increasing function, 40 slowly increasing measure, 152 solid harmonics, 85 spectral measure, 131 spectral representation, 403 spherical harmonics, 91 spherical transform, 364 Stone's theorem, 138 strict inductive limit, 150 strongly continuous representation, 6 summable, 3 symmetric linear operator, 281 .Y(R"), 103 Y(G), 170
T tangent space, 319 tangent vector, 319 tempered distribution, 152 tempered function on Z, 40 tensor product of Hilbert spaces, 125, 126 three dimensional proper Lorentz group, 21 1 topological group, 4 torus group, 5 total variation of a complex measure, 133 trace of an operator, 172 trace class, 172 Tschebyscheff polynomial, 257
U uniform approximation theorem, 27 uniform boundedness theorem, 395 unimodular locally compact group, 14, 25 uniqueness of Fourier transform -on a compact group, 28 - o n R",111 unitary representation, 5 , 18 universal enveloping algebra, 70
V von Neumann algebra, 11
4 52
INDEX
w W*-algebra, 11 weakly analytic, 201 weak*-topology,404
weight of representation, 69, 94
Z zonal function, 362 zonal spherical function, 364